An atom of which element is represented by this model Answer(ps if you dont have ther awnser dont say anything at all got it)​

Answer:

a = \(\frac{d}{b+c}\)

Step-by-step explanation:

a(b + c) = d

isolate a by dividing both sides by b + c

a = \(\frac{d}{b+c}\)

Answer:

1. b_ 2. a_ 3. c_ 4. d

Step-by-step explanation:

1 is b mainly because it is marked that way. Your picture doesn't show all of d so not really sure about it, but I used the process of elimination. Picture c is side angle side b/c of the vertical angles.

Answer:

24 sq yds

Explanation:

9 sq ft per sq yd

24*9=216 sq ft

The quadratic functions are: f(x) = 0.03x² for Design A and g(x) = 0.024x² for Design B.

A quadratic function is a type of polynomial function of the form f(x) = ax² + bx + c, where a, b, and c are constants and x is the variable. In a quadratic function, the highest power of the variable is 2.

The graph of a quadratic function is a parabola, which is a U-shaped curve that opens either upwards or downwards depending on the sign of the coefficient a. If a > 0, the parabola opens upwards, and if a < 0, the parabola opens downwards. The vertex of the parabola, which is the point where the curve changes direction, is given by the coordinates (-b/2a, f(-b/2a)).

Quadratic functions have a wide range of applications in various fields such as physics, engineering, economics, and finance. For example, they can be used to model the motion of projectiles, the trajectory of a rocket, the shape of a bridge arch, the optimization of business profits, and the behavior of financial markets.

Let's assume that each side of the cube has a length of x inches. Then, the surface area of the cube is 6x² square inches.

a. For Design A with a cost of $0.005 per square inch, the total cardboard cost can be calculated using the quadratic function:

f(x) = 0.005(6x²) = 0.03x²

b. For Design B with a cost of $0.004 per square inch, the total cardboard cost can be calculated using the quadratic function:

g(x) = 0.004(6x²) = 0.024x²

Therefore, the quadratic functions are:

f(x) = 0.03x² for Design A

g(x) = 0.024x² for Design B

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The complete question is:

In the quadratic equation y = a\(x^{2}\) + c ,the value of x = ± \(\sqrt \frac{y-c}{a}\)

A quadratic equation is any equation containing one term wherein the unknown is squared and no term wherein it's far raised to a higher power.

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, in which a and b are the coefficients, x is the variable, and c is the constant term.

To find the value of x

Assuming \(a\neq o\)

First, subtract c from both the sides to get:

\(y-c=ax^{2}\)

then, divide both sides by \(a\) and transpose to get:

\(x^{2} =\frac{y-c}{a}\)

So, \(x\) must be a square root of \(\frac{y-c}{a}\)  and we can deduce:

\(x=\) ± \(\sqrt \frac{y-c}{a}\)

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Answer:

163.5 cubes

Step-by-step explanation:

Answer:

A gift box has dimensions of: 8 12 inches, 5 12 inches, and 2 12 inches, respectively. How many cubes with side lengths of 12 inches would be needed to fill the gift box?

116.875 cubes

163.5 cubes

935 cubes

1870 cubes

163.5 cubes

Step-by-step explanation:

A gift box has dimensions of: 8 12 inches, 5 12 inches, and 2 12 inches, respectively. How many cubes with side lengths of 12 inches would be needed to fill the gift box?

116.875 cubes

163.5 cubes

935 cubes

1870 cubes

163.5 cubes

The upper bound of a 99% confidence interval is found as 57.07.

For the stated question-

Thus, upper confidence bound (UCB) is estimated as;

UCB = x + z(α/2)×s/√n

UCB = 36.5 + 2.576×33.88/√18

UCB = 36.5 + 20.57

UCB = 57.07

Thus, the upper bound of a 99% confidence interval is found as 57.07.

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Answer:

2.5m

Step-by-step explanation:

Using the adjusted accounting profits method.

Operating cash flow = After - tax profit + Depreciation. .......... ( 1 )

Given that :

* depreciation expense = $1 million

* Sales generated $7 million

* Tax rate = 25%

Tax rate = 25/100

= 0.25

From equation 1

= ( 7m - 4m - 1m ) ×( 1 - 0.25 ). + 1m

= ( 7m - 5m ) × ( 0.75 ) + 1m

= 2m × 0.75 + 1m

= 1.5m + 1m

= 2.5m

The firm operating cash flow = 2.5m

Given the expression:

We will find the value of the expression when m=2/3, and q= 1/4

So,

So, the answer will be: 5/12

Step-by-step explanation:

I hope this answer is helpful ):

Answer:

A dynamic environment is a business environment that is rapidly changing. In a dynamic market, businesses have to adapt quickly to changes and develop new ideas, products and services to keep up with technology and new trends.

