The VFR cruising altitudes begin at and above 3,000 feet above the surface and up to and including 18,000 feet MSL.
Visual Flight Rules (VFR) cruising altitudes are set for aircraft operating in uncontrolled airspace. These altitudes are used to maintain safe vertical separation between aircraft and to help avoid collision. The VFR cruising altitudes are established in increments of 500 feet based on the magnetic heading of the aircraft.
For headings of 0-179 degrees, the altitude should be maintained at an odd-numbered altitude plus 500 feet (e.g., 3,500 feet, 5,500 feet, etc.). For headings of 180-359 degrees, the altitude should be maintained at an even-numbered altitude plus 500 feet (e.g., 4,500 feet, 6,500 feet, etc.).
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While discussing PCV valve operation: Technician A says that the PCV valve opening is decreased at part-throttle operation compared to idle operation. Technician B says that the PCV valve opening is decreased at wide-open throttle compared to part throttle. Who is correct?
Answer:
Both are incorrect.
Explanation:
PCV valve opening is dependent on amount of manifold vacuum value. The opening cannot decrease due to part throttle operation. The PCV system is a tampered valve whose opening depend upon intake manifold vacuum. PCV valve is supported by a spring and is initially in a closed position.
Alex loves to build things and wants to study robotics. He needs to get a job over the summer but the only one he can find is at a fast food restaurant. Does taking the job mean that Alex cannot pursue a career in robotics? Explain your answer.
Answer:
He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.
Briefly explain thermal expansion using the potential energy–versus–interatomic spacing curve.
As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.
What are the uses of Thermal Expansion?Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.
It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.
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What application of bioengineering uses principles of electronics and computer science to design products?
The application of electro bioengineering uses principles of nick and computer science to design products is application of electrical engineering principles to biology, medicine, conduct, or health.
What is Bioelectronics?Bioelectronics is the application of electrical engineering principles to biology, medicine, conduct, or health.It advances the fundamental concepts, creates knowledge for the molecular to the organ techniques levels, and develops creative devices or methods for the deterrence, diagnosis, and treatment of disease, for patient rehabilitation, and for improving health.Bio electromagnetics, instrumentation, neural networks, robotics, and detector technologies are some of the disciplines necessary to develop new knowledge and creations in this area.A keystone of this research area is the building of and real-world devices and systems.Onsite facilities for prototyping and testing instrumentation systems, fabricating and measuring the performance of implantable devices, and making robotic prostheses, are readily available.New detectors and sensor arrays are microfabricated in a 2,000 sq ft cleanroom.To learn more about Bioelectronics, refer to:
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Which of the following lists, among other things, the vehicle identification, the customer's concern or complaint, and costs for parts? A. Repair order B. Owner's manual C. Comeback report D. Service manual
Answer:
I think it is D.service manual
Explanation:
Because it is the vehicle identification
the bellman-ford shortest path algorithm works ____O on graphs with negative edge weights, but not negative edge weight cycles O only on graphs without cycles O on any graph O only on graphs with non-negative edge weights
The bellman-ford shortest path algorithm works on graphs with negative edge weights, but not negative edge weight cycles.
Define an algorithm.
A finite sequence of exact instructions is known as an algorithm in mathematics and computer science. Algorithms are frequently used to solve a class of particular problems or to carry out computations. For carrying out calculations and data processing, algorithms are used as specifications.
A method used to solve a problem or carry out a command is known as an algorithm. Algorithms are precise lists of instructions that, in either software or hardware-based routines, carry out predetermined actions step by step.
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What is the meaning of beauty and completeness? In relation to these what are the attributes a Muslim should adopt?
ᴄᴏᴍᴘʟᴇᴛᴇɴᴇꜱꜱ ᴍᴇᴀɴꜱ ᴛʜᴇ ꜱᴛᴀᴛᴇ ᴏꜰ ʙᴇɪɴɢ ᴄᴏᴍᴘʟᴇᴛᴇ ᴀɴᴅ ᴇɴᴛɪʀᴇ; ʜᴀᴠɪɴɢ ᴇᴠᴇʀʏᴛʜɪɴɢ ᴛʜᴀᴛ ɪꜱ ɴᴇᴇᴅᴇᴅ.
