Abigail just measured her pet snake and found out it is 111 inches long. The last time she measured, the snake was 74 inches long. What percent longer is the pet snake now?

Answer:

no photo

Step-by-step explanation:

we need a photo to decide if answer is correct or not

Answer:

The average rate will be 2.40 dollars per kg.    

Hence, option D is correct.

Step-by-step explanation:

From the table, it is clear that the order size is located on the x-axis and the price is located on the y-axis.

The price of 100 kg cumin = $450

The price of 600 kg cumin = $1650

so

at x₁ = 100, f(x₁) = 450

at x₂ = 600,  f(x₂) = 1650

Using the formula to determine the average rate of change at which the total cost increases will be:

Average rate = [f(x₂) - f(x₁)] / [ x₂ - x₁]

                      = [1650 - 450] / [600-100]

                      = 1200 / 500

                      = 2.4

Therefore, the average rate will be 2.40 dollars per kg.    

Hence, option D is correct.

Answer: g(x)=lx-3l

Step-by-step explanation:

g(x) = |x − 3| is the translation of the graph has the domain [−3, 6]. Therefore, option D is the correct answer.

Given that, the function f(x) = |x| is graphed over the interval [−6, 3].

We need to find which translation of the graph has the domain [−3, 6].

The domain of a function is the set of all possible inputs for the function.

g(x) = |x − 3| graph has the domain [−3, 6].

Therefore, option D is the correct answer.

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Answer: x= 6, y= -2

Step-by-step explanation: hope this helps.

answer

x=6

y=-2

step by step explanation

Using the properties of modular arithmetic we have shown that if p is a prime number and p is not divisible by 2 or 3, then either p ≡ 1 (mod 6) or p ≡ 5 (mod 6)

To prove that if p is a prime number and p is not divisible by 2 or 3, then either p ≡ 1 (mod 6) or p ≡ 5 (mod 6), we can use the properties of modular arithmetic.

We know that any integer can be expressed as one of six possible remainders when divided by 6: 0, 1, 2, 3, 4, or 5.

Now, let's consider the prime number p.

Since p is not divisible by 2 or 3, it means that p is not congruent to 0, 2, 3, or 4 (mod 6).

So we are left with two possibilities: p ≡ 1 (mod 6) or p ≡ 5 (mod 6).

To determine which of these two possibilities holds, we can consider the remainders when p is divided by 6.

We know that p is a prime number, so it cannot be congruent to 0 or divisible by 6.

Thus, the only remaining possibilities are p ≡ 1 (mod 6) or p ≡ 5 (mod 6).

To show this, we can consider two cases:

1. p ≡ 1 (mod 6).

If p ≡ 1 (mod 6), then p can be written as p = 6k + 1 for some integer k.

Since p is prime, it cannot be expressed as a multiple of 2 or 3. Therefore, p satisfies the provided condition.

2. p ≡ 5 (mod 6)

If p ≡ 5 (mod 6), then p can be written as p = 6k + 5 for some integer k.

Again, since p is prime, it cannot be expressed as a multiple of 2 or 3.

Thus, p satisfies the provided condition.

Therefore, we have shown that if p is a prime number and p is not divisible by 2 or 3, then either p ≡ 1 (mod 6) or p ≡ 5 (mod 6)

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Answer:

Hey there!

3x+y=7

2x+y=6

3x+y=7

-2x-y=-6

Add these two equations vertically so the y terms cancel out (this is known as the elimination method)

x=1

3x+y=7

3(1)+y=7

3+y=7

y=4

(x=1, y=4)

Hope this helps :)

Answer:

6

Step-by-step explanation:

\(216^{\frac{1}{3} }\) is the same as \(\sqrt[3]{216}\)

so the answer is 6

(a) This is possible. P0​ is false, which makes the antecedent of (P0​⇒P1​) false. Since the conditional is true, its consequent P1​ must be true. Therefore, P1​ must be true.

(g) This is possible. P0​ is true, which makes the antecedent of (P1​⇒P0​) true. Since the conditional is true, its consequent P0​ must also be true. Therefore, P1​ may be either true or false.

