At the aquarium, posters of sharks cost $8 and posters of jellyfish cost $3. Mr. Shen spent $61 to buy 12 posters. How many of each type of poster did Mr. Shen buy?

Answer:

I would use it for a house, car, and own rhe restaraunt

Answer:

House+Car+restaurant

Step-by-step explanation:

Imagine being such an addict that you spend it on a video game tho

ez points :)

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Answer:

Hey mate,here is your answer. Hope it helps you.

Step-by-step explanation:

The answer is c- 8 x 4. As there are 8 groups of 4 the easiest way to calculate is by multiplying them both. Repeated addition is known as multiplication.

Answer:

There is no question showing up so I dont know how to help u

Step-by-step explanation:

Answer:

(-9,-3)

Step-by-step explanation:

When you are talking about in relation you do what I do.

Answer:

1. Ethan

2. 2.5 tons

3. 72 in

4. 5.7 mi

Step-by-step explanation:

1. Convert to pints by multiplying gallons by 4 to get quarts and quarts by 4 to get pints then compare.

2. Divide pounds by 2000 to get tons

3. Multiply by 12

4. Divide by 5280 to turn feet into miles

Answer:

Step-by-step explanation:

Sol'n,

Here,

The length of all sides of sq= height = h

Height of triangle=h

Base length of triangle=b

Now, We know that,

The entire figure is a trapezium,

so, Area of Trap.= 1/2 * h(length of diagonal one + length of diagonal 2)

or, 80 = 1/2 * h* {h +(b+h)}[ since here, the length of second diagonal is sum of the base and length of one side of sq]

or, 160 = h (2h+b)

2h^2 + hb - 160 = 0....(I)

Hence, I is the required eqn....

The Equation for Area of figure is area of Figure, h² + 1/2(h)(b) = 80

The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.

Given:

We have the figure consist of one square and one right triangle.

Now, Area of Figure,

= Area of square + area of Triangle

\(\dfrac{= \text{length} \times \text{width +}}{\times \text{base} \times \text{height}} =\)

\(= 16 \times 12 + \dfrac{1}{2} \times 10 \times 20\)

\(= 192+ 100\)

\(=292 \ \text{unit}^2\)

and, if the square with height, h, units and a right triangle with height, h units, and a base length, b units.

Then, area of Figure = h² + 1/2(h)(b) = 80 square units.

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The value of x that makes this equation (X-2)/2= (X+4)/4  to be true is 8.

An equation ca be described as the mathematical terms which can contains different digits as well we a as alphabet and it can simplified so that a particular expression or term can be found, in the given equation we were told to find the value of x by simplify the equation which is done below.

(X-2)/2= (X+4)/4

Then if we cross multiply we will have

(4x - 8) =(2x+8)

then we can simplify further and collect the like terms which is

2x=16

x=8

There, the correct option is B

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Answer:

She used 9-10 pages in total.

Step-by-step explanation: Once she gave away 16 cards, she was left with 88. If each page fills up with 9 cards it would take her around 9 pages to put 81 cards, so she would have a remainder of 7 cards so she would end up needing 1 more page that will have 7 cards and not 9.

Answer:

Step-by-step explanation:

\(2.4\times\:10\\\)

Multiply without the decimal points then put the decimal point in the answer

\(24\times\:10=240\\\)

2.4 has 1 decimal place

10 has 0 decimal places

Therefore, the answer has 1 decimal place

\(\\=24.0\\\\=24\)

The value product of 2.4 × 10 will be 24.

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

The expression is,

⇒ 2.4 × 10

Now,

Since, The expression is,

⇒ 2.4 × 10

After multiply, we get;

⇒ 2.4 × 10 = 24

Thus, The value = 24

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Answer:

12

Step-by-step explanation:

This is a special triangle with angle measure 45-45-90

The side lengths for this special right triangle is as follows:

The side length that sees angle measure 90 is represented by a\(\sqrt{2}\)

The side lengths that see angle measures 45 is represented by a

We can see from the image hypotenuse (the side that sees angle 90)

is given as 12\(\sqrt{2}\) that means a = 12

So the missing side lengths (both see angle measure 45) = 12

Answer:

is finding the square root

The inverse operation of squaring a number is finding the square root of that number. The square root of a number "x" is the value that, when squared, gives the original number.

When a number is squared, it is multiplied by itself. For example, squaring the number 4 gives 4^2 = 16.