ʙᴇᴀᴜᴛʏ ᴍᴇᴀɴꜱ combination of qualities, such as shape, colour, or form, that pleases the aesthetic senses, especially the sight.
Should you prefer rooftop solar panels?
The rooftop solar is a form of solar energy that can be installed on the roof of a home or business. It is cost-effective, environmentally friendly, and provides many benefits to homeowners and businesses.
The rooftop solar has many advantages over other forms of solar energy. One of the main advantages is that it provides 100% clean electricity from renewable sources. In addition, it can be combined with other sources such as wind power and geothermal power for even more benefits.
There are also many uses for rooftop solar panels in homes and businesses. One example is using it to heat water for hot water systems or heating swimming pools.
For me Bluebird Solar Private Limited is the best website in India for rooftop solar panels in India.
the san onofre nuclear power plant was recently decommissioned. when it was operating it produces about 2000 mw
The San Onofre nuclear power station, which was recently shut down, had a production capacity of roughly 2000 MW. Two pressurised water reactors at the facility produced about 2,000 megawatts (MW) of energy when it was in operation.
After more than 40 years of operation, the Southern Californian San Onofre Nuclear Power Plant was shut down in 2013. Two pressurised water reactors at the facility produced about 2,000 megawatts (MW) of energy when it was in operation. The facility supplied a significant portion of the area's electrical needs, supplying residences, businesses, and industries. The facility, however, encountered significant operating difficulties, such as equipment breakdowns and safety issues, which finally resulted in its shutdown. Since then, the area's electrical needs have been satisfied by energy imports, natural gas, renewable energy, and other sources.
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A _____ examination enables visualization of the inside of the bladder and urethra. A. dialysis. B. CT C. MRI D. cystoscope.
A cystoscope is a medical instrument that allows a doctor to see the inside of the bladder and urethra. A flexible or rigid cystoscope are made to measure engineering solutions for your machine lines are inserted into the urethra and advanced into the bladder. The correct answer is D. cystoscope.
A cystoscope is a medical instrument that allows a doctor to see the inside of the bladder and urethra. During a cystoscopy examination, a flexible or rigid cystoscope is inserted into the urethra and advanced into the bladder. This allows the doctor to visualize the lining of the bladder and urethra, as well as take biopsies or remove abnormal tissue if necessary. These are innovative and made to measure engineering solutions for your machine lines.
Cystoscopy is often used to diagnose and monitor conditions such as urinary tract infections, bladder cancer, and urinary incontinence. Dialysis, CT scans, and MRI scans are not used for this purpose. A cystoscope is a thin, flexible tube with a light and a camera on the end, which is inserted through the urethra and into the bladder. This examination allows doctors to diagnose, monitor, and treat conditions affecting the urinary system and machine lines, including the bladder and urethra.
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When groups of molecules within liquid and gases move, it is called
kinetics.
O radiation.
conduction.
convection.
Answer:
convenction is your answer
Answer:
Last one
Explanation:
I took the test
Compare automation and autonomous
Answer:
Automation generally means “a process performed without human assistance”, while autonomy implies “satisfactory performance under significant uncertainties in the environment and the ability to compensate for system failures without external intervention [emphasis mine].”
Explanation:
What is the first step necessary for initiating the visual transduction cascade in rods?.
'Capturing a photon by isomerization and rhodopsin of retinal' is the first step necessary for initiating the visual transduction cascade in rods.
Visual transduction refers to the process in the eye where absorption of light in the 'retina' is translated into electrical signals that then reach the brain. It is correct to state that visual transduction is the photochemical reaction that takes place when light or photon is converted to an electric signal in the retina. The visual pigment in the rods, called rhodopsin, is a membrane protein placed in the outer segments of the rods.
When initiating the visual transduction cascade in rods the first vital step is to capture a photon by isomerization and rhodopsin of retinal'.
