artaric acid, H2C4H4O6, has two acidic hydrogens. The acid is often present in wines and precipitates from solution as the wine ages. A solution containing an unknown concentration of the acid is titrated with NaOH. It requires 21.65 mL of 0.3500 M NaOH solution to titrate both acidic protons in 50.00 mL of the tartaric acid solution. You may want to reference (Pages 149 - 153) Section 4.6 while completing this problem. Part A Write a balanced net ionic equation for the neutralization reaction. Express your answer as a chemical equation including phases.

Answer:The ice will melt

Explanation:

The sun is the source, and the change is damage

Answer:

Option (c)

Explanation:

The characteristic properties of a metal tungsten are as follows :

Out of the given options, option (c) gives the best properties of the metal tungsten make it useful in the thin, glowing filaments of light bulbs i.e. ".Tungsten is ductile, has a high melting point, and is electrically conductive"

I hope the answer you are looking for is 5.51L

sorry if I'm wrong

Answer:

Aà bhûtÿ ñhjkjłfd hÿrèërqw

Explanation:

We know that the dipole moment moves from the negative to the positive line thus it is shown by option A

The dipole moment is a measure of the polarity of a chemical bond or a molecule. It is defined as the product of the magnitude of the charge on either end of a polar covalent bond and the distance between them. The dipole moment of a molecule is a vector quantity, with a direction pointing from the negatively charged end of the molecule to the positively charged end.

In simple terms, the dipole moment represents the separation of positive and negative charges within a molecule. The greater the dipole moment of a molecule, the more polar it is and the more likely it is to interact with other polar molecules or ions.

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PPE should be worn in the presence of chemical hazards to protect the individual from potential harm. Its usage should be dictated by the presence of the hazard, not by memory or peer action.

You should wear Personal Protective Equipment (PPE) to protect yourself from chemical hazards whenever chemical hazards are present (Option B). PPE is designed to protect you from harmful exposure and injuries. The use of PPE must be based on the hazard presented, not simply when remembered or when others are using it. Hence, whenever you are dealing with chemical hazards, it's crucial to wear the appropriate PPE, which could include items such as gloves, eye protection, protective clothing, and respirators.

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Answer:

Given:

Volume of wet hydrogen gas (Vwet) = 4.00 L

Pressure (P) = 737 torr

Temperature (Twet) = 23.0°C = 296 K

To find:

Volume of dry hydrogen gas (Vdry) at STP (Tdry = 273 K and Pdry = 760 torr)

Solution:

Convert temperature to Kelvin: T = Twet = 23.0°C + 273 = 296 K

Use the combined gas law: P1V1/T1 = P2V2/T2

Plug in values: P1 = P, V1 = Vwet, T1 = T, P2 = Pdry = 760 torr, T2 = Tdry = 273 K

Solve for V2 (Vdry): Vdry = Vwet x Pdry x T / P x Tdry

Substitute values: Vdry = 4.00 L x 760 torr x 296 K / 737 torr x 273 K

Simplify: Vdry ≈ 3.48 L

Therefore, the volume of dry hydrogen gas at STP is approximately 3.48 L.

So the answer key is correct, but their method may have been incorrect.

A titration's end can be indicated by an indicator because a significant pH change happens close to the standard solution of acid-base titrations. For acid-base titrations, use an indicator.

Acid-base titration is the term for a procedure that uses an acid-base reaction. It is known as a redox titration whenever a reduction process is used. Quantitative chemical analysis is a sort of titration, commonly referred to as volumetric analysis.

To determine the equivalency or the point in a reaction where a pH change occurs, indicators are therefore utilized in titrations. As an additional indicator that changes the color when pH changes, methylene yellow is also employed. In acidic solution, it is colored red, whereas in basic solution, it is colored yellow.

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Answer:

Explanation:

Here, we want to select the exothermic process

An exothermic process is one in which heat is released to the environment or surroundings

It simply involves the transfer of heat from the reaction system into the surroundings

An example of this is the solidification of molten gold

Taking into account the reaction stoichiometry, 0.1129 moles of P₄ is required to react with with 700.0 grams of calcium phosphate.

