Answer:
The answer is C. time. Please mark as brainliest.
The student has a mass of 50.0 kg. What is her momentum at 2 s (in kgm/s)?
Answer:
50kgm/2
Explanation:
An electric heater rated 2.75 kW is connected to a 240 V power line with a circuit breaker rated 10 A. Deduce whether or not the line will be active. when the heater is switched on.
To determine whether the line will be active when the heater is switched on, we need to calculate the current that will flow through the circuit when the heater is in operation. We can use Ohm's law, which states that current is equal to voltage divided by resistance, or I = V/R.
The resistance of the heater can be calculated using the formula:
R = V^2/P
where V is the voltage and P is the power of the heater.
In this case, the resistance of the heater is:
R = 240^2/2.75 kW = 20.87 Ω
Using Ohm's law, we can now calculate the current that will flow through the circuit when the heater is on:
I = V/R = 240/20.87 = 11.5 A
Since the current required by the heater (11.5 A) is greater than the circuit breaker rating (10 A), the circuit breaker will trip when the heater is switched on, and the line will not be active.
Which statement did Kepler’s investigations of the movement of the planets explain?
Jupiter has more moons than earth.
Gravity acts on all objects in the universe.
The sun is more massive than earth.
Earth is not the center of the universe.
Answer:
earth is not the center of the universe
Explanation:
i just took the test
Kepler's laws allow us to find that the correct answer, the basis is these is
d) Earth is not the center of the universe.
Kepler made extensive measurements and created a mathematical model of the movement of the planets around the sun, these analyzes are written in the form of three laws
Kepler's first law. Says the planets move elliptically Kepler's second law. Establish that the vector from the sun to the planet sweeps equal area in equal time intervals Kepler's third law. It is an application of Newton's second law to the movement of the planets around the sun, it gives a relationship between the period of the orbit and the semi-major axis of the ellipse.
\(T^2 = ( \frac{4\pi ^2}{G M_s} ) \ a^3\)
Where T is the period, a the major axis, G the universal gravitational constant and \(M_s\) the most of the sun.
When analyzing these Kepler's laws in all the sun is the center of movement.
Let's analyze the different claims;
a) False. The laws are not on a specific planet
b) False. Gravity is not in Kepler's laws
c) False. A ratio of the masses between planets and the sun is not established
d) True. In the laws the sun is the center of movement, therefore the earth is not the center of the universe.
In conclusion using Kepler's laws we can find that the correct answer for the bases of these is:
d) Earth is not the center of the universe.
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WHAT IS THE MEAING OF- Grouping Data
Grouping data refers to the process of categorizing or organizing data based on specific criteria or attributes.
It involves grouping similar data points together to gain a better understanding of patterns, relationships, and trends within the dataset. By grouping data, you can simplify complex information and derive meaningful insights from large amounts of data. The purpose of grouping data is to create subsets or clusters that share common characteristics.
This enables easier analysis, summarization, and comparison of data within each group. Grouping can be performed on various types of data, such as numerical, categorical, or time-based data. Grouping data allows for the exploration of data at different levels of granularity.
For example, you can group sales data by region to analyze regional performance, or group customer data by demographics to identify specific customer segments. This process helps in identifying outliers, detecting patterns, and making data-driven decisions.
Common techniques for grouping data include using functions like GROUP BY in SQL or utilizing data visualization tools to create charts or graphs that illustrate the grouped data. Grouping can be applied in various fields, such as marketing, finance, healthcare, and research, to uncover insights and support decision-making processes.
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Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
A piston absorbs 42 J of heat from its surroundings while being compressed
from 0.0007 m³ to 0.0002 m³ at a constant pressure of 1.0 × 105 Pa. What
are the correct values for heat and work for the piston?
OA. Q=-42 J, W = +50 J
OB. Q = +42 J, W = +50 J
OC. Q = +42 J, W = -50 J
OD. Q = -42 J. W = -50 J
The correct values for heat and work for the piston are;
Q = +42 J, W = -50 J
Option C
What is the work done?
