An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km before over flying a road junction. Calculate A. Distance of airplane from ikeja airport when it was directly above the road junction B. The bearing of the airplane from ikeja airport at this instant

Answer:

f=10gh

making h the subject of the formula, we have;

h=f/10g

Answer:

infinite solutions

Step-by-step explanation:

2x-6 = 3x+1-X-7

Combine like terms

2x-6 = 3x-x +1-7

2x-6 = 2x -6

subtract 2x from each side

-6 = -6

Since this is a true statement, x can be any real number

Answer:

40 m and 34 m

Step-by-step explanation:

vas muy bien seguro asi q hazlo tu JAJJA

Answer:

EF = 10

Step-by-step explanation:

DE + EF = DF

So, x + 22 + x + 23 = 21

2x + 47 = 21

2x = -26

x = -13

EF = x + 23

EF = 10

Answer:

not whoever wrote this question. every 10th person is surveyed. she surveyed 50 people. that mean 500 people and 50 surveyed people. then at the end the teacher said there is 1000 students. your teacher wrote you a bad question with no right answers.

The indifference curve and efficient frontier are two measures at which the optimum portfolio is said to occur at the point of tangency.

The indifference curve is the risk-return trade-off that investors are willing to make, while the efficient frontier is the best possible returns that could be expected from all possible portfolios. At the point of tangency, one has attained the optimal portfolio.

Efficient frontiers:

The efficient frontier is the set of optimal portfolios that offer the highest expected return for a defined level of risk or the lowest risk for a given level of expected return.

Therefore indifference curve and efficient frontier are two measures.

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The center of the circle is at -2 + 5i.

Complex Numbers. Complex numbers are those that are expressed as a+ib, where a and b are actual numbers and I is a fictitious number called a "iota."

Complex numbers are numbers that consist of two parts — a real number and an imaginary number.

Given:

Diameter = –10 – 1 i = (- 10, - 1)

6 + 11 i = (6, 11)

Given that we are aware that these are the diameter's endpoints, it follows that the circle's center is the place that lies midway between the endpoints.

Then,

x = (-10 + 6) / 2

  = - 4 / 2

   = -2

y = (- 1 + 11) / 2

   = 10 / 2

   = 5

Hence, the center is located at (- 2, 5).

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Answer:

The contact force between the block and the stick immediately before the system is released, we can use the equations of motion for the stick and the block.

Step-by-step explanation:

(a) To prove that the stick will hit the table before the block if cos θ0 ≥√2/3, we need to consider the motion of the stick and the block separately.

Let's start with the motion of the stick. The stick is pivoted at one end and released from rest at an angle θ0 with the table. The gravitational force acting on the stick can be resolved into two components: one parallel to the table and one perpendicular to the table. The component parallel to the table will cause the stick to rotate and the component perpendicular to the table will cause the stick to move downwards. The motion of the stick can be described using the following equations:

Iα = MgLsinθ - F

Ma = MgLcosθ - N

where I is the moment of inertia of the stick about its pivot point, α is the angular acceleration of the stick, M is the mass of the stick, g is the acceleration due to gravity, F is the force of friction between the stick and the table, a is the linear acceleration of the stick, and N is the normal force between the stick and the table.

Now, let's consider the motion of the block. The block is placed at the other end of the stick and remains at rest. The gravitational force acting on the block can be resolved into two components: one parallel to the table and one perpendicular to the table. The component parallel to the table will cause the block to move with the stick and the component perpendicular to the table will cause the block to move downwards. The motion of the block can be described using the following equation:

ma = MgLcosθ - N

where m is the mass of the block.

If the stick hits the table before the block, then the angle θ at which this happens satisfies the condition a = 0. In other words, the linear acceleration of the stick is zero at the instant the stick hits the table. Substituting a = 0 into the equation for the linear acceleration of the stick, we get:

MgLcosθ - N = 0

Substituting N = Mgcosθ into the equation for the linear acceleration of the block, we get:

ma = MgLcosθ - Mgcosθ

Simplifying this expression, we get:

ma = Mg(cosθ)(L - 1)

Since the block is at rest, its acceleration is zero. Therefore, cosθ = 0 or L = 1. Since L is the length of the stick, it cannot be less than 1. Therefore, we must have cosθ = 0, which means that θ = π/2.

Now, let's consider the condition cos θ0 ≥√2/3. We can rewrite this condition as θ0 ≤ cos-1(√2/3). If θ0 is less than or equal to π/4, then cos θ0 is greater than or equal to √2/2, which is greater than √2/3. Therefore, we can assume that θ0 is greater than π/4.

Using the equations for the motion of the stick and the block, we can show that if θ0 ≤ cos-1(√2/3), then the block will hit the table before the stick. This can be done by solving the equations of motion for the stick and the block numerically or by using energy conservation arguments. However, this is beyond the scope of this answer.

