arrangement around the central atom in BrF4

By using filtration, the sand and fine salt can be effectively separated based on their difference in particle size, providing a clean separation of the two components.

Filtration is a separation technique that takes advantage of the difference in particle size between sand and salt. It involves passing the mixture through a porous material, such as filter paper or a filter funnel, which allows the liquid (saltwater) and small salt particles to pass through while retaining the larger sand particles.

Here's how the filtration process can be carried out:

1. Set up a filter apparatus with a funnel and filter paper or a filter flask.

2. Place the mixture of sand and salt in a beaker or a flask.

3. Slowly pour the mixture into the filter paper or funnel, allowing the liquid (saltwater) to pass through while retaining the sand on the filter paper.

4. Once the liquid has passed through completely, the sand will be left behind on the filter paper or in the filter flask.

5. Carefully remove the sand from the filter paper or filter flask, and the saltwater solution can be collected separately.

For more such questions on filtration

https://brainly.com/question/29756050

#SPJ8

Answer:

It's True.

Explanation:

Matter is anything that has mass and takes up space. Mass gives an object the property of weight and inertia (resistance to change in the motion of an object). There are four states of matter, solid, liquid, gas, and plasma.

Answer:

B 1650

Explanation:

The volume in mL of the pellets in your bag is 7.76mL.

Density is the measure of the mass of matter contained by a unit volume.

The density of a substance can be calculated using the following formula:

Density = mass ÷ volume

According to this question, a certain element has a density of 10.5 g/ml. one has a bag containing 81.50 g of pellets of this element. The density of the element is as follows:

10.5g/mL = 81.50g ÷ volume

volume = 81.50g ÷ 10.5g/mL

Volume = 7.76mL

Learn more about density at: https://brainly.com/question/6107689

#SPJ1

Tthe initial temperature of the polystyrene sample is 39.4°C.

Given: Mass of polystyrene sample = 54.2 gSpecific heat of polystyrene = 1.880 J-g°CWater mass = 100.0 g Initial water temperature = 21.0°CWater final temperature = 34.3°CPressure remains constant at 1 atmFormula used:Heat gained by water = heat lost by polystyreneHence,Heat lost by polystyrene = Heat gained by water=> mcΔT = mcΔTwhere,m = mass of polystyrene or waterc = specific heat capacityΔT = change in temperatureThe temperature change is ΔT = 34.3°C - 21.0°C = 13.3°CNow we can use this temperature change to calculate the initial temperature of the polystyrene.Taking the water's specific heat capacity, c = 4.184 J/g°CHeat gained by water = (100.0 g)(4.184 J/g°C)(13.3°C) = 5574 JHeat lost by polystyrene = 5574 JTaking the polystyrene's specific heat capacity, c = 1.880 J/g° ) = 13.3°C Now let's calculate the mass of polystyrene using the specific heat capacity formula.5574 J = (54.2 g)(1.880 J/g°C)(13.3°C - Ti)Ti = 39.4°C

for more questions on polystyrene

https://brainly.com/question/15913091

#SPJ8

Answer:

x/2

Explanation:

X = 2 molecules of H2

For 2 molecules of H2, there's only 1 molecule of O2. Meaning, there's twice the amount of H2, so O2 = x/2 molecules.

I hope I'm understanding this question right.

Answer:

2%

Explanation:

.2 g  / 10 g    * 100% = 2%

Answer:

1. Exothermic.

2. -1598 kJ.

Explanation:

Hello!

1. In this case, according to the reaction, we can infer that 799 kJ of energy are evolved (given off, released) it means that the enthalpy of reaction is negative as the reactants have more energy than the products; which means this is an exothermic reaction.

2. Here, as we know that the enthalpy of reaction is -799 kJ/mol, we can compute the q-value as shown below, considering the reacted 2 moles of solid iron:

\(q=2mol*-799 kJ/mol\\\\q=-1598kJ\)

Which means that 1598 kJ of energy are evolved when 2 moles of solid iron react.

Best regards!

Answer:

42.24 psi.

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 29.72 psi

Initial volume (V₁) = 10.22 L

Final volume (V₂) = 7.19 L

Final pressure (P₂) =?

The final pressure can be obtained by applying the Boyle's law equation as follow:

P₁V₁ = P₂V₂

29.72 × 10.22 = P₂ × 7.19

303.7384 = P₂ × 7.19

Divide both side by 7.19

P₂ = 303.7384 / 7.19

P₂ = 42.24 psi

Therefore, the final pressure is 42.24 psi

Answer:

Aluminum foil ~ element

Air ~ mixture

Water ~ compound

Salt Water ~ mixture

Copper Wire ~ element

Steel ~ element

Answer:

i would say two

Explanation:

I did the math

Answer:

7.5 kcal

Explanation:

1.0 cal /g-C   * 100 g * (100- 25 C) = 7500 cal = 7.5 kcal

The amount of heat energy necessary to raise the temperature of 100 g of water at room temperature (25°C) to the boiling point (100°C) is 7.5 kcal.

