An amusement park sold 91 discount tickets and 84 full-priced tickets. What percentage of the tickets sold were discount tickets?

Answers

Answer 1
Total number of tickets = 91 + 84 = 175

Percentage = 91/175 x 100 = 52%
Answer 2

RESPUESTA: 175

Explico:


Related Questions

amelia started with $54, and spent $6 each day at camp. she has $18 left.write and solve an equation that can be used to find in how many days, d she has left at camp.which equation can be used to determine how many days d she was at camp?

Answers

Amelia was at camp for 6 days. The equation used to determine how many days(D) she was at camp is C x D = 6D and S - (C x D) = E

Given data:

S = initial amount = $54

D = the number of days

C = the cost per day = $6

E: the ending amount = $18

Amelia started with S=$54 and spent C=$6 each day at camp.

Therefore, the total amount she spent at camp is given in an algebraic expression that states the product of two variables:

C x D = 6D

Next, she ended with E=$18. So, the equation can be written in algebraic expression that states the difference between the variable:

S - (C x D) = E

Substituting the values in the equation we get:

54 - 6D = 18

54 - 18 = 6D

36 = 6D

D = 6

Therefore, Amelia was at camp for 6 days.

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Consider a standard normal random variable z. What is the value of z if the area to the right of z is 0.3336? Multiple Choice 0.43 0.52 O o 0.35 1.06 O

Answers

Using a standard normal distribution table or calculator, we can find the value of z such that the area to the right of z is 0.3336.

Looking up the value of 0.3336 in a standard normal distribution table, we find that the corresponding z-value is approximately 0.44.

Therefore, the answer is 0.43 (closest option).

Therefore, the value of z when the area to the right of z is 0.3336 is approximately 0.43.

Consider a standard normal random variable z. If the area to the right of z is 0.3336, the value of z can be found using the standard normal distribution table. The standard normal distribution table gives the area to the left of a given z-score. Since we are given the area to the right of z, we subtract 0.3336 from 1 to get the area to the left of z. This gives us an area of 0.6664 to the left of z on the standard normal distribution table. The closest value of z that corresponds to this area is 0.43. Therefore, the value of z when the area to the right of z is 0.3336 is approximately 0.43. The value of z, when the area to the right of z is 0.3336, is approximately 0.43.

Therefore, the value of z when the area to the right of z is 0.3336 is approximately 0.43.

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The sides of a rectangle are x and 3 - 2x. Express the rectangle's area as a function of x. Express the rectangle's perimeter as a function of x. Explain why x cannot equal 2.​

Answers

Answer: It is 3.5

Step-by-step explanation:

I think this because 2/2x=3/2=1.5 but you have 2 left to add which=3.5

A stone is thrown into a pond. A circular ripple is spreading over the pond in such a way that the radius is increasing at the rate of 6.4 feet per second. Find a function, r(t), for theradius in terms oft. Find a function, A(r), for the area of the ripple in terms of r. Find (A or) (t).

A stone is thrown into a pond. A circular ripple is spreading over the pond in such a way that the radius

Answers

SOLUTION

From the question, the r is increasing at the rate of 6.4 feet per seconds.

This means that the equation of the radius is

\(r=6.4\times t\)

So the function for the radius, in terms of t becomes

\(r(t)=6.4t\)

The Area A is given as

\(A=\pi r^2\)

So, the function for the area in terms of r becomes

\(A(r)=\pi r^2\)

Now, (A . r)t becomes

\(\begin{gathered} (A.r)t=\pi r^2,\text{ where r\lparen t\rparen = 6.4t, we have } \\ (A.r)t=\pi\times(6.4t)^2 \\ =40.96\pi t^2 \end{gathered}\)

Hence the answer is

\((A.r)t=40.96\pi t^2\)

The 3rd option is the answer

what's the value of x ?
\( {x}^{2} = 36\)

Answers

Answer:

\(x = \sqrt{36} = 6\)

Hope it helps

Have a good day Ahead

What fraction of 200 gallons is 171 L? Give your answer in simplest form. 1 gallon = 4.5 L.

