Answers
According to figure where the point P is located so that the magnitude of the Field at point p= Zero electric field will be \(E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}\).
The electric field is a fundamental concept in physics that describes the force experienced by a charged particle in the presence of other charges. It is a vector field, which means it has both magnitude and direction at each point in space.
The electric field is created by electric charges. A positive charge creates an outward electric field, while a negative charge creates an inward electric field.
The strength or magnitude of the electric field at a given point depends on the magnitude of the charge creating the field and the distance from that point to the charge.
E due to the dipole formed by charges at extreme end,
\(E_x=k_p/d^3\) in the x-direction
E due to the charge at center
\(E_y=k_q/d^3\)
Net electric field is,
\(E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}\). as p = 0.
Thus, the answer is \(E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}\).
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Your question seems incomplete, the probable complete question is:
According to figure below where the point P is located so that the magnitude of the Field at point p= Zero ?
Related Questions
Which statement describes a drawback of digital medical records over paper records?
a) Digital records may be more difficult to read than handwritten records.
b) Digital medical records might be impossible to access in a power outage.
c) Digital records would be less safe if there was a fire.
d) Digital records have no way to limit access to private information.
Answers
Answer:
b)
Explanation:
From the options provided, the only drawback of using digital medical records is that Digital medical records might be impossible to access in a power outage. This is because digital records are saved on a database either locally or remotely. Regardless of which, the records can only be accessed through an authorized computer system that is connected to the database. These are electronic systems that require power to function. Without power you would not be able to use the computer and therefore, would not have access to the medical records. Unlike, paper records which can be accessed regardless of whether there is power or not.
An aeroplaneflying above groundnd490m with 100 meterpersecond how far on ground it will strike
Answers
The airplane will strike the ground at a horizontal distance of 490 meters.
To determine how far the airplane will strike on the ground, we need to consider the horizontal distance traveled by the airplane during its flight.
The horizontal distance traveled by an object can be calculated using the formula:
Distance = Speed × Time
In this case, the speed of the airplane is given as 100 meters per second and the time it takes to cover the distance of 490 meters is unknown. Let's denote the time as t.
Distance = 100 m/s × t
Now, to find the value of time, we can rearrange the equation as follows:
t = Distance / Speed
t = 490 m / 100 m/s
t = 4.9 seconds
Therefore, it takes the airplane 4.9 seconds to cover a horizontal distance of 490 meters.
Now, to calculate the distance on the ground where the airplane will strike, we can use the formula:
Distance = Speed × Time
Distance = 100 m/s × 4.9 s
Distance = 490 meters
It's important to note that this calculation assumes a constant speed and a straight flight path. In reality, various factors such as wind conditions, changes in speed, and maneuvering can affect the actual distance traveled by the airplane.
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What is the cost per month to operate an A.C. 10hours per day whose power is 3kW and 1KWH cost 79francs
Answers
The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.
What is Power?Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.
Cost of operation for 10 hours a day;
Daily consumption = 3kW x 10 hours
Daily Consumption = 30kW
Since 1kWH = 79 francs;
Daily consumption amount = 30 x 79 francs
Daily consumption amount = 2,370 francs
Therefore, the monthly consumption (using 30days) will be;
2,370 francs x 30 = 71,100 francs
In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.
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The figure(Figure 1) shows the wave fronts of a circular wave.
a. What is the phase difference between points A and B?
b. What is the phase difference between points C and D?
c. What is the phase difference between points E and F?
Answers
The Phase difference between points A and B is zero of a circular wave.
= 5 pi/2-5pi/2=0
b) What is the phase difference between points C and D?
Phase difference between points C and D will be
= 9pi/2- pi/2=4pi
c) What is the phase difference between points E and F?
Phase difference between E and F will be
= 5pi/2 - 2pi/2= pi
Phase difference:The phase difference of a sine wave can be defined as "the time interval by which one wave leads or lags another", and phase difference is not only a property of one wave, but also the relative property of two or more waves. am. This is also called the "phase angle".
What causes the phase difference of waves?The phase difference between two sound waves of the same frequency passing through a fixed position is given by the time difference between the same position within the wave cycle of the two sounds.
How would you describe the phase difference?Phase difference is the difference in phase angle between two sine waves or phasors. In a three-phase system, the phase difference between conductors is one-third of the period.
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Distance is 80 seconds is 8 what is the average speed?
Answers
Answer:
speed =distance /time
speed =80/8
speed =10m/s
If the mass of the ladder is 12.0 kgkg, the mass of the painter is 55.0 kgkg, and the ladder begins to slip at its base when her feet are 70% of the way up the length of the ladder, what is the coefficient of static friction between the ladder and the floor
Answers
Answer:
μ = 0.336
Explanation:
We will work on this exercise with the expressions of transactional and rotational equilibrium.
Let's start with rotational balance, for this we set a reference system at the top of the ladder, where it touches the wall and we will assign as positive the anti-clockwise direction of rotation
fr L sin θ - W L / 2 cos θ - W_painter 0.3 L cos θ = 0
fr sin θ - cos θ (W / 2 + 0,3 W_painter) = 0
fr = cotan θ (W / 2 + 0,3 W_painter)
Now let's write the equilibrium translation equation
X axis
F1 - fr = 0
F1 = fr
the friction force has the expression
fr = μ N
Y Axis
N - W - W_painter = 0
N = W + W_painter
we substitute
fr = μ (W + W_painter)
we substitute in the endowment equilibrium equation
μ (W + W_painter) = cotan θ (W / 2 + 0,3 W_painter)
μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)
we substitute the values they give
μ = cotan θ (12/2 + 0.3 55) / (12 + 55)
μ = cotan θ (22.5 / 67)
μ = cotan tea (0.336)
To finish the problem, we must indicate the angle of the staircase or catcher data to find the angle, if we assume that the angle is tea = 45
cotan 45 = 1 / tan 45 = 1
the result is
μ = 0.336
A box of mass 20kg rests on a flat horizontal floor. if the density of air is negligible. Draw a diagram showing forces acting on the box
Answers
There are only two forces acting on the box!!!
Here it is, hope it helps!
How much work is it to push a box (mass 150 kg) up an incline (angle 15 degrees with the horizontal) that is 8.1 meters long, if the coefficient of kinetic friction between the box and the incline is 0.4
Answers
Given that,
Mass of a box, m = 150 kg
It is pushed at an angle of 15 degrees with the horizontal.
It is 8.1 m long.
The coefficient of kinetic friction between the box and the incline is 0.4
To find,
The work done in pushing the box.
Solution,
First let's see the net force acting on the box.
\(F_{net}=mg\sin\theta+f_k\\=mg\sin\theta+\mu_k mg\cos\theta\)
Work done is given by :
W = force × displacement
\(W=(mg\sin\theta+\mu_k mg\cos\theta)\times s\\\\=150\times 10(\sin15+8.1\times \cos15)\times 8.1\\\\=98206.24\\\\or\\\\=98.2\ kJ\)
So, the required work done is 98.2 kJ.
A projectile leaves the ground at 150 m/s and reaches a maximum height of 0.57 km. If there was no air resistance, at what angle above the horizontal did it leave the ground?
Answers
The projectile left the ground at an angle of 67.4 degrees above the horizontal, if there was no air resistance.
First, let's find the time of flight. We can use the kinematic equation:
y = yo + voy*t + 0.5*a*t^2
where y is the maximum height (0.57 km), yo is the initial height (0 m), voy is the initial vertical velocity (unknown), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time to reach the maximum height (unknown).
Plugging in the values and solving for t, we get:
0.57 km = 0 + voy*t + 0.5*(-9.81 m/s^2)*t^2
t = 12.19 seconds
Since the total time of flight is twice the time to reach the maximum height, we have:
total time of flight = 2*t = 24.38 seconds
Now we can use the range equation to find the initial velocity vector of the projectile:
x = vox*t
1500 m = vox*24.38 seconds
vox = 61.51 m/s
where x is the range and vox is the initial horizontal velocity.
Finally, we can use trigonometry to find the initial angle of projection, theta:
voy/vox = tan(theta)
voy = vox*tan(theta)
61.51 m/s*tan(theta) = (150 m/s)
theta = 67.4 degrees
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Select the correct answer from each drop-down menu.
Rocky metallic objects found between the orbits of Mars and Jupiter are(drop down). The largest known of these is(drop down).
Answers
Answer:
Blank 1 (asteroids)
Blank 2 (Ceres)
Explanation:
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
What are asteroids?Asteroids are stony elements that circle the Sun. Although asteroids circle the Sun in the same way as planets, they are considerably smaller.]
A dwarf planet located between Mars and Jupiter in the asteroid belt. Ceres was the first asteroid discovered, it was originally classed as a planet,
Rocky metallic objects found between the orbits of Mars and Jupiter are asteroids The largest known of these is ceres.
The correct option from the drop-down menu is asteroids and ceres.
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The physics of wind instruments is based on the concept of standing waves. When the player blows into the mouthpiece, the column of air inside the instrument vibrates, and standing waves are produced. Although the acoustics of wind instruments is complicated, a simple description in terms of open and closed tubes can help in understanding the physical phenomena related to these instruments. For example, a flute can be described as an open-open pipe because a flutist covers the mouthpiece of the flute only partially. Meanwhile, a clarinet can be described as an open-closed pipe because the mouthpiece of the clarinet is almost completely closed by the reed.
What is the frequency of the first possible harmonic after the fundamental frequency in the open-closed pipe described in Part E?
Part E was What length of open-closed pipe would you need to achieve the same fundamental frequency as the open-open pipe discussed in Part A? Half the length of the open-open pipe.
Part A was Consider a pipe of length 80.0 open at both ends. What is the lowest frequency of the sound wave produced when you blow into the pipe? frequency 214 Hz
Answers
Answer:
a) λ = 4L, b) L_c = ½ Lₐ, c) f = 214 Hz
Explanation:
a) in this part, the fundamental frequency (1st harmonic) is requested
In a pipe, the side that is closed has a node and the open side has a belly, so the wavelength inside the pipe is ¼ of the wavelength.
λ = 4L
to find the frequency let's use the definition of velocity
v = λ f
f = v /λ
f = v / 4L
b) in this part let's start by finding the resonance for a tube open at both ends
λ = 2 L
f = v / 2L
since they ask for the same frequency, let's match the two expressions
v / 4L_c = v / 2Lₐ
L_c = ½ Lₐ
therefore the length of the closed tube must be half the length of the open tube
c) It is indicated that the length of the open tube is L = 80 cm = 0.80 m
the frequency is
f = v / 2L
f = 343/2 0.8
f = 214 Hz
A mechanic applies a force of 60N at a distance of 80 cm from the pivot on a wheel wrench. What is the size of the moment?
Answers
Answer:
48 Nm
Explanation:
Moment, or torque, is the cross product of radius and force vectors.
τ = r × F
τ = (0.80 m) (60 N)
τ = 48 Nm
How many phase conductors are installed between the switch and the light fixture shown in the figure? A. Four
B. Three
C. Two
D. Five
Answers
Answer:
TWO
Explanation:
Great Company manufactures and sells a product whose peak sales occur in the third quarter. Management is now preparing detailed budgets for 20x4- the coming year and has assembled the following information to assist in the budget preparation: The company’s product selling price is Br. 20 per unit. The marketing department has estimated sales in units as follows for the next six quarters.
Answers
Answer:
Explanation:
Quarter 1 - 10,000 units
Quarter 2 - 12,000 units
Quarter 3 - 16,000 units
Quarter 4 - 14,000 units
Quarter 5 - 10,000 units
Quarter 6 - 8,000 units
Based on this information, the total estimated sales revenue for the next six quarters is Br. 480,000.
A 80kg stone falls from the top of the 360 meter cliff. Neglecting friction, how fast will the stone be moving just before it hits the ground?
Answers
The stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
To find how fast will the stone be moving just before it hits the ground?This problem can be solved using the laws of kinematics and conservation of energy. The potential energy of the stone at the top of the cliff is converted to kinetic energy as it falls. We can equate the potential energy at the top of the cliff to the kinetic energy just before hitting the ground.
Potential energy = mgh,
Where
m is the mass of the stone g is the acceleration due to gravity (9.8 m/s^2) h is the height of the cliff (360 meters)Kinetic energy = (1/2)mv^2,
Where
v is the velocity of the stone just before hitting the ground.Equating these two expressions and solving for v, we get:
mgh = (1/2)mv^2
v^2 = 2gh
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 x 9.8 m/s^2 x 360 m) = 84.4 m/s
Therefore, the stone will be moving at a speed of approximately 84.4 meters per second just before it hits the ground, neglecting friction.
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Calculate the de Broglie wavelength of a proton whose kinetic energy is equal to the rest mass energy of an electron. What should be the accelerating potential that need to be applied on an electron so that it has a de Broglie wavelength equal to that of the proton calculated above?
Answers
mvh=1. 654106. 6210=41014m is the de Broglie wavelength of a proton whose kinetic energy is equal to that of the proton.
What is the energy of an electron that has undergone a 100 kV potential difference?An electron has an energy of 100,000 eV (100 keV) at a potential difference of 100,000 V (100 kV), and so on. The energy gained by an ion with a double positive charge when it is accelerated through 100 V is 200 eV.
What is the relationship between kinetic energy and the de Broglie wavelength?De Broglie wavelength is the length of a particle with kinetic energy E. The wavelength changes to /2 when energy E is added to it.
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Explain the light detection technique of photovoltaic detection
Answers
Answer:
Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.
The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.
The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.
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At a fabrication plant, a hot metal forging has a mass of 90.8 kg, and a specific heat capacity of 434 J/(kg C°). To harden it, the forging is quenched by immersion in 689 kg of oil that has a temperature of 38.3°C and a specific heat capacity of 2680 J/(kg C°). The final temperature of the oil and forging at thermal equilibrium is 58.9°C. Assuming that heat flows only between the forging and the oil, determine the initial temperature in degrees Celsius of the forging.
Answers
The initial temperature of the forging is approximately 1,090.42°C.
To determine the initial temperature of the forging, we can use the principle of conservation of energy. The heat lost by the forging is equal to the heat gained by the oil during the quenching process.
The heat lost by the forging can be calculated using the formula:
Q_lost = m_forging * c_forging * (T_forging_initial - T_equilibrium)
where:
- Q_lost is the heat lost by the forging
- m_forging is the mass of the forging (90.8 kg)
- c_forging is the specific heat capacity of the forging (434 J/(kg C°))
- T_forging_initial is the initial temperature of the forging (unknown)
- T_equilibrium is the final temperature of the oil and forging at thermal equilibrium (58.9°C)
The heat gained by the oil can be calculated using the formula:
Q_gained = m_oil * c_oil * (T_equilibrium - T_oil_initial)
where:
- Q_gained is the heat gained by the oil
- m_oil is the mass of the oil (689 kg)
- c_oil is the specific heat capacity of the oil (2680 J/(kg C°))
- T_oil_initial is the initial temperature of the oil (38.3°C)
Since the heat lost by the forging is equal to the heat gained by the oil, we can set up the following equation:
m_forging * c_forging * (T_forging_initial - T_equilibrium) = m_oil * c_oil * (T_equilibrium - T_oil_initial)
Plugging in the given values, we can solve for T_forging_initial:
90.8 kg * 434 J/(kg C°) * (T_forging_initial - 58.9°C) = 689 kg * 2680 J/(kg C°) * (58.9°C - 38.3°C)
Simplifying the equation:
90.8 * 434 * (T_forging_initial - 58.9) = 689 * 2680 * (58.9 - 38.3)
Solving for T_forging_initial:
T_forging_initial - 58.9 = (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)
T_forging_initial = 58.9 + (689 * 2680 * (58.9 - 38.3)) / (90.8 * 434)
Calculating the value:
T_forging_initial ≈ 1,090.42°C
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a simple pendulum is made from a bob of mass 0.040 kg suspended on a light string of length 1.4m keeping the string taut the pendulum is pulled to one side until it has gained a height of 0.10m calculate the total energy of the oscillation
Answers
The total energy gained by the simple pendulum is 0.0392 J.
What is the total energy of the oscillation?The total energy of the oscillation is the energy gained by the simple pendulum when it is pulled to one side until it has gained a height of 0.10m.
The total energy of the oscillation of the simple is calculated as follows;
U = mgh
where;
m is the mass of the suspended objectg is acceleration due to gravityh is the height gained by the pendulumThe given parameters include the following;
mass of the suspended object = 0.04 kg
acceleration due to gravity = 9.8 m/s²
h is the height gained by the pendulum = 0.1 m
The total energy gained by the simple pendulum is calculated as follows;
U = 0.04 kg x 9.8 m/s² x 0.1 m
U = 0.0392 J
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a. When throwing a ball vertically upward, my hand moves through a distance of about 1.0 m before the ball leaves my hand. The 0.80 kg ball reaches a maximum height of about 20 m above my hand. while the ball is in my hand after the ball leaves my hand
Answers
The required, it experiences a downward force due to gravity and a force due to air resistance.
What is the projectile motion?Projectile motion is the movement of an entity projected into space. After the initial force that launches the object, it only experiences the force of gravity. The object is called a projectile, and its path is called its trajectory.
Here,
When throwing a ball vertically upward, there is a displacement of about 1.0 m from the initial position of the hand to the position where the ball leaves the hand. The mass of the ball is 0.80 kg and it reaches a maximum height of about 20 m above the initial position of the hand. While the ball is in the hand after it leaves, it experiences a downward force due to gravity and a force due to air resistance.
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A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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What type of bond is most likely to form between two gold (Au) atoms?
Answers
Answer:
I believe it would be a metallic bond.
Explanation:
A 0.10kg ball at rest is hit by a golf club. The club applies a force of 700N to the ball but is only in contact with the ball for about .05s. How fast would the ball be moving after the impact?
Answers
A ball at rest hit by a golf club has initial velocity zero. The ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
What is force?The action of push or pull which changes the state of motion or rest of a body is called force.
The club applies a force of 700N to the ball and the time of impact is 0.05s. The mass of ball is 0.10kg.
The impact force F is equal to the change in momentum of the ball multiplied by time of impact t. The momentum is the product of mass m and velocity v after impact.
F= (mv -mu) x t
The ball is initially at rest, so u =0
F = mvt
Substitute the values into the above equation of force to find the velocity.
v = F / mt
v =700 / (0.10 x 0.05)
v = 1.4 x 10⁵ m/s
Thus, the ball will be moving after the impact at speed of 1.4 x 10⁵ m/s.
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In 7.5 s, 4200 waves pass a given point. What is the frequency of the waves?
Answers
In 7.5 s, 4200 waves will pass a given point. Then, the frequency of the waves is 560 Hz.
Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is the rate at which a wave completes a full cycle, which is usually measured as the number of wavelengths that pass a fixed point in a unit of time.
The formula for frequency is;
frequency = waves/time
Where "waves" is the number of waves that pass a given point and "time" is the time it takes for those waves to pass.
In this case, we know that 4200 waves pass a given point in 7.5 seconds, so we can plug those values into the formula;
frequency = 4200/7.5
Simplifying;
frequency = 560
Therefore, the frequency of the waves is 560 Hz.
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a car is traveling with a momentum of 15,000 kgm/s. It strikes a garbage can on the curb. If the garbage can is launched off of the bumper with a momentum of 5,000 kgm/s, how much momentum does the car still have?
Answers
Answer:
c
Explanation:
it was a crash they both lost momentum
What is the function of vertebrae?
Answers
The vertebrae protect and support the spinal cord. They also bear the majority of the weight put upon your spine. The body of each vertebra is the large, round portion of bone.
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A fish pond appears to be 1m deep but when vewed vertically above the refractive Index of the Water on the pond is 1.5. calculate the real depth formed
Answers
Answer:
real depth / apparent depth = R.I.
Real depth = 1.5 x 1 = 1.5 m
Which of the following is not among the uses of dimensional analysis? (a) determination of the Numerical constant (b) to convert one system of unit to another (c) to change the units of derived quantities (d) to test the correctness of an equation
Answers
To convert one system of unit to another of derived quantities is not a use of dimensional analysis.
What is dimensional analysis?Checking for consistency in the dimensions on both sides of an equation entails looking at the dimensions of the physical quantities involved in a problem, such as length, mass, time, electric charge, and temperature.
The core tenet of dimensional analysis is that physical quantities, such as length, mass, and time, may be described in terms of their basic dimensions.
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All of the options listed are included in the uses of dimensional analysis.
What is dimensional analysis?Dimensional analysis is a powerful tool used in physics to:
check the correctness of equations derive new equationsconvert units from one system to anotherdetermine numerical constants that relate physical quantities.The dimensional analysis involves analyzing the dimensions of physical quantities and using them to establish relationships between them.
By using the principles of dimensional analysis, we can simplify complex physical problems and gain insights into the behavior of physical systems.
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a cheetah can accelerate from rest to a speed of 30.0 m/s in 7.00s. wht is its acceleration?
Answers
The given value of the speed of cheetah is,
\(v=30ms^{-1}\)The time during the speed v is,
\(t=7\text{ s}\)The relation between the acceleration, speed and time is,
\(a=\frac{v}{t}\)Substituting the known values,
\(\begin{gathered} a=\frac{30}{7} \\ a=4.3ms^{-2} \end{gathered}\)Thus, the value of the acceleration is 4.3 meter per second squared.
Answer:
30×7=210m it is easyokok
A 1.35 kg block is pulled across a flat, frictionless floor with a 3.07 n force at 32.0 above horizontal. What is the acceleration of the block
Answers
1. Calculating the horizontal component of the applied force:
Horizontal component = 3.07 N * cos(32.0°)
Horizontal component ≈ 2.597 N
2. Calculating the acceleration of the block:
Acceleration = Horizontal component / Mass
Acceleration = 2.597 N / 1.35 kg
Acceleration ≈ 1.925 m/s²
Therefore, the acceleration of the block is approximately 1.925 m/s².