Aqueous potassium phosphate reacts with aqueous nickel(ii) bromide to produce solid nickel(ii) phosphate and aqueous potassium bromide.

a.True
b. False

Answer:

The energy of the wave particle is 3.058 x 10⁻²³ J.

Explanation:

Given;

wavelength of the wave particle, λ = 6.5 x 10⁶ nm = (6.5 x 10⁶) x 10⁻⁹ m

The energy of the wave particle is calculated as;

\(E = hf\\\\E = \frac{hc}{\lambda}\)

where;

h is Planck's constant = 6.626 x 10⁻³⁴ J/Hz

c is speed of light = 3 x 10⁸ m/s

\(E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{6.5 \times 10^6 \times 10^{-9}} \\\\E = 3.058 \times 10^{-23} \ J\)

Therefore, the energy of the wave particle is 3.058 x 10⁻²³ J.

Answer:

Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?

Explanation:

Now, we have 0.025 M H2SO4 and we do not know how much volume we have.

We will use the standard N1 X V1 = N2 X V2 for this calculation.

N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.

So V1= (0.03 X 525)/(0.025) = 630 ml.

According to the molar concentration, 684 ml of 0.25 M H₂SO₄ can be prepared from 57 mL of a 3.0 M solution of H₂SO₄.

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.In case  of 2 solutions,it is calculated as, M₁V₁=M₂V₂ substitution gives V₁=3×57/0.25=684 ml.

Thus, 684 ml of 0.25 M H₂SO₄ can be prepared from 57 mL of a 3.0 M solution of H₂SO₄.

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Answer:11.60%

Explanation:

\(Percent Error = \frac{Actual - Theoretical}{Actual} (100)\\\)

\(Percent Error = \frac{74.65-66.89}{66.89} (100) = 11.60%\)%

Based on the given options, points 2 and 4 on the diagram represent areas of low pressure.

Convection cells are important in the formation of weather patterns and air circulation in Earth's atmosphere. The diagram mentioned in the question depicts the major atmospheric convection cells. The large-scale circulation patterns caused by temperature differences between the equator and the poles are known as Hadley cells, and they are what these cells are.

The rising air at the equator, as seen in point 2 on the diagram, represents an area of ​​low pressure. Point 4 shows air that is falling at a latitude of about 30 degrees, indicating another area of ​​low pressure. These areas of low pressure are important for understanding the patterns of air circulation around the world because they are associated with many meteorological phenomena.

Therefore, the correct option is C.

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Answer:

It is important to identify it because the two types of crust are made up of two different types of rock

Explanation:

Have a nice day

The original culture density (OCD) of a sample density would be 1,720,000 colony-forming units per unit volume.

The dilution factor is the ratio of the volume of the original sample to the volume of the final diluted sample. In this case, the final dilution factor is 10^-4, which means that the original sample was diluted by a factor of 10,000.

To calculate the OCD, we use the formula: OCD = CFU / Dilution Factor. In this case, the CFU count is given as 172 and the dilution factor is 10^-4.

Using the formula, OCD = 172 / 10^-4, we can simplify the calculation by converting the dilution factor to a whole number. 10^-4 is equivalent to 1 / 10,000.

Substituting the values, OCD = 172 / (1 / 10,000). Dividing by a fraction is equivalent to multiplying by its reciprocal, so OCD = 172 * 10,000.

Calculating the product, OCD = 1,720,000. Therefore, the original culture density of the sample would be 1,720,000 colony-forming units per unit volume.

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The company should contact with a material scientist to better know which materials can provide the needs that they demand. Hence option c is correct.

The chemical composition and structure of many man-made and natural materials are investigated and analyzed by materials scientists. In order to learn more or acquire new information, glass, rubber, ceramic, alloys, polymers, and metals are all explored and investigated.

Using what they have learnt, materials scientists then come up with methods to mix materials, reinforce existing materials, or develop whole new materials with specific features and characteristics for usage in a variety of applications and products.

A materials scientist develops techniques for evaluating certain materials to find out how they react to various environmental factors. They also design laboratory tests to assess the plausibility of methods and processes used to produce novel materials with enhanced properties.

Therefore, the company have to contact a material scientist.

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The volume of the balloon at the center of the typhoon exists at 41.7L.

Since no temperature changes were given, it exists supposed to be constant.

Thus, Boyle's law which defines the relationship between pressure and volume exists utilized to define the new volume at the center of Typhoon Odessa.

