An artificial satellite orbits earth at a speed of 7800 m/s and a height of 200 km above earth’s surface. The satellite experiences an acceleration due to gravity of:.

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Given the data from the question,

A. The frequency of the wave is 0.2 Hz

B. The speed of the wave is 0.5 m/s

f = 1 / T

f = 1 / 5

f = 0.2 Hz

v = λf

v = 2.5 × 0.2

v = 0.5 m/s

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The formula for the impulse exerted on the ball from the instant it is dropped to an arbitrary time later is:

Impulse = (Final momentum - Initial momentum)

Impulse is a vector quantity having both magnitude and direction, whereas momentum is a vector quantity, but the impulse is not equal to momentum. The impulse is the change in momentum.

If a ball of mass m is dropped from rest, then its initial momentum is zero.

The final momentum of the ball after falling for time t is:

Final momentum = mv

Where v is the velocity of the ball after falling for time t.

Therefore, the impulse exerted on the ball from the instant it is dropped to an arbitrary time later is:

Impulse = (mv - 0) = mv

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Answer:

Mechanical????????????

Answer:

9.8 m/ssr=2322

Explanation:

Stagnation pressure upstream  is \({Po_{1}=17.085\: atm\),Mach number downstream is \(Ma_{2}=0.5\) ,Static pressure downstream is  \(P_{2} =7.31\:atm\)Static pressure downstream  is \(Po_{2} =8.67\:atm\) Stagnation temperature downstream is  \({To_{2} } =673.29K\)

Stagnation pressure in fluid dynamics is the static pressure at a point where a fluid flow has stopped. A stagnation point has zero fluid velocity. Stalling pressure in an incompressible flow is the same as the total of free-stream static pressure and free-stream dynamic pressure. The fluid density is higher at the stagnation point than at the static point in compressible flow, though. The stagnation enthalpy or stagnation temperature in compressible flow serves many of the same functions as the stagnation pressure in incompressible flow.

The relation for normal shock will be used to find the \(M_{2} ,Po_{1} ,P_{2} ,Po_{2}, and\:\: To_{2}\)

\(Ma_{2} =\frac{Ma_{1} ^{2}+\frac{2}{r} -1 }{2Ma_{1} ^{2}+\frac{r}{r-1} -1 }\)

Working gas is air and helium

for air , r=1.4 for we r=\(\frac{5}{3}\)

\(\frac{Po_{1}}{P_{1}} =[1+\frac{r}{r-1} Ma_{1} ^2]^\frac{r}{r-1}\)

\(P_{1}=1 atm\)

\(\frac{Po_{1}}{P_{1}} =[1+\frac{0.4}{2} (2.5)^2]^\frac{1.4}{0.4}\)

\({Po_{1}=17.085\: atm\)

\(Ma_{2}^2 =\frac{Ma_{1} ^{2}+\frac{2}{r} -1 }{2Ma_{1} ^{2}+\frac{r}{r-1} -1 }\)

\(Ma_{2}^2 =\frac{2.5 ^{2}+\frac{2}{1.4} -1 }{2\times2.5 ^{2}+\frac{1.4}{1.4-1} -1 }\)

\(Ma_{2}^2=\frac{2.5^2+0.2}{21.857-1}\)

\(Ma_{2}=0.5\)

\(\frac{P_{2} }{P_{1} } =\frac{Ma_{1} \sqrt{1+Ma_1^2\frac{(r+1)}{2} }}{Ma_{2}\sqrt{1+Ma_2^2\frac{(r+1)}{2} }}\)

\(\frac{P_{2} }{P_{1} } =\frac{2.5 \sqrt{1+2.5^2\frac{(0.4)}{2} }}{0.5 \sqrt{1+0.5^2\frac{(0.4)}{2} }}\)

\(P_{2} =7.31\:atm\)

