A. What did the neuron say to the muscle say? (Use your basic physiological knowledge, such as the function of
neurons and muscles, to answer the question)

A) The body radiates approximately 190 W of thermal power into the room.

B) The net power radiated by the person is approximately 170 W.

C) The net radiated power by the person, when in a room with a temperature of 20 degrees Celsius, is approximately 452 W (rounded to the nearest 10 W).

A) The thermal power radiated by the body (Prb) can be calculated using the Stefan-Boltzmann law:

Prb = e * σ * A * (Tbody⁴ - Troom⁴)

Where:

e is the emissivity (0.6),

σ is the Stefan-Boltzmann constant (5.67 * 10⁻⁸ W/m²/K⁴),

A is the surface area of the body (2πrL, where r is the radius of the body),

Tbody is the temperature of the body (30 degrees C + 273.15 K),

Troom is the temperature of the room (20 degrees C + 273.15 K).

Substituting the given values into the equation, we can calculate Prb.

B) The net power radiated by the person (Pnet) is given by the difference between the power radiated by the body and the power absorbed from the room:

Pnet = Prb - Pabs

Pabs can be calculated using the Stefan-Boltzmann law:

Pabs = e * σ * A * Troom⁴

Substituting the given values into the equation, we can calculate Pabs. Then, we can calculate Pnet by subtracting Pabs from Prb.

C) Using the given dimensions, the radius (r) of the cylinder can be calculated from the circumference (C):

C = 2πr

0.8 = 2πr

r = 0.8 / (2π)

r ≈ 0.127 m

Now we can proceed with the calculation of the net radiated power (Pnet).

Using the Stefan-Boltzmann law, we can find the power absorbed (Pabs) by the person from the room temperature:

Pabs = εσA(Troom⁴)

Where:

ε is the emissivity (0.6)

σ is the Stefan-Boltzmann constant (5.67*10⁻⁸ W/m²/K⁴)

A is the surface area of the body (2πrL, where r is the radius and L is the length)

Troom is the room temperature (20 + 273.15 K)

Substituting the known values:

A = 2πrL

= 2π(0.127)(2.0)

≈ 0.802 m²

Troom = 20 + 273.15

= 293.15 K

Pabs = (0.6)(5.67*10⁻⁸)(0.802)(293.15⁴)

Performing the calculations, we find that Pabs is approximately 228 W.

The net radiated power (Pnet) can be calculated by subtracting Pabs from the total radiated power (Prb) obtained in Part A:

Pnet = Prb - Pabs

Since Prb was calculated to be approximately 680 W (as mentioned in Part A), we can now determine Pnet:

Pnet = 680 - 228 ≈ 452 W

Therefore, the net radiated power by the person, when in a room with a temperature of 20 degrees Celsius, is approximately 452 W (rounded to the nearest 10 W).

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Answer:

D

Explanation: The protons are found inside the nucleus

U prolly doing FLVS Lol...

...

a) To find the flux at the Earth from a single star with m = 0.0, we can use the formula:

m - M = -2.5log(F/F0)

where m is the apparent magnitude, M is the absolute magnitude, F is the flux, and F0 is the photometric constant.

Rearranging the formula, we get:

F = F0 x 10^(-0.4m+0.4M)

Plugging in the values, we get:

F = 10^(-0.4(0.0)+0.4(0.0)+18.91) = 3.98 x 10^18 J/s

Therefore, the flux at the Earth from a single star with m = 0.0 is 3.98 x 10^18 J/s.

b) To find the total flux at the Earth from the entire cluster, we need to sum up the fluxes from all the stars in the cluster. We can use the same formula as above, but with different values of m and the number of stars:

F = F0 x 10^(-0.4m+0.4M)

Total flux = (100 x F_0 x 10^(-0.4(0.0)+0.4(0.0)+18.91)) + (1000 x F_0 x 10^(-0.4(3.0)+0.4(0.0)+18.91)) + (10000 x F_0 x 10^(-0.4(6.0)+0.4(0.0)+18.91))

Total flux = 2.92 x 10^22 J/s

Therefore, the total flux at the Earth from the entire cluster is 2.92 x 10^22 J/s.

c) To find the apparent magnitude of the entire cluster as a whole, we can use the formula:

m = -2.5log(F/F0)

where F is the total flux from the cluster and F0 is the photometric constant.