Mathematically, Boyle's law notes that;

P1V1 = P2V2

Assuming 1 atm = 1 bar

1 mbar = 0.001 atm

40 mbar = 0.040 atm

Given: P1 = 1.0 atm

V1 = 40.0 L

P2 = 1 atm - 0.040 atm = 0.960 atm

Using P1V1 = P2V2

V2 = P1V1/P2

Substitute the values in the above equation, and we get

V2 = 1.0 \(*\) 40.0 / 0.96

The value of V2 = 41.67L

Therefore, the volume of the balloon at the center of the typhoon exists at 41.7L.

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The complete question is:

If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?

The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.

Answer:

Electrolysis of Al₂O₃: 4Al³⁺ (s) + 6O²⁺ (g) → 4Al (s) + 3O₂ (g)

Reduction of Elemental Fe: 2Fe₂O₃ (s) + 3C (s) → 4Fe (s) + 3CO₂ (g)

Atom Economy for Electrolysis of Al₂O₃: 52.9227%

Atom Economy for Reduction of Fe₂O₃: 62.8534%

Explanation:

Step 1: Define Compounds

Aluminum Oxide - Al₂O₃

Iron Oxide - Fe₂O₃

Step 2: RxN

Al₂O₃ (s) → Al (s) + O₂ (g)

Fe₂O₃ (s) + C (s) → Fe (s) + CO₂ (g)

Step 3: Balance RxN

2Al₂O₃ (s) → 4Al (s) + 3O₂ (g)

This is ONLY the decomposition reaction for Aluminum oxide, NOT the electrolysis.

2Fe₂O₃ (s) + 3C (s) → 4Fe (s) + 3CO₂ (g)

This is the final single-replacement reaction for the reduction of Iron Oxide to Iron.

Step 4: Electrolysis of Al₂O₃

We will have to use oxidation-reduction reactions (half-reactions). Let's break up the reaction into it's elements.

Al³⁺ + ? → Al

Al³⁺ + 3e⁻ → Al

O²⁻ → O₂ + ?

2O²⁻ → O₂ + ?

2O²⁻ → O₂ + 4e⁻

Our half reactions:

Al³⁺ + 3e⁻ → Al

2O²⁻ → O₂ + 4e⁻

4 (Al³⁺ + 3e⁻ → Al) = 4Al³⁺ + 12e⁻ → 4Al

3 (2O²⁻ → O₂ + 4e⁻) = 6O²⁻ → 3O₂ + 12e⁻

4Al³⁺ + 12e⁻ + 6O²⁺ → 4Al + 3O₂ + 12e⁻

4Al³⁺ (s) + 6O²⁺ (g) → 4Al (s) + 3O₂ (g)

Step 5: Atom Economy

According to GCSE and my own deciphering, your equation for Atom Economy is essentially calculating for something similar to percent yield (but not quite).

\(Atom \hspace{3} Economy \hspace{3} = \hspace{3} \frac{Molar \hspace{3} Mass \hspace{3} of \hspace{3} Product}{Molar \hspace{3} Mass \hspace{3} of \hspace{3} All \hspace{3} Reactants} \cdot 100 \%\)

Molar Mass of Al - 26.98 g/mol

Molar Mass of O - 16.00 g/mol

Reactants: 4(26.98 g/mol) + 6(16.00 g/mol) = 203.92 g/mol

Products (Al as end product): 4(26.98 g/mol) = 107.92 g/mol

\(Atom \hspace{3} Economy \hspace{3} = \hspace{3} \frac{107.92 \hspace{3} g/mol}{203.92 \hspace{3} g/mol} \cdot 100 \%=52.9227 \%\)

Molar Mass of Fe - 55.85 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of C - 12.01 g/mol

Reactants: 4(55.85 g/mol) + 6(16.00 g/mol) + 3(12.01 g/mol) = 355.43 g/mol

Products (Fe as end product): 4(55.85 g/mol) = 223.4 g/mol

\(Atom \hspace{3} Economy \hspace{3} = \hspace{3} \frac{223.4 \hspace{3} g/mol}{355.43 \hspace{3} g/mol} \cdot 100 \%=62.8534\%\)

Step 6: Check for significant figures

Since we are not given any values, we don't really need to change any numbers to fit sig fig rules.

Answer:

The reaction that takes place in an electro-chemical cell is the Redox reaction, a type of reversible reaction combining both oxidation and reduction reactions.

We require the equation to understand the process that occurs when X reacts with Y to form an ionic compound.The chemical equation for the formation of the ionic compound between X and Y would be: X + Y → XYwhere X represents the alkali metal in group I and Y represents a non-metal that is most likely in group VII. This equation represents the process of how the two elements react with each other to create an ionic compound.