\(\frac{Po_{2} }{P_{1} } ={(1+ {\frac{(r-1)}{2} Ma_{2}^2 })^\frac{r}{r-1}\)

\(\frac{Po_{2} }{7.31 } ={(1+ {\frac{(1.4-1)}{2} 0.5^2 })^\frac{1.4}{0.4}\)

\(Po_{2} =8.67\:atm\)

\(\frac{To_{2} }{T_{2} } ={(1+ {\frac{(r-1)}{2} Ma_{2}^2 })^\frac{r}{r-1}\)

\(\frac{To_{2} }{T_{2} } =(\frac{Po_{2} }{P_{1} })^2(\frac{Ma_{2} }{Ma_{1} })^2\)

\({T_{2} } =300\times(\frac{7.31 }{1 })^2(\frac{0.5}{2.5 })^2\)

\({T_{2} } =641.23K\)

\({To_{2} } =641.23K(1+\frac{0.4}{2}(0.5)^2)\)

\({To_{2} } =673.29K\).

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Question: A stationary normal shock has the following conditions upstream: static pressure P1 = 1 atm, static temperature T1 = 300 K, and Mach number M1 = 2.5. For each of the cases below determine the following variables (in the units indicated):

(i) The stagnation pressure upstream, P01 [atm],

(ii) The Mach number downstream, M2,

(iii) The static pressure downstream, P2 [atm],

(iv) The stagnation pressure downstream, P02 [atm],

(v) The stagnation temperature downstream, T02 [K].

The following actions are minimally necessary to determine if a motion detector should be calibrated before using it to investigate the motion of an object is option C which is both of this action are required.

Motion detector is a mechanical device that have sensor and it is use to detect the movements of people or objects in a place. It is use by security organizations to detect illegal movements and the sensors send alert to the system if there is any strange thing.

Therefore, The following actions are minimally necessary to determine if a motion detector should be calibrated before using it to investigate the motion of an object is option C which is both of this action are required.

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Answer:

a)

Explanation:

work done = Fscosθ

=(10)(5)(cos0⁰)

=50J

Some practical uses of solar energy include activities that require power per unit area on the order of 10² W/m² or less.

Solar energy is a renewable and sustainable source of power that can be harnessed through various technologies. The question highlights the power concentration of sunlight in different scenarios, such as the tropics with close to 1000W/m² and winter days in Manitoba with a power concentration of 100W/m². It further states that many human activities typically require power per unit area on the order of 10² W/m² or less.

Given this information, practical uses of solar energy can include activities that operate within the power limitations mentioned. Examples of such applications could be solar-powered lighting systems, small-scale electronics charging, water heating, or low-power devices in remote locations.

These uses take into account the available solar energy and optimize its utilization for specific purposes while considering the power requirements.

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If the strong force was suddenly turned off throughout the universe, atoms would almost immediately disintegrate as the strong force is responsible for holding the nucleus of an atom together.

This would result in a release of energy as the protons and neutrons in the nucleus repel each other due to the electromagnetic force. The energy released would be so great that it would cause a massive explosion, similar to a nuclear explosion. Furthermore, the absence of the strong force would also affect the stability of neutron stars and supernovae, which rely on the strong force to maintain their structure. Overall, the absence of the strong force would result in a catastrophic and potentially apocalyptic scenario for the universe.

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False. The heat capacity of a substance is the amount of heat required to raise the temperature of a given amount of that substance by 1 degree Celsius.

In this case, the video experiment showed that the heat capacity of aluminum is greater than that of water. If we replace the aluminum with a mystery metal and the water heats up to 40∘C while the mystery metal heats up to 80∘C, it means that the mystery metal absorbed more heat than water. However, the question states that the mass of the mystery metal is the same as that of water. Therefore, if the mystery metal absorbed more heat than water, it must have had a higher heat capacity, not one-third as great. Therefore, the statement that the heat capacity of our mystery metal is one-third as great as that of water is false.

