An understanding of which of these best enabled scientists to determine the approximate ages of fossils?.
Answers
The understanding of radioactive decay best enabled scientists to determine the approximate ages of fossils.
Radioactive decay refers to the process by which unstable atomic nuclei break down into stable ones by emitting radiation. In this process, the parent isotopes decay into daughter isotopes at a constant rate known as half-life, which helps scientists determine the age of a fossil.
Radiometric dating is a technique that uses the principles of radioactive decay to determine the age of rocks and fossils. By analyzing the proportions of parent and daughter isotopes in a sample, scientists can calculate the amount of time that has elapsed since the rock or fossil was formed. This technique has allowed scientists to establish the geological time scale and better understand the history of life on Earth.In conclusion, an understanding of radioactive decay has been instrumental in helping scientists determine the approximate ages of fossils.
To learn more about radioactive visit;
https://brainly.com/question/1770619
#SPJ11
Related Questions
how much energy would be required to vaporize 100 g of water?
Answers
The amount of energy required to vaporize 100 g of water can be calculated using the formula:
\(Energy = Mass * Heat of Vaporization\), where Mass is the mass of water and Heat of Vaporization is the specific heat required to convert a substance from its liquid state to a gas at a constant temperature.
The heat of vaporization for water is approximately \(2.26 * 10^6 J/kg\). Therefore, to calculate the energy required, we need to convert the mass of water from grams to kilograms.
Mass = 100 g = 0.1 kg
\(Energy = 0.1 kg * 2.26 * 10^6 J/kg = 2.26 * 10^5 J\).
Therefore, it would require approximately \(2.26 * 10^5\) joules of energy to vaporize 100 g of water.
The energy required to vaporize a substance is known as the heat of vaporization. It represents the amount of energy needed to overcome the intermolecular forces and convert the substance from a liquid state to a gaseous state at a constant temperature. For water, the heat of vaporization is a relatively high value of approximately \(2.26 * 10^6 J/kg\). By multiplying the mass of water (converted to kilograms) by the heat of vaporization, we can calculate the total energy required to vaporize the given amount of water. In this case, with 100 g of water, the calculated energy requirement is approximately \(2.26 * 10^5 joules\).
Learn more about energy here:
https://brainly.com/question/1932868
#SPJ11
A cannonball
of mass 25kg is
fired straight up at an initial
velocity of 8m/s. The
gravitational field strength is
9.8m/s. Calculate the
maximum height it can reach?
Answers
If a cannonball of mass 25 kg is fired straight up at an initial velocity of 8 m / s, the maximum height it can reach is 3.27 m
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
u = 8 m / s
a = - 9.8 m / s²
At maximum height,
v = 0
Using the equation from equations of motion,
0 = 8² + ( 2 * - 9.8 * s )
19.6 s = 64
s = 3.27 m
Therefore, the maximum height it can reach is 3.27 m
To know more about equations of motion
https://brainly.com/question/5955789
#SPJ1
Refer to the image shown to answer the question.
If a light ray is reflected off the shiny surface at 170 degrees, at what angle did the light ray first strike the surface?
170 degrees
70 degrees
110 degrees
10 degrees
Answers
Answer:10
Explanation: if you look it has a 170 but some people have 70 if you have 170 then it will be 10 if you have a 70 then it will be 110 if I'm right then Yw
Answer:
10
Explanation:
i took the quiz xoxo
Halley’s comet orbits the Sun in an elliptical path as shown.During its orbit, it moves faster when it is closer to the Sun than when it is further away.What can you conclude about the comet’s potential energy as it approaches the Sun? Explain.
Answers
Given what we know, we can confirm that as Halley's comet moves closer to the sun, we can expect its potential energy to be near its maximum.
How do we know this?We can conclude that its potential energy will increase as it comes closer to the sun, and will reach its maximum at the closest point to the sun. This is because the potential energy of an object is directly proportional to the force of gravity acting on that object. As Halley's comet approaches the sun, the sun's gravitational pull on the comet is stronger, and thus, its potential energy increases.
Therefore, given the relationship between gravity and potential energy, we can confirm that s Halley's comet moves closer to the sun, we can expect its potential energy to increase and be near its maximum.
To learn more about potential energy visit:
https://brainly.com/question/21288807?referrer=searchResults
How long would it take an object traveling 12 m/s to go 60 m? Round to the nearest whole number.
