An accelerometer is made with a crystal of natural frequency 20 khz. the damping ratio of the accelerometer is found to be 0.71. determine the upper cutoff frequency of the accelerometer for 1 accuracy.

3.5 m / s  is their speed after the collision.

Mass of a car = 1000 kg,

Velocity car = 8 m/s,

Mass  lorry = 3000 kg,

Velocity lorry = 2 m/s.

u = initial velocity,

v = final velocity.

m₁ = 1000 kg, m₂ = 3000 kg, u₁ = 8 m/s, u₂ = 2 m/s

(1000)(8) + (3000)(2) = (1000 + 3000)·v

8000 + 6000 = 4000·v

4000·v = 14000

v = 3.5 m/s

velocity (often abbreviated as "s") is a scalar variable that describes how lots an item's vicinity modifications over time or how plenty it modifications in step with unit of time.

The average speed of an item in a period of time is the distance traveled with the aid of the object divided by way of the length of the length.

Time divided with the aid of distance are the rate-associated metrics.. The meter in keeping with second (m/s) is the SI unit of pace, while the kilometer consistent with hour (kph) is the most usually used unit of speed in each day existence.

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Answer:

The electron degeneracy pressure is a type of pressure that arises when electrons are packed as tightly as the laws of quantum physics allow.

Explanation:

if it helped u please mark me a brainliest :-))

Degeneracy pressure occurs when a system of fermions reaches a high density, forcing fermions into the same quantum state. The Pauli Exclusion Principle prevents this, causing a 'pressure'. This concept is fundamental in understanding the stability of white dwarf stars.

Degeneracy pressure arises when a system of fermions (particles such as electrons, protons, and neutrons) reaches an extremely high density. This is a result of the Pauli Exclusion Principle, which states that no two identical fermions can occupy the same quantum state simultaneously. For example, in a white dwarf star when gravitational collapse continues to the extent that electrons are pressed close together, the system becomes so dense that many of the electrons try to occupy the same quantum state. But due to Pauli Exclusion Principle they can't, and they exert a 'pressure' - this is the degeneracy pressure. It is the degeneracy pressure that prevents white dwarf stars from collapsing under their own gravitational pull.

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Explanation:

weight of the piano = mg

w = 99 x 10 =990 N

The qualities that will allow you to deliver the most torque to the screw are a handle with a large diameter and increased width of the blade.


A screwdriver with a handle with a large diameter will provide better grip and allow you to exert more force on the screw, resulting in more torque. Similarly, increased width of the blade will provide more contact surface area with the screw, resulting in more torque. On the other hand, increased length of the screwdriver shank will not necessarily provide more torque as it can result in more bending and less force being applied to the screw.

A handle with a small diameter can also lead to less grip and less force being applied to the screw. Therefore, it is important to choose a screwdriver with a handle with a large diameter and increased width of the blade to loosen a stuck screw and deliver the most torque.

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The mirror image located behind the mirror  when an object is moved back to 25 cm from a concave spherical mirror is 6.25 cm

To determine the location of the image when an object is moved back to 25 cm from a concave spherical mirror, we can use the mirror equation:

1/d_o + 1/d_i = 1/f

where d_o is the distance from the object to the mirror, d_i is the distance from the image to the mirror, and f is the focal length of the mirror.

In this case, the object is initially placed 10 cm from the mirror and produces a virtual image 12.5 cm behind the mirror. Substituting these values into the mirror equation, we can solve for the focal length of the mirror:

1/10 cm + 1/(-12.5 cm) = 1/f

1/f = -0.12

f = -8.33 cm

The focal length of the mirror is negative, indicating that it is a concave mirror.

When the object is moved back to 25 cm from the mirror, the distance from the object to the mirror becomes d_o = 25 cm. Substituting this value and the focal length of the mirror into the mirror equation, we can solve for the distance from the image to the mirror:

1/25 cm + 1/d_i = -0.12

1/d_i = -0.12 - 1/25 cm

1/d_i = -0.12 - 0.04

1/d_i = -0.16

d_i = -6.25 cm

The distance from the image to the mirror is negative, indicating that the image is located behind the mirror. The image is located 6.25 cm behind the mirror.