The inverse operation undoes the effect of squaring and returns you to the original number. In this case, finding the square root of a number is the inverse operation of squaring.

The square root of a number "x" is a value that, when squared, gives the original number. It is denoted by the symbol √x.

For example, if you have the number 25 and you want to find its square root, you calculate:

√25 = 5

5 is the square root of 25 because when you square 5 (5^2), you get 25.

The inverse operation of squaring a number is finding the square root of that number. The square root of a number "x" is the value that, when squared, gives the original number. The concept of square root and squaring are inverse operations that are used in various mathematical calculations and problem-solving.

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Answer:

Step-by-step explanation:

Im gonna guess C, not sure. good luck tho

The reflection image is as follows,

To solve the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0, we can use algebraic methods and the unit circle to determine the values of x that satisfy the equation.

1. Start by rearranging the equation to a quadratic form: \(6sin^2(x)\) + 6sin(x) + 1 = 0.

2. Notice that the equation resembles a quadratic equation in terms of sin(x). Let's substitute sin(x) with a variable, such as u: \(6u^2\) + 6u + 1 = 0.

3. Solve this quadratic equation for u. You can use the quadratic formula or factorization methods to find the values of u. The solutions are u = (-3 ± √3) / 6.

4. Since sin(x) = u, substitute back the values of u into sin(x) to obtain the values for sin(x): sin(x) = (-3 ± √3) / 6.

5. To find the values of x, we can use the inverse sine function. Take the inverse sine of both sides: x = arcsin[(-3 ± √3) / 6].

6. The arcsin function has a range of [-π/2, π/2], so the values of x lie within that range. Use a calculator to find the approximate values of x based on the values obtained in step 5.

7. Plot the obtained x-values on the graph to show the solutions of the equation \(6sin^2(x)\) + 6sin(x) + 1 = 0. The graph will illustrate the points where the curve intersects the x-axis.

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Answer:

the answer is 14.13 in³ for the volume

The correct answer is D. f(x) = 11x - 4 and g(x) = (x + 4)/11

To determine which pair of functions are inverses of each other, we need to check if the composition of the functions results in the identity function, which is f(g(x)) = x and g(f(x)) = x.

Let's test each option:

Option A:

f(x) = x/2 + 15

g(x) = 12x - 15

f(g(x)) = (12x - 15)/2 + 15 = 6x - 7.5 + 15 = 6x + 7.5 ≠ x

g(f(x)) = 12(x/2 + 15) - 15 = 6x + 180 - 15 = 6x + 165 ≠ x

Option B:

f(x) = ∛3x

g(x) = (x/3)^3 = x^3/27

f(g(x)) = ∛3(x^3/27) = ∛(x^3/9) = x/∛9 ≠ x

g(f(x)) = (∛3x/3)^3 = (x/3)^3 = x^3/27 = x/27 ≠ x

Option C:

f(x) = 3/x - 10

g(x) = (x + 10)/3

f(g(x)) = 3/((x + 10)/3) - 10 = 9/(x + 10) - 10 = 9/(x + 10) - 10(x + 10)/(x + 10) = (9 - 10(x + 10))/(x + 10) ≠ x

g(f(x)) = (3/x - 10 + 10)/3 = 3/x ≠ x

Option D:

f(x) = 11x - 4

g(x) = (x + 4)/11

f(g(x)) = 11((x + 4)/11) - 4 = x + 4 - 4 = x ≠ x

g(f(x)) = ((11x - 4) + 4)/11 = 11x/11 = x

Based on the calculations, only Option D, where f(x) = 11x - 4 and g(x) = (x + 4)/11, satisfies the condition for being inverses of each other. Therefore, the correct answer is:

D. f(x) = 11x - 4 and g(x) = (x + 4)/11

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Answer:

1.5 hours

Step-by-step explanation:

Calculate speed using

time = \(\frac{distance}{speed}\) = \(\frac{21}{14}\) = 1.5 hours or 1 hour 30 mins

Answer:

Based on the information given, Sarah is 3 inches taller than Mike, and Emma is 1 inch taller than Sarah.

This means that if we arrange them in order of height, it would be Mike, Sarah, and Emma.

Since Mike is the shortest, the logical conclusion is that option B, Mike, is the shortest.

Step-by-step explanation:

Given:

A figure of a circle and two secants on the circle from the outside of the circle.

To find:

The measure of angle KLM.

Solution:

According to the intersecting secant theorem, if two secant of a circle intersect each other outside the circle, then the angle formed on the intersection is half of the difference between the intercepted arcs.

