An airplane is flying at a velocity of 122.4 m/s. It is getting ready to land so it slows down by accelerating at a rate of -2.8 m/s^2.
What will its new velocity be after 2.6 seconds?

TheThe charge applied on each ball is 2 X 10∧-9 C.

An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

The pitch balls repent each other with force

F= 4 X 10^-5N

Let the charge on each ball be Q.

4 X 10^-5= k(Q)(Q) /  (3 X 10^-2)^2

Q^2= 4*10^-5X 9*10^-4 / 9*10^9

Q^2 = 4 X 10^-18

Q= √4 X 10^-18

Q = 2 X 10^-9 C.

Therefore, the charge on each ball is 2X10^-9C.

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Each ball has been charged with 2 X 10⁹ C. When a product is held in electrostatic energy, its properties referred to as electric discharge allows it to feel force.

A force can compel a heavily armored item to increase or modify overall velocity. A push or a pull is a simple and effective method to explain force. That's because a force has both magnitude and direction it is a dimensionless number.

The pitch balls repent each other with force

F = 4 X 10⁻⁵N

4 X 10⁻⁵ = k(Q)(Q) /  (3 X 10⁻²)²

⇒ Q²      = 4 × 10⁻⁵ X   9 × 10⁻⁴ / 9 × 10⁹

⇒ Q²      = 4 X 10⁻¹⁸

⇒ Q        = √4 X 10⁻¹⁸

⇒ Q        = 2 X 10⁻⁹ C.

Therefore, the charge on each ball is 2 X 10⁻⁹C.

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After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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The bus resultant displacement is approximately 4.14 km at an angle of 59.5 degrees north of east.

The first movement is 2 km due east, which means it has an x-component of 2 km and a y-component of 0 km.

The second movement is 5 km at 45 degrees north of east. This can be broken down into x and y components using trigonometry: x = 5 km * cos(45) = 3.54 km y = 5 km * sin(45) = 3.54 km

The third movement is 4 km at 30 degrees north of west. This can also be broken down into x and y components using trigonometry: x = -4 km * cos(30) = -3.46 km (negative because it’s towards the west) y = 4 km * sin(30) = 2 km

The fourth movement is 2 km due south, which means it has an x-component of 0 km and a y-component of -2 km.

Adding up all the x and y components, we get: x_total = 2 + 3.54 + (-3.46) + 0 = 2.08 km y_total = 0 + 3.54 + 2 + (-2) = 3.54 km

The magnitude of the resultant displacement can be calculated using the Pythagorean theorem: resultant_displacement = sqrt(x_total^2 + y_total^2) = sqrt(2.08^2 + 3.54^2) ≈ 4.14 km

The direction of the resultant displacement can be calculated using the arctan function: direction = arctan(y_total / x_total) ≈ 59.5 degrees north of east

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The magnitude of the masses in planes B and E is 40 kg, and their positions are 120° and 240°, respectively, from the reference point on the shaft to achieve complete rotating balance.

To achieve complete rotating balance, the sum of the moments of the masses in planes A, C, D, B, and E should be equal to zero. Let's determine the magnitude of the masses in planes B and E and their positions.

Consider the moments of the masses in planes A, C, and D. The moment of a mass is given by the product of its magnitude and the sine of the angle between the mass and a reference line. The moments of masses A, C, and D are:

Moment of A = 50 kg * sin(0°) = 0 kg·m,

Moment of C = 40 kg * sin(90°) = 40 kg·m,

Moment of D = 80 kg * sin(135°) = -80 kg·m.

Since the moments of A, C, and D are known, we can use the principle of complete rotating balance to determine the magnitude and position of the masses in planes B and E.

Let's assume the magnitude of the masses in planes B and E as M. The moments of masses B and E can be represented as:

Moment of B = M * sin(120°) = M * √(3)/2,

Moment of E = M * sin(240°) = -M * √(3)/2.

Using the principle of complete rotating balance, the sum of the moments should be zero. Thus, we have:

Moment of A + Moment of C + Moment of D + Moment of B + Moment of E = 0.

0 + 40 kg·m + (-80 kg·m) + M * √(3)/2 + (-M * √(3)/2) = 0.

Simplifying the equation:

40 kg·m - 80 kg·m + M * √(3)/2 - M * √(3)/2 = 0,

-40 kg·m = 0.

From the equation, we can deduce that M must be equal to 40 kg to satisfy the condition of complete rotating balance.

Finally, we determine the positions of masses B and E. Since planes A, C, D, B, and E are equidistant from one another, and the angle between A and C is 90°, we divide the circle into 360°/5 = 72° sections. Thus, the positions of masses B and E are:

Position of B = 0° + 2 * 72° = 144°,

Position of E = 0° + 4 * 72° = 288°.

Therefore, the magnitude of the masses in planes B and E is 40 kg, and their positions to put the shaft in complete rotating balance are 144° and 288°, respectively, from the reference point on the shaft.

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Answer:

V = mRT /  (\(\frac{\pi }{4}\)d²)PM

Therefore, pressure decreases as velocity increases.

This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.

Explanation:

Given the data in the question;

we know that an ideal gas equation is;

\(_p\) = PM/RT --------------- let this be equation 1

P is pressure, M is molecular weight, R is universal gas constant and T is the absolute temperature.

The volumetric flow rate from the continuity equation is;

Q = AV

and A =  \(\frac{\pi }{4}\)d²

so, Q = (\(\frac{\pi }{4}\)d²)V ---------let this be equation 2

Expression for mass m in flowrate is;

m = Q\(_p\) ------------------let this be equation 3

so, m = (\(\frac{\pi }{4}\)d²)V × PM/RT

solve for V

V = mRT /  (\(\frac{\pi }{4}\)d²)PM

Therefore, pressure decreases as velocity increases.

This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.

n unit vector notation, -22j is the torque about the origin on a particle located at coordinate (o, -4.0m, 3.0m)


Torque is defined as the force that can cause an object to rotate along an axis is measured as torque. Estimate the angle between the vector connecting the force's application point and the pivot point and the direction of the applied force. You may calculate the torque by multiplying r by F and sin.

T=R (distance) x F (Force)

R=-4j+3k

F=2J

Hence, t=  R x F vector product

=(-4j+3k)x2j

=-4x2x(y x J)

=+3x2y(k x r)

=-8x(-k)+6j

=(6j+8k) nm

b) F^2=2J+4K

Hence, t=r x f^2

=(-4j+3k)x(2j+4k)

=0-16( J x k)+6(K x J)+0

=-16j-6j

=-22j  

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Answer:

Because it kills people. I have had 6 relatives who have died from it in the past 2 years. It's horrible.

Explanation:

If you're wondering what causes cancer, it is rapid and uncontrollable cell regeneration. The majority of cancers result from random mutations arising during DNA replication in the normal stem cells required during development and tissue maintenance.

Explanation:

Cancer kills by invading key organs such as

the intestines, lungs, brain, liver, and kidneys. cancer interfers with body functions that are necessary to live.

Answer:

10m/s2

Explanation:

250/25=10

Answer:

h = 69.6 m

Explanation:

Data:

Formula:

Replace and solve:

The building has a height of 69.6 meters.

Greetings.

Answer:

The speed of the second toy car after collision is \(v_2 = 0.155 \ m/s\)

Explanation:

Let movement to the right be positive and the opposite negative

From the question we are told that

   The mass of the car is  \(m_1 = 15 \ g = \frac{15}{1000} = 0.015 \ kg\)

    The initial velocity of the car is  \(u_1 = 24 \ cm /s = 0.24 m/s\)

    The mass of the second toy car  \(m_2 = 21 g = 0.021 \ kg\)

    The initial velocity of the car is \(u_2 = 31 \ cm/s =- 0.31 m/s\)

    The final velocity of the first car is  \(v = 41cm/s = - 0.41 m/s\)

     From law of momentum conservation we have that

     \(m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2\)

substituting values

       \((0.015* 0.24) +( 0.021 * -0.31) = (0.015 * -0.41 ) + 0.021 v_2\)

      \(-0.00291 = -0.0615 + 0.021 v_2\)

      \(v_2 = 0.155 \ m/s\)

Suspending the balloons near each other and observing which way they deflect

Suspending each balloon near the material it was not rubbed on and seeing which way it deflects

An object can be charged by friction. When two objects are rubbed against each other, electrons can be transferred from one object to the other, resulting in one object becoming positively charged and the other becoming negatively charged. This is known as the triboelectric effect.