WHOEVER CAN ANSWER THIS CORRECT FIRST I WILL MAKE A BRAINLIST

Answers

Answer:

757.08 is your answer

Step-by-step explanation:

Hope this helped!

Sorry for not answering sooner :(

Problem 2: Find a general solution for the following recurrence equation: Qn-1 +5Qn-2+3Qn-3+3". Show your work, clearly marking all steps of the solution. Hint: The characteristic polynomial factors into (x + 1)(x - 3).

Answers

The general solution of the given recurrence equation is Qn = (-1/4)(-1)n + (1/4)n(-1)n + (1/2)(3)n.

The given recurrence equation is

Qn-1 + 5Qn-2 + 3Qn-3 = 3

Let's find the characteristic equation of the given recurrence equation:

By assuming Qn = rn,

the characteristic equation can be derived as:

r3 - r2 - 5r - 3 = 0

So, the characteristic polynomial is

(r + 1)(r - 3)2

Let α = -1 and β = 3 (repeated roots)

Now, the solution of the given recurrence equation is:

Qn = Arn + Bnαn + Cnβn

As α = -1 and β = 3 are the roots of the characteristic equation, substitute these values in the above equation.

We have

A(-1)n + Bn(-1)n + Cn(3)n ... (1)

As we are going to find the general solution of Qn, the constants A, B, and C need to be determined.

Let's solve for A, B, and C by considering the first few terms of the given recurrence equation.

Suppose n = 3 in the recurrence equation Qn-1 + 5Qn-2 + 3Qn-3 = 3, we have

Q2 + 5Q1 + 3Q0 = 3 ... (2)

Now, substitute n = 2 in the general solution (1), we have

Q2 = A(-1)2 + B2(-1)2 + C23 ... (3)

Now, substitute n = 1 in the general solution (1), we have

Q1 = A(-1)1 + B1(-1)1 + C31 ... (4)

Now, substitute n = 0 in the general solution (1), we have

Q0 = A(-1)0 + B0(-1)0 + C30 ... (5)

Now, let's solve for A, B, and C using equations (2), (3), (4), and (5).

Q2 + 5Q1 + 3Q0 = 3:

2A + 5B + 3C = 3A(-1)2 + B2(-1)2 + C23:

A - B + 9C = 3A(-1)1 + B1(-1)1 + C31:

-A - B + 3C = 1A(-1)0 + B0(-1)0 + C30:

A + B + C = 1

On solving the above equations,

we get A = -1/4, B = 1/4, and C = 1/2

So, the general solution of the given recurrence equation is  

Qn = (-1/4)(-1)n + (1/4)n(-1)n + (1/2)(3)n

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PLEASE HELP!!! ILL GIVE BRAINLIEST
A map of a highway has a scale of 2 inches=33 miles. The length of the highway on the map is 8 inches. There are 17 rest stops equally spaced on the​ highway, including one at each end. You are making a new map with a scale of 1 inch=30 miles . How far apart are the rest stops on the new​ map?
How many inches apart are the rest stops?

Answers

Answer:

Step-by-step explanation:

Step-by-step explanation:

2/33=6/xx=99since there are 11 rest stops and you are trying to find the space in the middle of the two rest stops. 99/11 rest stops9 miles in between rest stops9/y=30/19/30=y3/10=y.3 inches=yHope that helps :)

Answer:

Step-by-step explanation:

i have the same question\

what place does the three sit at in 43,628,698,591

Answers

Answer:

Billion

Step-by-step explanation:

In 43,628,698,591 the three is in the Trillion spot.

One, Ten, Hundred, Thousand, Ten Thousand, Hundred Thousand, Million, Ten Million, Hundred Million, Billion.

There are 9 #’s after the 3 which means it is billions :)

How many litres can be held by a cylindrical can 14cm in diameter and 20cm hight?

Answers

Answer:

  about 3.08 L

Step-by-step explanation:

You want the number of litres in the volume of a cylindrical can 14 cm in diameter and 20 cm high.

Liters

A litre is a cubic decimeter, 1000 cubic centimeters. As such, it is convenient to perform the volume calculation using the dimensions in decimeters:

14 cm = 1.4 dm . . . . . . diameter20 cm = 2.0 dm . . . . . height

Volume

The volume of the cylinder is given by the formula ...

  V = (π/4)d²h . . . . . . . where d is the diameter and h is the height

  V = (π/4)(1.4 dm)²(2.0 dm) ≈ 3.079 dm³ ≈ 3.08 L

The cylindrical can will hold about 3.08 litres.

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How many litres can be held by a cylindrical can 14cm in diameter and 20cm hight?

-12 - 12x = 36 please help me with this problem due today.​

Answers

Answer:

x = -4

Step-by-step explanation:

-12 -12x = 36

add 12 to each side of the equation

-12x = 48

divide both sides by -12

x = -4

The ones digit in the cube of 529 is??

Answers

Answer:9

Step-by-step explanation: 529 x 529 x 529=

148035889

Kaj goes out to lunch. The bill, before tax and tip, was $17.35. A sales tax of 4% was added on. Kaj tipped 22% on the amount after the sales tax was added. How much tip did she leave? Round to the nearest cent.

Answers

$22.01 (final answer)

1.04 *17.35=18.044
1.22*18.044=(rounded) 22.01

Think of (*) as “of” (example below)

So 1.04 (4%) OF $17.35 is $18.04

Suppose Q and R are independent events. Find P(Q and R). P(Q)=0.37,P(R)=0.24

Answers

To find P(Q and R), we can use the formula: P(Q and R) = P(Q) × P(R) Since the events Q and R are independent, we can multiply the probabilities of each event to find the probability of both events occurring together. P(Q) = 0.37P(R) = 0.24P(Q and R) = P(Q) × P(R) = 0.37 × 0.24 = 0.0888.

Therefore, the probability of both Q and R occurring together is 0.0888. Long Answer:Independent events:In probability theory, two events are independent if the occurrence of one does not affect the probability of the occurrence of the other. Two events A and B are independent if the probability of A and B occurring together is equal to the product of the probabilities of A and B occurring separately. Mathematically,P(A and B) = P(A) × P(B) Suppose Q and R are independent events. Find P(Q and R).

We can use the formula: P(Q and R) = P(Q) × P(R) Since the events Q and R are independent, we can multiply the probabilities of each event to find the probability of both events occurring together. P(Q) = 0.37P

(R) = 0.24

P(Q and R) = P(Q) × P(R)

= 0.37 × 0.24

= 0.0888

Therefore, the probability of both Q and R occurring together is 0.0888. Hence, P(Q and R) = 0.0888. In probability theory, independent events are the events that are not dependent on each other. It means the probability of one event occurring does not affect the probability of the other event occurring.

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The area of a circular pizza is 2122.64 square centimeters. What is the diameter of the pizza?

Answers

Area of a circle = pi x r^2

---For the purposes of this problem, pi = 3.14

2122.64 = (3.14)(r^2)

676 = r^2

r = 26 cm

Diameter = 2 x radius

diameter = 2 x 26

diameter = 54 cm

Answer: diameter = 54 cm

Hope this helps!

a woman 5-feet tall casts an 8-foot shadow. at the same time of day, the shadow of a tree nearby is 120 feet long. in feet, how tall is the tree?

Answers

A woman 5-feet tall casts an 8-foot shadow. at the same time of day, the shadow of a tree nearby is 120 feet long. in feet, 75 feet  tall is the tree.

Let the tree height = x

From the question, we have

5/8 = x/120

x = (5*120)/8

x = 75 feet

Tree height = 75 feet

Multiplication:

Mathematicians use multiplication to calculate the product of two or more numbers. It is a fundamental operation in mathematics that is frequently utilized in everyday life. When we need to combine groups of similar sizes, we utilize multiplication. The fundamental concept of repeatedly adding the same number is represented by the process of multiplication. The results of multiplying two or more numbers are known as the product of those numbers, and the factors that are multiplied are referred to as the factors. Repeated addition of the same number is made easier by multiplying the numbers.