Using intersecting secant theorem, we get

\(\angle KLM=\dfrac{1}{2}(Arc(JON)-Arc(KM))\)

\((3x-4)=\dfrac{1}{2}(271-(x+6))\)

\((3x-4)=\dfrac{1}{2}(271-x-6)\)

Multiply both sides by 2.

\(6x-8=265-x\)

Isolate the variable x.

\(6x+x=265+8\)

\(7x=273\)

Divide both sides by 7.

\(x=\dfrac{273}{7}\)

\(x=39\)

Now,

\(\angle KLM=(3x-4)^\circ\)

\(\angle KLM=(3(39)-4)^\circ\)

\(\angle KLM=(117-4)^\circ\)

\(\angle KLM=113^\circ\)

Therefore, the measure of angle KLM is 113 degrees.

Answer:

\(\displaystyle \large{y=\frac{18+4h}{5} }\\\)

Alternatively, you can use \(\displaystyle \large{y=\frac{18}{5}+\frac{4h}{5} }\\\) as an answer.

Step-by-step explanation:

To make y as the subject of equation, we have to find a way to isolate y-variable.

First, add 4h both sides of equation which we obtain:

\(\displaystyle \large{5y-4h+4h=18+4h} \\\displaystyle \large{5y=18+4h}\)

Next, we divide both sides by 5 so we can finally have y-isolated equation and thus it becomes the new subject of equation.

\(\displaystyle \large{\frac{5y}{5} =\frac{18+4h}{5} }\\\displaystyle \large{y=\frac{18+4h}{5} }\)

Thus the answer is y = (18+4h)/5

Alternatively for solution, you can separate the fraction which we obtain a valid alternative solution.

\(\displaystyle \large{y =\frac{18}{5} +\frac{4h}{5} }\\\)

Either one of these solutions work.

_______________

Let me know in the comment if you have any questions.

We can start by finding the time it takes for Gill to travel the first 27km:

Time taken = Distance / Speed = 27km / 96 km/h = 0.28125 hours

Next, we need to account for the 3-minute stop in Lens. Since 1 hour has 60 minutes, 3 minutes is 3/60 = 0.05 hours.

The total time taken for the journey from the start to Lens is:

0.28125 hours + 0.05 hours = 0.33125 hours

Now we need to find the time it takes for Gill to travel the final 29km:

Time taken = Distance / Speed = 29km / 96 km/h = 0.30208 hours

Adding the time taken for the first part of the journey to the time taken for the second part gives the total time taken for the journey:

0.33125 hours + 0.30208 hours = 0.63333 hours

Finally, we can add this time to the departure time of 09:00 to find the arrival time:

09:00 + 0.63333 hours = 09:38 (rounded to the nearest minute)

ANSWER IS B

Okay, here are the steps to solve this problem:

1) Gill leaves Lille by train at 09:00.

2) The train travels 27km at 96km/h. 27km / 96km/h = 0.2833h = 17min

3) So the train will arrive at Lens at 09:17 (09:00 + 17min)

4) The train stops at Lens for 3 minutes. 3min = 0.05h

5) So the train leaves Lens at 09:22 (09:17 + 3min = 0.05h)

6) The train then travels 29km at 96km/h. 29km / 96km/h = 0.3021h = 18min

7) So the train will arrive at Lillers at 09:40 (09:22 + 18min)

Therefore, the answer is C 09:40

Let me know if you have any other questions!

Using arithmetic operations it is found that -

It took Castenea 10 hours and 36 minutes to finish the first book Eragon.

The number of pages in Castenea's second book Eldest is 707.

What is arithmetic operation?

A subject of mathematics known as arithmetic operations deals with the study and use of numbers in all other branches of mathematics. Basic operations including addition, subtraction, multiplication, and division are included.

The number of pages in Eragon is = 530 pages

The rate for Castanea's reading is = 1 page/72 seconds

The time taken by Castanea to finish the first book is -

Time Taken = Number of Pages × Time taken to read 1 page

Use the arithmetic operation of multiplication.

Substitute the values in the equation -

Time Taken = 530 × 72

Time Taken = 38160 seconds

To convert seconds into minutes use the arithmetic operation of division.

38160 / 60 = 636 minutes

To convert minutes into hour use the arithmetic operation of division.

636 / 60 = 10.6 hour

Therefore, it took Castanea 10 hours 36 minutes to finish the first book.

