Answer:
He thought he was going to bring Isaac back from the dead. They ended up sacrificing the donkey instead.
If the pressure on a gas decreases from 1480 mm Hg at 478 K to 555 mm Hg, what is the final temperature?
V1 = _____ P1 = _____ T1 = _____
V2 = _____
Law:
P2 = _____
T2 = _____
Answer:
179 K
Explanation:
From the question given above, the following data were:
Initial pressure (P₁) = 1480 mm Hg
Initial temperature (T₁) = 478 K
Final pressure (P₂) = 555 mm Hg
Final temperature (T₂) =?
The final temperature of the gas can be obtained as follow:
P₁/T₁ = P₂/T₂
1480 / 478 = 555 / T₂
Cross multiply
1480 × T₂ = 478 × 555
1480 × T₂ = 265290
Divide both side by 1480
T₂ = 265290 / 1480
T₂ ≈ 179 K
Therefore, the final temperature of the gas is 179 K
which is the graph of the function g(x) = f(-x)
To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.
What is a graph of the function g(x) = f(-x)?To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.
If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).
However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.
In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.
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What is the energy of a purple
lamp with a frequency of
7.5 x 10^14 Hz
Answer:
\( \huge{4.969 \times {10}^{ - 19} \:J }\)
Explanation:
The energy of the purple lamp can be found by using the formula
E = hf
where
E is the energy
f is the frequency
h is the Planck's constant which is
6.626 × 10-³⁴ Js
From the question.
\( f = 7.5 \times 10^14 \: Hz \)
We have.
\( E = 6.626 \times 10^{-34} \times 7.5 \times 10^{14} \)
We have the final answer as
\(4.969 \times {10}^{ - 19} \: J\)
Drag each tile to the correct box.
Arrange the bonds in order based on bond length. Start with the longest bond, and end with the shortest bond.
C-N
bond energy = 305 kJ/mol
C=N
bond energy = 615 kJ/mol
C=N
bond energy = 887 kJ/mol
The bond length has been defined by the distance shared by the covalently bonded atoms. C≡N (887 kJ/mol) has the longest bond followed by C=N and the shortest C-N.
What is the bond length?Bond length is a parameter that defines the bond distance and measures the length between the bonded atoms. It is determined by bonded electrons.
The bond energy and bond length are directly related and hence the C≡N (887 kJ/mol) has the longest bond length because of high energy followed by C=N (615 kJ/mol) and the shortest C-N (305 kJ/mol).
Therefore, the order of bond length is C≡N > C=N > C-N.
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what is the significance of forensic ballistic in criminal investigation
One piece of evidence may occasionally be helpful in both investigations. A ballistic comparison, for instance, can prove that a gun was used in a murder case as well as other crimes that were committed in another nation, which already indicates the routing of that gun.
What is Ballistic evidence ?Examining the facts pertaining to weapons and ammunition found at crime scenes is the focus of forensic ballistics. Analyses of the outcomes and behaviours of projectiles and explosives are also included.
Experts in ballistics frequently compare the rifling patterns of two rounds to see if they originated from the same gun. By identifying a suspect based on the possession of a gun used to fire bullets discovered at the crime scene, this can be helpful in prosecutions.Learn more about Ballistic evidence here:
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Which elements from the list would be likely to form an ionic bond with chlorine, Cl?
Answer:
metal calcium or (Ca).
Explanation:
For example, the metal calcium (Ca) and the nonmetal chlorine (Cl) form the ionic compound calcium chloride (CaCl2). In this compound, there are two negative chloride ions for each positive calcium ion
Nitrogen dioxide decomposes to nitric oxide and oxygen via the reaction: 2NO2 → 2NO + O2 In a particular experiment at 300 °C, [NO2] drops from 0.0100 to 0.00650 M in 100 s. The rate of disappearance of NO2 for this period is __________.
Answer:
\(rate=-1.75x10^{-5}\frac{M}{s}\)
Explanation:
Hello,
In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:
\(rate=\frac{1}{2}*\frac{C_f-C_0}{t_f-t_0}\)
Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript f is referred to the final condition and the subscript 0 to the initial condition, thus, we obtain:
\(rate=\frac{1}{2}*\frac{0.00650M-0.0100M}{100s-0s}\\\\rate=-1.75x10^{-5}\frac{M}{s}\)
Clearly, it turns out negative since the concentration is diminishing due to its consumption.
Regards.
What are the functional groups
Answer:hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl groups.
Explanation:
A functional group can participate in specific chemical reactions. Some of the important functional groups in biological molecules include
Convert the following measurement
Answer:
9.9 x 10^-2 g*cm²/s²
Explanation:
9.9 × 10^-9 kg*m²/s² = g*cm²/s²
1 kg*m²/s² = 1 joule(s)
1 g*cm²/s² = 1 erg(s)
britannica
1 kg = 1000g = 1x10^3 g
1 m²= 10000 cm² = 1x10^4 cm²
add the exponents 3 and 4 which = 7
-9 + 7 = -2
9.9 × 10^-9 kg*m²/s² = 9.9 x 10^-2 g*cm²/s²
Which of the following would have more inertia than a car:
A)a person
B)airplane
C)skateboard
D)bicycle
PLEASE HELP
HELPPPPPPPPP 35 POINTSSSSSS!!!!!
A metal is oxidized if it’s converted from its metallic form to make a compound, and it’s reduced if it’s converted back to its metallic form.
FILL IN THE BLANKS with either "reduce" or "oxidize"
Magnesium is able to copper, and copper is able to magnesium.
Zinc is able to magnesium, and magnesium is able to zinc.
Copper is able to zinc, and zinc is able to copper.
Answer:
oxidize
Explanation:
HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
.
A soft drink contains 33g of sugar in 349g of H\(_2\)O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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ii) Sodium thiosulphate dissolves in dilute nitric acid at a steady rate. Copy out which
of the following changes would quicken up the reaction- 3
a. Cooling the reacting vessel to drop the temperature.
b. Breaking the reactants into smaller pieces.
c. Adding more concentrated acid.
d. Using more sodium thiosulphate.
Answer:
d
Explanation:
Question: What volume of 4.50 M HCI can be
made by mixing 5.65 M HCI with 250.0 mL of
3.55 M HCI?
Approximately 0.157 liters or 157 milliliters of the 4.50 M HCl solution can be made by mixing the given solutions.
To determine the volume of 4.50 M HCl that can be made by mixing the given solutions, we can use the concept of the concentration-volume relationship:
C1V1 = C2V2
Where:
C1 = concentration of the first solution
V1 = volume of the first solution
C2 = concentration of the second solution
V2 = volume of the second solution
Let's assign the variables as follows:
C1 = 5.65 M
V1 = unknown volume (we'll solve for this)
C2 = 3.55 M
V2 = 250.0 mL = 0.250 L (since the volume is given in milliliters)
Now we can plug in the values into the equation and solve for V1:
(5.65 M)(V1) = (3.55 M)(0.250 L)
Dividing both sides of the equation by 5.65 M:
V1 = (3.55 M)(0.250 L) / 5.65 M
V1 ≈ 0.157 L
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Which sample matter is a pure substance
Answer:
Explanation:
If you have options, could you please tell me so I can further help you. If you just need an example then
Examples of pure substances include iron, steel, and water
Hope this helps (:
Answer
These are the following answers
A) zinc oxide
B) sugar dissolved in water
C) pond water
D) soil
Explanation:
How many molecules are in 15 moles of CO2?
There are 90.345 x 10^23 molecules in 15 moles of CO2.
What is Avogadro's number?Avogadro's number is the number of units, atoms or molecules in one mole of a substance which is equals to 6.02214076 × 1023. This number is also known as the Avogadro constant.
This means that one mole of a substance is equals to 6.02214076 × 1023 atoms, ions or molecules then 15 moles is equals to 90.345 x 10^23 molecules so we can conclude that there are 90.345 x 10^23 molecules are in 15 moles of CO2.
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What would be the volume in mL of 5.097 g of water delivered by a 5 mL pipet? You observe the temperature and find the density to be 0.9960 g/mL. Do not use units in answer and record to 3 significant figures.
The volume of the water is 5.11 mL.
What would be the volume?Density is a measure of mass per unit of volume of a substance. It is a physical property of matter and is expressed in units of grams per cubic centimeter (g/cm^3).
The density of a substance determines how much of it will occupy a given space, and is a crucial factor in many physical and chemical phenomena, such as buoyancy, phase changes, and thermal conductivity.
We have that;
Volume of the water = ?
