If 3 moles of a diatomic gas has an internal kinetic energy of 10 Kilojoules then the temperature of the gas when it reaches equilibrium is 364.67 Kelvin.
To determine the temperature of a gas, we can use the equation for the average kinetic energy of a molecule:
KE_avg = (3/2) * k * T
Where:
KE_avg is the average kinetic energy of a molecule,
k is the Boltzmann constant (approximately 1.38 x 10^-23 J/K),
T is the temperature in Kelvin.
Given that the gas has 3.0 moles and an internal kinetic energy of 10 kJ, we need to convert the energy to joules and divide by the number of moles to find the average kinetic energy per molecule.
Internal kinetic energy = 10 kJ = 10,000 J
Number of moles (n) = 3.0 mol
Average kinetic energy per molecule (KE_avg) = Internal kinetic energy / Number of molecules
KE_avg = 10,000 J / (3.0 mol * 6.022 x 10^23 molecules/mol)
Now we can rearrange the equation to solve for temperature (T):
T = (KE_avg * 2) / (3 * k)
Plugging in the values:
T = (10,000 J / (3.0 mol * 6.022 x 10^23 molecules/mol)) * 2 / (3 * 1.38 x 10^-23 J/K)
Simplifying:
T ≈ 364.67 K
Therefore, the gas's temperature after reaching equilibrium is approximately 364.67 Kelvin.
The complete question should be:
Assume 3.0 moles of a diatomic gas has an internal kinetic energy of 10 kJ. Determine the temperature of the gas after it has reached equilibrium.
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Which of the following solutions will have the greatest concentration?
a. 2 moles of solute dissolved in 1 liter of solution
b. 0.3 mole of solute dissolved in 0.6 liter of solution
c. 2 moles of solute dissolved in 10 liters of solution
d. 0.1 mole of solute dissolved in 0.5 liter of solution
2 moles of solute dissolved in 1 liter of solution has the greatest concentration.
What is concentration of a solution?Concentration refers to the quantity of solute that is dissolved in a specific amount of solution, and it is commonly measured in units such as moles per liter or grams per liter.
Equation:To determine which solution has the greatest concentration, we need to calculate the number of moles of solute present in each solution and then compare the values.
a. Concentration = 2 moles / 1 liter = 2 M
b. Concentration = 0.3 moles / 0.6 liters = 0.5 M
c. Concentration = 2 moles / 10 liters = 0.2 M
d. Concentration = 0.1 moles / 0.5 liters = 0.2 M
Comparing the concentrations, we see that solution (a) has the greatest concentration of 2 M, while the other solutions have concentrations of 0.5 M or lower.
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what element can be found in both plays and stories
The element that can be found in both plays and stories is "characters."
Characters are an essential element of both plays and stories. They are the individuals or entities that drive the narrative, interact with each other, and contribute to the development of the plot. In plays, characters are typically portrayed by actors who perform their roles on stage, while in stories, characters are described and depicted through written words.
Characters can be central or supporting figures in a play or story, and they play a vital role in engaging the audience or readers. They have distinct personalities, motivations, and relationships that influence the events and conflicts within the narrative. Through their actions, dialogue, and character development, they contribute to the overall themes and messages conveyed by the play or story.
Whether it is a theatrical production or a written narrative, the presence and portrayal of characters are fundamental to creating engaging and compelling plays and stories.
Thus, the element that can be found in both plays and stories is "characters."
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During a lab, a tablet i dropped into a bag and liquid i added. The ma of the tablet wa 20 g, the ma of the bag wa 50 g, the ma of the liquid wa 90 g. When the tablet hit the water, a chemical reaction took place and the bag filled with ga. If the ma of the liquid remained at 90 g, how much ga wa produced?
Response: 25 g. According to the law of conservation of mass, mass is maintained throughout a chemical process.
What instances from chemistry?The elements, including such zinc, helium, or oxygen, as well as compounds comprised of components like water, carbon dioxide, or salt, as well as more complicated materials, such as your computer, the air you breathe, rainfall, a chicken, a car, etc., are examples of chemicals.
Why do chemicals form?Chemical processes occur when atoms form or break chemical bonds. The molecules that start a chemical reaction are known as reactants, and the molecules that are produced as the result of the process are known as products.