(b) This is not possible. If P0​ is false, then the antecedent of (P0​⇒P1​) is true, which means that the conditional cannot be false. Therefore, this situation is not possible.

(h) This is possible. P0​ is true, which makes the consequent of (P1​⇒P0​) true. Since the conditional is false, its antecedent P1​ must be false. Therefore, P1​ must be false.

(c) This is possible. If P0​ is true, then the antecedent of (P0​⇒P1​) is true. Since the conditional is true, its consequent P1​ must also be true. Therefore, P1​ must be true.

(i) This is possible. If P0​ is false, then the antecedent of (P0​⇔P1​) is true. Since the biconditional is true, its consequent P1​ must also be true. Therefore, P1​ must be true.

(d) This is possible. P0​ is true, which makes the antecedent of (P0​⇒P1​) false. Since the conditional is false, its consequent P1​ can be either true or false. Therefore, P1​ may be either true or false.

(j) This is not possible. If P0​ is true, then the antecedent of (P0​⇔P1​) is true. Since the biconditional is false, its consequent P1​ must be false. But this contradicts the fact that P0​ is true, which makes the antecedent of (P0​⇔P1​) true. Therefore, this situation is not possible.

(e) This is possible. P0​ is false, which makes the consequent of (P1​⇒P0​) true. Since the conditional is true, its antecedent P1​ must also be true. Therefore, P1​ must be true.

(k) This is possible. If P0​ is false, then the antecedent of (P0​⇔P1​) is false. Since the biconditional is false, its consequent P1​ must be true. Therefore, P1​ must be true.

(f) This is possible. P0​ is false, which makes the antecedent of (P1​⇒P0​) true. Since the conditional is false, its consequent P0​ can be either true or false. Therefore, P0​ may be either true or false.

(l) This is possible. If P0​ is true, then the antecedent of (P0​⇔P1​) is true. Since the biconditional is true, its consequent P1​ must also be true. Therefore, P1​ must be true.

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The angle bisector that was constructed incorrectly is Example fiqure  2 , this was a result of not dividing the angle into equal parts.

An angle bisector can be described as a line which is used in dividing a  a given angle usually into  two equal degrees.

It should be noted that the the bisector in the second example was incorrectly constructed as a result of the  bisector not dividing <ABC into two equal parts it doe not matter if it passes intersection of the arcs and point B.

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Answer:

A Linear Pair is two adjacent angles whose non-common sides form opposite rays. ∠1 and ∠2 form a linear pair. The line through points A, B and C is a straight line.

Hope this helps

Answer:

Two adjacent angles can be supplementary or complementary.

Step-by-step explanation:

IF they are supplementary then they are a linear pair.

we have that

Part A

s=3 1/2

Find A

A=s^2

s=3 1/2=7/2

substitute

A=(7/2)^2

A=49/4 unit2

convert to mixed number

49/4=48/4+1/4=12+1/4=12 1/4 unit2

Part b

S=8.257 units

A=(8.257)^2

A=72.71 unit2

Part c

A=361 unit2

Find s

A=s^2

substitute

361=s^2

square root both sides

s=19 units

Part d

A=562 unit2

A=s^2

562=s^2

s=23.71 units

Answer:

1. \(2 / 5\) - Fractional form, \(0.4\) - Decimal Form

2. \(5 / 8\) - Fractional form, \(0.625\) - Decimal Form

3. \(6 / 7\) - Fractional form, \(0.8571\) - Decimal Form

4. \(\sqrt{a / b}\)

5. \(\sqrt{a * b}\)

Step-by-step explanation:

1. \(\sqrt{4 / 25}\)

Steps:

1. Divide  - \(4 / 25\)

2. Then take the square root of what you got - \(\sqrt{0.16}\) = \(0.4\)

2. \(\sqrt{25 / 64}\)

Steps:

1. Divide - \(25 / 64\)

2. Then take the square root of what you got - \(5 / 8\)

3. \(\sqrt{36 / 49}\)

Steps:

1. Take the square root of the top number - 6

2. Tage the square root of the bottom number - 7

3. Answer is 6/7.

4. \(\sqrt{a} / \sqrt{b}\) = \(\sqrt{a / b}\)

5. \(\sqrt{a} * \sqrt{b}\) = \(\sqrt{a * b}\)

Formula:

\(\sqrt{a} / \sqrt{b}\) = \(\sqrt{a / b}\)

\(\sqrt{a} * \sqrt{b}\) = \(\sqrt{a * b}\)

Answer:

4.87 to the fourth power

Step-by-step explanation:

0.000487 in Scientific Notation:

4.87  * 10^-4

The probability of either of the two die landing on 4 is 1/36.

