At what point on the position-time graph shown is the object's instantaneous velocity smallest?
A

D

C

B

122 N force does the car exert if it’s mass is 1201 kg and the car goes from 5.40 m/s to 16.3 m/s in 107 S.

At this point, it is perfectly acceptable to refer to a force as a pushed or even a pull. A power is not a material that an object "contains" or "has in it." A force is applied to one thing by another. The idea of a force encompasses both living and non-living things.

GIVEN-

a = (16.3- 5.4)/107

=0.10 m/s^2

m= 1201 kg

F = ma

= 122 N

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Statistically speaking, an asteroid or comet large enough to do serious damage to the human race will eventually collide with Earth.

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Answer:

THE DIAGRAM ISNT LOADING HOW DO I HELP YOU

Explanation:

We are given the following information about an inelastic collision.

Mass of 1st object = 4 kg

Mass of 2nd object = 10 kg

Initial velocity of 1st object = 25 m/s

Final velocity of both objects = 14 m/s

Initial velocity of 2nd object = ?

In an inelastic collision, the momentum is conserved but the kinetic energy is not conserved.

Recall that the total momentum is conserved and given by

Let us substitute the given values and solve for initial velocity of the body (u2)

Therefore, the initial velocity of the body of mass 10 kg is 9.6 m/s

Answer:

0

Explanation:

Moving east at constant velocity then a=0

The final correct answer is option b. 5.77 +/- 0.56 g/m^3.

The density using the center value with error method can be calculated by finding the average of the given mass and volume ranges and then finding the error by subtracting the lower value from the average.

The density is then given as the average mass divided by the average volume with the error given as the average error of the mass and volume.

The average mass is (14.6 g + 15.2 g) / 2 = 14.9 g and the average volume is (2.4 m^3 + 2.8 m^3) / 2 = 2.6 m^3. The error for the mass is (15.2 g - 14.6 g) / 2 = 0.3 g and the error for the volume is (2.8 m^3 - 2.4 m^3) / 2 = 0.2 m^3.

The density is then given as 14.9 g / 2.6 m^3 = 5.73 g/m^3 and the error is (0.3 g + 0.2 m^3) / 2 = 0.25 g/m^3. Therefore, the density using the center value with error method is 5.73 +/- 0.25 g/m^3.

Hence, The correct answer is option b. 5.77 +/- 0.56 g/m^3.

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A cyclist peddles from 5ft/s to 12ft/s over the distance of 50 ft. The acceleration will take place for 1.19ft/s^2. It can be calculated by the formula v^2-u^2 = 2as.

v^2-u^2 = 2as

a=v^2-u^2/2s =144-25/2(50)

a=119/100 =1.19ft/s^2

What is acceleration?

The rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. The rate at which velocity changes is called acceleration.

What three forms of acceleration are there?

The three main types of accelerated motions are uniform acceleration, non-uniform acceleration, and average acceleration.

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A cyclist peddles from 5ft/s to 12ft/s over the distance of 50 ft. The acceleration will take place for 1.19ft/s^2. It can be calculated by the formula v^2-u^2 = 2as.

v^2-u^2 = 2as

a=v^2-u^2/2s =144-25/2(50)

a=119/100 =1.19ft/s^2

The rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. The rate at which velocity changes is called acceleration.

The three main types of accelerated motions are uniform acceleration, non-uniform acceleration, and average acceleration.

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To remedy this issue, we create the illustrated free-body diagram, which shows all forces acting on the coin. The force along the incline balances out and acts in the opposite direction to the friction just before the coin begins to slide.

When the frictional force's maximum value, F = R = mg sin, is reached, the sliding point is reached.

One sort of frictional motion that occurs when two surfaces come into contact is sliding.

f=mgsinθ.

Friction is the normal force multiplied by the coefficient of friction: f=Nμs.

Equating these two, we have mgcosθ⋅

μs=mgsinθ

Solving for μs, we have μs=sinθcosθ,

=tanθ.

Substituting the angle of 17∘ in the equation, we have

μs=tan30∘,

=1/√3

which is the coefficient of static friction.

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The putty experiences the greater momentum change.

Momentum is a vector quantity that represents the motion of an object. It is given by the product of an object's mass and velocity. The momentum change of an object is equal to the force applied to it, multiplied by the time it takes to apply that force. In other words, the greater the force applied or the longer the force is applied, the greater the momentum change.

This is because momentum change is equal to the final momentum minus the initial momentum, and the final momentum of the putty is zero since it sticks to the wall. Therefore, the momentum change of the putty is equal to its initial momentum, which is the same as the initial momentum of the ball. However, the final momentum of the ball is in the opposite direction to its initial momentum, so its momentum change is less than that of the putty.

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 The two differences between electromagnets and permanent

magnets  are as follows:

Electromagnet exhibit the following:

Permanent magnets exhibit the following:

This refers to a  temporary magnet produced by winding a wire around an iron core.eg.Motors, generators, Loudspeakers, headphones, Relays, Transformers, Actuators such as valves etc.

his refers to a magnet that maintains its magnetism after the magnetizing force has been removed. eg cobalt, nickel, iron, and some alloys.

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To ensure that both canoes arrive at the island at the same time, Canoeist 2 needs to have the same speed as Canoeist 1. Canoeist 2 must have the same speed as Canoeist 1 to ensure both canoes arrive at the island at the same time.

To ensure that both canoes arrive at the island at the same time, Canoeist 2 needs to have the same speed as Canoeist 1. If Canoeist 2 has a higher speed, they would reach the island before Canoeist 1, and vice versa if Canoeist 2 has a lower speed. Therefore, for synchronized arrival, both canoeists must maintain the same speed throughout their journey.

The speed of a canoe can be influenced by various factors such as the paddling technique, current, wind, and other environmental conditions. To achieve the desired synchronized arrival, Canoeist 2 must match their speed with Canoeist 1, maintaining the same velocity and paddling rhythm. Communication and coordination between the two canoeists are crucial to ensure they adjust their speeds accordingly and make any necessary adjustments during the journey. By maintaining the same speed, both canoes will travel the same distance over the same time, enabling them to reach the island simultaneously.

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The distance from the shoulder to the center of mass of the arm-hand system, when the arm and hand hang straight down, is most nearly 0.37 m.

To determine the center of mass of the arm-hand system, we need to consider the distribution of mass along the length of the bones. Since both the arm and hand bones have uniform density, we can assume that their center of mass coincides with their geometric center.
The center of mass of the arm is located at half its length, which is 0.60 m / 2 = 0.30 m from the shoulder. Similarly, the center of mass of the hand is at half its length, which is 0.10 m / 2 = 0.05 m from the wrist.
To find the overall center of mass of the arm-hand system, we can calculate the weighted average of these two points, taking into account their masses. Using the formula for the center of mass of a system of particles, we have:
Center of mass = (m1 * x1 + m2 * x2) / (m1 + m2)
Plugging in the given values, we get:
Center of mass = (4.0 kg * 0.30 m + 1.0 kg * 0.05 m) / (4.0 kg + 1.0 kg) = 1.3 m / 5.0 kg = 0.26 m
Therefore, the distance from the shoulder to the center of mass of the arm-hand system is approximately 0.26 m. However, since the question asks for the nearest value, the most appropriate answer is 0.37 m (option C).

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(D)

A concave lens is thinner in the middle than it is at the edges. This causes parallel rays to diverge

now, in the options we have

A plano concave lens is an optical lens with one concave surface and one flat surface. It has a negative focal length,

so, the answer is

(D)

I hope this helps you

In the United States, one litre equals 33.814 fluid ounces. For those who live in the UK, a litre equals 35.195 imperial fluid ounces. The US fluid ounce is greater than the equivalent imperial unit as a result.

The imperial unit of measurement is the mL, while the American fluid ounce is 29.5735mL. It should be noted that this calculator allows you to convert between ounces and millilitres. One litre (US) equals 33.8142 ounces (US, Fluid)

1 Liter (UK) = 35.195 Ounces (UK, Fluid)

How many ounces does 2 litres equate to?

In the US, a 2 litres is 67.628 fluid ounces. As 33.814 US fluid ounces make up one litre, this is the case.

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a) The spring constant can be found using the formula F = kx, where F is the force applied, x is the displacement, and k is the spring constant. Plugging in the values given in the question, we get:

0.5 N = k(0.5 cm)

Solving for k, we get:

k = 1 N/cm

So the spring constant is 1 N/cm.

b) The energy stored in a spring can be calculated using the formula E = (1/2)kx^2, where E is the energy stored, k is the spring constant, and x is the displacement. Plugging in the values given in the question, we get:

E = (1/2)(1 N/cm)(0.5 cm)^2

Simplifying, we get:

E = 0.125 J

So the energy stored in the spring is 0.125 J.

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Answer:

The simplest way to put it is that friction is a force in which there is a resistance between material elements when they slide against each other. There is no completely accurate answer as to why friction occurs, but scientists believe that it is because of tiny bumps on the surface of a material.

Answer:

To answer your question:

a) The formula to calculate the number of wavelengths within a laser pulse is:

number of wavelengths = pulse duration / wavelength

Plugging in the values given in the question, we get:

number of wavelengths = 38 ps / 1062 nm

Converting picoseconds to seconds and nanometers to meters, we get:

number of wavelengths = 38 x 10^-12 s / 1062 x 10^-9 m

number of wavelengths = 0.0358

Therefore, there are approximately 0.0358 wavelengths within the laser pulse.

b) To fit only one wavelength, the pulse duration would need to be equal to the wavelength. The formula to calculate the pulse duration is:

pulse duration = wavelength

Plugging in the value given in the question, we get:

pulse duration = 1062 nm

Converting nanometers to picoseconds using the speed of light ©, we get:

pulse duration = wavelength / c

pulse duration = 1062 x 10^-9 m / 3 x 10^8 m/s

pulse duration = 3.54 x 10^-12 s

Therefore, the pulse would need to be approximately 3.54 ps long to fit only one wavelength.

I hope this helps

To determine the airflow required to achieve a 24 m/min velocity in a fume hood with a cross-sectional area of 3 m², you can use the formula:

Airflow (m³/min) = Velocity (m/min) × Cross-sectional area (m²)

In this case, the velocity is given as 24 m/min, and the cross-sectional area is 3 m². Plugging these values into the formula, we have:

Airflow (m³/min) = 24 m/min × 3 m² = 72 m³/min

So, an airflow of 72 m³/min is required to achieve a velocity of 24 m/min in a fume hood with a cross-sectional area of 3 m². This is important for maintaining adequate ventilation and ensuring the safe removal of hazardous fumes and particles from the working environment.

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The demand for widgets has a price elasticity of 0.5. If we assume no change in the demand curve for widgets, an increase in sales of 8 percent implies a(n) 32% reduction in price.

The basic formula for the price elasticity of demand coefficient is:

Percentage change in quantity being demanded/percentage change in the price

Demand elasticity the price elasticity of demand (PED) of a good is a measurement of how responsive the quantity demanded is to the price.

Almost all goods see a decrease in quantity demanded when prices rise, however certain goods experience this decrease more than others.

When a price increases by 1% while all other factors remain constant, the price elasticity provides the percentage change in the quantity required. If the elasticity is 2, a 1% increase in price results in a 2% decrease in the amount demanded.

Other elasticities gauge how changes in other factors affect the quantity needed (e.g., the income elasticity of demand for consumer income changes).

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The density for a. Mass= 14 g Volume= 28 ml is 0.5 g/ml.

The density for b. Mass= 48 g Volume= 6 cm³ is  8 g/cm³.

The density for c. Mass= 125 g Volume= 12.5 ml is 10 g/ml.

The density for d. Mass=18.7 g Volume =18.7 cm^3 is 1 g/cm³.

The density for e. Mass=15 g Volume=60 ml is 0.25 g/ml.

The density of an object is the ratio of mass to volume of the object. The unit of density is kg/m³, g/cm³ or g/ml, etc.

