a/a+2 = 3/5 ,, can someone give me the step by step solution to this? or at least explain it to me :’)

Answer:

\( - 1 \leqslant d < 5 \\ \)

Answer:

143.29

Step-by-step explanation:

\(\frac{14329}{100}\)

\(\frac{14329}{100}\)

<3 Red

Mary's HLV is $2,215,773.95.

Mary's HLV if she works until 70 is $1,611,008.23.

Mary's COE if she works until 75 is $5,130,372.40.

Mary's COE if she works until 70 is $2,985,308.60.

To calculate the Human Life Value insurance (HLV) of Mary, we need to determine the present value of her future income stream.

Annual after-tax earnings = $55,000 x (1 - 0.15) = $46,750

Total after-tax earnings over working life = $46,750 x (1 + 0.03)^(75-35) = $3,382,820.33

Total personal consumption = 27% x $3,382,820.33 = $914,073.89

Calculate Mary's HLV:

= $3,382,820.33 - (1 + 0.05)^(-1) x $914,073.89

= $2,215,773.95

Therefore, Mary's HLV is $2,215,773.95.

If Mary works until 70 total after-tax  = $46,750 x (1 + 0.03)^(70-35) = $2,124,182.09

Mary's HLV if she works until 70 is $1,611,008.23.

To calculate the Capitalization of Earnings (COE) method. Here's how we can calculate it:

Calculate Mary's expected earnings in her final year of work:

Expected earnings in final year = $55,000 x (1 + 0.03)^(75-35) = $256,518.62

Apply a capitalization rate to the expected earnings:

COE = expected earnings in final year / capitalization rate

= $256,518.62 / 0.05

= $5,130,372.40

Therefore, Mary's COE if she works until 75 is $5,130,372.40.

If Mary works until 70, her expected earnings in her final year of work would be:

Expected earnings in final year = $55,000 x (1 + 0.03)^(70-35) = $149,265.43

Mary's COE if she works until 70 is $2,985,308.60.

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26400 is what they travel in feet in a day divide that by 24 and that should be your answer

True. The double integral can be used to compute the area of a region d in a plane by integrating the function f(x,y). In fact, the double integral of f(x,y) over a region D in the xy-plane gives the volume of the solid between the surface z=f(x,y) and the xy-plane over the region D.

However, if we take the function f(x,y) to be the constant function 1, then the double integral of f(x,y) over the region D is simply the area of the region D. Therefore, we can compute the area of a region D in a plane by integrating the constant function 1 over the region D using the double integral. Integrating over two variables requires calculating two separate integrals, so the answer is more than 100 words.
True. A double integral can be used to compute the area of a region D in a plane by integrating the function f(x, y). To find the area, you would integrate the function f(x, y) = 1 over the region D, as the double integral represents the sum of the function values over the entire area. The double integral can be thought of as a generalization of single-variable integration, allowing us to find the area in two dimensions.

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Answer:

$52.50

Step-by-step explanation:

(2[7.25] + 2[24]) - 10

(14.50 + 48) - 10

62.50 - 10

= 52.50

Answer:

1/4

Step-by-step explanation:

in simplist form the answer is 1/4

Answer:

\( \boxed{3.744}\)

Step-by-step explanation:

\(62.4 = \frac{624}{10} \\ 0.06 = \frac{6}{100} \\ 62.4 \times 0.06 = \frac{624}{10} \times \frac{6}{100} = \frac{468}{125} = 3.744\)

The probability is 1%.

To determine the approximate probability that exactly two of the five marbles drawn from the bag are blue,

The total number of marbles in the bag is 10 + 15 + 5 + 20 = 50.

To calculate the favorable outcomes, we need to choose exactly two blue marbles from the 20 blue marbles available, which can be done in (20 choose 2) ways:

(20 choose 2) = 20! / (2! * (20 - 2)!) = 190 ways

Next, we need to choose the remaining three marbles from the non-blue marbles, which can be done in (30 choose 3) ways:

(30 choose 3) = 30! / (3! * (30 - 3)!) = 4,060 ways

The total number of possible outcomes is choosing any five marbles from the 50 available, which can be done in (50 choose 5) ways:

(50 choose 5) = 50! / (5! * (50 - 5)!) = 2,118,760 ways

Now, we can calculate the probability by dividing the favorable outcomes by the total outcomes:

Probability = (Number of favorable outcomes) / (Total number of outcomes) = 190 / 2,118,760

Approximately, the probability is 0.00896, which is approximately 0.896%.

Therefore, the closest option is 1%, which is the correct answer.

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7x+8y=19

-6x -8y=18

---------------  Add both equations

x = 37

Using x = 37 in the first equation:

7(37)+8y=19

259+8y = 19

8y = 19 - 259

8y = -240

y = -240/8

The ratio of the surface area of the earth and the moon is 16 / 1 and the ratio of the volume of the earth and the moon is 64 / 1.

The capacity occupied by a three-dimensional solid shape is known as volume. It is difficult to visualize in any shape, yet it may be compared among shapes. For instance, a compass box has a larger volume than an eraser placed inside of it.

Given:

The radius of the earth is 4 times the radius of the Moon, R = 4r

Calculate the ratio of the surface area of the earth and moon as shown below,

the surface area of the earth/surface area of the moon = 4πR² / 4πr²

the surface area of the earth/surface area of the moon = (4r)² / r²

the surface area of the earth/surface area of the moon = 16 / 1

Calculate the ratio of volume as shown below,

the volume of the earth/volume of the moon = 4 / 3 πR³ / 4 / 3 πr³

the volume of the earth/volume of the moon = (4r)³ / r³

the volume of the earth/volume of the moon = 64 / 1

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The system of equations on line 4 has the same solution set as the system of equations on line 1 because it was obtained from the original system by applying a series of elementary row operations that preserve the solution set of the system.

Yes, the system of equations on line 4 has the same solution set as the system of equations on line 1. This is because the system on line 4 was obtained from the system on line 1 by multiplying both sides of the first equation by 2 and the right-hand side of the second equation by -2.

These operations did not change the underlying equations themselves or the solution set of the system.

To understand this, we can use the concept of equivalent systems of equations. Two systems of equations are said to be equivalent if they have the same solution set, meaning they have the same set of values for the variables that make all the equations true simultaneously.

In this case, the system on line 4 was obtained from the system on line 1 by applying a series of operations that are known as elementary row operations.

These operations include multiplying an equation by a non-zero constant, adding a multiple of one equation to another, and swapping two equations.

Since each of these operations preserves the solution set of the system, the resulting system on line 4 has the same solution set as the original system on line 1.

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There are 5 possibilities:

a. That particular ad scored 140 percent above comparable ads.

b. That particular ad scored 40 percent above comparable ads.

c. The percentage of respondents who read half or more of the written material in the ad was 40 percent.

d. The percentage of respondents who recalled seeing the ad was 40 percent.

e. That particular ad is capable of generating market share gains of 40 percent.

The purpose of the Starch Service is to report to what extent a client's magazine advertisements are seen and read. Using Starch, a client can compare the readership of current advertisements with past advertisements, or competitors advertisements. One use for the service is that it provides information as to how advertisements can be presented so that readership can be increased by the manipulation of various elements of magazine advertising included in the reports.

The answer is option (b): That particular ad scored 40 percent above comparable ads.

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Answer:

  6050 square meters

Step-by-step explanation:

You want to know the largest rectangular area that can be enclosed using 220 meters of fencing for 3 sides.

For enclosure length x, the width of the enclosure is half the remaining fence: (220 -x)/2. The area is the product of length and width.

  A = (x)(220 -x)/2

This is the equation of a parabola that opens downward. Its vertex (maximum) is halfway between the zeros, which are x=0 and x=220. This means the area is maximized when x=110 and the width is (220-110)/2 = 55.

The maximum area is (110 m)(55 m) = 6050 m².

__

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The answer is 2025 sq. meter.

If you have 220 meters of fencing and want to enclose a rectangular area up against a long, straight wall, the largest area you can enclose is 4840 square meters. Explanation: To determine the largest possible area, we have to find out how to divide the 220 meters of fencing so that we can maximize the space enclosed by it. If one side of the rectangle is x meters long, the other side is (110 - x) meters long (because we have one straight wall to use as a side).The perimeter of the rectangle can be calculated by adding up all four sides of the rectangle. Hence:2x + (110 - x) + (110 - x) = 220We simplify the equation to solve for x:2x + 220 - 2x = 220-x = 55Therefore, one side of the rectangle is 55 meters long, and the other side is (110 - 55) = 55 meters long as well. The area of a rectangle is given by its length multiplied by its width. In this case, the area is:55 x 55 = 3025.

Therefore, the largest area that can be enclosed is 3025 square meters.

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The expression which is equivalent to 12 is 12 ÷ 1.

The correct answer choice is option B

check all that applies:

4 ÷ 12 = 0.34

12 ÷ 1 = 12

124 ÷ 4 = 31

12 ÷ 12 = 1

In conclusion, 12 ÷ 1 is the equivalent expression to 12

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Answer: 107.50

Step-by-step explanation:

RCV is more expensive compared to ACV, therefore, Shawn would have to pay more to insure his belongings with RCV coverage.

As Shawn rents an apartment in an all-brick building located in a historic, downtown neighborhood and the value of the belongings in the apartment is about $25,000, he will have to pay around $125 to $375 per year to insure his belongings while renting depending on the type of coverage he chooses.

A renter’s insurance policy can protect the belongings of renters who live in an apartment or house they rent and covers their liability towards others in case they get injured. For this reason, the cost of renter’s insurance will vary depending on the type of coverage needed. If Shawn wants more coverage, then he will pay a higher rate. There are two types of coverage which include actual cash value (ACV) and replacement cost value (RCV).

ACV is a coverage that pays for the value of the belongings, minus the depreciation. Whereas, RCV is a coverage that pays for the cost of replacing the belongings, regardless of their current value.  

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Cost function and Marginal cost function:

Example: Let's say a company produces widgets, and the cost function is given by C(q) = 1000 + 5q + 0.1q^2, where q is the quantity of widgets produced. The marginal cost function, MC(q), would be the derivative of this cost function, which is MC(q) = 5 + 0.2q.

Average cost function and Marginal Average cost function:

Example: Suppose the average cost function for a company manufacturing bicycles is AC(q) = 5000/q + 50, where q is the quantity of bicycles produced. The marginal average cost function, MAC(q), would be the derivative of this average cost function, which is MAC(q) = -5000/q^2.

Revenue function and Marginal Revenue function:

Example: Let's consider a company selling books, and the revenue function is given by R(q) = 20q - 0.5q^2, where q is the quantity of books sold. The marginal revenue function, MR(q), would be the derivative of this revenue function, which is MR(q) = 20 - q.

Average revenue function and Marginal average revenue function:

Example: Suppose

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The angle of elevation of the sun is \(tan^{-1}\)(106/ 135).

The angle of elevation:

The angle is formed by the line of sight and the horizontal plane for an object above the horizontal.

Here we have to find the angle of elevation of the sun.

Data given:

length of the tower = 106 feet

shadow form by the tower = 135 feet

The formula for the angle of elevation = height/base

tanФ = height/base

        = 106/ 135

Ф = \(tan^{-1}\)(106/135)

Therefore the angle of elevation is \(tan^{-1}\)( 106/ 135).

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The solution to the recurrence T(n) = 5T(n/5) + n using the iteration method is T(n) = n log_5(n+1).

To solve the recurrence T(n) = 5T(n/5) + n using the iteration method, we will start by expanding the recurrence for a few iterations:

T(n) = 5(5T(n/25) + n/5) + n

= 25T(n/25) + n + n

= 25(5T(n/125) + n/25) + n + n

= 125T(n/125) + n + n + n

We can observe a pattern emerging from the expansion:

T(n) = \(5^kT(n/5^k)\) + kn

where k is the number of iterations.

We continue this iteration process until n/\(5^k\) = 1, which gives us k = log_5(n).

Therefore, the final iteration is:

T(n) =\(5^(log_5(n))\)T(1) + n log_5(n)

Since T(1) is a constant, we can simplify further:

T(n) =\(n^log_5(5)\) + n log_5(n)

= n + n log_5(n)

= n log_5(n+1)

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Answer:

Rate of change = 2 & Initial value = -1

Answer:  \(\dfrac{\theta }{2\pi }\times A\)

Step-by-step explanation:

Given

If the central angle is \(\theta \) (Let's say)

Area of sector is given by (in radians)\(=\dfrac{\theta }{2\pi }\times A\)

Where A=Area of circle

where \(2\pi\) represent \(360^{\circ}\)

Answer:

this question doesn't make sense

The smallest number of digits that should be used to label the population is 4, since there are 1,020 students in the school.

To determine the smallest number of digits needed to label the population, we will follow these steps:

1. Determine the total number of students in the population.
2. Identify the number of digits needed to represent the largest student number.
3. Apply this number of digits to all student labels.

Let's apply these steps to your question:

1. The total number of students is 1,020.
2. The largest student number is 1,020, which requires 4 digits (since it has four numbers: 1, 0, 2, and 0).
3. To label the entire student population consistently, use 4 digits for all student labels.

So, the smallest number of digits that should be used to label the population is 4.

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In both the Vendor Compliance at Geoffrey Ryans (A) and Operational Execution at Arrows Electronics cases, there are common problems and challenges. These include issues related to vendor management.

One of the key problems faced by both companies is vendor compliance. This refers to the ability of vendors to meet the requirements and standards set by the company. Both cases highlight instances where vendors fail to meet compliance standards, leading to disruptions in the supply chain and operational inefficiencies. This problem affects the overall performance and profitability of the companies.

Another challenge faced by both companies is operational execution. This encompasses various aspects of operations, including inventory management, order fulfillment, and delivery. In both cases, there are instances where operational execution falls short, leading to delays, errors, and customer dissatisfaction. This challenge requires the companies to streamline their processes, improve communication and coordination, and enhance overall operational efficiency.

Overall, the problems and challenges in both cases revolve around effective vendor management, supply chain optimization, and operational excellence. Addressing these issues is crucial for both companies to improve their performance, meet customer demands, and maintain a competitive edge in the market.

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The speed of the walker is 16.67 miles per hour.

The speed of the cyclist is 25 miles per hour.

Let the speed of a walker = x

Biker's speed = 1.5x

Their relative speed will be:

= 1.5x - x = 0.5x

Distance between them = 12.5 miles

Time taken = 1.5 hours.

It should be noted that distance will be:

= Speed × Time

12.5 = 1.5 × 0.5x

Divide through to get x

12.5 = 0.75x

x = 16.67 miles per hour.

Speed of cyclist = 16.67 × 1.5 = 25 miles per hour.

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Answer:

-13

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

Hello. Y/x = a constant k because y and x are by definition always in the same ratio. (y varies directly as x so if x is doubled y is also doubled etc.)

Answer:

21 in

Step-by-step explanation:

by the Pythagorean theorem we have

\(841=400+x^2\\\\x^2=441\\\\x=21\)

notice that the 841 and the 400 don't go squared because they already squared!