Are all squares with equal sides congruent?

Answer:

Step-by-step explanation:

The slope of the line would be the constant of proportionality for the line

shown. The point (35, 49) is really close the line which would make the

constant of proportionality 49/35 = 7/5. The equation of the line would be y =

7/5x. The number of loaves of bread from 85 pounds of flour would be

7/5(85) = 119 loaves.

- The company estimates that 2% of the devices are defective from the start.
- Defective devices have a lifetime of 0 years.
- The remaining devices have a regular lifetime.

1. The company estimates that around 2% of the devices are defective from the start. This means that these devices have a lifetime of 0 years because they are already defective.
2. For the remaining devices that are not defective, they have a regular lifetime. The company should provide an estimate or average lifetime for these devices.
3. By considering the defect rate and the regular lifetime of the devices, the company can determine the overall lifetime distribution of their product. This information is important for warranty, maintenance, and customer satisfaction purposes.
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The laser dot on the wall at point a moves at a pace of 6 times the circle's diameter, while the laser dot at point (ii) moves at 6π radians per minute.

i. The equation for linear speed, can be used to calculate the speed of the laser dot on the wall at point a. The distance in this instance is equal to the diameter of the circle created by the rotation of the laser, and the amount of time required to transit it is equal to one revolution, or 1/6 of a minute. The diameter of the circle is divided by 1/6 of a minute or six times the circumference of the circle.

ii. The equation for angular speed is used to calculate the speed of the laser dot on the wall at position b. In this instance, the angle is 2 radians, and it takes 1/6 of a minute to cross that angle. Therefore, 2 radians divided by 1/6 of a minute, or 6π radians per minute, is the speed of the laser dot on the wall at point b.

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The highest score obtained in this group of 12 scores is 19

What is the distribution in statistics?

In statistics, a distribution refers to the way in which a variable is spread out or distributed across different values. A distribution describes the probability of different outcomes for a variable, and can be visualized using graphs such as histograms, box plots, and probability density functions.

The distribution in Table 2-3 shows frequency (f) for different score ranges (x). Without knowing the exact scoring system, we can't say for certain what the highest score obtained in this group of 12 scores is. However, we can determine the upper limit of the highest score range by multiplying the upper limit of the range by its frequency:

Upper limit of 20-24 range = 24

Frequency of 20-24 range = 2

Upper limit of 15-19 range = 19

Frequency of 15-19 range = 5

Upper limit of 10-14 range = 14

Frequency of 10-14 range = 4

Upper limit of 5-9 range = 9

Frequency of 5-9 range = 1

To find the highest score, we need to determine the upper limit of the score range that has the highest frequency. In this case, the highest frequency is 5, which corresponds to the range 15-19.

Hence, the highest score range is 15-19, and the highest score within that range is the upper limit of that range, which is 19. So, the highest score obtained in this group of 12 scores is 19 (assuming the scoring system is such that higher scores correspond to higher ranges).

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Answer:

3/6

Step-by-step explanation:

The statement is incorrect due to the invalid assumption of f(x) = g(x) = 0, and the incorrect application of the comparison test.

The comparison test states that if 0 ≤ f(x) ≤ g(x) and the integral of g(x) dx diverges, then the integral of f(x) dx also diverges. However, the statement assumes that f(x) and g(x) are equal to zero, which means that 0 ≤ f(x) ≤ g(x) is not satisfied.

Additionally, the assumption that g(x) dx diverges does not necessarily imply that f(x) dx also diverges. For example, let g(x) = 1/x^2 and f(x) = 0 for all x. Then g(x) dx diverges, but f(x) dx converges to zero.

In conclusion, the statement is incorrect due to the invalid assumption of f(x) = g(x) = 0, and the incorrect application of the comparison test.

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Answer:

9 and 3

Step-by-step explanation:

10/15=6/(2x-9)

90=10(2x-9)

9=2x-9

x=9

18-8=10

10/(4x+3)=8/12

120=8(4x+3)

30=8x+6

x=3

The statement should be: "On its domain, the curve Y = f(x) attains its maximum value at X = 0 and does not have a minimum value."

To determine the maximum and minimum values of the function f(x) = \(20x^2e^{(-3x)\) on the domain [0, ∞), we can analyze its behavior.

First, let's consider the limits as x approaches 0 and as x approaches infinity:

As x approaches 0, the term \(20x^2\) approaches 0, and the term \(e^{(-3x)\)approaches 1 since \(e^{(-3x)\) is continuous. Therefore, the overall function approaches 0 as x approaches 0.

As x approaches infinity, both terms \(20x^2\) and \(e^{(-3x)\) tend to 0, but the exponential term decreases much faster. Thus, the overall function approaches 0 as x approaches infinity.

Since the function approaches 0 at both ends of the domain and the exponential term dominates the behavior as x increases, there is no maximum value on the domain [0, ∞). However, since the function is always positive, it does not have a minimum value either.

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Answer:

1.2 ounces of each bracelet is made up from wire.

Step-by-step explanation:

2.2 x 2 = 4.4

6.8 - 4.4 = 2.4

2.4 / 2 = 1.2

Answer:

B)

Step-by-step explanation:

This is hope i got it and it may or may not be helpful 10 divide by 430

Answer:

100m

Step-by-step explanation:

First, find the area of one triangle. Use l*w/2 to do that.

10*5=50

50/2=25

Multiply this by 4 to get the total area

25*4=100

Have a good day!

Answer:

13.015625

Step-by-step explanation:

Answer:

13 remainder 1.

I have attached the work to your question.

Please see the attachment below.

I hope this helps!

Reena bought more spinach as the total weight of spinach is more than chili.

The weight of an object refers to as the force of gravity that is acting on the object. It is the amount of gravitational force applied by the Earth on that object.

Weight of spinach - 53.882 grams or 0.053882 kg

Weight of chili - 49.883 grams or 0.049883 kg

When comparing the above information, we get the weight of spinach to be more than the weight of chili as the weight of spinach is 53.882 grams which is more than the gross weight of chili i.e., 49.883 grams. So, Reena bought more spinach as compared to chili.

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Answer:

Step-by-step explanation:

Use the area formula:

\(\\ \sf\longmapsto Area=LB\)

\(\\ \sf\longmapsto Area=10\dfrac{3}{4}\times 8\dfrac{1}{2}\)

\(\\ \sf\longmapsto Area=\dfrac{43}{4}\times \dfrac{17}{2}\)

\(\\ \sf\longmapsto Area=\dfrac{731}{8}\)

\(\\ \sf\longmapsto Area=91\dfrac{3}{8}ft^2\)

Answer:

79

Step-by-step explanation:

2(2) - 4(2(-1)^2 + 5(-1)) + 3(-1)^2 + 8(2)^3 + 4(-1)

4 - 4 (2 - 5) + 3 + 64 - 4

4 - 4(-3) + 3 + 64 - 4

4 + 12 + 3 + 64 - 4

16 + 3 + 64 - 4

19 + 64 - 4

83 - 4

79

hope this  helps! <3

Answer:

A I'm Brainly

Step-by-step explanation:

xd xd xd xd XD

The values for R(detected), λ, and t into the equation, you can calculate the "true" count rate of your sample

To calculate the detected activity from the count rate due to background radiation and the sample of KCl, you can use the following equation:

R(detected) = R(total) - R(background)

In this equation, R(background) represents the count rate for background radiation, and R(total) represents the total count rate detected from your sample and background. By subtracting the count rate of background radiation from the total count rate, you can determine the detected count rate from your sample, R(detected).

To determine the "true" activity of your sample, you can use the following equation:

R(true) = R(detected) / (1 - exp(-λt))

In this equation, R(true) represents the "true" count rate of your sample, R(detected) represents the detected count rate from your sample, λ represents the decay constant of the radioactive isotope in your sample, and t represents the time during which the count rate is measured.

By plugging in the values for R(detected), λ, and t into the equation, you can calculate the "true" count rate of your sample, which represents the actual activity of the radioactive isotope in the sample.

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Complete question:

write a mathematical equations that show how you will calculate the detected activity from the count rate due to background radiation and the sample of KCl. also, write an equation that shows how you will determine the "true" activity of your sample. Use the following terms:

R(background) = count rate for background radiation

R(total) = total count rate detected from your sample and background

R(detected) = detected count rate from your sample less the background radiation

R(true) = the "true" count rate of your sample.

Answer:

the point ( 5, 7) lies in the first quadrant.

Step-by-step explanation:

X coordinate is positive and the Y coordinate is positive in the first quadrant.

Answer:

Quadrant I

Step-by-step explanation:

Quadrant I : (x, y)

Quadrant II : (-x, y)

Quadrant II : (-x, -y)

Quadrant IV : (x, -y)

Therefore, as the x and y values of (5, 7) are both positive, the point is located in Quadrant I

Answer:

18

Step-by-step explanation:

Step-by-step explanation:

Using BODMAS [Brackets() Of Division÷ Multiplication× Addition+ Subtraction-]

the expression has addition and multiplication so therefore in the order of BODMAS

we first Multiply

then finally add 6 to the product of 3×4 which is

O f(x) = 4(1.02)"

O f(x) = 0.5(1.02)

O f (x) =3/4 (1.35)

Of(x) = 7(5/4)

The soluation will be

Of(x) = 7(5/4)

Answer:

B

Step-by-step explanation:

I'm sorry if I'm wrong

Answer:

5

Step-by-step explanation:

meant b haha

The sample size needed to create a confidence interval with a margin of error smaller than 1.5 is 19.

To find the sample size needed to create a confidence interval with a margin of error smaller than 1.5, assuming a standard deviation of 4.8, we can use the following formula:

Sample size = (z-score)2 * Standard Deviation2 / Margin of Error2

Where the z-score is the number of standard deviations away from the mean that the margin of error is.

In this case, the z-score should be 1.96 to have a margin of error smaller than 1.5.

So, the sample size needed is:
Sample size = (1.96)2 * (4.8)2 / (1.5)2 = 18.92


Therefore, the sample size needed to create a confidence interval with a margin of error smaller than 1.5, assuming a standard deviation of 4.8, is 18.92.

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Answer:

2x(x+1) + 5x² - 5x= - 2

Step-by-step explanation:

a=7

b=-3

c=2

2nd degree equation is written as

ax^2+bx+c=0

2x(x+1) + 5x² - 5x= - 2

2x^2+2x+5x^2-5x=-2

Collect like terms

2x^2+5x^2+2x-5x+2=0

7x^2-3x+2=0

a=7, b=-3, c=2

Therefore, the 2nd degree equation that corresponds with the above coefficients is 2x(x+1) + 5x² - 5x= - 2

Answer:

Y is less than or equal to 2/5x+1

Answer:

it is 100% b

Step-by-step explanation:

Answer:

To transform a figure from Quadrant II to Quadrant IV, we need to reflect it across the x-axis and then rotate it 180 degrees counterclockwise. Therefore, the sequence of transformations is:

Reflect the figure across the x-axis

Rotate the reflected figure 180 degrees counterclockwise

Note: It's important to perform the transformations in this order since rotating the figure first would change its orientation before the reflection.

The hypotenuse of 4th triangle be \(2\sqrt{2}\\\)

The hypotenuse of 100th triangle be \(2\sqrt{26}\\\)

The hypotenuse of nth triangle be \(\sqrt{4+n}\\\)

Given, that Triangles be drawn according to the spiraling pattern

let hypotenuse of 1st triangle be \(h_{1}\), hypotenuse of 2nd triangle be \(h_{2}\) and so on.

as, we know Pythagoras theorem i.e.

\(hypotenuse^{2} = base^{2} + perpendicular^{2}\)

In 1st triangle,

base = 2 units and perpendicular = 1 unit

On applying Pythagoras theorem in 1st triangle, we get

\(h_{1}^{2}=2^2 +1^2\)

\(h_{1}^2=5\\ h_{1} = \sqrt{5}\) ... (1)

Now, hypotenuse of 1st triangle will be the base of 2nd triangle

so, In 2nd triangle,

base = \(\sqrt{5}\) units and perpendicular = 1 unit

On applying Pythagoras theorem in 2nd triangle, we get

\(h_{2}^2 = \sqrt{5}^2 + 1^2\)

\(h_{2}^2=5+1\\h_{2}^2=6\\ \\h_{2}=\sqrt{6} \\\)... (2)

Now, observing Eq (1) and Eq (2) we can define a rule to find the hypotenuse of nth triangle i.e.

\(h_{n}=\sqrt{4+n}\)

So, the hypotenuse of the 4th triangle be

\(h_{4}=\sqrt{4+4}\\ h_{4}=\sqrt{8}\\ h_{4}=2\sqrt{2}\)

Also, the hypotenuse of the 100th triangle be

\(h_{100}=\sqrt{100+4}\\ h_{100}=\sqrt{104}\\ h_{100}=2\sqrt{26}\)

The hypotenuse of 4th triangle be \(2\sqrt{2}\\\)

The hypotenuse of 100th triangle be \(2\sqrt{26}\\\)

The hypotenuse of nth triangle be \(\sqrt{4+n}\\\)

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To determine how well Luke must score on exam B in order to do equivalently well as he did on exam A, we need to first standardize his score on exam A using z-scores.

A z-score represents the number of standard deviations a given data point is away from the mean. The formula for calculating z-scores is:

z = (x - μ) / σ

where x is the data point, μ is the mean, and σ is the standard deviation.

In this case, Luke's score on exam A has a z-score of:

z = (850 - 750) / 50 = 2

This means that his score on exam A is 2 standard deviations above the mean.

To do equivalently well on exam B, Luke needs to achieve a score that has the same z-score of 2. We can use the formula for z-scores again to determine what score he needs to achieve:

2 = (x - 38) / 5

Solving for x, we get:

x = 48

Therefore, Luke needs to score 48 on exam B in order to do equivalently well as he did on exam A.

It's important to note that we're assuming that the distributions of the two exams are both normal distributions. If this assumption is not valid, then our answer may not be accurate.

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