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The stability of a system is influenced by all of the __________ in the system, especially those in the feedback loop.
Components in the system in a loop
What is the stability of a system?
If the output of a system is kept under control, it is considered to be stable. It is regarded as unstable if not. A stable system responds to a given bounded input with a bounded output.
The components in the system are:
Many contemporary automated systems incorporate feedback controls. A feedback control system is made up of five fundamental parts: an input, a controlled process, an output, sensor components, and a controller and actuation devices.
All the components play a major role in determining the feedback for the system.Hence to wrap up we can say that all the components are needed to keep the stability in a correct way
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which of these parts serves as the front end cross structure on most vehicles?
Answer:
Rear body panel. Rear bumper cover. Rear rails.
Explanation:
The body parts that serves as front end cross structures of vehicles are Rear body panel , front bumper and rear nails
What is Front end cross structure of automobilles?Front end cross structures refers to several frontal parts or part that are located at the front of automobilles that define it's appearance and it's effective workability. The frontal parts are essential for the effective running of the vehicles and also define the vehicles appearance.
Therefore, The body parts that serves as front end cross structures of vehicles are Rear body panel , front bumper and rear nails.
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Imagine that you are given a large budget and a team of competent sysadmins/devops engineers. Your boss has requested that you develop a plan to deploy the company's latest web application in their on-site datacenter. You have the freedom to recommend servers, extra components (RAM, HDDs, SSDs, network cards, etc), and additional hardware purchases as needed. The primary goal is to design the overall system so that it can provide high levels of uptime even in the presence of minor maintenance (OS reboots, HDD hot-swaps) or major issues (motherboard failures, network card failure, power outages). Write a ½ page report (12pt font, double spaced, 1" margins) that provides your recommendations for creating a robust deployment which can attempt to mitigate the various failures that were mentioned. It's perfectly fine to discuss software architecture choices along with your suggested hardware design considerations.
One can write the report under the title Deploying a Robust Web Application in an On-Site Datacenter by Design.
This report's recommendations for deploying the most recent web application of the business in the local datacenter are intended to guarantee high levels of uptime and reduce potential failures.
We can create a strong system that can resist both routine maintenance and significant problems while sustaining uninterrupted service if we have a sizable budget and a skilled staff of sysadmins and devops engineers.
We can develop a reliable deployment for the company's web application in the on-site datacenter by putting the suggested hardware and software design considerations into practise.
Thus, hardware failures will be less damaging because to redundant servers, RAID storage, network redundancy, and power backup systems.
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while discussing ei service, technician a says the crankshaft sensor may be rotated to adjust the basic ignition timing. technician b says the crankshaft sensor may be moved to adjust the clearance between the pickup coil and reluctor on some ei systems. who is correct?
It is true what technician b said about some ei systems allowing the clearance between the pickup coil and reluctor to be adjusted by moving the crankshaft sensor.
What mechanism is in charge of indicating when the coil is being switched on and off, or most often only on?A device that manages a bank of switches is a relay controller. Logic-controlled magnetic coils are turned on and off using relay controllers.
What occurs when the switching device interrupts the low voltage current flow in the coil primary winding?The magnetic field quickly collapses and a high voltage is induced in the primary winding when the primary current flow is stopped (CEMF Counter electromotive Force).
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A transformer winding contains 900 turns of wire which creates 400 ohms of primary importance how many terms of the same size wire required to create a secondary impedance of 25 ohms
Answer: 255
255 turns are required to create 25 ohms of secondary impedance.
Explanation:
Given that,
Number of turns in primary wire N₁ = 900
impedance on Primary wire Z₁ = 400 ohms
Number of turns in Secondary wire N₂ = ?
impedance on Secondary wire Z₂ = 25 ohms
we know that, the relationship between turn and impedance is
Zp / Zs = ( Np / Ns )²
(Primary impedance / secondary impedance) = Number of turns in primary wire / Number of turns in secondary wire)²
there fore
Z₁ / Z₂ = ( N₁ / N₂ )²
Now we substitute
( 400 / 25 ) = ( 900 / N₂ )²
400 / 25 = 900² / N₂²
we cross multiple to get our N₂
400 × N₂² = 900² × 25
N₂² = ( 900² × 25 ) / 400
N₂² = ( 810000 × 25 ) / 400
N₂² = 20250000 / 400
N₂² = 50625
N₂ = √50625
N₂ = 225
Therefore 255 turns are required to create 25 ohms of secondary impedance.
