Using a z-table or calculator, we can find that the probability of getting a z-score less than -3.14 is approximately 0.0008 (rounded to four decimal places as requested).
Using the Empirical Rule and the concept of probability, I can help you find the requested probability. The Empirical Rule, also known as the 68-95-99.7 rule, states that for a normal distribution:
- Approximately 68% of the data falls within 1 standard deviation (SD) of the mean
- Approximately 95% of the data falls within 2 SDs of the mean
- Approximately 99.7% of the data falls within 3 SDs of the mean
You are asked to find the probability P(z < -3.14). Since -3.14 is slightly beyond -3 SDs from the mean, we know that less than 0.15% of the data falls in that area, as 99.7% of the data is within ±3 SDs.
However, to get a more precise probability, we need to use a standard normal (Z) table or calculator. When looking up z = -3.14, we find that the probability P(z < -3.14) is approximately 0.0008.
So, the probability you are looking for is 0.0008.
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Luz, a math major, sees the drawing above as a Venn diagram. Her brother, an art major, sees it as two circles. The difference in perception is an example of…
a. synesthesia.
b. stereotyping.
c. stimulus variables.
d. top-down processing.
e. feature detection.
Option A, The image above, according to math central Luz, is a Venn diagram. A major in art, her brother, interprets it as two circles. One instance of synesthesia is the discrepancy in perception.
A Venn diagram is a type of visual representation that uses circles to emphasize the relationships among certain items or constrained groups of things. Rings with overlaps have several properties that circles without overlaps do not. Venn diagrams are helpful for visually illustrating the relationship and differences between two concepts.
A Venn diagram uses circles or other overlapping shapes to illustrate the relationships between three or more organizations of things. They usually serve to visually organize items while emphasizing their similarities and differences.
A triple Venn diagram is a helpful visual tool highlighting the similarities and differences between three sets of objects or statistics.
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2/5 x + 10 = 30 solve for x
x=
Answer:
90
Step-by-step explanation:
Step 1:
2/5x + 10 = 30 Equation
Step 2:
2/5x = 20 Subtract 10 on both sides
Step 3:
x = 20 ÷ 2/5 Divide
Step 4:
x = 20 × 5/2 Multiply
Answer:
x = 90
Hope This Helps :)
(1 point) if you have 140 meters of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest area you can enclose?
The largest area that can be enclose in straight wall is 2450 m².
What is meant by the largest area?Having to maximize or decrease a geometric figure's measurements, area, or volume is a special example of a geometry word problem.Let 'x' be the length of rectangle.
Let 'y' be the width rectangle.
Perimeter = 140 meters
2x + y = 140
y = 140 - 2x
Area = xy
Put the value of y in area.
Area = x(-2x + 140)
Area = -2x² + 140x
Differentiating the area with respect to x.
dA/dx = -4x + 140
Put dA/dx = 0 to get the critical point.
-4x + 140 = 0
x = 140/4
x = 35
Largest area at x = 35.
y = 140 - 2x
y = 140 - 2×35
y = 70
Area = xy
Area = 70×35
Area = 2450 m²
Thus, the largest area that can be enclose in straight wall is 2450 m².
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Given: ∆MNP, PM = 8 m∠P = 90°, m∠N = 58° Find: Perimeter of ∆MNP
(Not 22.4 or 22.43)
Please answer ASAP, brainly awarded.
Answer:
Step-by-step explanation:
Triangle MNP is a right triangle with the following values:
m∠P = 90°m∠N = 58°PM = 8Interior angles of a triangle sum to 180°. Therefore:
m∠M + m∠N + m∠P = 180°
m∠M + 58° + 90° = 180°
m∠M + 148° = 180°
m∠M = 32°
To find the measures of sides MN and NP, use the Law of Sines:
\(\boxed{\begin{minipage}{7.6 cm}\underline{Law of Sines} \\\\$\dfrac{a}{\sin A}=\dfrac{b}{\sin B}=\dfrac{c}{\sin C}$\\\\\\where:\\ \phantom{ww}$\bullet$ $A, B$ and $C$ are the angles. \\ \phantom{ww}$\bullet$ $a, b$ and $c$ are the sides opposite the angles.\\\end{minipage}}\)
Substitute the values into the formula:
\(\dfrac{MN}{\sin P}=\dfrac{NP}{\sin M}=\dfrac{PM}{\sin N}\)
\(\dfrac{MN}{\sin 90^{\circ}}=\dfrac{NP}{\sin 32^{\circ}}=\dfrac{8}{\sin 58^{\circ}}\)
Therefore:
\(MN=\dfrac{8\sin 90^{\circ}}{\sin 58^{\circ}}=9.43342722...\)
\(NP=\dfrac{8\sin 32^{\circ}}{\sin 58^{\circ}}=4.99895481...\)
To find the perimeter of triangle MNP, sum the lengths of the sides.
\(\begin{aligned}\textsf{Perimeter}&=MN+NP+PM\\&=9.43342722...+4.99895481...+8\\&=22.4323820...\\&=22.43\; \sf units\; (2\;d.p.)\end{aligned}\)
If a randomly selected student is in the animatronics club, what is the probability that this student also is in the chess club?
The probability that the student from animatronics club is in the chess club is 0.066
How to determine the probabilityFrom the question, we have the following parameters that can be used in our computation:
The Venn diagram
On the Venn diagram, we have the following readings
animatronics club = 530
Chess and animatronics club = 35
The probability that this student also is in the chess club is then represented as
Probability = Chess and animatronics club/animatronics club
substitute the known values in the above equation, so, we have the following representation
Probability = 35/530
Evaluate
Probability = 0.066
Hence, the probability is 0.066
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If a salesman sells a watch at 90% of the cost price, the watch will be sold at $108. At what price must he sell the watch if he wants to make $30?
Answer:
$150
Step-by-step explanation:
Let's call the cost price of the watch C. The salesperson sells the watch at 90% of the cost price, so they sell the watch for 0.9 * C dollars.
We know that 0.9 * C = 108 dollars, so C = 108 / 0.9 = <<108/0.9=120>>120 dollars.
The salesperson wants to make a profit of $30, so they need to sell the watch for 120 + 30 = <<120+30=150>>150 dollars.
What two expressions represent 3/12?
Answer:
2/12 + 1/12
3/1 × 1/12
Step-by-step explanation:
hope it help
hey could someone help me please two angles in a triangle are 40 and 95. list two exterior angles
two exterior angles for those angles would be 140 and 85
Andrew wants to run ten miles in three days .He ran 212 miles on Monday and 425 miles on Tuesday how many miles does Andrew need to run on Wednesday?
Answer: 3.63 miles
Step-by-step explanation: I think you meant to type 2.12 and 4.25 so I'm just going to go by that. To figure out how many more miles he needs to run, you add the amount he already ran together, and then subtract that from his goal. 4.25 plus 2.12 equals 6.37. 10 minus 6.37 equals 3.63. He needs to run 3.63 miles on Wednesday, in order to reach his goal of 10 miles.
HELP PLZZZZZZZZZ this has to be done by 11:59 i really need help :(
ON SATURDAY MORNINGS FROM 9:00 UNTIL NOON, BRENT WATCHES A GROUP OF PRESCHOOLERS WHILE THEIR PARENTS WORK OUT IN THE GYM. BRENT EARNS $7.25 PER HOUR PLUS $1.00 PER CHILD. TODAY THERE ARE 7 CHILDREN…HOW MUCH WILL BRENT EARN? SHOW YOUR WORK IN THE SOLUTION BOX AND CIRCLE YOUR FINAL ANSWER. PLACE IN THE BASKET WHEN FINISHED.
The total earning of the Brent for watch group of 7 preschool children is $28.75.
What is defined as the linear equation with two variables?A linear equation throughout two variables is just an equation in which the exponent of two variables is 1. A two-variable equation system has a single solution, no solutions, and infinitely many solutions. A sequential linear equation may contain 'n' variables. It is critical to remember that there must be n formulas to solve and ascertain the value of variables when solving function available with n variables.For the given question;
Let 'x' be the number of hours Brent watched the preschool children.
The rate of one hour is $7.25.
The number of hours from 9:00 am to noon is 3 hours.
Let 'y' be the number of children.
The price per child is $1.00.
Thus, the formation of linear equation will be;
= 7.25x + 1.00y
For x = 3 hours and y = 7 child.
= 7.25×3 + 1.00×7
= 21.75 + 7
= 28.75
Thus, the total earnings of the Brent for today is $28.75.
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Frame zero, F0. is the fixed global frame. For each of
the cases below find T 1: 0
(a) F1 is rotated by an angle θ about zo.
(b) F1 is rotated by θ about xo.
(c) F1 is rotated by θ about yo.
(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`
(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`
(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`
Given that Frame zero, F0 is the fixed global frame.
For each of the cases below find T1
Case (a)
F1 is rotated by an angle θ about zo.
Let O be the origin of the fixed frame F0, A be the origin of the frame F1 and α be the angle between the x-axis of the frame F0 and the projection of the x-axis of the frame F1 on the xy plane of the frame F0.
Let l, m, n be the direction cosines of the vector from O to A, expressed in F0.
The content-loaded frame zero F0 is the fixed global frame, which means that the vectors i, j, k representing the x, y, and z-axis of F0 are fixed and cannot be transformed.
Therefore, the transformation matrix T1:0
in this case is:
`T1:0 = [l1 m1 n1 0; l2 m2 n2 0; l3 m3 n3 0; 0 0 0 1]`
Case (b)
F1 is rotated by θ about xo.
Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.
Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.
The transformation matrix T1:0
in this case is given by:
`T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`
Case (c)
F1 is rotated by θ about yo.
Let β be the angle between the y-axis of F0 and the projection of the y-axis of F1 on the yz plane of F0.
Let γ be the angle between the z-axis of F0 and the projection of the z-axis of F1 on the zx plane of F0.
The transformation matrix T1:0
in this case is given by:
`T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`
Thus, the transformation matrix T1:0
for the three cases (a), (b), and (c) are given as follows:
(a) `T1:0 = [cosθ sinθ 0 0; -sinθ cosθ 0 0; 0 0 1 0; 0 0 0 1]`
(b) `T1:0 = [1 0 0 0; 0 cosθ sinθ 0; 0 -sinθ cosθ 0; 0 0 0 1]`
(c) `T1:0 = [cosθ 0 -sinθ 0; 0 1 0 0; sinθ 0 cosθ 0; 0 0 0 1]`
Given θ = 150,
T1:0 for the three cases are:
(a) `T1:0 = [cos150 sin150 0 0; -sin150 cos150 0 0; 0 0 1 0; 0 0 0 1]`
(b) `T1:0 = [1 0 0 0; 0 cos150 sin150 0; 0 -sin150 cos150 0; 0 0 0 1]`
(c) `T1:0 = [cos150 0 -sin150 0; 0 1 0 0; sin150 0 cos150 0; 0 0 0 1]`
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battery lifetime is normally distributed for large samples. the mean lifetime is 500 days and the standard deviation is 61 days. approximately what percent of batteries have lifetimes more than 561 days ?
15.87 % percent of batteries have lifetimes more than 561 days.
Given:
battery lifetime is normally distributed for large samples. the mean lifetime is 500 days and the standard deviation is 61 days.
μ = 500
σ = 61
we know that
z = X - μ / σ
z score :
A Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values.
Given X = 561 days
substitute
z = 561 - 500 / 61
= 61 / 61
z = 1
At z = 1 p value is 0.8413
1 - 0.8413 = 0.1587
= 0.1587 * 100 %
= 15.87 %
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Yertorm some sensitivity analysis on the base case, consider an appropriate range of alternative assumptions - in percentage or raw value terms. 2. Using all of the most conservative (i.e. Worst-case scenario) assumptions, is the facility feasible? Under what conditions? Is there significant project risk based on the assumptions and your sensitivity analysis?
Sensitivity analysis involves assessing the impact of alternative assumptions on the feasibility of a facility. By evaluating worst-case scenarios and analyzing project risk, the viability of the facility can be determined.
Identify key assumptions: Determine the assumptions that have the most significant impact on the feasibility of the facility. These could include factors like construction costs, operating expenses, revenue projections, interest rates, market demand, etc.
Define alternative scenarios: Create a range of alternative scenarios by varying the identified assumptions. For example, you can consider best-case, base-case, and worst-case scenarios by adjusting the assumptions in percentage or raw value terms.
Evaluate financial viability: For each alternative scenario, analyze the financial viability of the facility. Calculate key financial indicators such as net present value (NPV), internal rate of return (IRR), payback period, and profitability ratios. Compare the results of the different scenarios to assess their feasibility.
Assess project risk: Consider the level of project risk based on the assumptions and sensitivity analysis. Identify the scenarios that pose the highest risk to the project's success. Factors such as high construction costs, low market demand, or unfavorable interest rates can increase project risk.
Identify conditions for feasibility: Determine the conditions under which the facility remains feasible. Analyze the scenarios that yield positive financial indicators and meet the desired profitability thresholds. These conditions indicate the project's viability under conservative assumptions.
Mitigate risks: Develop strategies to mitigate the risks identified in the sensitivity analysis. This could involve adjusting the project scope, exploring alternative financing options, implementing cost-saving measures, or conducting further market research.
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Scores of an IQ test have a bell shaped distribution with a mean of 100 and standard deviation of 14. Use the emperical rule to determine the following (a) What percentage of pocgle has an 1Q score beiween 55 and 142 ? (b) What percentage of people has an 3 e score less than 86 or greoter than 114 ? (c) What percentage of people has an 4Q vore greaker than 742 ? (a) 6. (Type an integer of n decimall)
Using the empirical rule, we can determine the following probabilities for IQ scores: (a) approximately 68% of people have an IQ score between 55 and 142, (b) approximately 81.6% of people have an IQ score less than 86 or greater than 114, and (c) we cannot determine the exact percentage of people with an IQ score greater than 742 without additional information.
The empirical rule, also known as the 68-95-99.7 rule, is a statistical guideline that applies to data with a bell-shaped or normal distribution. According to this rule, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and approximately 99.7% falls within three standard deviations.
For (a), we calculate the z-scores for 55 and 142 using the formula z = (x - mean) / standard deviation. With a mean of 100 and a standard deviation of 14, the z-scores for 55 and 142 are approximately -3 and 3 respectively. Since the empirical rule states that approximately 68% of the data falls within one standard deviation of the mean, we can conclude that approximately 68% of people have an IQ score between 55 and 142.
For (b), we need to find the percentage of people with an IQ score less than 86 or greater than 114. Again, using the z-scores, we find that the z-score for 86 is approximately -1 and the z-score for 114 is approximately +1. According to the empirical rule, approximately 68% of the data falls within one standard deviation of the mean, which means that approximately 32% (100% - 68%) of the data falls outside this range. However, we need to consider both tails, so we double this percentage to get approximately 64% of people with an IQ score less than 86 or greater than 114, or 81.6% (100% - 64%) with an IQ score less than 86 or greater than 114.
For (c), we cannot determine the exact percentage of people with an IQ score greater than 742 without additional information. The empirical rule is applicable within three standard deviations of the mean. However, without knowing the value of the standard deviation or the range beyond three standard deviations, we cannot determine the precise percentage of people with an IQ score greater than 742.
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blank is the exchange of genes that occurs when a given population experiences a sudden expansion because of in-migration of outsiders from another population of the species.
Gene flow occurs when individuals from one population migrate and mate with individuals from another population, resulting in the exchange of genetic material.
The process you are referring to is called gene flow. This can lead to the introduction of new alleles into the population, increasing genetic diversity. In the context of a sudden population expansion due to the in-migration of outsiders, gene flow can have significant effects on the genetic composition of the population.
It can counteract genetic drift and the formation of new species, as gene flow tends to homogenize populations by spreading genetic variation.
In conclusion, gene flow plays a crucial role in maintaining genetic diversity and shaping the genetic structure of populations.
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Which three statements related to the equation are true?
The three statements that are true with regards to the equation are;
The solution of the equation is 2x + 5 = 7(x + 5)/2 = (x + 4)/2What is an equation?An equation is a statement that two expressions are equivalent.
The equation is; x + 5 = 4 + 3
Therefore; x = 4 + 3 - 5 = 2
The solution of the equation is 2The steps to find the solution is; x + 5 = 4 + 3 = 7, therefore;
x + 5 = 7x + 5 - 5 = 7 - 5 = 2
x + 5 - 5 = x = 2
x = 2
The division property indicates that we get;
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(3 points) Suppose that f(x) = (x²-16)6. (A) Find all critical values of f. If there are no critical values, enter -1000. If there are more than one, enter them separated by commas. Critical value(s)
To find the critical values of the function f(x) = (x²-16)6, we need to determine where the derivative of the function is equal to zero or undefined.
First, let's find the derivative of f(x) with respect to x:
f'(x) = 6(x²-16)' = 6(2x) = 12x
Now, to find the critical values, we set the derivative equal to zero and solve for x:
12x = 0
Solving this equation, we find that x = 0.
So, the critical value of f is x = 0.
Therefore, the only critical value of f(x) = (x²-16)6 is x = 0.
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8x - 3(2x - 4) = 3(x-6)
Answer:
X=30
Step-by-step explanation:
...
If 3 - 3k-1 = 81, what is the value of k?
Answer:
d
Step-by-step explanation:
I plugged in everything and 3x9 times 3=81
1. Which of the following is not an arithmetic sequence?
a. 11, 2, -8, -19
b. 4, 7, 10, 13
C. 57, 51, 45, 39...
d. -3, -5, -7, -9
Answer:
I think it is A
Step-by-step explanation:
Sorry if I'm wrong
HELP
The slope from this table value is:
The y-intercept from the table value is:
The equation of the line from this table of value is:
Slope: 1/5
Y-intercept: 0
Equation: Y= 5x
help em out pls and ill give brainliest
Answer:
- 10/5 = -2
- 1.25 = Box next to -2
0.75 = 2nd box facing the right
-0.5 = Box next to -1.25
3/2 = Last box facing the right
Answer:
-2 = -10/5, next is -1.25, next is -0.5, then 0.75, and finally 3/2, from left to right.
Step-by-step explanation:
What is an equation of the line that passes through the points (-8,0) and (8,4)?
Answer:
1/4
Step-by-step explanation:
We can use the formula [ y2-y1/x2-x1 ] to solve.
4-0/8-(-8)
4/16
2/8
1/4
Best of Luck!
Answer:
I’m sure the answer is
Y=1/4x+2
Step-by-step explanation:
I’m just got it correct
3. Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid’s weight, Pythagoras’s weight would still be pound less than he did in January. What is Euclid’s weight?
(a) Write an equation that represents the scenario. Begin by defining your variable.
(b) Solve the equation. Show your work.
(c) What is Euclid’s weight?
(d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined weight of the three dogs is 60 1/2 pounds. What is Riemann’s weight, and what is Pythagoras’s weight? Show your work.
The equation that represents the scenario is P + 1.2x + 0.25 = y. Euclid's weight is 10.625 pounds, and Riemann's weight is 21.25 pounds.
(a) Let us assume that the current weight of Euclid is x and the current weight of Pythagoras is P. Let us also assume that the weight of Pythagoras in January is y. The expression that represents the given scenario will be written as;
when Pythagoras lost 13 pounds in 5 months : P = y - 13
when Pythagoras gains 1.2 times Euclid's weight: = P + 1.2x
when Pythagoras' weight is 1/4 pound less than their weight in January:
(b) Solving the given equation,
P + 1.2x + 0.25 = y
y- 13 + 1.2x + 0.25 = y
1.2x - 12.75 = 0
(c) Euclid's weight is calculated as follows;
1.2x = 12.75
x = 12.75/1.2
x = 10.625 pounds
(d) The weight of Riemann is calculated as follows;
2(Euclid's weight)
2(10.625)
21.25 pounds
weight of Pythagoras = 60.5-(21.25 + 10.62)
= 28.7
The weight of Pythagoras is 28.7 pounds.
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The complete question is "Jake has two dogs, Euclid and Pythagoras. Euclid is a smaller dog and Pythagoras is larger. Jake found that Pythagoras lost 13 pounds from January to June. If Pythagoras gains 1.2 times Euclid's weight, Pythagoras's weight would still be 1/4 pound less than he did in January. What is Euclid's weight? (a) Write an equation that represents the scenario. Begin by defining your variable (b) Solve the equation. Show your work. (c) What is Euclid's weight? (d) Jake adopts a third dog, Riemann. Riemann weighs exactly twice what Euclid weighs. The combined 60.5 pounds. What is Riemann's weight, and what is Pythagoras's weight? weight of the three dogs is Show your work."