We must note that the work that has been done by the piston can be obtained by the formula that we know and that formula states that;
w = PdV
w = work that have been done
P = pressure
dV = change in the volume
As such we would have that the work done is;
w = 1.0 × 10^5 Pa (0.0002 - 0.0007)
w = -50 J
This is the work that has been done but the heat was absorbed hence it is positive.
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1. A bicyclist travels for 1.5 hours at an average speed of 23 km/h. How far does the bicyclist travel
in that time?
Explanation:
23 km/hr x 1.5 hrs = 34.5 km
34.5 km = 34500 meters
What force acts on a projectile in the horizontal direction?
The force that acts on a projectile in the horizontal direction is Gravitational force.
A projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile, thus causing a vertical acceleration. The horizontal motion of the projectile is the result of the tendency of any object in motion to remain in motion at constant velocity.
Due to the absence of horizontal forces, a projectile remains in motion with a constant horizontal velocity. Horizontal forces are not required to keep a projectile moving horizontally. Hence, The only force acting upon a projectile is gravity.
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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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The direction of force of Earth's magnetic field is from the geographic South
Pole to the geographic North Pole. Where is Earth's magnetic north pole?
A. Near Earth's center
B. Near Earth's equator
C. Near Earth's North Pole
D. Near Earth's South Pole
Answer:Near Earth's North Pole
Explanation:
A peregrine falcon dives at pigeon . the falcon start downward from rest with free-fall acceleration . if the pigeon is 76.0 m below the initial position of the falcon , how long the falcon take to reach the pigeon? Assume that the pigeon remains at rest .
Answer:
3.94 s
Explanation:
Take down to be positive. Given:
Δy = 76.0 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
76.0 m = (0 m/s) t + ½ (9.8 m/s²) t²
t = 3.94 s
You are told that the value of a car of the given model, based on its age, is less than $6000. Give a range of values that could represent the car.
The following equation represents the value (y) of a car based on its age (x).
\(y=-800x+12000\)We are told that the value of a car of the given model, based on its age, is less than $6000.
So, we can write
\(6000<-800x+12000\)Let us solve the above inequality for x.
\(\begin{gathered} 6000<-800x+12000 \\ 6000-12000<-800x \\ -6000<-800x \\ \frac{-6000}{-800}<\frac{-800x}{-800} \\ 7.5>x \\ x<7.5 \end{gathered}\)This means that the age of the car is less than 7.5 years.
Therefore, the possible range of values that could represent the age of the car is 0 to 7.5 years.
\(0Which equation describes the sum of the vectors plotted below?
The equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
What is vector quantity?A physical quantity that has both directions and magnitude is referred to as a vector quantity.
A lowercase letter with a "hat" circumflex, such as "û," is used to denote a vector with a magnitude equal to one. This type of vector is known as a unit vector.
According to the final position of the vector as shown in the figure, The final x co-ordinate is 4 and the final y co-ordinate is 2.
the equation describes the sum of the vectors plotted below is: \(\vec{r} = 4 \vec{x}+2 \vec{y}\)
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Which one of the statements below is true about mechanical waves?
They must travel in empty space.
They can travel in a vacuum.
Both sound and light are examples of mechanical waves.
They require a medium to travel through.
Answer:
They require a medium to travel through.
Explanation:
What are three hazardous chemicals found in cigarette smoke?
Answer: I believe hydrogen cyanide, carbon monoxide, and ammonia are the three chemicals involved, but im not sure
A toy car is given an initial velocity of 5.0 m/s and experiences a constant
acceleration of 2.0 m/s/s. What is the final velocity after 6.0 s?
The final velocity after 6.0 s is
1304.2 .
What is velocity?
velocityis the most fundamental quantity of physics . Work is said to be done when a force applied to an object cause a displacement of a object.
