Adding a pet warming pad to the floors so cats can lay on it a

answers:
radiation
convection
conduction

Answer:

10-10x10+10=10-100+10=20-100=-80

Answer:

10 is the answer

Explanation:

10-10=0x10=0+10=10

Answer:

Below

Explanation:

384 400 km / 300 000 km/s = 1.28 seconds

Answer:

(a) Ascend at 0.8 vertical meter/meter

(b) Descend at -0.2·√2 vertical meter/meter

(c) In the (-0.6, -0.8) direction. The path begins at 45° to the horizontal

Explanation:

The given equation of the shape of the hill is z = 2000 - 0.005·x² - 0.01·y²

The current location = (60, 40, 1966)  

The direction of the positive x-axis = east

The direction of the positive y-axis = north

(a) Walking due south = Reducing the y-value 40

From the equation, the elevation varies inversely with the motion towards the north

Therefore, walking south increases the elevation, and we ascend

The rate is given by the partial derivative at in the -j direction, which is 0.02

The rate is therefore 40 × 0.02 = 0.8

(b)The unit vector in the northwest direction u = 1/√2·(-1, 1)

∴ The rate = (-0.01(60), -0.02(40))·u = (-0.6, -0.8)·1/√2·(-1, 1) = -0.2·√2

Therefore we descend

(c) The slope is largest in the grad of the function at the point (60, 40) which is given as follows;

d(2000 - 0.005·x² - 0.01·y² )/dx, d(2000 - 0.005·x² - 0.01·y² )/dy = (-0.6, -0.8)

Therefore, the direction is tan⁻¹(-0.8/-0.6) ≈ S 36.87° W

The slope =(√((-0.4)² + (-0.8)²) = 1

Therefore, the angle is 45° to the horizontal.

Answer:

Maybe A.... I'm not sure

Explanation:

Most short-period comets do not have randomly oriented orbits because c. they formed in the Kuiper Belt, a belt-shaped region in the plane of the solar system.

The Kuiper Belt is a region beyond the orbit of Neptune that contains a vast number of small icy bodies, including comets. Short-period comets are comets that have orbital periods of less than 200 years and are believed to originate from the Kuiper Belt. The Kuiper Belt is situated in the same plane as the solar system, which means that the comets formed within this region generally have orbits that are aligned with the plane of the solar system. The formation process and gravitational interactions within the Kuiper Belt result in comets acquiring orbits that are relatively stable and confined to the plane of the solar system. the sun's gravity, solar wind, drag of their tails in the solar wind, or being originally ejected from the asteroid belt, may have some influence on comets, but they do not directly explain why most short-period comets have non-randomly oriented orbits. The primary factor that determines the orientation of their orbits is the formation within the Kuiper Belt.

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Answer:

Larva and pupa is present in complete metamorphosis while nymph is present instead of larva and pupa in incomplete metamorphosis.

Explanation:

Complete metamorphosis has four stages i. e. egg, larva, pupa, and adult while the incomplete metamorphosis has three stages i. e. egg, nymph, and adult. Grasshopper, dragonfly, cicada and cockroach have incomplete metamorphosis while ladybug , housefly, butterfly  and honeybee have complete metamorphosis. Both type of insects lay eggs and after hatching a baby insect comes out called larva. After sometime this larva transforms from immature to mature, this stage is known as pupa. After pupa, the insect converts into an adult which is ready for reproduction. Nymph is a stage that comes in place of larva and pupa in incomplete metamorphosis. in this stage, the insect is small in size and lack of wings but in adult stage the wings appear.

Answer:

The lever is a movable bar that pivots on a fulcrum attached to a fixed point. The lever operates by applying forces at different distances from the fulcrum, or a pivot. As the lever rotates around the fulcrum, points farther from this pivot move faster than points closer to the pivot.

IF HELPED MARK AS BRAINLIEST

(a) The magnitude of the maximum velocity of the piston is approximately 18.85 m/s.

(b) The magnitude of the maximum acceleration of the piston is approximately 113.10 m/s².

To calculate the maximum velocity of the piston, we can use the formula:

v_max = ω * A

Where:

v_max is the maximum velocity,

ω is the angular velocity,

A is the amplitude of the motion.

Given:

The engine is running at the rate of 3,600 rev/min, which is equivalent to 60 rev/s (since there are 60 seconds in a minute).

