An air-track glider attached to a spring oscillates between the 10.0 cm mark and the 51.0 cm mark on the track. The glider completes 13.0 oscillations in 33.0 s. What are the (a) period, (b) frequency, (c) amplitude, and (d) maximum speed of the glider? Part A - Express your answer using two significant figures. T = _________s Part B - Express your answer using two significant figures. f = _________Hz Part C - Express your answer using two significant figures. A = _________cm Part D - Express your answer using two significant figures. vmax = _________cm/s

Acceleration is -7 m/s²

Explanation:

initial velocity (u) = 14 m/s

since it's gonna stop,

final velocity (v) = 0m/s

time taken(t) = 2 seconds

now,

a = (v-u)/t

or, a = (0-14)/2

or, a = -14/2

a = -7m/s²

Answer : Gretchen's rate of speed is 72.5 kilometers per hour.

What is the distance?

-- Distance is defined as the product of speed and time.

-- Since there are 3600 seconds in an hour, we can divide the time it takes -- Gretchen to travel 5500 meters by 3600 to find the number of hours it takes her:

⇒ 275 seconds / 3600 seconds/hour = 0.0763888889 hours.

Next, we need to convert the distance she travels to kilometers.

-- Since there are 1000 meters in a kilometer, we can divide the distance Gretchen travels by 1000 to find the number of kilometers she travels:

⇒ 5500 meters / 1000 meters/kilometer = 5.5 kilometers.

Now that we have the distance Gretchen travels and the time it takes her to travel that distance in the appropriate units, we can divide the distance by the time to find her rate of speed in kilometers per hour:

⇒ 5.5 kilometers / 0.0763888889 hours = 72.5 kilometers/hour.

Thus, Gretchen's rate of speed is 72.5 kilometers per hour.

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Answer:

\(1.6 \times 10 { }^{ - 1} kg \\ \)

Explanation:

I hope, it helped you.

A) Moving with a constant speed in the positive direction, B) Moving in the negative direction and speeding up, C) Moving in the positive direction, first fast then slow, and D) Moving with negative velocity and negative acceleration.

A) Moving with a constant speed in the positive direction: This indicates a linear motion where the object maintains a constant velocity in the positive direction. The sketch would show a straight line with a constant positive slope, indicating a steady speed.

B) Moving in the negative direction and speeding up: This suggests an object that is initially moving in the negative direction and is accelerating, or increasing its speed. The sketch would depict a line with a negative slope that becomes steeper over time, indicating an increase in velocity.

C) Moving in the positive direction, first fast then slow: This implies an object initially moving in the positive direction at a high speed and gradually slowing down. The sketch would show a line with a positive slope that becomes less steep over time, indicating a decrease in velocity.

D) Moving with negative velocity and negative acceleration: This refers to an object moving in the negative direction with decreasing speed, or decelerating. The sketch would display a line with a negative slope that becomes less steep over time, representing a decrease in velocity.

These sketches provide visual representations of the predicted actions/movements, illustrating the changes in velocity over time for each scenario.

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Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

To determine the capacitance and the maximum voltage that can be applied to a Teflon-filled parallel plate capacitor, we can use the formula for capacitance:

(a) The capacitance of a parallel plate capacitor is given by the formula:

C = (ε₀ * εᵣ * A) / d,

where C is the capacitance, ε₀ is the vacuum permittivity (8.854 x 10^-12 F/m), εᵣ is the relative permittivity (dielectric constant) of Teflon (approximately 2.1), A is the plate area, and d is the distance (insulation thickness) between the plates.

First, we need to convert the plate area from square centimeters to square meters:

A = 175 cm² = 175 x 10^-4 m²

Now we can calculate the capacitance:

C = (8.854 x 10^-12 F/m * 2.1 * 175 x 10^-4 m²) / (0.0400 x 10^-3 m)

= 7.73 x 10^-11 F

Therefore, the capacitance of the Teflon-filled parallel plate capacitor is approximately 7.73 x 10^-11 Farads.

(b) The maximum voltage that can be applied to a capacitor depends on its breakdown voltage, which is the voltage at which the dielectric material (in this case, Teflon) begins to break down and conduct electricity. Teflon has a high breakdown voltage, typically around 20,000 to 50,000 volts per millimeter.

To calculate the maximum voltage, we need to convert the insulation thickness from millimeters to meters:

d = 0.0400 mm = 0.0400 x 10^-3 m

The maximum voltage can be estimated by multiplying the breakdown voltage per unit thickness by the total thickness:

Maximum voltage = (Breakdown voltage/mm) * d

Taking a conservative estimate of the breakdown voltage at 20,000 volts per millimeter:

Maximum voltage = (20,000 V/mm) * 0.0400 x 10^-3 m

= 800 V

Therefore, the maximum voltage that can be applied to the Teflon-filled parallel plate capacitor is approximately 800 volts.

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The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).

To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.

To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).

The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).

The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).

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The lost volts in the battery are 0.0672 V. The current flowing through the resistors is 0.16 A.

Given values, Resistance R1 = R2 = R3 = 9.02 V Voltage, V = 4.4 V Internal resistance, r = 0.42 Ω(a) Calculating the current flowing through the resistors. The equivalent resistance, R in a series circuit is given by:

R = R1 + R2 + R3R

= 9.02 + 9.02 + 9.02R

= 27.06 Ω

We know that the current, I flowing through the circuit is given by:

I = V / (R + r)I

= 4.4 / (27.06 + 0.42)I

= 0.16 Ampere

Therefore, the current flowing through the resistors is 0.16 A.

(b) Calculating the "lost volts" in the battery. Lost volts in a battery can be found using the formula:

VL = I × rVL

= 0.16 × 0.42VL

= 0.0672 V

Therefore, the lost volts in the battery are 0.0672 V.

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Answer:

y=k(1/x

Explanation:

Answer:

(A)                  y=kx

Explanation:

Slumped area only supports grassy vegetation and no trees can be grow on it.

A slump is a form of mass wasting that occurs when a rock layer moves at a short distance down a slope, this type of area is called slumped area. The speed of the mass movement at slumped area is slow i.e. few cm per year or meter per year.

There are no trees growing in the slumped area because trees required fixed land but the land moves at the slumped area so we can conclude that slumped area only supports grassy vegetation and no trees can be grow on it.

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Answer:

The grassy vegetation in the slumped soil indicates slow movement of material, and it appears recently enough that trees have not had time to establish themselves.

Explanation:

It likely moved gradually over a period ranging from days to years. Grassy vegetaion has been able to establish on the surface without any breaks or open soil visible, this is evidence of the gradual movement.

Astronomers call the vast, rotating cloud of vapor and dust from which the solar system formed as D) The Solar Nebula.

The Solar Nebula is the rotating cloud of gas and dust that is believed to have formed the Sun and the solar system approximately 4.6 billion years ago. This theory is supported by observations of other star-forming regions in our galaxy, which exhibit similar conditions and structures. As the Solar Nebula collapsed under its own gravity, it began to spin faster and flatten into a disk shape, with the Sun forming at the center and the planets forming from the material in the disk.

The Solar Nebula theory is currently the most widely accepted explanation for the formation of the solar system. It states that a rotating cloud of gas and dust collapsed under its own gravity, eventually forming the Sun and the planets.

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Answer:

Approximately \(3.7\; {\rm N \cdot kg^{-1}}\) (or equivalently, \(3.7\; {\rm m\cdot s^{-2}}\).)

Explanation:

Gravitational field strength measures the force (weight) that the field exerts on object of unit mass (e.g., \(1\; {\rm kg}\).)

Divide the weight of the object by its mass to find the gravitational field strength at the position.

In this question, \(\text{weight} = 55.5\; {\rm N}\) while \(\text{mass} = 15\; {\rm kg}\). Therefore, the gravitational field strength will be:

\(\begin{aligned} & (\text{gravitational field strength}) \\ =\; & \frac{(\text{weight})}{(\text{mass})} \\ =\; & \frac{55.5\; {\rm N}}{15\; {\rm kg}} \\ =\; & 3.7\; {\rm N \cdot kg^{-1}} \end{aligned}\).

The bird travels a total distance of 92 km. When the two trains are 46 km apart, the bird starts flying from one train toward the other train.

Let's assume that the distance between the bird and the first train is x km. Since the bird is flying towards the other train at a speed of 46 km/h and the trains are moving towards each other at a combined speed of 46 km/h, the relative speed of the bird with respect to the first train is

69 km/h (46 km/h + 23 km/h).

Therefore, it takes the bird x/(69 km/h) hours to reach the second train.

During this time, the two trains move towards each other and reduce the distance between them by

Therefore, the distance between the bird and the second train is also x km. Now, the bird starts flying towards the first train at the same speed of 46 km/h. Again, it takes the bird

hours to reach the first train.

During this time, the two trains move towards each other and reduce the distance between them by another x/3 km. Therefore, the total distance traveled by the bird in one round trip is 2x km.

Since x + x/3 + x/3 = 92 km (the initial distance between the trains)

the total distance traveled by the bird in all the round trips is

2(92 km) = 184 km.

However, since the bird only flies halfway towards each train before turning back, the actual distance traveled by the bird is half of 184 km, which is 92 km.

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To show that the pion is in a p orbital, we need to first express the wave function in spherical coordinates. The wave function will be L² = -2ħ² [sin²(φ + π/4) ∂²/∂φ² + cos²(φ + π/4) ∂²/∂φ².

x = r sinθ cosφ, y = r sinθ sinφ, z = r cosθ

where r is the radial distance from the origin, θ is the polar angle measured from the positive z-axis, and φ is the azimuthal angle measured from the positive x-axis.

Substituting these expressions into the given wave function, we get:

ψ = (r sinθ cosφ + r sinθ sinφ + r cosθ) e(\(-\frac{-r^{2} }{2b_{0} }\))

ψ = r(e^(-Squareroot)) (sinθ cosφ + sinθ sinφ + cosθ)

ψ = r( e(\(-\frac{-r^{2} }{2b_{0} }\)))) (sinθ (cosφ + sinφ) + cosθ)

ψ = r( e(\(-\frac{-r^{2} }{2b_{0} }\))) (sinθ (2sin(φ + π/4)) + cosθ)

ψ = r( e(\(-\frac{-r^{2} }{2b_{0} }\)))) [(2sin(φ + π/4)) cosθ + sinθ sin(φ + π/4)]

Now, we can see that the wave function depends only on θ and φ, and not on the azimuthal angle φ. This indicates that the pion is in a p orbital.

The magnitude of the orbital angular momentum L is given by:

L²= -ħ² (sinθ ∂/∂φ + cosθ ∂/∂θ)²

Substituting the wave function into this expression and simplifying, we get:

L = -ħ² [sin²θ (∂²/∂φ²) + cos²θ (∂²/∂θ²) + sinθ cosθ (∂/∂θ)(∂/∂φ) + sinθ cosθ (∂/∂φ)(∂/∂θ)]

Evaluating each term separately and using the fact that the wave function depends only on θ and φ, we get:

L² = -ħ² [sin²θ (-sinφ ∂/∂θ - cosφ cotθ ∂/∂φ)²+ cos²θ (∂²/∂²θ) + sinθ cosθ (-sinφ cotθ ∂/∂φ + cosφ ∂/∂θ) (∂/∂θ)(-sinφ ∂/∂θ - cosφ cotθ ∂/∂φ) + sinθ cosθ (-sinφ cotθ ∂/∂φ + cosφ ∂/∂θ) (∂/∂φ)(-sinφ ∂/∂θ - cosφ cotθ ∂/∂φ)]

Simplifying this expression and evaluating it at θ = π/2 (since the pion is in a p orbital), we get:

L² = -2ħ² (∂²/∂φ²)

Substituting the wave function into this expression and simplifying, we get:

L² = -2ħ² [sin²(φ + π/4) ∂²/∂φ² + cos²(φ + π/4) ∂²/∂φ²]

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Answer:

Yes it is a physical change

Explanation:

The cookie is still a cookie even when it has been broken apart, so it cannot be a chemical change. The cookie only changed physically.

Answer:

B is the answer to me in short

Answer:

B) The period would change by a factor of \(\frac{1}{\sqrt{2} }\)

Explanation:

Edmentum/Plato

The net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.

The net force direction can be determined by finding the net vector sum of the forces acting on it.

Since the first person pulled the cart to the right with a force of 10n,

Assuming the right direction as positive, this force can be represented as a vector ⇒(+)10n

Similarly, as the second person pulls the cart to the left, the force can be represented as a vector ⇒ (-)3n,

∴ Net force = Net vector sum of the forces

                   =(+10n) + (-3n)

⇒Net force = +7n

Thus, the net direction on the cart, if a person pulls on a cart to the right with a force of 10n and a second person pulls to the left with a force of 3n, is 7n to the right.

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Answer: 7n

Explanation:

The total work done on the system of two equal-mass pucks on frictionless ice pushed towards each other by two equal but opposite forces is negative.

When two equal but opposite forces act on two equal-mass pucks on frictionless ice, the pucks will accelerate towards each other with equal magnitude but in opposite directions.

Since the two forces are equal and opposite, the net force on the system is zero. Therefore, the acceleration of the system is zero, and the velocity of the pucks remains constant.

The work done on an object is defined as the force applied to the object multiplied by the distance over which the force acts. When the two pucks are pushed towards each other by the equal but opposite forces, each puck experiences a force over a certain distance. However, the force and the displacement are in opposite directions for each puck, resulting in negative work done on each puck separately.

However, since we are considering the system of both pucks together, the total work done on the system is the sum of the work done on each puck. Since the work done on each puck is negative, the total work done on the system is also negative.

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Explanation:

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

Answer:

The answer is 39.3

Explanation:

Answer:

1.) 347,000,000

2.)7,940

3.)0.00196

4.)4,500,000,000

5.)0.00000961

6.)102,000

7.).000000000701

8.)44.4

Explanation:

when the power is positive, you just need to move decimal point to your right , for a number of times which is similar to the value of the power.

Eg. 3.47×10 raised to the power 8.

with this, move the decimal point to the right eight times which will be 347,000,000.

But when the power is negative, move the decimal point to the left for a number times which will be similar to the value of the power.

Eg. 1.96×10 raised to the power negative 3.

move the decimal point leftwards three times which will be 0.00196

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The human person and electromagnetic fields both have their benefits and drawbacks. They do present a threat to public health. Power plants produce a tremendous amount of electricity.

When an electrically charged object moves through space, it receives a magnetic force in the magnetic field. The coil becomes magnetised when current passes through the circuit. A straight wire's magnetic field in an electrical circuit is weaker than a coiled wire's magnetic field.

Power plants produce a tremendous amount of electricity, which is then sent across the nation on high-voltage cables. Electromagnetic fields are produced by appliances, power lines, radars used by the military and airports, substations, transformers, computers, and other electrically powered machinery. Scientists have shown that our well-being is actually influenced by the earth's electromagnetic climate. Since there are so many objects in our daily lives that produce electromagnetic fields, it is challenging to avoid them.

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Answer:

Im sorry but i really need these points. FORGIVE ME

Explanation:

Answer:

Valence Electrons

Explanation:

The electrons of an atom that can participate in the formation of chemical bonds with other atoms. they are the furthest electrons from nucleus

The amount of force that is exerted on a balloon by the gas inside the balloon is (the pressure of the gas inside the balloon) multiplied by (the surface area of the inside of the balloon).

According to Newton's law of motion, the direction of motion of an object depends on the direction of the applied force.

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force and it will move in the direction of the applied force.

The Newton's first law of motion is also called the law of inertia because it depends on the mass of the object. The more massive an object is, the more inertia the object will possess and vice versa.

Also, the Newton's second law of motion states that the force acting on an object is directly proportional to the product of mass and acceleration of the object.

Mathematically, Newton's second law of motion is given as;

F = ma

F = mv/t

Ft = mv

This law (Newton's second law of motion) is also states that the force applied on an object directly proportional to the rate of change of momentum of the object.

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The smallest angle at which you would get destructive interference when 550 nm light passes two slits 50 μm apart is 0.32°.

The condition for destructive interference is gotten  by:

Δϕ = 2πΔx/λ = π

where Δx=  path difference between the two slits,

λ =  wavelength of light,

and Δϕ =  phase difference.

λ/2 = Δx sinθ

Here, θ is the angle between the incident light and the line connecting the center of the slits to the point of interest on the screen.

sinθ = (λ/2) / Δx = (550 nm / 2) / (50 μm) = 0.0055

θ = sin⁻¹(0.0055) = 0.32°

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Answer:

Here is the solution hope it helps:)

Answer:

280v

Explanation:

Velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

This is a which have both magnitude and direction. Example include:

This is a quantity which has magnitude but no direction. Example include:

From the above, we can see that velocity, acceleration, force, and displacement, have magnitude and direction (ie vector quantity) in common

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