Plugging in the values, we get:

m = -2.5log(2.92 x 10^22/1.51 x 10^8) = -22.98

Therefore, the apparent magnitude of the entire cluster as a whole is -22.98.

d) If the values given were the absolute magnitudes instead of the apparent magnitudes, we could use the formula:

M = m - 5log(d/10)

where d is the distance to the cluster in parsecs.

We do not have enough information to find the distance to the cluster, so we cannot determine the absolute magnitude of the cluster as a whole.

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The electric field strength at the point midway between the charges of an electric dipole is 0 N/C.

An electric dipole consists of two equal but opposite point charges, in this case, each having a magnitude of 4.0 nC and separated by a distance of 2.0 cm.

When we want to determine the electric field strength at the midpoint between these charges, we need to consider the individual electric fields created by each charge and their directions.
At the midpoint, the electric fields due to each charge are equal in magnitude but opposite in direction. This is because the distance from each charge to the midpoint is the same, and the charges have the same magnitude but opposite signs. Therefore, the electric fields will cancel each other out.
In an electric dipole with charges of equal magnitude but opposite signs, the electric field strength at the point midway between the charges is 0 N/C, as the electric fields created by each charge cancel each other out.

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The strength of the magnetic field at the center of the solenoid is 0.006 T

The strength of the magnetic field at the center of a solenoid is given by:

B = μ₀ * n * I

where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current flowing through the solenoid.

In this case, the length of the solenoid is not given, but we can assume that it is much greater than the diameter of the solenoid, so we can treat it as a long solenoid. The number of turns per unit length is given as 200 loops divided by the length of 6.5 cm, or:

n = 200 / 0.065 m = 3076.92 turns/m

The current flowing through the solenoid is 5 A.

The permeability of free space, μ₀, is a constant with a value of 4π x 10^-7 T m/A.

Therefore, the magnetic field strength at the center of the solenoid is:

B = μ₀ * n * I

= 4π x 10^-7 T m/A * 3076.92 turns/m * 5 A

= 0.006 T

So the strength of the magnetic field at the center of the solenoid is 0.006 T. The north pole of the solenoid is the end from which the magnetic field emerges, and the south pole is the end where it enters.

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Answer:

800 meters

Explanation:

4 x 200 is 800 meters.

The ball's acceleration after leaving the tennis player's hand is -9.8 m/s^2, which represents the acceleration due to gravity.

As the tennis ball leaves the player's hand, it experiences an initial upward velocity of +14.7 m/s. However, due to the force of gravity acting upon it, the ball's velocity will decrease over time until it reaches its highest point and begins to fall back down towards the ground. The acceleration due to gravity, which is always directed downwards towards the center of the Earth, is -9.8 m/s^2. This means that the ball's velocity will decrease by 9.8 m/s every second until it reaches its highest point, and then increase by the same amount as it falls back down towards the ground. Therefore, the correct answer is -9.8 m/s^2.

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Answer: Use the x/t = v formula!!! x is distance, t is time, and v is velocity. you just need to do 40 / 5 = 8 and 100 / 15 = 6.66

Kinetic energy is the energy of an object that is in motion. It can be calculated by using the formula KE = (1/2)mv², where m is the mass of the object and v is the velocity of the object.

Kinetic energy is the energy of motion. When an object is in motion, it has kinetic energy. This type of energy is the result of an object's mass and velocity. The kinetic energy of an object is equal to one half of its mass multiplied by the square of its velocity. Kinetic energy can be converted into other forms of energy, such as electrical energy and thermal energy. Kinetic energy can also be transferred between objects when they collide. Kinetic energy is used in many everyday activities, such as running and cycling.

(a) KE = (1/2) (45 g) (20 m/s)2 = 18000 g m2/s2 = 18 J
(b) KE = (1/2) (45 g) (40 m/s)2 = 72000 g m2/s2 = 72 J
(c) KE = (1/2) (45 g) (60 m/s)2 = 162,000 g m2/s2 = 162 J.

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Answer:

10.71 mL

Explanation:

We know,

=> density= mass/volume

=> 1.4 = 15 / Volume

=> volume= 15/1.4 mL

=> volume= 10.71 mL

Answer:

Q = C M ΔT    where C is specific heat in cal / gm*deg C

C (Fe) = .11

C (Al) = .22

obviously ΔT has to be twice as great for Iron (Fe) as for (Al) for the same amount of heat to be transferred

ΔT = Q /(C * M)      where ΔT is the change in temperature

a) iron would have the higher final temperature

Correlation is a measure of the linear relationship between two variables. It indicates the degree to which a change in one variable is associated with a change in the other variable.

Correlation does not necessarily imply causation, meaning that just because two variables are correlated does not mean that one variable caused the other to change.

There are a few reasons for this. First, correlation does not indicate the direction of the relationship. For example, two variables could be positively correlated (increase together) or negatively correlated (one increases while the other decreases), but correlation alone does not indicate which is the case.

Second, there may be third variables that are affecting both of the variables being correlated. For example, a study might find that ice cream sales are positively correlated with shark attacks.

However, this does not mean that eating ice cream causes people to be attacked by sharks, or that sharks attack more when people are eating ice cream. Instead, the third variable is likely temperature.

On hot days, people are more likely to buy ice cream and more likely to go swimming, which leads to more shark attacks.

In summary, correlation does not necessarily imply causation and other methods, such as experiments, are needed to establish causal relationships.

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Answer: 10

Explanation:

The control in the experiment is option B. The group that is given no shock.

The method utilized by the researcher in scientific study to reduce the impact of unimportant factors is known as experimental control. The power of the independent variable to alter the dependent variable is further strengthened by experimental control. 9 Nov 2021

A controlled experiment is a scientific test carried out under predetermined circumstances in which only one (or a small number of) variables are altered at a time while all other variables are maintained constant.

Researchers use experimental controls to reduce the impact of unrelated experience and environmental factors, as well as to strengthen the conclusion that changes in the dependent variable are caused by the independent variable (the ability to infer causality).

Hence, option B is correct as it is not receiving any special treatment in the experiment.

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A) Minimum recommended spiral parameter: 150.03m.

b) Distance P: 150.03m.

c) Distance Q: 4.122m.

d) Angle Φs: 16°30'14.0".

e) Distance Tc: 150.03m.

a) Calculation for the minimum recommended spiral parameter:

Design radius (R) = 300 m

Maximum superelevation (e_max) = 0.06 m/m

Spiral Parameter (A) = (R + e_max) / 2

A = (300 m + 0.06 m/m) / 2

A ≈ 150.03 m

b) Calculation for the distance P:

Distance P is equal to the length of the first spiral curve, which is the same as the minimum recommended spiral parameter.

P ≈ 150.03 m

c) Calculation for the distance Q:

Distance Q represents the length of the circular curve. It is given by the formula:

Q = (Deflection angle at Point of Intersection) / (Degree of Curve, D)

Deflection angle at Point of Intersection = 16°30'14.0"

Converting the angle to decimal degrees:

16° + (30'/60) + (14.0"/3600) = 16.504°

Q = 16.504° / (360° / D)

Q ≈ D / 21.814

Since the RAU80 has 4 lanes, the degree of curve (D) is 360° / 4 = 90°.

Q ≈ 90° / 21.814

Q ≈ 4.122 m

d) Calculation for the angle Φs:

The angle Φs is the deflection angle at the Point of Intersection.

Φs = 16°30'14.0"

e) Calculation for the distance Tc:

Distance Tc is equal to the length of the second spiral curve, which is the same as the minimum recommended spiral parameter.

Tc ≈ 150.03 m

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Answer: It has the skill to nest

sorry if I'm wrong

Answer:

B: A colorful beak

Explanation:

i hope this helped!

The acceleration due to gravity near the surface of Mars is 3.7 m/s^2.

The time it takes for the marker to fall to the ground on Mars is longer than on Earth, indicating that the acceleration due to gravity is weaker on Mars.

Using the formula for acceleration due to gravity, g = (2d/t^2), where d is the distance traveled and t is the time it took to fall, we can calculate the magnitude of the acceleration due to gravity on Mars.

Plugging in the values, we get g = (2 x 1.52 m) / (2.12 s)^2 = 3.7 m/s^2.

Therefore, the acceleration due to gravity near the surface of Mars is 3.7 m/s^2, which is about 0.38 times the acceleration due to gravity on Earth.

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Answer:

She would travel 175.5 m in the same amount of time

Explanation:

Here is the complete question:

Seven bicyclist are racing. Each bicyclist rides for 9s. If a bicyclist, with initial velocity of zero, steadily gained speed until reaching a final velocity of 39m/s, how far would she travel during the race in the same amount of time)?

Explanation:

To determine how far she would travel in the same amount of time, that is the distance she would cover in the same amount of time

From the question,

The bicyclist has an initial velocity of zero

That is, u = 0 m/s

and a final velocity of 39 m/s

That is, v = 39 m/s

Each bicyclist rides for 9s,

She also traveled for the same amount of time

that is, t = 9s

To determine the distance,

From one of the equations of motion for linear motion

s = \(\frac{1}{2}\) t(u + v)

Then

s = \(\frac{1}{2}\) (9)(0+39)

s = 4.5 (39)

s = 175.5 m

Hence, she would travel 175.5 m in the same amount of time

A neutral stimulus will turn into a conditioned stimulus (CS) and cause a conditioned response (CR) that is comparable to the initial unconditioned response if it is combined with an unconditioned stimulus (US) that has already caused an unconditioned response (UR).

A neutral stimulus is one that first merely directs attention and doesn't elicit any specific responses. When coupled with an unconditioned stimulus in classical conditioning, the neutral stimulus becomes a conditioned stimulus. The neutral stimulus will also elicit a response, known as a conditioned response, with repeated presentations of both the neutral stimulus and the unconditioned stimulus.

So, CR i.e., conditioned response is after learning while NS i.e.,  Neutral Stimulus is before learning.

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Answer:

The Difference between Radio Waves and Infrared Light. According to NASA, radio waves have a longer wavelength than infrared light, in the electromagnetic spectrum. Radio waves are able to reach the earth’s surface, unlike most infrared light.

Explanation:

I hope this helps.

To determine the new force of gravity in the first scenario, we can use the formula for gravitational force:

\(Fg = (G * m1 * m2) / r^2,\)

where G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between their centers.

If we triple the mass of one object and double the distance between their centers, the new force of gravity can be calculated as follows:

New \(Fg = (G * (3m) * m) / (2r)^2.\)

Simplifying this expression, we get:

New Fg = (G * 3m * m) / (4r^2).

Since (3m * m) / (4r^2) is equivalent to (3/4) * (m * m) / (r^2), we can rewrite the equation as:

New \(Fg = (3/4) * (G * m * m) / r^2.\)

Comparing this to the original force of gravity, Fg, we see that the new force is (3/4) times the original force. Therefore, the answer is C) 0.75 Fg.

Regarding the second scenario, for objects in stable orbit, the orbital period is determined by the formula:

\(T = 2π * sqrt(r^3 / (G * M)),\)

where T is the orbital period, r is the distance between the center of the object and the center of the Earth, G is the gravitational constant, and M is the mass of the Earth.

If Satellite B is twice as far from the Earth's center compared to Satellite A, we can say that r_B = 2 * r_A.

Let's compare the orbital periods of the two satellites:

T_B = 2π * sqrt((2r_A)^3 / (G * M)) = 2π * sqrt(8r_A^3 / (G * M)).

T_A = 2π * sqrt(r_A^3 / (G * M)).

Dividing T_B by T_A, we get:

T_B / T_A = (2π * sqrt(8r_A^3 / (G * M))) / (2π * sqrt(r_A^3 / (G * M))).

Simplifying this expression, we find:

T_B / T_A = sqrt(8r_A^3 / (r_A^3)) = sqrt(8) = 2.83.

Therefore, the answer is a) 2.83 times larger.

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When two objects are experiencing gravitational attraction, if you triple the mass of one of the objects and double the distance between their centers, the new force of gravity compared to the old will be 0.75 times the original force (0.75 Fg).The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the force of gravitational attraction between two objects is inversely proportional to the square of the distance between their centers of mass. If you double the distance between two objects, the force of gravitational attraction decreases by a factor of 4 (2^2). On the other hand, if you triple the mass of one of the objects, the force of gravitational attraction increases by a factor of 3.

Therefore, combining these effects, the new force of gravity will be 3/4 or 0.75 times the original force.

Satellite A and Satellite B are both in stable orbit around the Earth, but Satellite B is twice as far from the Earth's center as Satellite A. The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

This is because the orbital period of an object in circular motion is dependent on the radius of the orbit. The further an object is from the center of the orbit, the longer it takes to complete one full orbit. Since Satellite B is twice as far from the Earth's center as Satellite A, its radius is also twice as large. The orbital period is directly proportional to the radius, so Satellite B's orbital period will be 2.83 times larger than Satellite A's orbital period.

Therefore, the correct statement is:

The new force of gravity compared to the old will be 0.75 Fg.

The orbital period of Satellite B compared to Satellite A is 2.83 times larger.

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The power is the 20Ω resistor dissipating if the 10Ω resistor is dissipating 35 W of power is 39.2 W.

The power dissipated by a resistor is given by:

P = I² R ....(1)

where I is the current through the resistor and R is the resistance.

We are told that the resistor of 10Ω dissipates 35 W of power. By rearranging the previous equation (1), and by using these data, we can find the current flowing through the resistor of 10Ω:

\(I_{L} = \sqrt{\frac{P}{R} } = \sqrt{\frac{35}{10} } =1.87A\)

This is the current flowing in the left brаnch of the circuit: we need to find the current flowing in the right brаnch, \(I_{R}\) . The equivаlent resistаnce on the left brаnch is the sum of the two resistаnces since they аre in series:

\(R_{L}\) = 10Ω + 5Ω = 15Ω

We know that this resistance is in parallel with the resistor on the right, \(R_{R}\) = 20Ω, so they have the same potential difference:

\(V_{L} = V_{R}\)

which can be rewritten, by using Ohm's law:

\(I_{L} R_{L} = I_{R}R_{R}\)

Rearranging the equation, we find the current through the right branch:

\(I_{R} = \frac{I_{L}R_{L} }{R_{R} }\)

\(= \frac{ (1.87A)(15)}{20}\)

= 1.40A

And now we can find the power dissipated through the resistor on the right:

P = I² R

= (1.40A)² (20Ω)

= 39.2 W

Your question is incomplete, but most probably your figure can be seen in the Attchment.

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Genevieve works for a company that manufactures office furniture. it is her responsibility to source component parts such as casters, laminate, and plastic to make the office furniture. Genevieve works in purchasing.

A business or organization uses the purchasing process to acquire products or services in order to achieve its objectives. Although many organizations make an effort to establish standards for the purchasing process, procedures can differ significantly between organizations.

The major functions of purchasing sector in a business organization includes the following:

Determine the products, materials, and services that the business needs. Find trustworthy vendors to satisfy these needs. Discuss pricing, construction quality, and delivery schedules. Make bid requests on supply contracts and set up the order quantities.

The question is incorrect. The correct question is

Genevieve works for a company that manufactures office furniture. It is her responsibility to source component parts such as casters, laminate, and plastic to make the office furniture. Genevieve works in ______.

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The height the ball rebounds to can be considered the same as the initial height, which is 1 meter. To determine the height the ball rebounds to, we can use the concept of the coefficient of restitution (e), which represents the ratio of the final velocity to the initial velocity of an object after a collision.

Given:

Initial height (h1) = 1 m

Coefficient of restitution (e) = 0.6

The coefficient of restitution is defined as the ratio of the relative velocity after the collision to the relative velocity before the collision. In the case of a ball dropped from a height, the relative velocity after the collision is equal to the negative of the initial velocity.

Using the equation:

e = -(v_final / v_initial)

We can rearrange the equation to solve for the final velocity (v_final):

v_final = -e * v_initial

When a ball is dropped, the initial velocity is determined by the height it is dropped from. The initial velocity (v_initial) can be calculated using the equation:

v_initial = sqrt(2 * g * h1)

where g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the given values:

v_initial = sqrt(2 * 9.8 m/s^2 * 1 m)

= sqrt(19.6) m/s

≈ 4.427 m/s

Now, we can calculate the final velocity:

v_final = -0.6 * 4.427 m/s

≈ -2.656 m/s

The negative sign indicates that the ball rebounds in the opposite direction.

Finally, we can find the height the ball rebounds to by using the final velocity and the equation for the potential energy of the ball:

Potential energy (PE) = (1/2) * m * v_\(final^2\)

where m is the mass of the ball. However, since the mass is not provided, we can assume it cancels out when comparing the heights.

Therefore, the height the ball rebounds to can be considered the same as the initial height, which is 1 meter.

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Answer:

私は知らない

Explanation:

Answer:

5.1 meters

Explanation:

Terra tosses a 0.20kg volleyball up at at a speed of 10 m/s

The height can be calculated as follows

= v^2/2g

= 10^2/2×9.8

= 100/19.6

= 5.1 meters

Hence the height is 5.1 meters

Answer: A. 1.0

Explanation: