An increase in amplitude that occurs when an object vibrating at its natural frequency absorbs energy from a nearby object vibrating at the same frequency.

The potential difference needed to give a helium nucleus is approximately 7.49 x 1\(0^{4}\) volts (V).

To give a helium nucleus, which consists of two protons and two neutrons, we need to overcome the electrostatic repulsion between the protons. This can be achieved by providing enough potential energy to bring the protons close enough together for the strong nuclear force to overcome the electrostatic repulsion.

The potential energy due to electrostatic repulsion between two charged particles is given by the equation:

PE = k * (q1 * q2) / r

Where:

PE is the potential energy

k is the electrostatic constant (approximately 8.99 x 1\(0^{9}\) \(N*m^2/C^2\))

q1 and q2 are the charges of the particles

r is the separation distance between the particles

In the case of a helium nucleus, both protons have a charge of +e (elementary charge, approximately 1.602 x 1\(0^{-19}\) C). Thus, we can rewrite the equation as:

PE = k * (e * e) / r

To determine the potential difference (V) needed to give a helium nucleus, we can equate the potential energy to the potential difference multiplied by the elementary charge:

PE = V * e

Setting these two expressions equal to each other and rearranging, we find:

V = (k * e * e) / r

Now, we need to determine the separation distance (r) between the protons in the helium nucleus. The nuclear radius of a helium nucleus is approximately 1.75 femtometers (1.75 x 1\(0^{-15}\) meters). Therefore, we can substitute this value into the equation:

\(V = (8.99 * 10^9 N*m^2/C^2 * (1.602 * 10^-19 C)^2) / (1.75 * 10^-15 m)\)

Calculating this expression will give us the potential difference needed to give a helium nucleus.

V = 7.49 x  \(10^4 N*m^2/C^2\)

Therefore, the potential difference needed to give a helium nucleus is approximately 7.49 x 1\(0^{4}\) volts (V).

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The potential difference needed to give a helium nucleus depends on the charge of the nucleus and the electric field strength in the region where it is located.

To calculate the potential difference needed to give a helium nucleus, we need to consider the charge of the nucleus and the electric field strength. The charge of a helium nucleus is twice the charge of a proton, which is approximately 3.2 x 10^-19 coulombs.

The potential difference, or voltage, is given by the equation:

V = E * d

Where:

Since we are given the charge of the helium nucleus, we need to determine the electric field strength in the region where the nucleus is located. Without this information, we cannot calculate the exact potential difference required.

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The lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

(a) μ = 0

The heavier block will accelerate to the right with an acceleration of:

a = F / m = k x / m = (3.70 N/m) (0.0864 m) / 0.261 kg = 1.22 m/s²

The lighter block will also accelerate to the right with an acceleration of 1.22 m/s².

(b) μ = 0.110

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m) (0.0864 m) / 0.261 kg - (0.110)(0.261 kg)(9.80 m/s²) = 0.68 m/s²

The lighter block will not accelerate because the force of friction is greater than the force of the spring.

(c) μ = 0.480

The heavier block will accelerate to the right with an acceleration of:

a = F - μk / m = k x / m - μk / m = (3.70 N/m)(0.0864 m) / 0.261 kg - (0.480)(0.261 kg) (9.80 m/s²) = -0.82 m/s²

Therefore, the lighter block will also accelerate to the right with an acceleration of -0.82 m/s².

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Answer:

10 kg rock at 15 degrees

Explanation:

did test

The range of possible speeds when a car speedometer reads 100 km/h with a 3% uncertainty is 97 km/h to 103 km/h.

When a car speedometer has a 3% uncertainty, it means that the displayed speed can deviate by 3% from the actual speed. In this case, if the speedometer reads 100 km/h, the actual speed could be either lower or higher. For calculating the range of possible speeds, need to find the 3% deviation from 100 km/h.

For determining the lower limit of the range, subtract 3% of 100 km/h from 100 km/h:

Lower limit = 100 km/h - (3/100) * 100 km/h = 100 km/h - 3 km/h = 97 km/h

For determining the upper limit of the range, add 3% of 100 km/h to 100 km/h:

Upper limit = 100 km/h + (3/100) * 100 km/h = 100 km/h + 3 km/h = 103 km/h

Therefore, the range of possible speeds when the speedometer reads 100 km/h with a 3% uncertainty is from 97 km/h to 103 km/h.

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Answer:

Explanation:

Given:

H = 75 m

Δt = 0.091 s

g =9.81 m/s²

_________

V₀ - ?

