assuming you exert a constant force on the wagon, how fast is it moving after 5 seconds?

a.  The force on the +3.0 mC charge is 1.35 x 10^-6 N.

b.   The electric field at (x, y) = (1.00 m, 0.50 m) is  5.49 x 10^5 N/C

c. The point where the bc is zero (other than at infinity) is located on the line that connects the two charges and at the midpoint of the line segment connecting them.

d.  The potential at the point found in part c is at point zero

An electric field is described as the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

a.  we need to use Coulomb's law, which states that the force between two charges is given by:

F = k * (q1 * q2) / r^2

F = k * (q1 * q2) / r^2 = 8.99 x 10^9 Nm^2/C^2 * (1.0 x 10^-3 C * 3.0 x 10^-3 C) / (2.0 m)^2 = 1.35 x 10^-6 N

b. To calculate the electric field at (x, y) = (1.00 m, 0.50 m), we use the equation for the electric field due to a point charge:

E = k * q / r^2

The distance from the point charge is:

r = sqrt((1.00 m - 2.0 m)^2 + (0.50 m - 0 m)^2) = sqrt(3.25 m^2) = 1.8 m

Therefore, the electric field at (x, y) = (1.00 m, 0.50 m) is:

E = k * q / r^2 = 8.99 x 10^9 Nm^2/C^2 * (3.0 x 10^-3 C) / (1.8 m)^2 = 5.49 x 10^5 N/C

c. This point is located on the line that connects the two charges and at the midpoint of the line segment connecting them.

d.  At the point found in c, the electric field is zero, so the work done to move a test charge from infinity to that point is also zero.

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Answer:

Explanation:

To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).

The mass of a pure platinum disc can be gotten by multiplying the density with the volume.

Therefore the mass is 2418.2 grams or 2.4182 kilograms.

A body's mass is an inherent quality. Prior to the discovery of the atom and particle physics, it was widely considered to be tied to the amount of matter in a physical body.

The kilogram is the primary mass unit in the SI.

The resistance of the body to acceleration in the presence of a net force can be measured as mass.

Due to the lower gravity on the Moon, an object would weigh less than it does on Earth while maintaining the same mass. This is due to the fact that mass, coupled with gravity, determines the strength of weight, which is a force.

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What is the mass of a pure platinum disk with a volume of 113 cm3? The density of platinum is 21.4 g/cm3.

Give your answer in grams and kilograms.

The final velocity of the red ball is 18 m/s.

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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The angular velocity of the rotating tire is 100.95 rad/s.

The angular velocity of the rotating tire is approximately 964.8 RPM.

Part A:

The linear velocity of the truck is given as 42.4 m/s. The angular velocity of the rotating tire can be found using the formula:

ω = v/r

where ω is the angular velocity, v is the linear velocity, and r is the radius of the tire.

Substituting the given values, we get:

ω = 42.4 m/s / 0.420 m

ω = 100.95 rad/s

Therefore, the angular velocity of the rotating tire is 100.95 rad/s.

Part B:

The angular velocity can also be expressed in revolutions per minute (RPM). To convert from rad/s to RPM, we can use the following conversion factor:

1 rev/s = 60 RPM

1 rad = 1/(2π) rev

Combining these two conversion factors, we get:

1 rad/s = (1/(2π)) x 60 RPM

1 rad/s = 9.55 RPM

Therefore, the angular velocity of the rotating tire in RPM is:

ω = 100.95 rad/s x 9.55 RPM/rad

ω ≈ 964.8 RPM

Therefore, the angular velocity of the rotating tire is approximately 964.8 RPM.

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(a)

In order to find the original speed, let's use the formula below to find an expression for the acceleration:

Now, we can use the following formula to find the initial speed:

(b)

Now, calculating the acceleration, we have:

Answer:

1.48kg

Explanation:

Here,

potential energy (P.E) = 29j

height (h) = 2m

acceleration due to gravity(g) =

\(9.8m {s}^{ - 2} \)

mass(m) = ?

we know,

P.E = mgh

or, 29 = m×9.8×2

or, 29/19.6 = m

or,m = 1.48kg

Answer:

The interaction with the highest electrostatic potential energy is:

A +1 and -2 particle separated by a distance of 5 nm.

Explanation:

The electrostatic potential energy between two charged particles depends on the magnitude of their charges and the distance between them. The formula for calculating electrostatic potential energy is:

U = k * (q1 * q2) / d

where U is the electrostatic potential energy, k is Coulomb's constant, q1 and q2 are the magnitudes of the charges, and d is the distance between them.

In the given options, the interaction between +1 and -2 particles separated by a distance of 5 nm has the highest electrostatic potential energy because the charges have a higher magnitude (compared to other options) and they are close to each other, resulting in a stronger electrostatic force of attraction. The other options either have smaller charges, larger distances, or both, leading to lower electrostatic potential energy.