We know that if the objects do have the same charge then they will deflect away from each other but towards each other if they have opposite charges.

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The greater the density of the electric field lines the stronger the electric field and vice versa

Electric field can be defined as the region where an electric force is experienced by a charged body. A charged body experiences a force whenever it is positioned close to another charged body.

An electric field may be described in terms of lines of force which represent the direction of a small positive charge placed at that point assuming that the charge is so small that it does not change appreciably in the presence of another charge.

The lines of force are indicated in such a way that the strength of the electric field is shown by the number or density of electric field lines crossing a unit area perpendicular to the lines.

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The chosen sport for this assignment is cricket, which is played in South Asian countries like  India, Pakistan, Australia, England, and South Africa.  The game is played with 11 players on each team, using a cricket ball and a bat, and the objective is to score more runs than the other team. it is not popular in the U.S. but will grow popular. Beginners should focus on learning proper techniques.

For this assignment, let's say I choose cricket. I have knowledge about cricket due it's popularity. Cricket is most popular in countries like India, Pakistan, Australia, England, and South Africa. Cricket is a team sport played with two teams consisting of 11 players each. The equipment used in cricket includes a ball, bat, stumps, and protective gear.

The basic objective of the game is to score more runs than the opposing team. The team that bowls tries to dismiss the batsmen by getting them out. Each team takes turns batting and fielding. The game consists of overs, which are six balls bowled by one team. The team with the most runs at the end of the match wins.

It's hard to say whether cricket will become more popular in the U.S. due to the dominance of traditional American sports. However, with the increasing popularity of T20 cricket and the formation of the Major League Cricket, it may gain more popularity.

For someone considering playing cricket, it would be helpful to watch matches, join a local cricket club or league, and practice basic skills like batting, bowling, and fielding.

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a) To determine if the car will hit the object before coming to a stop, we need to calculate the distance required to stop the car, assuming maximum braking deceleration. We can use the following formula:

d = (v^2) / (2a)

where:

d = distance required to stop

v = initial velocity

a = acceleration/deceleration

In this case, v = 100 km/h = 27.78 m/s (converted from km/h to m/s)

a = -7 m/s^2 (negative sign indicates deceleration)

We know that the car's headlights extend out to a range of 30 m, so if the distance required to stop the car is greater than 30 m, the car will hit the object before coming to a stop.

Plugging in the values to the formula, we get:

d = (27.78^2) / (2 x -7) = 108.61 m

Since 108.61 m is greater than 30 m, the car will hit the object before coming to a stop.

b) To calculate the time required to stop, we can use the following formula:

t = v / a

where:

t = time required to stop

v = initial velocity

a = acceleration/deceleration

Plugging in the values, we get:

t = 27.78 / 7 = 3.97 s

Therefore, it will take 3.97 seconds to stop the car.

The final area of the plate is 4.0000352 \(m^2\) if the temperature raised to 100 °C and the coefficient of linear expansion of iron is 1.1 x 10-7.

Expecting that the plate of iron is rectangular, we can involve the recipe for warm extension of solids to compute the last region of the plate. The equation for direct warm development is given by ΔL = αLΔT, where ΔL is the adjustment of length, α is the coefficient of straight extension, L is the first length, and ΔT is the adjustment of temperature.

Since the region of the plate is given by A = L*W, where L is the length and W is the width, we can involve the equation for straight warm extension to compute the adjustment of length of the plate and afterward use it to compute the last region.

ΔL = αLΔT = \((1.1 x 10^-7 m/oC)(2 m)(80 oC) = 1.76 x 10^-5 m\)

The last length of the plate is L + ΔL = 2 m + 1.76 x \(10^-5\) m = 2.0000176 m (approx.)

The last width of the plate is thought to be unaltered as it isn't impacted by the adjustment of temperature.

Thusly, the last region of the plate is A = L*W = (2.0000176 m)(2 m) = 4.0000352 \(m^2\) (approx.)

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The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

To find the power dissipated in resistor R4, use the formula:

P = I² × R

where P = power, I = current flowing through the resistor, and R = resistance of the resistor.

The total resistance, Rt, can be calculated using the formula:

1/Rt = 1/R1 + 1/R2 + 1/R3

Substituting the given values:

1/Rt = 1/3 + 1/0.8 + 1/2

Simplifying the equation:

1/Rt ≈ 1.6667

Rt ≈ 0.6 Ω

Next, calculate the total voltage, Vt, by summing the individual voltage sources:

Vt = ε1 + ε2 + ε3

Substituting the given values:

Vt = 9 + 6 + 4

Vt = 19 V

Now calculate the current flowing through resistor R4 using Ohm's Law:

I = Vt / Rt

Substituting the calculated values:

I = 19 / 0.6

I ≈ 31.6667 A

Finally, calculate the power dissipated in resistor R4:

P = I² × R4

Substituting the calculated values:

P = (31.6667)² × 10

P ≈ 10,028 W

Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.

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Answer:

a. True

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission.

Sound travels faster through solids than it does through either liquids or gases. A student could verify this statement by measuring the time required for sound to travel a set distance through a solid, a liquid, and a gas.

Mathematically, the speed of a sound is given by the formula:

\( Speed = wavelength * frequency \)

Generally, the frequency of a sound wave determines the pitch of the sound that would be heard.

Diffraction occurs for all types of waves, including sound waves.

Answer:show me the graph please so i can help you

Explanation:

Invert level of the stilling basin should be at el. 101.654 m to form a hydraulic jump.

Manmade lake that is created when a dam is built on a river is called reservoir.

Total energy at the upstream of the spillway is: E₁ = z₁ + (v1² / 2g) + (P₁/ γ)

z₁ is elevation of upstream reservoir level, v₁ is velocity of flow approaching the spillway, P₁ is the pressure at the upstream of spillway, γ is the specific weight of fluid

Velocity of flow approaching the spillway can be calculated using the continuity equation: Q = A₁ * v₁

Q is flow rate (800 m³/s) and A₁ is cross-sectional area of flow at the upstream of the spillway (width x depth).

Total energy at the downstream of spillway is: E₂ = z₂ + (v₂² / 2g) + (P₂ / γ)

z₂ is elevation of downstream river level, v₂ is velocity of flow downstream of spillway, and P₂ is pressure at the downstream of spillway.

x = 4.14 * Q² / (g²* B * h₁³)

where B is width of spillway (30 m), and h1 is the upstream depth of flow at the spillway.

The depth of flow downstream of the hydraulic jump can be calculated as:

h₂ = (1/2) * (h₁ + h₃)

where h₃ is depth of flow in the stilling basin.

The total energy at the downstream of the hydraulic jump is:

E₃ = z₂ + (v₃² / 2g) + (P₂ / γ)

where v₃ is the velocity of flow downstream of the hydraulic jump.

The total energy at upstream of the stilling basin is:

E₄ = z1 + (v₄² / 2g) + (P₁/ γ)

where v4 is the velocity of flow approaching the stilling basin.

We can assume that the total energy at the downstream of the hydraulic jump (E₃) is equal to total energy at the upstream of the stilling basin (E4):

E₃ = E₄

z₂ + (v₃² / 2g)

E₃ = z₂ + (v₃² / 2g) + (P₂ / γ)

E₄ = z₁ + (v₄² / 2g) + (P₁ / γ)

z₂ = 100 m (given)

P₂ = P₁ (both atmospheric pressure)

v₃ = Q / (B * h₃)

h₃ = (5/2) * h1

v₄ = v₃ + 2g(h₃ - h₄)

h₄ = h₃ - (v₃² / 2g * (1 + (v₃ / √(g * h₃))²))

h₄ = 1.654 m

Therefore, the invert level of the stilling basin is:

el. = z₂ + h₄ = 101.654 m

So, the invert level of the stilling basin should be at el. 101.654 m to form a hydraulic jump.

