Aerotron Electronics is considering purchasing a water filtration system to assist in circuit board manufacturing. The system costs $32,000. It has an expected life of 7 years at which time its salvage value will be $5,000. Operating and maintenance expenses are estimated to be $2,000 per year. If the filtration system is not purchased, Aerotron Electronics will have to pay Bay City $13,000 per year for water purification. If the system is purchased, no water purification from Bay City will be needed. Aerotron Electronics must borrow 1/2 of the purchase price, but they cannot start repaying the loan for 2 years. The bank has agreed to 3 equal annual payments, with the 1st payment due at the end of year 2. The loan interest rate is 8.5 % compounded annually. Aerotron electronics’ MARR is 12.5 % compounded annually.

Required:

a. What is the present worth of this investment? (Carry all interim calculations to 5 decimal places and then round your final answer to the nearest dollar. The tolerance is £10.)
b. What is the decision rule for judging the attractiveness of investments based on present worth?
c. Should Aerotron Electronics buy the water filtration system?

Answer:

What ! you are an Engineer and I am a High school why are You in my feed..!!

(a) The pressure and volume of the third state point located midway between the first two state points will be approximately 35 Bar and 400 li, respectively.

(b) The pressure and volume of the state point located at the junction of the two legs of the right triangle will be approximately 40 Bar and 250 li, respectively.

(a) To find the pressure and volume of the third state point, we can use the concept of linear interpolation. Since the two given state points are joined by a straight line, we can determine the pressure and volume at the midpoint by taking the average of the corresponding values of the two points. Thus, the pressure at the third state point is (60 + 10)/2 = 35 Bar, and the volume is (100 + 700)/2 = 400 li.

(b) In a right triangle, the hypotenuse represents the straight line joining the two state points. By using the Pythagorean theorem, we can calculate the length of the hypotenuse, which corresponds to the pressure and volume at the junction of the two legs. The difference in pressure between the two state points is 60 - 10 = 50 Bar, and the difference in volume is 700 - 100 = 600 li. Treating these differences as the legs of a right triangle, we can calculate the hypotenuse length using the theorem. The pressure at the junction point is given by sqrt((40^2) + (50^2)) = 40 Bar, and the volume is sqrt((250^2) + (600^2)) = 250 li.

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The minimum direct-burial depth for rigid metal conduit containing a 480-volt circuit not encased in concrete and not subject to vehicular traffic is 24 inches.

Rigid metal conduit (RMC) is a thin-walled threaded tubing that is made of galvanized steel or stainless steel. Rigid metal conduit is often used as a tubing raceway in the installation of electrical wiring in commercial and industrial buildings. RMC is one of the most durable electrical conduit materials available, as it is both rugged and corrosion resistant.

The minimum direct-burial depth for rigid metal conduit containing a 480-volt circuit not encased in concrete and not subject to vehicular traffic is 24 inches.

The purpose of direct burial is to provide protection and stability to electrical wiring and conduit while also preventing contact with people and animals.

Direct burial depths are frequently specified by electrical codes.

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A light weight vehicle traveling 50 mph can stop in approximately 200 feet.

The break system of a car is composed by several items that are always working together to slow down and bring a vehicle to a complete stop. It also has the function of keeping the car stationary when it is parked. In general, this system has two manual activation modes: the lever and the pedal, with the exception of vehicles adapted for people with disabilities.

Most vehicles today use the disc brake system. Disc brakes work by using pads, which are held inside a hydraulic caliper, receiving pressure to brake. Such pads generate friction on a disc, which makes the vehicle stop permanently.

The drum brake is another type, being older and dependent on the famous linings to cause friction in the wheel and stop the vehicle. A hydraulic cylinder makes the plies move inside the drum, which is a hollow part fastened with screws and attached to the wheels. This type of brake is on the rear wheels, for the most common models.

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The solution to the diameter asked in the question is 35.8 ft and the wire loading rate is 0.000011 gpd/ft. We can calculate it in the following manner.

To determine the diameter required for the clarifiers:

a. We can start by calculating the total surface area needed for both clarifiers. Since both are equally sized, we can divide the flowrate in half and use it for each clarifier:

2.0 mgd / 2 = 1.0 mgd

Convert mgd to gpd:

1.0 mgd x 1,000,000 g/mgd = 1,000,000 gpd

Calculate the surface area needed for one clarifier:

1,000,000 gpd / (800 gpd/ft2) = 1,250 ft2

Since the clarifiers are upflow, we can assume a height of about 10-12 feet. Let's use 12 feet for this calculation.

The volume of one clarifier is then:

1,250 ft2 x 12 ft = 15,000 ft3

To determine the diameter of the clarifiers, we can use the formula for the volume of a cylinder:

V = πr²h

Where V is the volume, r is the radius, and h is the height.

