A.The energy of the incoming photon is: \(E_photon = (0.01m)c^2\)
B. the energy of the photon (0.01m times c^2) is much greater than just 0.01m.
(a) To find the energy of the incoming photon, we'll use the mass-energy equivalence formula, which is E = mc^2. Since the mass of the particle increased by 1.01m after absorbing the photon, the increase in mass is 0.01m. Therefore, the energy of the incoming photon is:
\(E_photon = (0.01m)c^2\)
(b) The energy of the incoming photon is greater than 0.01m because energy has units of mass times the speed of light squared (mc^2). The factor c^2 is a very large number, so the energy of the photon (0.01m times c^2) is much greater than just 0.01m.
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A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute. How much power is needed for the elevator’s trip?
A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute is 12500 W (12.5 kW).
What is Power?
Power is the amount of work that is done per unit of time. It can be associated with the speed of a change of energy within a system, or the time it takes to perform a job.
There are different types of power,
Mechanical power: is that work performed by an individual or a machine in a certain period of time.
Electric power: which is the result of the multiplication of the potential difference between the ends of a load and the current flowing there.
P= W/t
Where, P- Power,
W- Work
T- Time
The total weight of the passenger + elevator is
Fg = 500+24500
= 25000
The total work done to rise the elevator + passenger is equal to the product between the total weight and the distance covered during the trip (d = 30 m):
W = Fgd
= 25000×30
=7,50,000 J.
The power needed for the trip is equal to the ratio between the work done (W) and the time taken (t):
P = W/t
Since the time taken is t = 1 min = 60 s, the power needed is
P = 750000 / 60
= 12,500 W
P = 12.5 kW
Thus, Power was calculated as P = 12.5 kW.
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Heat energy always moves from a _ _ _ place to a _ _ _ _ _ _ place. The three methods of heat transfer are?
Plz help i need ASAP
Answer:Heat can travel from one place to another in three ways: Conduction, Convection and Radiation.
Explanation:
Help...
If a machine allows us to apply less force to do work what is the cost?
If a machine allows us to apply less force to do work, the cost is that we must apply the force over a greater distance.
What is machine?The above is so because, according to the principle of work and energy, the amount of work done remains constant, but the force and distance can be traded off. In other words, if we decrease the force required to do a certain amount of work, we must increase the distance over which the force is applied in order to compensate.
Therefore, For example, consider a simple lever. By using a lever, we can apply less force to lift a heavy object, but we must move the lever over a greater distance in order to do so. The work done, which is the product of the force and the distance, remains constant. In this case, the force is reduced, but the distance over which it is applied is increased.
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What is the acceleration of a 56 kg object pushed with a force of 800 newtons?
Answer:
The acceleration of an object can be calculated using Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. The equation is:
F = ma
where F is the force, m is the mass, and a is the acceleration.
So, if we know the mass of the object (m = 56 kg) and the force acting on it (F = 800 N), we can calculate the acceleration (a) by dividing the force by the mass:
a = F / m
a = 800 N / 56 kg
a = 14.28 m/s^2
So the acceleration is 14.28 m/s^2
A satellite with a mass of 15,000 kg orbits the Earth. The satellite and Earth are 5x10³ m apart from their centers. What is the acceleration of the satellite? (mearth = 5.972 x10²4 kg)
The acceleration of the satellite would be 8,926.67 m/s².
Acceleration of a satelliteThe acceleration of the satellite can be calculated using the following equation:
a = GM/r²
where:
G = gravitational constant = 6.6743 x 10^-11 Nm²/kg²
M = mass of the Earth = 5.972 x 10^24 kg
r = distance between the centers of the Earth and the satellite = 5 x 10^3 m
First, we need to calculate the gravitational force between the Earth and the satellite:
F = G(Mm)/r²
where m is the mass of the satellite.
F = (6.6743 x 10^-11 Nm²/kg²)(5.972 x 10^24 kg)(15,000 kg)/(5 x 10^3 m)²
F = 1.339 x 10^8 N
Now we can calculate the acceleration of the satellite:
a = F/m
a = (1.339 x 10^8 N)/(15,000 kg)
a = 8,926.67 m/s²
Therefore, the acceleration of the satellite is 8,926.67 m/s².
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If it has enough kinetic energy, a molecule at the surface of the Earth can escape the Earth’s gravitation.The acceleration of gravity is 9.8 m/s 2 , and the Boltzmanns’ constant is 1.38066 × 10−23 J/K. Using energy conservation, determine the minimum kinetic energy needed to escape in terms of the mass of the molecule m, the free-fall acceleration at the surface g, and the radius of the Earth R. Calculate the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule.
The temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is 291.15 K.
At the surface of the Earth, the potential energy of a molecule of mass m is given by,
U = -GmM/R
where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth.
To escape the Earth's gravitational pull, the molecule needs to have enough kinetic energy such that its total energy, given by the sum of its kinetic and potential energies, is zero or positive
K + U ≥ 0
where K is the kinetic energy of the molecule.
Substituting the expression for U and solving for K,
K ≥ GmM/R
The temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule can be determined by equating the minimum escape energy to 15 times the average kinetic energy per molecule,
(3/2) kT = 15 (1/2) mv^2
where k is Boltzmann's constant, T is the temperature, m is the mass of an oxygen molecule, and v is the root-mean-square speed of oxygen molecules at that temperature.
Substituting the expression for v and solving for T,
T = (15mvg^2)/(3k)
T = (5mvg^2)/(k)
Therefore, the minimum escape energy in terms of m, g, and R is,
K = GmM/R
And the temperature for which the minimum escape energy is 15 times the average kinetic energy of an oxygen molecule is,
T = (5mvg^2)/(k)
Substituting the values of G, M, R, k, m, and g,
K = (2.0 × 10^-20) m Joules
T = (5 × 32 × 1.66 × 10^-27 × (9.8)^2)/(1.38066 × 10^-23) K
T = 291.15 K
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Distance time graphs
Answer:
A distance-time graph shows how far an object has travelled in a given time. It is a simple line graph that denotes distance versus time findings on the graph. Distance is plotted on the Y-axis. Time is plotted on the X-axis
Explanation:
Cane Company manufactures two products called Alpha and Beta that sell for $240 and $162, respectively. Each product uses only one type of raw material that costs $5 per pound. The company has the capacity to annually produce 131,000 units of each product. Its average cost per unit for each product at this level of activity are given below:
Alpha Beta
Direct materials $ 35 $ 15
Direct labor 48 23
Variable manufacturing overhead 27 25
Traceable fixed manufacturing overhead 35 38
Variable selling expenses 32 28
Common fixed expenses 35 30
Total cost per unit $ 212 $ 159
The company considers its traceable fixed manufacturing overhead to be avoidable, whereas its common fixed expenses are unavoidable and have been allocated to products based on sales dollars.
8. Assume that Cane normally produces and sells 80,000 Betas and 100,000 Alphas per year. If Cane discontinues the Beta product line, its sales representatives could increase sales of Alpha by 13,000 units. What is the financial advantage (disadvantage) of discontinuing the Beta product line?
9. Assume that Cane expects to produce and sell 100,000 Alphas during the current year. A supplier has offered to manufacture and deliver 100,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 100,000 units from the supplier instead of making those units?
10. Assume that Cane expects to produce and sell 75,000 Alphas during the current year. A supplier has offered to manufacture and deliver 75,000 Alphas to Cane for a price of $160 per unit. What is the financial advantage (disadvantage) of buying 75,000 units from the supplier instead of making those units?
The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000. The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.
To calculate the financial advantage or disadvantage of discontinuing the Beta product line, we need to compare the costs and revenues associated with the current situation and the proposed scenario.
Currently, the company produces and sells 80,000 Betas and 100,000 Alphas. If the Beta product line is discontinued, the sales representatives can increase Alpha sales by 13,000 units.
In the current situation:
Revenue from Beta sales = 80,000 units × $162 = $12,960,000
Revenue from Alpha sales = 100,000 units × $240 = $24,000,000
Total revenue = $12,960,000 + $24,000,000 = $36,960,000
In the proposed scenario:
Increased Alpha sales = 113,000 units × $240 = $27,120,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Revenue in proposed scenario - Revenue in current situation
Financial Advantage = $27,120,000 - $36,960,000 = -$9,840,000
The financial advantage of discontinuing the Beta product line would be a disadvantage of $9,840,000.
To determine the financial advantage or disadvantage of buying 100,000 units from the supplier instead of making them, we need to compare the costs of production with the purchase cost from the supplier.
Cost of producing 100,000 Alphas:
Direct materials cost = 100,000 units × $35 = $3,500,000
Direct labor cost = 100,000 units × $48 = $4,800,000
Variable manufacturing overhead = 100,000 units × $27 = $2,700,000
Traceable fixed manufacturing overhead = 100,000 units × $35 = $3,500,000
Variable selling expenses = 100,000 units × $32 = $3,200,000
Common fixed expenses = 100,000 units × $30 = $3,000,000
Total cost of producing 100,000 units = $3,500,000 + $4,800,000 + $2,700,000 + $3,500,000 + $3,200,000 + $3,000,000 = $20,700,000
Cost of buying 100,000 units from the supplier = 100,000 units × $160 = $16,000,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Cost of producing - Cost of buying
Financial Advantage = $20,700,000 - $16,000,000 = $4,700,000
The financial advantage of buying 100,000 units from the supplier instead of making them would be an advantage of $4,700,000.
Similarly, to determine the financial advantage or disadvantage of buying 75,000 units from the supplier instead of making them, we follow the same calculations as in question 9, but with the quantities adjusted accordingly.
Cost of producing 75,000 Alphas:
Direct materials cost = 75,000 units × $35 = $2,625,000
Direct labor cost = 75,000 units × $48 = $3,600,000
Variable manufacturing overhead = 75,000 units × $27 = $2,025,000
Traceable fixed manufacturing overhead = 75,000 units × $35 = $2,625,000
Variable selling expenses = 75,000 units × $32 = $2,400,000
Common fixed expenses = 75,000 units × $30 = $2,250,000
Total cost of producing 75,000 units = $2,625,000 + $3,600,000 + $2,025,000 + $2,625,000 + $2,400,000 + $2,250,000 = $15,525,000
Cost of buying 75,000 units from the supplier = 75,000 units × $160 = $12,000,000
Therefore, the financial advantage or disadvantage can be calculated as:
Financial Advantage = Cost of producing - Cost of buying
Financial Advantage = $15,525,000 - $12,000,000 = $3,525,000
The financial advantage of buying 75,000 units from the supplier instead of making them would be an advantage of $3,525,000.
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The walls of a dam are much thicker at the base than at the top
Answer:
I guess it is the reason
Explanation:
A dam is thicker at the bottom than at the top because the forces exerted are strongest close to the ground. Water pressure increases proportionally with depth, so the lower portion of the dam has greater water pressure exerted upon it. The increasing thickness of the lower dam also helps it support its own weight.
This is because of Pressure.
Pressure is directly proportional to depth and the deeper the length the high the pressure. Thus at the bottom, water pressure is very high and the walls must be made thicker to accommodate that pressure.
what is the formula for calculating velocity
Answer:
Velocity = Displacement by time
Explanation:
Answer:
The formula to calculate velocity =distance(s) ÷ time taken(t)
find the pressure increase in the fluid in a syringe when a nurse applies a force of 41 n to the syringe's circular piston, which has a radius of 1.2 cm.
The pressure increase is:pressure increase = pressure - atmospheric pressure, pressure increase = 191,863.51 - 101,325pressure increase = 90,538.51 Pa = 284,722.22 Pa (rounded to two decimal places)
Explanation:Pressure is defined as force per unit area.
Therefore, we use the formula:pressure = force/areaPiston area = πr²Where r is the radius of the piston, given as 1.2 cm = 0.012 m.Area of the piston:Area = πr²Area = π(0.012m)²Area = 4.5239 × 10⁻⁴ m²The force applied to the piston is 41 N.pressure = force/areapressure = 41/4.5239 × 10⁻⁴pressure = 90,538.51 PaHowever, this is the gauge pressure, that is, the pressure relative to atmospheric pressure.
To find the absolute pressure, we need to add the atmospheric pressure which is approximately 101,325 Pa.pressure = gauge pressure + atmospheric pressurepressure = 90,538.51 + 101,325pressure = 191,863.51 PaBut this is still not the final answer since the question asks for the pressure increase in the fluid.
Hence, the pressure increase is:pressure increase = pressure - atmospheric pressurepressure increase = 191,863.51 - 101,325pressure increase = 90,538.51 Pa = 284,722.22 Pa (rounded to two decimal places)
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Use the information from the graph to answer the
question.
Velocity (m/s)
45
40
35
30
25
20
15
Velocity vs. Time
0 2
4
6 8
Time (s)
10
12
What is the acceleration of the object?
m/s²
The velocity after 8 seconds 15 m/s. the acceleration of the object m/s² 2.
What is velocity ?
Velocity is a vector quantity that expresses both the speed and direction of an object's motion. It can be described in terms of both magnitude and direction, and is measured in terms of meters per second (m/s). Velocity is an important concept in physics because it is used to describe the motion of objects. In addition, it is used to calculate the force of an object, the acceleration of an object, and the momentum of an object.
Velocity is an important concept in physics and engineering, as it is used to measure the rate at which objects move, as well as the rate of change of an object's motion. Velocity can also be used to calculate the work done on an object and to determine the direction of an object's motion.
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Quick please I'll give you brainliest.
Answer:
its c
Explanation:
Talk to your parents why we do not see many sparrows in and around our house
The reason you are not seeing many sparrows in and around your house could be due to a variety of reasons, namely: disease, loss of habitat and predators.
The following are a few possibilities:
Loss of habitat: Sparrows may not be visiting your house since their habitat may have been altered or destroyed by humans, as is typical in urban areas. Insecticides and pesticides may have been used in your area to eliminate insects. Unfortunately, this will have a negative effect on sparrows since they rely heavily on insects for food.Predators: There may be predators, such as cats, birds of prey, or snakes, in your area that are hunting and killing sparrows. Climate change could be causing sparrows to move to new areas that are more suited to their requirements. Environmental changes like this can be caused by humans and natural events, such as changes in weather patterns.Disease: The sparrow population may have been affected by a disease or illness that has decreased their population. In such situations, they may relocate to other areas to avoid the outbreak.Thus, if you're not seeing many sparrows in and around your house, there may be a variety of reasons for this, and talking to your parents about this would be a good way to learn more.Learn more about sparrows at:
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A train is traveling N at 45 m/s. After 10s, it is traveling at 90 m/s. What is it's acceleration?
Answer:
The train's acceleration is 4.5 m/s²
Explanation:
The train's speed increased by 45 m/s after 10 seconds, which means that it's speed increased by 4.5 m/s each second, or rather 4.5m/s²
A piece of wood has a mass of 8g and a volume of 10cm³. Work out the density of the wood in /3 .
no links please just explain how you got the answer.
Answer:
8×10^-3÷10×10^-6=8×10^2=800 kg/m^3
Answer:
2.4/3
Explanation:
first we make 8g/10cm then 0.8 so the only number that can fit for /3 is 2.4
hope helped!
Find the current produced when a voltage of 60 V is applied to a resistance of 15 Ω? What is the equation?
Answer:
V = IR
Explanation:
V = voltage
I = current
R = resistance
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Select ALL that are results of the application of Bernoulli‘s principle .
A. A paper airplane flying across the room.
B. A dump truck, raising its bed to dump a load of dirt.
C. A jetliner carrying passengers overseas.
D. A child flying a kite on a spring day.
E. A remote controlled airplane taking off and flying.
Answer:
B.C AND maybe E
Explanation:
Who would benefit from using a topographic map? Check all that apply
Military
Hikers
Geologists
Submarine divers
Cross Country runners
Airplane Pilots
how is the size of a land animal related to the speed it can attain?
The size of a land animal is related to the speed it can attain on the function of its body weight.
However, the speed of an animal is determined by its size in relation to it's body weight.
So therefore, it may seem intuitive that animals with longer limbs or fins will travel far and fast
What are vertebrates?Vertebrates can simply be defined as those animals with backbones.
The classes of vertebrates are:
PiscesAmphibiansReptileAvesMammalsSo therefore, the size of a land animal is related to the speed it can attain on the function of its weight.
However, regardless of all other factors, the speed of animal is determined by how far an animal moves in a given amount of time.
So therefore, it may seem intuitive that animals with longer limbs or fins will travel far and fast
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A transformer usefully transfers 190,000 W of the 200,000 W of energy supplied to it. How efficient is the transformer?
Calculate the force (in N) needed to bring a 1050 kg car to rest from a speed of 80.0 km/h in a distance of 120 m (a fairly typical distance for a non-panic stop). N (b) Suppose instead the car hits a concrete abutment at full speed and is brought to a stop in 2.00 m. Calculate the force exerted on the car and compare it with the force found in part (a). force in (b) force in (a)
The force exerted on the car when it hits a concrete abutment at full speed and is brought to a stop in 2.00 m is much greater than the force required to bring the car to rest from a speed of 80.0 km/h in a distance of 120 m. because the distance over which the force acts is much less in the second case, which makes the force greater.
The calculation of the force (in N) needed to bring a 1050 kg car to rest from a speed of 80.0 km/h in a distance of 120 m can be done as follows: First, we need to find the initial velocity of the car in m/s. v = 80 km/h = 22.22 m/s Next, we need to find the final velocity of the car. It is 0 as the car comes to a complete stop. Therefore, vf = 0. We have been given the distance covered by the car, which is 120 m. Now, we can use the formula to find the force required to bring the car to rest: f = (m × (vf - vi)) / d Where m is the mass of the car, vf is the final velocity, vi is the initial velocity and d is the distance covered. Putting the given values in the formula, we get: f = (1050 × (0 - 22.22)) / 120= -192.5 N Therefore, the force required to bring the car to rest is 192.5 N. Suppose instead the car hits a concrete abutment at full speed and is brought to a stop in 2.00 m. We can calculate the force exerted on the car as follows: f = (m × (vf - vi)) / d Where m is the mass of the car, vf is the final velocity, vi is the initial velocity and d is the distance covered. Putting the given values in the formula, we get:f = (1050 × (0 - 22.22)) / 2= -115,500 N Therefore, the force exerted on the car is 115,500 N.
To conclude, the force exerted on the car when it hits a concrete abutment at full speed and is brought to a stop in 2.00 m is much greater than the force required to bring the car to rest from a speed of 80.0 km/h in a distance of 120 m. This is because the distance over which the force acts is much less in the second case, which makes the force greater.
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how does Newton's third law describe the force affecting a rocket as it descends to
Answer:
Explanation:
Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.
For a particular transformer, the voltage E in the circuits is related to the number of windings W of wire around the core by the equation E = 40W. How many windings will produce a voltage of 760 V?
ANSWER
\(19\text{ windings}\)EXPLANATION
The voltage, E, is related to the number of windings, W, by the equation:
\(E=40W\)To find the number of windings that will produce 760 V, we have to solve for W when E is 760 V. That is:
\(\begin{gathered} 760=40W \\ \Rightarrow W=\frac{760}{40} \\ W=19\text{ windings} \end{gathered}\)That is the answer.
how do you know the pole on the left is the south pole and the pole on the right is the north pole?
Answer:
Left is deciamled to the right \(x_{123}\)
Explanation:
A bullet of mass 0.05kg has a speed 400.what is it's kinetic energy.
if the bullet hits a wall of which the average resistive force is 10000 newton.calculate the distance penetrated by the bullet.
Answer:
K.E =1÷2M×V^2
= 1÷2×0.05×(400)^2
= 4000
Explanation:
2. A sled with no initial velocity accelerates at a rate of 1.1 m/s down a hill. How
long does it take the sled to go 13 m to the bottom?
Answer:
Time, t = 4.862 seconds
Explanation:
Given the following data;
Initial velocity = 0
Acceleration = 1.1m/s²
Distance = 13m
To find the time, we would use the second equation of motion;
S = ut + ½at²
Substituting into the equation, we have;
13 = 0*t + ½*1.1*t²
13 = 0.55t²
t² = 13/0.55
t² = 23.64
Taking the square root of both sides, we have;
Time, t = 4.862 seconds
Two stars orbiting each other are separated by 6.67 AU and revolve around their common center of gravity in 10 years. Use Newton’s form of Kepler’s third law to calculate the combined mass of the 2 stars in solar masses.
Answer:
The combined mass of the two stars is 2.9417 solar masses.
Explanation:
The mathematical expression for Kepler's third law is;
\(P^{2}\) = \(\frac{4\pi ^{2} }{k^{2} (M_{1} + M_{2} }a^{3}\)
Where: P is the period in days, a is the semimajor axis in AU, \(M_{1}\) is the mass of the first star, \(M_{2}\) is the mass of the second star and k is the Gaussian gravitational constant.
Given that;
P = 10 years = 3670 days (including two leap years)
a = 6.67 AU
k = 0.01720209895 rad
\(\pi\) = \(\frac{22}{7}\)
The sum of the masses of the two star can be determined by;
\((M_{1} + M_{2})\) = \(\frac{4\pi ^{2} }{P^{2}k^{2} } a^{3}\)
= \(\frac{4*(\frac{22}{7}) ^{2} } {(3650)^{2} * (0.01720209895)^{2} } (6.67)^{3}\)
= \(\frac{11724.29601}{3942.2904}\)
= 2.9417 solar masses
Thus the combined mass of the two star is 2.9417 solar masses.
If a planet's average distance from the sun is 10 AU, what is its orbital period?
The period will be 11.18 years
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|| ▼ Answer ▼ ||
The orbital period is 31.62 years when the average distance from the sun is 10AU
|| ✪ Explanation✪ ||
Given:
The average distance of the planet from the sun is r = 10 AU
To find the orbital period.
According to Kepler's third law,
\(T^{2}\) ∞ \(r^{3}\)
\(T^{2} =kr^{3}\)
\(T=\frac{3}{2}\)
Here, the constant k is taken to be 1.
Substituting the values, the orbital speed will be
\(T=(10)\frac{3}{2}\)
\(=31.62~years\)
Final Answer: The orbital period is 31.62 years when the average distance from the sun is 10AU
Hope this helps!
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yes that.
Read the excerpt below and then answer the question that follows:
The Book of Dragons
Chapter III The Deliverers of Their Country, an excerpt
By E. Nesbit
It all began with Effie's getting something in her eye. It hurt very much indeed, and it felt something like a red-hot spark—only it seemed to have legs as well, and wings like a fly. Effie rubbed and cried—not real crying, but the kind your eye does all by itself without your being miserable inside your mind—and then she went to her father to have the thing in her eye taken out. Effie's father was a doctor, so of course he knew how to take things out of eyes.
When he had gotten the thing out, he said: "This is very curious." Effie had often got things in her eye before, and her father had always seemed to think it was natural—rather tiresome and naughty perhaps, but still natural. He had never before thought it curious.
Effie stood holding her handkerchief to her eye, and said: "I don't believe it's out." People always say this when they have had something in their eyes.
"Oh, yes—it's out," said the doctor. "Here it is, on the brush. This is very interesting."
Effie had never heard her father say that about anything that she had any share in. She said: "What?"
The doctor carried the brush very carefully across the room, and held the point of it under his microscope—then he twisted the brass screws of the microscope, and looked through the top with one eye.
"Dear me," he said. "Dear, dear me! Four well-developed limbs; a long caudal appendage; five toes, unequal in lengths, almost like one of the Lacertidae, yet there are traces of wings." The creature under his eye wriggled a little in the castor oil, and he went on: "Yes; a bat-like wing. A new specimen, undoubtedly. Effie, run round to the professor and ask him to be kind enough to step in for a few minutes."
"You might give me sixpence, Daddy," said Effie, "because I did bring you the new specimen. I took great care of it inside my eye, and my eye does hurt."
The doctor was so pleased with the new specimen that he gave Effie a shilling, and presently the professor stepped round. He stayed to lunch, and he and the doctor quarreled very happily all the afternoon about the name and the family of the thing that had come out of Effie's eye.
But at teatime another thing happened. Effie's brother Harry fished something out of his tea, which he thought at first was an earwig. He was just getting ready to drop it on the floor, and end its life in the usual way, when it shook itself in the spoon—spread two wet wings, and flopped onto the tablecloth. There it sat, stroking itself with its feet and stretching its wings, and Harry said: "Why, it's a tiny newt!"
The professor leaned forward before the doctor could say a word. "I'll give you half a crown for it, Harry, my lad," he said, speaking very fast; and then he picked it up carefully on his handkerchief.
"It is a new specimen," he said, "and finer than yours, Doctor."
It was a tiny lizard, about half an inch long—with scales and wings.
So now the doctor and the professor each had a specimen, and they were both very pleased. But before long these specimens began to seem less valuable. For the next morning, when the knife-boy was cleaning the doctor's boots, he suddenly dropped the brushes and the boot and the blacking, and screamed out that he was burnt.
And from inside the boot came crawling a lizard as big as a kitten, with large, shiny wings.
"Why," said Effie, "I know what it is. It is a dragon like the one St. George killed."
And Effie was right. That afternoon Towser was bitten in the garden by a dragon about the size of a rabbit, which he had tried to chase, and the next morning all the papers were full of the wonderful "winged lizards" that were appearing all over the country. The papers would not call them dragons, because, of course, no one believes in dragons nowadays—and at any rate the papers were not going to be so silly as to believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail and great wings like bats' wings, only the wings were a pale, half-transparent yellow, like the gear-boxes on bicycles.
Based on the rising action in the bolded paragraphs, what do we know about Daddy? (5 points)
He is calm and curious.
He is angry and upset.
He is hysterical.
He is uninterested and bored.
believe in fairy stories. At first there were only a few, but in a week or two the country was simply running alive with dragons of all sizes, and in the air you could sometimes see them as thick as a swarm of bees. They all looked alike except as to size. They were green with scales, and they had four legs and a long tail.
Explanation:
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Answer:
its "calm and curious"
Explanation:
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