Density of the water = 0.9960 g/mL
Mass of the water = 5.097 g
Volume of the water = Mass/Density
= 5.097 g / 0.9960 g/mL
= 5.11 mL
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7) How many molecules of CO2 are in 2.5 L at STP?
By using the ideal gas law and Avogadro's number, we find that there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.
To determine the number of molecules of CO2 in 2.5 L at STP (Standard Temperature and Pressure), we can use the ideal gas law and Avogadro's number.
Avogadro's number (N_A) is a fundamental constant representing the number of particles (atoms, molecules, ions) in one mole of substance. Its value is approximately 6.022 × 10^23 particles/mol.
STP conditions are defined as a temperature of 273.15 K (0 °C) and a pressure of 1 atmosphere (1 atm).
First, we need to convert the volume from liters to moles of CO2. To do this, we use the ideal gas law equation:
PV = nRT,
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Since we have STP conditions, we can substitute the values:
(1 atm) × (2.5 L) = n × (0.0821 L·atm/(mol·K)) × (273.15 K).
Simplifying the equation:
2.5 = n × 22.4149.
Solving for n (the number of moles):
n = 2.5 / 22.4149 ≈ 0.1116 moles.
Next, we can calculate the number of molecules using Avogadro's number:
Number of molecules = n × N_A.
Number of molecules = 0.1116 moles × (6.022 × 10^23 particles/mol).
Number of molecules ≈ 6.72 × 10^22 molecules.
Therefore, there are approximately 6.72 × 10^22 molecules of CO2 in 2.5 L at STP.
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Sucrose (C12H22011) is combusted in air according to the following reaction:
C12H22011(s) + O2(g) = CO2(g) + H2O(l )
How many moles of carbon dioxide would be produced by the complete combustion of 38.5 grams of sucrose in the presence of excess oxygen?
Okay, let's break this down step-by-step:
1) The molecular formula for sucrose is C12H22011. This means each mole of sucrose contains 12 moles of carbon and 22 moles of hydrogen.
2) You are combusting 38.5 grams of sucrose. To convert grams to moles, we divide by the molar mass:
Molar mass of C12H22011 = 342.3 g/mol
So 38.5 g / 342.3 g/mol = 0.113 moles of sucrose
3) According to the combustion reaction, each mole of sucrose produces 12 moles of CO2.
So 0.113 moles of sucrose will produce 0.113 * 12 = 1.356 moles of CO2.
4) Round to the nearest whole number:
1 mole of CO2
Therefore, the complete combustion of 38.5 grams of sucrose in excess oxygen would produce 1 mole of carbon dioxide.
Let me know if you have any other questions!
How do you out pizza the hut?
how can you demonstrate that iodine can melt to form a liquid at atmospheric pressure
By monitoring the temperature at just above the iodine melting point and observing the melt, it is possible to get liquid iodine at atmospheric pressure.
What happens to iodine when it melts?Iodine is a chemical element that has the symbol I and atomic number 53. If the temperature is 113.7 oC or higher, liquid iodine will be present at the bottom, though, as Mike points out, it may be challenging to see it through the intensely colored iodine vapour. The heaviest of the stable halogens, it is a semi-lustrous, non-metallic solid under normal conditions. It melts at 114 °C (237 °F) to form a deep violet liquid and boils at 184 °C (363 °F) to form a violet gas.
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Potassium chlorate, a common oxidizing agent in fireworks and matchheads, undergoes a solid-state disproportionation reaction when heated:
4KClO3 (s) ⟶ Δ3KClO4 (s) + KCl (s).
Use ΔHf ° and S° values to calculate ΔG_sys ° (which is ΔGrxn °) in kJ at 25°C for this reaction.
Answer:
Explanation:
\(\text{From the information given:}\)
\(\text{The chemical reaction is : } 4 KClO_{3(s)} \to 3 KClO_{4(s)} + KCl_{(s)}\)
\(\text{To find} \ \Delta G^0_{rxn}\ \text{using the formula}: \\ \\ \Delta G^0_{rxn} = \sum n_p \times \Delta _f G^0 (Products) - \sum n_R \times \Delta _fG^0 ( Reactants) \\ \\ where; n_p = \text{no of moles of products } \ and; \\ \\ n_R = \text{no of moles of reactants }\)
\(\implies G^0_{rxn} = 3 \times \Delta _fG^0 [KClO_4{(s)}] + \Delta_fG^0[KCl_{(s)}] - 4 \times \Delta _f G^0 [ KClO_3 (s) ]\)
\(\Delta _fG^0 \ values \ at \ 25^0 \ C (298 \ K) are\ given \ as:\\\\ \Delta _fG^0 [KClO_4(s)] = -303.09 \ kJ \\ \\ \Delta _fG^0 [KCl(s) ] = - 409.14 \ kJ \\ \\ \Delta_f G^0 [KClO_3_{(s)}] = -296.25 \ kJ \\ \\ replacing \ the \ above \ values \ into \ equation (1) ; then:\\ \\ \\\Delta G^0_{rxn} = 3 *(-303.09) + (-409.14) - 4*(-296.25) \ kJ \\ \\ = (-909.27 - 409.14 + 1185) \ kJ \\ \\ = -133.41 \ kJ \\ \\ \mathbf{\Delta G^0_{rxn} = -133.4 \ kJ }\)
The standard free energy change of the reaction is -133 kJ.
From the reaction equation, we have; 4KClO3 ⇄ 3KClO4 (s) + KCl (s). The standard free energy of formation of each specie is given below;
ΔG°f KClO3 = -296.35 kJ
ΔG°f KClO4 = -303.09 kJ
ΔG°f KCl = -409.14 kJ
Hence;
ΔG°rxn = [3(-303.09)] + ( -409.14)] - [(4( -296.35))]
ΔG°rxn = (-909.27) + (-409.14) - (-1185.4)
ΔG°rxn = -133 kJ
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A local barista serves coffee at 85°C. You add ice to the coffee to cool it to 55°C. Assume that an ice cube is 24 g and -18.5°C. How many ice cubes would you need to add to your 355 mL cup of coffee to bring it to 55°C? The specific heat of ice is 2.05 J/g°C, the specific heat of water is 4.184 J/g°C, and the specific heat of fusion of water is 334 J/g. Remember that an ice cube will need to be warmed to 0°C, will melt, and then the newly melted water will be warmed to 55°C.
A. 1
B. 2
C. 3
D. 4
To solve this problem, we need to consider the energy required to warm the ice cube from -18.5°C to 0°C, the energy required to melt the ice cube, and the energy required to warm the melted water from 0°C to 55°C. Let's calculate the energy for each step and determine the number of ice cubes needed.
Warming the ice cube to 0°C:
The specific heat capacity of ice is 2.05 J/g°C. The temperature change is from -18.5°C to 0°C. Therefore, the energy required to warm the ice cube can be calculated as:
Energy = mass × specific heat capacity × temperature change
Energy = 24 g × 2.05 J/g°C × (0°C - (-18.5°C))
Energy = 24 g × 2.05 J/g°C × 18.5°C = 899.4 J
Melting the ice cube:
The heat of fusion (specific latent heat of fusion) of water is 334 J/g. We need to determine the energy required to melt the ice cube. The mass of the ice cube is 24 g, so the energy required can be calculated as:
Energy = mass × heat of fusion
Energy = 24 g × 334 J/g = 8016 J
Warming the melted water from 0°C to 55°C:
The specific heat capacity of water is 4.184 J/g°C. We need to determine the energy required to warm the melted water from 0°C to 55°C. The mass of the melted water can be calculated by subtracting the mass of the ice cube that melted from the initial mass of the ice cube (24 g).
Mass of melted water = 24 g - 24 g = 0 g (since all the ice melted)
Therefore, no additional energy is required for this step.
Now, let's add up the energy required for each step to determine the total energy needed to cool the coffee from 85°C to 55°C:
Total energy required = Energy to warm the ice cube to 0°C + Energy to melt the ice cube
Total energy required = 899.4 J + 8016 J = 8915.4 J
Given that each ice cube provides 8915.4 J of energy, we can determine the number of ice cubes needed to cool the coffee.
Energy per ice cube = 8915.4 J
Energy required to cool the coffee = Total energy required = 8915.4 J
The number of ice cubes needed = Energy required to cool the coffee / Energy per ice cube
Number of ice cubes needed = 8915.4 J / 8915.4 J = 1
Therefore, you would need to add 1 ice cube to your 355 mL cup of coffee to bring it to 55°C.
The correct answer is A. 1.
how do molecules attract each other when they are dying predict how ethanol would interact with the food dye molecues
Answer:
Kindly check the explanation section.
Explanation:
Chemical bonding is a very important concept in chemistry. It involves the bonding of atoms, molecules and/or compounds.
There are different ways in which molecules get attracted to each other. The bonding may be through induced dipole interaction, ionic bonding, hydrogen bonding, Van-der wal interaction, or through covalent bonding.
For the second part of the question. The question asked to predict how ethanol would interact with the food dye molecules.
Ethanol bonds with food dye molecules through one of the chemical bonding known as the Hydrogen bond. Which is as a result of the bonding between hydrogen atoms and another atom which is much more electronegative than Hydrogen atoms.
How many grams of Nacl would you need to prepare 200 ml of a 5 M SOLUTION. ?
Answer:
58.44 g of NaCl are needed.
Explanation:
Given data:
Mass of NaCl needed = ?
Volume of solution = 200 mL (200/1000 =0.2 L)
Molarity of solution = 5 M
Solution:
We will solve this problem through molarity formula.
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Now we will put the values.
5 M = moles of solute / 0.2 L
Moles of solute = 5 mol/L × 0.2 L
Moles of solute = 1 mol
Mass of sodium chloride:
Mass = number of moles × molar mass
Mass = 1 mol × 58.44 g/mol
Mass = 58.44 g
Thus, 58.44 g of NaCl needed.
Which of the following explains the interactions that occur between the atoms of water molecules and the ions that form when sodium chloride dissolves in water?
hydrogens interact with the chloride ion, oxygens interact with the sodium ion
Water's covalent bonds are more powerful than salt molecules' ionic bonds, so when salt is combined with water, the salt dissolves.
The negatively charged side of the water molecules is drawn to the positively charged sodium ions, whereas the positively charged side is drawn to the negatively charged chloride ions. In essence, a tug-of-war takes place, with the water molecules coming out on top. The ionic link that held sodium and chloride ions together is broken when water molecules force the ions apart.
Both the water molecule and the salt molecule are polar, meaning that the positive and negative charges are located on opposite sides of the molecule. This makes it possible for the salt molecule to dissolve in the water molecule.
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HRISTINA HERRERA: Attempt 1
Question 9 (2.5 points)
3
Which of the following sets of data are consistent with the law of conservation of
matter?
6
7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.
9
50 g gasoline reacts with 243 g oxygen to form 206 g of carbon dioxide and 97 g
water
12
17.7 g nitrogen react with 34.7 g oxygen to form 62.4 g nitrogen dioxide.
all of these
15
none of these
Answer:
7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.
Explanation:
Here we have the check if the mass of the reactants is equal to the mass of the products.
Reactants
\(7.5+50=57.5\ \text{g}\)
Products
\(57.5\ \text{g}\)
The data is consistent with the law of conservation of matter.
Reactants
\(50+243=293\ \text{g}\)
Products
\(206+97=303\ \text{g}\)
The data is not consistent with the law of conservation of matter.
Reactant
\(17.7+34.7=52.4\ \text{g}\)
Products
\(62.4\ \text{g}\)
The data is not consistent with the law of conservation of matter.
Only the first data is consistent with the law of conservation of matter.
What system is used to help match DNA from crime scenes to a DNA database?
A.
CODIS
B.
AFIS
C.
NIBIN
D.
FBI
Answer:
A. CODIS
Explanation:
The Combined DNA Index System (CODIS), administered by the FBI, maintains DNA profiles obtained through federal, state, and local DNA sample collection programs, and makes this information available to law enforcement agencies across the country for law enforcement identification purposes.
What is the pH of 6.00 M H2CO3 if it has 7% dissociation? SHOW YOUR WORK!!!
From the calculation, the pH of the solution can be obtained as 0.39.
What is the pH of the solution?We first have to obtain the dissociation constant of the solution;
α = √Ka/C
Ka = Cα^2
Ka = 4.9 * 10^-3 * 6
Ka = 0.0294
Then we have that;
0.0294 = [x]^2/[6 - x]
0.0294 * [6 - x] = x^2
0.1764 - 0.0294 x = x^2
x^2 + 0.0294 x - 0.1764 =0
x = 0.41 M
Thus the pH of the solution is;
pH = -log[0.41]
= 0.39
pH is an important parameter in chemistry, biology, and many other fields, as it can affect the behavior and properties of substances and reactions.
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