A(n) ____ option for wimax is one in which a fixed-dish antenna points at the wimax tower from a rooftop or pole.

For a spring-mass-damper system subject to harmonic direct excitation, the frequency of the steady-state response, x(t), is equal to the frequency of the excitation force or input.

In a spring-mass-damper system subject to harmonic direct excitation, the steady-state response refers to the behavior of the system after it has reached a stable, periodic motion. This occurs when the transient behavior of the system has died out, and the system is oscillating at a constant amplitude and frequency.

The frequency of the steady-state response, denoted as ω (omega), is determined by the frequency of the excitation force or input applied to the system. When the excitation force is a sinusoidal function, such as F(t) = F0sin(ωt), where F0 is the amplitude and ω is the angular frequency, the system responds with a corresponding steady-state response at the same frequency.

The equation of motion for the spring-mass-damper system can be expressed as:

m(d²x/dt²) + c(dx/dt) + kx = F0sin(ωt).

To find the steady-state response, we assume a solution of the form x(t) = Xsin(ωt + φ), where X is the amplitude and φ is the phase angle. Substituting this into the equation of motion and equating coefficients of sin(ωt) and cos(ωt), we can solve for X and φ.

The frequency of the steady-state response, ω, is determined solely by the excitation force and is not influenced by the system parameters (mass, damping coefficient, and spring constant). It represents the rate at which the system oscillates in response to the harmonic excitation.

Therefore, in a spring-mass-damper system subject to harmonic direct excitation, the frequency of the steady-state response, x(t), is equal to the frequency of the excitation force or input, ω.

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Answer:

The last one

Explanation:

Pick the last one : )

The terms specific to the observer are e, f, and g. The ecliptic is the path that the Sun appears to follow across the sky throughout the year as viewed from Earth.

The horizon is an imaginary line that marks the point where the sky and the Earth's surface seem to meet. The zenith is an imaginary point directly overhead from the observer's location.

The celestial equator is an imaginary line that runs around the celestial sphere, dividing it into two hemispheres. The north celestial pole is the point directly above the observer's north horizon. The nadir is an imaginary point directly below the observer's location.

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Balancing the forces acting on a body is not enough to establish equilibrium because equilibrium also requires the balancing of torques or moments acting on the body.

In physics, equilibrium refers to a state in which an object or system experiences no net force and no net torque. For an object to be in equilibrium, both the forces and the torques acting on it must be balanced.

Balancing the forces means that the vector sum of all the forces acting on the body is equal to zero. This ensures that there is no net force acting on the object, and it will not accelerate in any direction. However, even if the forces are balanced, the object can still rotate or have a tendency to rotate if the torques acting on it are not balanced.

A torque, also known as a moment, is a measure of the tendency of a force to rotate an object about a specific axis. It depends on the magnitude of the force, the distance from the axis of rotation, and the angle between the force and the lever arm. When torques are balanced, the sum of all the torques acting on the object is equal to zero.

To establish equilibrium, both the forces and the torques acting on the body must be balanced. This means that not only should the vector sum of the forces be zero, but also the algebraic sum of the torques should be zero. When both conditions are met, the object will remain at rest or continue to move with a constant rotational motion.

Balancing the forces acting on a body is not enough to establish equilibrium because equilibrium requires the balancing of both forces and torques. Simply balancing the forces ensures that there is no net force acting on the object, but it does not guarantee that the object will be in a state of complete equilibrium. To achieve equilibrium, the torques acting on the object must also be balanced, ensuring that there is no tendency for rotation.

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Explanation:

By keeping the galaxies safe and not launching stuff into space hurting planets and other universes out there in the entire galaxy

The force field F(p) = -(k/p^2)e represents an inverse square force law, where k is a constant and p is the radial distance from the origin. To find the angular frequency of polar vibrations around stable circular motion, we can consider the equation of motion for a particle in a circular orbit.

For circular motion, the centripetal force is given by Fc = mω^2p, where m is the mass of the particle, ω is the angular frequency, and p is the radial distance.Equating the centripetal force to the force field, we have:-
(k/p^2)e = mω^2p
Simplifying, we get:
k/p^3 = mω^2
Taking the square root and rearranging, we find:
ω = √(k/(mp^3))
This is the angular frequency of polar vibrations around stable circular motion.To show that this frequency is equal to the rotational angular frequency of circular motion, we can recall that in circular motion, the rotational angular frequency ω_rot = v/p, where v is the tangential velocity.Since the tangential velocity v = ω_rot * p, we can substitute this into the equation for ω:
ω = √(k/(m * p^3)) = √(k/(m * p^2)) * (1/p)
Using the relation v = ω_rot * p, we can rewrite the expression as:
ω = √(k/(m * p^2)) * (1/p) = √(k/(m * p^2)) * (1/(v/p))
Simplifying, we get:
ω = √(k/(m * p^2)) * (p/v) = v/√(m * k)
This shows that the angular frequency ω is equal to the rotational angular frequency ω_rot. Therefore, the angular frequency of polar vibrations around stable circular motion is equal to the rotational angular frequency of circular motion.

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Distanced travelled by a ship with a constant velocity in a day is 719712m

VELOCITY is defined as rate of change of displacement in a given interval of time.

it is a vector quantity.

its unit is m/s

to calculate the distance of a ship travelled

distance = speed x time

d = s x t   ----1.

velocity of ship = 8.33m/s

time taken = 1 day =86400 sec

now using the above values in equation 1 we get

d =8.33m/s x  86400 sec

d = 719712m

thus a ship travels 719712m in a day.

Distanced travelled by a ship with a constant velocity in a day is 719712m

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Answer:

My feet and my fists

Explanation:

My feet help me walk

and my fists help me one punch people

Answer:a farmer?

Explanation:

Because they raise their livestock or plants then eat them once they are big enough or fully grown?

Answer:

yes

Explanation:

1.98×10 m/s

you can use a physics text

I remember but am not sure

3.00 × 10 m/s

I think you do 10 ×10 in 8 places for both them you do the rest

The form of energy that the elements absorb in the gas lamp is heat energy.

This heat energy is used to excite the atoms of the gas inside the lamp, causing them to emit light. The heat energy is typically provided by a flame, which is produced by the combustion of a fuel such as propane or natural gas. The flame heats the gas inside the lamp, causing the atoms to become excited and emit light. This is the basic principle behind the operation of a gas lamp.

In summary, the form of energy absorbed by the elements in a gas lamp is heat energy, which is used to excite the atoms of the gas and produce light.

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Answer:

B or D

Explanation:

I wanna say B but I don't really know if it's a trick question

my explanation for D is that anvils are usually 110 decibles and ear drums usually are damaged when exposed to 82dbs or higher at a consistant rate so I'd imagine that'd be the answer I hoped this helped

Answer:

the answer is B

Explanation:

Any harmful noises can be bad. yes, an Anvil and Hammer can be bad but so can explosions and gun fire and having music to loud

The specific gravity of the solids in the soil sample is approximately 0.227.

To find the specific gravity of the solids in the soil sample, we need to compare the weight of the soil to the weight of an equal volume of water.

Given that the weight of the soil is 100 g, we can calculate the weight of the water that fills the flask up to the etch mark. The weight of the filled flask is 690 g, and the weight of the empty flask is 250 g. Therefore, the weight of the water is 690 g - 250 g = 440 g.

When the soil is added to the flask and some water is added to fill it up to the etch mark, the total weight becomes 754 g. This weight includes the weight of the soil and the weight of the added water. So, the weight of the water added is 754 g - 690 g = 64 g.

To find the specific gravity of the solids, we compare the weight of the soil (100 g) to the weight of an equal volume of water (440 g). The specific gravity is given by:

Specific gravity = (Weight of soil) / (Weight of water)

Specific gravity = 100 g / 440 g ≈ 0.227.

Therefore, The specific gravity of the solids in the soil sample is approximately 0.227.

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Answer:

d = 513 m

Explanation:

Given that,

An echo returned in 3s.

We need to find the distance of the reflecting surface from the source, given that the speed of sound is 342 m/s.

The sound will cover 2d distance. The formula for the speed is given by :

v = d/t

So,

\(v=\dfrac{2d}{t}\\\\d=\dfrac{vt}{2}\\\\d=\dfrac{342\times 3}{2}\\\\d=513\ m\)

So, the required distance is 513 m.

The equation F=ma, where F is the net force, m is the mass, and an is the acceleration, can be used. . Rearranging the formula to solve for mass, we get m=F/a. Substituting the given values, we get m=12 N/48 m/s^2 = 0.25 kg. Therefore, the answer is A) 0.25 kg.

To solve this problem, you can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force (F) is 12 N, and the acceleration (a) is 48 m/s². You are asked to determine the mass (m) of the hockey puck.

Using the equation F = ma, you can rearrange it to find the mass: m = F/a

Plug in the given values: m = 12 N / 48 m/s²

Calculate the mass: m = 0.25 kg

The mass of the hockey puck is 0.25 kg, which corresponds to option A.

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The x-ray tube life may be extended by reducing exposure time, controlling temperature, and ensuring proper maintenance. These measures help in prolonging the tube's performance and minimizing wear.

X-ray tubes are essential components of x-ray machines, and their lifespan plays a crucial role in the efficient functioning of the equipment. Reducing exposure time can significantly decrease the amount of heat generated within the x-ray tube, thus reducing the wear on its components. Using the lowest possible exposure time that still provides adequate image quality is one way to extend the tube's life.

Temperature control is also important in preserving the x-ray tube's lifespan. The tube generates heat during operation, and excessive heat can damage its components. Ensuring that the equipment has adequate cooling mechanisms and is used in a temperature-controlled environment will help minimize heat-related issues and prolong the tube's life.

Lastly, proper maintenance of the x-ray tube is essential in extending its life. This includes regular cleaning and inspection of the tube, as well as following the manufacturer's guidelines for usage and care. By adhering to proper maintenance procedures, potential problems can be detected early, and appropriate measures can be taken to prevent further damage to the tube.

In conclusion, extending the life of an x-ray tube can be achieved through reducing exposure time, controlling temperature, and ensuring proper maintenance. These steps will help maintain the performance and efficiency of the x-ray machine, ultimately benefiting both patients and healthcare providers.

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Answer:

I would say the beaker with less water.

Explanation:

I was say this because while they are the same temperature the beaker with more water still has to fluctuate the heat or cold. They do this at the same speed but since there is less water in one beaker it finishes faster where as the beaker with more water will finish later.

Answer:

It has to do with the polairity of said molelule. If you have vegetable oil, for example, it will not disolve in water because the oil is a non-polar compound, unlike water which is polar. The bond dipoles and differences in electronegetivity in the molecule results in this.

The noise level is I=1029 I=log2 times over the threshold of human hearing.

Logarithmic scales are used to measure decibels. This is a method of accounting for or measuring an exponentially growing quantity. For instance, every 10 dB increase in decibels corresponds to a 10-fold increase in sound pressure level (SPL).

The formula for sound speed is vw=f, where f is sound frequency and is sound wavelength. The distance between adjacent, identical wave components, such as between adjacent compressions, determines a sound's wavelength.

The hertz is the SI unit for frequency (Hz). One cycle per second equals one hertz.

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The magnitude of the acceleration due to gravity near the surface of Mars considering the time that takes the marker to fall to the ground is: 3.75 m/s²

It is when the object or mobile falls from a height (h) with a positive acceleration equal to the gravity, describing a vertical rectilinear travel.

The free fall formula and the procedure we will use is:

h = (g * t²)/2

Where:

Information of the problem:

Applying the height formula with the time of the fall on Earth we get:

h = (g * t²)/2

h= (9.8 m/s² * (1.3 s)²)/2

h=(9.8 m/s² * 1.69 s²)/2

h= 16.562 m/2

h=8.281 m

Applying the height formula, with the time of the fall on Mars and clearing the gravity we get:

h = (g * t²)/2

g= (h*2)/ t²)

g(Mars)= 8.281 m *2/(2.1 s) ²

g(Mars)= 16.562 m/4.41 s²

g(Mars)= 3.75 m/s²

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Answer:

Explanation:

Battery is removed so its charge stored  becomes fixed .

Energy of capacitor E₁ = Q² / 2C

When dielectric is inserted , the capacity of the capacitor is increased to KC .

Charge on it still remains the same ie Q

So its new energy

E₂ = Q² / 2 KC

E₂ / E₁ = 1 / K

E₂ = E₁ / K

Change in energy

= E₂ - E₁

= E₁ / K - E₁

= E₁ [ (1 / K)  - 1 ]

Factor by which energy is changed

= [ (1 / K)  - 1 ] .

Answer:

the index of refraction of the coating is 1.33  

Explanation:

Given the data in the question;

refraction index of  interior portion of the rod η\(_{interior\) = 1.55

angle of incidence θ\(_i\) = 59.5°

From Snell's law, we know that;

η\(_{interior\) × sinθ\(_i\)  = η\(_{coating\) × sinθ\(_r\)

where η\(_{interior\)  is the index of refraction of the rod ( material 1 )

θ\(_i\)  is the angle of incidence

η\(_{coating\) is the index of refraction in outer coating ( material 2 )

θ\(_r\) is the angle of refraction

so we substitute our values into the equation;

η\(_{interior\) × sinθ\(_i\)  = η\(_{coating\) × sinθ\(_r\)

1.55 × sin( 59.5° )  = η\(_{coating\) × sin( 90° )

1.55 × 0.861629  = η\(_{coating\) × 1

1.3355 = η\(_{coating\) × 1

η\(_{coating\) = 1.33   { 2 decimal places }

Therefore, the index of refraction of the coating is 1.33  

The gravitational acceleration on the asteroid is 0.195 m/s².

Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.

From the question above, we know that

h = 100 m

vo = 5 m/s

vt = 8 m/s

By substituting the given parameters, we get

vt² = vo² + 2a . s

vt² = vo² + 2g . h

8² = 5² + 2.g . 100

64 = 25 + 200g

g = 0.195 m/s²

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Answer:

8 N

Explanation:

work=force*distance

force=work/distance

=56/7

=8

The difference in power for two people carrying the boxes up the ramp is 30 W.

Given the following data:

W = 40.0 N is the weight of a box.

The ramp's length is L = 2.00 m.

The platform height is h = 1.0 m.

t = 2.0 s is the time interval for the first person.

t' = 4.0 s is the time interval for the other person.

Power is the rate at which energy is used. The expression for the Power is given in the given question as,

P = W×(L+h)/t

Assume that you are solving for the first person.

P₁ = W(L+h)/t₁.................................................................. (1)

Substitute the following values into equation (1):

P₁ = 40(2+1)/2

P₁ = 20(3) (3)

P₁ = 60 W.

Regarding the second person,

P₂ = W(L+h)/t₂..................................................................... (2)

Fill in the blanks in equation (2) as follows:

P₂ = 40(2+1)/4

P₂ = 10*(3) *3)

P₂ = 30 W

Obtaining the difference in power as

P = P₁ - P₂

P = 60-30

P = 30 W

As a result, we can conclude that the difference in power for two people carrying the boxes up the ramp is 30 W.

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Responder:

Explicación:

Fuerza = Masa × aceleración

Dado que aceleración = velocidad final - velocidad inicial / tiempo

Fuerza = m (v-u) / t

Dado

Masa = 1000 kg

v = 15 m / s

u = 0 m / s

t = 20 segundos

Sustituye los valores dados en la fórmula para calcular la fuerza.

F = 1000 (15-0) / 20

F = 1000 (15) / 20

F = 15000/20

F = 750N

Answer:

дангггггггггггггггггггггггггггггггггггггггггггггг

Answer: D.

Explanation: I took the test

Answer:

F = m*(g - a) →

a = g - F/m = 0.891 m/s² downward

Explanation:

If elevator was stationary, the normal force of elevator floor on man* would be = mg

mg = (38.5)(9.81) ≈ 378 N.

If elevator is accelerating downward the floor is accelerating away from man and so the normal force will be less than man's weight by: 378 - 343 = 35 N.

Hope this helps.

Answer:

-0.891

Explanation:

negative because downward

Answer:

Abiotic referfers to non-living and biotic factors are living or once living

Explanation:

480.0 Newtons force is required to lift a 49-newton object with an acceleration of 9.8 m/s2/. The explaination is mentioned below:

To calculate the amount of force required to lift a 49-newton object with an acceleration of 9.8 m/s2, we need to use the formula F = ma, where F is the force required, m is the mass of the object (in this case, 49 newtons), and a is the acceleration (in this case, 9.8 m/s2).
Plugging in the values, we get:
F = 49 x 9.8
F = 480.2 Newtons
Therefore, the amount of force required to lift a 49-newton object with an acceleration of 9.8 m/s2 is 480.2 Newtons.

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