The top of the tee joint heats up faster than the bottom because?
Answer: the bottom is a harder material than, the actual w33d inside it
Explanation:
A steam power plant with a power output of 230 MW consumes coal at a rate of 60 tons/h. If the heating value of the coal is 30,000 kJ/kg, determine the overall efficiency of this plant.
Answer:
\(\eta =46\%\)
Explanation:
Hello!
In this case, we compute the heat output from coal, given its heating value and the mass flow:
\(Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW\)
Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:
\(\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%\)
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The distance between the centers of the two arms of a U-tube open to the atmosphere is 30 cm, and the U- tube contains 20-cm-high alcohol in both arms. Now the U-tube is rotated about the left arm at 4.2 rad/s. Determine the elevation difference between the fluid surfaces in the two arms.
The U-tube is rotated about the left arm at a speed of 4.2 rad/s. The distance between the centers of the two arms of the U-tube open to the atmosphere is 30 cm, and both arms contain 20-cm-high alcohol.
We need to determine the elevation difference between the fluid surfaces in the two arms.In order to determine the elevation difference between the fluid surfaces in the two arms, we'll use Bernoulli's equation as follows:P₁ + ρgh₁ + 1/2 ρv₁² = P₂ + ρgh₂ + 1/2 ρv₂²Here, P₁ and P₂ are the pressures at points 1 and 2, respectively. ρ is the density of the fluid. h₁ and h₂ are the heights of points 1 and 2, respectively. v₁ and v₂ are the velocities of the fluid at points 1 and 2, respectively. Since both the arms contain alcohol, their density is the same.
Therefore, the density term cancels out from both sides of the equation. P₁ and P₂ are atmospheric pressures, so they are also the same. We can ignore them. The velocity at point 1 is zero because it's at rest. We need to find the difference in elevation, so we can subtract h₁ from h₂.
Therefore, the equation becomes:0 + 0 + 0 = 0 + (h₂ - h₁)g + 1/2 v₂²where g is the acceleration due to gravity, and we've ignored the factor of 1/2 ρv₁² since v₁ is zero. The velocity of the fluid at point 2 can be calculated using the formula:v = ωrwhere ω is the angular velocity, and r is the radius of rotation. Since the U-tube is rotated about the left arm, the radius of rotation is 15 cm.
Therefore, v = 4.2 × 0.15 = 0.63 m/s. Substituting this value in the equation, we get:0 = (h₂ - h₁)9.8 + 1/2 (0.63)²Rearranging the terms, we get:(h₂ - h₁) = (1/2 × 0.63²)/9.8 = 0.020 mTherefore, the elevation difference between the fluid surfaces in the two arms is 0.020 m. Answer: 0.020 m.
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A farmer has 12 hectares of land on which he grows corn, wheat, and soybeans. It costs $4500 per hectare to grow corn, $6000 to grow wheat, and $5000 to grow soybeans. Because of market demand the farmer will grow twice as many hectares of wheat as corn. He has allocated $6,375,000.00 for the cost of growing his crops. How many hectares of each crop should he plant?
The number of hectares of each crop he should plant are; 250 hectares of Corn, 500 hectares of Wheat and 450 hectares of soybeans
How to solve algebra word problem?