Consider the following two successive reactionsC-->MM-->Х If the percent yield of the first reaction is 66.9% and the percent yield of the second reaction is 31,6%, what is the overall percent yield for C-->X?a. 10.9% b. 17.3% c. 11.3% d. 21.1% e.16.8%
The overall percent yield for C --> X is approximately 21.1% (answer choice d).
A chemical reaction's efficiency is gauged by its percent yield. It is the theoretical yield—the greatest quantity of product that could be obtained if the reaction proceeded to completion—to the actual yield, the amount of product that was received from the reaction, represented as a percentage. Reaction conditions, contaminants, and incomplete reactions are only a few of the variables that can have an impact on the percent yield.
To find the overall percent yield for the successive reactions C --> M and M --> X, you need to multiply the percent yields of each reaction together and then divide by 100.
First, let's identify the percent yield for each reaction:
Reaction 1 (C --> M): 66.9%
Reaction 2 (M --> X): 31.6%
Now, multiply the percent yields together:
(66.9/100) * (31.6/100)
Then, multiply the result by 100 to convert back to a percentage:
(0.669 * 0.316) * 100
Calculate the result:
21.13364
The overall percent yield for C --> X is approximately 21.1% (answer choice d).
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A small company has $8,250,000 in (annual) revenue, spends 49% of its revenues on purchases, and has a net profit margin of 8. 5%. They would like to increase their profits and they are looking at focusing in one of two directions. First, they think they can save 2. 05% on their purchase expenses. Or second, they can focus on increasing sales. By how many dollars would they have to increase sales in order to equal a 2. 05% savings to purchasing expenses? (Display your answer as a whole number. )
as far as I can read that, well, the company has a revenue income of 8250000 and their expenditure on purchases is 49% of that amount, how much is that?
\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{49\% of 8250000}}{\left( \cfrac{49}{100} \right)8250000}\implies 4042500\)
so on saving 2.05% of purchasing expenses or namely 2.05% of 4042500
\(\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{2.05\% of 4042500}}{\left( \cfrac{2.05}{100} \right)4042500}\implies 82871.25\)
so sales must be increased by that much in order to match the 2.05% of 4042500.
12. use summation (õ) or product (œ) notation to rewrite the following.(a) 2 4 6 8 ··· 2n.(b) 1 5 9 13 ··· 425.(c) 1 12 13 14 ··· 150 .
Hello! I'm happy to help you with your question. Here's the notation for each sequence:
(a) 2 + 4 + 6 + 8 + ... + 2n can be rewritten as:
∑(2i) where i goes from 1 to n.
(b) 1 + 5 + 9 + 13 + ... + 425 can be rewritten as:
∑(4j-3) where j goes from 1 to 106. (Note: 425 is the 106th term in this sequence)
(c) 1 + 12 + 13 + 14 + ... + 150 can be rewritten as:
1 + ∑(k) ,where k goes from 12 to 150
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solve for x in this triangle
Answer:
x = 5.006 (approximate answer)
Step-by-step explanation:
According to the instructions, the two triangles are similar. Thus, we can write and solve an equation of ratios:
2x - 10 39
-------------- = ------------
78 169
x - 5 1
This reduces to ------------ = -----------
1 169
or (after cross-multiplication) 169x - 845 = 1
Solve for x: Add 845 to both sides, which results in 169x = 846
Dividing both sides by 169 results in x = 5.006 (approximate answer)
Can y’all help me in question 11?
After evaluation of these value we get:
a) |5| = 5
b)|-5| = 5
c) -(5) = -5
d) -(-5) = 5
What is Integer?
Zero, a positive natural number, or a negative integer denoted by a minus sign are all examples of integers. The inverse additives of the equivalent positive numbers are the negative numbers. The set of integers is frequently represented in mathematical notation by the boldface Z or blackboard bold mathbb Z.
What is Modulus?
A modulus function is a function that determines a number or variable's absolute value. It generates the size of the variable count. A function with absolute values is another name for it. No matter what input was provided to this function, the outcome is always favorable.
We are given some values to evaluate;
a) |5| = 5 (This is positve number so does not changes are made into it.)
b) |- 5| = 5 (Modulus has the property that it change every negative integer into positive integer)
c) - (5) = -5 (This number is multiplies by negative sign that's why it become negative integer.)
d) -(-5) = 5 (a negative integer multiplies with again negative sign so it become postive [- * - = +])
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