To calculate the probability of either of the two dice landing on 4 when rolling two regular dice, we need to determine the favorable outcomes and the total possible outcomes.

Favorable outcomes: There are three ways to get a 4 with two dice: (1, 3), (3, 1), and (2, 2).

Total possible outcomes: Each die has 6 sides, so there are 6 possible outcomes for the first die and 6 possible outcomes for the second die.

Therefore, the total possible outcomes are 6 x 6 = 36.

Probability = Favorable outcomes / Total possible outcomes

Probability = 1/6 x 1/6

Probability = 1/36

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we have

Lineal function

y = mx+b

Replacing with the values given:

y = 2x+7

y=2(8)+7

y= 23

Answer:

1.= Correct

2.= False(Raul has a negative slope and Becky has a positive, it is not both positive so FALSE)

3.= Corect(They both cross on the x and y axis.)

Step-by-step explanation:

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The area if base x height

8 x height = 96

Divide both sides by 8 to find the base size:

96 / 8 = base

base = 12

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The area of a rhombus can be found by multiplying the length of one of its sides by the height of a perpendicular line from the center to a side.

The height of the rhombus is the distance from the center of the rhombus to one of its sides, perpendicular to that side.

The formula for the area of a rhombus can be written as A = s*h, where A is the area, s is the length of one of the sides of the rhombus, and h is the height of the rhombus.

It's important to note that this method of finding the area of a rhombus without diagonals can only be used when the rhombus is a regular polygon, a polygon with all sides and angles congruent. When the rhombus is not a regular polygon, then you can find the area by using the diagonals.

Additionally, it's important to mention that a rhombus can be defined as a parallelogram with all sides congruent or a square with its angles not 90 degrees.

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Answer:600

Step-by-step explanation:

300,000/ 500 =600

The minimum distance that Malia needs on her last throw to win the game is less than 2.12 meters.

In this target game, Malia needs to have the lowest mean distance of all throws to win. The mean distance is calculated by adding up all the distances and dividing by the number of throws.

First, we need to calculate the mean distance of Malia's first 7 throws.

Mean distance = (2 + 3 + 4 + 2 + 5 + 3 + 4) / 7 = 3.14

Now, we know that Malia's mean distance must be less than 3.14 to win the game. Let's call the distance of her last throw x.

The mean distance of all 8 throws will be: (2 + 3 + 4 + 2 + 5 + 3 + 4 + x) / 8

To find the minimum distance that Malia needs on her last throw to win the game, we can set up an inequality:

(2 + 3 + 4 + 2 + 5 + 3 + 4 + x) / 8 < 3.14

Multiplying both sides by 8 gives us:

2 + 3 + 4 + 2 + 5 + 3 + 4 + x < 25.12

Simplifying gives us:

x < 25.12 - 23

x < 2.12

Therefore, the minimum distance that Malia needs on her last throw to win the game is less than 2.12 meters.

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An arc whose measure is less than 180 degrees is called a minor arc. An arc whose measure is greater than 180 degrees is called a major arc. An arc whose measure equals 180 degrees is called a semicircle, since it divides the circle in two.

Minor arcs are associated with less than half of a rotation, so minor arcs are associated with angles less than 180°. Major arcs are associated with more than half of a rotation, so major arcs are associated with angles greater than 180°.

A chord AB of a circle divides the circle into two segments. If AB is a diameter, the two congruent segments are called semicircles − the word 'semicircle' is thus used both for the semicircular arc, and for the segment enclosed by the arc and the diameter.