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If the dimensions of a triangle are cut in ____, then the new perimeter is one-fourth of the original perimeter.

1. half
2. thirds
3. fourths

Answers

Answer:

Fourths

Step-by-step explanation:

If all the sides of the triangle added together is equal to P, then the sides of the new triangle would be P/4. Therefore the answer would be fourths.

find the taylor series for f centered at 5 if f(n)(5) = e5 14 for all n.

Answers

The Taylor series for the function f centered at 5 is given by f(x) = \(e^5\) + (x - 5)\(e^5\) + (1/2!)\((x - 5)^2\)\(e^5\) + (1/3!)\((x - 5)^3\)\(e^5\) + ...

The Taylor series expansion of a function f(x) centered at a point a is given by the formula:

f(x) = f(a) + f'(a)(x - a) + (1/2!)f''(a)\((x - a)^2\) + (1/3!)f'''(a)\((x - a)^3\) + ...

In this case, we are given that f(n)(5) = \(e^5\) * 14 for all n. This implies that all the derivatives of f at x = 5 are equal to \(e^5\) * 14.

Therefore, the Taylor series for f centered at 5 can be written as:

f(x) = f(5) + f'(5)(x - 5) + (1/2!)f''(5)\((x - 5)^2\) + (1/3!)f'''(5)\((x - 5)^2\) + ...

Substituting the given values, we have:

f(x) = \(e^5\) * 14 + (x - 5)\(e^5\) * 14 + (1/2!)\((x - 5)^2\)\(e^5\) * 14 + (1/3!)\((x - 5)^3\)\(e^5\) * 14 + ...

Therefore, the Taylor series for f centered at 5 is given by the above expression.

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Which expression is equivalent to m 2 - 13 m -30?

Answers

Answer:

=−13m−28

Step-by-step explanation:

Let's simplify step-by-step.

2−13m−30

=2+−13m+−30

Combine Like Terms:

=2+−13m+−30

=(−13m)+(2+−30)

=−13m+−28

how many multiples of $9^3$ are greater than $9^4$ and less than $9^5$?

Answers

There are 72 multiples of 9³ that are greater than \(9^4\) and less than \(9^5\).

We have,

The values of 9³, \(9^4\), and \(9^5\):

9³ = 729

\(9^4\) = 6561

\(9^5\) = 59049

Now,

The multiples of 729 that fall within the range (6561, 59049).

The number of multiples can be calculated as follows:

Multiples = (Highest value ÷ Divisor) - (Lowest value ÷ Divisor)

= (59049 ÷ 729) - (6561 ÷ 729)

= 81 - 9

= 72

Therefore,

There are 72 multiples of 9³ that are greater than \(9^4\) and less than \(9^5\).

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Please do it with step by step explanation it will help me so much thanks!

Carolyn is searching online for tickets to a concert. Two weeks ago, the cost was $30. Now the cost is $39.
a. What is the percent increase?
b. What would be the percent increase if the ticket agent charges an additional $4.50 fee with the new ticket price?

Answers

Answer:

A) The percent increase is by 30%.

B) for the original price = 15%.

B2.0) for the existing price (39) = approximately 11.54%.

Step-by-step explanation:

A) First, we divide 30 by 100. The result is the amount that 1% would be(0.3). If you multiply it by 30(which will become 30%) it will be 9. And from 30-39 is 9.

B) First we divide 30 by 100. The result is the amount that 1% would be(0.39). then if you multiply it by 11.54(which will become 11.54%) it will be 4.50(approximately because it actually is 4.5006 and there is no amount that ends up in 4.50). But if you are asking what percentage from the original cost(30) it would be 15% of it(because 0.3 * 15 = 4.50).

How do you simplify and verify trig identities?

Answers

In order to simplify and verify trig identities, one needs to use the rules of trigonometry and algebra to manipulate the equation until it is in a simplified form.

The most common trig identities to remember include the Pythagorean identity, reciprocal identities, quotient identities, and sum and difference identities. When simplifying an equation, it is important to remember to include the negative sign when necessary and to factor out any common factors.

After simplifying, it is important to verify the equation. This can be done by plugging in known values for the variables and verifying that the equation is true. By utilizing the rules of trigonometry and algebra, one can simplify and verify trig identities. This process is essential for working with trigonometric functions.

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The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $4 and each adult ticket sells for $8.50. The auditorium can hold at most 79 people. The drama club must make no less than $460 from ticket sales to cover the show's costs. If 53 student tickets were sold, determine the minimum number of adult tickets that the drama club must sell in order to meet the show's expenses.

Answers

Answer:

79 people can only be in this so we have 53 kids so 53 * 4 = 212

Step-by-step explanation:

However, there is 53 kids to find how many adults you will have to do 79 - 53 which that = 26 so 26 adults were there. so 26 * 8.50 = 221.

To fine how much money they earn you will just have to add them up so

$212 + $ 221 = $433 so they didn't really earn the amount of money they really want which is $ 460.

Thus the minimum number of adult tickets that the drama club must sell in order to meet the show's expenses is 29 tickets.

Given,

The drama club is selling tickets to their play to raise money for the show's

expenses.

Each student ticket sells for $4 and each adult ticket sells for $8.50.

The auditorium can hold at most 79 people.

The drama club must make no less than $460 from ticket sales to cover

the show's costs.

If 53 student tickets were sold, determine the minimum number of adult

tickets that the drama club must sell in order to meet the show's expenses.

How to find the number of items from a total cost where each item cost is the same?

We will divide the total cost by the cost of each item.

Example:

Cost of each item = $3

Total cost = $9

Number of items = $9 / $3 = 2

We have,

Student ticket:

Cost of each ticket = $4

Number of tickets sold = 53

Total sell from student tickets sold = 53 x $4 = $212

Adult ticket:

Cost of each ticket = $8.50

Number of adult tickets sold = M

Total sell of adult tickets sold = M x $8.50

Total number of people the auditorium can hold = 79

Minimum amount to make from ticket sales = $460

The remaining amount that needs to sale from adult tickets:

= $460 - $212

= $248

The number of adult tickets sold:

M = $248 / $8.50 = 29

Thus the minimum number of adult tickets that the drama club must sell in order to meet the show's expenses is 29 tickets.

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I used a tutor for this and the answer I was given is 50.2. Which is incorrect. I am trying to understand how to solve.

I used a tutor for this and the answer I was given is 50.2. Which is incorrect. I am trying to understand

Answers

Since you have the hypotenuse and the adjacent length, you have to use the trigonometric ratio cosine to

solve for x. Formulating the equation we have:

\(\begin{gathered} \cos (x)=\frac{\text{ adjacent length}}{\text{hypotenuse}} \\ \cos (x)=\frac{9}{14}\text{ (Replacing the values)} \\ \cos ^{-1}(\cos (x))=\cos ^{-1}(9/14)\text{ (Using the inverse function of cosine)} \\ x\text{ = 49.99}5\text{ (Dividing 9 by 14 and using the inverse function of cosine)} \\ \text{The answer would be 50\degree{}rounded to the nearest integer. } \end{gathered}\)

Given m\\n find the value of x

Given m\\n find the value of x

Answers

Answer:

A big number probably

Step-by-step explanation:

You revived 1/4 pound of candy from your grandmother, 1/2 pound of candy from your sister, and 1/8 pound of candy from your best friend. How many pounds of candy did you receive?

Answers

Answer:

⅞ pound

Step-by-step explanation:

You received 1/4 pound of candy from your grandmother.

You received 1/2 pound of candy from your sister.

You received 1/8 pound of candy from your best friend.

The total amount of candy you received is given as the sum of all the candy that he received from your grandmother sister and best friend.

The total amount of candy is therefore:

¼ + ½ + ⅛ = ⅞ pound

You received ⅞ pound of candy in total.