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A 100-L bioreactor is used to grow recombinant E. coli with air being supplied at 100 L/min. The dissolved oxygen level is maintained at 0.1 mM. The solubility of oxygen is 0.2 mM. The inlet air has 21% oxygen (79% nitrogen) while the outlet on a dry basis (after removing the moisture carried from the reactor) is 19% O2, 2% CO2, and 79% nitrogen. In the scale-up process, a reactor 125 times larger is constructed in a geometrically-similar way. The superficial velocity of air flow can only be increased 2.5 fold above that of the 100-L scale.
a. What is the KLa in the 100-L scale?
b. If one can keep KLa constant in the 12,500 L scale, can you keep the same oxygen uptake rate as in the 100-L scale? If yes, what is the dissolved oxygen concentration?
a) The KLa in the 100-L scale is 10 \(min^{-1\).
b) No, it is not possible to keep the same oxygen uptake rate as in the 100-L scale while keeping KLa constant in the 12,500 L scale.
What is the KLa value in the 100-L scale?The KLa (mass transfer coefficient) represents the efficiency of oxygen transfer from the gas phase to the liquid phase in a bioreactor.
In the given 100-L scale, the dissolved oxygen level is maintained at 0.1 mM, and the solubility of oxygen is 0.2 mM.
To calculate KLa, we need the volumetric flow rate of air and the concentration difference between the outlet and the saturation concentration.
Given that air is supplied at 100 L/min and the solubility of oxygen is 0.2 mM, we can calculate KLa as follows:
KLa = (C*/C)*(Q/V)
Where C* is the saturation concentration of oxygen, C is the dissolved oxygen concentration, Q is the volumetric flow rate of air, and V is the volume of the bioreactor.
Plugging in the values:
KLa = (0.2 mM / 0.1 mM) * (100 L/min / 100 L) = 2 \(min^{-1\)
Therefore, the KLa in the 100-L scale is 10 \(min^{-1\).
How to find the dissolved oxygen concentration?The dissolved oxygen concentration would be lower in the 12,500 L scale.
In the scale-up process, the reactor is constructed 125 times larger, resulting in a 12,500 L scale.
While the superficial velocity of air flow can only be increased 2.5-fold, the reactor volume has increased by a factor of 125.
As a result, the oxygen uptake rate cannot be maintained at the same level as in the 100-L scale.
Since KLa represents the mass transfer efficiency, which is dependent on the surface area and mixing in the reactor, keeping it constant does not compensate for the increased volume.
Therefore, in the 12,500 L scale, the dissolved oxygen concentration would be lower compared to the 100-L scale.
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redict The Formula For A Compound Made From X^+ And Y^2- Insert Subscripts As Needed. Formula:
To predict the formula for a compound made from X^+ and Y^2-, we need to first determine the charges of the ions and balance them to form a neutral compound. The X^+ ion has a positive charge of +1, while the Y^2- ion has a negative charge of -2.
To balance these charges, we need two X^+ ions to cancel out the negative charge of the Y^2- ion. Therefore, the formula for the compound made from X^+ and Y^2- is X2Y.
In this compound, there are two X ions and one Y ion. The subscripts of 2 and 1 represent the number of ions in the compound, respectively. The X ions have a charge of +1, while the Y ion has a charge of -2, resulting in a neutral compound overall.
It is important to note that the charges of the ions in a compound must always balance to form a neutral compound. Predicting the formula for a compound requires understanding the charges of the ions and balancing them accordingly.
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what does Le châteliers principle state?
what is not true about monosaccharides?
Fructose and Glucose cannot be distinguish by \(BR_{2}\) /\(H_{2}\)O and Glucose and mannose are anomers.
Since they cannot be hydrolyzed into smaller carbs, monosaccharides are the most basic types of carbohydrates. They are chemically defined as aldehydes or ketones with two or more hydroxyl groups, and they play a crucial role in the production of fuel molecules, or glycolysis, as well as nucleic acids.
Monosaccharides are carbohydrates that cannot be further hydrolyzed to produce a simpler molecule of polyhydroxy aldehyde or ketone.
\(BR_{2}\) /\(H_{2}\)O can be used to differentiate between glucose and fructose because fructose doesn't react with \(BR_{2}\) /\(H_{2}\)O. Fehling's solution can distinguish between glucose and fructose because it only produces a good test result for aldehydes, such as glucose.
Mannose and glucose are epimers because they only vary at C-2, the first asymmetric carbon atom.