Answers
Answer: It would take 5 seconds for an object traveling at 12 m/s to go 60 m. Rounded to the nearest whole number, the answer is 5 seconds.
Explanation:
To find the time it would take an object to travel a certain distance at a given speed, we can use the formula:
time = distance / speed
Plugging in the given values, we get:
time = 60 m / 12 m/s
time = 5 seconds
A trampoline spring has a force constant k = 800 N/m and is stretched exactly 17.5cm. What is the energy required to do this?
Answers
Answer:
the energy required for the extension is 12.25 J
Explanation:
Given;
force constant of trampoline spring, k = 800 N/m
extension of trampoline spring, x = 17.5 cm = 0.175 m
The energy required for the extension is calculated as;
E = ¹/₂kx²
E = 0.5 x 800 x 0.175²
E = 12.25 J
Therefore, the energy required for the extension is 12.25 J
A stationary 3-kg hard steel ball is hit head-on by a 1-kg hard steel ball moving to the right at 4 m/s. After the collision, the 3-kg ball moves to the right at 2 m/s. What is the velocity (speed and direction) of the 1-kg ball after the collision?
Answers
From conservation of momentum we have that:
\(\begin{gathered} 1(4)+3(0)=1v+3(2) \\ 4=v+6 \\ v=4-6 \\ v=-2 \end{gathered}\)Therefore the velocity of the 1 kg ball after the collision is 2 m/s to the left.
A block of mass M is sliding with an initial speed vi along a horizontal surface with negligible friction. A constant force of magnitude FA is exerted on the object at an angle θ above the horizontal, causing the object to speed up. Derive an equation for the change in the block’s kinetic energy as it moves a horizontal distance Δx. The block remains in contact with the surface the entire time.
Answers
This equation describes the change in kinetic energy of the block due to the force exerted on it as it moves a horizontal distance Δx.
What is kinetic energy?Kinetic energy is the energy an object has due to its motion. It is the energy that an object has because of its mass and velocity. Kinetic energy is measured in joules (J). Kinetic energy increases as the mass of the object increases and as the velocity of the object increases. For example, a car moving at 30 miles per hour has more kinetic energy than a car moving at 10 miles per hour.
The change in kinetic energy of the block can be calculated using the following equation:
ΔKE = (1/2)Mv2f - (1/2)Mv2i
Where M is the mass of the block, v2f is the final speed of the block, and v2i is the initial speed of the block.
To calculate the final speed of the block, we can use the equation below.
v2f = v2i + (2FAcosθΔx / M)
Where FA is the magnitude of the force, θ is the angle of the force, and Δx is the horizontal displacement of the block.
Using this equation and the equation for the change in kinetic energy, we can derive an equation for the change in the block’s kinetic energy as it moves a horizontal distance Δx.
ΔKE = (1/2)M[v2i+(2FAcosθΔx/M)]2 - (1/2)Mv2i
This equation can be simplified to:
ΔKE = (FAcosθΔx)v2i + (FAcosθΔx)2/2M
This equation describes the change in kinetic energy of the block due to the force exerted on it as it moves a horizontal distance Δx. The first term of this equation represents the increase in kinetic energy due to the increase in speed, while the second term represents the increase in kinetic energy due to the work done by the force.
To learn more about kinetic energy
https://brainly.com/question/20658056
#SPJ4
1. a ball is dropped from a height of 10 meters onto a hard surface so that the collision at the surface may be assumed elastic. under such conditions the motion of the ball is
Answers
When a ball is dropped from a height of 10 meters onto a hard surface with an assumed elastic collision, the motion of the ball will exhibit specific characteristics.
When the ball is dropped, it undergoes free fall acceleration due to gravity. As it approaches the hard surface, it gains speed due to the acceleration. Upon collision, assuming an elastic collision, the ball rebounds back up from the surface with the same speed and energy it had before the collision.
The direction of motion is reversed, causing the ball to move upwards. The ball will then undergo a deceleration due to gravity, gradually losing speed until it reaches its maximum height. The process continues, with the ball oscillating up and down, gradually losing energy due to friction and air resistance until it eventually comes to rest.
To learn more about Motion : brainly.com/question/32389249
#SPJ11
A student jumps off a sled toward the west after it stops at the bottom of an icy hill.
Based on the law of action-reaction, in what direction will the sled most likely move as the student jumps off?