A class of 28 students had a mean score of 72 on a math test. After the teacher realized that one of the questions had an alternative correct answer, he gave 4 points each to the 7 students who had given the alternative answer. What is the new mean test score?

Answers

Answer:

73

Step-by-step explanation:

The wheels of a car are of radius 40cm each, if the car is travelling at a speed of 66km/h, find the number of revolutions made by each wheel in 20 minutes​

Answers

Answer: Each wheel makes 437.5 revolutions in 20 mins

Step-by-step explanation:

Circumference = 2πr

Given that the radius is 40 cm

Circumference = 2π(40) = 80π cm

Find the distance traveled in 20 mins

Speed = 66 km/h

1 hour = 66 km

Rewrite hour into min

60 min = 66 km

1 min = 66 ÷ 60 = 1.1 km

Rewrite km in cm

1.1 km = 1.1 x 10,000 cm = 110,000 cm

Find the number of revolutions in 20 mins:

1 revolution = 80π cm

Number of revolution = 110,000 ÷ 80π = 437.5

Given g(x)=-2x-4, find g(6)

Answers

Answer:

g(6)= -16

Step-by-step explanation:

g(x)= -2x-4

To complete this problem, we must first substitute 6 for x.

g(6)= -2(6)-4

We can now solve.

g(6)= -12-4

g(6)= -16

possible points: 7.14 question the student council is selecting officers for the next school year from the 7 freshmen, 4 sophomores, and 6 juniors that are running for the 5 officer positions available. at least three officers must be juniors. how many different possibilities are there for the 5 different officer positions?

Answers

The 5 separate possibility that officer seats may be filled in 336 different ways.

7 + 4 + 6 = 17 students are running for the 5 officer positions. If at least 3 of the 5 positions must be filled by juniors, there are 6 ways to choose which 3 juniors will fill these positions.

Then there are 7 + 4 - 3 = 8 remaining students 3 juniors and 5 from the remaining sophomores and freshmen to fill the remaining 2 positions.

There are 8 ways to choose the first of these 2 positions and 7 ways to choose the second, so there are a total of 6 × 8 × 7 = 336 ways to choose the officers.

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Part 1: Develop an IP Addressing Scheme (20 points, 25 minutes) Part 2: Initialize and Reload Devices (10 points, 20 minutes) Part 3: Configure Device IP address and Security Settings (45 points, 35 minutes) Part 4: Test and Verify IPv4 and IPv6 End-to-End Connectivity ( 15 points, 20 minutes) Part 5: Use the IOS CLI to Gather Device Information ( 10 points, 10 minutes) Scenario In this Skills Assessment (SA) you will configure the devices in a small network. You must configure a router, Switch and PCs to support both IPv4 and IPv6 connectivity. You will configure security, including SSH, on the router. In addition, you will test and document the network using common CLI commands. Required Resources Implement in Packet tracer using the following resources: - 1 Router (Cisco 4221 with Cisco IOS XE Release 16.9.4 universal image or comparable) - 1 Switch (Cisco 2960 with Cisco IOS Release 15.2(2) lanbasek9 image or comparable) - 2 PCsi - Console cables to configure the Cisco los devices via the console ports - Ethernet cables as shown in the topology Instructions Part 1: Develop an IP Addressing Scheme Total points: 20 Time: 25 minutes a. Subnet one network belowifyour choice)to provide IP addresses to two subnets that will support the required number of hosts. No subnet calculators may be used. All work must be shown using the IP Addressing worksheet below. IP Addressing Worksheet b. Record your subnet assignment in the table below. 1) Assign the first IPv4 address of each subnet to a router interface (i) subnet A is hosted on R1G/O/1 (ii) subnet B is hosted on R1GO/0/0 To calculate profit, producers subtract their total production cost from theirtotal revenuemarginal revenuemarginal Posttotal units produced 2. a. Which of the following best describes the Nun (the Prioress) in the Prologue from The Canterbury Tales? well educated and wise b. friendly and fun loving c. refined and sentimental d. strong and outspoken SOMEONE PLEASE HELP MEEE