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Answer:

i can`t help without showing me the choses

Explanation:

Answer:

O.8A

Explanation:

(i) The magnitudes of the electric fields they separately create at a radial distance of 6 cm is \(E_{a}\)=\(E_b}\). and (ii) The magnitudes of the electric fields they separately create at radius 4 cm is \(E_{a} =E_{b}\), so the correct option is option b.

A conductor refers to a material that allows an electric current to flow through it with ease. In other words, it has a low electrical resistance. Conductors are materials that have a high number of free electrons that are able to move freely through the material. Examples of conductors include copper, aluminum, gold, and silver. These materials are commonly used in the electrical industry to make wires and other electrical components that need to conduct electricity. In addition to materials, a conductor can also refer to a person or an organization that is responsible for directing or leading an orchestra or a choir. In this context, a conductor is in charge of maintaining the ensemble's rhythm and intonation, and interpreting the score in a way that brings out the music's emotional content and intended meaning.

(i) The magnitude of the electric field created by a charged conductor is given by the formula E = \(\frac{kq}{r}\), where k is the Coulomb constant, q is the charge, and r is the distance from the center of the sphere.

For a good conductor, like sphere A, the charge will be distributed evenly on the surface of the sphere. So, the electric field at a radial distance of 6cm will be Eₐ = \(\frac{kq}{r^{2} }\) = \(k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

For an insulator, like sphere B, the charge is distributed uniformly throughout its volume. The electric field at a radial distance of 6cm will be \(E_{b}\)=  \(\frac{kq}{r^{2} }=k\frac{210^{-6} }{(619^{-2} )}^{2} =\frac{k}{72}\)

As we can see, the magnitudes of the electric fields created by both spheres are equal, so the answer is (b) \(E_{a} =E_{b}\)

(ii) For the radius of 4cm, the electric field created by sphere A and sphere B will

\(E_{a} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\E_{b} =\frac{kq}{r^{2} }=k\frac{210^{-6} }{(410^{-2} )^{2} } =\frac{k}{16}\\\)

As we can see, the magnitudes of the electric fields created by both spheres are equal at a radius of 4cm, so the answer is (b) \(E_{a} =E_{b}\)

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Answer:

You only have  12 Seconds to Pitch

A baseball game usually lasts 3 hours long

The record of most home runs in a baseball match by one person is 4

Explanation:

I hope this helps u

Answer:

Velocity, V = 33.33 m/s

Explanation:

Given the following data;

Mass = 180grams to kilograms = 180/1000 = 0.18 kg

Kinetic energy = 100J

To find the speed;

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

\( K.E = \frac{1}{2}MV^{2}\)

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Substituting into the equation, we have;

100 = ½*0.18*V²

Cross-multiplying, we have;

200 = 0.18*V²

V² = 200/0.18

V² = 1111.11

Taking the square root of both sides, we have;

Velocity, V = 33.33 m/s

Give u = start velocity

        v = end velocity

v = u + at

50 = 400 + a*30

30a = -350

a = -116.67 m/\(s^{2}\)

**Why the accecleration is negative number**

Because displacement, velocity, and acceleration are VECTOR QUANTITIES.

Vector Quantity must have direction.

Answer:

The rate of heat transfer of the second object is greater than the first object.

Explanation:

\(\varepsilon\) = Emissivity of the object

\(\sigma\) = Stefan-Boltzmann constant = \(5.67\times 10^{-8}\ \text{W/m}^2/\text{K}^4\)

\(T_1\) = Temperature of surface 1 = \(25^{\circ}\text{C}+273.15=298.15\ \text{K}\)

\(T_2\) = Temperature of surface 2 = \(40^{\circ}\text{C}+273.15=313.15\ \text{K}\)

\(T_0\) = Surrounding temperature = \(25^{\circ}\text{C}+273.15=298.15\ \text{K}\)

Rate of heat transfer is given by

\(P_1=\varepsilon \sigma (T_1^4-T_0^4)\\\Rightarrow P_1=\varepsilon \sigma A_1(298.15^4-298.15^4)\\\Rightarrow P_1=0\ \text{W}\)

\(P_2=\varepsilon \sigma (T_2^4-T_0^4)\\\Rightarrow P_2=\varepsilon 5.67\times10^{-8} A_2(313.15^4-298.15^4)\\\Rightarrow P_2=\varepsilon A_297.2\)

\(\varepsilon A_297.2>0\)

So, \(P_2>P_1\)

Hence, the rate of heat transfer of the second object is greater than the first object.

First of all, how long does it take it to fall 0.93m to the floor ?

Distance falling from rest = (1/2) · (g) · (T²)   <== memorize this formula

(0.93 m) = (1/2) (9.8m/s²) (T²)

Divide each side by (4.9 m/s²) :  T² = (0.93/4.9)  =  0.1898 s²

Square root each side:  T to hit the floor = 0.436 second

It got 0.56m away from the desk horizontally in 0.436 sec.

Speed = (distance) / (time)    <=== memorize this formula

Speed = (0.56 m) / (0.436 sec)

Speed = 1.28 m/s

The two-input LUT is a very versatile logic element that can be used to implement a wide variety of functions.

a) Behavioral modeling in Verilog HDL is a high-level language that allows you to describe the behavior of a digital circuit without worrying about the underlying hardware implementation. This makes it a very effective way of describing digital circuits, as it allows you to focus on the functionality of the circuit without getting bogged down in the details of how it will be implemented.

b) The main difference between using a general-purpose processor and digital design in developing an electronic application is that a general-purpose processor is designed to be able to execute a wide variety of instructions, while digital design is specifically designed to implement a particular function. This means that a general-purpose processor may not be the most efficient way to implement a specific function, as it may require more hardware resources than a custom-designed digital circuit.

c) The four principles for effectively and quickly achieving the design are:

Regularity: The design should be as regular as possible. This means that the design should be made up of a small number of repeated units, rather than a large number of unique units.

Simplicity: The design should be as simple as possible. This means that the design should be easy to understand and implement.

Efficiency: The design should be as efficient as possible. This means that the design should use the minimum amount of hardware resources.

Verifiability: The design should be verifiable. This means that the design should be able to be checked to ensure that it meets its specifications.

The regularity principle can be explained by the following example. If you are designing a digital circuit to add two numbers, you could use a design that is made up of a small number of repeated units, such as adders and registers. This would be a more regular design than a design that used a large number of unique units, such as a custom-designed adder. A more regular design is easier to understand and implement, and it is also more likely to be efficient.

d) A two-input LUT in the FPGA implements a logic f = a b + ab by storing the truth table for the function in its memory. When the inputs to the LUT are applied, the LUT will output the corresponding value from its memory.

For example, if the inputs to the LUT are a = 0 and b = 1, the LUT will output the value 1, because the truth table for f shows that the output is 1 when a = 0 and b = 1.

The two-input LUT is a very versatile logic element that can be used to implement a wide variety of functions. It is a key building block in many FPGA designs.

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Answer:

If you haven't heard, Joe Biden would like to unite America.

It was a focus of the Democrat's campaign. It's even the theme of Biden's inauguration — "America United."

The inaugural committee says the slogan "reflects the beginning of a new national journey that restores the soul of America, brings the country together, and creates a path to a brighter future."

If only it were that easy.

When Biden is sworn in at 12:01 p.m. ET Wednesday as the 46th president of the United States, it will be with the understanding that the country is as divided as it's ever been, as pessimistic as it's been in three decades and facing health, economic and racial crises.

It will also be a very different inauguration than has ever been seen in U.S. history. Four years ago, President Trump was arguing over his crowd size compared with Barack Obama's record-setting turnout of supporters on the National Mall.

