An atom of iron has an atomic number of 26 and a mass number of 56. How many protons, neutrons, and electrons are contained in this atom?​

Answer:I know the answer for B cus I’m doing the same problem. For B, you would only take the coefficient of friction given and then multiply it by the Normal Force, which in this case is the same as the Gravitational Force.

Explanation:

The magnitude of acceleration of block 2 is 4.67 m/s².

The diagram representing the blocks is shown below:It can be observed that the two blocks are connected by a massless string that passes over a massless pulley. 1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. 2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.Now let's derive the equation for acceleration, a2.

A key concept that must be understood to solve the problem is the difference in tension on either side of the string. Since the pulley is massless and frictionless, the tension must be the same on both sides. We can derive this concept using the following equations:Tension on block 1 side:T1 = m1(g)sin(1) - m1(g)cos(1) * f1Tension on block 2 side:T2 = m2(g)sin(2) + m2(g)cos(2) * f2Where g is acceleration due to gravity, which is equal to 9.8 m/s².Then:T1 = T2T1 + m1(g)cos(1) * f1 = m2(g)sin(2) + m2(g)cos(2) * f2Substitute the values into the above equation:2.25(9.8)cos(42.5) * 0.205 + 2.25(9.8)sin(42.5) = 5.55(9.8)sin(33.5) + 5.55(9.8)cos(33.5) * 0.105T2 = 25.836 N (correct to 3 significant figures)Now we can find the acceleration of block 2.

The acceleration of block 1 can be determined using the following equation:a1 = g(sin(1) - f1 cos(1))a1 = 9.8(sin(42.5) - 0.205cos(42.5))a1 = 5.748 m/s² (correct to 3 significant figures)Using the equation for acceleration of block 2:a2 = (T1 - T2) / m2a2 = (25.836 - 0) / 5.55a2 = 4.667 m/s² (correct to 3 significant figures).

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Answer:

Difference between MeV and meV?

1 MV = 1000000 volts. 1 MeV stands for million electron volts. It is a unit of energy. 1 MeV = 1.60217653 x 10 13

Explanation:

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Answer:

5 cm - 53 degrees

Explanation:

\( \sqrt{ {4}^{2} + {3}^{2} } = 5cm\)

\( \tan ^{ - 1} (4 \div 3) \) = 53°

Answer:

C. Influenced by the Sun's electromagnetic field

Explanation:

"Sunspots occur in pairs because each is one side of a loop of the Sun's magnetic field that reaches the Sun's surface. Solar prominences are the plasma loops that connect two sunspots."

Answer:

b

Explanation:

Answer:

140.8/2.54=55.43 inches

(a) The magnitude of the gravitational force on the rock is 64.68 N and on the pebble is 5.488 x 10⁻³ N.

(b) The acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

The gravitational force exerted on each object is calculated by applying Newton's law of universal gravitation as follows;

Fg = Gm₁m₂ / R²

where;

The acceleration of each object will be constant and equal to acceleration due to gravity, the force on each object is calculated by using Newton's second law of motion.

Force on the rock;

F = mg

where;

F = 6.6 kg x 9.8 m/s²

F = 64.68 N

The force on the pebble;

F = mg

F = 5.6 x 10⁻⁴  x 9.8

F = 5.488 x 10⁻³ N

Thus, the acceleration of each object is equal to acceleration due to gravity, = 9.8 m/s².

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The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.

The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;

The total voltage in loop 1 is calculated as;

2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

The current flowing in loop 2 is calculated as;

I = V/R

I₂ = ( 6 V - 4 V ) / (3 + 4)

I₂ = 0.286 A

The value of the current flowing in loop 1 is calculated as;

6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0

6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0

6 - 3I₁ - 3₁ + 0.858 = 0

-6I₁ = -6.858

I₁ = 6.858 / 6

I₁ = 1.14 A

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Answer:

Explanation:

We shall apply here Doppler's effect in optics . The formula is as follows

\(\frac{\triangle\lambda }{\lambda } = \frac{v}{c}\)

Δλ is change in wavelength , λ is original wavelength , v is velocity and c is velocity of light

Δλ = 685 - 590 = 95 nm

λ = 685

95 / 685 = v / 3 x 10⁸

v = .416 x 10⁸ m / s

= 4.16 x 10⁷ m /s

Modern LCD and LED screens have taken the role of the Cathode Ray Tubes (CRTs) that were once used in televisions. The magnitude of the electric field (in V/m) in the region between the plates is 1.88 x 10^6 V/m.

The CRT is made up of an electron gun that produces a beam of electrons that are then directed by an electric field towards a fluorescent screen at the end of the tube. The electric field between the plates of a CRT (Cathode Ray Tube) has to be found. The plates are 1.30 cm apart and there is a potential difference of 24.5 kV between the plates. Here’s how to find the electric field: The formula to calculate the electric field between the plates is: `E = V/d`, where E is the electric field.

Substitute the given values in the formula: E = V/d = 24.5 kV/0.013 m= 1.88 x 10^6 V/m. Therefore, the magnitude of the electric field (in V/m) in the region between the plates is 1.88 x 10^6 V/m.

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Answer:

2 minutes

Explanation:

From the graph, it takes 2 minutes for the piece of ice to go to the completely liquid phase.

The final velocity of a truck is 74.0 ft/s, if it accelerates at a range of 3.00 ft/\(s^2\) from an initial velocity of 5.00 ft/s, then it will take the truck 23.67 seconds to attain its final velocity of 74.0 ft/s.

v = u + at

Here, v =the final velocity, u =the initial velocity, a =the acceleration, and t =the time taken.

Substituting the given values, one can get,

74.0 ft/s = 5.00 ft/s + 3.00 ft/\(s^2\) × t

Solving for t, one gets,

t = (74.0 ft/s - 5.00 ft/s) / (3.00 ft/\(s^2\)) = 23.67 s (that is  23.67 seconds is needed to attain final velocity of 74.0 ft/s)

Hence, a truck needs 23.67 seconds time to attain its final velocity of 74.0 ft/s and this is the final velocity.

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Answer:

Acceleration = m/s²

Explanation:

T= Newtons compared to the weight W = Newtons for the hanging mass. If the weight of the hanging mass is less than the frictional resistance force acting on the mass on the table, then the acceleration will be zero.

The rests of a transverse wave are like the compression of the longitudinal waves.

In terms of physics, a transverse wave refers to the wave where  oscillations should be perpendicular to the direction of the wave's in advance. This is in contrast to a longitudinal wave that travels in the direction of its oscillations.

Therefore, we can conclude that The rests of a transverse wave are like the compression of the longitudinal waves.

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When a 9.0-kg box of oranges slides from rest down a frictionless incline from a height of 5.0 m with a  frictional force then the coefficient of kinetic friction between A and B is 9.9m/s.

The frictional force acting between two moving objects is termed as Kinetic friction.

Given:

Let v represent the speed of the box at point A, x represent the distance the box slides down the slope (without friction), and represent the angle of the incline.

Remember that v = ultimate speed, therefore v 2 - v02 = 2 an x

beginning speed being

A=acceleration and X=displacement

While moving up the slope, the box begins at rest (v0 = 0) and moves a distance x with an acceleration of a to reach a speed v.

F = m g sin() = m a, where m = 9.0 kg and g = 9.8 m/s2, and a = g sin().

Using a little trigonometry, write the distance x in terms of :

x = (5.0 m) / sin(x), where sin(x) = (5.0 m)

v, enter the following into the formula above:

= 2 g sin(5.0 m) / sin(5.0 m)

10.0 m) g v

= 9.9 m/s

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Answer:

B. A responding variable changes as a result of changes made to the

manipulated variable.

Explanation:

A responding variable is different from a manipulated variable because a responding variable keeps on changing, but a manipulated variable stays the same. Thus, the correct option is D.

A variable is any characteristic, number, or quantity which can be measured or counted easily. A variable may also be called as an item. Age, sex, business income and expenses, country of birth, capital expenditure, class grades, eye color and vehicle type all are the example of variables.

Manipulated Variable are those variables which is changed by the scientist and are called as the controlled variable. Responding Variable is the variable that might change on its own because of what the scientist changes in the experimental study.

Therefore, the correct option is D.

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Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation:

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

1.6 time constants must elapse

Explanation:

voltage on a cap, charging is given as

v = v₀[1–e^(–t/τ)]

Where R is resistance in ohms,

C is capacitance in farads

t is time in seconds

RC = τ = time constant

v = v₀[1–e^(–t/τ)]

1–e^(–t/τ) = 0.8

e^(–t/τ) = 0.2

–t/τ = –1.609

t = 1.609τ

The monocular cue of relative size

The object will fall through a distance of 638.45 m.

Considering the question given above, the following data were obtained:

Time (t) = 11.3 s

NOTE: Acceleration due to gravity (g) = 10 m/s²

We can obtain the height as illustrated below:

H = ½gt²

H = ½ × 10 × 11.3²

H = 5 × 127.69

Therefore, the distance the object will fall is 638.45 m

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The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Answer:

Explanation:

what do you really need help with

The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

To find the power dissipated in resistor R4, use the formula:

P = I² × R

where P = power, I = current flowing through the resistor, and R = resistance of the resistor.

The total resistance, Rt, can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3

Substituting the given values:

1/Rt = 1/3 + 1/0.8 + 1/2

Simplifying the equation:

1/Rt ≈ 1.6667

Rt ≈ 0.6 Ω

Next, calculate the total voltage, Vt, by summing the individual voltage sources:

Vt = ε1 + ε2 + ε3

Substituting the given values:

Vt = 9 + 6 + 4

Vt = 19 V

Now calculate the current flowing through resistor R4 using Ohm's Law:

I = Vt / Rt

Substituting the calculated values:

I = 19 / 0.6

I ≈ 31.6667 A

Finally, calculate the power dissipated in resistor R4:

P = I² × R4

Substituting the calculated values:

P = (31.6667)² × 10

P ≈ 10,028 W

Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

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Answer:

Explanation:

A = 6i - 4j + 8k

B = 2i + 4j - 14k

A + B = (6+2)i + (-4+4)j + (8-14)k

A + B = 8i +0j -6k

A + B = 8i - 6k

(1/2)(A + B) = 4i - 3k

d = √ (4² + 3²) = 5

e = (4/5)i -(3/4)j

The reading on each of the scales on the right is 421.4 N.

The reading on each of the scales on the left is 156.8 N.

The reading on each scale is determined from the distribution of the weight of the woman.

The weight of the board is distributed uniformly and each scale with have equal reading of the weight of the board.

weight of the board = 10 kg x 9.8 m/s² = 98 N

Reading of each due to weight of the board is calculated as;

W₁ = ¹/₂ (98 N) = 24.5 N

The distribution of the weight of the woman on the right scale is calculated as;

W (R) = ( 1.5 m / 2 m) x ( 54 x 9.8 )

W (R) =  396.9 N

The distribution of the weight of the woman on the left scale is calculated as;

W (L) = ( 0.5 m / 2 m) x ( 54 x 9.8 )

W (L) =  132.3 N

Total reading on the scale on the right = 396.9 N + 24.5 N = 421.4 N

Total reading on the scale on the left = 132.3 N + 24.5 N = 156.8 N

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