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Answer:

C 2000v its obviously ans because if o is 1000 2 vo is 2000v

Answer:

3 tens

Explanation:

The value

of 3 in 24.635 is at 3 tens place as the place is two to the left.

The correct answer to the given is question is "0.03".

Let's display the number 24.635 using a place value chart.

Tens -> 2   Ones -> 4   Tenth -> 6   Hundredths -> 3   Thousandths -> 5

The 3 is in Hundredths Place or the value of 3 in 24.635​ is 0.03.

Thus, we can conclude that the value of 3 in 24.635​ is 0.03 after solving the question.

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Answer:

neither will happen

Explanation:

cause the water is already defreezed

Answer:

Therefore, the 10 kg mass should be placed at x = 5.7 m along the x-axis to achieve a center of mass located at y = 4.5 m.

Explanation:

To find the position along the x-axis where a 10 kg mass should be placed such that the center of mass is located at y = 4.5, we can use the formula for the center of mass:

x_cm = (m1 * x1 + m2 * x2) / (m1 + m2)

Here, m1 and x1 represent the mass and position of the 8 kg mass, respectively. m2 is the mass of the 10 kg mass, and we need to find x2, its position.

Given:

m1 = 8 kg

x1 = 3 m

x_cm = unknown (to be found)

m2 = 10 kg

y_cm = 4.5 m

Since the center of mass is at y = 4.5, we only need to consider the y-coordinate when calculating the center of mass position along the x-axis.

To solve for x2, we can rearrange the formula as follows:

x2 = (x_cm * (m1 + m2) - m1 * x1) / m2

Substituting the given values:

x2 = (x_cm * (8 kg + 10 kg) - 8 kg * 3 m) / 10 kg

Simplifying:

x2 = (x_cm * 18 kg - 24 kg*m) / 10 kg

Now, we can set the y-coordinate of the center of mass equal to 4.5 m and solve for x_cm:

4.5 m = (8 kg * 3 m + 10 kg * x2) / (8 kg + 10 kg)

Simplifying:

4.5 m = (24 kg + 10 kg * x2) / 18 kg

Multiplying both sides by 18 kg:

81 kg*m = 24 kg + 10 kg * x2

Subtracting 24 kg from both sides:

10 kg * x2 = 81 kg*m - 24 kg

Dividing both sides by 10 kg:

x2 = (81 kg*m - 24 kg) / 10 kg

Simplifying:

x2 = 8.1 m - 2.4 m

x2 = 5.7 m

(brainlest?) ples:(

Answer:

the 10 kg mass should be placed at x = -2.4 m to achieve a center of mass at y = 4.5 m.

Explanation:

To find the position along the x-axis where the 10 kg mass should be placed so that the center of mass is located at y = 4.5, we can use the principle of the center of mass.

The center of mass of a system is given by the equation:

x_cm = (m1x1 + m2x2) / (m1 + m2),

where x_cm is the x-coordinate of the center of mass, m1 and m2 are the masses, and x1 and x2 are the positions along the x-axis.

Given:

m1 = 8 kg,

x1 = 3 m,

m2 = 10 kg,

y_cm = 4.5 m.

To solve for x2, we need to find the x-coordinate of the center of mass (x_cm) by using the y-coordinate:

y_cm = (m1y1 + m2y2) / (m1 + m2),

where y1 and y2 are the positions along the y-axis.

Rearranging the equation and substituting the given values:

4.5 = (83 + 10y2) / (8 + 10).

Simplifying the equation:

4.5 = (24 + 10*y2) / 18.

Multiplying both sides by 18:

81 = 24 + 10*y2.

Rearranging the equation:

10*y2 = 81 - 24,

10*y2 = 57.

Dividing both sides by 10:

y2 = 5.7.

Therefore, the y-coordinate of the 10 kg mass should be 5.7 m.

To find the x-coordinate of the 10 kg mass, we can use the equation for the center of mass:

x_cm = (m1x1 + m2x2) / (m1 + m2).

Substituting the given values:

x_cm = (83 + 10x2) / (8 + 10).

