Answer:
84
Step-by-step explanation:
100-point test = 50 questions which are worth 2-points each.
(50 x 2 = 100)
If she got 8 wrong, this means she lost 16 points ( 8 questions x 2 points each = 16 points in total)
100 - 16 = 84
To find her score if she got x questions wrong just multiply x by 2 and subtract the answer to 100.
2.29. The following are the impulse responses of continuous-time LTI systems. Determine whether each system is causal and/or stable. Justify your answers. (a) h(t)= e-u(t - 2) (b) h(t) = e-u(3-t) (c) h(t)= e-2¹u(t + 50) (d) h(t)= e2u(-1-t)
(a) The system is causal and stable.
(b) The system is causal and stable.
(c) The system is causal and unstable.
(d) The system is causal and stable.
(a) The impulse response is given by h(t) = e^(-u(t - 2)). Here, u(t) is the unit step function which is 1 for t ≥ 0 and 0 for t < 0. The system is causal because the impulse response is nonzero only for t ≥ 2, which means the output at any time t depends only on the input at or before time t. The system is also stable since the exponential term decays as t increases, ensuring bounded output for bounded input.
(b) The impulse response is given by h(t) = e^(-u(3 - t)). The system is causal because the impulse response is nonzero only for t ≤ 3, which means the output at any time t depends only on the input at or before time t. The system is also stable since the exponential term decays as t increases, ensuring bounded output for bounded input.
(c) The impulse response is given by h(t) = e^(-2¹u(t + 50)). The system is causal because the impulse response is nonzero only for t ≥ -50, which means the output at any time t depends only on the input at or before time t. However, the system is unstable because the exponential term grows as t increases, leading to unbounded output even for bounded input.
(d) The impulse response is given by h(t) = e^(2u(-1 - t)). The system is causal because the impulse response is nonzero only for t ≥ -1, which means the output at any time t depends only on the input at or before time t. The system is also stable since the exponential term decays as t increases, ensuring bounded output for bounded input.
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Solution of
3/20+1/25-11/60=
Answer:0.06
Step-by-step explanation:
Answer:
0.006
Step-by-step explanation:
3/20 = 0.15 + 1/25 = 0.19 - 11/60
= 0.00666666
Interior and Exterior Triangle Angles
Answer:
∠ WXY = 20°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ XYZ is an exterior angle of the triangle, thus
10x - 5 = 3x + 17 + 3x + 2
10x - 5 = 6x + 19 ( subtract 6x from both sides )
4x - 5 = 19 ( add 5 to both sides )
4x = 24 ( divide both sides by 4 )
x = 6
Thus
∠ WXY = 3x + 2 = 3(6) + 2 = 18 + 2 = 20°
Carrie will spin the arrow on the spinner four times. What is the probability that the arrow will stop on A, then B, then C, Then D?
Answer:
1 / 256
Step-by-step explanation:
Sample space Total sections of spinner = (A, B, C, D) = 4
P(spinner stops on A) = 1 /4
Second spin :
P(stops on B) = 1/4
Third spin :
P(stops on C) = 1/4
Fourth spin :
P(stops on D) = 1/4
Hence,
P(A then B then C then D)
1/4 * 1/4 * 1/4 * 1/4 = 1
Complete two expressions that have the same product as 3 x 5 . 12
__________ x
1
12 __________ x
3
12 hurry up please
In the laboratory analysis of samples from a chemical process, 5 samples from the process are analyzed daily. In addition, a control sample is analyzed 2 times each day to check the calibration of the laboratory instruments.a) How many different sequences of process and control samples are possible each day? Assume that the five process samples are considered identical and that the two control samples are considered identical.b) How many different sequences of process and control samples are possible if we consider the five process samples to be different and the two control samples to be identical?c) For the same situation as part (b), how many sequences are possible if the first test of each day must be a control sample?
a) The total number of different sequences of process and control samples each day is 823,543. b) The total number of different sequences of process and control samples each day is 120. c) The total number of different sequences of process and control samples each day, considering the first test as a control sample, is 46656.
a) To calculate the number of different sequences of process and control samples each day, we can consider the samples as distinguishable. We have 5 process samples and 2 control samples.