(b) To find the contact force between the block and the stick immediately before the system is released, we can use the equations of motion for the stick and the block. At the instant the system is released, the stick and the block are at rest and

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Using the linear approximating polynomial, e^(-0.7) is approximately 1.7, and using the quadratic approximating polynomial, e^(-0.7) is approximately 1.945.

To find the linear approximating polynomial, we need the first-degree Taylor polynomial centered at a = 0. The linear approximating polynomial is given by p_1(x) = f(a) + f'(a)(x - a), where f(x) = e^(-x).

First, we find f(a) and f'(a):

f(a) = f(0) = e^0 = 1

f'(a) = f'(0) = -e^0 = -1

Substituting these values into the linear approximating polynomial, we get:

p_1(x) = 1 - 1(x - 0) = 1 - x

b. To find the quadratic approximating polynomial, we need the second-degree Taylor polynomial centered at a = 0. The quadratic approximating polynomial is given by p_2(x) = f(a) + f'(a)(x - a) + (1/2)f''(a)(x - a)^2.

First, we find f''(a):

f''(a) = f''(0) = -f'(0) = -(-1) = 1

Substituting all the values into the quadratic approximating polynomial, we get:

p_2(x) = 1 - 1(x - 0) + (1/2)(1)(x - 0)^2

= 1 - x + (1/2)x^2

= 1 - x + (1/2)x^2

c. Using the linear approximating polynomial p_1(x) = 1 - x, we can approximate e^(-0.7) by substituting x = -0.7:

p_1(-0.7) = 1 - (-0.7) = 1 + 0.7 = 1.7

Using the quadratic approximating polynomial p_2(x) = 1 - x + (1/2)x^2, we can approximate e^(-0.7) by substituting x = -0.7:

p_2(-0.7) = 1 - (-0.7) + (1/2)(-0.7)^2 = 1 + 0.7 + (1/2)(0.49) = 1 + 0.7 + 0.245 = 1.945

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Answer:

-5/3

Step-by-step explanation:

Answer:

-5/3

Step-by-step explanation:

y=mx+b

m is the slope

so its -5/3

Hope this helps plz hit the crown :D

The change in the amount of water in 12 weeks is \(16\frac{1}{2}\) pints.

Let's first find the amount of water that decreases in one week:

\(9\frac{5}{8}\) pints / 7 weeks = \(1\frac{3}{8}\) pints per week

So the amount of water decreases by \(1\frac{3}{8}\) pints per week.

To find the change in the amount of water in 12 weeks

we can simply multiply the amount of decrease per week by the number of weeks:

\(1\frac{3}{8}\)  pints per week x 12 weeks

= \(16\frac{1}{2}\) pints

Therefore, the change in the amount of water in 12 weeks is \(16\frac{1}{2}\) pints.

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Answer:

4 hours

Step-by-step explanation:

24+12+12+12

above is the hint

Answer: 4 hours

Step-by-step explanation:

ok so for the first hour you'd pay 24, so subtract that from the total

60 - 24 = 36

and now to see how many hours you used it after the original  hour, divide 36 by 12

36 ÷ 12 = 3

so you used it for three hours after the original hour

1 + 3 = 4

so you used it for 4 hours in total

hope this helps

The answer is D! Hope you have a great day!

Plllllz mark brainliest if you dont mind

Answer:

the answer is 14 hopes this helps

Step-by-step explanation:

Ac/b=?

-2(-12)=24/3

24/3=8

8-(a+d)=?

8-(-2(+-)4)=?

8-(-2-4)=?

8+2+4=?

10+4=?

14

Answer:

answer it is 17 for real it is

Answer:

8 feet

Step-by-step explanation:

you have to calculate :(19+2x)(6+2x)=770

you will get X1=8,X2= negetive some value but measurement cant be negative .if you put X=8 you'll find LHS=RHS

Answer:

\(x= \frac{-25}{4}+\frac{1}{4} \sqrt{3705}\)  or  \(x= \frac{-25}{4} + \frac{-1}{4}\sqrt{3705}\)

Step-by-step explanation:

So first you need to find the area of the swimming pool:

19*6 = 114

Next you add the area of the swimming pool and the area of the walkway:

114 + 770 = 884

After this you solve for x using this equation:

(19 +2x) * (6 + 2x) = 884

This would normally find the area of the whole swimming pool area and the walkway but because we know that we can use it to solve for x.

The step-by-step is this:

\(4x^{2} +50x+114=884\)

\(4x^2+50x+114-884=884-884\)

 \(4x^2+50x+114-884=0\)

Now we'll use the quadratic formula to simplify it farther:

\(x= \frac{-(50) + \sqrt{(50)^2-4(4)(-770)} }{2(4)}\)

\(x=\frac{-50 + or - \sqrt{14820} }{8}\)

\(x= \frac{-25}{4}+\frac{1}{4} \sqrt{3705}\) or \(x= \frac{-25}{4} + \frac{-1}{4}\sqrt{3705}\)

Yes, the explicit solution of y dy dx = 3x that passes through the origin is y = x^3.

Yes, there is an explicit solution of y dy dx = 3x that passes through the origin. The explicit solution is y = x^3.

To find the explicit solution, we can separate the variables and integrate both sides of the equation:

y dy = 3x dx

∫y dy = ∫3x dx

(1/2)y^2 = (3/2)x^2 + C

y^2 = 3x^2 + 2C

y = √(3x^2 + 2C)

Since we want the solution to pass through the origin, we can plug in the coordinates of the origin (0,0) into the equation and solve for C:

0 = √(3(0)^2 + 2C)

0 = √(2C)

C = 0

Plugging C back into the equation, we get:

y = √(3x^2)

y = x√3

Squaring both sides of the equation gives us the explicit solution:

y^2 = 3x^2

y = x^3

Therefore, the explicit solution of y dy dx = 3x that passes through the origin is y = x^3.

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Answer:

The best estimate for her earnings is $1200

Step-by-step explanation:

Number of time spent babysitting each week = 21 hours = BBS

Number of time spent dog walking each week = 9 hours = DW

She earns $7.50 per hour for dog walking,

She earns $(7.50+1.50) = $9 for baby sitting,

There are 4 1/2 weeks = 9/2 weeks in July,

Now, for each week she earns 21(9) = $189 from baby sitting

and 9(7.5) = $67.5 from dog walking,

So, for the month of July, i.e. 9/2 weeks, she earns,

9/2(189) = $ 850.5 from baby sitting,

and (9/2)(67.5) = $303.75 from dog walking,

In total for the month, she earns,

850.5 + 303.75 = $1154.25

Hence the best estimate for her earnings is $1200

Answer:

Answer:

x = 30

Step-by-step explanation:

The problem is \(\frac{x}{5}\) = 6.  We need to end up with "x equals some number."  This is called solving for x.  In order to do this we need to have x by itself.  We look at the problem and ask, "what is preventing x from being by itself?"  In this case x has a "divided by 5" with it.  How can we get rid of that?  Well we can do the opposite of "divided by 5,"  and that is to multiply the left side by 5.  That leaves x by itself which is exactly what we need.  But if do something to one side of an equation, we need to do it to the other side for the equation to still be true.  So in this case we also have to multiply the right side by 5 also, which gives us 30 on the right side.  So in our original problem:

 \(\frac{x}{5}\)= 6

Multiply both sides by 5 and we have the answer:

x = 30

66x + 8 = 20x - 15

66x - 20x = -15 - 8

46x = -23

x = -23/46

x = -1/2

The volume of Uranus having a diameter of 50724000 m is 6.829 x 1022 m3.

Volume is defined as the quantity of the three-dimensional space occupied by a closed three-dimensional figure. In the case of any object, volume is measured in cubic units. In cases of solid objects, their volume is measured in cubic units of length, such as meters, centimeters, etc.

To calculate the volume of spherical objects, viz. for a planet (assuming it is an ideal sphere in shape), the following formula is applied:

Volume (V) = 4/3  π\(R^{3}\) cubic units

where R = radius and π  = 3.14, a mathematical constant.

It is given that the diameter ( D ) of Uranus = 50724000 m.

Therefore radius ( R ) = D/ 2 = 50724000 m/ 2 = 25362000 m.

Therefore volume of planet Uranus = 4/3 π\(R^{3}\).

Substituting  π by 3.14 and R by 25362000m, we get

Volume = 6.829 x 1022 \(m^{3}\)

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A (-2,1)

B (-1,3)

\(\tt slope=\dfrac{y_2-y_1}{x_2-x_1}\\\\=\dfrac{3-1}{-1-(-2)}=2\)

y - y1 = m(x-x1), input point A or B for x1,y1

y - 1 = 2(x + 2)

25% is the larger circle area is gray.

Area of a Circle: The area of a circle is pi times the radius squared.

To calculate the area of the circle we have the formula:

A = π r²-----(1)

where

A=area

r=radius.

First, we have to analyze the given data, the large circle center o passes through d, so

Gray circle area=π*(radius)^2----(2)

The radius of the smaller circle = OD/2 substitute in (2)

Gray circle area=π*(OD/2)^2

Gray circle area=π*OD^2/4

Larger circle area=π*(radius)2    

radius of the larger circle = OD

larger circle area=π*OD^2  

To know the percentage of a large circle we have a small formula:

gray circle area/large circle area--------(3)

=π*OD^2/4/π*OD^2  

=π*OD^2/4*1/π*OD^2=1/4

=25/100

=25%

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Therefore, the figure's volume is 32 times Prism A's length less 40 cubic feet.

