A uniform rod of length 50cm and mass 0.2kg is placed on a fulcrum at a distance of 40cm from the left end of the rod. At what distance from the left end of the rod should a 0.6kg mass be hung to balance the rod

Answer:

the required current is 0.12 A

Option b) 0.12 A is the correct answer

Explanation:

Given the data in the question,

to determine the current needed in the wire, we use the following relation;

B = μ₀n\(I\)

\(I\) = B / μ₀n

where μ₀ is the magnetic constant   ( 4π × 10⁻⁷ T.m/A )

n is the number of turns ( 1 / 1mm\(\frac{10^{-3}m}{1 mm}\)) = 1000 m⁻¹

B is magnitude ( 150μT ( \(\frac{10^{-6}m}{1uT}\)) )

so we substitute

\(I\) =  [ 150μT ( \(\frac{10^{-6}m}{1uT}\)) ] / [ ( 4π × 10⁻⁷ T.m/A ) × 1000 m⁻¹ ]

\(I\) =  [ 0.00015 ] / [ 0.00125 ]

\(I\) = 0.12 A

Therefore, the required current is 0.12 A

Option b) 0.12 A is the correct answer

78% of the houses in Elizabeth's town were for sale last summer.

To find the percentage of houses that were for sale last summer in Elizabeth's town, we need to divide the number of houses for sale by the total number of houses and then multiply by 100.

The total number of houses in Elizabeth's town is given as 9,000. Last summer, 7,020 houses were for sale. To calculate the percentage, we divide 7,020 by 9,000:

Percentage = (7,020 / 9,000) * 100

Simplifying the calculation:

Percentage = 0.780 * 100

Percentage = 78.0%

To explain further, we take the number of houses for sale (7,020) and divide it by the total number of houses (9,000) to get the ratio of houses for sale to the total. Multiplying this ratio by 100 gives us the percentage. In this case, 78.0% indicates that a significant portion of the houses in Elizabeth's town were available for sale during the summer.

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Answer:

The answer is (A)

Explanation:

We know this because The suns energy is entirely re-radiated back into space.

We know also that the answer is not (D) It makes Earth too hot for plants and animals to survive.

Atmospheric gases are gases located in the Earth's atmosphere

The green house effect is a natural process that warms the Earth's surface

I also know the answer because I took the test... FLVS exam 3.09 right?

I took it and got this question right... So i know you will! GOOD LUCK!!

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Answer:

It will go up to 93.75 m before it is moving at 20 m/s

Explanation:

As we know that

\(v^2 - u^2 = 2aS\)

here v is the final speed i.e 20 m/s

u is the initial speed i.e 5 m/s

a is the acceleration due to gravity i.e 2 m/s^2

Substituting the given values in above equation, we get -

\(20^2 - 5^2 = 2*2*S\\S = 93.75\)meters

Complete Question

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string,  If the breaking strength of the string is 120 N, what's the minimum angle the string can make with the horizontal?

Answer:

The value is \(\theta = 4.41^o\)      

Explanation:

From the question we are told that

  The mass of the rock is  \(m_r = 940 \ g = 0.94 \ kg\)

   The length of the string is \(l = 1.30 \ m\)

    The breaking strength(i.e the maximum tension) on the string is \(T = 120 \ N\)

Gnerally the vertical component of the tension experienced by the string is mathematically represented as

     \(T_v = T sin(\theta)\)

Generally this vertical component  of tension is equivalent to the weight of the rock

So

     \(Tsin (\theta) = mg\)

=>  \(\theta = sin^{-1} [\frac{mg}{ T} ]\)

=>    \(\theta = sin^{-1} [\frac{0.940 *9.8 }{ 120} ]\)

=>    \(\theta = 4.41^o\)      

The falcon take 14 seconds to reach the pigeon.

A mathematical expression that expresses the location, speed, or acceleration of a body in relation to a specified frame of reference is called as Equation of motion,

By using equation of motion

s = \(\frac{1}{2}\)g\(t^{2}\)

where, s = total distance travelled by an object = 68.6 m

g = acceleration of gravity = 9.8m/\(s^{2}\)

t = time taken to travel the distance = ?

Therefore, t = \(\sqrt{2s/g}\)

t = \(\sqrt{2*68.6/9.8}\)

t = 14 seconds

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The RMS value for the maximum-voltage and current is 155.56 V and 3.54 A, respectively.

Define RMS ?

RMS stands for Root Mean Square. It is a mathematical formula used to determine the effective or average value of a set of values, particularly those that vary over time, such as voltage and current in electrical circuits. RMS takes into account both the magnitude and duration of each value, and provides a value that is equivalent to the DC value of the signal that would produce the same amount of power in a resistive load.

To calculate the RMS (Root Mean Square) value for voltage and current, we use the following formulas:

RMS Voltage = Max Voltage / √2

RMS Current = Max Current / √2

Using these formulas, we can calculate:

RMS Voltage = 220 V / √2 = 155.56 V

RMS Current = 5 A / √2 = 3.54 A

Therefore, the RMS value for the maximum-voltage and current is 155.56 V and 3.54 A, respectively.

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Answer:

a. Power = 1000 Watts or 1 Kilowatts.

b. Current = 4 Amperes.

Explanation:

Given the following data;

Energy consumed = 1.8MJ = 1.8 × 10^6 = 1800000 Joules

Voltage = 250V

Time = 30 minutes to seconds = 30 * 60 = 1800 seconds

To find the power rating;

Power = energy/time

Substituting into the equation, we have;

Power = 1800000/1800

Power = 1000 Watts or 1 Kilowatts.

b. To find the current taken from the supply;

Power = current * voltage

1000 = current * 250

Current = 1000/250

Current = 4 Amperes.

Answer:

\(kinetic \: energy = \frac{1}{2} m {v}^{2} \\ m = mass \: of \: the \: object \\ v = velocity \: \)

Answer:

37.4m/s

Explanation:

since the car doesn't accelerate, we can use the formula v=ωr where v is linear speed, ω is angular speed (rads/second) and r is radius. Substitute values for equation:

v=55*0.68

v=37.40

Answer:

6 km is the right answer

hope it helps you

Explanation:

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On the surface of the Moon, the free-fall acceleration is roughly one-sixth that of the Earth. Their average densities are 0.667 apart.

Given the radius of the Moon is (Rm) = 0.250 RE

The radius of the earth (RE) = 6.4 x 10^6 m

Let freefall acceleration of the moon = gm

Let freefall acceleration of the earth = ge

Given gm = ge/6

We know that g = Gm/r^2 where G is the gravitational constant

Let mass of moon = m1 and mass of earth = m2

Gm1/Rm^2 = Gm2/6xRE^2

mass = densityxvolume

let density of moon = d1 and density of earth = d2

d1 x (4/3Rm^3)/Rm^2  =  d2x (4/3RE^3)/6xRE^2

d1xRm = d2xRE/6

d1/d2 = RE/6X0.250RE

d1/d2 = 0.667

Hence the ratio of densities of moon and earth is 0.667

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Answer:

C firework

Explanation:

from Quizlet

An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I

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Taking into account the scientific notation, the result of the sum is 6.363×10¹³.

Scientific notation is a quick way to represent a number using powers of base ten. The numbers are written as a product:

a×10ⁿ

where:

You want to add two numbers in scientific notation that not have the same base 10 exponent. So, the base 10 power with the highest exponent must be found. In this case, the highest exponent is 13.

Then all the values ​​are expressed as a function of the base 10 exponent with the highest exponent. In this case: 8.30×10¹¹= 0.0830×10¹³

Taking the quantities to the same exponent, all you have to do is add what was previously called the number "a". In this case:

6.28×10¹³ +  0.0830×10¹³= (6.28+ 0.0830)×10¹³= 6.363×10¹³

Finally, the result of the sum is 6.363×10¹³.

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The total volume occupied by two internal clamps, six 12 AWG conductors and one grounding conductor, and a single-pole switch is 20.25 cu in.

When counting the number of conductors in a box a conductor running through the box is counted as conductor S?

An unbroken conductor, passing through the box without splice or termination, can be counted as one conductor if it is less than two times the minimum length required for the free conductor in 300.14. For example, two conduits are entering opposite sides of a four-inch square metal box that has a depth of 1 1/2 inches.

How many amps can 12 AWG handle?
The twelve-gauge wire is good for 20 amps, 10-gauge wire is good for 30 amps, 8-gauge is good for 40 amps, and 6-gauge is good for 55 amps, and The circuit breaker or fuse is always sized to protect the conductor [wire].

12 AWG =2.25 cu. in. ( 6 x 2.25 = 13.5)

Device( 2 x 12 AWG cu. in.)= ( 2 x 2.25 = 4.5)

Clamp ( 1 x 12 AWG cu. in.)= ( 1 x 2.25 = 2.25)

13.5 + 4.5 + 2.25 = 20.25 cu. in.

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The magnetic field of the wire will be directed towards west. Using right thumb rule one can get the direction of field lines.

According to the question, oxygen is the gas with the highest concentration in our environment.

Environment refers to the natural world and the physical, chemical, and biological conditions that surround and influence an organism or a community of organisms. It includes the air, water, land, sunlight, plants, animals, and other living and nonliving things that make up our planet. Environmental conditions can affect the health, growth, and activities of living organisms, both positively and negatively. For example, a warm, sunny environment is necessary for plants to grow, while a polluted environment can be damaging to the health of people, animals, and plants. Humans can also have a positive or negative impact on the environment, either through their activities or by taking steps to protect it.

It makes up around 21% of the Earth's atmosphere. Nitrogen is the second most abundant gas, making up about 78%. Hydrogen and carbon dioxide make up a small fraction of the atmosphere.

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When a force is applied to a wedge, it is used to overcome the resistance of the object being split or lifted. The force does not create potential energy, but rather converts mechanical energy into work to overcome friction and resistance.

When a force is applied to a wedge, the mechanical energy is indeed used to overcome the resistance of the object being split or lifted. The operation of a wedge involves the conversion of mechanical energy into work. However, it is important to clarify the concept of potential energy in this context.

Potential energy refers to the energy possessed by an object due to its position or configuration in a force field. In the case of a wedge, the applied force is not creating a potential energy difference between the wedge and the ground. The potential energy associated with the wedge primarily depends on its position and orientation, not the applied force.

Instead, the mechanical energy provided by the applied force is utilized to overcome the friction and resistance of the object being split or lifted. As the wedge exerts a force on the object, it applies pressure at specific points, causing the object to separate or move. The work done by the applied force is what allows the object to overcome the resistance and achieve the desired splitting or lifting action.

In summary, the force applied to a wedge does not directly create a potential energy difference between the wedge and the ground. The mechanical energy provided by the force is used to overcome the resistance of the object, allowing for splitting or lifting. The concept of potential energy is more relevant to the configuration and position of the wedge itself, rather than the applied force and the object being manipulated.

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Answer:

Define universal gravitational constant. Why is newton's law of gravitation called universal law?

Answer:

The cost of running the electric water heater for one year is 55.2391 $

Explanation:

The simple rule of 3 helps to quickly solve proportionality problems when you have three known values ​​and one unknown. If two quantities are directly proportional (that is, when multiplying or dividing one of them by a number, the other is multiplied or divided respectively by the same number) the rule of three can be applied as follows:

a ⇒ b

c ⇒ x

So: \(x=\frac{c*b}{a}\)

where a, b and c are the known values ​​and x is the value you want to find out.

In this case, you can first apply the following rule of three: if 2.5 kW are consumed in 1.9 hours, in 1 hour how many kW are consumed?

\(kWh=\frac{1 h*2.5 kW}{1.9 h}\)

kWh=1.316

So an electric water heater consumes 1.316 kWh in one day. You apply another simple rule of three: if the heater in 1 day consumes 1.316 kWh, in 365 days (1 year) how many kWh are consumed?

\(kWh=\frac{365 days*1.316 kWh}{1 day}\)

kWh= 480.34

So an electric water heater consumes 480.34 kWh in a year.

If 1 kWh costs 11.5 cents, 480.34 kWh how many cents does it cost?

\(cost=\frac{480.34 kWh*11.5 cents}{1 kWh}\)

cost= 5,523.91 cents

Finally, if 100 cents is equal to 1 dollar, 5,523.91 cents, how many dollars are equal?

\(cost=\frac{5,5523.91 cents*1 dollar}{100 cents}\)

cost= 55.2391 $

The cost of running the electric water heater for one year is 55.2391 $

Answer:

e)

Explanation:

i)

        \(V = I*r_{i} + I*R_{1} (1)\)

      \(I_{i} = \frac{V}{r_{int} + R_{i}} = \frac{1.5V}{0.1 \Omega + 1.4 \Omega} = 1.0 A (2)\)

ii)

       \(I_{ii} =\frac{V_{term} }{R_{ii} } =\frac{3.6V}{1.8 \Omega} = 2.0 A (3)\)

iii)

      \(I_{iii} =\frac{V-V_{term}}{r_{int} } =\frac{12.0 V- 11.0 V}{0.2 \Omega} =\frac{1.0V}{0.2\Omega} = 5.0 A (4)\)

smallest possible potential energy The potential energy of the cart began to rise once more as it advanced higher up the loop as it entered the loop, but it was never able to match its level at the top of the hill.

Potential energy is the energy that is held in reserve by an object due to its position or condition. Potential energy exists in objects like a spring stretched out, a bicycle on a hilltop, and a book held above your head.

On the other hand, kinetic energy is the energy of an object or a system's particles in motion .The most gravitational potential energy between the cart and the Earth was stored at the top of the hill, which was the tallest point on the ride where the cart was stationary. When the cart was at the top of the hill, it had the highest potential energy due to its position above the ground. As the cart began to move downhill, some of this potential energy was converted into kinetic energy, which increased the cart's speed.

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A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

(i) C=3Co

(ii) V=Vo/3

(iii) Decrease

Explanation:

(i) capacitance increase K times.

(ii) As charge remain constant so by using Q=CV

you will get potential decrease by K time.

(iii) Decrease due to induced electric field inside

dielectric material..

E=Eo-Eind

Explanation:

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Answer:

lol

Explanation:

Answer:

F = M v^2 / R = M w^2 R      where w represents the angular frequency

Only 1 / R causes a reduction in centripetal force when increased

(B)   is the answer

Option B. The radius of curvature causes a reduction in centripetal force with an increase in the magnitude.

Centripetal force is a force that acts on the object that moves in a circular motion and is directed towards the center of the circular moving path. The mathematical representation of centripetal force is -

Where Fc = the centripetal force,

m = mass of the object,

v = velocity

and r = radius.

From the given explanation above, The centripetal force and radius of curvature are inversely proportional to each other,

that is, Fc = 1/r.

Therefore, an increase in the radius of curvature leads to a reduction in the centripetal force.

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jacob first stack is 1

Answer:

help

Explanation:

me

Answer:

Opposite

Explanation:

Waves that hit a fixed boundary return to the starting point on the opposite side that it began.

After striking, the wave gets reflected and it moves in the direction opposite to the initial direction.

Hence, it would mean that waves that hit a fixed boundary return to the starting point on the opposite direction.