He grows corn, wheat and soya beans on the farm of 1200 hectares. Thus;
C + W + S = 12 ----(1)
It costs $45 per hectare to grow corn, $60 to grow wheat, and $50 to grow soybeans. Thus;
45C + 60W + 50S = 63750 -----(2)
He will grow twice as many hectares of wheat as corn. Thus;
W = 2C ------(3)
Put 2C for W in eq 1 and eq 2 to get;
C + 2C + S = 1200
3C + S = 1200 -----(4)
45C + 60(2C) + 50S = 63750
45C + 120C + 50S = 63750
165C + 50S = 63750 ------(5)
Solving eq 4 and 5 simultaneosly gives;
C = 250 and W = 500
Thus; S = 1200 - 3(250)
S = 450
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The readings, tA and tB, of two Celsius thermometers, A and B, agree at ice-point (0 oC) and steam point (100 oC), but elsewhere are related by equation tA = l + m tB + n tB 2 where l, m, and n are constants. When both thermometers are immersed in well-stirred oil bath, A registers 51 oC while B registers 50 oC. Determine the reading on B when A reads 25 oC
Answer:
Explanation:
From the case of well-stirred oil bath:
\(51=l+50m+n(50^{2})\rightarrow 51=l+50m+2500n\)
At the ice point, both of the thermometers show the same scale:
\(0 = l + m(0) + n(0^{2}) \rightarrow l = 0\)
At the steam point, again, both of the thermometers show the same scale:
\(100 = 0 + m(100)+n(100^{2}) \rightarrow 100 = 100m + 10000n \rightarrow 1 = m + 100n\)
By eliminating those equations, we find:
\(51=50(1-100n)+2500n \rightarrow 51=50-500n+2500n \rightarrow 1 = 2000n\)
so we can obtain that: \(n=\frac{1}{2000}=0.0005\) and \(m=1-100(0.0005)=1-0.05=0.95\)
Now, we have the complete description of the relation between A and B scale as: \(t_{A}=0.95t_{B}+0.0005t_{B}^{2}\)
So, for \(t_{A}=25^{0}C\):
\(25 = 0.95t_{B}+0.0005t_{B}^{2} \rightarrow 0.0005t_{B}^{2}+0.95t_{B}-25=0\)
\(t_{B}_{1,2}=\frac{-0.95\pm\sqrt{0.95^{2}-4(0.0005)(-25)}}{2(0.0005)}\approx-950\pm975\)
\(t_{B}_{1}=25^{0}C \vee t_{B}_{2}=-1925^{0}C\)
implement the function calcWordFrequencies() that uses a single prompt to read a list of words (separated by spaces). Then, the function outputs those words and their frequencies to the console.
Ex: If the prompt input is:
hey hi Mark hi mark
the console output is:
hey 1
hi 2
Mark 1
hi 2
mark 1
Please implement this using Javascript and associative arrays
This implementation converts all words to lowercase for case-insensitive counting.
Using Javascript and associative arrays, the following code can be used to implement the function calcWordFrequencies():
// Read the user input
var input = prompt("Please enter a list of words, separated by spaces: ");
// Create an associative array to store the words and frequencies
var words = {};
// Split the user input string into words
var wordsArray = input.split(" ");
// Iterate through the words and store the frequencies in the associative array
wordsArray.forEach(function(word) {
// Check if the word is already stored in the array
if (words.hasOwnProperty(word)) {
// Increase the frequency of the word
words[word]++;
} else {
// Set the frequency of the word to 1
words[word] = 1;
}
});
// Output the words and their frequencies to the console
for (var word in words) {
console.log(word + " " + words[word]);
}
This function first prompts the user for a list of words, then splits the input string into an array of words. It then creates an empty object to store the word frequencies, and loops through the words array to update the frequencies object. For each word, it checks if the word is already a key in the frequencies object, and either increments its count or initializes its count to 1. Finally, it loops through the frequencies object and outputs the word-frequency pairs to the console using console.log().
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What will be the future of cyber security?
. consider the following statements: a.) liquid moves faster in a turbulent flow than in a laminar flow; b.) turbulent flow produces more noise than laminar flow; c.) laminar flow does not change in time (it is a quasi-steady state), while turbulent flow is unsteady; d.) streamlines of a laminar flow stick together, but diverge in a turbulent case.
Real-world fluid flows can exhibit a combination of laminar and turbulent characteristics, depending on factors such as flow velocity, fluid properties, and the presence of obstacles or disturbances.
a) Liquid moves faster in a turbulent flow than in a laminar flow.