For each position in the sequence, we have 7 choices (5 process samples or 2 control samples). Since the samples are independent and can be selected in any order, we can use the multiplication principle.
Therefore, the total number of different sequences of process and control samples each day is 7⁷ = 823,543.
b) Now, let's consider the five process samples to be different and the two control samples to be identical.
We have 5! (5 factorial) ways to arrange the process samples among themselves. However, the two control samples are identical, so they remain fixed in their positions.
Therefore, the total number of different sequences of process and control samples each day is 5! = 120.
c) If the first test of each day must be a control sample, we need to consider the control sample fixed in the first position. We have 1 choice for the first position (control sample) and 6 choices for the remaining 6 positions (5 process samples and 1 control sample).
Therefore, the total number of different sequences of process and control samples each day, considering the first test as a control sample, is 1 * 6⁶ = 46656.
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Which inequality matches the graph?
A.−3x + 2y > 7
B.3x − 2y < 7
C.−2x + 3y > 7
D.2x − 3y < 7
the blue line represents . the green line represents . the yellow line represents . the red dot is the lower limit of integration. the yellow dot is the upper limit of integration.
The blue line represents the curve of the function that is being integrated. The green line represents the area under the curve between the lower and upper limits of integration. The yellow line represents the area between the two points on the curve. The red dot is the lower limit of integration, and the yellow dot is the upper limit of integration.
Integration is a way of finding the area under a function. The lower limit of integration is the point at which the area starts to be measured, while the upper limit of integration is the point at which the area stops being measured.
When calculating the area under the curve between two points, the lower and upper limits of integration can be identified by the red and yellow dots.
To calculate the area between the two points, we will use the formula for integration. This involves taking the integral of the function between the lower and upper limits of integration. This is done by summing the area of each small slice of the function between the two points.
Once the area under the curve is found, it can be compared to the area represented by the green line. If the green line is larger than the area under the curve, then the area under the curve will be negative. If the area under the curve is larger than the green line, then the area under the curve will be positive.
By comparing the green line to the area under the curve, it is possible to determine whether the area is positive or negative. This can help to solve mathematical problems that require integration.
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In a right-angled triangle, the hypotenuse is h cmlong aand the other two sides are f cm and g cm in height. Write down a formula which connects f g and h
Answer: f²+g²=h²
Step-by-step explanation:
In a right triangle, you use the Pythagorean Theorem: a²+b²=c² to find the hypotenuse of the triangle. I would believe that you could just substitute the variables in this equation with the ones that you have. This should show the relationship between the 3 unknown lengths of the sides.
Graph y=1/2x=+1
Use the table or identify m and b if it helps you graph.
Answer: 1/3
Step-by-step explanation:
need help! h(x) = square root of x-10 what is the domain of h?
if a television screen with a length-to-height ratio of 16:9 has an area of 576 square inches, what is its perimeter?
The perimeter of television is = 100 inches
What is mensuration ?The study of measuring geometric shapes and their qualities such as length, volume, shape, surface area, lateral surface area, and so on is known as mensuration. Mensuration will be covered in fundamental mathematics.
Calculationlet the length be 16x and width be 9x
area given = 576 sq. inches
16x * 9 x = 576
144 \(x^{2}\) = 576
x = 24/12
x = 2
length = 32
width = 18
perimeter = (32 + 18)*2 =100 inches
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help w−3/4=8 a) 5 b) 35 c) 29 d) -1
Answer:
w = 35/4
im not exactly sure why the options are whole numbers.
Step-by-step explanation:
8 = w-3/4
-w + 8 = -3/4
-w = -3/4 - 8
-w = -3/4 - 32/4
-w = -35/4
w = 35/4
WILL MARK BEST ANSWER BRAINLIEST
Miranda compared the function f (x) = 1/4x + 5 to the linear function, g(x), shown in the table.
table:
X G(X)
-9 -10
-6 -8
-3 -6
0 -4
What is the slope of the function with the larger slope?
A: 5/1
B: 1/4
C: 3/2
D: 2/3
The answer above is correct, i got it right on the test!