The amplitude of the motion is ±5.00 cm, which is 0.05 m.

The angular velocity can be calculated as:

ω = 2π * f

Where:

ω is the angular velocity,

π is a mathematical constant (approximately 3.14159),

f is the frequency.

Since the frequency is 60 rev/s, we have:

ω = 2π * 60 = 120π rad/s

Plugging the values into the formula for maximum velocity:

v_max = (120π rad/s) * (0.05 m)

    ≈ 18.85 m/s

Therefore, the magnitude of the maximum velocity of the piston is approximately 18.85 m/s.

To calculate the maximum acceleration of the piston, we can use the formula:

a_max = ω² * A

Plugging the values into the formula:

a_max = (120π rad/s)² * (0.05 m)

    ≈ 113.10 m/s²

Therefore, the magnitude of the maximum acceleration of the piston is approximately 113.10 m/s².

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Answer:

1) 15,328

2) 54.528

3) 375

4)0.96362530413

\(\sf{ [26.84, 26.88]  }\)

Explanation:

The precision of a balance is ±0.02 g.

The accepted value for a measurement is 26.86 g.

The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.

To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).

The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.

To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.

Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.

By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.

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The frequency of the light source is 1.5 x 10¹⁵ Hz.

The frequency of the light source is determined using the following equations;

c = fλ

where;

c is speed of light

f is the frequency

λ is the wavelength

f = (3 x 10⁸) / (2 x 10⁻⁷)

f = 1.5 x 10¹⁵ Hz

Thus, the frequency of the light source is 1.5 x 10¹⁵ Hz.

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Answer:

Option D. It quadruples

Explanation:

Let the initial voltage be V.

Let the initial power be P.

We shall determine the final power of the circuit as follow:

Initial voltage (V₁) = V

Initial power (P₁) = P

Final voltage (V₂) = double the initial voltage = 2P

Final power (P₂) =?

NOTE: Resistor (R) is constant

P = V² / R

Cross multiply

PR = V²

Divide both side by P

R = V² / P

Thus

V²₁ / P₁ = V²₂ / P₂

V² / P = (2V)² / P₂

V² / P = 4V² / P₂

Cross multiply

V² × P₂ = P × 4V²

Divide both side by V²

P₂ = P × 4V² / V²

P₂ = P × 4

P₂ = 4P

Thus, the power will be four times the initial power i.e quadruple.

Substituting the values, we getr = [(9.11 × 10⁻³¹ kg)(1.11 × 10⁷ m/s)]/[(1.6 × 10⁻¹⁹ C)(200 mT)]r = 3.16 × 10⁻⁴ mTherefore, the answer is 1.11 x 10^7 m/s, 3.16 x 10^-4 m.

(a) Speed of the electronThe formula for potential energy isPE = qVWhere q is the charge and V is the potential difference. The electron is negatively charged, and its charge is 1.6 × 10⁻¹⁹ C.Therefore, PE = (1.6 × 10⁻¹⁹ C)(350 V)PE = 5.6 × 10⁻¹⁷ JThe formula for kinetic energy isKE = (1/2)mv²where m is the mass and v is the velocity of the electron. The mass of the electron is 9.11 × 10⁻³¹ kg.Using the law of conservation of energy, we can equate the kinetic energy of the electron with the potential energy it gains when accelerated by the potential difference.

Kinetic energy of the electron = Potential energy gainedKE = PEKE = 5.6 × 10⁻¹⁷ Jv² = (2KE)/mv² = (2(5.6 × 10⁻¹⁷ J))/(9.11 × 10⁻³¹ kg)v² = 1.23 × 10¹⁷v = √(1.23 × 10¹⁷)v = 1.11 × 10⁷ m/s(b) Radius of the pathThe formula for the radius of the path of a charged particle moving in a magnetic field isr = (mv)/(qB)where r is the radius, m is the mass of the charged particle, v is its velocity, q is its charge, and B is the magnetic field strength.Substituting the values, we getr = [(9.11 × 10⁻³¹ kg)(1.11 × 10⁷ m/s)]/[(1.6 × 10⁻¹⁹ C)(200 mT)]r = 3.16 × 10⁻⁴ mTherefore, the answer is 1.11 x 10^7 m/s, 3.16 x 10^-4 m.

