answer in comments pls!

Subsets 1 and 3 are subspaces, while subsets 2 and 4 are not.

To determine which subsets are subspaces, we need to check if they satisfy the three conditions of being a subspace:

closure under addition, closure under scalar multiplication, and containing the zero vector. Let's evaluate each subset:

  This subset is a subspace. It satisfies closure under addition, closure under scalar multiplication, and contains the zero vector (0, 0, 0). Therefore, it is a subspace of ℝ³.

  This subset is not a subspace. While it satisfies closure under addition, it fails to satisfy closure under scalar multiplication. If we multiply a polynomial with a non-zero term by zero, the result will not have a non-zero term. Therefore, it does not contain the zero vector, violating the subspace condition.

  This subset is a subspace. It satisfies closure under addition, closure under scalar multiplication, and contains the zero matrix [0, 0; 0, 0]. Hence, it is a subspace of the space of 2x2 matrices.

  This subset is not a subspace. It fails to satisfy closure under scalar multiplication.

If we scale a vector whose endpoint lies on the line y = 2x by a non-zero scalar, the endpoint will no longer lie on the line y = 2x.

Thus, it does not contain the zero vector, violating the subspace condition.

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The probability of having 3 earthquakes in the same year that all measure 6.0 or more is approximately 0.1106 or 11.06%.

What is probability?

Probability is a measure of the likelihood or chance that an event will occur. It is usually expressed as a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain.

Assuming that the number of earthquakes measuring 6.0 or more on the Richter scale in a year follows a Poisson distribution with a mean of 0.93 (i.e., an average of 0.93 such earthquakes per year over the past 100 years), we can use the Poisson probability formula to find the probability of having exactly 3 such earthquakes in a year:

\(P(X = 3) = (e^{(-0.93)} * 0.93^3) / 3!\)

where X is the number of earthquakes measuring 6.0 or more on the Richter scale in a year.

Plugging in the values, we get:

\(P(X = 3) = (e^{(-0.93)} * 0.93^3) / 3! = 0.1106\)

Therefore, the probability of having 3 earthquakes in the same year that all measure 6.0 or more on the Richter scale, given that there have been 93 such earthquakes in the past 100 years, is approximately 0.1106 or 11.06%.

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Answer:

$35.75

Step-by-step explanation:

=18.75+12.50+(2 x 7.25) = $35.75

Answer: See explanation

Step-by-step explanation:

PRINCETON:

December - 50

January - 40

Decrease = 50 - 40 = 10

Percentage Decrease = Decrease/Original value × 100

= 10/50 × 100

= 20%

2) WORCESTER:

December - 256

January - 197

Decrease = 256 - 197 = 59

Percentage Decrease = Decrease/Original value × 100

= 59/256 × 100

= 23.05%

3) CHICAGO:

December - 7050

January - 6708

Decrease = 7050 - 6708 = 342

Percentage Decrease = Decrease/Original value × 100

= 342/7050 × 100

= 4.85%

Step-by-step explanation:

\(\sqrt{x^2-6x + 9} = \sqrt{(x - 3)^2}= x - 3\)

The question pertains to graphing a function and finding a one-sided limit. Specifically, we need to graph the function P(x) = 50 - 6x and determine the one-sided limit as x approaches a specific value.

Graphing the function P(x) = 50 - 6x using a graphing utility, we can visualize the behavior of the function. The graph represents a straight line with a slope of -6 and a y-intercept of 50. It slopes downwards from left to right, indicating a negative relationship between x and P(x). The graph helps us understand the overall trend and shape of the function.

To find the one-sided limit, we need to consider the behavior of the function as x approaches a specific value. In this case, the question does not provide the specific value. Therefore, we cannot determine the exact one-sided limit without knowing the value towards which x is approaching.

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The value of p-hat (the sample proportion) is 0.24, or 24% if total number of skittles in a sample is 300 out of which 72 skittles are purple.