Element X is found in group I of the periodic table, which means it belongs to the alkali metal group. Alkali metals are well-known for their reactivity, with the exception of lithium, which is the least reactive alkali metal. Alkali metals react with other elements to form ionic compounds. Let’s take a closer look at this process.Element X reacts with Element Y to create an ionic compound, which means that Element X becomes an ion in the process. Since Element X is an alkali metal, it has only one valence electron.

To form a positive ion, it loses this valence electron.Element Y, on the other hand, is probably a non-metal since it’s reacting with an alkali metal. Non-metals, unlike alkali metals, have a high electronegativity. As a result, they have a tendency to take electrons from other elements in order to complete their valence shells.

As a result, Element Y gains an electron in this instance.Since X loses its valence electron and Y gains an electron, X becomes a positive ion and Y becomes a negative ion. The resulting ionic compound is formed by the attractive forces between the positive and negative ions. The formula of the ionic compound is determined by the ratio of the ions present.

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Answer:

F

Explanation:

"The mass of the products is equal to the mass of the reactants" is true about the principle of the conservation of mass.

So, option f is correct one.

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Answer:

The value \(N_A = 0.192 \ mol \cdot m^{-2} \cdot \ s\)

Explanation:

From the question we are told that

     The thickness of the air is \(z_2 - z_1 = 1 \ cm =0.01 \ m\)

      The temperature is  \(T = 25^oc = 25 +273 = 298 \ K\)

     The total pressure is  \(P_T = 1 atm = 1.01325*10^{5} \ Pa\)

      The partial pressure of Ammonia first side is  \(P_{AO} = 0.9 \ atm = 0.9 * 1.01325*10^{5} = 91192.5 \ Pa\)

      The partial pressure of Ammonia to the second side is \(P_{A} = 0.1 \ atm = 0.1 * 1.0325*10^{5} = 10132.5 \ Pa\)

 Rate of flow of ammonia is  

          \(D_{AB} = 0.214 \ cm/s = \frac{0.214 }{10000} = 2.14 *10^{-5} \ m^2 /s\)

Generally the  molar flux of ammonia is mathematically represented as

         \(N_A = \frac{D_{AB} * P_T }{RT(z_2 -z_1)} * ln [\frac{P_T - P_{Al}}{P_T - P_{AO}} ]\)

Here R is the gas constant with value  

         \(R = 8.314 \ m^3 \cdot Pa \cdot mol^{-1} \cdot K\)

             \(N_A = \frac{2.14 *10^{-5} * 1.01325*10^{5} }{8.314 *298 (0.01)} * ln [\frac{1 - 0.1}{1 - 0.9} ]\)

=>           \(N_A = 0.192 \ mol \cdot m^{-2} \cdot \ s\)

Total 5×10²¹ molecules of C₂H₆ are present in a sample of ethane which contain 3.00 x 10²² atoms of hydrogen.

We have a sample of ethane. Number of hydrogen atoms contain in C₂H₆ = 3.00 x 10²² atoms. Let us consider a reaction,

C₂H₆ → 2C+ 6H

From the equation, there is two carbon atoms and six hydrogen atoms. That means one molecule of ethane contains six hydrogen atoms. Six H-atoms are present in the no. of molecules of C₂H₆

= 1 molecule

3.00 x10²², H-atoms are present in the no. of molecules of C₂H₆= (3x10²²)/6 molecule

= 0.5×102²² molecule

= 5 × 10²¹ molecule

Hence, required number of molecules are 5×10²¹ molecule.

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The following statements on HPLC modes are true is more polar compounds elute first in normal-phase HPLC (Option E).

The liquid chromatography (HPLC) is a technique in analytical chemistry employed for the separation, identification, and quantification of elements. It is considered a highly sensitive method, and it works by separating the components in a mixture with the assistance of a solvent under high pressure.

There are two modes of HPLC: Reversed-Phase HPLC (RP-HPLC) and Normal-Phase HPLC (NP-HPLC). In RP-HPLC, a nonpolar stationary phase, such as C18, is used, and polar solvents, such as water, are used as mobile phases. Polar stationary phases, such as silica gel, are used in NP-HPLC, while nonpolar solvents, such as hexane, are used as mobile phases.

More polar compounds have a greater affinity for the polar stationary phase than less polar compounds, which have a higher affinity for the nonpolar mobile phase in NP-HPLC. As a result, less polar compounds elute first in normal-phase HPLC.