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Answer:

1. 360/6=60 Kilometers per hour

2. 120/3=40 Kilometers per hour

Answer:

no

Explanation:

Answer:

Elisa

Explanation:

I I agree with her because when you're at the top of the ramp you are going down and you are going to go down in an exact fast speed so you do have more energy and momentum at the top of the ramp

Answer:

square metre is the answer

Explanation:

Hope this helps u

Crown me as brainliest:)

Answer:

\(\huge\boxed{\sf F=31.88 \ N}\)

Explanation:

Mass = m = 0.15 kg

Velocity = v = 17 m/s

Time = t = 0.08 s

Force = ?

\(\displaystyle F=\frac{mv}{t}\)

\(\displaystyle F=\frac{(0.15)(17)}{0.08} \\\\F=\frac{2.55}{0.08} \\\\F=31.88 \ N\\\\\rule[225]{225}{2}\)

Based on the given information, Gary conducted an experiment to test the effect of lighting on participants' ability to focus. He compared three different lighting conditions: bright lighting, low lighting, and neon lighting. The results showed a significant effect, with an F-value of 5.6 and p-value less than 0.05. Now we need to determine what Gary can conclude from these results.

The F-value and p-value are indicators of statistical significance in an analysis of variance (ANOVA) test. In this case, the F(2, 90) value suggests that there is a significant difference in participants' ability to focus across the three lighting conditions.

Since the p-value is less than 0.05, Gary can reject the null hypothesis, which states that there is no difference in focus ability between the different lighting conditions. Therefore, he can conclude that the type of lighting does have some effect on focus.

However, the specific nature of the effect cannot be determined solely based on the information provided. The mean values indicate that participants performed best under bright lighting (M = 10), followed by low lighting (M = 5), and neon lighting (M = 4). This suggests that bright lights may make it easier to focus compared to low lights or neon lights, but further analysis or post-hoc tests would be required to provide a more definitive conclusion.

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A rock climber stands on the top of a 53 m high cliff overhanging a pool of water, so for 3.1 seconds, after which the second stone hit the water.

The overall distance the object covers in a given amount of time is its average speed. The scalar quantity represents the average speed. It does not have direction; it is represented by magnitude.

Average Speed= \(Total\ Distance/ Total\ time\)

According to the question, the given values are :

v₁ = 1.5 m/s

y₂ = 52 m

y₁ = 0 m

Acceleration, a = 9.8 m/s²

Use Formula :

y₂ = y₁ + v₁t + 0.5 at²

52 = 0 + 1.5t + 0.5 (9.8)t²

4.9 t² + 1.5 t - 52 = 0

\(t=-b\frac{+}\ \sqrt{b^2-4ac}/2a\)

t = -1.5 + \(\sqrt{2.25+1019.2}\)/9.8

t = (-1.5 + 31.9)/9.8

t = 3.10 seconds.

Hence, the time period will be 3.10 seconds.

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The distance between second-order fringes for the 720-nm wavelength is 1.18 mm, and for the 650-nm wavelength, it is 1.03 mm.

The distance between second-order fringes for two wavelengths, we can use the formula:

δy = λD/d

Where δy is the distance between adjacent fringes, λ is the wavelength of light, D is the distance from the slits to the screen, and d is the distance between the two slits.

For the 720-nm wavelength, we have:

δy = (720 × 10⁻⁹ m)(1.0 m)/(0.61 × 10⁻³ m) = 1.18 mm

For the 650-nm wavelength, we have:

δy = (650 × 10⁻⁹ m)(1.0 m)/(0.61 × 10⁻³ m) = 1.03 mm

The distance between second-order fringes for the 720-nm wavelength is 1.18 mm, and for the 650-nm wavelength, it is 1.03 mm.

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The height of the building is 42.4 meters.

Let's call the height of the building "h". We can use the following kinematic equations to solve for "h":

For the stone that is dropped from the top of the building:

h = (1/2)gt² (Equation 1)

For the stone that is thrown upwards from the ground:

y = vt - (1/2)gt² (Equation 2)

where;

We know that the two stones meet at exactly 5s after their release. This means that the distance travelled by the stone thrown upwards from the ground is equal to the height of the building, i.e.,

y = h

We can substitute this equation into Equation 2 and rearrange it to solve for "t":

h = vt - (1/2)gt²

h = 20t - (1/2)gt²

t = (2h/g - 20)/(-1) (Equation 3)

Now we can substitute Equation 3 into Equation 1 and solve for "h":

h = (1/2)g((2h/g - 20)/(-1))²

h = (1/2)g(2h/g - 20)²

h = (1/2)g(4h²/g² - 80h/g + 400)

Simplifying this equation by multiplying everything by 2g and moving all the terms to one side, we get:

4h² - 160h - 400 = 0

Solving this quadratic equation using the quadratic formula, we get:

h = (160 ± sqrt(160² + 4(4)(400))) / (2(4))

h = (160 ± sqrt(32,000)) / 8

We can ignore the negative solution, so:

h = (160 + 178.88) / 8

h = 42.4 meters

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(a) The velocities of the steel blocks after impact can be determined using the principle of conservation of linear momentum. According to this principle, the total momentum before the impact is equal to the total momentum after the impact.

The initial velocities of the blocks are given as follows:
Block 1 (0.6 kg): v1i = 2 m/s (to the right)
Block 2 (0.9 kg): v2i = -1 m/s (to the left)
Let's denote the velocities after impact as v1f and v2f for Block 1 and Block 2, respectively.
Applying the conservation of linear momentum:
m1 * v1i + m2 * v2i = m1 * v1f + m2 * v2f
Substituting the given values:
(0.6 kg * 2 m/s) + (0.9 kg * -1 m/s) = (0.6 kg * v1f) + (0.9 kg * v2f)
Now, solve this equation to find the velocities after impact.

(b) The energy lost during impact can be calculated using the coefficient of restitution (e) and the initial and final velocities of the blocks.

The coefficient of restitution (e) relates the relative velocity of separation after the impact to the relative velocity of approach before the impact.
The formula for calculating the energy lost during impact is:
Energy lost = (1/2) * (m1 + m2) * (v1i^2 + v2i^2 - v1f^2 - v2f^2)
Substitute the given values and the velocities after impact obtained from part (a) into this formula to find the energy lost during impact.

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The magnitude of the resulting angular acceleration of the pulley is 8.0 rad/s².

To find the magnitude of the resulting angular acceleration of the pulley, we can use the formula:

α = τ / I

Where α is the angular acceleration, τ is the torque applied to the pulley, and I is the moment of inertia of the pulley.

First, we need to find the torque applied to the pulley. The force applied to the string (12 N) creates a torque by pulling on the pulley, which can be calculated using the formula:

τ = rF

Where τ is the torque, r is the radius of the pulley (0.10 m), and F is the force applied to the string (12 N).

τ = (0.10 m)(12 N) = 1.2 N·m

Now we can use this torque and the moment of inertia of the pulley (0.15 kg·m²) in the formula for angular acceleration:

α = τ / I

α = (1.2 N·m) / (0.15 kg·m²)

α = 8.0 rad/s²

Therefore, the pulley will have an angular acceleration of 8.0 rad/s².

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Answer: 2 half lives

2 half-lives have passed if a sample contains 25% of its original carbon-14.option B is correct.

The act of producing radiation spontaneously is known as radioactivity. This is accomplished by an unstable atomic nucleus that want to give up some energy in order to move to a more stable form.

The half life is found as;

\(\rm N=\frac{N_0}{2^n}\)

Archaeologists use radioactive decay of an isotope of the element carbon. Because it has a fairly short half-life, and is found in anything that was once living.

2 half-lives have passed if a sample contains 25% of its original carbon-14.

Hence,option B is correct.

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Answer:

The manner in which the Earth's movement affect how the Sun is seen is;

The Sun is stationary, but Earth's rotation makes it appear to move East to West across the sky

Explanation:

The Earth's movement affect the way the Sun is seen

The Sun appears to rise in the Eastern part of the sky and continues in motion till the it sets at the Western part of the sky

However, the Sun does not actually move relative to the Earth as seen in the sky. The observed motion of the Sun is due to the counterclockwise  rotation of the Earth about its axis

Therefore, the Earth's movement affect the way the Sun is seen by making the Sun appear to move across the sky from East to West

Answer:

The sun stays still but the rotation of the earth makes it look like it goes east to west.

Explanation: