ASAPIf 10 g of oxygen gas is in a 2.00 L container at 50 Cwhat is the pressure in the container ? Round to one decimal place.

We have a 0.020 M NaCl solution with a volume of 350 mL.0.40908 g NaCl is present in 350 mL of 0.020 M NaCl solution.

Let's begin the problem by recalling that molarity is defined as the number of moles of solute per liter of solution. Therefore, the equation we can use to find the number of moles of solute in our solution is:Molarity = \frac{moles of solute}{ liters of solution}

Rearranging this equation gives us the following: moles of solute = Molarity * liters of solution

Next, let's use this equation to find the number of moles of NaCl in our solution. We have a 0.020 M NaCl solution with a volume of 350 mL, which is equal to 0.350 L (since 1 L = 1000 mL).

Therefore ,moles of NaCl = 0.020 mol/L * 0.350 L= 0.007 mol NaCl

Finally, we can use the molar mass of NaCl (58.44 g/mol) to convert the number of moles of NaCl to grams of NaCl:grams of NaCl = moles of NaCl * molar mass of NaCl= 0.007 mol * 58.44 g/mol= 0.40908 g

NaCl is present in 350 mL of 0.020 M NaCl solution, to be precise up to three significant figures.

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The type of compound can be identified by looking at its formula. Ionic compounds typically consist of a metal cation and a non-metal anion, and their formula will look like this: M(+n) X(-m), where M is the metal cation, X is the non-metal anion, and n and m are the charges of the ions.

Covalent compounds contain only non-metals and their formula will look like this: XyZz, where X, Y, and Z are the elements present in the compound and the subscripts (y and z) represent the number of atoms of each element.

Acidic compounds typically have the formula HX, where X is the anion present in the compound.

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The heat required to convert convert 3.12 moles of liquid benzene at 75.1°c to gaseous benzene at 115.1°c is 11,377.08 J

We are given:

Moles of benzene = 3.12 moles

Initial temperature T1 = 75.1Â °C

Final Temperature T2 = 115.1Â °C

The total energy is equal to sensible heat + latent heat

The equation for the change in heat is given is:

Energy = n. Cp, liquid (T,bp - T₁) + nΔH + nCp, gas(T₂ - T, bp)

Where

n is the number of moles

T(bp) refers to the boiling point of benzene at 80.1°C

Cp (liquid) = 134.8 J/mol °C

Cp (gas) = 82.44 J/mol °C

ΔH = 87.1 J/mol

Total Energy = (3.12 moles) x (134.8 J/mol·°C) (80.1°C - 75.1°C) + (3.12 moles) x (87.1 J/ mol) + (3.12 moles) x (82.44 J/mol·°C) x (115.1°C - 80.1°C)

Total Energy = 420.576 J x (5 °C) + [271.752 + 257] [ 35 °C]

Total Energy = 11,377.08 J

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the use of NaOH solution in extraction procedures can help to adjust the pH of the solution, enhance the solubility of organic compounds in the aqueous layer, and help to separate different compounds based on their relative solubilities.

NaOH (sodium hydroxide) solution is often used in extraction procedures to adjust the pH of the solution and to make the organic compounds more soluble in the aqueous layer.

When an organic compound is mixed with water, it may dissolve partially or not at all due to differences in polarity between the two substances. By adjusting the pH of the solution with NaOH, the organic compounds can become more soluble in the aqueous layer because the addition of a basic solution can convert acidic functional groups in the organic compound to their conjugate bases. For example, carboxylic acids (an acidic functional group commonly found in organic compounds) can be converted to their water-soluble carboxylate salt forms by the addition of a basic solution such as NaOH.

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The molarity of the HCl, if the solution has a density of 1. 20 g/ml will be  12.83 M

% of HCL in the solution = 39.0 %

Density of the solution = 1.20 g/ml

Molarity of HCL = ?