In three dimensions, each object takes up some space. What is being assessed is the size of this region. The volume of an item is the region that fills its three-dimensional boundaries. It is additionally known as an object's potential.

To determine the volume of the figure, we need to find the dimensions of both prisms and then add their volumes together.

Let's start by finding the width of Prism A. Since Prism A and Prism B are attached to each other, they must share a common width. We know the width of Prism B is 4 feet, so the width of Prism A must also be 4 feet.

Now we can calculate the volume of Prism A:

Volume of Prism A = length x width x height

Volume of Prism A = unknown x 4 feet x 8 feet (since we don't know the length of Prism A)

We don't know the length of Prism A, but we do know that it is connected to Prism B, which has a length of 2 feet. Therefore, the length of Prism A must be the remaining distance between the two prisms, which is:

Length of Prism A = total length - length of Prism B

Length of Prism A = unknown - 2 feet

Now we can substitute this value into the volume equation for Prism A:

Volume of Prism A = (unknown - 2 feet) x 4 feet x 8 feet

Next, we can calculate the volume of Prism B:

Volume of Prism B = length x width x height

Volume of Prism B = 2 feet x 4 feet x 3 feet

Volume of Prism B = 24 cubic feet

Finally, we can add the volumes of the two prisms together to get the total volume of the figure:

Total volume = Volume of Prism A + Volume of Prism B

Total volume = (unknown - 2 feet) x 4 feet x 8 feet + 24 cubic feet

Without knowing the value of "unknown", we cannot calculate the exact volume of the figure. However, we can simplify the equation by multiplying out the terms:

Total volume = (32 x unknown - 64) cubic feet + 24 cubic feet

Total volume = 32 x unknown - 40 cubic feet

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Driving a personal car would be the most cost-effective mode of transportation for this commute, with a total daily cost of approximately $4.60 ($3.60 for gas + $1 for travel time).

Based on the given information, the most cost-effective mode of transportation for this commute would be to drive a personal car. Taking public transportation or carpooling may be more environmentally friendly options, but they may not save as much money as driving alone.

Assuming an average speed of 60 miles per hour on the highway, the commute would take approximately 20 minutes each way, or 40 minutes round-trip. This means the total cost of travel time for each workday would be $40 ($60/hour x 2/3 hour).

Using a cost calculator such as GasBuddy, we can estimate that the cost of driving 20 miles per day (round-trip) would be around $3.60 per day, assuming an average fuel efficiency of 25 miles per gallon and a gasoline price of $2.50 per gallon.

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Answer:

the 3(2m+1m) and 9m.

Step-by-step explanation:

Charnita Huezo's federal income tax withholdings would be $4,277 based on the 2021 tax brackets and rates.

To calculate Charnita Huezo's federal income tax withholdings, we need to use the graduated tax table to determine her tax liability based on her income and filing status. As the exact tax brackets and rates may vary depending on the year, I will use the 2021 tax brackets and rates for demonstration purposes.

Here are the 2021 tax brackets for a single filer:

- 10% on income up to $9,950
- 12% on income between $9,951 and $40,525
- 22% on income between $40,526 and $86,375
- 24% on income between $86,376 and $164,925
- 32% on income between $164,926 and $209,425
- 35% on income between $209,426 and $523,600
- 37% on income over $523,600

Now, let's calculate Charnita Huezo's federal income tax withholdings step by step:

1. Calculate her taxable income by subtracting her deductions from her gross income:
  Taxable Income = Gross Income - Deductions
  Taxable Income = $61,700 - $24,400
  Taxable Income = $37,300

2. Determine the tax liability based on the tax brackets:

  - The first $9,950 is taxed at 10%.
  - The amount between $9,951 and $40,525 is taxed at 12%.
  - The remaining amount between $40,526 and $37,300 is not taxed.

  Tax Liability = (10% of $9,950) + (12% of ($37,300 - $9,950))
  Tax Liability = ($995) + (12% of $27,350)
  Tax Liability = $995 + $3,282
  Tax Liability = $4,277

Therefore, Charnita Huezo's federal income tax withholdings would be $4,277 based on the 2021 tax brackets and rates. Please note that the actual tax brackets and rates may differ based on the tax year, so it's important to refer to the correct tax tables for accurate calculations.

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The given situation is represented by two equations which results in system of equation.

A group of equations comprising one or more variables is known as a system of equations. The variable mappings that satisfy each component equation, or the points where all of these equations cross, are the solutions of systems of equations.

The three types of system of equation is dependent, inconsistent and independent.

According to given condition the resulting system of equation is

125a +65 s = 1,200

140a +50 s = 1,230

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