Answers
Answer:
Explanation:
That’s dangerous who would do that.
Me
if an object is dropped from a height of 10 m, which of the following statements are true?multiple choice question.at any point during the fall, neither the velocity nor acceleration depends on the mass of the object.at any point during the fall, the acceleration depends on the mass of the object.at any point during the fall, the velocity depends on the mass of the object.at any point during the fall, both the velocity and acceleration depend on the mass of the object.
Answers
The correct statement regarding an object dropped from a height of 10m is that, at any point during the fall, neither the velocity nor acceleration depends on the mass of the object. Option 1 is correct.
When an object is dropped from a height of 10m, it falls freely under the influence of gravity. According to the laws of motion, the acceleration due to gravity is constant and is equal to 9.81 m/s^2. This means that the object's velocity changes by the same amount every second, regardless of its mass. Moreover, since the acceleration of the object is due to the gravitational force acting on it, it is independent of the object's mass.
Therefore, both the velocity and acceleration of the object during its fall do not depend on the mass of the object. This principle is known as the equivalence principle and is a fundamental concept in physics. It states that in a gravitational field, the effects of gravity are indistinguishable from the effects of acceleration. Therefore, the mass of an object has no influence on its motion under gravity, and both the velocity and acceleration are independent of the object's mass. Option 1 is correct.
To know more about the Object, here
https://brainly.com/question/30714190
#SPJ4
Solar Energy The amount of energy collected by a solar panel depends on the intensity of the sun's rays and the area of the panel. Let the vector I represent the intensity, in watts per square centimeter, having the direction of the sun's rays. Let the vector A represent the area, in square centimeters, whose direction is the orientation of a solar panel. See the figure. The total number of watts collected by the panel is given by W=|I⋅A|
Suppose that I=⟨−0.02,−0.01⟩ and A=⟨300,400⟩
(Image can't copy)
(a) Find ‖ and and interpret the meaning of each.
(b) Compute and interpret its meaning.
(c) If the solar panel is to collect the maximum number of watts, what must be true about I and A?
Answers
The intensity of the sun's rays and the orientation of the solar panel must be aligned in the same direction.
How to CalculateA) To find the magnitude of I and A, we can use the formula
‖I‖ = √(x^2 + y^2)
where x and y are the components of the vector.
‖I‖ = √((-0.02)^2 + (-0.01)^2) = 0.02236 watts per square centimeter
‖A‖ = √(300^2 + 400^2) = 500 square centimeters
The magnitude of I represents the intensity of the sun's rays, and the magnitude of A represents the area of the solar panel.
B) To compute W, we can use the formula
W=|I⋅A|
where I and A are vectors. The dot product of two vectors is given by I⋅A = (Ix)(Ax) + (Iy)(Ay). W = |(-0.02)(300) + (-0.01)(400)| = |-6 - 4| = 10 watts
The meaning of W is the total number of watts collected by the solar panel.
C) To collect the maximum number of watts, the vectors I and A must be parallel. This means that the angle between them must be 0 degrees, and the dot product I⋅A will be equal to ‖I‖‖A‖.
In other words, the intensity of the sun's rays and the orientation of the solar panel must be aligned in the same direction.
Learn more about solar energy at
https://brainly.com/question/404452
#SPJ11
Which type of electromagnetic wave has the lowest frequency?
A. Infrared light
B. Visible light
C. X-rays
D. Gamma rays
Answers
The type of electromagnetic wave that has the lowest frequency is infrared light (option A).
What is an electromagnetic wave?Electromagnetic spectrum is the entire range of wavelengths of all known electromagnetic radiations.
The electromagnetic spectrum extends from the following waves:
gamma raysX-raysvisible lightinfraredradio waves.The frequency of each electromagnetic wave is as follows:
Gamma ray: 10²⁰ – 10²⁴X-rays: 10¹⁷– 10²⁰Visible light: 10¹⁵– 10¹⁷Infrared: 10¹³ – 10¹⁴radio waves: < 3 x 10¹¹Therefore, infrared light has the lowest frequency of the options.
Learn more about electromagnetic waves at: https://brainly.com/question/3101711
#SPJ1
Answer: Infrared light
Explanation: I took the test
Help me please!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
I think 100V but I'm not sure.
A projectile has a range of 60 m and can reach a maximum height of 15 m. Calculate the angle at which projectile is fired? ( g = 10m/s2 )
Answers
Answer:
The angle the projectile was fired is \(45^o\)
Explanation:
Recall the formulas for maximum height and ranges for a projectile fired with initial velocity "v" at an angle \(\theta\):
\(h = \frac{v^2\,sin^2(\theta)}{2\,g}\\R=\frac{v^2\,sin(2\,\theta)}{g}\)
we can use them to solve for the angle by first isolating the value \(v^2\) which is common in both equations:
\(v^2=2\,h\,g/sin^2(\theta)=2\,(15)\,g/sin^2(\theta)=30\,(g)/sin^2(\theta) \\ \\v^2=R\,g/sin(2\,\theta)=60\,(g)/sin(2\,\theta)\)
and now, making those to expressions equal and using the formula for the sine of a double angle, we get:
\(\frac{30\,(9.8)}{sin^2(\theta)} =\frac{60\,(g)}{sin(2\,\theta)} \\30\,(g)\,sin(2\,\theta)=60\,(g)\,sin^2(\theta)\\sin(2\,\theta)=2\,sin^2(\theta)\\2\,sin(\theta)\,cos(\theta)=2\,sin(\theta)\,sin(\theta)\\cos(\theta)=sin(\theta)\)
This happens when \(\theta=45^o\)
Which organism are most likely to die from competition
Answers
Answer: An owl cause it is a organism
Explanation:
Blue bird is the organism are most likely to die from competition. Bluebird are replaced by the sparrow in many conditions.
Write about the competition in organisms?Competition is most commonly characterized as the interaction of people vying for a limited-supply shared resource,
Competition in organism can also be defined as the direct or indirect interaction of organisms that results in a change in fitness when they share the same resource.
Bluebird are replaced by the sparrow in many conditions.
Hence, blue bird is the organism are most likely to die from competition.
To learn more about the competition in organisms, refer to the link;
https://brainly.com/question/13775651
#SPJ2
If the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27o, find the refractive index of the material
Answers
The refractive index of the material is 0.
When the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27°, the refractive index of the material can be determined. The formula for Snell’s law is used to calculate refractive index. It states that: `sin i / sin r = n where i is the angle of incidence, r is the angle of refraction and n is the refractive index`.Snell’s law can be re-arranged to make n the subject of the formula to be: `n = sin i / sin r`Hence, we can calculate the refractive index as follows:
For the incident ray, i = 360° and the angle of refraction within the material, r = 27°.n = sin i / sin r= sin 360°/ sin 27°= 0/1 (since sin 360° = 0)= 0Therefore, the refractive index of the material is 0. T
Learn more about refractive index here :-
https://brainly.com/question/30761100
#SPJ11
a car has a velocity of 87 km/hr to the east. What is its displacement if it travels at this velocity for 30 minutes?
Answers
Answer:
displacement = 43.5 km
Explanation:
displacement = velocity * time taken
Here speed is 87 km/hr, which is given in km per hour
So we need to change the given time to hours:
60 minutes = 1 hours
30 minutes = 0.5 hours
Then using the formula lets find displacement:
displacement = velocity * time taken
displacement = 87 km/hr * 0.5
displacement = 43.5 km
A block of mass 5 kg is pulled across a horizontal bench by a horizontal force. the acceleration of the block is 2.5 m/s2 when the friction force is 10 n. calculate the horizontal pulling force.
Answers
The horizontal pulling force on the block is 22.5 N.
When a block is pulled by applying a force, friction also acts on it.
The net force is calculated by taking the net value of the two forces.
The free-body diagram(FBD) of the block, is shown in the adjoining diagram.
Thus,
F - f = ma
Here F is the applied horizontal force and f is the frictional force.
Putting the given values in the above equation
F - 10 N = 5 x 2.5
F = 22.5 N
Thus, the horizontal pulling force on the block is 22.5 N.
To know more about "frictional force", refer to the following link:
https://brainly.com/question/13707283?referrer=searchResults
#SPJ4
The horizontal pulling force on the block is 22.5 N.
When a block is pulled by applying a force, friction also acts on it.
The net force is calculated by taking the net value of the two forces.
The free-body diagram(FBD) of the block, is shown in the adjoining diagram.
Thus,
F - f = ma
Here F is the applied horizontal force and f is the frictional force.
Putting the given values in the above equation
F - 10 N = 5 x 2.5
F = 22.5 N
Thus, the horizontal pulling force on the block is 22.5 N.
To know more about "frictional force", refer to the following link:
brainly.com/question/13707283?referrer=searchResults
#SPJ4
A man lowers an object of mass 12 kg from a height of 0.5m to the floor. What is the work done by him?
Answers
Answer:
Work = Force × distance
= m × g × d
= 12 × 9.8 × 0.5
= 58.8 N
If in the case , you need any help pleasee leg me know! [ you'll have to pay btw]
13. mass a (10 kg) is travelling west at 8 m/s and collides inelastically with mass b (30 kg) which is travelling east at 4 m/s. a) find the final velocity of both masses after the collision b) calculate the change in momentum of mass a. c) calculate the change in momentum of mass b d) what is the impulse mass a experiences? e) if the collision lasts for 0.06 seconds, find the net force on mass a.
Answers
After the collision, the momentum of the two-mass system must be conserved. The momentum of the system before the collision is equal to the momentum of the system after the collision. Therefore, the momentum of the two-mass system before the collision is equal to the momentum of the two-mass system after the collision.
Before the collision, the momentum of mass A is 8 kg m/s (10 kg times 8 m/s). The momentum of mass B before the collision is -12 kg m/s (30 kg times -4 m/s). Therefore, the total momentum of the two-mass system before the collision is equal to 8 - 12 = -4 kg m/s.
After the collision, the momentum of the two-mass system must also equal -4 kg m/s. Since mass A has a mass of 10 kg and mass B has a mass of 30 kg, we can set up the following equation:
10vA + 30vB = -4 kg m/s
Solving this equation for vB gives us the following expression:
vB = (-4 kg m/s - 10vA) / 30
We can substitute the initial velocity of mass A, 8 m/s, into this equation to get the final velocity of mass B:
vB = (-4 kg m/s - 10(8 m/s)) / 30
vB = -6 m/s
Since momentum must be conserved, the final velocity of mass A must be equal to the total momentum of the system (minus the momentum of mass B) divided by the mass of mass A. This gives us the following expression:
vA = (-4 kg m/s + 30(-6 m/s)) / 10
vA = 2 m/s
Therefore, the final velocity of mass A is 2 m/s and the final velocity of mass B is -6 m/s.
The change in momentum of mass A is equal to the initial momentum of mass A minus the final momentum of mass A.
The initial momentum of mass A before the collision is 8 kg m/s (10 kg times 8 m/s). The final momentum of mass A after the collision is 2 kg m/s (10 kg times 2 m/s). Therefore, the change in momentum of mass A is equal to 8 - 2 = 6 kg m/s.
The change in momentum of mass B is equal to the initial momentum of mass B minus the final momentum of mass B.
The initial momentum of mass B before the collision is -12 kg m/s (30 kg times -4 m/s). The final momentum of mass B after the collision is 6 kg m/s (30 kg times -6 m/s). Therefore, the change in momentum of mass B is equal to -12 - 6 = -18 kg m/s.
The impulse experienced by mass A is equal to the change in momentum of mass A divided by the time during which that change occurs. Since the change in momentum of mass A is 6 kg m/s and the time of the collision is likely instantaneous, the impulse experienced by mass A is 6 kg m/s.
The net force on mass A is equal to the impulse experienced by mass A divided by the time of the collision. Since the impulse experienced by mass A is 6 kg m/s and the time of the collision is 0.06 seconds, the net force on mass A is equal to 6 kg m/s / 0.06 s = 100 N.
Learn more about colission:
https://brainly.com/question/24915434
#SPJ4
A car traveling at 25 m/s speeds up to 30 m/s over a period of 5 seconds. The average acceleration of the car is?
Answers
Answer:
a= 1 m/s^2
Explanation:
Average acceleration can be found by dividing the change in velocity by the time.
a= ΔV/t
The change in velocity is the difference of the final velocity and initial velocity.
ΔV= final velocity - initial velocity
The final velocity is 30 m/s and the initial velocity is 25 m/s
ΔV= 30 m/s- 25 m/s
ΔV= 5 m/s
The time is 5 seconds.
Now we know the two values.
ΔV= 5 m/s
t= 5 s
Substitute the values into the formula.
a= 5 m/s / 5 s
Divide.
a= 1 m/s/s
a= 1 m/s^2
The average acceleration of the car is 1 meter per second squared.
One strategy that has been implemented to address the drug epidemic in Philadelphia was the creation of something called
Answers
The One strategy implemented to address the drug epidemic in Philadelphia is the creation of Comprehensive User Engagement Sites (CUES). These sites aim to tackle the widespread issue of drug addiction and related energy health concerns.
The CUES are safe spaces where individuals battling addiction can energy access various harm reduction services, such as clean syringes, medical support, and overdose prevention. These sites provide connections to addiction treatment programs and mental health services, helping people on their path to recovery. By offering safe and supervised spaces, CUES work to reduce public drug use, discarded syringes, and other related issues in the community. CUES also serve as educational hubs, raising awareness and providing information about the dangers of drug addiction and available resources for support. Lastly, these sites foster community engagement and collaboration, uniting various stakeholders in the fight against the drug epidemic. In summary, Comprehensive User Engagement Sites play a significant role in addressing the drug epidemic in Philadelphia. They provide harm reduction services, treatment programs, and community support, all while promoting a safer and healthier environment for the city's residents.
learn more about energy here.
https://brainly.com/question/2409175
#SPJ11
If the mass of both vehicles were doubled, how would the final velocity and the change in kinetic energy be affected?
-The change in kinetic energy would be 2 times as great.
-The final velocities would each have the same magnitude as before
Answers
The kinetic energy of the vehicles would double, and the mass would also double, the change in kinetic energy would be twice as great as it was before.
Explanation:-
The change in kinetic energy would be 2 times as great and the final velocities would each have the same magnitude as before if the mass of both vehicles were doubled.
The law of conservation of energy states that the change in kinetic energy of an object is equal to the work done on it. Kinetic energy is directly proportional to mass and the square of the velocity;
thus, the final velocity and the change in kinetic energy can be determined as follows:
KE = (1/2)mv²,
where KE is the kinetic energy, m is the mass, and v is the velocity.
When the mass of both vehicles is doubled, it is expected that their final velocities would each have the same magnitude as before.
According to Newton's Second Law, the acceleration is inversely proportional to the mass when the force remains constant.
F = ma,
where F is the force, m is the mass, and a is the acceleration.
The magnitude of the force acting on each vehicle would be constant,
so the acceleration would be inversely proportional to the mass.
As a result, the final velocities would each have the same magnitude as before.
Mathematically,
v = √(2KE/m)
Since the kinetic energy of the vehicles would double, and the mass would also double, the change in kinetic energy would be twice as great as it was before.
Therefore, the change in kinetic energy would be 2 times as great.
Know more about Newton's Second Law here,
https://brainly.com/question/15280051
#SPJ11
Empujamos un baúl 3 metros, para ello aplicamos una fuerza de 200 Newton. ¿Cuál es el trabajo realizado?
Answers
Answer:
Trabajo realizado = 600 Nm
Explanation:
Dados los siguientes datos;
Fuerza = 200 Newton
Distancia = 3 metros
Para encontrar el trabajo realizado; Trabajo realizado = fuerza * distancia
Sustituyendo en la ecuación, tenemos; Trabajo realizado = 200 * 3
Trabajo realizado = 600 Nm
You push a 400 kg car for 6 m with a force of 300 N? What is the car’s final speed if all your work became kinetic energy?
Group of answer choices
3 m/s
5.8 m/s
80 m/s
0.40 m/s
Answers
Answer:
3m/s
Explanation:
KE = ¹/₂ mv²
But workdone = F x d
Workdone = 300 x 6
Workdone = 1800J
Now per the question.
assuming
workdone= KE
Then
KE = ¹/₂ mv²
1800J = ¹/₂ 400kg x V²
3600J = 400 x V²
3600J / 400kg = V²
9 =V²
V =√(9)
V = 3m/s
What is the current in a 160 V circuit if the resistance is 2 ohms?
Answers
Answer:
Question: What is the current in a 160V circuit if the resistance is 2Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 2Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 2
⇒ I = 160 / 2 = 80A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 20Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 20Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 20
⇒ I = 160 / 20 = 8A
\rule{200}2
Question: What is the current in a 160V circuit if the resistance is 10Ω?
Answer:
Voltage ( V ) = 160V
Resistance ( R ) = 10Ω
Current ( I ) = ?
By Ohms law
⇒ V = IR
⇒ 160 = I × 10
⇒ I = 160 / 10 = 16A
\rule{200}2
Question: Based on questions 2, 3, and 4, what happens to the current in a circuit as the resistance decreases? Increases?
Answer:
From ohms law
⇒ I = V / R
If we take Voltage as proportionality constant
⇒ I ∝ 1 / R
So, we can conclude that current is inversely proportional to resistance.
From 2, 3, 4 questions we can conclude that,
If resistance increases, current decreases and when resistance decreases, current increases.
\rule{200}2
Question: What voltage is required to move 6A through 5Ω?
Answer:
Resistance ( R ) = 5Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 5
⇒ V = 30V
\rule{200}2
Question: What voltage is required to move 6A through 10Ω?
Answer:
Resistance ( R ) = 10Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 10
⇒ V = 60V
\rule{200}2
Question:What voltage is required to move 6A through 20Ω?
Answer:
Resistance ( R ) = 20Ω
Current ( I ) = 6A
Voltage ( V ) = ?
By Ohms law
⇒ V = IR
⇒ V = 6 × 20
⇒ V = 120V
\rule{200}2
Answer:
80 amps
Explanation:
V = IR
160 volts = I(2 ohms)
I = 80 amps
It takes Josh 8 seconds to slow down from 39 m/s to 21 m/s. Calculate his acceleration
Answers
a: acceleration
Δv: change in velocity
t: time
a = Δv/t = (21-39)/8 = -18/8 m/s^2 = -2.25 m/s^2
you have two balls, a and b. ball a has mass 2.00 kg and is sitting on top of a hill 10.0 m high. ball b has a mass of 4.00 kg. a. how much potential energy does ball a have? b. if ball a were to roll to the bottom of the hill, how much kinetic energy would it have, assuming no energy lost to surroundings?
Answers
The answer to your question is: a. Ball A has a potential energy of 196 J. (b.) If Ball A were to roll to the bottom of the hill, it would have a kinetic energy of 196 J.
To calculate the potential energy of Ball A, we need to use the formula PE = mgh, where m is the mass of the object (in kg), g is the acceleration due to gravity (9.8 m/s²), and h is the height of the hill (in meters). Plugging in the values given, we get:
PE = 2.00 kg x 9.8 m/s² x 10.0 m = 196 J
So Ball A has a potential energy of 196 J.
Now, if Ball A were to roll to the bottom of the hill, it would lose its potential energy and gain kinetic energy. Since no energy is lost to the surroundings, the total energy (potential + kinetic) must remain constant. Therefore, the kinetic energy at the bottom of the hill must be equal to the potential energy at the top of the hill. That means:
KE = 196 J
So if Ball A were to roll to the bottom of the hill, it would have a kinetic energy of 196 J.
To further break down the calculations:
- For part a, we start by finding the potential energy of
A using the formula PE = mgh. We plug in the given values: m = 2.00 kg, g = 9.8 m/s², and h = 10.0 m. Then we multiply them together to get:
PE = 2.00 kg x 9.8 m/s² x 10.0 m = 196 J
So Ball A has a potential energy of 196 J.
- For part b, we need to find the kinetic energy of Ball A at the bottom of the hill. Since no energy is lost to the surroundings, the total energy (potential + kinetic) must remain constant. Therefore, the kinetic energy at the bottom of the hill must be equal to the potential energy at the top of the hill. That means:
KE = 196 J
So if Ball A were to roll to the bottom of the hill, it would have a kinetic energy of 196 J.
To know more about potential energy refer to
https://brainly.com/question/24284560
#SPJ11
Two packing crates of masses 10.0kg and 5.00kg are connected by a light string that passes over a frictionless pulley as shown in Figure. The 5.00kg crate lies on a smooth incline of angle 40.0 degree . Find the acceleration of the crates and the tension in the string.
Answers
The acceleration of the string is 4.3 m/s2.
What is Acceleration?We regard the positive direction for the vertical motion of mass m1 to be downward and the positive direction for the motion of mass m2 on the incline to be to the right and parallel to the incline.
There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
Changing the speed at which an object is travelling is what acceleration is all about. A substance is not accelerating if its velocity is not changing. The information on the right depicts an object that is speeding as it moves northward.
Therefore, The acceleration of the string is 4.3 m/s2.
To learn more about acceleration, refer to the link:
https://brainly.com/question/12550364
#SPJ1
.