Solving for r:

r = √(V/πh) = √(15,000 ft3 / (π x 12 ft)) = 17.9 ft

The diameter is twice the radius, so:

diameter = 2 x 17.9 ft = 35.8 ft

b. To determine the wire loading rate, we need to calculate the total length of wire required for one clarifier, and then divide by the flow rate. We can use the equation:

Q = CLH¹°⁵

Where Q is the flow rate (gpd), C is a constant (we'll use 3.33 for rectangular wires), L is the length of the weir (ft), and H is the height of the weir (ft).

Solving for L:

L = Q / (CH¹°⁵) = 1,000,000 gpd / (3.33 x 12^¹°⁵ ft) = 5.5 ft

Since there are two clarifiers, the total length of wire required is:

2 x 5.5 ft = 11 ft

Dividing by the flow rate:

11 ft / 1,000,000 gpd = 0.000011 gpd/ft

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(a) To find the time when the velocity is again zero, we set the velocity equal to 0 and solve for t:

0 = v0 + at = 9t - 3t^3

Solving for t, we find that t = ±1.

(b) To find the position and velocity when t = 4 s, we first need to find the velocity equation by integrating the acceleration equation:

v = ∫a = ∫(9 - 3t^2)dt = 9t - t^3 + C

Using the initial condition v(0) = 0, we find C = 0 and

v(t) = 9t - t^3

Next, we integrate v(t) to find the position equation:

x = ∫v = ∫(9t - t^3)dt = 3t^2 - t^4 + C

Using the initial condition x(0) = 5, we find C = 5 and

x(t) = 3t^2 - t^4 + 5

Evaluating x(t) and v(t) at t = 4 s, we have:

x(4) = 3(4^2) - 4^4 + 5 = 51

v(4) = 9(4) - 4^3 = -36

(c) To find the total distance travelled by the particle from t = 0 to t = 4 s, we need to find the distance between the initial and final positions:

d = x(4) - x(0) = 51 - 5 = 46 ft

So the total distance travelled by the particle from t = 0 to t = 4 s is 46 ft.

Answer:

d) "Napoleon Declares Himself Holy Roman Emperor"

Explanation:

The French Revolution is defined as a period of the major social upheaval which began in the year 1787 and lasted till year 1799. This revolution completely redefined the the very nature of the political power in France. and also the relationship between the rulers of France and the people they governed.

The 1789 Estates-General was the 1st meeting since year 1614 of the French Estates-General. It is a general assembly which represents the French estates of  realm.

During the French revolution was at peak, the National Assembly issued the Declaration of the rights of the man to the public.

Maximilien Robespierre was considered to be one of the most influential figure and most important statesman during the French Revolution.

Thus all the options (a),(b) and (c) are headlines about the French Revolution, except option (d).

The dealer would accept any offer that is at least 500 dollars over the dealer's cost The algorithms for your query are 1) Declare list Price as a double READ list Price• Declare and initialize most-0.85*list Price+500.0.

A set of rules is a method used for fixing a hassle or acting a computation. Algorithms act as a specific listing of commands that behavior certain moves grade by grade in both hardware- or software-primarily based totally routines. Algorithms are broadly used during all regions of IT.

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The speed of the rotor field relative to the stator rotating field is also equal to the slip speed, which is 36 RPM.

(a) The synchronous speed (N_s) of the motor can be determined by the formula:

N_s = 120f / P

Where:

f = frequency (60 Hz)

P = number of poles (6)

Substituting the values, we get:

N_s = (120 * 60) / 6 = 1200 RPM

The slip (S) is given as 3%, or 0.03. The speed of the motor (N) can be determined by the formula:

N = N_s * (1 - S)

Substituting the values, we get:

N = 1200 * (1 - 0.03) = 1164 RPM

The motor is rotating in the same direction as the rotating field, because the slip is positive.

(b) The rotor frequency (f_r) can be determined by the formula:

f_r = S * f

Substituting the values, we get:

f_r = 0.03 * 60 = 1.8 Hz

(c) The speed of the stator field is equal to the synchronous speed. Therefore, it is 1200 RPM.

(d) The speed of the air gap field is also equal to the synchronous speed. Therefore, it is 1200 RPM.

(e) (i) The speed of the rotor field relative to the rotor structure is zero, because the rotor field is stationary in the reference frame of the rotor.

(ii) The speed of the rotor field relative to the stator structure is equal to the slip speed, which is the difference between the synchronous speed and the rotor speed. Therefore, it is 1200 - 1164 = 36 RPM.

(iii) The speed of the rotor field relative to the stator rotating field is also equal to the slip speed, which is 36 RPM.

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The total present worth is $19,783.01

The present worth of a series of cash flow is the value of the cash flows in year 0 (today)

Cash flow in year 0 = 5330

Cash flow in year 1 = 0

Cash flow in year 2 = 0

Cash flow in year 3 = 13075 / (1.02)^3 = 12,320.86

Cash flow in year 4 = 2308 / (1.02)^4 = 2,132.24

Present worth = $19,783.01

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Answer:

silos to store grains

Explanation:

I got it from PLATO... hope this helps...

A broad range of subjects are included in the culinary arts. Food science and nutrition, ingredient quality, seasonality, flavors and textures, presentation and plate layout, and more are some of these. There are numerous specialties, sub-niches, and job titles that fall within this broad category.

Additionally, to help students become more well-rounded cooks, a variety of cooking techniques, numerous recipes, new ingredients, and various flavor profiles are presented to them.

The term “culinary arts” is used to refer broadly to the processes involved in preparing, cooking, plating, presenting, and serving food. It relates to meals and the goods, not sweets or breads. That make up a meal, such as appetizers, side dishes, and main courses.

Therefore, Students who pursue a culinary education have the opportunity to study under several of the industry's best chefs.

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Critical load Fcr or buckling load is the value of load that causes the phenomenon of change from stable to unstable equilibrium state.

With that beign said, first it is neessary to calculate the moment of inercia about the x-axis:

\(Ix= \frac{db^3}{12}\\ Ix = \frac{2.(4)^3}{12} = 10.667in\)

Then it is necessary to calculate the moment of inercia about the y-axis:

\(Iy = \frac{db^3}{12}\\ Iy = \frac{4.(2)^3}{12} = 2.662in\)

Comparing both moments of inercia it is possible to assume that the minimun moment of inercia is the y-axis, so the minimun moment of inercia is 2662in.

And so, it is possible to calculate the critical load:

\(Pc\gamma = \frac{2046\pi ^2E.I}{L^2} \\Pc\gamma= \frac{2046.\pi ^2.(1,6.10^3.10^3).2662}{(10.12)^2} \\Pc\gamma= 5983,9db\)

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As the temperature of the material increases, the potential energy of the molecules increases. Thermal expansion occurs due to changes in temperature, and interatomic distances increase as potential energy increases.

Thermal expansion is used in a variety of applications such as rail buckling, engine coolant, mercury thermometers, joint expansion, and others.

It is to be noted that an application of the concept of liquid expansion in everyday life concerns liquid thermometers. As the heat rises, the mercury or alcohol in the thermometer tube moves in only one direction. As the heat decreases, the liquid moves back smoothly.

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The code statements have a syntax error because "integer" is not a valid data type in most programming languages. I will assume that "integer" is meant to represent the "int" data type. Also, the capitalization of "Z" is incorrect.

Assuming these corrections, the correct code statements and the output will be:

int x = 34.54, y = 20, z = -5;

System.out.println(y > 50 && 2 > 10 || x > 30);

The output of this code will be:

true

Here's how the output is obtained:

The first expression y > 50 is false because y is 20, which is not greater than 50.

The second expression 2 > 10 is false because 2 is not greater than 10.

The third expression x > 30 is true because x is 34, which is greater than 30.

The && operator has higher precedence than the || operator, so the first two expressions are evaluated first. Since false && false is false, the third expression is evaluated next.

The expression false || true is true because at least one of the operands is true.

Therefore, the overall result of the expression is true.

Answer:

15x

Explanation:

The LER of the same wing is 0.21 using the chord values.

In agriculture, the term "land equivalent ratio" refers to the proportion of land area needed for monoculture (single-crop farming) to yield the same amount of yield as intercropping (polyculture).

The FAO defines the land equivalent ratio (LER) as the ratio of the area used for sole cropping to the area used for intercropping in order to produce an equal amount of yield at the same management level. The result is the sole-crop yields multiplied by the sum of the intercropped yield fractions.

We must use a chord, so I'm assuming that it is 0.045 m in length.

The formula provides the Area.

Area = span × chord

Area = 0.245 × 0.045

Area = 0.011 m²

We then divide the area obtained by the glider weight we obtain the final result.

LER = area / weight

LER = 0.011 / 0.0523

LER = 0.21

As a result, the Lee of the same wing is 0.21 using the chord values.

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Answer:

the pitch point im pritty sure what is is

The point of contact of two pitch circles of mating gears is called the pitch point.

A pitch point is where two pitch circles frequently come into touch. A common point of contact between two pitch circles of mating gears is called a pitch point. The pitch circle and is centered on the top of the teeth. Dedendum circle, also known as the root circle, is the circle traced through the base of the tooth.

The pressure angle, often known as the “tooth shape,” is the angle at which pressure from one gear's tooth is transferred to another gear's tooth. Pure rolling motion will occur at pitch point.

Therefore, it is pressure point.

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Answer:

thank you

Explanation:

have a nice day

Answer:

thankd

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On average, the percentage of manufactured ball bearings that will be scrapped is 4.56%.

An example of a rolling element bearing is a ball bearing, which has three major purposes in addition to facilitating motion: carrying weights, lowering friction, and positioning moving machine elements.

Note that:

x1 = 3-0.01 = 2.99

x2 = 3+0.01 = 3.01

So, It can be scrapped by:

1−P(2.99 < Z <3.01)= 1−P (2.99 −3/ 0.005 < Z < 2.99+30.00/5)

=1−P(2.99 − 3/0.005 <  Z <2.99 + 3/0.005)= 1 − P ( −2 < Z <2)

=1−(P (Z < 2.0) − (P (Z> − 2.0)) = ( P (Z > 2.0) + P( Z < −2.0)=

2 x 0.0228 = 0.0456

Therefore, the Answer will be 4.56% of the manufactured ball bearings need to be scrapped.

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Answer:

Tires or wheels? I think this is the answer. ^_^

Explanation:

To ionize the air at the surface of the wires in an electrostatic air ionizer with given dimensions a = 0.1 mm and h = 5 mm, and an electric field intensity Ec = 3.0 MV/m, you must apply a voltage of 6000 V across the wires.

The electric field intensity Ec between the two wires can be calculated using the formula

Ec = V/h,

where V is the voltage and h is the distance between the wires.

Given the electric field intensity Ec = 3.0 MV/m (3.0 x 10^6 V/m) and h = 5 mm (5 x 10^-3 m), we can find the voltage V by rearranging the formula:

V = Ec * h.

Substituting the values, V = (3.0 x 10^6 V/m) * (5 x 10^-3 m) = 6000 V.

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The estimated drag force on the actual golf ball will be equal to the force on the replica.

When the student develops a replica of the golf ball that is 5 times smaller in diameter, the ratio of their diameters is 1:5. Let's denote the diameter of the actual golf ball as D and the diameter of the replica as D/5.

The student sets the wind speed in the wind tunnel to be 5 times larger than the actual speed of the golf ball. Let's denote the actual speed of the golf ball as U and the wind speed in the wind tunnel as 5U.

To estimate the drag force on an object moving through a fluid, we can use the drag equation, which states that the drag force (Fd) is proportional to the square of the velocity (v) and the reference area (A), and also depends on the drag coefficient (Cd):

Fd = 0.5 ˣ Cd * ρ ˣ A ˣ v²

In this case, the golf ball and the replica have the same shape and design, so we can assume that their drag coefficients are similar (Cd_actual ≈ Cd_replica).

The reference area (A) is proportional to the square of the diameter, so A_actual = π ˣ (D/2)² and A_replica = π ˣ ((D/5)/2)².

Now, let's compare the drag forces. Since the drag coefficient is similar and the reference area is proportional to the square of the diameter, the only difference lies in the velocity term.

Therefore, the estimated drag force on the actual golf ball will be equal to the force on the replica.

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Answer: True

Explanation:

Oil oxidation is a process that all oil goes through and involves a series of chemical reactions between compounds in the oil and oxygen that lead to the quality of the oxygen falling. In other words, oxidation degrades oil.

Even though this is a process that all oil goes through and one that cannot be stopped, it's pace can be reduced. One way of doing this is by adding oxidation inhibitors which are antioxidant additives that work to slow the degradation  of the oil stock by oxidation.

Answer:

12 32

Explanation:

True. The record source property is an important property of forms in Access. It specifies the table or query that the form is based on. This property can be set to a table name, a query name, or a SQL statement.

The record source property specifies the table or query that a form is based on. This property can be set to a table name, a query name, or a SQL statement. When the record source property is set to a table name, the form will display all of the records in the table. When the record source property is set to a query name, the form will display the results of the query. When the record source property is set to a SQL statement, the form will display the results of the SQL statement.

For example, the following code sets the record source property of a form to the Customers table:

Code snippet

Form1.RecordSource = "Customers"

The following code sets the record source property of a form to a query that selects all of the customers who have placed an order in the past month:

Code snippet

Form1.RecordSource = "SELECT * FROM Customers WHERE OrderDate >= '2023-04-01'"

The following code sets the record source property of a form to a SQL statement that joins the Customers and Orders tables:

Form1.RecordSource = "SELECT * FROM Customers JOIN Orders ON Customers.CustomerID = Orders.CustomerID"

The record source property is an important property of forms in Access. It specifies the table or query that the form is based on. This property can be set to a table name, a query name, or a SQL statement.

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Answer:

a

Explanation: