addictive substances, for which demand is inelastic, are products for which producers can pass higher costs on to consumers.

The final temperature of the combined metals is approximately 31.7°C.

To solve this problem, we can use the principle of heat transfer between two objects in thermal contact, known as the heat equation:

q = m*c*ΔT

where q is the amount of heat transferred, m is the mass of the object, c is its specific heat capacity, and ΔT is the change in temperature.

Assuming that no heat is lost to the surroundings, we can set the heat gained by the iron equal to the heat lost by the gold:

mc*ΔT = m*c*ΔT

where the subscripts 'i' and 'g' refer to iron and gold, respectively.

\(final temperature = \frac{(mi ciTi+mgcgtg)}{(mici+mgcg)}\)

We get

\(final temperature = \frac{(1908*0.45*51.1+10.4*0.13*16.3)}{(19.8*0.45+10.4*0.13)}\)

                                = 31.7°C

As a result, the final temperature of the metals is approximately 31.7°C.

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Answer:ABC4

Explanation:

The charge of a atom is not visible in a formula.

The product formed when the acetal is hydrolyzed with aqueous acid is \(R-CH(OH)-O-CH(OH)-R\)

The product formed when the acetal is hydrolyzed with aqueous acid is two molecules of alchohol  namely  \(R-CH2-OH and R-CH2-OH.\)  This occurs as aqueous acid catalyzes the hydrolysis of the acetal bond, which breaks the bond between the two alcohol groups and releases them as individual molecules.

The hydrolysis of the acetal bond involves the acid protonating the oxygen atom, resulting in the formation of a positively charged oxonium ion. The positively charged oxonium ion then attracts a lone pair of electrons from an adjacent oxygen atom, resulting in the formation of a new bond between the two alcohol groups and the release of the two alcohol molecules.

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Answer:

oxygen (O2) is a molecular element

Explanation:

Molecular compound are chemical compounds that take the form of discrete molecules.

atomic element is an element which occurs independently as atoms and can react with other elements to form a compound

Ionic compounds are the compound which on dissolution form ions in solution

Mixture is the composition of different compounds

Answer:

1. Mg (s) + 2Na+(aq) → 2Na(s) + Mg²⁺(aq)

2. 2K(s) + Cd²⁺(aq) → 2K⁺(aq) + Cd(s)

Explanation:

The net ionic equation of a reaction express only the chemical species that are involved in the reaction:

1. Mg (s) + Na2CrO4 (aq) → 2Na + MgCrO4(aq)

The ionic equation:

Mg (s) + 2Na+(aq) + CrO4²⁻ (aq) → 2Na + Mg²⁺ + CrO4²⁻(aq)

Subtracting the ions that don't change:

2. 2K(s) + Cd(NO3)2(aq) → 2KNO3(aq) + Cd(s)

The ionic equation:

2K(s) + Cd²⁺(aq) + 2NO3⁻(aq) → 2K⁺(aq) + 2NO3⁻(aq) + Cd(s)

Subtracting the ions that don't change:

Answer:

False

Explanation:

Answer:

False

Explanation:

The number of electrons determines the chemical properties.  

Explanation:

.

.

The percent error of the density of silver obtained by the student using the water displacement method can be calculated by comparing the experimental density to the known value.

To calculate the percent error, we use the formula: percent error = [(experimental value - known value) / known value] × 100.

Plugging in the values, we have: percent error = [(9.9 g/cm³ - 10.5 g/cm³) / 10.5 g/cm³] × 100.

Simplifying the expression, we get: percent error = (-0.6 g/cm³ / 10.5 g/cm³) × 100 = -5.71%.

Therefore, the percent error of the density of silver obtained by the student using the water displacement method is approximately -5.71%. The negative sign indicates that the experimental value is lower than the known value, resulting in a negative deviation.

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The acid associated with \(NH_3\) is \(NH_4^+\), with I- is HI, with \(SO_4^{2-}\) is \(HSO_4^-\), with Cl- is HCl, with OH- is \(H_2O\), and with F- is HF.

1. NH3: It is a base that accepts a hydrogen ion (H+) from an acid. \(NH_3 + H^+ --> NH_4^+\). The acid associated with \(NH_3\) is \(NH_4^+\).

2. I-:  is a base that accepts a hydrogen ion (H+) from an acid. \(I^- + H^+ --> HI\) . The acid associated with I- is HI.

3. \(SO_4^{2-}\) : is a base that accepts a hydrogen ion (H+) from an acid. \(SO_4^{2-} + H^+ --> HSO_4^-\). The acid associated with \(SO_4^{2-}\) is \(HSO_4^-\).

4. Cl-: is a base that accepts a hydrogen ion (H+) from an acid. Its conjugate acid is the species formed when Cl- accepts a hydrogen ion (H+). \(Cl^- + H^+ --> HCl\). The acid associated with Cl- is HCl.

5. OH-: It is a base that accepts a hydrogen ion (H+) from an acid. Its conjugate acid is the species formed when OH- accepts a hydrogen ion (H+). \(OH^- + H^+ --> H_2O\). The acid associated with OH- is \(H_2O\).

6. F-:  It is a base that accepts a hydrogen ion (H+) from an acid. \(F^- + H^+ --> HF\).  The acid associated with F- is HF.

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The sample initially contains 1.35mg of Pu-236, the mass of Pu-236 is present after 5.00 years is 0.402mg.

Calculation shown in image below.

The 1/2-life of a radioactive isotope is the amount of time it takes for one-half of of the radioactive isotope to decay. The half-life of a specific radioactive isotope is steady; it's far unaffected by means of situations and is unbiased of the preliminary quantity of that isotope.

information the concept of half of-life is useful for figuring out excretion quotes as well as steady-nation concentrations for any precise drug. different drugs have different half-lives; but, they all follow this rule: after one half of-existence has passed, 50% of the initial drug amount is removed from the body.

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TLC analysis of 2-bromooctane and 2-decene, the best solvent of choice depends on the polarity of the compounds. Water is a polar solvent, while ether is nonpolar.

If the compounds are polar, water would be the better solvent of choice. However, if the compounds are nonpolar, ether would be the better solvent of choice. Therefore, the choice of solvent for TLC analysis of 2-bromooctane and 2-decene would depend on the polarity of the compounds.

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Answer:

0.690g/cm^3

Explanation:

•Mass: 2.331g

•Volume: 3.375 cm^3

One side is 1.5cm.

1.5^3

3.375cm^3

•Density: Mass/Volume

Mass = 2.331g

Volume = 3.375cm^3

2.331g/3.375cm^3

0.690g/cm^3

Answer:

true

Explanation: all matter down to the molecular or even atomic level has a constant vibration and movement. The only time that any matter could stop moving would be at absolute zero.

This problem is giving information about the proton concentrations of three solutions at 25 °C. Despite they are not numerically given, we can propose three scenarios to see how to approach the question.

Let the following solutions to come up:

[H⁺] = 2.63x10⁻³ M

[H⁺] = 1.00x10⁻⁷ M

[H⁺] = 4.511x10⁻⁹ M

The first step, will be the calculation of the pH for each solution via:

pH = -log([H⁺])

So that they turn out to be:

pH = -log(2.63x10⁻³ M) = 2.580

pH = -log(1.00x10⁻⁷ M) = 7.000

pH = -log(4.511x10⁻⁹ M) = 8.3457

In such a way, since acidic solutions have a pH below 7, neutral have a pH equal to 7 and basic have it above 7, we infer the first one is acidic, second one is neutral and third one is basic.

Thus, you can reproduce this methodology with the proton concentrations you are given.

Learn more:

Responder:

2H2 + O2 → 2H2O

CaO + H2O → Ca (OH) 2

Fe + S → FeS

H2SO3 → SO2 + H2O

CaCO3 → CaO + CO2

Explicación:

2H2 + O2 → 2H2O

2 moléculas de hidrógeno gaseoso reaccionan con oxigente para producir 2 moléculas de agua

CaO + H2O → Ca (OH) 2

El óxido de calcio reacciona con el agua para producir hidróxido de calcio.

Fe + S → FeS

El hierro reacciona con el azufre para producir sulfuro de hierro.

H2SO3 → SO2 + H2O

Por descomposición, el ácido sulfuroso se descompone para producir dióxido de azufre y agua.

CaCO3 → CaO + CO2

El carbonato de calcio se descompone para producir óxido de calcio y dióxido de carbono.

1) crust 2)mantle 3) asthenosphere 4)core 5) hydrosphere are the correct matches for the given options.

A atomic number 26 & chemical symbol Fe are given to the element iron. It is a metal that belongs to the first transition series and the eight group of a periodic table. It is the most common element on the planet by mass, just above of oxygen, and makes up a significant amount of both the outer and inner core of the planet.

Iron is found in substantial amounts in hemoglobin, a type of protein found in red blood cells that delivers oxygen from lungs to each and every part of the body. If the body doesn't have enough iron, it won't produce enough red blood cells to deliver oxygen, which leads to fatigue.

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Answer:

D) lithium

Sodium Chloride is salt which is oviously present.

Oxygen is also present because fish use their gills to get oxygen from water.

Plants are present under ocean which release Carbon dioxide.

Answer:

At < I < Br < Cl < F

Explanation:

Electronegativity is defined as the ability of an atom to attract pair of electrons. On the periodic table, electronegativity decreases down the group and increases along the period.

The given atoms belong to the same group, so following the above rule,  F has the highest electronegativity than other given atoms as it is at the top of the group and At will have the least electronegativity as it is at the bottom of the group.

Hence, the order of increasing electronegativity is

At < I < Br < Cl < F.

Based on the chemical equation provided, the missing reactant in the reaction is an alkene.

Tertiary alcohols are alcohols in which the carbon atom attached to the hydroxyl group is bonded to three other carbon atoms. They can be formed by the hydration of tertiary alkenes, which are alkenes in which the carbon atom at the site of the double bond is bonded to three other carbon atoms.

In the given reaction, the hydrogen molecule is added to the double bond of a tertiary alkene to form a new carbon-carbon single bond, while the two hydrogen atoms are added to the two carbon atoms of the double bond. The resulting compound is a tertiary alcohol. Therefore, the missing reactant in the reaction is a tertiary alkene that would undergo the addition of H₂ to form the given tertiary alcohol product.

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--The complete reaction is, What is the missing reactant in this organic reaction?--

The pH of the solution after 25.0 mL of KOH has been added to the acid is  10.37.

HCOOH is a weak acid that reacts with KOH (a strong base) to form the HCOO⁻ ion and water:

HCOOH + KOH → HCOO⁻ + H₂O

The balanced chemical equation shows that the stoichiometric ratio of HCOOH to KOH is 1:1, so 25.0 mL of 0.20 M KOH corresponds to the same amount of moles of HCOOH. This means that 25.0 mL of the original 0.35 M HCOOH solution has reacted with the 25.0 mL of 0.20 M KOH solution.

moles of HCOOH remaining = moles of HCOOH initially - moles of KOH added

moles of HCOOH initially = 0.35 mol/L × 0.0250 L = 0.00875 mol

moles of KOH added = 0.20 mol/L × 0.0250 L = 0.00500 mol

moles of HCOOH remaining = 0.00875 mol - 0.00500 mol = 0.00375 mol

The concentration of the remaining HCOOH is:

[ HCOOH ] = moles of HCOOH remaining / volume of solution remaining

= 0.00375 mol / (25.0 mL + 25.0 mL)

= 0.075 M

Now we can use the expression for the dissociation constant of HCOOH to calculate the pH of the solution:

Ka = [ H⁺ ][ HCOO⁻ ] / [ HCOOH ]

We can assume that the HCOO⁻ ion behaves as a weak base and calculate its concentration using the equation:

[ HCOO⁻ ] = Ka / [ HCOOH ]

[ HCOO⁻ ] = (1.77 × 10⁻⁴) / 0.075 ≈ 2.36 × 10⁻³ M

Now we can use the equation for the ionization of water to calculate [ H⁺ ]:

Kw = [ H⁺ ][ OH⁻ ]

1.00 × 10⁻¹⁴ = [ H⁺ ][ 2.36 × 10⁻³ ]

[ H⁺ ] = 4.24 × 10⁻¹¹ M

Therefore, the pH of the solution is:

pH = -log[H⁺] ≈ 10.37

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Answer:

i have done this before

Explanation:

the bag just starts shrinking after sparkling a little bit

Answer:

LOL ked e e. E e s e

Explanation:

This is my account

Answer:

A single compound is simultaneously oxidized and reduced.

Explanation:

In chemistry, disproportionation is a simultaneous oxidation and reduction of a single chemical specie.

What this means is that; in a disproportionation reaction, only one compound is both oxidized and reduced. This implies that two products are formed during disproportionation. One is the oxidized product while the other is the reduced product.

Consider the disproportionation of CuCl shown below;

2CuCl -----> CuCl2 + Cu

Here, CuCl2 is the oxidized product while Cu is the reduced product.

Answer:

A & c & e

Explanation:

(a)The mass of Cl in the FeClₓ solution is 0.979 g. (b) The number of moles of Fe present in the FeClₓ solution is approximately 0.0138 mol.

To determine the mass of chlorine (Cl) in the FeClₓ solution, we need to use the information provided.

a) Calculation of the mass of Cl in the FeClₓ solution:

Given:

Mass of Fe = 0.771 g

Mass of FeClₓ = 1.750 g

To find the mass of Cl, we need to subtract the mass of Fe from the total mass of FeClₓ:

Mass of Cl = Mass of FeClₓ - Mass of Fe

= 1.750 g - 0.771 g

= 0.979 g

Therefore, the mass of Cl in the FeClₓ solution is 0.979 g.

b) Calculation of the number of moles of Fe in the FeClₓ solution:

Given:

Mass of Fe = 0.771 g

Atomic mass of Fe = 55.845 g/mol

To find the number of moles of Fe, we can use the empirical formula:

Number of moles = Mass / Molar mass

Number of moles of Fe = 0.771 g / 55.845 g/mol

≈ 0.0138 mol

Therefore, the number of moles of Fe present in the FeClₓ solution is approximately 0.0138 mol.

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folic Acid

Folic acid, often known as folate, is a water-soluble B vitamin that is necessary for the generation of healthy red blood cells and the regular functioning of the brain system. Folate is present in numerous foods, including leafy green vegetables, legumes, nuts, and grains. Numerous processed goods, including breakfast cereals, breads, and rice, contain it as well. Folic acid is essential for pregnant women because it prevents birth abnormalities. It is also crucial for people of all ages since it helps maintain the health and normal operation of the body's cells. Folic acid is also essential for the production and repair of DNA, as well as the breakdown of specific proteins. Without appropriate folic acid, the body cannot produce red blood cells effectively, which can result in anemia. It is essential to consume adequate amounts of folic acid through diet or supplementation.

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