Solution -
As per the given-
Mass of runner m = 74kg
initial velocity of runner u=4.8 m/s
final velocity of runner v =0
Coefficient of friction ¥=0.7
Let's d be the distance moved by runner till the stop.
a- mechanical energy lost due to friction
As friction does negetive work causing the runner to stop.
As we know,
Mechanical energy lost= Kinetic energy of runner
Mechanical energy lost =
1/2 mv^2 = 1/2 ×74×4.8^2=852.2
Distance move by runner-
Work done by friction = mechanical energy lost
-¥×mg×d =852.2 j
-0.7×74×9.8×d = -491.2
Solving the equation we get
1304.2.
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If you move for 4 seconds, and travel a distance of 360 meters, how fast were you going?
Answer:
90 m/s
Explanation:
Time taken = 4 sec
Distance travelled = 360 m
Speed = Distance / Time = 360/4 = 90 m/s
Distance travelled = 360m
Time taken = 4s
We have to find speed\(.\)
_________________________________
◈ Speed is defined as the ratio of distance travelled to the timr taken.
SI unit : m/s
➝ Speed = Distance / Time
➝ Speed = 360/4
➝ Speed = 90m/s
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?
A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.
To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).
The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:
E_initial = KE_initial + PE_initial
The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:
E_final = KE_final + PE_final
The nonconservative work done on the boy is equal to the change in mechanical energy:
Work_nonconservative = E_final - E_initial
Let's calculate each term:
KE_initial = (1/2) * m * v_initial^2
= (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = m * g * h_initial
= 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * m * v_final^2
= (1/2) * 66.1 kg * (8.51 m/s)^2
PE_final = m * g * h_final
= 66.1 kg * 9.8 m/s^2 * 0
Since the boy ends at ground level, the final potential energy is zero.
Substituting the values into the equation for nonconservative work:
Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)
Simplifying:
Work_nonconservative = KE_final - KE_initial - PE_initial
Calculating the values:
KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2
PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m
KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2
Substituting the values:
Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]
Calculating the result:
Work_nonconservative ≈ -42.7 kJ
Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.
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A charged Adam or particle is called a
Answer:
A charged atom or particle is called an ion :)
What is the displacement (in miles, with direction) from the
Aquarium to the Cemetery?
Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test. I have it with me right now and it has everything I've ever been taught about math in it so it might help you.
in which states of matter will a substance have a fixed volume
Answer:
Solid is the state in which Matter maintains a fixed volume
Answer:
The state of matter that has a fixed volume is Solid.
Explanation:
Solid substances will maintain a fixed volume and shape.
If friction is present when an object is dropped and hits the ground, how does its kinetic energy just before striking the ground compare to its gravitational potential energy at the top of the drop? OKinetic energy is greater. Kinetic energy is less. The energies are the same. The energies are unrelated.
Kinetic energy is less just before striking the ground compare to its gravitational potential energy at the top of the drop.
What is kinetic energy?
Kinetic energy, which can be seen in the moving of an object or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving entity. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food dropping from a table, and a charged particle in an electric field.
A falling object loses potential energy while gaining kinetic energy. The difference between the rise in kinetic energy and the decrease in potential energy is exact. Thus, potential energy is transformed into kinetic energy when an item falls freely. The kinetic energy of the object is transformed into heat and sound energy when it strikes the earth.
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IBM has a fast computer that it calls the Blue Gene/L that can do '136.8
teracalculations per second. How many calculations can it do in a microsecond?
Answer:
138.6 megacalculations
Explanation:
This is a pretty straightforward one.
All it needs is to convert the degree of measurement.
Dimensions in physics are attributed names, which state the power to which they're are raised. Just as how
Kilo and Mega means the numbers are raised to the power of 3 and 6 respectively. There also exists the ones that indicates how small, such as milli and micro, which are to the powers of -3 & -6.
The question says the IBM computer calculates at an astonishing 136.8 teracalculations.
Tera in physics means it's raised to the power of 12. Thus, the IBM calculates at an astonishing rate of
136.8*10^12 calculations per second.