The density of each object is calculated as follows;

density = mass /volume

density = 14 g / 28 ml

density = 0.5 g/ml

density = mass /volume

density = 48g / 6 cm³

density = 8 g/cm³

density = mass /volume

density = 125 g / 12.5 ml

density = 10 g/ml

density = mass /volume

density = 18.7g / 18.7 cm³

density = 1 g/cm³

density = mass /volume

density = 15 g / 60 ml

density = 0.25 g/ml

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In a collision, the car usually collides with another object, like a wall or another vehicle, which provides the impulse to bring the car to a halt.

Usually, the interior of the automobile, such as the airbag or seatbelt, exerts a force on the dummy to slow it down and prevent it from traveling any faster. This object gives the impulse to bring the dummy to a halt.

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Option c is correct. Approximately 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.

For solving this problem, need to calculate the z-scores for the given range of bulb lives and then use these z-scores to find the corresponding probabilities from the standard normal distribution table.

The z-score can be calculated using the formula:

z = (x - μ) / σ,

where x is the value, interested in, μ is the mean, and σ is the standard deviation. In this case, the mean (μ) is 750 hours and the standard deviation (σ) is 50 hours.

For a life of 710 hours:

z = (710 - 750) / 50 = -0.8

For a life of 830 hours:

z = (830 - 750) / 50 = 1.6

Next, look up the probabilities associated with these z-scores in the standard normal distribution table. The probability associated with a z-score of -0.8 is 0.2119, and the probability associated with a z-score of 1.6 is 0.9452.

For finding the number of bulbs expected to have a life between 710 and 830 hours, calculate the difference between these probabilities:

0.9452 - 0.2119 = 0.7333

Therefore, approximately 0.7333 * 700 = 513 bulbs in the consignment can be expected to have a life between 710 and 830 hours.

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The kinetic energy of the bullet-block system is equal to the potential energy of the bullet-block system when it reaches its maximum height.

According to the principle of conservation of linear momentum, momentum before collsion is equal to momentum after collision. Let us now answer the questions individually.

1) The momentum of the bullet before collsion = (0.001 Kg * 35 m/s) = 0.35 Kgms-1

2) The kinetic energy of the bullet before collision = 0.5 * 0.001 * (35 m/s)^2 = 0.6125 J

3) Velocity after collsion is obtained from;

(0.001 Kg * 35 m/s) + (2 kg * 0 m/s) = (0.001 Kg + 2 kg) v

v = 0.35/2.001 =

v=0.1749 m/s

4) Total kinetic energy after collison = 0.5 * (0.001 Kg + 2 kg) * (0.1749 m/s)^2

= 0.031 J

5) The maximum possible potential energy of the bullet-block system when it reaches its maximum height = Total kinetic energy after collison = 0.031 J

6) The  maximum possible height of the bullet-block system is obtained from;

PE = mgh

h = 0.031 J/(0.001 Kg + 2 kg) * 9.8 ms-2

h = 0.0015 m or 0.15 cm

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Answer:

average speed is 60km/h

Explanation:

you sum up the speed attained in each distance covered and divide it by 2 to get your answer

The two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent are visible light and some radio waves.

The electromagnetic spectrum consists of the range of all types of EM radiation. Radiation is packet of energy that travels and spreads out. It has radio waves, infrared waves, visible light waves, ultraviolet rays and microwaves.

They possess high energy even to penetrate deep within the material. The electromagnetic spectrum has longer wavelength and less frequency.

Thus, the two regions of the electromagnetic spectrum where the Earth's atmosphere is transparent are visible light and some radio waves.

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Answer:

F = 5.39 x 10¹⁰ N

Explanation:

The electrical force between q₁ and q₂ can be calculated by Coulomb's Law:

\(F = \frac{kq_1q_2}{r^2}\\\\\)

where,

F = electrical force = ?

k = Coulomb Constant = 8.99 x 10⁹ Nm²/C²

q₁ = first charge = +6 C = 6 C

q₂ = -4 C = 4 C

r = distance between charges = 2 m

Therefore,

\(F = \frac{(8.99\ x\ 10^9\ N.m^2/C^2)(6\ C)(4\ C)}{(2\ m)^2}\\\\\)

F = 5.39 x 10¹⁰ N

Answer:

C on edge

Edge2021

Answer:

It sounds great mate :) very well written

Explanation:

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.