A box contains 8 red marbles, 4 white marbles, and 6 blue marbles. if a marble is randomly selected from the box, what is the probability that it is red? express your answer as a fraction or a decimal number rounded to three decimal places, if necessary.
The probability of selecting red marble is 0.444.
Probability is calculated using the formula :
Probability = number of favourable outcomes ÷ total number of outcomes
Number of favourable outcomes = number of red marbles in box
Number of favourable outcomes = 8
Total number of outcomes = total number of marbles
Total number of outcomes = 8 + 4 + 6
Total number of outcomes = 18
Keep the values in formula of probability to find the probability of selecting red marble
Probability = 8 ÷ 18
Performing Division by 2
Probability = 4/9
Representing in decimal round to three decimal places = 0.444
Hence, the probability of selecting red marble is 0.444.
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What is the slope of the line?
Please hurry!!!
Answer:
slope = 3/4
Step-by-step explanation:
rise over run
The Watson household had total gross wages of $105,430. 00 for the past year. The Watsons also contributed $2,500. 00 to a health care plan, received $175. 00 in interest, and paid $2,300. 00 in student loan interest. Calculate the Watsons' adjusted gross income.
a
$98,645. 00
b
$100,455. 00
c
$100,805. 00
d
$110,405. 00
This past year, Sadira contributed $6,000. 00 to retirement plans, and had $9,000. 00 in rental income. Determine Sadira's taxable income if she takes a standard deduction of $18,650. 00 with gross wages of $71,983. 0.
a
$50,333. 00
b
$56,333. 00
c
$59,333. 00
d
$61,333. 0
For the first question: The Watsons' adjusted gross income is $100,805.00 (option c).For the second question: Sadira's taxable income is $50,333.00 (option a).
For the first question:
The Watsons' adjusted gross income is $100,805.00 (option c).
To calculate the adjusted gross income, we start with the total gross wages of $105,430.00 and subtract the contributions to the health care plan ($2,500.00) and the student loan interest paid ($2,300.00). We also add the interest received ($175.00).
Therefore, adjusted gross income = total gross wages - health care plan contributions + interest received - student loan interest paid = $105,430.00 - $2,500.00 + $175.00 - $2,300.00 = $100,805.00.
For the second question:
Sadira's taxable income is $50,333.00 (option a).
To calculate the taxable income, we start with the gross wages of $71,983.00 and subtract the contributions to retirement plans ($6,000.00) and the standard deduction ($18,650.00). We also add the rental income ($9,000.00).
Therefore, taxable income = gross wages - retirement plan contributions - standard deduction + rental income = $71,983.00 - $6,000.00 - $18,650.00 + $9,000.00 = $50,333.00.
Therefore, Sadira's taxable income is $50,333.00.
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PLS HELP!
What type of angle is shown? (1 point)
an angle of one hundred eighty degrees
a
Straight angle
b
Obtuse angle
c
Acute angle
d
Right angle
It takes Amelia 45 minutes to rake her yard every Saturday during the fall. It takes Andy 1 hour to rake the same yard. If Amelia and Andy work together, how long will it take them to rake the yard? Round your answer to the nearest minute.
The hypotenuse of a right triangle measures 3 cm and one of its legs measures 2 cm. Find the measure of the other leg. If necessary, round to the nearest tenth.
The required length of the other leg is \($\sqrt{5}$\) cm. If we need to round to the nearest tenth, we get: \($b \approx 2.2$\) cm
How to use Pythagoras theorem to find sides of right angled triangle?Let's use the Pythagorean theorem to solve this problem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs. So we have:
\($c^2 = a^2 + b^2$\)
where c is the length of the hypotenuse, a and b are the lengths of the legs.
We are given that the length of the hypotenuse is 3 cm and the length of one leg is 2 cm. Let's substitute these values into the equation above:
\($3^2 = 2^2 + b^2$\)
\($9 = 4 + b^2$\)
\($b^2 = 5$\)
\($b = \sqrt{5}$\)
So the length of the other leg is \($\sqrt{5}$\) cm. If we need to round to the nearest tenth, we get: \($b \approx 2.2$\) cm (rounded to one decimal place).
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Function f(x) represents the population of bacteria x hours after 9 a.m. What does F(2)-F(1) represent?
Answer:
f(2)-f(1) => Difference between the count of bacteria between 11AM and 10AM
Step-by-step explanation:
Here x is the number of hours after 9AM
f(2) means the count of bacteria after 2 hours of 9AM i.e. at 11AM
f(1) means the count of bacteria after 1 hour of 9AM i.e. at 10 AM
f(2) - f(1) will give us the difference between the count of bacteria between 11 AM and 10 AM
Hence,
f(2)-f(1) => Difference between the count of bacteria between 11AM and 10AM
Help me please
A. 3.0
B. 1.8
C. 1.0
D. 2.5
Answer:
The average GPA would be 1.8
Step-by-step explanation:
Hope this is helpful. I did a test like this exact question and I got it right.
1) Explain the problem of unit root in standard regression and in time-series models and Explain how to use the Dickey-Fuller and augmented Dickey-Fuller tests to detect this. In clearly and detailed . Kindly type your answers . Course Econometrics
The problem of unit root in standard regression and time-series models arises when a variable exhibits a non-stationary behavior, meaning it has a trend or follows a random walk. Unit root tests, such as the Dickey-Fuller and augmented Dickey-Fuller tests, are used to detect the presence of a unit root in a time series. These tests examine whether the coefficient on the lagged value of the variable is significantly different from one, indicating the presence of a unit root.
In standard regression analysis, it is typically assumed that the variables are stationary, meaning they have a constant mean and variance over time. However, many economic and financial variables exhibit non-stationary behavior, where their values are not centered around a fixed mean but instead follow a trend or random walk. This presents a problem because standard regression techniques may produce unreliable results when applied to non-stationary variables.
Time-series models, such as autoregressive integrated moving average (ARIMA) models, are specifically designed to handle non-stationary data. They incorporate differencing techniques to transform the data into a stationary form, allowing for reliable estimation and inference. Differencing involves computing the difference between consecutive observations to remove the trend or random walk component.
The Dickey-Fuller test and augmented Dickey-Fuller test are commonly used to detect the presence of a unit root in a time series. These tests examine the coefficient on the lagged value of the variable in a regression framework. The null hypothesis of the tests is that the variable has a unit root, indicating non-stationarity, while the alternative hypothesis is that the variable is stationary.
The Dickey-Fuller test is a simple version of the test that includes only a single lagged difference of the variable in the regression. The augmented Dickey-Fuller test extends this by including multiple lagged differences to account for potential serial correlation in the data. Both tests provide critical values that can be compared to the test statistic to determine whether the null hypothesis of a unit root can be rejected.
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This question is about the process of forming diamond from graphite. a) For C(graphite) ↔C (diamond) at 298 K and 1 bar, Δ
T
H
∘
=+1.895 kJ mol
−1
and Δ
r
S
∘
=−3.363 J K
−1
mol
−1
. Calculate ΔS
miv
for the forward process (constant T and P ). b) Based on your answer to part a, does diamond form graphite under these conditions? Why/why not? Does the reverse reaction occur? Why/why not?
a) The ΔS_miv for the forward process of forming diamond from graphite at constant temperature and pressure is -3.363 J K^(-1) mol^(-1).
b) Based on the calculated ΔS_miv value in part a, diamond does not form graphite under these conditions, and the reverse reaction does not occur.
a) The ΔS_miv represents the change in molar entropy for a process. In this case, the forward process is the conversion of graphite to diamond. The given value of ΔrS° (-3.363 J K^(-1) mol^(-1)) represents the change in molar entropy at standard conditions. Since the process is occurring at constant temperature and pressure, ΔS_miv can be considered equal to ΔrS°. Therefore, the ΔS_miv for the forward process is -3.363 J K^(-1) mol^(-1).
b) The sign of ΔS_miv is negative (-3.363 J K^(-1) mol^(-1)), indicating a decrease in molar entropy during the forward process. According to the second law of thermodynamics, a spontaneous process favors an increase in entropy. Since the forward process of forming diamond from graphite leads to a decrease in molar entropy, it is not favored under these conditions. Therefore, diamond does not form graphite under these conditions.
Additionally, the reverse reaction (conversion of diamond to graphite) would also be unfavorable because it would require an increase in molar entropy, which contradicts the negative value of ΔS_miv.
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Is y=4/x-3 linear or non-liner
18 rice cakes weigh a total of 130 g. There are 329 calories in 100 g of rice cakes. How many calories are there in one rice cake?
Answer:
1 rice cake has 23.761 calories
Step-by-step explanation:
18 rice cakes weigh a total of 130 g.
There are 329 calories in 100 g of rice cakes.
Step 1
We calculate the number of calories is 18 rice cakes
18 rice cakes = 130g
Hence,
100g = 329 calories
130g = x
Cross Multiply
100g × x = 130g × 329 calories
x = 130g × 329 calories/100g
x = 427.7 calories
Therefore, 18 rice cakes had 427.7 calories
Step 2
How many calories are there in one rice cake?
18 rice cakes = 427.7 calories
1 rice cake = x
Cross Multiply
18 × x = 1 × 427.7
x = 427.7/18
x = 23.761111111 calories
Approximately = 23.761 calories
Therefore, 1 rice cake has 23.761 calories
the children in mr. wilson’s class were standing in a circle. zach, who was the second person, stood directly across from mary, the seventh person. how many people are there in mr. wilson’s class?
There are 7 people in Mr. Wilson's class, as Zach is the second person and Mary is the seventh person.
To calculate the total number of people in the class, we can use the formula 2x = 7, where x is the total number of people. Solving for x, we get x = 7.
To determine the number of people in Mr. Wilson's class, we can use the formula for the number of people in a circle, which is N = 2(n-1), where n is the number of people standing opposite each other in the circle. In this case, n is 2 (Zach and Mary). Therefore, N = 2(2-1) = 2 people. However, since there are 7 people in total in the circle, we can conclude that the number of people in Mr. Wilson's class is 7. To explain further, based on the given information, we can say that Zach is the second person, which means there are 2 people before him in the circle. Therefore, there are 7 people in Mr. Wilson's class. To further explain, we can break down the equation as follows: The person opposite of Zach is the seventh person, or 7th, so we can say that 7 is equal to the number of people in the class multiplied by 2, or 2x. Then, solving for x, we get x = 7. This means that the total number of people in the class is 7.
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Line l contains points (0, -3) and (7, 4). point p has coordinates (4, 3).
The distance between the Line [L] that contains points (0, -3) and (7, 4) and Point [p] has coordinates (4, 3) is 2/5 units.
What is the general equation of a Straight line?The general equation of a straight line is -
[y] = [m]x + [c]
where -
[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].
[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.
We have line [L] contains points (0, -3) and (7, 4). Point [p] has coordinates (4, 3).
The distance between a point P(m, n) and a straight line Ax + By + C = 0
is given by -
d = (|Am + Bn + C|)/ (\(\sqrt{A^{2} +B^{2} }\))
We can find the equation of line as follows :
slope = [m] = (7/7) = 1
y = x + c
For point (7, 4) -
4 = 7 + c
c = - 3
Equation of the line will be -
y = x - 3
x - y - 3 = 0
and
m = 4
n = 3
d = |1 x 4 + (-1) x 3 - 3|/5
d = 2/5
Therefore, the distance between the Line [L] that contains points (0, -3) and (7, 4) and Point [p] has coordinates (4, 3) is 2/5 units.
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⚠️⚠️Please help⚠️⚠️ Pip and Ali share S785 in the ratio Pip:Ali = 4:1.
Work out Pip's share.
==========================================================
Work Shown:
x = Ali's share
4x = Pip's share, because it is four times bigger due to the ratio 4:1
x+4x = 5x = total amount of money = 785
5x = 785
x = 785/5
x = 157 dollars is Ali's share
4x = 4*157 = 628 dollars is Pip's share
Note that 157+628 = 785 to help confirm the answer.
What is 8/15 times -2/3??
Answer:
-16/45
Step-by-step explanation:
8/15*-2/3= -16/45
Answer:
8/15 times -2/3 =-0.35555555555