The time took by Castanea to finish the second book = 14 hours 8 minutes and 24 seconds

To convert hours into minutes use the arithmetic operation of multiplication.

14 × 60 = 840 minutes

To convert minutes into seconds use the arithmetic operation of multiplication.

848 × 60 = 50880 seconds

Use the arithmetic operation of addition to get the total seconds -

50880 + 24 = 50904 seconds

The rate for Castanea's reading is = 1 page/72 seconds

The number of pages in Castanea's second book is -

Number of Pages = Time Taken in total/Time taken to read 1 page

Use the arithmetic operation of division.

Substitute the values in the equation -

Number of Pages = 50904/72

Number of Pages = 707

Therefore, there were seven pages in the second book.

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The correct statements are: B. β^0 and β^1 are biased estimators of β0 and β1, respectively. D. The sampling distribution of β^0 and β^1 is well approximated by the bivariate normal distribution if the sample is sufficiently large.

A. The sampling distribution of β^0 and β^1 is not always well approximated by the bivariate normal distribution. It depends on the specific conditions and assumptions of the linear regression model.

B. β^0 and β^1 are biased estimators because, on average, they may not equal the true population parameters β0 and β1. However, in linear regression, they are consistent estimators, meaning that as the sample size increases, their bias tends to zero.

C. This statement is incorrect. β^0 and β^1 are biased estimators, as mentioned in statement B.

D. The sampling distribution of β^0 and β^1 can be well approximated by the bivariate normal distribution if the sample size is sufficiently large. This is a result of the Central Limit Theorem, which states that the sampling distribution approaches a normal distribution as the sample size increases.

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The area of the octagon ABCDEFGH is 119 cm².

The figure is attached below for reference.

AP = 4 cm

HC = CD = 11 cm

Area of trapezium ABCH = Area of trapezium GDEF

Now, Area of a trapezium = \(\frac{1}{2} (a+b)h\)

Area of trapezium ABCH = Area of trapezium GDEF  = \(\frac{1}{2} (5+11)4 = 32\) cm².

So, Area of trapezium GDEF = 32 cm².

Area of rectangle MCDG = l x b = 11 x 5 = 55 cm²

Area of the Octagon ABCDEFGH = Area of the two trapeziums + Area of the rectangle

= (2 x 32) + 55 = 119 cm².

Hence, the area of the octagon ABCDEFGH is 119 cm².

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The value of the measure of Arc CDE is,

⇒ Arc CDE = 128 degree

Since, An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.

Here, A circle is shown in figure.

And, By circle we have;

The measure of Arc CDE is,

⇒ Arc CDE = 128 degree

Thus, The value of the measure of Arc CDE is,

⇒ Arc CDE = 128 degree

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Answer:

b

Step-by-step explanation:

end of life

edge 2020

Answer:

b

Step-by-step explanation:

Answer:

Fact

Step-by-step explanation:

Answer:

16

Step-by-step explanation:

6/2=3 and 48/3=16

The amount of storage required to represent a simple graph with n vertices and m edges can vary depending on the chosen representation. Here's the storage requirement for each representation:

a) Adjacency lists:

In an adjacency list representation, we typically use an array of size n to store the vertices, and for each vertex, we maintain a linked list or an array to store its adjacent vertices. The space complexity of this representation is O(n + m), where n is the number of vertices and m is the number of edges.

Each vertex requires constant space, and each edge is represented by a link or entry in the adjacency list.

b) Adjacency matrix:

In an adjacency matrix representation, we use a 2D matrix of size n x n to represent the graph. Each entry (i, j) in the matrix represents whether there is an edge between vertices i and j. The space complexity of this representation is O(n^2), as we need to store n^2 entries for the complete matrix. However, if the graph is sparse (few edges compared to vertices), the space complexity can be reduced to O(n + m) by only storing the entries corresponding to the existing edges.

c) Incidence matrix:

In an incidence matrix representation, we use a 2D matrix of size n x m, where n is the number of vertices and m is the number of edges. Each entry (i, j) in the matrix represents whether vertex i is incident to edge j. The space complexity of this representation is O(n * m), as we need to store n * m entries for the matrix.

Similar to the adjacency matrix, if the graph is sparse, the space complexity can be reduced to O(n + m) by storing only the entries corresponding to the existing edges.

In summary:

a) Adjacency lists: O(n + m)

b) Adjacency matrix: O(n^2) or O(n + m) for sparse graphs

c) Incidence matrix: O(n * m) or O(n + m) for sparse graphs

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