The sample proportion, denoted by p-hat, is the proportion of purple skittles in the sample. We can calculate p-hat by dividing the number of purple skittles by the total number of skittles in the sample

p-hat = number of purple skittles / total number of skittles in sample

In this case, we have

Number of purple skittles = 72

Total number of skittles in sample = 300

Therefore,

p-hat = 72/300 = 0.24

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The equilibrium quantity is q = 24 at price p = $7,200

To find the equilibrium quantity and price, we need to set the supply equal to demand:

q^2 + 30q = -4q^2 + 10q + 19,200

Simplifying and rearranging, we get:

5q^2 - 20q + 19,200 = 0

Using the quadratic formula, we can solve for q:

q = [20 ± sqrt(20^2 - 4(5)(19,200))]/(2(5))

q = [20 ± 220]/10

Since a negative quantity of the commodity doesn't make sense in this context, we can reject the negative solution, leaving us with:

q = (20 + 220)/10 = 24

Now, we can use either the supply or demand function to find the equilibrium price. We'll use the demand function:

p = -4(24)^2 + 10(24) + 19,200

p = $7,200

Therefore, the equilibrium quantity is 24 units and the equilibrium price is $7,200 per unit.

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Answer:1

Step-by-step explanation:

to find the slop you have to use the formula m=y2-y1/x2-x1 but before you do that you have to label them like the first points (-8,-5) is (x1,y1) the the other points are (5,-8) which are (x2,y2) put them in a formula like M=y2-y1/x2-x1 which you get +1 as they answer.

Answer:

Step-by-step explanation:

m = \(\frac{y_{2} -y_{1} }{x_{2} -x_{1} }\)

y - \(y_{1}\) = m( x - \(x_{1}\) )

(- 8, - 5)

(5, - 8)

m = \(\frac{-5+8}{- 8-5}\) = \(-\frac{3}{13}\)

y + 8 = \(-\frac{3}{13}\) ( x - 5 )

y = \(-\frac{3}{13}\) ( x - 5 ) - 8

Explanation

To solve the question, we will be aware that

There are 3 hours between 6PM and 9PM ,

The main pump's emptying rate is 1/4 tanker per hour. It will be open

the entire 3 hours, so it will empty 3/4 of the tank.

this means that the auxiliary pump must empty the remaining 1/4

Thus

Thus, we will have

Therefore

The auxiliary pump should start by 6pm + 45 minutes = 6:45pm

Answer:

I think the right answer is d

Answer:

The last equation (D): doesn't have a real solution

Step-by-step explanation:

Notice that equation A has for solution x = 1/2

Equation B has for solution x = 0

Equation C has for solution x = 0

There is no real number that multiplied by itself can render a negative value.

Answer:

58.1 degrees

Step-by-step explanation:

Given the following

JK = 9.4miles (towards south) negative y axis

If the move 15.1 miles towards east (that will be towards the positive x axis)

Using the SOH CAH TOA identity

opposite= 15.1 miles(side facing m<J)

adjacent= JK = 9.4miles

tan theta = opposite/adjacent

tan m<J = 15.1/9.4

tan m<J = 1.6063

m<J = arctan (1.6063)

m<J = 58.09 degrees

Hence the measure of m<J to the nearest tenth is 58.1 degrees

The statement "The control limits represent the range between which all points are expected to fall if the process is in statistical control" is True.

Control limits play a crucial role in statistical process control (SPC) by delineating the range within which all data points are anticipated to fall if the process operates under statistical control.

These limits, usually set at a certain number of standard deviations from the process mean, aid in assessing whether a process exhibits statistical control. The commonly employed control limits are ±3 standard deviations, which encompass approximately 99.7% of the data when the process adheres to a normal distribution and maintains statistical stability.

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Answer:

184

Step-by-step explanation:

i did it this on a test a while back

Answer: 125 Pencils per Box

Step-by-step explanation:

This is a fraction equal to

2250 Pencils ÷ 18 Boxes

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 18

2250 Pencils ÷ 18

18 Boxes ÷ 18

=  

125 Pencils

1 Box

=  

125 Pencils

Box

= 125 Pencils per Box

Among the given numerical iterative methods for solving ordinary differential equations, the Euler Method typically results in the highest error.

The Euler Method is a first-order numerical method that approximates the solution of an ordinary differential equation (ODE) by using a simple forward difference formula. While it is relatively easy to implement, it tends to introduce a larger error compared to higher-order methods. The method essentially approximates the derivative at each step by assuming a constant slope between two points, which can lead to significant errors, especially when dealing with complex or nonlinear ODEs.

On the other hand, the other methods listed—such as the Modified Euler Method, 2nd Order Runge-Kutta Method, and 4th Order Runge-Kutta Method—are higher-order methods. They involve more calculations and take into account multiple points and intermediate steps to improve the accuracy of the approximation. These methods are known to provide better results and higher precision compared to the Euler Method.

Therefore, among the given options, the Euler Method generally results in the highest error when solving ordinary differential equations, while the other methods listed offer improved accuracy and are commonly preferred for numerical ODE solutions.

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Answer:

(-5, 0, 1, 5)

Step-by-step explanation:

It is asking for all the points on the domain (the x line / the one going sideways)

So you take each point and bring it down until it touches the x line. Then you order the numbers you get from least to greatest.

Answer: C. a prediction based on the data is reliable, because the means of the samples are close together.

Step-by-step explanation:

Answer:

1. Angles: <F=<J, <H=<H, <G=<K

Sides: FG/JK, GH/KH, FH/JH

2. 1/4 3. 5/2 4. X=12 5. 122.5 units 6. x=8; y=35 7. X=3 8. x=25 9. x=12 10. x=15 11. X=14 12. x=13

Step-by-step explanation:

2. 4/8 =1/4

3. 10/4=5/2

4. 5x=60(x=12)

5. 7(35)/2: 245/2= 122.5 units

6. x/28= 6/21: 21x=168: x=8

7. 49/14= 9(x+1)/(x+5): 49(x+5)=9(x+1)+14: 49x+245=126x+14: 245-14=126x-49x: 231=77x: x=3

8. 52/91=x+3/2x1: 52(2x-1)= 91(x+3): 104x-52=91x+273: 13x=325: x=25

9. 5x-3/3x+2= 60/40: 60(3x+2)= 40(5x-3): 200x-120=180x+120: 200=180x+120: 20x=240: x=12

10. 168x-280=160x-60: 8x-120: x=15

11. 12/x+1= 32/3x-2: 12(3x-2)= 32(x+1): 36x-24=32x+32: 4x=56: x=14

12. x+4/2x-7= 51/57: 57(x+4)= 51(2x-7): 57x +228=102x-357: -45x = -585: x=13

The value of the lesser integer is 7

Algebraic expressions are expressions consisting of both variables and constants and are also made up of mathematical operations such as addition, subtraction, division, multiplication, etc.

From the information given, we have;

Let the integers be (x) and ( x + 2)

8(x + 2) - (x)= 23

Expand the bracket

8x + 16 - x = 23

collect like terms

8x - x = 23 - 16

Add/subtract like terms

7x = 7

Make 'x' the subject

x = 7/7

The value for the lease integer = x

Substitute the value of x

7

Thus, the value of the lesser integer is 7

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Answer:

This will plot as an upward  "V" with the vertex at x = 4/3, y = 5

Step-by-step explanation:

The absolute value will mean that y can only be positive. y will be at a minimin when the absolute value is zero. To determine that find the x that makes it zero, so

-3x + 4 = 0

-3x = -4

x = 4/3

which makes y = 5 (the minimin)

Answer:

Below

Step-by-step explanation:

k = 4-a

a (4-a) = 3

-a^2 +4a -3 = 0   ====> Quadratic Formula ===>  a =  1   and k = 3

1^3 + 3^3 = 28

Each person who buys a ticket can expect to lose 45 cents. This can be answered by the concept of Average.

The expected value of the raffle is the average amount a ticket buyer can expect to win or lose. To find the expected value, we need to multiply the probability of winning each prize by the value of the prize, and then sum up those products.

Therefore, the expected value of the raffle is calculated as the sum of the probability of winning the grand prize multiplied by its value, plus the probability of winning the second prize multiplied by its value, plus the probability of winning any of the five $100 Amazon cards multiplied by their value, minus the cost of buying a ticket.

To calculate the expected value, we need to determine the probability of winning each prize. Since there are 2,200 tickets sold, the probability of winning the grand prize is 1/2,200, the probability of winning the second prize is 1/2,199, and the probability of winning any of the five $100 Amazon cards is 1/440.