Volume of the solution is not given so we take it as 1.0 L

Calculate the mass of silution

   mass = density × volume

    mass of solution = 1.20 g/ml × 1000 ml/L × 1.0 L

    mass of solution = 1200 g

Calculate the mass of HCl

38 %  = 38 g / 100 g

    mass of HCl = 1200 g (39 g / 100 g)

    mass of HCl = 1200g × 0.39 g

    mass of HCl = 468 g

Now calculate the number of moles of HCl

    number of moles = mass / molar mass

    number of moles of HCl = 468 g / 36.46 g

    number of moles of HCl = 12.83 mol

Calculate molarity

    molarity = number of moles of solute / volume L

    molraty HCl = 12.83 mol / 1 L

    molarity of HCl = 12.83 mol/L or 12.83 M

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generally speaking, the Bohr model encapsulates the modern understanding of the atom. This model is often depicted in artwork showing a central atomic nucleus and oval lines representing the orbits of the electrons.

Bohr

Answer:

81 °C

Explanation:

This is a calorimetry question so a few things you will need for this. The calorimetry equation q=mcΔT & the specific heat of water (4.2J/g•°C). Other definitions are:

q = heat added/released by a sample

m = mass of sample

c=specific heat of sample

ΔT = change in temperature

from here we can rearrange the equation to state:

q/(mc) = ΔT

1200J/((20.0g)(4.2J/g•°C)) = ΔT

14°C = ΔT

If the starting temperature was 95.0°C and we know that the temperature was cooled by 14°C then the final temperature of the water would be 81.

Answer:

C. 81 c

Explanation:

took the test :)

Answer:

independent: amount of baking powder

dependent: the banana bread that it produces

constants: the amount of other ingredients/the other ingredients, the type of baking powder, rest of the baking process (heat, temperature, timing of steps), and who's tasting the bread.

Explanation:

The independent variable is the thing that we are directly changing.

We usually change this to test out differences between different amounts of this variable;

This variable is the "x" variable in a function or graph, if it helps you to think of it as that.

The dependent variable is the thing that changes because of the independent variable

Once again, if you think of a graph or function, this would be the "y" variable--it changes in relation to x

The constants are the things that stay the same no matter what the changing variables are

This element is key to an experiment--an experiment would be almost pointless without it. We need to see what is actually changing as a result of the independent and intentional changes.

Here's an example:

Let's say I want to test out how much condensation forms on a bottle based on the temperature of the liquid inside.

I will be changing the temperature of the liquid inside, meaning that this is the independent variable

I will be expecting/looking for a change in the condensation because of my change in the independent variable, meaning that this is the dependent variable

In my experiment, there are some things I need to make sure don't change, so that I can see the effect of my change in the temperature directly--perhaps I need to keep the same bottle shape and size, the same amount of liquid, the same location, the same type of liquid, the same amount of time I let it sit for, etc.  meaning that these are my constants.

So, with all of this in mind, let's take a look at our experiment given.

Here, I will be changing the amount of baking powder that I use, whilst observing the change in the banana bread that it directly produces.

There are a few things I must keep constant: the amount of the other ingredients, the rest of the baking process (heat/temperature, mixing time, etc.), and the type of baking powder I use

There is another consideration that I probably want to keep consistent: who is deciding the taste of the bread. If the person switches, then I might get a different opinion for the same recipe.

hope this helps! have a lovely day :)

Option 2 involves conducting an experiment to find the ideal amount of baking powder to add to a batch of banana bread.

The amount of baking powder served as the independent variable. The goal of this experiment is to determine the ideal amount of baking powder to use in each batch of banana bread.

Dependent Variable: The standard of banana bread served as the dependent variable. It is called the outcome you are measuring or observing in response to a change in the independent variable. In this instance it could be the taste, texture or texture of banana bread.

Constant: Some variables must remain constant throughout the experiment to ensure that only the independent variable has an effect on the dependent variable. Following are some possible constants in this experiment:

By holding these variables constant, you can isolate the effect of different amounts of baking powder on the quality of the banana bread and determine the exact amount needed for best results.

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Answer:

-27.2 kJ

Explanation:

We can use the heat-transfer formula. Recall that:

\(\displaystyle q = mC\Delta T\)

Where m is the mass, C is the substance's specific heat, and ΔT is the change in temperature.