Since the center of mass is at x_cm = 0 (the origin), we can solve for x2:

0 = (83 + 10x2) / (8 + 10).

Rearranging the equation:

83 + 10x2 = 0.

24 + 10*x2 = 0.

10*x2 = -24.

Dividing both sides by 10:

x2 = -2.4.

Answer: The speed of the moon's rotation keeps the same side always facing Earth.

Explanation: Please mark me brainiest

Answer:

The speed of the Moon's rotation keeps the same side always facing Earth.

Explanation:

got it right on study island :)

2.5 mL of Thallium-201 should be injected to administer a recommended dose of 3.0 mCi.

Thallium-201 is a radioisotope that is used in brain scans to detect brain cancer. It is used in nuclear medicine as a radiopharmaceutical. The recommended dose for Thallium-201 is 3.0 mCi. If a vial of Thallium-201 contains 60. mCi in 50. mL, we can determine the number of milliliters that should be injected by using proportionality.A proportion can be used to compare two ratios and solve for an unknown value. For example, if x is the unknown value we are trying to solve for and a/b and c/d are two ratios that are equal, we can write a proportion:

a/b = c/d.

Cross-multiplying gives us the equation

ad = bc.

This formula can be used to solve for the unknown value x. For this problem, we can use a proportion to solve for the number of milliliters that should be injected. Let x be the number of milliliters that should be injected. Then we have the following ratio:

3.0 mCi / x mL = 60. mCi / 50. mL

To solve for x, we can cross-multiply:

3.0 mCi * 50. mL = 60. mCi * x mL150. mCi mL = 60. mCi x mCx = (150. mCi mL) / (60. mCi) x = 2.5 mL

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Required: the mass of the block B.

Explanation:

we assume that mass of the block A is

and mass of the block B is

now, look at the free body diagram

from the above diagram, we can apply newton's law. we assume that both the block moves with the same acceleration a.

for block A

for block B

from equations 1 and 2

we can write

this is the acceleration of the whole system.

By the above equation, we can calculate the acceleration of the both the blocks.

we are interested in determining the mass of block mB.

we assume that block mA moves with above acceleration.

we know that

if we know the height of the block A and measure the time to reach the block A to the ground.

by the equation 3 we can calculate the acceleration.

from the equation 2 and 4, we can write

by the above equation, we can easily can calculate the mass of the block B.

(a) part

only the mass of the block A and the distance block A falls to reach the floor is correct answer.

As we can see from the above equation.

Explanation:

I don't knoejajajajjjaj

You’re in luck!

Answer:

It would rise for about 19.2 meters or a little more than half a meter before falling back to the ground, though an observer on the Moon would be able to see it rise for nearly 46 meters. Why? A new measure of gravity called "g" can help us figure this out. Let's first start with a quick review of Newton's second law of motion: force equals mass times acceleration, or "F=ma." When you throw an object up vertically on Earth, the acceleration due to gravity is 9.8m/s/s--or as we know from earlier gradeschool physics, 32ft/s squared at sea level on Earth. If there were no air resistance and the ball weighed 10 grams, then it would take .45 seconds to reach the top of its arc, where it will be moving at 10m/s (or 22.7 mph, which is about how fast you'd have to throw the ball straight up to get it back down in .45 seconds). If there were no gravity, however, the ball would just keep going faster and faster as it moved away from Earth's surface. As an object reaches lower orbital speeds farther away from Earth, docking takes relatively longer--which brings us back to our question about the Moon. The gravitational force between any two objects drops off according to a very simple formula: one over the distance squared. So even though g on Earth is 9.8 m/s/s near sea level, at the height of one meter above the ground, g is approximately 9.81m/s/s--just a tiny bit less than sea level value due to the very small distance between an object and its center of mass (the Earth). On the Moon, however, gravity drops off quite rapidly because there's no atmosphere to slow down objects in low orbit around it (so you'd have to throw something really fast to keep it orbiting around), and it has almost no mass compared with Earth.

**ANSWER BY AN AI**

Answer:

acceleration = change in velocity / change in time

acceleration = 14/10

acceleration = 1.4/s^2