Therefore, the expected value of the raffle is (1/2,200 x $2,500) + (1/2,199 x $500) + (5/440 x $100) - ($5 x 2,200) = $-0.45. This means that on average, each person who buys a ticket can expect to lose 45 cents

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Answer:

6/18 which simplifies to 1/3

Step-by-step explanation:

you know that there are 6 reds so you put that on the numerator of the fraction and you add everything together to get the denominator. then the final answer is 6/18 and you simplify that to 1/3

The compound inequality for the given situation is $2.75x + $4.25y ≥ $65 and $2.75x + $4.25y ≤ $75, where x represents the number of daylight cameras and y represents the number of flash cameras.

To solve this compound inequality, we need to find the values of x and y that satisfy both conditions. The inequality $2.75x + $4.25y ≥ $65 represents the lower bound, ensuring that the total cost of the cameras is at least $65. The inequality $2.75x + $4.25y ≤ $75 represents the upper bound, making sure that the total cost does not exceed $75.

To list the solutions involving whole numbers of cameras, we need to consider integer values for x and y. We can start by finding the values of x and y that satisfy the lower bound inequality and then check if they also satisfy the upper bound inequality. By trying different combinations, we can determine the possible solutions that meet these criteria.

After solving the compound inequality, we find that the solutions involving whole numbers of cameras are as follows:

(x, y) = (10, 10), (11, 8), (12, 6), (13, 4), (14, 2), (15, 0), (16, 0), (17, 0), (18, 0), (19, 0), (20, 0).

These solutions represent the combinations of daylight and flash cameras that fulfill the requirements of buying exactly 20 cameras and spending between $65 and $75.

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The value of the probability of choosing a green lollipop and a purple lollipop is, 8 / 45

We have to given that;

One bag contains 3 red lollipops and 2 green lollipops.

And, The other bag contains four purple lollipops and five blue lollipops.

Hence, The probability of choosing a green lollipop is,

P₁ = 2 / 5

And, The probability of choosing a purple lollipop is,

P₂ = 4 / 9

Thus, The value of the probability of choosing a green lollipop and a purple lollipop is,

P = P₁ ×  P₂

P = 2/5 × 4/9

P = 8/45

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Step-by-step explanation:

4x,+10-2x=70

2x+10=70

2x=60

x=60

2

x=30

hope it helps.

Answer:

x=30

Step-by-step explanation:

4x+10-2x=70

Combine 4x and -2x

2x+10=70

Isolate variable

2x=60

divide everything by 2

x=30

Answer:

31/33

0.93 is a repeating decimal number and you want to convert it to a fraction or mixed number. When you say 0.93 repeating, you could mean that 3 or 93 is repeating.

Thus, there are two different ways of answering "What is 0.93 repeating as a fraction?" Here are the two questions formulated in mathematical terms with the vinculum line above the decimal numbers that are repeating.

0.93 repeating as a fraction

0.93 repeating as a fraction

The formula to convert any repeating decimal number to a fraction is as follows:

(DN x F) - NRP

DN = Decimal Number

F = 10 if one repeating number, 100 if two repeating numbers, 1000 if three repeating numbers, etc.

NRP = Non-repeating part of decimal number.

Below shows you how to get the answer to each of the two different questions above using our formula.

0.93 repeating as a fraction

(0.93 x 10) - 0.9

9

 =  

8.4

9

 =  

84

90

Below is the answer in the simplest form possible:

0.93 repeating as a fraction

= 14/15

0.93 repeating as a fraction

(0.93 x 100) - 0

99

 =  

93

99

Below is the answer in the simplest form possible:

0.93 repeating as a fraction

= 31/33

To find the coordinate matrix of the polynomial p(x) = 5 + 8x + x^2 + 4x^3 relative to the standard basis for P3, follow these steps:

1. Identify the standard basis for P3: {1, x, x^2, x^3}.
2. Write the polynomial p in terms of the standard basis: p(x) = 5(1) + 8(x) + 1(x^2) + 4(x^3).
3. Create a coordinate matrix by placing the coefficients of the standard basis elements in a column matrix:

The coordinate matrix is:
[5]
[8]
[1]
[4]

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