Thus, the correct option is E.

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Answer:

A. cars, submarines, spacecraft

Explanation:

I took the test.

Answer: I don't know try your best

Explanation:

NaCl is correct answer of your question

Answer:

NH4OH

Explanation:

BCOZ IT IS PRESENT IN 15th GROUO WHICH NON METAL

There are 2.96 x 10^23 CN^-1 ions in the sample of 20.9 g of Ca(CN)2.

The first step to solving this problem is to calculate the number of moles of Ca(CN)2 in the sample:

\(moles of Ca(CN)2 = mass / molar mass\\moles of Ca(CN)2 = 20.9 g / (40.08 g/mol + 2 * 26.02 g/mol)\\moles of Ca(CN)2 = 0.2458 mol\)

Next, we can use the stoichiometry of the reaction to find the number of moles of CN^-1 ions:

1 mol Ca(CN)2 → 2 mol CN^-1

\(moles of CN^{-1} = 2 * moles of Ca(CN)2 \\moles of CN^{-1 }= 2 * 0.2458 mol\\moles of CN^{-1} = 0.4916 mol\)

Finally, we can convert the moles of CN^-1 ions to the number of ions using Avogadro's number:

1 mol CN^-1 → 6.022 x 10^23 ions

number of CN^-1 ions = moles of CN^-1 x Avogadro's number

number of CN^-1 ions = 0.4916 mol x 6.022 x 10^23 ions/mol

number of CN^-1 ions = 2.96 x 10^23 ions

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A chemical conducts electricity when dissolved in water, turns litmus red, and has a sour flavor. The substance in the solution can be acidic.

Depending on how one chooses to view the characteristics of acidity and basicity, the terms "acid" and "base" have different definitions. According to Arrhenius, bases are chemicals that ionize to produce hydroxide ions while acids are compounds that ionize to produce hydrogen ions. According to the Lowry-Bronsted definition, a base is a proton acceptor, whereas an acid is a proton giver.

According to the Lewis definition, bases are described as molecules or ions that can coordinate with unshared electron pairs while also having unshared electron pairs that are accessible for sharing with acids. For a molecule to be acidic in the Lewis sense, it must be electron-deficient. The most inclusive definition of acid and base is this.

All Lowery Bronstead acids are Lewis acids, which also contain a variety of other reagents like boron trifluoride, aluminum chloride, etc.

Because amine groups are frequently found in naturally occurring bitter compounds, many bases are in reality bitter chemicals, whereas acidic compounds are supposed to taste sour due to the presence of hydrogen ions. Amine bases can easily break. Acids taste sour due to the pH level.

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The SL-3 components of the M240B medium machine gun are used for barrel replacement and maintenance.

The SL-3 components of the M240B consist of a spare barrel and a barrel bag. The spare barrel is an essential component for sustained firing and allows for the replacement of a hot or worn-out barrel during extended periods of continuous use. When the barrel becomes overheated, it can negatively impact the weapon's accuracy and potentially cause malfunctions. The spare barrel is designed to be quickly swapped with the hot barrel to ensure optimal performance and prevent damage to the weapon.

The barrel bag is used to safely store the hot or dirty barrel after it has been replaced. It serves as a protective cover to prevent accidental contact and potential burns while the barrel is still hot. Additionally, the bag helps contain any carbon or residue that may be present on the barrel, preventing it from spreading and contaminating other equipment or personnel. The barrel bag is an essential part of the maintenance process, ensuring safe handling and transportation of the replaced barrel until it can be properly cleaned and inspected.

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Answer:

46.5

Explanation:

1.307 m + 45.2 m = 46.507

Rounded to the correct amount of signifigant figures it would be 46.5.

The operation 1.307 m + 45.2 m results in the value of m is equivalent to 46.5 m

The operations is defined as a functions which is take zero or more input value to give a well defined output value.

There are mainly four arithmetic operations:

This operations are well known as binary operations.

This four operations are considered as very important operations for all kind of calculations.

1.307 m + 45.2 m = 46.507 m

Rounded to correct amount of significant figures it would be 46.5 m

Thus, the operation 1.307 m + 45.2 m results in the value of m equivalent to 46.5 m

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Alpha-amylase breaks the alpha-1,4-glycosidic bonds found in starch molecules.

Alpha-amylase is an enzyme that catalyzes the hydrolysis of alpha-1,4-glycosidic bonds in starch, a type of polysaccharide composed of glucose monomers. Starch is a major carbohydrate storage molecule in plants and is also an important component of the human diet.