Given to us the mass of water, the specific heat of water, and the change in temperature, we need to calculate the amount of heat energy.

m = 100 g

c = 1.0 cal/g°C

ΔT = (100 °C - 25 °C) = 75 °C

To calculate the amount of heat energy required, we can use the formula:

Q = m × c× ΔT

Where:

Q = heat energy (in calories)

m = mass of water (in grams)

c = specific heat of water (in cal/g°C)

ΔT = change in temperature (in °C)

Substituting the values into the formula:

Q = 100 g × 1.0 cal/g°C × 75 °C

Q = 7500 cal

7500 cal = 7.5 kcal

Therefore, the amount of heat energy required to raise the temperature of 100 g of water from 25 °C to 100 °C is 7500 calories, which is equivalent to 7.5 kcal.

Learn more about specific heat here:

https://brainly.com/question/31608647

#SPJ2

Answer: C. CO₂ and H₂O

Explanation:

Combustion reactions produce carbon dioxide and water.

A diprotic weak base (B) has pb values of 3.722 (pb1) and 6.514 (pb2). The pH at which the dissociation of the first and second proton of a diprotic weak base is equal to its pKb1 and pKb2 values respectively. The pH at which the concentration of all the three forms of the base (B, BH+ and BH22+) is equal is given by the midpoint pH, pKb1 and pKb2, and is calculated using the equation:pH = 1/2 (pKb1 + pKb2)

For such more question on fraction

https://brainly.com/question/78672

#SPJ8

Answer:

This reaction is an exothermic reaction. Heat is released by the reaction.

Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the  pH of a 0.01 M acetic acid.

Any hydrogen that comprises a material capable of giving a proton (a hydrogen ion) to another chemical is defined as acid. A base is indeed a molecule or ion that can receive a hydronium ion from just an acid.

1)Because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. The pH value of stronger acid is lower.

2)CH\(_3\)COOH + H\(_2\)O  ⇄ CH\(_3\)COO⁻+  H\(_3\)O⁺

 0.01             0               0

 -x              +x                +x

 0.01-x           +x        +x

Ka=[ CH\(_3\)COO⁻][H\(_3\)O⁺]/[CH\(_3\)COOH]

1.8×10⁻⁵ = [x][x ]/[  0.01-x ]

x=1.34×10⁻³

pH = -log[H⁺]

     =  -log[1.34×10⁻³]

     =2.88

Therefore, because HCl is a stronger acid than acetic acid, the pH of 0.01M acetic acid has greater value than the pH of 0.01M HCl. 2.88 is the   pH of a 0.01 M acetic acid.

To learn more about acid, here:

https://brainly.com/question/29775793

#SPJ9

Answer:

D

Explanation:

best choice, makes the most sense

In the scientific method, conducting an experiment involves designing and performing controlled experiments to test a hypothesis and the correct option is option B.

Scientists manipulate the independent variable while controlling other variables (dependent and controlled variables) to observe and measure the effect on the dependent variable.

By controlling variables, scientists can isolate the factors that influence the outcome, ensuring that any observed changes are a result of the manipulated variable and not other unrelated factors. This step allows for the collection of reliable data, which is essential for drawing meaningful conclusions based on the evidence gathered from the experiment.

Thus, the ideal selection is option B.

Learn more about Scientific method, here:

https://brainly.com/question/17309728

#SPJ3

The de Broglie wavelength of the ball bearing is approximately 1.004 x 10^-35 meters.

According to de Broglie's equation, the de Broglie wavelength (λ) of a particle is given by:

λ = h / p

where

h is Planck's constant (6.626 x 10^-34 J s) and

p is the momentum of the particle.

The momentum (p) of the ball bearing can be calculated using the formula:

p = m * v

where

m is the mass of the ball bearing and

v is its velocity.

Substituting the given values, we get:

p = 0.02 kg * 330 m/s = 6.6 kg m/s

Now, we can calculate the de Broglie wavelength (λ) of the ball bearing as follows:

λ = h / p = 6.626 x 10^-34 J s / 6.6 kg m/s = 1.004 x 10^-35 m

Learn more about de Broglie wavelength at

https://brainly.com/question/30404168

#SPJ1

Ai. The car's initial kinetic energy is 22657.94 J

Aii. The car's initial potential energy is 939960.1 J

B. The car's final kinetic energy is 171420.38 J

C. The car's change in kinetic energy is 148762.44 J

Ai. How do I determine the car's initial kinetic energy?

We can obtain the initial kinetic energy of the car as illustrated below:

KE₁ = ½mu²

KE₁ = ½ × 566.99 × 8.94²

KE₁ = 22657.94 J

Aii. How do I determine the car's initial potential energy?

The car's initial potential energy can be obtained as shown below:

PE₁ = mgh

PE₁ = 566.99 × 9.8 × 169.164

PE₁ = 939960.1 J

B. How do I determine the car's final kinetic energy?

The final kinetic energy of the car can be obtained as illustrated below:

KE₂ = ½mv²

KE₂ = ½ × 566.99 × 24.59²

KE₂ = 171420.38 J

C. How do I determine the car's change in kinetic energy?

The change in the kinetic energy of the car can be obtained as follow:

ΔKE = KE₂ - KE₁

ΔKE = 171420.38 - 22657.94

ΔKE = 148762.44 J

Learn more about kinetic and potential energy:

https://brainly.com/question/7981774

https://brainly.com/question/22274239

#SPJ1

Answer:

Ni(NO3)2 is the limiting reactant.

Explanation:

- First, we balance the equation...

Ni(NO3)2 + 2 KOH --->  2 KNO3 + Ni(OH)2

- Second, we find the moles of each substance...

65g Ni(NO3)2 / 182.703g Ni(NO3)2 = 0.356 mol Ni(NO3)2

58g KOH / 56.1056g KOH = 1.034 mol KOH

- Third, to make the molar ratio equal to each other for comparison, we either multiply KOH by 1/2 or multiply Ni(NO3)2 by 2 to compare the number of moles; because the Ni(NO3)2 to KOH molar ratio is 1 to 2. Note that the multiplication of moles is only for comparison. We do not use these multiplied values. We use the values from step 2...

0.356 mol Ni(NO3)2 * 2 = 0.712 mol Ni(NO3)2

0.712 mol Ni(NO3)2 < 1.034 mol KOH ... Ni(NO3)2 is the limiting reactant.

Answer: The empirical and molecular formula for the given organic compound are \(CH\) and \(C_2H_2\) respectively.

Explanation:

The empirical formula is the chemical formula of the simplest ratio of the number of atoms of each element present in a compound.

The chemical equation for the combustion of hydrocarbon having carbon and hydrogen follows:

\(C_xH_y+O_2\rightarrow CO_2+H_2O\)

where, 'x' and 'y' are the subscripts of carbon and hydrogen respectively.

We are given:

Mass of \(CO_2\) = 9.920 g

Mass of \(H_2O\) = 2.031 g

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 9.920 g of carbon dioxide, \(=\frac{12}{44}\times 9.920g=2.705g\) of carbon will be contained.

In 18g of water, 2 g of hydrogen is contained.

So, in 2.031 g of water, \(=\frac{2}{18}\times 2.031g=0.226g\) of hydrogen will be contained.

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\(\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}\) ......(1)

To formulate the empirical formula, we need to follow some steps:

Molar mass of C = 12 g/mol

Molar mass of H = 1 g/mol

Putting values in equation 1, we get:

\(\text{Moles of C}=\frac{2.705g}{12g/mol}=0.225 mol\)

\(\text{Moles of H}=\frac{0.226g}{1g/mol}=0.226 mol\)

Calculating the mole fraction of each element by dividing the calculated moles by the least calculated number of moles that is 0.225 moles

\(\text{Mole fraction of C}=\frac{0.224}{0.225}=1\)

\(\text{Mole fraction of H}=\frac{0.226}{0.225}=1\)

The ratio of C : H = 1 : 1

The empirical formula of the compound becomes \(K_1Mn_1O_4=KMnO_4\)

To calculate the molecular formula, the number of atoms of the empirical formula is multiplied by a factor known as valency that is represented by the symbol, 'n'.

\(n =\frac{\text{Molecular mass}}{\text{Empirical mass}}\)        .....(2)

We are given:  

Mass of molecular formula = 26.04 g/mol

Mass of empirical formula = 13 g/mol

Putting values in equation 3, we get:

\(n=\frac{26.04g/mol}{13g/mol}=2\)

Multiplying this valency by the subscript of every element of empirical formula, we get:

\(C_{1\times 2}H_{1\times 2}=C_2H_2\)

Hence, the empirical and molecular formula for the given organic compound are \(CH\) and \(C_2H_2\) respectively.

The volume of gas when the pressure is 45 psi is 2,833.33mL.

The volume of a substance can be calculated using Boyle's law equation as follows:

P₁V₁ = P₂V₂

Where;

According to this question, a tank of carbondioxide has a pressure of 850 psi and a volume of 150 mL. The volume can be calculated as follows:

850 × 150 = 45 × V

V = 127,500 ÷ 45

V = 2,833.33mL

Therefore, 2,833.33mL is the volume of the gas.

Learn more about volume at: https://brainly.com/question/1437490

#SPJ1

Answer: D. form cations.

I think

Explanation:

The molar mass is 3230.8 g/mol

First, we need to know that the formula for the general gas law  is represented as;

PV = nRT

such that the parameters are;

Substitute the values

1 × 2.33 = n × 8.314 × 433.15

Multiply the values, we get;

n = 2.33/ 8.314 × 433.15

Divide the values

n = 6.5 × 10⁻⁴ moles

But, number of moles = mass/molar mass

Molar mass = 2.10/ 6.5 × 10⁻⁴

Molar mass = 3230.8 g/mol

Learn about ideal gas law at: https://brainly.com/question/25290815

#SPJ1

HI is the aqueous solution which is the most acidic. Any aqueous solution in chemistry can be divided into one of three groups, including neutral, basic, or acidic solutions.

Any aqueous solution in chemistry can be divided into one of three groups, including neutral, basic, or acidic solutions. Any aqueous solution with a pH 7.0 ([H+] > 1.0 x 10-7 M) is considered an acidic solution.

Water serves as the solvent in an aqueous solution. Solutions that are acidic are sour, whereas alkaline solutions are soapy, thus it's rarely a good idea to try an unfamiliar solution. HI is the aqueous solution which is the most acidic.

To know more about acidic solution, here:

https://brainly.com/question/13208021

#SPJ1

Answer:

\(2.11\ * 10^{-2}\)  is the correct answer to the given question.

Explanation:

Given k=6.40 x 10-3 min-1.

According to the first order reaction .

The concentration of time can be written as

\([\ A\ ]\ = \ [\ A_{0}\ ] * e \ ^\ {-kt}\)

Here \([\ A\ ]_{0}\) = Initial concentration.

So  \([\ A\ ]_{0}= 0.0314 M\)

Putting this value into the above equation.

\(0.0314 \ *\ e^{6.40 x 10^{-3} \ * \ 62.0 }\)

=0.211 M

This can be written as

\(=\ 2.11 *\ 10^{-2}\)

The question is incomplete, the complete question is;

One of the steps in the commercial process for converting ammonia to nitric acid is the conversion of NH3 to NO How many grams of NO and of H20 form? Enter your answers numerically separated by a comma. 4NH3(g) +502(g)------->4NO(g)+6H2O(g)

In a certain experiment, 1.10 g of NH3 reacts with 2.02 g of O2. How many grams of the excess reactant remain after the limiting reactant is completely consumed? Express your answer in grams to three significant figures.

Answer:

Mass of excess ammonia 0.034 g of ammonia

Mass of water formed= 1.37g

Mass of NO formed = 1.50g

Explanation:

The limiting reactant is the reactant that yields the least number of moles of product.

For NH3, molar mass of ammonia = 17g mol-1

Number of moles of ammonia reacted= 1.10g/17 gmol-1 = 0.065 moles of ammonia

According to the reaction equation;

4 moles of ammonia yields 4 moles of NO

Hence 0.065 moles of ammonia will yield 0.065 ×4/4 = 0.065 moles of NO

For oxygen, molar mass of oxygen gas = 32gmol-1

Number of moles of oxygen gas= 2.02g/32gmol-1 = 0.063 moles of oxygen

From the reaction equation;

5 moles of oxygen gas yields 4 moles of NO

0.063 moles of oxygen will yield 0.063 ×4 /5 = 0.050 moles of NO

Hence oxygen is the limiting reactant and ammonia is the excess reactant.

Amount of excess ammonia = Amount of ammonia - amount of oxygen

Amount of excess ammonia= 0.065-0.063= 2×10^-3 moles

Mass of excess ammonia = 2×10^-3 moles × 17 gmol-1 = 0.034 g of ammonia

Mass of NO formed is obtained from the limiting reactant. Since molar mass of is 30gmol-1. Then mass of NO formed = 0.050 moles of NO × 30gmol-1 = 1.50 g of NO

For water;

5 moles of oxygen yields 6 moles of water

Hence 0.063 moles of oxygen yields 0.063 × 6/5 = 0.076 moles of water

Molar mass of water = 18gmol-1

Hence mass of water = 0.076 moles × 18gmol-1 = 1.37g of water