aracely and jonah went to breakfast and ordered chicken and waffles aracely ordered 1 waffle and 2 pieces of chicken and paid $8.50 joah order 2 waffles and 1 piece of chicken and paid $7.25 how much is each waffle and each piece of chicken

The lengths of the sides of the rectangular field so as to minimize the amount of fencing needed is 30 feet by 20 feet

Let x represent the length of the fence and y represent the width of the fence.

Since the area is 600, hence:

Area = length * width = x * y

600 = xy

y = 600/x

A fence divide the field in half and is parallel to one of the sides of the rectangle. Hence:

Amount of fencing needed (P) = x + x + y + y  + y = 2x + 3y

Amount of fencing needed (P) = 2x + 3(600/x) = 2x + 1800/x

To minimize the amount of fencing needed, dP/dx = 0, hence:

dP/dx = 2 - 1800/x²

2 - 1800/x² = 0

2 = 1800/x²

2x² = 1800

x² = 900

x = 30 feet

y = 600/x = 600/30 = 20 feet

Hence, the lengths of the sides of the rectangular field so as to minimize the amount of fencing needed is 30 feet by 20 feet

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Answer:

10/12 =5/6

Step-by-step explanation:

Answer:

5/6

Step-by-step explanation:

I believ you meant what is the simplest version of that fraction and that would be 5/6. Both 10 and 12 are divisable by 2 and 5 can not be reduced

Answer: 9 sq. units

Step-by-step explanation:

(6x3)(1/2)=9

Answer:

267 km

Step-by-step explanation:

\(\frac{396}{132}\) => 3

3 x 89 -> 267 km on 89 liters

hi

as consumption is proportional to distance we have :  

 132  =  396

   89 =    ?  

? =   89*396  / 132 =  267

with 89 liters  of gasoline, boat goes 267 km.

The equation of the hyperbola for the cross section of the cooling tower is x²/8100 - y²/9506.25 = 1.

We must take into account its characteristics in order to formulate the hyperbola's equation for the cooling tower's cross section.

Since the origin serves as the hyperbola's centre, its coordinates are (0, 0).

The left/right opening of the hyperbola indicates that the primary axis is horizontal.

The cooling tower's smallest diameter is 180 metres, which is the same length as the minor axis.

The primary axis' 195 m length and the diameter at its highest point are matched.

The hyperbola's highest point is 80 metres above the centre.

These characteristics allow us to write the hyperbola's equation in standard form:

(x - h)²/a² - (y - k)²/b² = 1

Where (h, k) represents the center of the hyperbola.

Substituting the given values:

Center: (h, k) = (0, 0)

Minor axis: 2a = 180 m, so a = 90 m

Major axis: 2b = 195 m, so b = 97.5 m

Vertical shift: c = 80 m

Now we can write the equation of the hyperbola:

x²/90² - y²/97.5² = 1

Simplifying, we have:

x²/8100 - y²/9506.25 = 1

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Answer:

102 degrees

Step-by-step explanation:

m< CDA & m<CBA are both 78 degrees because they are both acute angles.

m<DAB & m<DCB are both 102 degrees because they are both obtuse angles.

Whenever you add 78 + 78 + 102 + 102 you get 360 degrees which is how much a four-sided figure should be.

Hope this helps!

Answer:

∠ DAB = 102°

Step-by-step explanation:

The consecutive angles of a parallelogram are supplementary.

∠ CDA and ∠ DAB are consecutive angles, then

∠ DAB = 180° - 78° = 102°

Answer:

$382.5

Step-by-step explanation:

450x$0.85 is $382.5

Answer:

140

Step-by-step explanation:

80 x 1.75 = 140

The length of BC in this problem is given as follows:

BC = 3.6.

Two triangles are defined as similar triangles when they share these two features listed as follows:

The similar triangles for this problem are given as follows:

ABC and ADE.

Hence the proportional relationship for the side lengths is given as follows:

3/5 = BC/6.

Applying cross multiplication, the length BC is given as follows:

BC = 6 x 3/5

BC = 3.6.

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To solve the given problems, we'll use the properties of the normal distribution with mean μ = 100 and standard deviation σ = 10.

a. Probability that X > 85:

To find this probability, we need to calculate the area under the normal curve to the right of 85. We can use the standard normal distribution table or a calculator to find the corresponding z-score and then use the z-table to find the probability.

First, let's calculate the z-score:

z = (X - μ) / σ

z = (85 - 100) / 10

z = -15 / 10

z = -1.5

Using the z-table or a calculator, we find that the probability of Z > -1.5 is approximately 0.9332.

Therefore, the probability that X > 85 is 0.9332 (rounded to four decimal places).

b. Probability that X < 80:

Similarly, we'll calculate the z-score for X = 80:

z = (X - μ) / σ

z = (80 - 100) / 10

z = -20 / 10

z = -2

Using the z-table or a calculator, we find that the probability of Z < -2 is approximately 0.0228.

Therefore, the probability that X < 80 is 0.0228 (rounded to four decimal places).

c. Probability that X < 90 or X > 130:

To calculate this probability, we'll find the individual probabilities of X < 90 and X > 130, and then subtract the probability of their intersection.

For X < 90:

z = (90 - 100) / 10

z = -10 / 10

z = -1

Using the z-table or a calculator, we find that the probability of Z < -1 is approximately 0.1587.

For X > 130:

z = (130 - 100) / 10

z = 30 / 10

z = 3

Using the z-table or a calculator, we find that the probability of Z > 3 is approximately 0.0013.

Since these events are mutually exclusive, we can add their probabilities:

P(X < 90 or X > 130) = P(X < 90) + P(X > 130)

P(X < 90 or X > 130) = 0.1587 + 0.0013

P(X < 90 or X > 130) = 0.1600

Therefore, the probability that X < 90 or X > 130 is 0.1600 (rounded to four decimal places).

d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?

To find the two X-values, we need to find the corresponding z-scores for the cumulative probabilities of 0.005 and 0.995. These probabilities correspond to the tails beyond the 99% range.

For the left tail:

z = invNorm(0.005)

z ≈ -2.576

For the right tail:

z = invNorm(0.995)

z ≈ 2.576

Now we can find the corresponding X-values:

X1 = μ + z1 * σ

X1 = 100 + (-2.576) * 10

X1 = 100 - 25.76

X1 ≈ 74.24

X2 = μ + z2 * σ

X2 = 100 + 2.576 * 10

X2 = 100 + 25.76

X2 ≈ 125.76

Therefore, 99% of the values are greater than 74.24 and less than 125.76 (rounded to two decimal places).

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The P-value for a left-tailed hypothesis test with a test statistic of z = -1.40 is approximately 0.0808. Since the P-value (0.0808) is greater than the level of significance (α = 0.10), we do not have enough evidence to reject the null hypothesis at the 0.10 significance level.

To find the P-value for a left-tailed hypothesis test, we need to calculate the probability of observing a test statistic as extreme as or more extreme than the given value of z = -1.40 under the null hypothesis.

Using a standard normal distribution table or a statistical software, we can find that the cumulative probability for z = -1.40 is approximately 0.0808.

Comparing the P-value (0.0808) to the level of significance (α = 0.10), we see that the P-value is greater than α. Therefore, we do not have enough evidence to reject the null hypothesis at the 0.10 significance level.

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Given statement solution is :- When the weight of apples is increased by a factor of 4, the total cost also increases by a factor of 4. The correct answer is 4, not 8.

To determine the factor by which the total cost increases when the weight of apples is increased by a factor of 4, let's examine the relationship between the weight and total cost in the given ratio table.

Weight (lb) | Total cost (S)

1 | 2

4 | 8

6 | 12

10 | 20

To find the factor by which the total cost increases, we need to compare the change in total cost to the change in weight. Let's consider the first and last entries in the table:

Initial weight: 1 lb

Initial total cost: 2 S

Final weight (increased by a factor of 4): 4 * 1 lb = 4 lb

Final total cost: 8 S

The change in weight is from 1 lb to 4 lb, which is a factor of 4. The change in total cost is from 2 S to 8 S, which is also a factor of 4.

Therefore, when the weight of apples is increased by a factor of 4, the total cost also increases by a factor of 4. The correct answer is 4, not 8.

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The final equation for the tangent plane to the graph of f at the point (a, b) is z = 2e^a(x - a) - y + 2e^a - 2b. This equation represents the plane that is tangent to the graph of f at the specified point (a, b).

To find the equation for the tangent plane to the graph of the function f(x, y) = 2e^x - y at a given point (x0, y0), we need to calculate the partial derivatives of f with respect to x and y at that point.

The partial derivative of f with respect to x, denoted as ∂f/∂x or fₓ, represents the rate of change of f with respect to x while keeping y constant. Similarly, the partial derivative of f with respect to y, denoted as ∂f/∂y or fᵧ, represents the rate of change of f with respect to y while keeping x constant.

Let's calculate these partial derivatives:

fₓ = d/dx(2e^x - y) = 2e^x

fᵧ = d/dy(2e^x - y) = -1

Now, we have the partial derivatives evaluated at the point (x0, y0). Let's assume our point of interest is (a, b), where a = x0 and b = y0.

At the point (a, b), the equation for the tangent plane is given by:

z - f(a, b) = fₓ(a, b)(x - a) + fᵧ(a, b)(y - b)

Substituting fₓ(a, b) = 2e^a and fᵧ(a, b) = -1, we have:

z - f(a, b) = 2e^a(x - a) - (y - b)

Now, let's substitute f(a, b) = 2e^a - b:

z - (2e^a - b) = 2e^a(x - a) - (y - b)

Rearranging and simplifying:

z = 2e^a(x - a) - (y - b) + 2e^a - b

The final equation for the tangent plane to the graph of f at the point (a, b) is z = 2e^a(x - a) - y + 2e^a - 2b.

This equation represents the plane that is tangent to the graph of f at the specified point (a, b).

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ANSWER

My answer is in the photo above

The correct set of hypotheses is: b. H0: μ ≤ 10.0% Ha: μ > 10.0%.

In hypothesis testing, the null hypothesis (H0) represents the statement that is being tested or assumed to be true, while the alternative hypothesis (Ha) represents the statement that contradicts or challenges the null hypothesis. In this case, the null hypothesis states that the average yearly rate of return on the stocks is less than or equal to 10.0%, and the alternative hypothesis states that the average yearly rate of return on the stocks is greater than 10.0%.

By formulating the hypotheses in this way, you are testing whether there is sufficient evidence to support the claim made by your investment executive that the average yearly rate of return on the stocks she recommends is at least 10.0%.

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Answer:

$9.25

Step-by-step explanation:

Total cost = sum of cost of hot dogs, french fries and soda:

                 =  2($2.85/hot dog) +          1($2.35/fries)   +  1($1.20)

                  =  $5.70                    +        $2.35                + $1.20

                   = $9.25

It is false, that the sum of the numbers of dots that show up when we roll three dice simultaneously does not follow a discrete uniform distribution.

The Discrete uniform distribution is a symmetric probability distribution used in probability theory and statistics. It contains a finite number of values that are equally likely to be observed; each value has an equal chance of 1/n. "A known, finite number of outcomes equally likely to occur" is another approach to describe the discrete uniform distribution.

The perfect example of Discrete uniform distribution is throwing a die. Tossing a fair dice is an easy illustration of the discrete uniform distribution. The possible results are 1, 2, 3, 4, 5, and 6, and the likelihood of a certain result is 1/6 each time the die is thrown. Because not all sums have an equal chance, the distribution that results when two dice are thrown and their values are summed is no longer uniform.  

From the above observation, we can say that the sum of the number of dots that show up when we roll three dice simultaneously will follow a discrete uniform distribution.

It is false, that the sum of the numbers of dots that show up when we roll three dice simultaneously does not follow a discrete uniform distribution.

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Answer:

C = 18π cm

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Geometry

Circumference Formula: C = 2πr

Step-by-step explanation:

Step 1: Define

Identify variables

r = 9 cm

Step 2: Find C

If the boxplot for one set of data is much wider than the boxplot for a second set of data, Option d, "none of the above need to be true" is the correct answer.

The width of a boxplot is determined by the range of the data, as well as the spread of the data within the interquartile range (IQR). A wider boxplot indicates a greater range and/or more spread in the data.

However, the mean and median are measures of central tendency that describe where the "middle" of the data is located. The spread of the data does not necessarily provide any information about the mean or median.

Therefore, right answer is option d "none of the above need to be true". As the width of the boxplot alone cannot tell us anything about the means or medians of the two sets of data, nor can it tell us whether one set of data contains outliers.

We need to examine additional measures, such as the mean and median, to make any conclusions about the data.

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The point of intersection of the two lines v1 and v2 is P1 = ⟨-7, 1, -8⟩.

The vector equation of the two lines is given as follows:v1(t) = ⟨-9, 3, -6⟩ + t⟨1, -1, -1⟩v2(s) = ⟨-11, 6, -9⟩ + s⟨-1, 0, 3⟩To find the intersection point, we must solve the two equations simultaneously.⟨-9, 3, -6⟩ + t⟨1, -1, -1⟩ = ⟨-11, 6, -9⟩ + s⟨-1, 0, 3⟩⇒ -9 + t = -11 - s⇒ 3 - t = 6⇒ -6 - t = -9 + 3s⇒ -t = -2 - s⇒ t = 2 + s

So we can rewrite the vector equation as follows:v1(t) = ⟨-9, 3, -6⟩ + (2 + s)⟨1, -1, -1⟩

Let's substitute the value of t in the equation of v1(t) to obtain P1.v1(2 + s) = ⟨-9, 3, -6⟩ + (2 + s)⟨1, -1, -1⟩⟨-7 + 3s, 1 - s, -8 + s⟩

Let's substitute the value of s in the above equation to obtain the point of intersection of the two lines, P1.P1 = ⟨-7 + 3s, 1 - s, -8 + s⟩

P1 = ⟨-7 + 3(0), 1 - 0, -8 + 0⟩P1 = ⟨-7, 1, -8⟩

Hence, the point of intersection of the two lines is P1 = ⟨-7, 1, -8⟩.

Explanation:Two lines can be expressed in vector form as v1(t) = a + tb and v2(s) = c + sd where a, b, c, and d are vectors, and t and s are scalars.The two lines intersect at a point if there is a common solution to the equation:v1(t) = v2(s).We can rewrite the equation as follows:a + tb = c + sdWe can solve for the unknown variables t and s by using the components of the vectors.

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Answer:

Step-by-step explanation:

84.21

The solution to the system of equations is (-6, -9).

Given y=2x+3,

we are to find the solution to the system of equations.

In order to find the solution to the system of equations,

we require another equation in the system.

The system of equations is:

y = 2x + 3 ...

(1)Let's assume another equation:y - 3x = 9 ...

(2)The given system of equations is:

y = 2x + 3 ... (1)y - 3x = 9 ...

(2)Substituting equation (1) into equation (2), we get:

(2x + 3) - 3x = 9 => -x + 3 = 9 => -x = 9 - 3 => -x = 6 => x = -6

Therefore, substituting this value of x in equation (1), we get:

y = 2x + 3 => y = 2(-6) + 3 => y = -12 + 3 => y = -9

Therefore, the solution to the given system of equations is (-6, -9).

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Answer:

cos E =9/41

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos E = adjacent/ hypotenuse

Cos E = 18/82

cos E =9/41

Answer:

<L = <E

<MFL = <DFE

vertical opposite

angles are same

by, AA simillary postulate triangles are similar.

Answer:

4

Step-by-step explanation:

5-1=4

...............

Answer:

Step-by-step explanation:

so  do 72÷24= 3 then do x 46= 138

Answer:

the answer is 40:15

Step-by-step explanation:

Answer:

answer 40:15

Step-by-step explanation:

Step-by-step explanation:

200

thanks for the free points!

have a great day!