In first place, the balanced reaction is:

2 Ca₃(PO₄)₂ + 6 SiO₂ + 10 C → 6 CaSiO₃ + 10 CO + P₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 620 grams of Ca₃(PO₄)₂ produces 1 mole of P₄, 70 grams of Ca₃(PO₄)₂ produces how many moles of P₄?

\(moles of P_{4} =\frac{70 grams of Ca_{3}(PO_{4} )_{2}x1 mole of P_{4} }{620 grams of Ca_{3}(PO_{4} )_{2}}\)

moles of P₄= 0.1129 moles

Finally, 0.1129 moles of P₄ is required to react with with 700.0 grams of calcium phosphate.

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1. Height of the shooter: approximately 183.20 ft.

2. Height of the shooter: approximately 880.24 ft.

3. Height of the shooter: approximately 229.33 ft.

1. Given: Angle of trajectory: 15°

Distance to the building: 700 ft

Height of the victim: 6.0 ft

Using trigonometry, we can write the equation:

tan(angle) = opposite/adjacent

tan(15°) = 6.0 ft/h

h = 700 ft * tan(15°) / 1

h ≈ 183.20 ft

Therefore, the height of the shooter is approximately 183.20 ft.

2. Using the trigonometric equation, we have:

tan(angle) = opposite/adjacent

tan(35°) = 4.8 ft/h

Rearranging the equation, we get:

h = 1000 ft * tan(35°) / 1

h ≈ 880.24 ft

Therefore, the height of the shooter is approximately 880.24 ft.

3.h = 500 ft * tan(25°) / 1

h ≈ 229.33 ft

Therefore, the height of the shooter is approximately 229.33ft.

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Answer:

Mass of compound c = 6 g

Explanation:

Given:

Mass of compound a = 2.5 g

Mass of compound b = 3.5 g

Find:

Mass of compound c

Computation:

According to Law of conservation of mass

Mass of compound a + Mass of compound b = Mass of compound c

Mass of compound c = 2.5 + 3.5

Mass of compound c = 6 g

a) In the reaction \(H_2CO_3 + CN^- = HCN + HCO^{3-}\), \(H_2CO_3\) acts as an acid by donating a proton (\(H^+\)) to \(CN^-\).

b) In the reaction \(F^- + HSO_4^{-} = HF + SO_4^{2-}\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(F^-\).

c) In the reaction \(HSO_4^- + H_2O = H_3O^+ + SO_4^{2-\), \(HSO_4^{-}\) acts as an acid by donating a proton (\(H^+\)) to \(H_2O\).

a) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

b) The acid is both an Arrhenius acid (produces \(H^+\) ions in water) and a Bronsted-Lowry acid (donates a proton to a base).

c) The acid is a Bronsted-Lowry acid (donates a proton to a base) but not an Arrhenius acid because it does not produce \(H^+\) ions in water. However, the \(H_3O^+\) ion that is formed can be considered an Arrhenius acid because it produces \(H^+\) ions in water.

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Answer:

boi i need the choices idiot

Explanation:

Nobody can add an answer without context.

But if this helps,

"Vaporization of an element or compound is a phase transition from the liquid phase to vapour. There are two types of vaporization: evaporation and boiling. Evaporation is a surface phenomenon, whereas boiling is a bulk phenomenon." - Wikipedia

https://en.wikipedia.org/wiki/Vaporization

Answer:

a. <1.0

b. 1.30

c. 3.00

d. 11.00

e. 12.70

Answer:

\(\rm CH_2\).

Explanation:

Carbon and hydrogen are the only two elements in a hydrocarbon. When a hydrocarbon combusts completely in excess oxygen, the products would be \(\rm CO_2\) and \(\rm H_2O\). The \(\rm C\) and \(\rm H\) would come from the hydrocarbon, while the \(\rm O\) atoms would come from oxygen.

Look up the relative atomic mass of these three elements on a modern periodic table:

Calculate the molar mass of \(\rm CO_2\) and \(\rm H_2O\):

\(M(\mathrm{CO_2}) = 12.011 + 2 \times 15.999 = 44.009\; \rm g \cdot mol^{-1}\).

\(M(\mathrm{H_2O}) = 2 \times 1.008 + 15.999 = 18.015\; \rm g \cdot mol^{-1}\)

Calculate the number of moles of \(\rm CO_2\) molecules in \(33.01\; \rm g\) of \(\rm CO_2\!\):

\(\displaystyle n(\mathrm{CO_2}) = \frac{m(\mathrm{CO_2})}{M(\mathrm{CO2})} = \frac{33.01\; \rm g}{44.009\; \rm g\cdot mol^{-1}} \approx 0.7501\; \rm mol\).

Similarly, calculate the number of moles of \(\rm H_2O\) molecules in \(13.51\; \rm g\) of \(\rm H_2O\!\):

\(\displaystyle n(\mathrm{H_2O}) = \frac{m(\mathrm{H_2O})}{M(\mathrm{H_2O})} = \frac{13.51\; \rm g}{18.015\; \rm g\cdot mol^{-1}} \approx 0.7499\; \rm mol\).

Note that there is one carbon atom in every \(\rm CO_2\) molecule. Approximately\(0.7501\; \rm mol\) of \(\rm CO_2\!\) molecules would correspond to the same number of \(\rm C\) atoms. That is: \(n(\mathrm{C}) \approx 0.7501\; \rm mol\).

On the other hand, there are two hydrogen atoms in every \(\rm H_2O\) molecule. approximately \(0.7499\; \rm mol\) of \(\rm H_2O\) molecules would correspond to twice as many \(\rm H\!\) atoms. That is: \(n(\mathrm{H}) \approx 2 \times 0.7499 \; \rm mol\approx 1.500\; \rm mol\).

The ratio between the two is: \(n(\mathrm{C}): n(\mathrm{H}) \approx 1:2\).

The empirical formula of a compound gives the smallest whole-number ratio between the elements. For this hydrocarbon, the empirical formula would be \(\rm CH_2\).

Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).

The Nernst equation is given as follows:

E = E° - (RT/nF) * ln(Q)

Given information:

Ksp = 1 × 10^(-12)

E = +0.799 V (standard reduction potential of Ag+ to Ag)

Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].

Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.

Therefore, Q = Ksp = 1 × 10^(-12).

Substituting the values into the Nernst equation, we have:

0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))

Now, solving for E°:

E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))

The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.

Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.

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Answer:

The answer would be a line graph because it is used to track changes over time.

The percent by mass of the carbon is 30.4%.

The term percentage has to do with the ratio of the mass of a particular atom to the total mass of the compound multiplied by one hundred. Thus the first step is to find the total mass or the molar mass of the compound.

Molar mass = 40 + 2(2(12) + 3(1) + 2(16))

= 40 + 2(24 + 3 + 32)

= 40 + 2(59)

= 40 +118

= 158

Thus the mass of carbon is;

4(12)/158 * 100/1

= 30.4%

Thus carbon is only about 30.4% by mass of the compound.

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Answer:

2.64 M

Explanation:

Use the dilution equation M1V1 = M2V2, where:

M1 = 12.0 M HCl

V1 = 220 mL HCl

M2 = ?

V2 = 1000 mL HCl

(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)

M2 = 2.64 M HCl

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

First, we need to determine the molar mass of HCl.

The molar mass of HCl = the mass of hydrogen (1.008 g/mol) + the mass of chlorine (35.45 g/mol) = 36.45 g/mol.

Next, we can use Avogadro's number (6.02 x 10^23 molecules/mol) to convert the number of molecules to moles:

6.02 x 10^24 molecules / 6.02 x 10^23 molecules/mol = 10 moles

Finally, we can use the molar mass to convert moles to grams:

10 moles x 36.45 g/mol = 364.5 grams

Therefore, the mass of 6.02 x 10^24 molecules of HCl is 364.5 grams.