At a certain bakery, the price of each doughnut is $1.50. Let the random variable D represent the number of doughnuts a typical customer purchases each day. The expected value and variance of the probability distribution of D are 2.6 doughnuts and 3.6 (doughnuts)2 , respectively. Let the random variable P represent the price of the doughnuts that a typical customer purchases each day. Which of the following is the standard deviation, in dollars, of the probability distribution of P ? 1.5(3.6) 1.5(3.6) A 1.53.6−−−√ 1.53.6 B 1.5(3.6)−−−−−−√ 1.5(3.6) C 1.5(2.6) 1.5(2.6) D 1.52.6−−−√ 1.52.6 E

Answers

Answer 1

Answer: C ( square root of 1.5 x 3.6)

Step-by-step explanation:

The price for the variance is 3.6 times 1.5. Standard deviation is the square root of variance, so the answer is the square root of 1.5 x 3.6.

Answer 2

The standard deviation expression of the distribution P is √(1.50 × 3.6)

Given the Parameters :

Expected value = 2.6Variance = 3.6 Price per doughnut = $1.50

The price for the variance of the distribution can be written as :

Price per doughnut × Variance

Variance = $1.50 × 3.6

The standard deviation of the distribution D is related to the variance by the formular :

Standard deviation = √variance

Standard deviation = √(1.50 × 3.6)

Therefore, the standard deviation in $ of P will be √(1.50 × 3.6)

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Related Questions

What number is negative and is the absolute value of 16

Answers

Answer: -16

Step-by-step explanation:

The distance away from zero is 16 and -16 is negative + do u do rsm

Find a, b & c value

Find a, b & c value

Answers

The value of a, b and c are found as 6, 10 and 2 respectively.

Explain about the exponents of the number?

Values for exponents, commonly referred to as powers, indicate how many often to multiply a quantity by itself.

For instance, 43 instructs you to divide by three the number four. The base of a power is the integer being increased, and the exponent or power is the superscript number it above base.A number's exponent shows the amount of times the number has been multiplied by itself.

The given expression is;

\(4x^{8} y^{c} = \frac{24x^{b}y^{-3} }{ax^{2} y^{-5} }\)

Solving expression using the law of indices.

\(x^{8} y^{c} = \frac{6x^{b-2}y^{-3+5} }{a}\)

\(ax^{8} y^{c} = {6x^{b-2}y^{2} }\)

Comparing powers of both sides:

a = 6

8 = b-2 : b = 10

c = 2

Thus, the value of  a, b and c are found as 6, 10 and 2 respectively.

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what is the solution for 15= 1/2 + 3/2x + 10

Answers

Answer:

x = 3

Step-by-step explanation:

There are 250 people at Acorn Lake Sports Camp, and 25 of them are counselors. What percent of the people at Acorn Lake are counselors?

Answers

out of the 250, 10% of them are counselors for the camp

Which expression is equivalent to (3.1x−2.4y+1.9)+(2.2x−1.4y−3.4)?

Answers

Answer:

5.3x - 3.8y - 1.5

Answer:

(3.1x+2.2x)+(−2.4y+1.4y)+(1.9+3.4)

Step-by-step explanation:

I just did this problem :>

Chay is buying mulch for the zoo's summer flower beds. She has enough in her budget to purchase 55 bags of mulch. If there are 20 flower beds, how many bags of mulch can be used in each flower bed?

Answers

Chay can use 3 bags of mulch per flower bed.

Chay is buying mulch for the zoo's summer flower beds. She has enough in her budget to purchase 55 bags of mulch. If there are 20 flower beds, how many bags of mulch can be used in each flower bed?The number of bags of mulch that can be used in each flower bed can be found by dividing the total number of bags of mulch by the number of flower beds, as given by the problem.Let X be the number of bags of mulch used in each flower bed. Then, the following equation can be written:Total number of bags of mulch = X × number of flower beds (20)Or, 55 = 20XDividing both sides of the equation by 20, we get: X = 55/20X = 2.75.Therefore, Chay can use 2.75 bags of mulch in each flower bed. However, since we cannot have a fraction of a bag of mulch, she would have to round up to 3 bags of mulch per flower bed to ensure each flower bed has enough mulch.

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4.
The distance around the school track is 0.25 mile. It takes Maribeth 5.1 minutes to run 2 laps around the school track. At that pace, how long does it take Marib
A 2.55 minutes
B 7.65 minutes
C 10.2 minutes
20.4 minutes

Answers

Answer:

the distance around the school track would be x

Step-by-step explanation:

you would have to divide 0.25 by 5.1 is 20.4

A science club is made up of 18 girls and 12 boys. Four girls and 5 boys are also in the Spanish club. What percent of the science club is in the Spanish club?

Answers

Answer:

The answer is 30%

Step-by-step explanation:

I believe this should work for an explanation :) Have fun!

A science club is made up of 18 girls and 12 boys. Four girls and 5 boys are also in the Spanish club.

By using a 3-simple rule, we will see that 30% of the science club is on the Spanish club.

How to find the percentage of science club students is in the Spanish club?

First, we know that there are 18 girls and 12 boys in the science club, then there are 12 + 18 = 30 students on the science club, this will be the 100%.

30 = 100%.

And there are 4 girls and 5 boys in the Spanish club, then there are 4 + 5 = 9 students on the Spanish club, let's say that this number represents a percentage X.

9 = X

Then we have the equations:

30 = 100%

9 = X

To find the value of X, we can take the quotient of these two equations:

9/30 = X/100%

Solving for X, we get:

(9/30)*100% = X = 30%

Then we can conclude that 30% of the science club is in the Spanish club.

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How to find right triangle with Pythagorean theorem

Answers

Answer:

By using the formula of;

A² + B² = C²

Where A and B could be either of the 2 legs and C always have to be the hypotenuse of the right triangle. Hypotenuse is the longest leg of the triangle is the leg that's opposite to the right angle of the right triangle.

Hope this helps! I have attached a diagram for u to help you understand:

How to find right triangle with Pythagorean theorem

Consider parallelogram QRST below. Use the information given in the figure to find m

Consider parallelogram QRST below. Use the information given in the figure to find m

Answers

The missing values are

<UTQ = 41 degree

x= 1

<UQT = 47 degree

We have a parallelogram QRST.

We know that the opposite sides of the parallelogram is equal and parallel then

QR || ST

QT || SR

Then, <SRT = <RTQ (<UTQ) (alternate Interior Angle)

<UTQ = 41

Similarly, <UQT = <SRQ = 47

Now, RU = UT

2x + 1= 3

2x = 2

x= 1

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Heeeelp please, Can be zero or not?
with all steps and explanay.​

Heeeelp please, Can be zero or not? with all steps and explanay.

Answers

The value of integral is 3.

Let's evaluate the integral over the positive half of the interval:

∫[0 to π] (cos(x) / √(4 + 3sin(x))) dx

Let u = 4 + 3sin(x), then du = 3cos(x) dx.

Substituting these expressions into the integral, we have:

∫[0 to π] (cos(x) / sqrt(4 + 3sin(x))) dx = ∫[0 to π] (1 / (3√u)) du

Using the power rule of integration, the integral becomes:

∫[0 to π] (1 / (3√u)) du = (2/3) . 2√u ∣[0 to π]

Evaluating the definite integral at the limits of integration:

(2/3)2√u ∣[0 to π] = (2/3) 2(√(4 + 3sin(π)) - √(4 + 3sin(0)))

(2/3) x 2(√(4) - √(4)) = (2/3) x 2(2 - 2) = (2/3) x 2(0) = 0

So, the value of integral is

= 3-0

= 3

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Answer:

\(3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x\approx 0.806\; \sf (3\;d.p.)\)

Step-by-step explanation:

First, compute the indefinite integral:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x\)

To evaluate the indefinite integral, use the method of substitution.

\(\textsf{Let} \;\;u = 4 + 3 \sin x\)

Find du/dx and rewrite it so that dx is on its own:

\(\dfrac{\text{d}u}{\text{d}x}=3 \cos x \implies \text{d}x=\dfrac{1}{3 \cos x}\; \text{d}u\)

Rewrite the original integral in terms of u and du, and evaluate:

\(\begin{aligned}\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\int \dfrac{\cos x}{\sqrt{u}}\cdot \dfrac{1}{3 \cos x}\; \text{d}u\\\\&=\int \dfrac{1}{3\sqrt{u}}\; \text{d}u\\\\&=\int\dfrac{1}{3}u^{-\frac{1}{2}}\; \text{d}u\\\\&=\dfrac{1}{-\frac{1}{2}+1} \cdot \dfrac{1}{3}u^{-\frac{1}{2}+1}+C\\\\&=\dfrac{2}{3}\sqrt{u}+C\end{aligned}\)

Substitute back u = 4 + 3 sin x:

                            \(= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

Therefore:

\(\displaystyle \int \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x= \dfrac{2}{3}\sqrt{4+3\sin x}+C\)

To evaluate the definite integral, we must first determine any intervals within the given interval -π ≤ x ≤ π where the curve lies below the x-axis. This is because when we integrate a function that lies below the x-axis, it will give a negative area value.

Find the x-intercepts by setting the function to zero and solving for x in the given interval -π ≤ x ≤ π.

\(\begin{aligned}\dfrac{\cos x}{\sqrt{4+3\sin x}}&=0\\\\\cos x&=0\\\\x&=\arccos0\\\\\implies x&=-\dfrac{\pi }{2}, \dfrac{\pi }{2}\end{aligned}\)

Therefore, the curve of the function is:

Below the x-axis between -π and -π/2.Above the x-axis between -π/2 and π/2.Below the x-axis between π/2 and π.

So to calculate the total area, we need to calculate the positive and negative areas separately and then add them together, remembering that if you integrate a function to find an area that lies below the x-axis, it will give a negative value.

Integrate the function between -π and -π/2.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_1=-\displaystyle \int^{-\frac{\pi}{2}}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=- \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{-\frac{\pi}{2}}_{-\pi}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(-\pi\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (-1)}+\dfrac{2}{3}\sqrt{4+3 (0)}\\\\&=-\dfrac{2}{3}+\dfrac{4}{3}\\\\&=\dfrac{2}{3}\end{aligned}\)

Integrate the function between -π/2 and π/2:

\(\begin{aligned}A_2=\displaystyle \int^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= \left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\frac{\pi}{2}}_{-\frac{\pi}{2}}\\\\&=\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}-\dfrac{2}{3}\sqrt{4+3 \sin \left(-\frac{\pi}{2}\right)}\\\\&=\dfrac{2}{3}\sqrt{4+3 (1)}-\dfrac{2}{3}\sqrt{4+3 (-1)}\\\\&=\dfrac{2\sqrt{7}}{3}-\dfrac{2}{3}\\\\&=\dfrac{2\sqrt{7}-2}{3}\end{aligned}\)

Integrate the function between π/2 and π.

As the area is below the x-axis, we need to negate the integral so that the resulting area is positive:

\(\begin{aligned}A_3=-\displaystyle \int^{\pi}_{\frac{\pi}{2}} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&= -\left[\dfrac{2}{3}\sqrt{4+3\sin x}\right]^{\pi}_{\frac{\pi}{2}}\\\\&=-\dfrac{2}{3}\sqrt{4+3 \sin \left(\pi\right)}+\dfrac{2}{3}\sqrt{4+3 \sin \left(\frac{\pi}{2}\right)}\\\\&=-\dfrac{2}{3}\sqrt{4+3 (0)}+\dfrac{2}{3}\sqrt{4+3 (1)}\\\\&=-\dfrac{4}{3}+\dfrac{2\sqrt{7}}{3}\\\\&=\dfrac{2\sqrt{7}-4}{3}\end{aligned}\)

To evaluate the definite integral, sum A₁, A₂ and A₃:

\(\begin{aligned}\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3\sin x}}\; \text{d}x&=\dfrac{2}{3}+\dfrac{2\sqrt{7}-2}{3}+\dfrac{2\sqrt{7}-4}{3}\\\\&=\dfrac{2+2\sqrt{7}-2+2\sqrt{7}-4}{3}\\\\&=\dfrac{4\sqrt{7}-4}{3}\\\\ &\approx2.194\; \sf (3\;d.p.)\end{aligned}\)

Now we have evaluated the definite integral, we can subtract it from 3 to evaluate the given expression:

\(\begin{aligned}3-\displaystyle \int^{\pi}_{-\pi} \dfrac{\cos x}{\sqrt{4+3 \sin x}}\; \text{d}x&=3-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9}{3}-\dfrac{4\sqrt{7}-4}{3}\\\\&=\dfrac{9-(4\sqrt{7}-4)}{3}\\\\&=\dfrac{13-4\sqrt{7}}{3}\\\\&\approx 0.806\; \sf (3\;d.p.)\end{aligned}\)

Therefore, the given expression cannot be zero.

Heeeelp please, Can be zero or not? with all steps and explanay.

Skip's Dog shelter rescue collies 3/4 of the collies are older than 10 and 1/3 of the remaining are between 3 and 5.If there are 2 dogs between the ages of 6 and 10.How many dogs are there in all in the shelter answer

Answers

Answer: It’s 12 dogs

Step-by-step explanation:

Help please!
Please lay the answers in order!
Ex.1:5(x-9)

Help please!Please lay the answers in order!Ex.1:5(x-9)

Answers

Answer:

Step-by-step explanation:

1. x=1

2.x=  -2

3. x=13

4. x= -17

5. x= -41

7. Find the area of Q in terms of .
Q
20 in.
a. 400.7 in.2
b. 100 in
c. 200.7 in.
d. 100.7 in.

7. Find the area of Q in terms of .Q20 in.a. 400.7 in.2b. 100 inc. 200.7 in.d. 100.7 in.

Answers

The answer is c hope it helps

Write in algebra expression

1. Four times ten divided by five
2.twelve diminished by two
3.six times three added to seven
4.eight added to the product of five and three
5.twenty five added to two
5.three times twenty five less twenty
7.the sum of three and thirty nine divided by seven

Answers

Answer:

look at the image :)

Step-by-step explanation:

Write in algebra expression1. Four times ten divided by five2.twelve diminished by two3.six times three

Pls help me with this problem

Pls help me with this problem

Answers

Answer:

what is your problem?    

Step-by-step explanation:

How much food can this container hold 3in 9in

Answers

Answer:

27

Step-by-step explanation:

Answer:

18Πin3

Step-by-step explanation:

How many times larger is 2x10^15 than 4x10^9

Answers

Answer:

500,000

Step-by-step explanation:

2 · 10^15 = 2,000,000,000,000,000

4 · 10^9 = 4,000,000,000

2,000,000,000,000,000 divided by 4,000,000,000 = 500,000

Tip: When you're multiplying 10 to the power of any number, you can just add that amount of zeros to 1.

Example: 10^7

Answer: 10,000,000

There are seven zeros.

Hope I helped :)

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A graph shows the number of texts, numbered 10 to 100, on the x-axis, and the total cost in dollars, numbered 3 to 27, on the y-axis. A straight red line with a positive slope, labeled Emilia, begins at (0, 10), and a straight blue line with a positive slope, labeled Hiroto, begins at (0, 20). Both lines intersect at point (50, 22.5).
Hiroto’s texting plan costs $20 per month, plus $0.05 per text message that is sent or received. Emilia’s plan costs $10 per month and $0.25 per text. Using the graph below, which statement is true?

Hiroto’s plan costs more than Emilia’s plan when more than 50 texts are sent.
Both plans cost the same when 22 texts are sent.
Emilia’s plan costs more than Hiroto’s plan when more than 22 texts are sent.
Both plans cost the same when 50 texts are sen

Answers

Answer:

Both plans cost the same when 50 texts are sent

Step-by-step explanation:

Both the plans cost the same amount $22.5 when 50 texts are sent:

\(20+0.05*50 = 10+0.25*50\)✔️

Have a nice day! :)

simplify pls do fast

simplify pls do fast

Answers

The sum of the decimal values given is 0.93

Simplifying the decimal values can be done thus :

0.36 + 0.57

Both values are in two decimal places, hence we can multiply by 100 to obtain a whole number .

0.36*100 = 36

0.57*100 = 57

Adding the whole numbers :

__36

+_57

_____

__93

Dividing the sum by 100 to convert to an equivalent decimal value,

93/100 = 0.93

Therefore, the required value is 0.93

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Write an equation of the line that passes through (4, 5) and is perpendicular to the line y = -4x+6.
An equation of the perpendicular line is y=

Answers

Y = -1/4x + c
5 = -1/4 x 4 + c
5 = -1 + c
c = 6
y = -1/4 + 6

Identify the next number in the following sequence and tell how:
25 - 49 - 97 - ?
a) 124 b) 171 c) 139 d)193

Answers

Answer:

d

Step-by-step explanation:

multiply by 2 then subtract 1

2(25)-1=49

2(49)-1=97

2(97)-1=193

A one batch recipe of muffins makes a dozen muffins. it requires 2 eggs, two
cups of flour, and a 1\4 pound of sugar. There are 454 grams of sugar in a pound.
How many grams of sugar are in a muffin? **

Answers

Answer: 9.46 grams

Step-by-step explanation:

Given: Number of muffins made in one batch = 1 dozen =12 ]

[ as 1 dozen = 12]

Also, in one batch the quantity of sugar = \(\dfrac14\) pound

As there are 454 grams of sugar in a pound.

So,  in one batch the quantity of sugar = \(\dfrac14\times454=113.5\ grams\)

i.e. in 12 muffins , there is 113.5 grams of sugar.

Then, in one muffin the quantity of sugar = (113.5 grams) ÷ 12

≈9.46 grams

Hence, there are 9.46 grams of sugar in 1 muffin.

Bob reads 1/2 of a 200 page book in 4 days. How long would it take him to read 600 page book

Answers

24 days

1) Consider that Bob reads at a regular pace. So, we can write out a pair of ratios. Note that if Bob reads half of a 200 pages book so he does 100 pages in 4 days

\(\begin{gathered} pages--------days \\ 100---------4 \\ 600---------x \end{gathered}\)

2) So writing out a pair of ratios we have:

\(\frac{100}{600}=\frac{4}{x}\)

Now, we can cross multiply them:

\(\begin{gathered} 100x=600\cdot4 \\ 100x=2400 \\ \frac{100x}{100}=\frac{2400}{100} \\ x=24 \end{gathered}\)

Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (3, -1)

Answers

Answer:

The equation of the line is 2x - 3y = 9

Step-by-step explanation:

Given:

Write the equation of a line that is parallel to the line 2x - 3y = 5 and passes through the point (3, -1)

Solve:

- The line is parallel to the line 2x - 3y = 5

⇒ the slope of the line = the slope of the line 2x - 3y = 5

- Rearrange the terms of the equation to be in the form

⇒  y = mx + c to find the slope of it

2x - 3y = 5 → subtract 2x from both sides

-3y = 5 - 2x ⇒ divide two sides by -3

y = 5/-3 - 2x/-3 ⇒ y = 2/3 x - 5/3

The slope of the line is 2/3

Given that: The line passes through point (3, -1)

Lets use the rule to find the equation of the line:

y - (-1)/x - 3 = 2/3

y + 1/x - 3 = 2/3 ⇒ by using cross multiplication

3(y + 1) = 2(x - 3) ⇒ open the brackets

3y + 3 = 2x -6 ⇒ put x and y on one side

2x - 3y = 3 + 6

2x - 3y = 9

The equation of the line is 2x - 3y = 9

~Kavinsky

hello can you help me with this question

hello can you help me with this question

Answers

Answer:

B. x is less than or equal to 5

Step-by-step explanation:

The dot is on 5 and is also a solid dot which means it is less than or equal to or greater than or equal to

In this case it is less than or equal to because the line goes to the left

Hope this helped!

In an ESP experiment subjects must predict whether a number randomly generated by a computer will be odd or even. (Round your answer to four decimal places.) (b) What is the probability that a subject would guess more than 20 correct in a series of 36 trials?

Answers

The probability that a subject would guess more than 20 correct in a series of 36 trials is 0.0001

How to find the pobability that a subject would guess more than 20 correct in a series of 36 trials

In a series of 36 trials, if the subject is guessing randomly, then the probability of correctly guessing odd or even is 1/2.

Let X be the number of correct guesses in a series of 36 trials. X follows a binomial distribution with parameters n = 36 and p = 1/2.

The probability of guessing more than 20 correct is:

P(X > 20) = 1 - P(X ≤ 20)

Using a binomial distribution table, we can find that P(X ≤ 20) = 0.9999 (rounded to four decimal places).

Therefore: P(X > 20) = 1 - 0.9999 = 0.0001

So the probability that a subject would guess more than 20 correct in a series of 36 trials is 0.0001 (rounded to four decimal places).

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The least common denominator is: (x − 4)(x + __ )(x −__ )

Answers

the least common denominator should be >>>> if wrong im sorry (x-4)(x+1)(x-1)

A cube has a side length of 20 in . find the value

Answers

The other side and all the sides should be 20 add them together

Consider the following number line

Consider the following number line

Answers

Answer: 4.5 looks the most reasonable to me.

Step-by-step explanation:

I would say 4.5 hope it helps
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