Hence substitute:

\(\displaystyle \begin{aligned} q & = (100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(20.0\text{ $^\circ$C} - 85.0\text{ $^\circ$C}) \\ \\ & =(100.0\text{ g})\left(\frac{4.18\text{ J}}{\text{g-$^\circ$C}}\right)(-65.0\text{ $^\circ$C}) \\ \\ & = -2.72\times 10^4\text{ J} = -27.2\text{ kJ}\end{aligned}\)

Therefore, the cooling of the water released about 27.2 kJ of heat.

Enough kinetic energy and proper orientation are the two requirements for the collision to form a product.

The two requirements for a collision to form a product are enough kinetic energy and proper orientation. When particles collide, they need sufficient kinetic energy to overcome the activation energy barrier. The activation energy is the minimum energy needed for a chemical reaction to occur. If particles possess enough kinetic energy during a collision, it allows the reactants to transform into products by breaking existing bonds and forming new ones.

Proper orientation is crucial because the reactant molecules need to be aligned correctly for a successful reaction to take place. The correct alignment allows for the appropriate interaction between reactive sites on the molecules. If the molecules are not correctly oriented, even with sufficient kinetic energy, the collision may not result in a product formation.

In summary, for a collision to form a product, it is necessary for the reacting particles to have enough kinetic energy to overcome the activation energy barrier and to be properly oriented to enable effective bond formation. Both of these factors play a significant role in determining the rate and success of a chemical reaction.

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The mass of 2 moles of zinc oxide (ZnO) is 162.76g/mol

The International System of Units uses the mole (symbol: mol) as the unit of material quantity. How many elementary entities of a particular substance are present in an object or sample is determined by the quantity of that material. It is specified that the mole contains exactly 6.02214076×\(10^{23}\) elementary entities.

As, we know that

moles = mass / molar mass

so, using the formula

2 = mass / 81.38

mass = 162.76g/mol

So,  the mass of 2 moles of zinc oxide (ZnO) is 162.76g/mol

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Answer:

B) 88.6%

Explanation:

Percent yield equals actual yield divided by theoretical yield

actual yield is 31.0g

theoretical yield is 35g

percent yield was 88.57 which rounds up to 88.6%

Answer:

there is about 6 zeros in 1,000,000

Answer:

6   0's

Explanation:

happy bday #LibraGurl

Answer:

5.52

Explanation:

2.76 10^-3 M = 2.76mM

2.76mM*2L= 5.52mmol

The activity of 1 gram of U3Si2, where uranium is 5% enriched in 235U, is calculated to be 0.394 MCi (megaCuries).

To calculate the activity, we need to consider the radioactive decay of the 235U isotope in U3Si2. The activity can be determined using the decay constant (λ) and the number of atoms of the radioactive isotope present.

Since uranium is 5% enriched in 235U, we can calculate the number of atoms of 235U in 1 gram of U3Si2. Then, using the decay constant for 235U, we can determine the activity.

The detailed calculations involve determining the number of moles of 235U in 1 gram of U3Si2, converting it to the number of atoms, and then multiplying by the decay constant and Avogadro's number to obtain the activity in curies. The final result is 0.394 MCi, indicating the rate of radioactive decay for the given sample.

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Answer:

SEE EXPLANATION

Explanation:

The equation of this reaction is shown below;

CuCO3(s) + H2SO4(aq) ----------> CuSO4(aq) + H2O(l) + CO2(g)

Our intention is to make pure crystals of copper sulfate from copper carbonate and dilute sulfuric acid.

We have to place the dilute sulfuric acid in a beaker and then add copper carbonate using a spatula little by little until the copper carbonate is in excess or effervescence is no longer observed.

The solution is now filtered using a filter paper and funnel. This removes the excess copper carbonate.

The solution is now poured into an evaporating dish/basin and heated using a bunsen burner until crystals of copper sulfate are left behind.

