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What is: n(An BC).
Question Help: Message instructor

Question:

Felipe is riding his skateboard toward Lilah at 15 km/h. He throws a football to Lilah. The football is thrown at 8.

Answer:

23 km/h

Explanation:

photo means light in latin

kinetic means to move

The potential difference across the each bulb and the current entering each bulb.

Each bulb in a straightforward parallel circuit receives the entire battery power. This is explains why the parallel circuit's lights will shine stronger than the series circuit's. The parallel circuit also has the benefit of maintaining an electricity even if one loop is disconnected.

The same brightness is produced when two identical bulbs are linked in parallel as it is when they are connected in a series, which is why.

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The rocket comes to rest from an initial velocity  of 1000 km/h  or 277.7 m/s within 1.1 seconds. Then the deceleration of the rocket stud  is - 252.52  m/s² .

The acceleration of an object is the rate of change in velocity. The term "accelerating" is used to indicate the positive change in velocity. Deceleration is just opposite, it indicates the decreasing rate of velocity.

acceleration a=  v - u/t

where v is the final velocity and u be the initial velocity.

Given t = 1.1 s

v = 0 since the rocket is going to rest.

u = 1000 km/hr

  = 277.7 m/s.

Then a = 0 - 277.7 m/s/ 1.1 s

            = - 252.52  m/s²

Therefore, the deceleration of the rocket is -252.52  m/s² .

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the rope wouldnt move, the force of both dogs pulling us also called tension

The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².

To calculate the average acceleration of the motorcycle, we can use the formula:

Average acceleration = (final velocity - initial velocity) / time

First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.

Converting the final velocity:

Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s

Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:

Average acceleration = (21.67 m/s - 0 m/s) / time

To find the time taken to reach this velocity, we need to use the formula for average speed:

Average speed = total distance/time

Rearranging the formula:

time = total distance / average speed

Plugging in the values:

time = 50 m / 21.67 m/s ≈ 2.31 seconds

Now we can calculate the average acceleration:

Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²

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To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

Answer:

A

Explanation:

One of the main benefits of informational interviewing is that it allows the person conducting the interviews to gain insights and information about a particular career or industry.

Hi there!

Recall the equation for work given a potential difference and charge:
\(\large\boxed{W = qV}\)

W = Work (J)
q = charge (C)
V = Potential difference (V)

The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.

Thus:

\(W' = (2Q)(V) = 2W\)

This is equivalent to:

\(\large\boxed{2W = \text{ d) } 2K}}\)

The position at time t = 0.2 s, given the data from the question is 132 cm

Velocity is simply defined as the rate of change of displacement with time. Mathematically, it can be expressed as:

Velocity = change of displacement / time

With the above formula, we can obtain the position at t = 0.2 s. Details below:

From the question given above, the following data were obtained:

Velocity = change of displacement / time

510 = (Displacement 2 - 30) / 0.2

Cross multiply

Displacement 2 - 30 = 510 × 0.2

Displacement 2 - 30 = 102

Collect like terms

Displacement 2 = 102 + 30

Displacement 2 = 132 cm

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Answer:

where?

Explanation:

ill edit my answer when see it

The speed at the intake is 199.89 cm/s

Since the volume flow rate, Q = Av is constant where

We have that from the continuity equation,

A₁v₁ = A₂v₂ where

So, A₁v₁ = A₂v₂

πd²v₁/4 = L²v₂

Making v₁ subject of the formula, we have

v₁ = 4L²v₂/πd²

So, substituting the values of the variables into the equation, we have

v₁ = 4L²v₂/πd²

v₁ = 4(25.06 cm)² × 100 cm/s/[π(20 cm)²]

v₁ = 4 × 628.0036 cm² × 100 cm/s/[400π cm²]

v₁ = 2512.0144 cm² × 100 cm/s/1256.6371 cm²

v₁ = 1.9989 × 100 cm/s

v₁ = 199.89 cm/s

So, the speed at the intake is 199.89 cm/s

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The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO

When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.

When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.

            At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.

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When a car comes to a stop, the car’s brakes create a force that is in the opposite direction as the velocity vector.

A friction force is a type of force that opposes two surfaces that are in contact with each other.

According to Newton's first law of motion, an object at rest or uniform motion in a straight line will continue in that state unless it is acted upon by an external force. And the object will tend to move in the direction of the applied force.

So if a car's brake is applied, it will create a friction force that will oppose the motion of the car and by so doing, it will gradually bring the car to a complete stop.

The force created by the brake of the car is friction force and it is in opposite direction to the force of the car.

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\( \Large {\underline { \sf {Required \; Solution :}}}\)

We have ―

We have been asked to calculate the mass of the car, m.

\(\qquad\implies\boxed{\red{\sf{ P = mv}}}\\\)

\( \quad \twoheadrightarrow\sf { 20000 = 25m} \\ \)

\( \quad \twoheadrightarrow\sf { \cancel{\dfrac{20000}{25}} = m} \\ \)

\(\quad\twoheadrightarrow\boxed{\red{\sf{ m = 800 \; kg}}}\\\)

Therefore, mass of the car is 800 kg.

Answer:cart 3

Explanation:

The area οf the clοud that was struck by lightning had a negative charge, sο, οptiοn (d) is cοrrect.

The negatively charged atοm's electrοns are respοnsible fοr this. An atοm's tοtal negative charge, which is prοduced by all οf its electrοns, cοunteracts the pοsitive charge οf the prοtοns in the atοmic nucleus.

Prοtοns and electrοns, which functiοn as charge carriers, frequently carry bοth pοsitive and negative electric charges. By mοving charges, energy is prοduced. Charge—alsο referred tο as electric charge, electrical charge, οr electrοstatic charge—is a prοperty οf a unit οf matter in physics and is denοted by the letter q.

Therefοre, The area οf the clοud that was struck by lightning had a negative charge, sο, οptiοn (d) is cοrrect.

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If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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The upward acceleration of the acrobat is 1.833 m/s².

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

Given parameters:

Mass of the acrobat; M = 588 N.

Weight of the acrobat acting downwards; W = 588 N.

Upward force provided by each of the two ropes; f = 349 N.

Hence, net force acting on the acrobat in upward direction = 2f -w

= (2×349 - 588 ) N.

= 110 N.

Hence, the upward acceleration of the acrobat is = net force/ mass

= 110/60 m/s².

=1.833 m/s².

So, the upward acceleration of the acrobat is 1.833 m/s².

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Answer:

1,860 g

Explanation:

In a system, the coefficient of static friction is usually higher than the coefficient of kinetic friction. This means that the kinetic friction is usually less than the static friction. From the question, since the book is already sliding, it means that kinetic friction is the friction in play. This means that before the reading on the scale that could have been possible at the moment the student overcame the static friction must be greater than the reading on the scale during sliding. The only option above 1580 g is 1860 g

The average angular speed in each direction of the rotating head is 9.42 rad/s.

The average linear speed in each direction of the bristles against the teeth is 5.09 cm/s.

The approximate speed of the bristles against the teeth when brushing by hand with an ordinary toothbrush is 1.26 cm/s.

Part A: The formula ω = Δθ/Δt can be used to determine the rotating head's average angular speed in each direction.

Where Δθ denotes the angular displacement, Δt denotes the rotational time, and ω denotes the angular speed.

In this instance,

Δt = 1/(7600/2) s/rotation, and Δθ= 70.0 degrees = 70.0 x (π/180) radians.

Thus, ω = (70.0 x (π/180)) / (1/(7600/2)) = 9.42 rad/s is the average angular speed in each direction.

Part B: The following equation can be used to determine the average linear speed of the bristles against the teeth:

v = rω

where r is the head's radius (0.55 cm), v is the linear speed, and ω is the angular speed.

The average linear speed is therefore v = 0.55 x 9.42 = 5.09 cm/s in each direction (rounded to two significant figures)

Part C: Although it is challenging to measure precisely, it is possible to estimate the speed of the bristles against the teeth when brushing by hand with a regular toothbrush. The average linear speed can be estimated using the formula v = rΔθ/Δt if we suppose that the bristles rotate through an average displacement of 45 degrees five times each second.