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The complete question is:
What is not true about monosaccharides?
a. Optically active polyhydroxy carbonyl compounds.
b. Fructose and Glucose cannot be distinguish by \(BR_{2}\) /\(H_{2}\)O
c. Glucose and mannose are anomers.
d. Fructose and Glucose cannot be distinguish by Fehling's solution.
when the acetylcholine receptor sites are not occupied multiple choice a. a ligand is formed. b. the sodium channels open. c. the sodium channels remain closed. d. sodium ions diffuse through and enter the cell. e. sodium ions diffuse through and leave the cell.
When the acetylcholine receptor sites are not occupied, a ligand is formed. Thus, sodium channels remain closed, so sodium ions do not diffuse through or enter or leave the cell. Thus, option c is correct.
Acetylcholine receptors are a kind of transmembrane protein that is embedded in the cell membrane. Acetylcholine is a neurotransmitter that binds to this receptor.
When acetylcholine is released into the synaptic cleft, it binds to the acetylcholine receptor. The channel that allows positively charged ions to flow into the cell opens as a result of this.
This causes the interior of the cell to become more positive, resulting in the generation of an action potential that can be propagated down the axon.
The sodium channels remain closed when the acetylcholine receptor sites are not occupied. The acetylcholine receptors are critical for neuron action potential generation.
If acetylcholine cannot bind to these receptors, no electrical impulse can be transmitted. Thus option c is correct.
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What are the answers for this
Answer:
Solid:
shape: definite
volume:definite
closeness...: tightly packed
motion ..: vibrate in their position
liquid:
shape: indefinite
volume: definite
closeness: loosely packed
motion... : slide past each other
gas:
shape: indefinite
volume: indefinite
closeness: far apart
motion..: random movement
Explanation:
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A gas has a volume of 13.4 L at 17C. What is the volume of the gas at standard temperature?
Answer:
This law states that the volume and temperature of a gas have a direct relationship: As temperature increases, volume increases, when pressure is held constant. Heating a gas increases the kinetic energy of the particles, causing the gas to expand.
Explanation:
Considering the Charles's law and STP conditions, the volume of the gas at standard temperature is 12.61 L.
Charles's lawCharles's law establishes the relationship between the volume and temperature of a gas sample at constant pressure.
This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases. That is, the volume is directly proportional to the temperature of the gas.
Mathematically, Charles's law states that the ratio between volume and temperature will always have the same value:
\(\frac{V}{T} =k\)
Considering an initial state 1 and a final state 2, it is fulfilled:
\(\frac{V1}{T1} =\frac{V2}{T2}\)
Definition of STP conditionThe STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere and temperature at 0 ° C (or 273 K) are used and are reference values for gases. And in these conditions 1 mole of any gas occupies an approximate volume of 22.4 liters.
Volume of the gas at standard temperatureIn this case, you know:
V1= 13.4 LT1= 17 C= 290 K (being 0 C= 273 K)V2= ?T2= 0 C= 273 K (at STP)Replacing in the definition of Charles's law:
\(\frac{13.4 L}{290 K} =\frac{V2}{273 K}\)
Solving:
\(V2= 273 K\frac{13.4 L}{290 K}\)
V2= 12.61 L
Finally, the volume of the gas at standard temperature is 12.61 L.
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what is the molar mass of a substance that has a mass of 40 grams and a molar amount of 0.8 moles
Answer:
The molar mass is 0.02 g/mol
Explanation:
The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).
\(M=\frac{n}{m}\)
We are given
\(m=40\) g
\(n=0.8\) mol
Substituting our values into the equation gives us
\(M=\frac{0.8}{40}\)
\(M=0.02\) g/mol
what chemicals help reduce a change in ph when acids are added to a solution?
Chemicals that help reduce a change in pH when acids are added to a solution are called buffers. Buffers are substances that are capable of resisting changes in pH by accepting or donating protons (H+ ions) in order to maintain a relatively stable pH.
Buffers typically consist of a weak acid and its conjugate base (or a weak base and its conjugate acid). When an acid is added to a buffered solution, the weak base component of the buffer can accept the additional H+ ions, minimizing the increase in pH. Conversely, when a base is added, the weak acid component of the buffer can donate H+ ions, minimizing the decrease in pH. Common examples of buffer systems include acetic acid/acetate buffer (found in vinegar), phosphate buffer (used in biological systems), and bicarbonate buffer (important in maintaining blood pH).In summary, buffers help reduce the change in pH when acids are added to a solution by accepting or donating protons to maintain the pH within a relatively narrow range.
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........,,,,,,?!!mm........
Answer:
añadir agua a la mezcla para disolver la sal. Después la arena se separa del agua salada por filtración. Finalmente, el agua salada se deja evaporar.
Explanation:
:u
What are some examples of a chemical change? (list more than 2 examples)
Cooking any food.
Burning of wood.
Digestion of food.
Acid-base reaction.
Two parent reproduction involves cell division that includes ___________? *
Meiosis
Fibrosis
Mitosis
Answer:
Mitosis
Explanation:
Predict the initial and final products for the following reaction involving 2-pentyne or pent-2-yne. Hint: the products are isomers and in equilibrium with each other. H2O H2SO4 Hg2+ (cat) ---> initial products ===> final products. Draw the final products.
The initial product is 2-pentyn-1-ol and the final products are 2-penten-1-ol and 3-penten-1-ol (cis/trans isomers).
The response of 2-pentyne (confined 2-yne) with H2O, H2SO4, and Hg2+ is a corrosive catalyzed hydration response. Within the sight of H2SO4 and Hg2+ impetus, the protonation of the triple bond happens first, trailed by the expansion of water to give an enol transitional. The enol middle of the road can then tautomerize to frame either a ketone or an aldehyde isomer.
The underlying item shaped will be the enol middle of the road, which can tautomerize to give the end results: 3-pentanone (a ketone) and 2-pentanone (an aldehyde). These two isomers are in harmony with one another.
The construction of 3-pentanone has a carbonyl gathering at the third carbon position, though 2-pentanone has a carbonyl gathering at the subsequent carbon position. The eventual outcomes are both established isomers, varying in the place of the carbonyl gathering. The component for the response includes the expansion of water across the triple bond, trailed by tautomerization of the enol halfway, which brings about the two isomers.
Generally, this response is an illustration of corrosive catalyzed hydration, which is a significant response in natural science, with various applications in the amalgamation of alcohols, ketones, and aldehydes.
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The given response is a corrosive catalyzed hydration of 2-pentyne or confined 2-yne.
The underlying items are the enol tautomer and the keto tautomer of 2-pentanone. The enol tautomer is shaped by protonation of the triple bond with H+ from H2SO4, trailed by assault of water atom on the carbocation. The keto tautomer is shaped from the enol tautomer by tautomerization.
The end results are the protected isomers of 3-pentanone and 2-pentanone. The keto tautomer of 2-pentanone modifies to shape 3-pentanone, which is more steady because of the stretching of the carbonyl gathering. The keto tautomer of 2-pentanone is the significant item since it is more steady than the enol tautomer.The response system is displayed underneath:
Introductory items:
Enol tautomer of 2-pentanone:
H2C=C(CH3)CH2C(=O)H
Keto tautomer of 2-pentanone:
CH3CH2C(=O)CH2CH3
End results:
3-pentanone:
CH3CH2CH2C(=O)CH2CH3
2-pentanone:
CH3CH2C(=O)CH(CH3)CH2
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what is the ph of a 0.01 m solution of a weak acid with a pka = 6?
The pH of a 0.01 M solution of a weak acid with a pKa of 6 is 4.
How to calculate the pH of a weak acid?To calculate the pH of a 0.01 M solution of a weak acid with a pKa of 6,
1. Write down the given values: pKa = 6, [Acid] = 0.01 M.
2. Calculate the Ka value using the pKa: Ka = 10^(-pKa) = 10^(-6).
3. Use the Ka expression to set up an equation for the acid ionization:
Ka = [H+][A-]/[HA],
where [H+] is the concentration of hydrogen ions, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.
4. Since the acid is weak, assume that the initial concentration of [A-] and [H+] is negligible compared to the initial concentration of the acid.
5. As the acid ionizes, the concentration of [H+] and [A-] will increase by x, while the concentration of [HA] will decrease by x.
6. Write the equation with the new concentrations: Ka = (x)(x)/(0.01 - x).
7. Because the acid is weak, we can assume that x is much smaller than 0.01, so the equation can be simplified to Ka = x^2/0.01.
8. Solve for x: x^2 = Ka * 0.01 = 10^(-6) * 0.01.
9. Find the square root of both sides to find the concentration of [H+]: [H+] = x = sqrt(10^(-6) * 0.01) = 10^(-4) M.
10. Finally, calculate the pH using the formula
pH = -log[H+]:
pH = -log(10^(-4)) = 4.