This statement is generally true. In a turbulent flow, the fluid moves in a chaotic manner, characterized by eddies and swirling motion. This turbulent motion enhances the mixing and transport of fluid particles, which can result in higher overall flow velocities compared to laminar flow, where fluid moves smoothly in parallel layers.
b) Turbulent flow produces more noise than laminar flow.
This statement is generally true. Turbulent flow is associated with fluctuating velocities and pressure fluctuations, which can generate noise. The irregular motion and collisions of fluid particles in turbulent flow create vibrations and sound waves, resulting in higher noise levels compared to the smooth, ordered flow of laminar flow.
c) Laminar flow does not change in time (it is a quasi-steady state), while turbulent flow is unsteady.
This statement is generally true. Laminar flow is characterized by smooth and ordered flow with parallel streamlines. It remains relatively constant over time, assuming steady conditions. On the other hand, turbulent flow is characterized by irregular and unsteady motion with constantly changing velocities and pressure fluctuations. Turbulent flow exhibits fluctuations in time and space due to the presence of eddies and vortices.
d) Streamlines of a laminar flow stick together, but diverge in a turbulent case.
This statement is generally true. In laminar flow function, adjacent fluid particles move smoothly and in parallel along the streamlines without significant mixing or cross-stream diffusion. As a result, the streamlines tend to remain close together and maintain their initial separation. In turbulent flow, however, the chaotic motion and mixing of fluid particles cause streamlines to diverge and become highly convoluted, leading to intermingling and spreading of fluid particles. Real-world fluid flows can exhibit a combination of laminar and turbulent characteristics, depending on factors such as flow velocity, fluid properties, and the presence of obstacles or disturbances.
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Match the term to the correct definition. bus full mesh ring star
Bus: linear arrangement Round in the form of a ring Systems are arranged in the form of a star using wire in this topology. Mesh: A non-synchronized arrangement of systems.
What is star bus topology?This topology is referred to as a star bus topology since it incorporates different star topologies into a single bus. A bus or star topology is comparable to the widely used tree topology in networks.
What distinguishes mesh topology from star star?The most popular topology in home and office networks is the star topology because it is so simple to deploy, operate, and troubleshoot. A redundant network of connections between nodes forms a mesh topology.
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I really need help on this!
Which of the following is a term for a comparison between product metrics and values to industry standards and competitions metrics and values?
A: ideal value
B: competitive analysis
C: benchmark
D: marginally accepted value
Is a diesel truck less expensive to drive than a gas truck?
Answer:
Typically, diesel trucks cost more than those with gas engines, especially when you're first buying them, as diesel is usually featured as an add-on for gas-powered cars. Diesel add-ons can cost over $5,000 for midsize trucks and around $10,000 for heavy-duty trucks.
Explanation:
Make me brain pls
External crack of length of 3.0 mm was detected on the surface of the shaft of wind turbine made from 4340 steel. The diameter of the shaft of wind turbine is equal to 32 mm. Assume the shaft is subjected to a maximum load of 50,000 N during operation and the radius of the curvature of the crack is 3 x 10-2 mm. Determine the Fracture toughness KC of the shaft Express your answer in to four significant figures. Do not include the units.
Answer:
The correct answer is "\(K_c=6.0369 \ MPa\sqrt{m}\)".
Explanation:
Given:
Maximum load,
P = 50,000 N
Crack length,
a = 3mm
or,
= 3×10⁻³ m
Diameter,
d = 32 mm
As we know,
⇒ Maximum stress, \(\sigma=\frac{P}{A}\)
\(=\frac{50000}{(\frac{\pi}{4}\times 32^2)}\)
\(=62.20 \ N/mm^2\)
Now,
⇒ Fracture tougness, \(K_c=Y \sigma\sqrt{\pi a}\)
On substituting the values, we get
\(=1\times 62.20\times \sqrt{3.14\times 3\times 10^{-3}}\)
\(=6.0369 \ MPa\sqrt{m}\)