We're then asked how many calculations it does in 1 micro second. Like I had highlighted earlier, 1 micro second is 1 raised to the power of -6. Or succinctly put,
1 micro second = 1*10^-6.
If the IBM does
138.6*10^12 = 1 second,
Then it does
x = 1*10^-6 second.
When we cross multiply, we have
138.6*10^12 * 1*10^-6, and that is
138.6*10^6 calculations, or say, 138.6 megacalculations.
The IBM does 138.6 megacalculations in 1 micro second, which is still astonishing, by the way
the two factors that affect the amount of heat
Answer:
The two important factors that affect heat energy are specific heat and temperature. Specific heat is a heat-constant of a material per unit mass per degree of temperature change (in units of energy per mass and temperature), like Joules/Kg-°C .
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Two vectors A and B are such that A =1,B=2,A.B=1 find angle
Answer:\(60^{\circ}\)
Explanation:
Given
\(\mid\Vec{A}\mid=1\)
\(\mid\Vec{B}\mid=2\)
And \(A\cdot B=1\)
We know \(\vec{A}\cdot \vec{B}=\mid\Vec{A}\mid\mid\Vec{B}\mid\cos \theta\)
Where \(\theta\) is the angle between them
Substituting the values
\(1=1\times 2\cos \theta\)
\(\cos \theta =\dfrac{1}{2}\)
\(\theta =60^{\circ}\)
Thus the angle between \(A\) and \(B\) is \(60^{\circ}\)
An object is being shot from a horizontal ground at an incline angle of 30 degree with respect to the ground at a speed of 52 m/s. Find the duration in seconds that the object is above the height of 14 m. Give your answer with one decimal place.
When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.
What is speed?Speed is the time rate at which velocity is changing.
Vertical speed component is
V₀y = 52sin 30°= 26 m/s
Given is the height h=14m
Using second equation of motion,
S=ut+ 1/2 at²
Substituting the values, we get
14 = 26t - 4.9t²
4.9t² - 26t +14 =0
Solving the quadratic equation, we get the time as
taking the positive sign, t =4.698 s
taking the negative sign , t = 0.6082 s
Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.
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9. A car travels accelerates at a rate of 2.5 m/s² to the right for 9.5 seconds. If it
traveled a total of 500 meters during this timeframe, how fast was it moving
initially?
I
Answer:
51.38m/s
Explanation:
displacement=initial speed×time+1/2acceleration×time^2
s=ut+1/2at^2
500=9.5u+1/2×2.5×9.5
divide everything by 9.5 and minus 2.5×1/2
500/9.5-1/2×2.5=u
u=51.38m/s
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A 30.0 kg box hangs from a rope. What is the tension (in N) in the rope if the box has an initial velocity of 2.0 m/s and is slowing down at 2.0 m/s2?
Answer:
360 N
Explanation:
m = 30kg u = 2 m/s a = -2m/s/s
Since the object has an initial velocity of 2 m/s and acceleration of -2 m/s/s
the object will come to rest in 1 second but the force applied in that one second can be calculated by:
F = ma
F = 30 * -2
F = -60 N (the negative sign tells us that the force is acting downwards)
Now, calculating the force applied on the box due to gravity
letting g = -10m/s/s
F = ma
F = 30 * -10
F = -300 N (the negative sign tells us that the force is acting downwards)
Now, calculating the total downward force:
-300 + (-60) = -360 N
Hence, a downward force of 360 N is being applied on the box and since the box did not disconnect from the rope, the rope applied the same amount of force in the opposite direction
Therefore tension on the force = 360 N
A car travels 15 m to the right in 0.02 seconds, what
is the average velocity of the car during this time
period? (4B)
a. 0.3 m/s
b. 750 m/s
C. 7.5 m/s
d. 3 m/s
Answer: B. 750
Explanation:
the relation between speed ,distance and time can relate by formula S=VT
finding velocity V=s/t
15/0.02=750
so B. option is correct