When alpha-amylase encounters a starch molecule, it binds to the polysaccharide chain and cleaves it into smaller pieces, called dextrins, by breaking the alpha-1,4-glycosidic bonds between glucose monomers.

The resulting dextrins can then be further broken down into glucose by other enzymes, such as beta-amylase and glucoamylase.

Alpha-amylase is produced by various organisms, including humans, animals, and bacteria. In humans, alpha-amylase is produced in the salivary glands and pancreas and is involved in the initial breakdown of starch in the mouth and small intestine, respectively.

Overall, alpha-amylase plays an important role in the digestion and utilization of starch as a source of energy.

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Alpha-amylase breaks α-1,4-glycosidic bonds between glucose molecules in polysaccharides such as starch and glycogen.

Alpha-amylase breaks glycosidic bonds between glucose molecules in polysaccharides such as starch and glycogen. It specifically targets the α-1,4-glycosidic bond, which is the bond between two glucose units connected in a linear chain. This enzyme hydrolyzes this bond, releasing maltose and shorter polysaccharide chains.

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The wave B has wavelength of 415 nm. The value for c is 3.00 x 10 8 m/s. The frequency is 7.22 x 10¹¹ Hz.

Frequency is defined as the number of waves passing through a fixed point in a given amount of time.

The frequency can also be defined as a repeated event is the number of occurrences per unit of time.

Frequency can be expressed as

f = c / ∧

Where c = 3.00 x 10⁸ m/s

           ∧ = 415 nm

So, f = 3.00 x 10⁸ m/s x 415 nm

      f = 7.22 x 10¹¹ Hz.

Thus, the wave B has wavelength of 415 nm. The value for c is 3.00 x 10 8 m/s. The frequency is 7.22 x 10¹¹ Hz.

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Answer:

Things that are negatively charged and things that are positively charged pull on (attract) each other. This makes electrons and protons stick together to form atoms. Things that have the same charge push each other away (they repel each other). This is called the Law of Charges.

Explanation:

According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge.

Answer:

Like charges repel each other; unlike charges attract.

Explanation:

Answer: Part A / The four quantum numbers tell you the location and energy of an electron.

Part B / _C_ Defines the electron's orbital

            _A_ Defines the electron's energy level

            _D_ Defines the electron's spin

            _B_ Defines the electron's sublevel

Answer:  

method for procuring ammonia

Explanation:

In the Haber process, atmospheric nitrogen is converted to ammonia by reacting it with hydrogen (H2)

The number of grams of iron present in 14.79 cm length of the same iron rod is 640.51 g.

Ounces is a unit of mass which is used to define a very little amount of anything.

In the question, given that:

In one inch of iron rod whose weighs is 3.88 ounces = 2.54 cm long

In 1 g = 0.035273 ounces present

So we can calcuylate the number of grams in which 3.88 ounces present as:
x = (3.88 ounces) / (0.035273 ounces/g)

x = 110g

So, in 110g = 3.88 ounces present

And in 2.54 cm = 110g of iron present

In 14.79 cm, present grams of iron can be calculated as:

y = (14.79cm x 110g) / 2.54cm

y = 640.51 g

Hence option (c) is correct i.e. 640.51 g.

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The weight of the iron rod with 14.79 cm length with same density is given by: Option C; 640.51 g

Suppose that a finite amount of substance is there having its properties as:

Then, they are related as:

\(d = \dfrac{m}{v}\)

We know that:

Now, from the facts given in the problem, we have:

The weight of first iron rod which is one inches long = 3.88 ounces

The new rod is 14.79 cm long. And 1 cm = 0.3937 inches approx, thus the new rod is: \(14.79 \times 0.3937 \approx 5.8228 \: \rm inches\)

As for 1 inch long rod, there is  weight of 3.88 ounces, thus:

for 5.8228 inch rod, the weight of the rod would be \(5.8228 \times 3.88 \approx 22.5924 \: \rm ounces\)

And since 1 ounce = 28.3495 g approx

Thus, weight of the new rod in grams would be \(22.5924\times 28.3495 \approx 640.485 \approx 640.51\: \rm g\)

Thus, the weight of the iron rod with 14.79 cm length with same density is given by: Option C; 640.51 g

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Answer:

When an electron absorbs energy, it jumps to a higher orbital. This is called an excited state. An electron in an excited state can release energy and 'fall' to a lower state. When it does, the electron releases a photon of electromagnetic energy.

Explanation: