As you go up in elevation, the atmospheric pressure ________.

Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

\(volume = \frac{mass}{density} \\\)

From the question

mass = 24 g

density = 1.2 g/mL

We have

\(volume = \frac{24}{1.2} \\ \)

We have the final answer as

Hope this helps you

Answer:

probly c or b

Explanation: experinse

A light-year is a unit of distance, specifically the distance that light travels in one year.

Light travels at a speed of approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum. Therefore, to determine which planet is 20 light-years away from Earth, we need to identify a planet located at a distance of approximately 20 times this speed of light.

As of my knowledge cutoff in September 2021, no known exoplanets have been directly observed and confirmed to be located exactly 20 light-years away from Earth. However, there are numerous exoplanets that have been discovered within a range of distances from Earth.

Some notable exoplanets discovered within approximately 20 light-years of Earth include:

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Answer:

The distance between the Earth and the Sun is:

1.5 multiplied by 10 raised to the power 8 km

Explanation:

(5.0 x 10²) x (3.0 x 10⁸) = 1.5 x 10¹¹ meters = 1.5 x 10⁸ km.

Explanation:

According to newtons first law of motion " A body is at a state of rest or uniform motion unless acted upon by a force (external)" which will either

1. change the direction

2. change the acceleration

3. change the velocity(moves or stop the body from moving)

4. change the shape or size

Answer:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. The total momentum of the trolleys after separation is zero

c. The momentum of the 2 kg trolley after separation is 12 kg·m/s

d. The momentum of the 3 kg trolley is -12 kg·m/s

e. The velocity of the 3 kg trolley = -4 m/s

Explanation:

a. The total momentum of the trolleys which are at rest before the separation is zero

b. By the principle of the conservation of linear momentum, the total momentum of the trolleys after separation = The total momentum of the trolleys before separation = 0

c. The momentum of the 2 kg trolley after separation = Mass × Velocity = 2 kg × 6 m/s = 12 kg·m/s

d. Given that the total momentum of the trolleys after separation is zero, the momentum of the 3 kg trolley is equal and opposite to the momentum of the 2 kg trolley = -12 kg·m/s

e. The momentum of the 3 kg trolley = Mass of the 3 kg Trolley × Velocity of the 3 kg trolley

∴ The momentum of the 3 kg trolley = 3 kg × Velocity of the 3 kg trolley = -12 kg·m/s

The velocity of the 3 kg trolley = -12 kg·m/s/(3 kg) = -4 m/s

a-The total momentum of the trolleys before separation=0

b.The total momentum of the trolleys after  separation=0

c. The momentum of 2kg trolley after  separation=12kg-m/sec

d. The momentum of 3kg trolley after separation=-12kg-m/sec

e. The velocity of the 3kg trolley=4kg-m/sec

Given-

Trolley A with mass= 2kg

Trolly B with mass= 3kg

Velocity of trolly A =6m/sec

A- Total momentum of the trolleys before separation-

Here, in this problem both the trolleys are in the rest position hence the momentum of both trolleys = 0

B- Total momentum of the trolleys after  separation-

We know that motion never changes in an isolated collection of objects,

hence the momentum of the trolleys before and after the separation=0

C- Momentum of the Trolley A (2kg)-

It is known that momentum= Mass x Velocity

\(P=m\times v\)

\(P=2\times 6\)

\(P=12\)

Hence, the momentum of the 2kg trolley is 12 kg-m/sec

D- Momentum of the Trolley B (3kg)-

As we know that  motion never changes in an isolated collection of an object hence the total moment of after saparation = 0

hance the momentum of the trolley B will be equal and opposite to the momentum of trolley A=

\(P= -12\)

Momentum of trolley B (3kg) is -12kg-m/sec

E- The velocity of the 3kg trolley-

The momentum of trolley A= Momentum of trolley B

\(m_{b} v_{a} =m_{b} v_{a}\)

\(-2\times 6=3\times v_{a}\)

\(v_{a}=-4\)

The value of the velocity of the 3kg trolley is -4m/sec

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Astronomers much more interested in the luminosity of a star than its apparent brightness are because the luminosity tells us how bright a star really is, while apparent brightness only tells us how bright it happens to look from Earth.

Luminosity refers to the total amount of energy that a star radiates per unit time. It is a fundamental property of a star that is directly related to its mass, size, and temperature. Luminosity is measured in units of watts and is often expressed relative to the luminosity of our sun, which is called solar luminosity.

Luminosity is a critical parameter for studying stars because it provides insight into their physical properties and evolutionary history. By measuring a star's luminosity and combining it with its temperature and distance, astronomers can determine its size, mass, and age. Luminosity is also used to classify stars into different categories based on their brightness and temperature.

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Answer:

1609.3

Explanation:

(105 N/m) x (0.1 m)  =  10.5 Newtons.

Answer:

(105 N/m) x (0.1 m) = 10.5 Newtons.

Explanation:

apex quiz

Explanation:

vertical force = 460,000 * sin(70) - 300,000

Fv = 187,717.75N

The new velocity of the ball is 17.7 m/s north-east.

Velocity can be defined as the rate of change of displacement.

The S.I unit of velocity is m/s.

To calculate the magnitude and direction of the new velocity, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the new velocity of the ball is 17.7 m/s north-east.

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Given, Area of first piston (a₁) = 0.006 m²Area of second piston (a₂) = 0.6 m²Weight of the car (W) = 10000 NUsing the formula of force transmitted in hydraulic press:F = (a₂/a₁) * FW is the weight of the car, which needs to be raised.

Let's calculate the force F exerted by the fluid on the smaller piston using the above formula:We getF = (a₂/a₁) * FW = 10000 NF = (0.6/0.006) * 10000F = 600000 NSo, the fluid must exert a force of 600000 N on the smaller piston if the larger piston will raise a car with a weight of 10000 N. The hydraulic lift is a significant example of the working of the PASCAL law, which states that when there is pressure applied at any point in a fluid, it is uniformly transmitted in all directions. In a hydraulic lift, the hydraulic fluid exerts a force on a piston that is then transmitted through the liquid in all directions and ultimately raises a larger piston, which lifts the load. In this way, a small force can lift a heavier load, and this is known as force multiplication. Let's consider an example where we have a hydraulic car lift. The car lift consists of two pistons with different areas. The smaller piston has an area of 0.006 m², while the larger piston has an area of 0.6 m². If we apply a force on the smaller piston, the hydraulic fluid inside the cylinder transmits this force throughout the fluid. As a result, equal pressure is applied on the larger piston, and the load is lifted. The larger piston raises the car, which has a weight of 10000 N. To find the force exerted by the fluid on the smaller piston, we can use the formula: F = (a₂/a₁) * FW is the weight of the car, which needs to be raised. Substituting the given values in the above formula, we get F = (0.6/0.006) * 10000F = 600000 N. Therefore, the fluid must exert a force of 600000 N on the smaller piston to raise a car with a weight of 10000 N. Thus, the hydraulic lift works on the principle of force multiplication.

In summary, the hydraulic lift is a crucial example of the working of the Pascal law. It works on the principle of force multiplication, where a small force can lift a heavier load. In a hydraulic lift, the hydraulic fluid exerts a force on a piston that is transmitted through the liquid, ultimately lifting the larger piston. To calculate the force exerted by the fluid on the smaller piston in a hydraulic car lift, we can use the formula F = (a₂/a₁) * Fw. In this case, the fluid must exert a force of 600000 N on the smaller piston if the larger piston will raise a car with a weight of 10000 N.

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The wavelength shift Δλ of the exoplanetary system at a wavelength of 3168 angstroms, caused by a Doppler shift of 1.5 km per second, is approximately 1.584 * 10⁻¹² angstroms.

To calculate the wavelength shift Δλ caused by the Doppler shift, we can use the formula:

Δλ = λ * (v / c)

Where:

Δλ is the wavelength shift

λ is the original wavelength

v is the velocity causing the Doppler shift

c is the speed of light in a vacuum

In this case, the original wavelength is given as W angstroms, which is equivalent to W * 10⁻¹⁰ meters. The velocity causing the Doppler shift is 1.5 km/s, which is equivalent to 1.5 * 10³ meters per second. The speed of light in a vacuum is approximately 3 * 10⁸ meters per second.

Plugging in these values into the formula:

Δλ = (W * 10⁻¹⁰) * (1.5 * 10³ / (3 * 10⁸))

Simplifying further:

Δλ = W * 10⁻¹⁰ * 5 * 10⁻⁶

Combining the exponents:

Δλ = 5 * 10⁻¹⁶ * W

Now, substituting the given value for W:

Δλ = 5 * 10⁻¹⁶  * 3168

Calculating the product:

Δλ = 1.584 * 10⁻¹² angstroms

Therefore, the wavelength shift Δλ of the exoplanetary system at a wavelength of 3168 angstroms, caused by a Doppler shift of 1.5 km per second, is approximately 1.584 * 10⁻¹²  angstroms.

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Answer:

False

Explanation:

he proposed that Pangea drifted apart int what is now the continents

pleaase mark brainliest

Answer:

it's green chilly or red chilly

Explanation:

I hope it's correct!

∅=2021rad  is the phase difference (in radians) in the light from the two slits.

using the formula below

Φ =( \(2\pi d/\)β )sinα

∅=2021rad

The time difference between the same points within the two sounds' wave cycles (the peaks or positive-going zero crossings, for example), expressed as a fraction of one wave cycle, determines the phase difference between two sound waves of the same frequency travelling past a fixed spot.

Phase shift occurs when the sine and cosine function graphs are moved to the left or right of where they usually are, or we can say that the function is moved horizontally how far from its normal position. Functions are typically moved  from their normal place.

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After getting the acceleration of the object, the calculated velocity is 8 m/s

Velocity is the distance travelled by an object in a specific direction. It is a vector quantity. And it is measured m/s

Given that a force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg, before we calculate its velocity, we need to calculate its acceleration by using the formula

F = ma

Where

Substitute the parameters into the formula

80 = 10a

a = 80/10

a = 8 m/s

To calculate its velocity, use the formula

v² = u² + 2as

where u = 0

v² = 0 + 2 × 8 x 4

v² = 64

v = √64

v = 8 m/s

Therefore, the velocity of the object is 8 m/s

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Friction is the force that acts on the opposite side of direction of force, thus it manages to decelerate an object, so it acts upward along the plane

The location at which the net gravitational force exerted on the spaceship is approximately zero is position c. The correct option is c.

Gravity, also known as gravitational force, pulls objects with mass toward one another. We frequently consider the force of gravity from Earth. This force is responsible for keeping your body on the ground.

Any item with mass, on the other hand, exerts a gravitational force on all other objects with mass. There is a net force because the force exerted by the Earth exceeds the force exerted by the Moon.

Therefore, the correct option is c, position C.

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The question is incomplete. Your most probably complete question is given below:

The image is also added below:

A. position A.

B. position B.

C. position C.

D. cannot be determined.

Hoodlum's speed at the lowest point of the circular-shaped dip is approximately 26.5 m/s second law of motion states that the force acting on an object is equal to its mass times its acceleration, and it is given by the formula F=ma.  when a vehicle goes over a bump or dip

in the road, the force on the seat and the vehicle must be considered as it moves up and down. The seat is responsible for producing an upward force on the occupant of the vehicle. When the vehicle reaches the lowest point of the circular-shaped dip, the force required to support the occupant equals their weight plus the required force for the seat to support them, as per the problem. Using the formula F = ma and rearranging to solve for the acceleration, we have that a = F/m. At the lowest point of the dip, the acceleration is the sum of the radial acceleration, which is directed towards the center of the circle, and the tangential acceleration, which is directed tangent to the circle. Centripetal force Fc = ma_r is given by Fc = mv^2 / r, where m is the mass of the vehicle and v is its speed at the bottom of the dip. In this case, the upward force required is equal to the sum of the weight of the hoodlum and the force required for the seat to support him, or 250 lb, which is equivalent to 1112.4 N.

Therefore, F_ total = m(g+a_r) = 1112.4 N, where g is the acceleration due to gravity (9.8 m/s^2). At the same time, the tangential acceleration is zero, implying that F_total = F_r = mv^2 / r. Therefore, v = sqrt(rF_total / m) = sqrt(50*1112.4/77) = 26.5 m/s. Hence, Hoodlum's speed at the lowest point of the circular-shaped dip is approximately 26.5 m/s The radius of the circular-shaped dip is given as 50 m.The upward supporting force exerted by the seat on the Hoodlum is 250 .The weight of the Hoodlum is 170 lb.We need to calculate his speed at the lowest point of the circular-shaped dip. At the lowest point of the dip, the acceleration is the sum of the radial acceleration, which is directed towards the center of the circle, and the tangential acceleration, which is directed tangent to the circle.Centripetal force Fc = ma_r is given by Fc = mv^2 / r, where m is the mass of the vehicle and v is its speed at the bottom of the dip.Therefore, F _total = m(g +a_r) = 1112.4 N, where g is the acceleration due to gravity (9.8 m/s^2).At the same time, the tangential acceleration is zero, implying that F_total = F_r = mv^2 / r.

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Answer:

Is it a sin to like them all...? haha

Answer:

Schlatt, Nikki, Tubbo, and Wilbur :O

Explanation:

how is this a question lol-

Answer:

The Natural sounds contained sounds of living objects. The Musical sounds contained notes of different musical instruments, whereas the Artificial sounds were daily object-like sounds.

Explanation:

hope this helps!

Answer:

11

Explanation:

i've been in k12 and i got an a on this anser

The velocity of the satellite is V = \(\frac{V}{\sqrt{6} }\)

The speed at which one body orbits the other body is known as the orbital velocity. The term "orbit" refers to an object's consistent circular motion around the Earth. The distance between the object and the earth's center determines the orbit's velocity.

In contrast to the orbital velocity, the angular velocity of the revolving disc is constant at all mass sites (of which the disc is composed). The orbital velocity, on the other hand, rotates the disk in a different direction at each site and is tangential to the circular orbit.

We can derive the mathematical equation of orbital velocity :

v = \(\sqrt{\frac{GM}{r} }\)

where, v = orbital velocity

G = gravitational constant

M = mass of the satellite

r = radius

V = \(\sqrt{\frac{GM}{6r} }\)

V = \(\sqrt{\frac{1}{6} }\) ×    \(\sqrt{\frac{GM}{r} }\)

Thus we can write it as:

V = \(\frac{V}{\sqrt{6} }\)

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The energy of the wavelength of the photon is 258 m.

Given:

f = 1160 kHz = 1160 x 10³ Hz

The velocity is c = 3 x 10⁸ m/s, the velocity of light (approximately).

The reflectance curve for a white piece of paper would reflect Long, medium and short wavelengths equally.

white piece paper serves as perfectly reflective surfaces and reflects all the incident radiations without any absorbtion or transmission. Hence a white piece of paper would reflect Long, medium and short wavelengths equally.

ultra violet rays has larger wavelength than radio waves.

As we know that the energy is inversely proportional to the wavelength.

The energy of radio waves is more than the energy of ultra violet waves.

Energy of ultra violet photons < Energy of radio waves

Wavelength of ultra violet photons > Wavelength of radio waves

Wavelength(lambda) is the distance between one peak to the next peak or one trough to another trough parallel to the direction of propagation.

Calculate the wavelength, λ.

V = f λ

V is the speed

F is the frequency  

F λ is wavelength  

c = fλ

λ = c/f = (3 x 10⁸ m/s)/(1160 x 10³ 1/s) = 258 m

Therefore the energy of the wavelength of the photon is 258 m.

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[NOTE: THIS QUESTION IS AN INCOMPLETE QUESTION. THE COMPLETE QUESTION IS: What is the wavelength of a radio photon from an "am" radio station that broadcasts at 1160 kilohertz? What is its energy?]

Answer:

125N

Explanation:

force =mass×acceleration

50 =mass×8m/s2

mass=6.25kg

Answer with Explanation:

We can use the formula for acceleration to find the train's acceleration:

acceleration = (final velocity - initial velocity) / time

In this case, the initial velocity of the train is 60 m/s (since that's how fast it was going before it hit the brakes), the final velocity is 0 m/s (since the train comes to a complete stop), and the time it takes for the train to stop is 1 minute and 40 seconds, or 100 seconds.

So, plugging in the values we have:

acceleration = (0 m/s - 60 m/s) / 100 s

acceleration = -60 m/s / 100 s

acceleration = -0.6 m/s^2

Note that the negative sign indicates that the train is decelerating (slowing down), as opposed to accelerating (speeding up).