Step-by-step explanation:

The two column proof showing that  ΔWXZ ≅ ΔYXZ is as shown below

From the given triangle, we see that;

Given: WX ≅ XY, XZ bisects WXY

Prove: ΔWXZ ≅ ΔYXZ

The two column proof for the above is as follows;

Statement 1;  WX ≅ XY, XZ bisects 2

Reason 1; Given

Statement 2: ∠WXZ ≅ YXZ

Reason 2; Angle bisector

Statement 3; XZ ≅ XZ

Reason 3: Reflexive property of congruence

Statement 4:  ΔWXZ  ≅ ΔYXZ

Reason 4:  SAS Congruence Postulate

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0.5236 meters is the length of the given arc.

The formula for the length of an arc is given by:

Arc Length = (θ/360) * 2πr

Where:

In this case, the central angle is 60 degrees and the radius is 1/2 meters.

Plugging the values into the formula, we have:

Arc Length = (60/360) * 2π(1/2)

Arc Length = (1/6) * π

Arc Length = π/6

Therefore, the length of the arc that subtends an angle of 60 degrees at the center of a circle with a radius of 1/2 meters is π/6 meters or approximately 0.5236 meters.

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Correct option is A)

Consider the given equation,

3

2x

+10.3

x

−9=0

Let ,y=3

x

Now ,

y

2

−10y+9=0

y

2

−9y−y+9=0

y(y−9)−1(y−9)=0

(y−9)(y−1)=0

When,

x−9=0

x=9

Now ,

9=3

x

3

2

=3

x

x=2

When,

y−1=0

y=1

3

x

=1

3

x

=3

0

x=0

x=0,x=2

This is the answer

Huh?? Can u attach a picture or some

The volume of the solid is 250r³ when  the base of s is a circular disk with radius 5r.

Given that,

We have to discover the described solid's volume, v. The parallel cross-sections perpendicular to the base of s are squares, and the base of s is a circular disk with radius 5r.

We know that,

A cylinder is a solid with square cross sections parallel to the bases and circular bases. Its height is equal to the base circle's diameter.

The radius = 5r,

So the height = diameter = 10r

Volume of the cone is base × height= πr²×h

=π(5r)²×(10r)

=250πr³

Therefore, The volume of the solid is 250r³ when  the base of s is a circular disk with radius 5r.

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The least common denominator needed to solve the equation is given as follows:

D. x(x - 3).

The equation in this problem is given as follows:

1/x + 2/(x - 3) = 5.

The denominators of each expression are given as follows:

x and x - 3 are not factors of each other, hence we multiply them and the least common denominator needed to solve the equation is given as follows:

D. x(x - 3).

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The number of square meters that the space that Araceli rents is, is 30. 66 square meters.

The space that Araceli rents has a rectangular space so to find the area of the rectangular space that Araceli rents, we need to multiply the length by the width.

The given width is 4. 2 meters and the length is 7. 3 meters.

The area of the space in square meters is therefore :

Area = Length × Width

Area = 7. 3 meters × 4. 2 meters

Area = 30. 66 square meters

In conclusion, the space that Araceli rents has an area of 30. 66 square meters.

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Answer:

✓ C. f(x)= sqrt 1/x

Step-by-step explanation:

i hoep this answer your question

Answer:

\(\pi\)

Step-by-step explanation:

Area = \(\pi x^{2}\)  For a full circle.  This is 1/4 of a circle

A= \(\frac{\pi 2^{2} }{4}\) = \(\frac{\pi 4}{4}\) = \(\pi\)

Answer : The area of the shape is, 111.02 units 2

The dimensions of the cup that minimize the construction cost are 2 x 2 x 5 in

Given:  Capacity = 20 in³, cost of material for the side = 12¢/in² and cost of material for the base = 60¢/in²

In order to calculate the dimension of the cup

Let h and x represent the height and square base respectively

Thus, the capacity (volume) of the pencil cup is can be represented as:

V = x²h     (where V = 20)

20 = x²h

h = 20/x²

At minimum cost, we have:

C(x) = 60x² +  12(4xh)

C(x) = 60x² +  48xh         (put h = 20/x²)

C(x) = 60x² +  48x(20/x²)

C(x) = 60x² +  960/x

Differentiating with respect to x, we have:

C(x) = 120x - 960/x²      (multiply through by x²)

120x³-960 = 0

120x³ = 960

x³ = 960/120

x³ = 8

x = ∛8 = 2 in

For the height:

h = 20/x²

h = 20/2²

h = 20/4 = 5 in

dimensions = 2 x 2 x 5 in

Therefore, the dimensions of the cup that minimize the construction cost are a 2 x 2  square base and  height of 5 in

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Answer:

B option is right.

Step-by-step explanation:

To find y intercept put x=0 From given equation in question.

y = 1/2x -2

put x = 0

y = -2

From B option x+4y = -8

put x=0 to find y intercept.

4y = -8

y = -2

Note: To find x intercept put y=0 and to find y intercept put x = 0.

The linear function that describes the distance (in miles) is therefore y = 65x + 80

We have to find the slope and the intercept in other to get the linear function

The data points are:

(1, 145) and (3, 275).

m = (y2 - y1) / (x2 - x1)

fixing the data points we have

m = (275 - 145) / (3 - 1)

= 130 / 2

= 65

y = mx + b

(1, 145):

145 = 65(1) + b

b = 145 - 65

= 80

y intercept is 80

The linear function is therefore y = 65x + 80

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Step-by-step explanation:

s1 = 5

s2 = s1 × -2 = 5×-2 = -10

s3 = s2 × -2 = -10 × -2 = 20

...

now, we could do all that manually.

but there is also a formula for geometric sequence.

in fact, there are 2 - one for finite and one for infinite sequences.

and I was not completely honest, each of these 2 had some sub-forms depending on the size of the multiplier or ratio.

since we need the sum of the first 5 terms, which of the 2 do you think we need ?

of course, finite, because 5 is a normal number we can "touch". it is not infinity.

so, the formulas for finite sums of geometric sequences are :

if |r| < 1, Sn = a(1 - r^n)/(1 - r)

if |r| > 1, Sn = a(r^n - 1)/(r - 1)

if r = 1, Sn = na

if r = -1, then Sn = a or 0 depending on if n is odd or even.

the sequence is in general

s1 = a

sn = sn-1 × r

in our case a = 5, r = -2.

so, what form of the formula do we need ?

|-2| = 2, and 2 > 1, so ...

S5 = 5(-2^5 ‐ 1)/(-2 - 1) = 5(-32 - 1)/-3 = 5×-33/-3 =

= 5 × 11 = 55

quick check, as the 5 terms are

5

-10

20

-40

80

and their sum is : 55

correct !

Answer:

  ₹ 1,50,000

Step-by-step explanation:

You want to know the value of machinery to be shown if the value ₹ 2,00,000 is (100/3)% too high.

The value shown (₹ 2,00,000) is (100/3)% more than the actual value, so the relation is ...

  ₹ 2,00,000 = actual value + (100/3)% × actual value

  ₹ 2,00,000 = actual value · (1 +1/3)

Multiplying by 1/(1 +1/3), we have ...

  actual value = (3/4)·(₹ 2,00,000) = ₹ 1,50,000

The value of machinery to be shown in the New Balance Sheet is ₹1,50,000.

__

Additional comment

(100/3)% = (100/3)/100 = 1/3

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Answer:friends

Step-by-step explanation:

Answer:

11.35

Step-by-step explanation:

13.25

-

1.9

_____________

11.35

Answer:

The percentile rank for Park Street's revenues this week is 60th.

The percentile rank for Bridge Road's revenues this week is 73rd.

Step-by-step explanation:

The missing information are as follows:

Variable     N       Mean       SD

  Park        36       6611       3580

Bridge      40      5989       1794

A z-score (aka, a standard score) specifies the number of standard deviations an observation is from the mean.  

The formula to compute the z-score is, \(Z = \frac{(X - \mu)}{\sigma}\), where X = observation, µ = mean, σ = standard deviation.

Compute the z-score for Park Street's revenues, $7500 as follows:

\(Z_{p} = \frac{(X - \mu)}{\sigma}=\frac{7500-6611}{3580}=0.25\)

The z-score for Park Street's revenues this week is 0.25.

Compute the percentile rank for Park Street's revenues this week as follows:

\(P(Z<Z_{p})=P(Z<0.25)=0.5987\approx 0.60\ \text{or}\ 60\%\)

The percentile rank for Park Street's revenues this week is 60th.

This implies that the Park Street's performed better than 60% of the revenue recorded for the restaurant.

Compute the z-score for Bridge Road's revenues, $7100 as follows:

\(Z_{p} = \frac{(X - \mu)}{\sigma}=\frac{7100-5989}{1794}=0.62\)

The z-score for Bridge Road's revenues this week is 0.62.

Compute the percentile rank for Bridge Road's revenues this week as follows:

\(P(Z<Z_{b})=P(Z<0.62)=0.7324\approx 0.73\ \text{or}\ 73\%\)

The percentile rank for Bridge Road's revenues this week is 73rd.

This implies that the Bridge Road's performed better than 73% of the revenue recorded for the restaurant.