Where Δθ = 45 degrees, Δt = 1/5 s, and r = the radius of the bristles (estimated as 0.2 cm).

So, the average linear speed is approximately:

v = 0.2 x (45 x (π/180)) / (1/5) = 1.26 cm/s (rounded to two significant figures).

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Based on the research data, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.

A confidence interval is a range of values within which a researcher can be fairly certain that the true value of the mean can be found.

The confidence Interval of the survey above is calculated using the formula:

\( x ± z( σ/√n)\)

where

From the data provided;

x = 2.0

σ = 5.1

n = 200

z = 2.576 for 99% confidence

Therefore, the confidence Interval is:

\( 2.0 ± 2.576( 5.1/√200)\)

Confidence interval = 2.0 ± 0.93.

Therefore, the psychologist can be 99% confident that the interval from 1.07 to 2.94 includes the unknown population mean µ.

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Answer:

486,750 kg*m/s

Explanation:

Momentum is mass*velocity

M = m*v

M = 8850kg*55m/s

M = 486,750 kg*m/s

The momentum of an 8850 kg medium truck that is traveling with a velocity of 55 m/s west on the highway is 486750 kg m / s.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.

According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum.

Given:

The mass of the truck is, m = 8850 kg,

The velocity of the truck is, v = 55 m/s,

Calculate the momentum of the truck as shown below,

Momentum = m × v

Momentum = 8850 × 55

Momentum = 486750 kg m / s

Thus, the Momentum of the truck is 486750 kg m / s.

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The skater's final angular velocity is approximately 9.86 rad/s.

The skater's final angular velocity can be calculated using the principle of conservation of angular momentum. The equation for angular momentum is given by:

L = Iω

where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.

Initially, the skater has an angular momentum of:

L_initial = I_initial * ω_initial

Substituting the given values:

L_initial = 2.12 kg m² * 3.25 rad/s

The skater's final angular momentum remains the same, as angular momentum is conserved:

L_final = L_initial

The final moment of inertia is given as 0.699 kg m². Therefore, the final angular velocity can be calculated as:

L_final = I_final * ω_final

0.699 kg m² * ω_final = 2.12 kg m² * 3.25 rad/s

Solving for ω_final:

ω_final = (2.12 kg m² * 3.25 rad/s) / 0.699 kg m²

Hence, the skater's final angular velocity is approximately 9.86 rad/s.

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Answer:

9.8 seconds

Explanation:

Let's start by changing the speeds of both animals into meters per second:

107 km/h = 107000 m/3600s = 29.72 m/s

71.8 km/h = 71800 m/3600s = 19.94 m/s

The distance covered equation for the cheetah is:

Dc = 29.72 t

The distance covered equation for the gazelle considering as origin the cheetah's starting location, is:

Dg = 95.6 + 19.94 t

We make both equations equal at the time (t) the cheetah catches with the gazelle:

Dc =Dg

29.72 t = 95.6 + 19.94 t

solve for "t":

29.72 t - 19.94 t = 95.6

9.78 t = 95.6

t = 95.6 / 9.78

t = 9.775 seconds

We can approximate it to 9.8 seconds

Answer: B im sorry if its wrong

Explanation:

Yes it can, an object can be moving a certain direction while the ACCELERATION is in the opposite direction.

Lets say your riding a bike... if your squeezing your handle bar breaks, the acceleration of the bike would be pushing in the opposite direction of the direction the bike is moving.

Hope this helped!

Answer:

Where is following ??

Post proper Ques

Answer:

I don't know but take a guess from these

Explanation:

Trojan Asteroids

Moons

Satellites

trojan asteroids revolves around the planet due to gravitational force of that planet.

An asteroid that is pulled by a gravitational force of planet and orbits around that planet is called trojan asteroids. These trojan asteroids are present around the Jupiter planet. The Jupiter has a large population of trojan asteroids revolving around the planet.

The gravitational force of the planet compels the asteroid to move around the planet and prevent it from going away to the atmosphere so we can conclude that trojan asteroids revolves around the planet due to gravitational force of that planet.

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