Ariana borrowed some money from her friend in order to help buy a new video game system. Ariana originally borrowed $150 and agreed to pay back her friend $15 per week

The angle whose vertex is on the circle and the sides of the angle are the chords is called an Inscribed Angle .

What is an Inscribed Angle ?

An inscribed angle in the circle is formed by the two chords which have a common end point on circle and this common end point is called the vertex of inscribed angle.

The arc formed by the inscribed angle in the circle is called as the intercepted arc .

also the Inscribed Angle Theorem states that inscribed angle on the circle is half the measure of central angle that subtends the same arc .

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In the short run, an automobile maker experiencing an increase in the demand for a certain kind of car will be limited in its ability to adjust its production capacity.

In economics, the short run refers to a period of time during which some factors of production are fixed, while others can be adjusted. In the context of the automobile maker facing increased demand for a specific car, the short run implies that certain aspects of production capacity cannot be changed immediately.

In the short run, the automobile maker may not have the flexibility to expand its production facilities or build new manufacturing plants. This means that the company is constrained by its existing resources and production capacity. Instead, the company can make temporary adjustments to production levels by utilizing existing resources more efficiently, such as adding additional shifts or optimizing the utilization of labor and machinery.

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Answer:

5 is the answer

Step-by-step explanation:

Answer:

40x-16

Step-by-step explanation:

Distribute the 8 to the 5x and -2

8*5x=40x

8*-2=-16

So the answer is 40x-16

Standard deviation and median are less affected by extreme scores, while mode is not affected at all since it represents the most frequently occurring value.

The measure of variation affected most by a few extreme scores is the range, as it considers only the difference between the highest and lowest values in a dataset. However, the mean can also be influenced by extreme scores, causing it to deviate from the central tendency. Standard deviation and median are less affected by extreme scores, while the mode is not affected at all since it represents the most frequently occurring value.

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The measure of variation affected most by a few extreme scores is the range. The range is the difference between the

highest and lowest values in a data set. Extreme scores significantly increase the range, making it a sensitive measure

of variation.

The measure of variation that is affected most by a few extreme scores is the standard deviation.

The reason for this is that the standard deviation is calculated by taking the square root of the sum of squared

deviations from the mean, and the squared deviations from the mean are particularly sensitive to extreme scores.

On the other hand, the mode, range, median, and mean are less affected by a few extreme scores.

The mode is simply the most frequently occurring value in a dataset and is not affected by extreme scores.

The range is the difference between the highest and lowest values in a dataset and can be affected by extreme scores, but only to a limited extent.

The median is the middle value in a dataset, and it is also not affected by extreme scores unless they are extreme

enough to change the position of the middle value.

The mean is the average value in a dataset, and while it can be influenced by extreme scores, its effect is typically less

pronounced than on the standard deviation.

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a. Null Hypothesis: H0: μ1 = μ2 , Alternative Hypothesis: H1: μ1 > μ2

b. Test Statistic = 1.43

c. The degrees of freedom are 2089.

a. State the appropriate null and alternate hypotheses:

The hypothesis for testing if the mean number of hours per week spent on the Internet decreased between 2010 and 2012 can be stated as follows;

Null Hypothesis: The mean number of hours spent on the Internet in 2010 and 2012 are equal or there is no significant difference in the mean numbers of hours spent per week by adults on the Internet in 2010 and 2012. H0: μ1 = μ2

Alternative Hypothesis: The mean number of hours spent on the Internet in 2010 is greater than the mean number of hours spent on the Internet in 2012. H1: μ1 > μ2

b. Compute the test statistic: To calculate the test statistic we use the formula:

Test Statistic = (x¯1 − x¯2) − (μ1 − μ2) / SE(x¯1 − x¯2)where x¯1 = 10.52, x¯2 = 9.58, μ1 and μ2 are as defined above,

SE(x¯1 − x¯2) = sqrt(s12 / n1 + s22 / n2), s1 = 14.76, n1 = 1020, s2 = 13.33 and n2 = 1071.

Using the above values we have:

Test Statistic = (10.52 - 9.58) - (0) / sqrt(14.76²/1020 + 13.33²/1071) = 1.43

c. The degrees of freedom can be calculated

using the formula:

df = n1 + n2 - 2

where n1 and n2 are as defined above.

Using the above values we have:

df = 1020 + 1071 - 2 = 2089

Therefore, the degrees of freedom are 2089.

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The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.

Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%

In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:

The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.

The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation

Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.

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(a) The general solution for the given differential equation y" + 4y' + 4y = e^(-x) cos(x) is y(x) = C₁e^(-2x) + C₂xe^(-2x) + (1/10)e^(-x)sin(x), where C₁ and C₂ are arbitrary constants.