Assume that the stool fell freely, then the time of its fall:

H = g·t²/2

t = √ (2·H / g) = √ (2*75 / 9.81) ≈ 3.910 s

The refrigerator was thrown down with initial speed and fell:

t₁ = t - Δt = 3.910 - 0.091 ≈ 3.82 s

Find the initial chip of the refrigerator:

H = V₀·t₁ + g·t₁²/2

V₀·t₁ = H - g·t₁²/2

V₀ =H / t₁ - g·t₁ / 2

V₀ = 75 / 3.82 - 9.81·3.82 / 2 ≈ 0.90 m/s

So, at first, the stool is simply released from the hands, and the refrigerator is thrown down with the initial speed 0.90 m/s

Answer:

description

Explanation:

Motion can be defined as a change in the location (position) of a physical object or body with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

Mathematically, the motion of an object is described in terms of acceleration, time, distance, speed, velocity, displacement, position, etc.

A reference point refers to a location or physical object from which the motion (movement) of another physical object or body can be determined.

For example, a point on a map is considered to be a reference point because it represents the starting point of an object or person in motion.

If the reference point changes, the description of position changes, but the actual position does not change.

Answer:

description

Explanation:

Hope this helps

Answer:

Elephant and the eath because Fg is determined by Mass of an object.. So elephant has greater mass therefore, it's Fg is higher

According the universal  law of gravitation, the gravitational force is directly proportional to the mass of an object.  An elephant weighs so much than a man and thus it will experience larger gravitational force from earth.

Gravitational force is a resistive force by which an object attracts other objects towards its centre of mass. The force exerted by the object depends on the mass and the force experienced by the other object depends on its mass and distance between the two objects.

According to universal law of gravitation, the gravitational force is directly proportional to the mass of the object and distance from the ground. The expression for the law is written as:

\(\rm g = G \frac{M_{1} M_{2}}{r^{2}}\)

Where, G is the universal gravitational constant and M1 and M2 be the masses of two objects which and r be the distance between them. As per this relation gravity decreases with increase in distance and increase with an increase in mass.

Therefore, a massive body such as an elephant will experience greater gravitational force from the earth.

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Answer:

Force can change the speed and direction of an object.

Explanation:

Answer:

A cube of wood is 3 cm on each side. It has a mass of 27 g. What is its density?The volume of a cube is given by s^3. So the volume of this block is 3cm x 3cm x3 cm = 27 cm^3. density = mass/volume =27 g / 27 cm^3 = 1 g/cm^3. the answer is 1 g/cm^3.

What is the mass of a billiard ball that has a volume of 100 cm³ and a density of 2.5 g/cm³?what is the density of a billiard ball that has a volume of 100cm cubed and a mass of 250g? Density = 250g / 100cm^3 = 2.5 g/cm^3.

BRAINLIST PLEASE!!

A crystal or is a solid material whose constituents are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions

hope this helps

An object dropped from rest, its velocity be 294 m/s in downward direction after 30 s .

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them.

initial velocity = u =  0

time = t = 30sec

g = acceleration due to gravity = 9.8 \(m/s^{2}\)

using equation of kinematics

v = u - g*t

v = 0 - 9.8 * 30

v = - 294 m/s

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Answer:

Imp = 25 [kg*m/s]

v₂= 20 [m/s]

Explanation:

In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.

1)

\((m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})\)

where:

m₁ = mass of the object = 5 [kg]

v₁ = initial velocity = 0 (initially at rest)

F = force = 5 [N]

t = time = 5 [s]

v₂ = velocity after the momentum [m/s]

\((5*0) +(5*5) = (m_{1}*v_{2}) = Imp\\Imp = 25 [kg*m/s]\)

2)

\((m_{1}*v_{1})+(F*t)=(m_{1}*v_{2})\\(0.075*0)+(30*0.05)=(0.075*v_{2})\\v_{2}=20 [m/s]\)

Force = F = 5N

time = t = 5 seconds

mass = m = 5 kg

momentum = p = ?

The force which acts for a very short period of time is called impulse force. It is given by,

                                      I = F x t

Where,

              I is impulse

              F is force

              t is time till which force is exerted

The impulse experienced by the object equals the change in momentum of the object. In equation form,

                                    F x t = M x ΔV

 So,

                     F x t = Final momentum - initial momentum

                     F x t = final momentum - (0)

initial momentum is zero because the object was initially at rest.

                     Final momentum = 5 x 5

                     Final momentum = 25 \(kgms^{-1}\)

So B is the answer

Force = F = 30 N

time = t = 0.05 seconds

mass = m = 0.075 kg

V = ?

impulse force is given by,

                                      I = F x t

Where,

              I is impulse

              F is force

              t is time till which force is exerted

The impulse experienced by the object equals the change in momentum of the object. So,

                                    F x t = M x ΔV

 So,

                     F x t = Final momentum - initial momentum

                     F x t = final momentum - (0)

Since it was at rest initially, initial momentum is zero.

Momentum is given by,

                                p = m x V

where,

           p is momentum

           m is mass

           v is velocity

                 F x t = m x V

Rearrange the equation,

                                        V = \(\frac{Fxt}{m}\)

                                        \(V = \frac{(30)x(0.05)}{0.075} \\\\V = 20 m/s\)

So C is the answer

Answer:

See below

Explanation:

The red flowering plant must be heterozygous with a dominant R gene and a recessive w gene......the white will have w  w   (homozygous)

        R                 w

w      wR (red)     ww(white)

w     wR (red)       ww(white )              50% red     50% white

F=150N.

A high wind velocity is defined as quickness of motion or operation; swiftness; or speed.

The speed at which a body's position changes over time in a given direction is known as mechanics. the velocity of activity or reaction; the rate at which something occurs.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is traveling along a path. The displacement that an object or particle experiences with respect to time are expressed vectorially as velocity

(1400-1250)

150 N

F=150N

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Answer:

1.05kg

Explanation:

Soln

Kinetic energy = 475 J

Velocity = 30.0m/s

mass = ?

Recall,

Kinetic energy = 1/2 × mass × (velocity)²

K.E = 1/2 × m × v²

475 = 1/2 × m × (30)²

475 = 1/2 × m × 900

475 = m × 450

divide both sides by 450

475/450 = m

m = 475/450

m = 1.05kg

Answer:

Show the wave

Explanation:

Answer:

The number of complete wavelengths in a given unit of time is called frequency (f). As a wavelength increases in size, it's frequency and energy (E) decrease. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength get longer.

Explanation:

I majored in Physics

The only true statement about the toy car is " the toy does not approach the spring".

option A is the correct answer.

The acceleration of the car is calculated by applying Newton's second law of motion, which states that the force applied to an object is directly proportional to the product of mass and acceleration of the object.

F - Ff = 0

F = Ff

ma = μmg

a = μg

where;

a = 0.14 x 9.8 m/s².

a = 1.37 m/s²

The distance traveled by the car before stopping is calculated as follows;

v² = u² - 2as

where;

when the car stop's the final velocity, v = 0

0 = u² - 2as

2as = u²

s = u²/2a

s = ( 2² ) / ( 2 x 1.37 )

s = 1.5 m

Thus, the final distance travelled by the car is less than 3 m, hence the car did not come in contact with spring.

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The work done in lifting a 1 kg object from the center of the earth to its surface is 5.928 x 10^6 J.

To find the amount of work done on the 1 kg object to lift it from the center of the earth to its surface, we need to use the formula for work, which is given by W = Fd, where W is work, F is force, and d is distance.We are given that the gravity force on a 1 kg object at a distance r from the center of the Earth is given by F(r) = 0.0015r.

We know that the distance from the center of the earth to its surface is 6,371,000 meters. Therefore, to find the work done in lifting the 1 kg object from the center of the earth to its surface, we need to integrate the force function from r = 0 to r = 6,371,000 m:W = ∫(0 to 6,371,000) F(r) dr

W = ∫(0 to 6,371,000) 0.0015r dr

W = 0.00075[r^2] (0 to 6,371,000)

W = 0.00075(6,371,000^2)

W = 5.928 x 10^6 J

Therefore, the work done in lifting a 1 kg object from the center of the earth to its surface is 5.928 x 10^6 J.

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Answer:

1 deg C = 5/9 deg F         (Ex. 212 F - 32) * 5/9 = 100

So deg F = 9/5 deg C = 9/5 * 2.9 = 5.2 deg F

Answer: A Neutron.

I know this is correct. Thank's and yw :3

Answer:

I think it's 12.5s

Explanation:

Bare with me, because I just started physics, but I think I have the answer right... Hopefully.

starting with your knowns, we know velocity is 25 m/s from the problem. you also can figure out your acceleration, -2 m/s.

You're looking for the time it takes until the ball stops rolling. Your time is unknown.