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Which form of energy does a battery-powered flashlight receive as an input?
Answer:
chemical energy
Explanation:
A battery stores energy in the form of chemical energy. Chemical energy is stored in the bond of atoms and molecules. These bonds break and convert to other forms of energy. In the given case, the chemical energy is converted to electric energy which powers the flashlight. Thus, flashlight receives energy input in the form of chemical energy.
The air we breathe is mostly a mixture of oxygen and hydrogen. How do air molecules change above 100 km?
Gases are no longer evenly mixed but layered.
The electrically charged ions in the ionosphere creates turbulence.
Water vapor condenses from the cold air.
Meteors burn in Earth's atmosphere.
Answer:
The answer is a
Explanation:
The atmosphere be fits itself with light gases and therefore the gases no longer evenly mix .
Answer:
Explanation:
Gasses are no longer evenly mixed but
CH3CHOHCH3 an electrolyte in solution.
The complete statement is "CH3CHOHCH3 is not an electrolyte in solution." This is further explained below.
What is electrolyte ?Generally,a liquid or gel containing ions that may be broken down by electrolysis, such as the kind used in batteries.
In conclusion, "CH3CHOHCH3 is not an electrolyte in solution," is the whole sentence.
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What is the Ka of a 0.479 M
solution of acetic acid
(CH3COOH) with a pH of 4.76?
r
Answer:
6.31x10^-10
Explanation:
Answer: 6.31 x 10^-10
Explanation:
Which option is a particulate associated with air pollution? (
O coal dust
Oozone
o chlorofluorocarbons
O carbon monoxide
Answer: coal dust
Explanation:
I just took the quiz and got it wrong.
The option that represents a particulate associated with air pollution is "coal dust."
Coal dust refers to the fine particles and small airborne particles that are generated during the mining, processing, handling, and combustion of coal. These particles can be released into the air and contribute to air pollution.
Coal dust is a significant source of particulate matter (PM) pollution, particularly PM2.5, which refers to particles with a diameter of 2.5 micrometers or smaller. These tiny particles can easily enter the respiratory system and have detrimental effects on human health. Prolonged exposure to coal dust can lead to respiratory issues such as bronchitis, asthma, and even lung cancer.
Furthermore, coal dust can contribute to the formation of smog and haze, reducing visibility and impacting air quality. It can also contain various toxic substances, including heavy metals like mercury and lead, which pose additional health and environmental risks.
Reducing coal dust emissions requires effective dust control measures at every stage of coal production and combustion, including proper mining practices, dust suppression techniques, and the use of cleaner technologies. Such measures are crucial for mitigating the adverse impacts of coal dust on air quality and human health.
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is density a chemical or physical property of a substance?
Answer:
A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.
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I understand that I answered wrong with 15ml instead of 14, but would I have to put the 0 after or no?
Answer:
no dont worry its in decimal point
anything after the point is considered as not to the fullest
How would antibodies against NT receptors affect the neuromuscular junction?
Antibodies against nicotinic acetylcholine receptors (nAChR), present at neuromuscular junction (NMJ), can affect function of junction by interfering with normal signaling between nerve and muscle.
How would the antibodies against NT receptors affect neuromuscular junction?Antibodies against nicotinic acetylcholine receptors (nAChR), which are present at neuromuscular junction (NMJ), can affect the function of junction by interfering with normal signaling between nerve and muscle.
At NMJ, the nerve terminal releases acetylcholine (ACh), which binds to nAChR on muscle cell membrane, leading to depolarization of muscle cell and muscle contraction. If antibodies bind to nAChR, they can block or reduce the number of available receptors for ACh, leading to decrease or even complete loss of the normal muscle response to nerve stimulation.
This can result in muscle weakness, fatigue, and even paralysis, depending on the severity of antibody binding and amount of functional nAChR remaining at the NMJ.
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gallium is a metal which forms compounds with a wide variety of uses. some of the applications of gallium compounds include computer memory chips, light emitting diodes and lasers. radioactive isotopes of gallium are used to image the human body and locate tumors. naturally occurring gallium consists of two isotopes. one of those isotopes is 71ga with an isotopic mass of 70.9247050 amu 70.9247050 amu and an abundance of 39.892% 39.892 % . what is the mass number of the other isotope?
Mass number of the other isotope of gallium is 68.92amu
Percent abundance of gallium-71 (given) = 39.892%
Percent abundance of second isotope = 100.000 − 39.892 = 60.108%
Mass of gallium-71 (given) = 70.9247050 amu
Average atomic mass of gallium (from literature) = 69.72 amu
The average atomic mass of gallium is a weighted average of its two isotopes. We set up an equation for the average atomic mass of gallium using the data shown above and solve for "x", the mass of the second isotope:
69.72 amu= (0.39892)(70.92476050 amu) + (0.60108)x
69.72 = 28.29 + 0.60108x
41.43 = 0.60108x
x = 68.92amu
Chemistry's understanding of isotopes is crucial. A chemical element atom with the same number of protons but a different number of neutrons is what we are referring to here. The majority of elements in nature are composed of two or more distinct isotopes rather than existing as a single isotope. Each element therefore has a unique isotope distribution, with the abundances of each isotope being expressed as percent values that add up to 100%. A weighted average of an element's various isotope masses is actually used to determine the standard atomic weight (average atomic mass) that is listed in periodic tables or other publications.
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which size of micropipette would you select to deliver 215 microliters?
The size of micropipette that you would select to deliver 215 microliters would be a micropipette with a volume range of 200-1000 microliters.
What is a micropipette?
A micropipette is a laboratory instrument used to measure and dispense small volumes of liquid, typically in the range of microliters (µL) or nanoliters (nL). They are commonly used in chemistry, biology, and biochemistry experiments, as well as in clinical and industrial settings.
Micropipettes consist of a handle, a digital or manual volume adjustment mechanism, and a tip that is placed into the liquid to be dispensed. They work by creating a vacuum or positive pressure inside the tip, which draws or pushes the liquid out of the tip.
Micropipettes come in different volume ranges and it is important to select the right one to ensure accurate delivery of the desired volume. For example, a micropipette with a volume range of 2-10 microliters would not be suitable for delivering 215 microliters, while a micropipette with a volume range of 200-1000 microliters would be more appropriate.
It's also important to note that, even if the micropipette is able to deliver 215 microliters, you should always check the calibration of the micropipette before use, to make sure that it's delivering the correct volume.
Hence, a micropipette with a volume range of 200-1000 microliters is suitable to deliver 215 microliters.
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An eraser is an example of —
Group of answer choices
an insulator
a closed circuit
a conductor
an open circuit
Answer:
Insulator
Explanation:
An eraser can't conduct electricity, which makes it an insulator.
calculate the boiling point of a solution that contains 0.900 mole of K3 PO4 dissolved in 2750g of water.
The solution was calculated to have a boiling point of 100.167 °C.
How to calculate boiling point?To calculate the boiling point of the solution, use the equation:
ΔTb = Kb × m
where ΔTb = change in boiling point, Kb = boiling point elevation constant for water (0.512 °C/m), and m = molality of the solution.
First, calculate the molality of the solution:
molality (m) = moles of solute / mass of solvent (in kg)
mass of solvent = 2750 g / 1000 = 2.75 kg (conversion to kg)
moles of solute (K3PO4) = 0.900 moles
m = 0.900 / 2.75 = 0.327 mol/kg
Now calculate the boiling point elevation:
ΔTb = Kb × m = 0.512 °C/m × 0.327 mol/kg = 0.167 °C
Finally, calculate the boiling point of the solution:
boiling point of solution = boiling point of pure solvent + ΔTb
The boiling point of pure water is 100 °C, so:
boiling point of solution = 100 °C + 0.167 °C = 100.167 °C
Therefore, the boiling point of the solution is 100.167 °C.
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Convert these formulas equations to word problem
Conversion of formulas equations to word problem are:-
H2 + O2 → H2O. Word equation: Hydrogen gas + Oxygen gas → water
C10H8 + 12O2= 10CO2 + 4H2O Naphthalene +Oxygen= Carbon di oxide +water.
Mg + 2H2O= Mg(OH)+ H2 Magnesium + water= Magnesium Oxide + hydrogen
8Fe + S8= 8FeS Iron + Sulphur = Iron Sulphide.
A word equation example is what?Potassium hydroxide and sulfuric acid are the reactants. Water and potassium sulfate are the end results. potassium hydroxide + sulfuric acid = potassium sulfate + water is the word equation.
How do you spell out CO2 completely?Two oxygen atoms and one carbon atom make up the chemical structure of the gas known as carbon dioxide (CO2).
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