The given differential equation is a linear second-order homogeneous equation with constant coefficients. The characteristic equation is r² + 4r + 4 = 0, which factors as (r + 2)² = 0. This equation has a repeated root of -2.

Since the characteristic equation has a repeated root, the general solution includes terms involving e^(-2x) and xe^(-2x). The particular solution for the non-homogeneous term e^(-x) cos(x) can be found using the method of undetermined coefficients. Assuming a particular solution of the form y_p(x) = A e^(-x) cos(x) + B e^(-x) sin(x), we can solve for A and B by substituting this solution into the original differential equation.

After solving for A and B, the general solution is obtained by combining the homogeneous solution and the particular solution, resulting in y(x) = C₁e^(-2x) + C₂xe^(-2x) + (1/10)e^(-x)sin(x), where C₁ and C₂ are arbitrary constants.

(b) The general solution for the given differential equation (3D² + 27I)y = 3cos(x) + cos(3x) is y(x) = A cos(x) + B sin(x) + (1/30)cos(3x), where A and B are arbitrary constants.

The given differential equation is a linear second-order homogeneous equation with constant coefficients. It can be rewritten as 3D²y + 27y = 3cos(x) + cos(3x), where D represents the differential operator d/dx and I represents the identity operator.

To solve this equation, we first find the characteristic equation by substituting y = e^(rx) into the homogeneous equation, which gives 3r² + 27 = 0. This equation simplifies to r² + 9 = 0, leading to the characteristic roots r = ±3i. Since the roots are complex, the general solution will involve sine and cosine terms.

Assuming a general solution of the form y(x) = A cos(x) + B sin(x), we can substitute it into the differential equation to find the values of A and B. Then, to find the particular solution for the non-homogeneous term, we use the method of undetermined coefficients. Assuming a particular solution of the form y_p(x) = C cos(3x), we substitute it into the differential equation and solve for C.

Combining the homogeneous and particular solutions, we obtain the general solution y(x) = A cos(x) + B sin(x) + (1/30)cos(3x), where A and B are arbitrary constants.

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The converse of the statement "If a figure is a square, its diagonals divide it into isosceles triangles" would be:

"If a figure's diagonals divide it into isosceles triangles, then the figure is a square."

The converse statement is not necessarily true. While it is true that in a square, the diagonals divide it into isosceles triangles, the converse does not hold. There are other shapes, such as rectangles and rhombuses, whose diagonals also divide them into isosceles triangles, but they are not squares. Therefore, the converse of the statement is not always true.

Therefore, the converse of the given statement is not true. The existence of diagonals dividing a figure into isosceles triangles does not guarantee that the figure is a square. It is possible for other shapes to exhibit this property as well.

In conclusion, the converse statement does not hold for all figures. It is important to note that the converse of a true statement is not always true, and separate analysis is required to determine the validity of the converse in specific cases.

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Each bar's height corresponds to the value of the quantity it represents. For comparing numbers and data, bar graphs are excellent.

In mathematics, the word "graph" has (at least) two distinct meanings. The term "graph" in elementary mathematics refers to a diagram known as a function graph or "function graph." A graph is, in the language of mathematics, a set of points and lines that link a subset (potentially empty) of the points and lines. Graphs are visual representations or charts used in mathematics to methodically express data or values. A relationship between two or more objects is frequently represented by a point on a graph. Bar charts, line charts, histograms, and pie charts are the four types of fundamental statistical charts.

Each bar's height corresponds to the value of the quantity it represents. For comparing numbers and data, bar graphs are excellent. The x and y axes are the names of the vertical and horizontal axes in bar graphs, respectively. A bar graph can be used, for instance, to compare your classmates' heights.

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Answer:

18 servings

Step-by-step explanation:

If one serving is 1/3 cup, one cup is 3 servings. Therefore, we can multiply 3 x 6 for an answer of 18 servings

Answer:

68.785 miles per hour

Step-by-step explanation:

make one of the numbers 0 and divide the other one by that number

If you travel 550 miles in 8 hours your unit rate is 68.75 miles per hour

550 miles / 8 hours

Keep in mind when calculating unit rate your require division

Answer:

x answer: x = ( y + 134 ) / 18

y answer: y = 18x - 134

Step-by-step explanation:

y - 10 = 18( x - 8 )

y - 10 = 18x - 144

x answer:

y - 10 = 18x - 144

y + 134 = 18x

( y + 134 ) / 18 = x

y answer:

y - 10 = 18x - 144

y = 18x - 134

Answer: B & D

Step-by-step explanation:

In this scenario we want to come out with a situation where both sides are in an even playing field, as the equation solves to zero.

If a diver is 35 feet below water (-35) and he comes up to breathe, he goes up 35ft (35) meaning he is at the surface (0).

If Manuel is in debt for 35$ (-35) and then he pays off the 35$ (+35) then he is even (at 0).

Answer:

A diver is 35 feet below the surface of the water and then comes up to the surface.

You need to include an image or the measurements. No one can give you the answer without those numbers.

The volume of a right-circular cone of base radius 7cm and height 24cm is 1232 cm³.

An object or substance's volume is the amount of space it takes up. The capacity of a container is typically understood to be equal to its volume rather than the amount of space it occupies. The SI unit for volume is the cubic metre (m³).

Given that radius r = 7

height h = 24

The volume formula of a right-circular cone is

V = 1/3hπr²

Putting the values, we get

\($\text V = \frac{1}{3} \times 24 \times \frac{22}{7} \times 7 \times 7\)

V = 1232 cm³

Thus, The volume of a right-circular cone of base radius 7 and height 24 is 1232 cm³.

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Complete question:

Find the volume of a right-circular cone of base radius r and height h, from the figure given below.

Note that the attached graph represents the impression of the dilated triangles.

To do this, we make use of the following coordinates

A = (1, 0)

B = (5, 0)

C = (1, 6)

The lengths of the triangle are calculated using

D = √ [(x2-x1)² + (y2 - y1)²]

So, this yields:

AB = √[(1-5)² + (0-0²] = 4

BC = √[(1-5)² + (6-0²] = 7.2

AC = √[(1-1)² + (6-0²] = 5

Utilizing the scale factor of 2, we have the image of the dilation to be:

D = (2, 0)

E = (10, 0)

F = (2, 12)

Thus the lengths of these sides are

DE = 8

EF = 14.4

DF = 10

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Answer:

D

Step-by-step explanation:

The given expressions, when A=1, B=0, and C=1, X evaluates to 1.001; when A=B=C=1, X evaluates to 1.111; and when A=B=C=0, X evaluates to 0.000. These evaluations are based on the given values of A, B, and C, and the notation ¯¯¯¯¯¯BC represents the complement of BC.

To evaluate the expression X = A.¯¯¯¯¯¯BC, we substitute the given values of A, B, and C into the expression.

(a) For A = 1, B = 0, and C = 1:

X = 1.¯¯¯¯¯¯01

To find the complement of BC, we replace B = 0 and C = 1 with their complements:

X = 1.¯¯¯¯¯¯01 = 1.¯¯¯¯¯¯00 = 1.001

(b) For A = B = C = 1:

X = 1.¯¯¯¯¯¯11

Similarly, we find the complement of BC by replacing B = 1 and C = 1 with their complements:

X = 1.¯¯¯¯¯¯11 = 1.¯¯¯¯¯¯00 = 1.111

(c) For A = B = C = 0:

X = 0.¯¯¯¯¯¯00

Again, we find the complement of BC by replacing B = 0 and C = 0 with their complements:

X = 0.¯¯¯¯¯¯00 = 0.¯¯¯¯¯¯11 = 0.000

In conclusion, when A = 1, B = 0, and C = 1, X evaluates to 1.001. When A = B = C = 1, X evaluates to 1.111. And when A = B = C = 0, X evaluates to 0.000. The evaluation of X is based on substituting the given values into the expression A.¯¯¯¯¯¯BC and finding the complement of BC in each case.

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Answer:  A≈153.94

A= π r 2  = π 7 2 ≈ 153.93804

Step-by-step explanation:

The correct option is b) Label.

In a chart, each data point, bar, slice, and so on has a unique label. This label is used to identify and differentiate the different elements within the chart. It provides a clear and concise description of what each element represents.

For example, in a bar chart that shows the sales of different products, each bar would have a label indicating the specific product it represents. This allows the viewer to easily understand which product corresponds to each bar.

The label is crucial in making the chart understandable and meaningful. Without it, the chart would be confusing and difficult to interpret. It helps to provide context and clarity to the data being presented.

While color, size, and position can also be used to distinguish between elements in a chart, they do not provide the same level of specificity as a label. Color, for instance, may be used to represent different categories, but it does not provide specific information about each individual element.

In summary, the unique label assigned to each data point, bar, slice, or other element in a chart is what helps identify and differentiate them. It provides a clear description of what each element represents, making the chart more understandable and meaningful.

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Answer:

Option a 340 cm²

Area= bxh

20x17=340 cm²

Answer:

I think you just have to plug the 7 in for x so b(x)=6

Step-by-step explanation:

(5·7)-5=30

(3·7)-16=5

30/5=6

Answer:

y-axis

Step-by-step explanation:

points are (x,y)

since the y-coordinate does not change, but the x-coordinate does, it rotates around the y-axis.

reflection just means it rotates 180 degrees (out of the paper, not around)

Answer: 0.65

13/20 as a decimal is 0.65.

Answer:

1. 8x

2. 3x

3. 14x

4. 12x

5. 11x

6. 11x

7. 7x + 2

8. 16x +3

9.8x+5

10.9x + 4

11. 21x + 9

12. 7x + 8

Step-by-step explanation:

1. 8x

2. 3x

3. 14x

4. 12x

5. 11x

6. 11x

7. 7x + 2

8. 16x +3

9.8x+5

10.9x + 4

11. 21x + 9

12. 7x + 8

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1.

5x + 3x = 8x

2.

3x + x = 3x

3.

6x + 8x = 14x

4.

9x + 3x = 12x

5.

7x + 4x = 11x

6.

10x + x = 11x

7.

3x + 2 + 4x = 7x + 2

8.

15x + 3 + x = 16x + 3

9.

2x + 5 + 6x = 8x + 5

10.

7x + 2x + 4 = 9x + 4

11.

18x + 3x + 9 = 21x = 9

12.

6x + x + 8 = 7x + 8

EXPLANATION:

If it has the same base value, just add the coefficient.

More simply put, if they have an 'x' in front of them, just add the number before the 'x.'

You can't add a value with an 'x' in front and a value that doesn't

or example, you can't add 12x and 3

13.

3(7x + 5y)

14.

2(x + 7y)

15.

5(3x + 2y)

16.

6(2x + 3y)

17.

10(x + 3y)

18.

2(3x + 7y)

19.

8(x + 2y)

20.

9(5x + 3y)

21.

6(9x + 8y)

EXPLANATION

Find the highest common factor and divide the expression by this value

Place the HCF outside the brackets

Quick test: If you multiply the value outside the brackets by what is on the inside, it should give the original expression

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a). The difference between the two population means is estimated at a location to be 2.7.

b). 49 different possible outcomes make up the t distribution. The margin of error at 95% confidence is 1.7.

c). The range of the difference between the two population means' 95% confidence interval is (0.0, 5.4).

d). The (0.0, 5.4) represents the 95% confidence interval for the difference among the two population means.

The variability or spread in a set of data is commonly measured by the standard deviation. The deviation between the values in the data set and the mean, or average, value, is measured. A low standard deviation, for instance, denotes a tendency for data values to be close to the mean, whereas a high standard deviation denotes a larger range of data values.

Using the equation \(x_1-x_2\), we can determine the point estimate of the difference between the two population means. In this instance, we calculate the point estimate as 2.7 by taking the mean of Sample

\(1(x_1=22.8)\) and deducting it from the mean of Sample \(2(x_2=20.1)\).

With the use of the equation \(df=n_1+n_2-2\), it is possible to determine the degrees of freedom for the t distribution. In this instance, the degrees of freedom are 49 because \(n_1\) = 20 and \(n_2\) = 30.

We must apply the formula to determine the margin of error at 95% confidence \(ME=t*\sqrt[s]{n}\).

The sample standard deviation (s) is equal to the average of \(s_1\) and \(s_2\) (3.4), the t value with 95% confidence is 1.67, and n is equal to the

average of \(n_1\) and \(n_2\) (25). When these values are entered into the formula, we get \(ME=1.67*\sqrt[3.4]{25}=1.7\).

Finally, we apply the procedure to determine the 95% confidence interval for the difference between the two population means \(CI=x_1-x_2+/-ME\).

The confidence interval's bottom limit in this instance is \(x_1-x_2-ME2.7-1.7=0.0\) and the upper limit is \(x_1+x_2+ME=2.7+1.7=5.4\).

As a result, the (0.0, 5.4) represents the 95% confidence interval for the difference among the two population means.

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Answer:

19. 0•7431

20. 1•2800

21. 0•4850

All inequalities are true , then the sides form a triangle.

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side.

Now, According to the question:

Side 1 of the triangle is = 4

Side 2 of the triangle is = 8

Side 3 of the triangle is = 10

Form a triangle :

To check if they form a triangle or not, we make use of triangle inequality theorem which states that; for sides a, b and c

a + b > c

a + c > b

b + c > a

So for sides 4, 8 and 10, we have:

5 + 8 > 10

5 + 10 > 8

8 + 10 > 5

All inequalities are true , then the sides form a triangle

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