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Answer:

The marginal revenue of the 7th unit of output is the additional revenue generated from producing and selling that unit. The marginal cost of the 7th unit of output is the additional cost incurred in producing that unit.

To determine the marginal revenue and marginal cost for the 7th unit, we would need more specific information about the revenue and cost functions or data associated with the production and sale of the units. Marginal revenue is typically calculated as the change in total revenue divided by the change in quantity, while marginal cost is calculated as the change in total cost divided by the change in quantity.

Without further information, it is not possible to provide an exact numerical answer for the marginal revenue and marginal cost of the 7th unit.

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The difference between the momentum before and after the bounce was 1.407 kg/s.

initial energy = mg(3) J = 29.4J

After bouncing ,energy = mg(2) =19.6J

Ball's change in energy = 29.4J - 19.6J = 9.8J

This energy is dissipated in the form of heat energy or sound energy.

work done during the bounce = 9.8J

change in momentum = mvf-mvi

29.4 = 1/2m\(vi^{2}\)

vf =7.668m/s

19.6J =1/2m\(vf^{2}\)

vf=6.261m/s

Change in momentum = m(vf-vi) = 1kg x (-1.407m/s) = -1.407

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Based on the given information, the most appropriate classification for the state of the volcano would be "Active-Dormant."

The volcano's history of generating multiple lava flows over the past 10,000 years indicates that it has been active in the relatively recent past. The presence of lava flows that have spread over large areas suggests ongoing volcanic activity, although not necessarily in the immediate present.

Additionally, the mention of very little tephra (volcanic ash and fragments) indicates that the volcano is not currently experiencing explosive eruptions. Instead, it has been primarily characterized by effusive eruptions that produce lava flows.

The fact that people in the nearby town remember the last eruption, which caused some forest fires, further supports the classification of the volcano as active-dormant. While the volcano may not be actively erupting at the moment, the memory of the recent eruption and the potential for future volcanic activity suggests that it is still in a state of activity, albeit in a relatively dormant phase.

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Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

The potential at a point due to a charge is given by V = kQ/r, where k is Coulomb's constant (~\(9x10^9 Nm^2/C^2\)), Q is the charge, and r is the distance from the charge.

The total potential at the center of the square is the sum of the potentials due to each charge.

The distance of each charge to the center is half the diagonal of the square, which is \(\sqrt2 * side/2 = \sqrt2 * \sqrt4.5/2 = 1.5m.\)

The total potential is then V_total

= \(k * [(510^8/1.5) + (210^8/1.5) - (510^8/1.5) - (710^8/1.5)] = -2 * k * 10^8 / 1.5 \\= -1.2 x 10^9 V.\)

Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

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Answer:

D

Explanation:

because the slope decreases

Answer:

Should be D the correct answer

Explanation:

Answer:

Objective Lenses: Usually you find 3 or 4 objective lenses on a microscope. They almost always consist of 4x, 10x, 40x and 100x powers, when coupled with a 10x (most common) eyepiece lens, total magnification is 40x (4x times 10x) 100x, 400x and 1000x

Explanation:

Objective lenses come in various magnification powers, with the most common being 4x, 10x, 40x, and 100x, also known as scanning, low power, high power and typically oil immersion objectives, respectively

the vector gravitational force acting on block 2 due to block 1 is approximately 1.2674 x 10^(-7) N in magnitude.

To determine the vector gravitational force acting on block 2 due to block 1, we can use Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (approximately 6.67430 x 10^(-11) N m^2/kg^2), m1 and m2 are the masses of the two blocks, and r is the distance between their centers of mass.

Given that the mass of block 1 is 37 kg and its position is (4, 11, 0) m, and the mass of block 2 is 1140 kg and its position is (22, 11, 0) m, we can calculate the distance between their centers of mass:

r = √((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

r = √((22 - 4)^2 + (11 - 11)^2 + (0 - 0)^2)

r = √(18^2 + 0^2 + 0^2)

r = 18 m

Now we can calculate the gravitational force:

F = (6.67430 x 10^(-11) N m^2/kg^2) * (37 kg * 1140 kg) / (18 m)^2

F ≈ 1.2674 x 10^(-7) N

Therefore, the vector gravitational force acting on block 2 due to block 1 is approximately 1.2674 x 10^(-7) N in magnitude.

For the second part of the question, to determine the momentum of block 2 at 4.55 seconds after noon, we need to know its velocity. Without that information, we cannot calculate the momentum. Please provide the velocity of block 2 at that time so that we can assist you further.

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The gravitational force acting on block 2 from block 1 depends on the distances between them but can't be calculated with the given information. The momentum of block 2 at any given time would be zero due to no external forces. The comparison of speed of block 1 and block 2 can't be made without information about their velocities.

The gravitational force acting on block 2 due to block 1 can be calculated using Newton's law of gravitation. This law states that every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

To calculate the vector force, we would need to know the exact position of these two blocks in three dimensional space. This would involve calculating the distance vector from block 1 to block 2, then use this to calculate the force vector by multiplying the magnitude of the gravitational force (calculated using Newton's law) by the unit vector in the direction of the distance vector. However, given the current details, a precise calculation can't be performed.

As for the momentum of block 2 at 4.55 seconds after noon, it can be calculated using the equation p = mv , where p is momentum, m is mass and v is velocity. Since no external forces are mentioned, block 2 would remain at rest, meaning its velocity is 0 and thus its momentum is also 0.

The question about whether block 1 is moving faster than block 2, or vice versa or both have the same speed, cannot be answered without knowing details about their velocities.

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Answer:

Explanation:

To find the volume of the object we use the formula

volume of object = final volume of water - initial volume of water

From the question

final volume of water = 86 mL

initial volume of water = 75 mL

So we have

volume of object = 86 - 75

We have the final answer as

Hope this helps you

Answer:

I believe D

Explanation:

You need to have a more accurate reading and you want to test it multiple times throughout the week though to get a base resting rate.

I hope this is correct good luck!

As cloud shrink in size, there is decrease in moment of inertia and angular speed must increase.

It is given that stars originate as large bodies of slowly rotating gas.  Because of gravity, these clumps of gas slowly decrease in size.

We need to determine the angular speed of a star as it shrinks.

Angular momentum is conserved for the gas.

The product of I and omega remains constant. So, as cloud shrinks in size, moment of inertia decreases. Hence, there must be increase in angular speed.

So, we can say that as cloud shrink in size, there is decrease in moment of inertia and angular speed must increase.

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The factory worker need to know is the state of the material at room temperature and atmospheric pressure.

Matter is anything that has mass and occupy space. Everything around is composed of matter. The material can easily be classified by considering the state of matter in which the material is found at room temperature and atmospheric pressure.

Hence, all the factory worker need to know is the state of the material at room temperature and atmospheric pressure. This will tell us whether it is a liquid, solid or gas.

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Answer:

2 m/s

Explanation:

Applying,

The law of conservation of momentum

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')............... Equation 1

Where m = mass of the first freight car, m' = mass of the second freight car, u = initial velocity of the first freight car, u' = initial velocity of the second freight car, V = final combined velocity/ speed.

make V the subject of the equation

V = (mu+m'u')/(m+m')........... Equation 2

From the question,

Given: m = 1234 kg, m' = 2468 kg, u = 6 m/s, u' = 0 m/s (at rest)

Substitute these values into equation 2

V = [(1234×6)+(2468×0)]/(1234+2468)

V = 7404/3702

V = 2 m/s

Answer:

The time taken for the airplane to cover the distance is 15 minutes.

Explanation:

Given;

velocity of airplane, u = 800 km/h

distance traveled by the airplane, s = 200 km

The time of this motion is given by;

s = ut + ¹/₂at²

at constant velocity, acceleration, a = 0

s = ut

t = s / u

t = (200 km) / (800 km/h)

t = 0.25 hour = 15 mins

Therefore, the time taken for the airplane to cover the distance is 15 minutes.

After considering the given data we conclude that the wavelength of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2 is approximately 102.55 nm.

To evaluate the wavelength (in nm) of visible light emitted by a hydrogen atom when its excited electron drops from n = 6 to n = 2, we can apply the Rydberg formula:
\(1/\lambda = R(1/n_1^{2} - 1/n_2^{2} )\)
Here:
λ = wavelength of the emitted light
R = Rydberg constant \((1.097 *10^7 m^{-1} )\)
\(n_1\) and \(n_2\) = initial and final energy levels of the electron
Applying substitution of the given values, we get:
\(1/lambda = (1.097 * 10^7 m^{-1} )(1/6^{2} - 1/2^{2} )\)
Evaluating for λ, we get:
λ = 102.55 nm
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Answer:

i would help but im just as confused. sorry.

The correct answer is A) Less than 1 million years

Explanation:

A continental ice sheet is a massive layer of ice that covers thousands of kilometers. Nowadays, these can only be found in zones such as Antarctica but millions of years ago these were more common. Indeed, a continental ice sheet known as the Laurentide ice sheet covered Canada, Greenland, and some zones in the U.S. including New York, this ice sheet first formed around 2.5 million of years ago and changed over time as this covered more or less kilometers due to growth and melting cycles. However, around 20,000 years ago the ice sheet began to definitely retreat due to higher temperatures, and now is reduced to Greeland. Thus, this ice sheet retreat from New York State less than 1 million years ago because it occurred between 20,000 and 8,000 years ago.

State mandates, known as renewable portfolio standards (RPS), are the primary drivers in the deployment of clean energy at utility scale.

Renewable portfolio standards (RPS) are regulations that require utilities to obtain a certain percentage of their electricity from renewable energy sources. These mandates are established at the state level and serve as a key policy tool to promote the development and deployment of clean energy technologies.

By setting specific targets for renewable energy generation, RPS create a market demand for clean power and incentivizes utilities to invest in renewable projects such as solar, wind, and hydroelectric power. This has led to significant growth in the renewable energy sector, contributing to reduced greenhouse gas emissions and a more sustainable energy mix.

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the calculated values for magnetic flux density (B) are as follows:

a) At a point with \(\(r = \frac{b}{2}\): \(\mathbf{B}\\= \mu_0 \cdot a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{8}\)\)

b) At a point with \(\(r = \frac{3b}{2}\): \(\mathbf{B}\)

\(= \mu_0 \cdot a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{2}\)\)

To find the magnetic flux density (B) at a point with a given distance (r) from the central axis of the wire, we can apply Ampere's Law in integral form.

According to Ampere's Law, the line integral of the magnetic field around a closed loop is equal to the permeability of free space (μ₀) multiplied by the total current passing through the loop.

The formula for Ampere's Law in integral form is:

\(\[\oint \mathbf{B} \cdot d\mathbf{l} = \mu_0 I_{\text{enc}}\]\)

where:

\(\(\mathbf{B}\)\) is the magnetic field vector,

\(\(d\mathbf{l}\)\) is an infinitesimal length element along the closed loop,

\(\(\mu_0\)\) is the permeability of free space \((4\pi \times 10^{(-7)} Tm/A)\),

\(\(I_{\text{enc}}\)\) is the total current passing through the closed loop.

For a cylindrical wire carrying a current with a variable current density \(\(\int(r)\)\), the enclosed current within a circular loop of radius r is given by:

\(\(I_{\text{enc}} = \int_0^r \int(r) \cdot 2\pi r \, dr\)\)

Now, let's calculate the magnetic flux density at the given points:

a) At a point with \(\(r = \frac{b}{2}\)\):

Substituting\(\(r = \frac{b}{2}\)\) into the expression for \(\int(r)\):

\(\(\int\left(\frac{b}{2}\right) = a\mathbf{a}_z \int_0/b^2 \, r^2 \, dr\)\)

Integrating the expression:

\(\(\int\left(\frac{b}{2}\right) = a\mathbf{a}_z \int_0^{b/2} \frac{r^2}{b^2} \, dr\)

\(= a\mathbf{a}_z \left[\frac{r^3}{3b^2}\right]_0^{b/2}\)\)

\(\(\int\left(\frac{b}{2}\right) = a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{(b/2)^3}{b^2}\)\)

\(\(\int\left(\frac{b}{2}\right) = a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b^3}{2^3 \cdot b^2}\)\)

\(\(\int\left(\frac{b}{2}\right) = a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{8}\)\)

Therefore, at \(\(r = \frac{b}{2}\)\), the magnetic flux density (B) is given by:

\(\(\mathbf{B} = \mu_0 \cdot \int\left(\frac{b}{2}\right)\)\)

\(\(\mathbf{B} = \mu_0 \cdot a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{8}\)\)

b) At a point with \(r = \frac{3b}{2}\):

Following the same steps as above, we substitute \(\(r = \frac{3b}{2}\)\) into the expression for \(\(\int(r)\)\) and integrate to find:

\(\(\int\left(\frac{3b}{2}\right) = a\mathbf{a}_z \cdot \\)

\(frac{1}{3} \cdot \frac{b}{2}\)\)

Therefore, at \(\(r = \frac{3b}{2}\)\), the magnetic flux density (B) is given by:

\(\(\mathbf{B} = \mu_0 \cdot \int\left(\frac{3b}{2}\right)\)\)

\(\(\mathbf{B} = \mu_0 \cdot a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{2}\)\)

Hence, the calculated values for magnetic flux density (B) are as follows:

a) At a point with \(\(r = \frac{b}{2}\): \(\mathbf{B} = \mu_0 \cdot a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{8}\)\)

b) At a point with\(\(r = \frac{3b}{2}\): \(\mathbf{B} = \mu_0 \cdot a\mathbf{a}_z \cdot \frac{1}{3} \cdot \frac{b}{2}\)\)

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Answer:

Arsenic

Explanation:

Arsenic is in group 5 and period 4. Group numbers tell us the number of valence electron and period number tells us the number of shells in an element.

Answer:

Thermal equilibrium

Explanation:

Two systems are said to be in thermal equilibrium when there is no further exchange of thermal energy between them. At thermal equilibrium, these systems possess equal temperature.

Thermal energy is transferred between objects of varying temperatures or between a system and the surrounding. The thermal energy is transferred from the object with higher temperature (hotter) to the one with lower temperature (colder) until a state of equilibrium is attained.

In the case of the coffee and the environment, if the coffee is at higher temperature than the surrounding, it loses heat energy to the surrounding until both of them are now at the same temperature. Conversely, if the coffee has a lower temperature than the surrounding, it gains thermal energy from the surrounding until thermal equilibrium is achieved.

Answer:

\(T=62.9*10^{-9}\)

Explanation:

From the question we are told that:

Index of refraction of Rinestones \(\gamma_1 =1.5\)

Index of refraction of silicon \(\gamma_2 =2.0\)

Wavelength  \(\lambda=576nm=576*10^{-9}\)

Let each layer have thickness T

Therefore

Total Thickness =2T

Generally the equation for  Constructive interference is mathematically given by

\(2T=(m+0.5)\frac{l\lambda}{\gamma_2}\)

Where

 \(M=0\)

 \(2T=(0+0.5)\frac{576*10^{-9}}{2*2.0}\)

 \(T=62.9*10^{-9}\)

Answer:

physical change

Explanation:

Physical change are changes affecting the form of a chemical substance, but not its chemical composition. Examples of physical change: melting, freezing, shape, size, color...

Answer:

It is physical change

Explanation

Because it didn't change the substances

After the wood is being cut into pieces it cant still be called wood