Your equation would be a=v/t (acceleration being a, velocity being v, and time being t)

You have to solve for t giving you t=v/a

Now you have to fill in your numbers. t=25m/s divided by -2m/s^2

Your answer should end up as -12.5

You have to solve for your units, but since you're finding time it's pretty straightforward in knowing you're dealing with seconds.

Hope this helped... :) sorry if it didn't-

When an object is released with an initial velocity upward, the direction of its acceleration is typically downward.

This is because the force of gravity, which acts on the object, pulls it in the opposite direction to its motion. According to Newton's second law of motion, the net force on an object is equal to its mass multiplied by its acceleration. In this case, the force of gravity acts as the net force, causing the object to accelerate downward.

The acceleration due to gravity is approximately 9.8 meters per second squared on Earth, and it acts downward towards the center of the planet. Therefore, when the object is released with an initial velocity upward, the gravitational force causes it to decelerate and eventually change direction, resulting in a downward acceleration. This downward acceleration opposes the initial upward velocity of the object until it eventually reaches its peak and starts to fall back down under the influence of gravity.

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Answer:2AgI + Na2S → Ag2S + 2NaI I am pretty sure this is the answer

Explanation:

The model of the light wave shows many light waves traveling in all directions from a source.

option C is the correct answer.

Wave motion is the transfer of energy and momentum from one point of the medium to another point of the medium without actual transport of matter between two points.

The following explanation illustrates how light waves can travel. Light propagates as electromagnetic waves. Light can travel in all all directions as light waves are spherical waves which travel radially outwards from its source.

From the given image we can conclude the following;

Thus, it is safe to say that the model of light being represented shows many light waves travelling from a single to many direction due to presence of many circular wave path shown in the picture.

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The distance which the football which cover before landing back on the ground level will be about 56.4 meters.

The mass of football, m = 0.43 kg, Initial velocity of football (v) = 24 m/s, Angle of inclination(θ) = 53°

From the given data, we know that the vertical component of the initial velocity is given by, vsin(θ) and the horizontal component of initial velocity is given by, vcos(θ). So, the time taken by the football to reach the maximum height is given by,

t = (vsin(θ))/g

Here, g = 9.8 m/s²

Now, the maximum height attained by the football is given by,h = (vsin(θ))²/(2g).

Therefore, the time of flight or the total time which is taken by the football to land on the ground level is given by,

T = 2t

Now, the horizontal distance travelled by the ball is given by, d = (vcos(θ))T

Substituting the given values in the above formulas, we get:

t = (24sin(53°))/9.8 = 1.71 s

h = (24sin(53°))²/(2×9.8) = 23.4m

T = 2×1.71 = 3.42 s

d = (24×cos(53°))×3.42 = 56.4 m

Therefore, the football will go 56.4 m before it is landing back on the level ground.

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The magnitude of the sum of two vectors A and B is 4.13 m and the angle of the resultant vector is 10.86°.

From the given,

A = 3.14 m

B = 2.71 m

The resultant vector C= A + B

Vector A is resolved into its vertical and horizontal components,

Aₓ = 3.14 cos(30) = 2.71 m

Ay = 3.14 sin (30) = 1.57 m

Vector B is resolved into its vertical and horizontal components,

Bx = 2.71 cos(60) = 1.355 m

By = ₋2.71 sin (60) = -2.35 m

C = A + B

  = (2.71+1.355) x + (1.57 -2.35) y

 = 4.064 i - 0.78 j

the magnitude of C = √(4.06)² + ( 0.78)² = 4.13 m

The angle, tan α = 0.78 / 4.06

 α = 10.8°

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The magnitude of the vector B is 10.9

A vector is a quantity which has magnitude as well as direction and it follows vector laws of addition.

To calculate the magnitude of the vector, we have to put the square of the components of the vector along the axes under the root.

Vector B has components,

x = 2.4

y = 9.8

z = 4.1

Applying the formula,

|B| = √x²+y²+z²

|B| = √(2.4)² + (9.8)² + (4.1)²

|B| = √5.76+96.04+16.81

|B| = √118.61

|B| = 10.9

Talking about the direction the the Vector B, it will be the line joining the origin with the points (2.4,9.8,4.1)

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Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

f is the force

m is the mass

From the question we have

\(a = \frac{35000}{1500} = \frac{350}{15} = \frac{70}{3} \\ = 23.33333...\)

We have the final answer as

Hope this helps you

The interval of time it takes for the team to do a work of 2.35×10⁷ J is 15000 seconds.

Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.

To calculate the time interval the work was done by the team on the wagon, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the interval of time it takes to the the work is 15000 seconds.

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