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Algebraically, it was possible to show that the point (2,0) is on the side (PR) of the given triangle.

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  In this triangle from the trigonometric ratios or the Pythagoras Theorem (\((hypotenuse)^2=(side_1)^2+(side_2)^2\)), it is possible finding angles or sides.

The question gives the points for a right triangle, you can draw the triangle, see the attached image. From the figure, it is possible to see the lengths for the sides PQ=8 and QR=10.

A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:

a= the slope. If

b=the constant term that represents the y-intercept.

The slope for the line PR can be calculated from the ratio between the side PQ and QR.

\(a=\frac{PQ}{QR}=\frac{4-(-4)}{(-3-7)}=\frac{8}{-10} =-0.8\)

From the attached figure, it is possible to see that the y-intercept is (2,0). Therefore, the given point is on the side PR, but the question asks to show this algebraically.

From the Standard form (ax+b), the equation for the line PR will be:                      y=- 0.8x+b. After that, you should replace the coordinates of the given point P (-3,4) in the equation line:  y=-0.8x+b for finding b.

4=-0.8*(-3)+b

4=2.4+b

b=4-2.4= 1.6

Then, the equation line y=-0.8x+1.6.

Now you should replace the x-coordinate for the point (2,0) in the equation  y=-0.8x+1.6.

y=-0.8*2+1.6

y=-1.6+1.6

y=0

The calculated y-coordinate is the same the y-coordinate for the point (2,0), thus the point (2,0) is on the side of the triangle.

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Answer:

x = 0

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

2x+6<−x+6

Step 2: Add x to both sides.

2x+6+x<−x+6+x

3x+6<6

Step 3: Subtract 6 from both sides.

3x+6−6<6−6

3x<0

Step 4: Divide both sides by 3.

3/3 < 0 /3

x = 0

Answer:

Step-by-step explanation:

(sin5-sin15+sin25-sin 35)/(cos 5-cos 15+cos 25 +cos 35)\(=\frac{-(sin 35-sin 5)+(sin 25-sin 15)}{(cos 35+cos 5)-(cos 25+cos 15)} \\\)

\(=\frac{-2 cos \frac{35+5}{2}sin \frac{35-5}{2}+2 cos \frac{25+15}{2} sin \frac{25-15}{2} }{2cos \frac{35+5}{2}cos \frac{35-5}{2}-2cos \frac{25+15}{2} cos \frac{25-15}{2} }\)

\(=\frac{-cos 20 sin 15+cos 20 sin 5}{cos 20 cos 15-cos 20 cos 5} \\\)

\(=\frac{- cos 20(sin 15-sin 5)}{cos 20(cos 15-cos 5)}\)

\(=\frac{-(sin 15-sin 5)}{cos 15-cos 5)} \\=\frac{-2cos \frac{15+5}{2}sin \frac{15-5}{2} }{-2 sin \frac{15+5}{2}sin \frac{15-5}{2} } } }\)

\(=\frac{cos 10 sin 5}{sin 10 sin 5}\)

\(=\frac{cos 10}{sin 10}\)

=cot 10

Answer:

Option A

Step-by-step explanation:

-5(3+4) = -15 - 20 = -35

It means that both people have antigens, but the second person has more of them.

Antigens are substances that can trigger an immune response in the body. They are typically proteins that are found on the surface of bacteria, viruses, and other foreign substances that enter the body. When the immune system detects an antigen, it produces antibodies to attack and destroy it. This helps the body to defend itself against infections and other diseases. Antigens can also be used in vaccines to help the body build immunity to a particular disease.

Since there is a color change in the sample in the given case, this indicates that although both individuals possess the antigen, the second individual has a greater quantity or concentration of the antigen in their body. The dilution is 1/5 and 1/100. This is so as the amount of antigen in the sample is still detected even in larger quantities of solution.

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Answer:

-14

Step-by-step explanation:

2a + 4b

Let a = 5 and b = -6

2*5 +4(-6)

Multiply

10 - 24

Subtract

-14

Answer:

-14

Step-by-step explanation:

2a + 4b

= 2(5) + 4(-6)

= 10 -24

= -14