Answer:

Explanation:

Assuming no friction between the roller coaster car and the hill, and neglecting air resistance, the kinetic energy the roller coaster car would have at the bottom of the hill would be equal to its gravitational potential energy at the top of the hill, by conservation of energy.

The magnitude of the velocity the blinking tree has when it is 2 meters from the ground is 21.8 m/s.

To calculate the velocity of the blinking tree when it is 2 meters from the ground, we can use the principles of conservation of energy.

First, let's determine the potential energy of the tree when it is 50 meters off the ground. The potential energy (PE) can be calculated using the formula:

PE = mgh

Where:

m = mass of the tree (2.3 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = height (50 m)

PE = 2.3 x 9.8 x 50

PE = 1131 J

Next, we can calculate the potential energy of the tree when it is 2 meters from the ground:

PE = mgh

Thus:

PE = 2.3 x 9.8 x 2

PE = 45.04 J

According to the conservation of energy principle:

PE(initial) = PE(final) + KE(final)

1131 J = 45.04 J + KE(final)

Now, let's solve for the kinetic energy (KE) at the final position:

KE(final) = PE(initial) - PE(final)

KE(final) = 1131 J - 45.04 J

KE(final) = 1085.96 J

KE = (1/2)mv^2

1085.96 J = (1/2) x 2.3 kg x v^2

Thus

v^2 = (2 x 1085.96 J) / 2.3 kg

v^2 = 474.76 m^2/s^2

v ≈ 21.8 m/s

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Johnny Answer:

Explanation:Sins

The final temperature in terms of 1 and 2 is Tₓ= √12 and the work delivered is W= NC (3-2√12) after connecting with the Carnot engine.

A Carnot heat engine is a theoretical engine that operates on the principle of Carnot cycle.

The internal energy is

           U=NCT

Thus, dQ₁ = NCdT₁

And, dQ₂= NCdT₂

For a Carnot engine, we have

dQ₁/T₁ = -dQ₂/T₂

Thus,

∫dT₁/T₁ = ∫dT₂/T₂

Therefore, Tₓ= √T₁T₂

                   Tₓ= √12

Conservation of energy gives ₍

W= NC (T₁+T₂-2Tₓ)

W= NC (1+2-2√12)

W= NC (3-2√12)

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Answer:

9.461 × 10^12 Km s

..............................

Answer:

F = 160.0 N

Explanation:

Given: Soccer payer with a mass = 80 kg, force = 20 N

To find: force

Formula: \(F=ma\)

Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

F = m × a

F = 20 kg - 10 = 2  

F = 80 × 2 = 160

F = 160.0 N

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

Answer:

It’s a

Explanation:

Don’t actually put that i needed the points mb

The sum tone has a frequency of (Cs+Gs) and the difference tones have frequencies of (Cs-Gs) and (Gs-Cs).

Combination tones are tones that are produced by the interaction of two or more pure tones in the ear or in a resonant system. They are produced by the sum and difference of the frequencies of the pure tones.

The Pythagorean diatonic scale is a tuning system in which the frequency ratios between adjacent notes are based on the ratios of small whole numbers. This scale was used in ancient Greek music and later became the basis for Western music theory.

The Pythagorean tuning system is related to music because it provides a mathematical foundation for the intervals and relationships between musical notes, and has influenced the development of Western music for centuries.

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Answer: A.

tracking training through a leaming records store LRS.

Explanation:

An LRS uses xAPI to collect learner data, or experiences, from both online and offline sources. These experiences are reported back to the LRS in the form of xAPI statements, where they are stored. These statements can then be retrieved for reporting and interpretation of the learner data.

a. The minimum time for the rocket to reach the sound barrier is 33.67 seconds.

b. The maximum vertical thrust of the rocket engines under these conditions is 250,893.6 N.

c. The rocket is 5548.1 meters above the Earth's surface when it breaks the sound barrier.

To solve this problem, we'll use Newton's second law of motion (F = ma) and consider the forces acting on the rocket and the instrument inside.

Calculating the minimum time for the rocket to reach the sound barrier without breaking the inside wire.

a) Minimum time to reach the sound barrier:

Given:

Mass of the rocket (m) = 2.56 × \(10^4\) kg

Acceleration due to gravity (g) = 9.8 m/\(s^2\)

Maximum tension the wire can support (T_max) = 27.5 N

Weight of the instrument (W) = mass of the instrument × acceleration due to gravity = 13.6 N

The forces acting on the instrument inside the rocket are its weight (W) and the tension in the wire (T). At maximum tension, the net force on the instrument is zero.

T - W = 0

T = W

Therefore, the maximum tension in the wire is equal to the weight of the instrument, which is 13.6 N.

Now, let's determine the acceleration of the rocket. The total force acting on the rocket is the sum of the rocket's weight (mg) and the tension in the wire (T).

F_total = mg + T

F_total = (2.56 × \(10^4\) kg)(9.8 m/\(s^2\)) + 13.6 N

F_total = 250,880 N + 13.6 N

F_total = 250,893.6 N

Since we're assuming the rocket's acceleration is constant.

we can use Newton's second law:

F_total = ma

250,893.6 N = (2.56 × \(10^4\) kg)a

Solving for acceleration:

a = 250,893.6 N / (2.56 × \(10^4\) kg)

a ≈ 9.8 m/\(s^2\)

The acceleration of the rocket is approximately 9.8 m/\(s^2\), which is the same as the acceleration due to gravity.

To find the minimum time to reach the sound barrier, we can use the following equation of motion:

v = u + at

where,

v = final velocity (sound barrier velocity = 330 m/s)

u = initial velocity (which is zero since the rocket starts from rest)

a = acceleration

t = time

330 m/s = 0 + (9.8 m/\(s^2\))t

Solving for t:

t = 330 m/s / 9.8 m/\(s^2\)

t ≈ 33.67 s

Therefore, the minimum time for the rocket to reach the sound barrier without breaking the inside wire is approximately 33.67 seconds.

b) Maximum vertical thrust of the rocket engines:

The maximum vertical thrust of the rocket engines is equal to the total force acting on the rocket, which we calculated earlier:

Maximum vertical thrust = F_total

Maximum vertical thrust ≈ 250,893.6 N

Therefore, the maximum vertical thrust of the rocket engines under these conditions is approximately 250,893.6 N.

c) Distance above the Earth's surface when breaking the sound barrier:

To determine the distance above the Earth's surface when breaking the sound barrier, we can use the following equation of motion:

s = ut + (1/2)at^2

where,

s = distance

u = initial velocity (which is zero)

a = acceleration

t = time it takes to reach the sound barrier (33.67 s).

s = 0 + (1/2)( 9.8 m/\(s^2\))\((33.67 s)^2\)

s = (\(4.9 m/s^2\))(1132.8289 \(s^2\))

s ≈ 5548.1 m

Therefore, the rocket is approximately 5548.1 meters (or 5.55 kilometers) above the Earth's surface when it breaks the sound barrier.

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Answer:

d your welcome ehhehe:)

After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be  0.441 m below its initial position, with a velocity of approximately 2.94 m/s.

To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.

Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.

(a) Position:

Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.

After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)

After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)

After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)

(b) Velocity:

The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.

After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)

After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)

After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)

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Answer:

216 m/s

Explanation:

Final velocity will be resultant of the initial horizontal velocity ( 180 m/s) and the vertical velocity from falling  734.7 m

Verital   vf = at     need to find time

             df = 734.7 = 1/2 a t^2

                                  t= 12.2 sec

vf = at

   = 9.81 (12.2) = 120 m/s

Just before hotting the ground,

   resultant velocity = sqrt(180^2 + 120^2) = 216 m/s

Answer:

Two Main Branches of Physics

it is Classical Physics and Modern Physics.

Explanation:

Further sub Physics branches are Mechanics, Electromagnetism, Thermodynamics, Optics, etc. The rapid progress in science during recent years has become possible due to discoveries and inventions in the field of physics.

hope it helped

For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle  is mathematically given as

theta=25.3

Option A is correct

Generally, the equation for the the angle   is mathematically given as

\(\theta=n(\lambda/d)\)

Therefore

\(\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)\)

In conclusion

theta/7=16/5

theta=10*7/5

theta=25.3

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The weight of a 190 lb person is 844.5 N.

Newton is the SI (International System) unit of force, named after Sir Isaac Newton, a famous physicist, and mathematician. It is defined as the force required to accelerate a mass of one kilogram at a rate of one meter per second squared (1 N = 1 kg m/s²).

To convert pounds (lb) to Newtons (N), we need to use the conversion factor:

1 lb = 4.45 N

Therefore, a 190 lb person weighs:

190 lb × 4.45 N/lb = 844.5 N

So the weight of a 190 lb person is 844.5 N.

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Answer: Can't see clearly.

Explanation:

Answer:

3300 J

Explanation:
P = Q/t

Q = Pt = 110 * 30 = 3300 J

The current in amps 5.00 milliseconds after the switch is moved to disconnect the battery, if the initial current was 11 A found to be 1.488A.

Inductors oppose changes in current through them by dropping a voltage directly proportional to the rate of change of current, as opposed to resistors, which merely oppose the flow of current through them (by dropping a voltage directly proportional to the current).

I (t=5ms) = Io exp (- Rt/L)

             => 11 exp (- 3 x 5 / 7.5)

             => 1.488A.

Similar to series circuits, when resistors and inductors are combined in parallel circuits, the overall impedance will have a phase angle between 0° and +90°. The phase angle of the circuit current will be between 0° and -90°.

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The potential difference at the point is 44 V

From the question given above, the following data were obtained:

Energy (E) = 44 J

Charge (Q) = 2 C

The potential difference can be obtained as follow:

E = ½QV

44 = ½ × 2 × V

44 = 1 × V

Therefore, the potential difference is 44 V

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