Explanation:

btw i would rather have him as president

Answer:

10.71 mL

Explanation:

We know,

=> density= mass/volume

=> 1.4 = 15 / Volume

=> volume= 15/1.4 mL

=> volume= 10.71 mL

Explanation:

First, convert terameters to meters.

234 Tm × (10¹² m / Tm) = 234×10¹² m

Now convert meters to nanometers.

234×10¹² m × (10⁹ nm / m) = 234×10²¹ nm

In scientific notation, that's 2.34×10²³ nm.

The potential energy is utilized during work done against frictional force.

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.

When a driver applies the brakes to keep a car going down hill at constant speed and constant kinetic energy, the potential energy of the car decreases. The potential energy is utilized during work done against frictional force and total energy remains constant.

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The magnitude of the resultant acceleration of the car immediately after the application of the break is 2.495 m/s².

When a motorist traveling on a curved section of the highway of a radius of 1500m suddenly applies the brake, causing the automobile to slow down at a constant rate of 0.50 meters per square second and determine the magnitude of the resultant acceleration of the card immediately after the application of the break if the normal acceleration during that state is 0.185 meters per square seconds.

The centripetal force, fc is given by the expression:

fc = m v² / where m is the mass of the object and the velocity of the object is the radius of the path.

The acceleration of the object, a is given by the expression:

a = fc / where m is the mass of the object and is the centripetal force acting on the object when the brakes are applied, the normal force acting on the object increases.

The resultant force acting on the object is given by:

F = fN - friction, where fN is the normal force acting on the objectification, and is the frictional force acting on the object.

The frictional force is given by: friction = μ * where μ is the coefficient of friction between the object and the surface of the paths acceleration of the object, a is given by the expression:

a = (fN - friction) / When the object is in a state of equilibrium, the sum of the forces acting on the object is equal to zero.

The normal force acting on the object, fN is given by: fN = mg - where, g is the acceleration due to gravity

a = fc / m = m v² / r / m = v² / r = (60 / 3.6)² / 1500 = 0.694 m/s²

The force of friction acting on the object, friction is given by:

friction = μ * fN = μ * (mg - fc)fN = mg - fc = m * g - m v² / rr = 1500m

Therefore, the acceleration of the object after the brakes are applied is given by:

a = (fN - friction) / m= [(m * g - m v² / r) - μ * (m * g - m v² / r)] / m= [(1 - μ) * (m * g - m v² / r)] / m= [(1 - μ) * g - (1 - μ) * v² / r] = [(1 - 0.5) * 9.81 m/s² - (1 - 0.5) * (60 / 3.6)² / 1500] m/s²≈ 2.495 m/s².

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Answer:

D: tipping over dominoes

Explanation:

tipping over dominoes makes a wave-like movement

Answer:

the answer is D. just got it right 4/19/22

Explanation:

C. A heat pump absorbs 100 J of heat from a cool reservoir and releases 120 J of heat to a hot reservoir.

In order to operate, a heat engine must reject some of the heat it receives from the high-temperature source to a low-temperature sink.

A heat engine that violates the second law converts 100 percent of this heat to work. This is physically impossible. This heat engine violates the second law of thermodynamics.

The second law can also be stated as no heat engine can have a thermal efficiency of 100 percent.

The thermal efficiency of a heat engine is defined as the ratio of the work output to the heat input:

Clearly, if the thermal efficiency of a heat engine is 100 percent,

Qin=Wout

If the second law precludes a heat engine from having a thermal efficiency of 100 percent. A heat engine is a device that converts a portion of the heat supplied to it from a high-temperature source into work. The remaining heat is rejected to a low-temperature sink.

Therefore:

A heat pump absorbs 100 J of heat from a cool reservoir and releases 120 J of heat to a hot reservoir.

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The 0.500 kg wheel of radius and moment of inertia of 40 cm and 0.200 kg•m² has an acceleration of approximately 2.803 m/s², and a tension of 3.5035 N

The moment of inertia of a body determines the torque that produces a specified angular acceleration.

Using the linear and rotational form of Newton's second law of motion, we have;

\( \sum F_{x} = m \cdot \: a_{x}\)

\( \sum F_{y} = m \cdot \: a_{y}\)

\( \sum \tau_{z} = I_z \cdot \: a_{z}\)

From the above equations, we have;

\( \sum F_{x} = m \cdot \: a_{x}\)

Which gives;

T - m•g = -m•a

Where;

T = The tension of the string

m = The mass of the wheel

g = Acceleration due to gravity

a = The linear acceleration of the wheel

\( \sum \tau_{z} = I_z \cdot \: a_{z}\)

\(R \cdot T = I\cdot \alpha _{cm}\)

\(\alpha _{cm} = \frac{a}{R} \)

Which gives;

\(R \cdot T = I\cdot \frac{a}{R}\)

Where;

I = The moment of inertia of the wheel

R = The radius of the wheel

\( \alpha _{cm}\) = The rotational acceleration of the wheel

The given parameters are;

Mass of the wheel, m = 0.500 kg

Radius of the wheel, R = 40 cm = 0.4 m

Moment of inertia of the wheel, I = 0.200 kg•m²

Which gives;

T - m•g = -m•a

T = m•g - m•a

\( T = I\cdot \frac{a}{R^2}\)

Which gives;

\( I\cdot \frac{a}{R^2} = m \cdot g - m\cdot a \)

\( I\cdot \frac{a}{R^2} + m\cdot a = m \cdot g \)

\( a \cdot \left(\frac{I}{R^2} + m \right) = m \cdot g \)

Therefore;

\( a = \frac{m \cdot g}{ \left(\frac{I}{R^2} + m \right)} \)

Which gives;

\( a = \frac{0.5 \times 9.81}{ \left(\frac{0.2}{0.4^2} + 0.5 \right)} \approx 2.803 \)

The tension, T = m•g - m•a

Which gives;

T ≈ 0.5 × 9.81 - 0.5 × 2.803 ≈ 3.5035

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After considering all the given data we come to the conclusion that the tension in each cable is 122.6 N

The tension in each of the cables can be evaluated applying  the formula
T = mg
Here,
T = tension in the cable,
m = mass of the object
g = acceleration due to gravity.
For the given case, the mass of the loudspeaker is 25.0 kg and g is approximately 9.81 m/s².
Since each cable makes equal angles with the ceiling, we can consider that each cable carries half of the weight of the loudspeaker.
Hence, we can evaluate the tension in each cable as follows:
T = (1/2)mg
T = (1/2)(25.0 kg)(9.81 m/s²)
T = 122.6 N
Therefore, the tension in each of the cables is approximately 122.6 N.
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To continue testing his hypothesis, Neil should repeat the experiment, but only wait 20 seconds before testing the comb's attractive effects.

In a controlled experiment, all other factors are held constant with the exception of one. One or more other groups are studied with all conditions being the same as the control group and each other except for one variable. Typically, a collection of data is considered to be the control group, which is often the normal or usual state.

Comparing a control group to an experimental group is a popular form of controlled experiment. The factor being examined is the only difference between the two groups' variables.

A controlled experiment has the benefit of making it simpler to determine whether the results are meaningful.

Imagine you want to know if the type of soil influences how long it takes a seed to germinate and you choose to conduct a controlled experiment to find out. Five similar pots might be used, each filled with a different kind of soil, and each with identical bean seeds. The pots could then be placed in a sunny window, watered equally, and the time it takes for the seeds in each pot to sprout could be recorded.

This is a controlled experiment because the only variable that will change is the kind of soil you use. You are in charge of these options.

Here in given case Neil's goal is to find out how quickly charge dissipate in humid air. So he should try his hypothesis by varying wait time.

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