The average rate of the reaction over the first 450 seconds -2.2×10⁻³ M/s

Speed is defined as the rate of change of the distance moved with time. Mathematically, it can be expressed as:

Speed = distance / time

With the above idea, we can obtain the rate of the reaction as illustrated below:

Rate = Change in concentration / time

Rate = -1 / 450

Rate = -2.2×10⁻³ M/s

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D is correct for number 2. i just finished

explanation; i got it right

Answer B

From least luminous to most luminous:

White dwarf A star - White dwarfs are small, dense, and dim stars that have exhausted their nuclear fuel and have cooled down. They emit very little light, and their luminosity is much lower than that of most other types of stars.

Red giant K star - Red giants are large and relatively cool stars that have exhausted the hydrogen fuel in their cores and have expanded to several times their original size. They are brighter than main-sequence stars like our Sun but less bright than supergiants.

Supergiant F star - Supergiants are massive and luminous stars that are in the last stages of their lives. They are much larger and brighter than most other types of stars, including red giants, and have a high luminosity. F-type supergiants are particularly bright and have a high surface temperature.

Earth's main wind patterns are the result of the Earth's rotation.

Winds is a term to refer to a climatic factor in which bodies of air move in a specific direction. Winds influence various terrestrial phenomena such as:

On Earth, global wind patterns are influenced by several factors. However, the most important is the rotation of the planet, because this creates counterclockwise rotations of low pressure cells in the northern hemisphere, and a corresponding clockwise rotation in the southern hemisphere (the Coriolis effect).

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The mole ratio between sodium bicarbonate and that of acetic acid is 1:1

A mole ratio can be defined as that ratio in whole numbers between the amounts in moles of any two compounds involved in a balanced chemical reaction.

In conclusion, the mole ratio between sodium bicarbonate and that of acetic acid is 1:1

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A statement that stores the uppercase equivalent of the string referenced by the city variable is as follows:

uppercity = city.toUpperCase();

```

To store the uppercase equivalent of the string referenced by the variable "city" in the variable "uppercity," you can use the "toUpperCase()" method in Java. In the given code snippet, the "toUpperCase()" method is applied to the "city" variable and the resulting uppercase string is assigned to the "uppercity" variable.

The "toUpperCase()" method is a built-in function in Java that converts all the characters in a string to uppercase. It returns a new string with all uppercase characters, while leaving the original string unchanged. By invoking this method on the "city" variable, we ensure that the resulting uppercase string is assigned to the "uppercity" variable.

Using the "toUpperCase()" method is a convenient and straightforward way to convert a string to its uppercase form. It eliminates the need for manual conversion and provides a more concise and readable code.

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The molecular formula of the compound is (d) \(S_2O_6\).

The molar mass of a compound represents the mass of one mole of that compound. To determine the molecular formula, we need to find the ratio between the empirical formula and the molecular formula. The empirical formula gives the simplest whole-number ratio of atoms in a compound. In this case, the empirical formula is \(SO_2\), indicating that for every one sulfur atom, there are two oxygen atoms.

To find the molecular formula, we need to compare the molar mass of the empirical formula with the given molar mass of the compound. The molar mass of the empirical formula \(SO_2\) can be calculated by adding the atomic masses of sulfur (S) and oxygen (O):

Molar mass of \(SO_2\) = (32.07 g/mol for S) + (2 × 16.00 g/mol for O) = 64.07 g/mol.

Since the molar mass of the empirical formula matches the given molar mass of the compound, the empirical formula is also the molecular formula. Therefore, the molecular formula of the compound is \(S_2O_6\).

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The the mass of the heavier isotope of chlorine (in amu) is 73.932 amu.

The term isotopes refers atoms that have the same atomic number but different mass number. We must know that all these atoms belong to the same element an differ only in the number of neutrons present in the atom of the element. Hence isotopes are different atoms of the same element hence they have the same chemical properties or reactivity. The mass spectrum is able to show the masses of each of the isotopes according to their order of relative abundance in nature.

Looking at the peaks, we know that the heaviest isotope is the one whose mass will have the highest peak as shown in the mass spectrum of the element as shown. Thus, the the mass of the heavier isotope of chlorine (in amu) is 73.932 amu. The mass spectrum of element also shows this fact.

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The partial pressure of N₂ is 3.75 atm, the partial pressure of O₂ is 2.50 atm, and the partial pressure of CO₂ is 1.25 atm in the given mixture at 25 °C and a total pressure of 10.0 atm.

To calculate the partial pressure of each gas in the mixture, we can use the concept of Dalton's law of partial pressures. According to this law, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas.

First, we need to find the mole fraction of each gas in the mixture. The mole fraction of a gas is the ratio of the number of moles of that gas to the total number of moles in the mixture. We can calculate the mole fraction using the following formula:

Mole fraction (X) = Moles of gas / Total moles of all gases

For N₂:

Mole fraction of N₂ (X_N₂) = 3.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.375

For O₂:

Mole fraction of O₂ (X_O₂) = 2.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.250

For CO₂:

Mole fraction of CO₂ (X_CO₂) = 1.00 mol / (3.00 mol + 2.00 mol + 1.00 mol) = 0.125

Next, we can use the mole fractions to calculate the partial pressures of each gas. The partial pressure of a gas is equal to the mole fraction of that gas multiplied by the total pressure of the mixture.

Partial pressure of N₂ (P_N₂) = X_N₂ * Total pressure = 0.375 * 10.0 atm = 3.75 atm

Partial pressure of O₂ (P_O₂) = X_O₂ * Total pressure = 0.250 * 10.0 atm = 2.50 atm

Partial pressure of CO₂ (P_CO₂) = X_CO₂ * Total pressure = 0.125 * 10.0 atm = 1.25 atm

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Which of the following compounds do not contain an sp3 hybridized oxygen atom is option E) water. The oxygen atom in an sp3 hybridized state has a tetrahedral arrangement of its bonds, which is achieved through the hybridization of one s orbital and three p orbitals.

This creates four identical sp3 hybrid orbitals that point to the vertices of a tetrahedron. Each of the listed chemical substances has an oxygen atom bonded to other atoms or functional groups.

The following is a brief explanation of each of them: Ketones contain a carbonyl group, which consists of a carbon atom with a double bond to an oxygen atom, and two additional carbon-containing groups. As a result, the oxygen atom in a ketone is sp2 hybridized, with one lone pair in an unhybridized p orbital.Alcohols have an -OH functional group, which consists of an oxygen atom covalently bonded to a hydrogen atom and a carbon-containing group. The oxygen atom in an alcohol is also sp3 hybridized.

Ethers have two carbon-containing groups connected to an oxygen atom. The oxygen atom in an ether is sp3 hybridized.Esters have a carbonyl group and an alkoxy group (-OR). The oxygen atom in an ester's carbonyl group is sp2 hybridized, while the oxygen atom in the -OR group is sp3 hybridized. Water, on the other hand, is composed of two hydrogen atoms and an oxygen atom, with no other atoms connected to the oxygen atom. In water, the oxygen atom is also sp3 hybridized, with two lone pairs and two single bonds to hydrogen atoms. Therefore, Option E is correct.

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Explanation:

Big C carbon surrounded by He helium

(b) false

It is not ok to pour it back in the bottle

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The acid H3PO4 can donate three hydrogen ions (H+) per molecule.

Thus, the number of H+ ions that the acid H3PO4 can donate per molecule is 3.Explanation:H3PO4 is also known as phosphoric acid. Phosphoric acid is an inorganic mineral acid that is commonly used in fertilizers, detergents, and food additives.

The chemical formula of H3PO4 is H3PO4 which implies that it has three hydrogen ions that are attached to the phosphate anion.Each hydrogen ion, which is donated by H3PO4, has the ability to donate a single positive hydrogen ion or proton (H+).

Therefore, since H3PO4 has three hydrogen ions, it has the ability to donate three H+ ions per molecule (per H3PO4 molecule).

In other words, one molecule of H3PO4 can donate three hydrogen ions.

Therefore, the number of H+ ions that the acid H3PO4 can donate per molecule is 3.

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