a uniform meter stick is freely pivoted about the 0.20m mark. if it is allowed to swing in a vertical plane with a small amplitude

We can calculate the focal length of the lens as follows:1/f = 1/d₀ - 1/d₁ = 1/2940 + 1/215910 = 0.00052So,f = 1/0.00052 = 1923.08 mm . Therefore, the focal length of the projection lens is approximately 1923.08 mm.

In order to find out the focal length of the projection lens for the given LCD projector, we can use the thin lens equation which is given as follows:1/f = 1/d₀ + 1/d₁ where f = focal length of the projection lensd₀ = distance of the object from the lensd₁ = distance of the image from the lens .

Given data: Object height, h₀ = 24.2 mm Image height, h₁ = 1.78 m = 1780 mm .

Distance of the object from the lens, d₀ = 2.94 m = 2940 mm . Now, we need to calculate the distance of the image from the lens, d₁. For that, we can use the magnification formula which is given as:m = - h₁/h₀ = d₁/d₀So, we can rearrange the above formula as:d₁ = - (h₁/h₀) × d₀ = - (1780/24.2) × 2940 = - 215910 mm .

We can see that the value of d₁ comes out to be negative which means that the image is formed on the opposite side of the lens. This shows that the lens is a diverging lens. Therefore, we can calculate the focal length of the lens as follows:1/f = 1/d₀ - 1/d₁ = 1/2940 + 1/215910 = 0.00052So,f = 1/0.00052 = 1923.08 mm . Therefore, the focal length of the projection lens is approximately 1923.08 mm.

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Given the fact that the arrow is in motion, it the follows that the arrow possesses kinetic energy.

The kinetic energy is the energy that is possessed by a body by virtue of its motion. This is different form the potential energy of the body which is the energy that the body possesses as a result of the fact that the object is located at a particular position. These are actually the two kinds of mechanical energy that we have in the study of physics.

If we consider this matter closely, we would see that the arrow as shown is in motion. The arrow does posses a velocity and such the arrow is in motion. As long as we can see that the arrow is in motion, it the follows that the arrow as we can see does and in fact possesses the kinetic energy.

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The angular diameter of the Jupiter is 3.79 × 10⁴ meter, if its actual diameter is 1.43 × 10⁸ meter, and it is seen from a distance of 7.783 × 10⁸ m.

Angular diameter is defined as the apparent diameter that describes how large a circle or sphere appears from a given point of view.

Actual diameter of the Jupiter, D₁ =  1.43 × 10⁸ m

Distance, from which it is seen, d = 7.783 × 10⁸ m

Angular diameter, D = 206265 × (Actual diameter)/(distance)

D = (206265 × 1.43 × 10⁸)/(7.783 × 10⁸)

D = 3.79 × 10⁴ m

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Answer:

2H₂S + SO₂ —> 2H₂O + 3S

Explanation:

From the question given above, the following equation were obtained:

H₂S + SO₂ —> H₂O + S

The equation can be balance as illustrated below:

H₂S + SO₂ —> H₂O + S

There are 2 atoms of O on the left side and 1 atom on the right side it can be balance by writing 2 before H₂O as shown below:

H₂S + SO₂ —> 2H₂O + S

There are 2 atoms of H on the left side and 4 atoms on the right side. It can be balance by writing 2 before H₂S as shown below:

2H₂S + SO₂ —> 2H₂O + S

There are 3 atoms of S on the left side and 1 atom on the right side. It can be balance by writing 3 before S as shown below:

2H₂S + SO₂ —> 2H₂O + 3S

Now, the equation is balanced.!

A ball of mass 0.3 kg, initially at rest, is kicked directly toward a fence from a point 16m away. The velocity of the ball as it leaves the kicker's foot is 16 m/s at an angle of 48 degrees above the horizontal. The top of the fence is 3 m high. The ball hits nothing while in flight and air resistance is negligible. The acceleration due to gravity is 9.8 meters per second square.

a) The time it takes for the ball to reach the plane of the fence is (t)= 1.49 s

b) The ball pass above the top of the fence will be (h)=3.81m

c) The vertical component of the velocity when the ball reaches the plane of the fence is [v(y)]= -2.71 m/s

The term velocity means that the object's covered distance within the given time. Example: A car goes 3m in 1 second the velocity of the car is 3m/s.

a) To calculate the time we are using the formula,

x=vcosθt

Or, t = x/ vcosθ

Here we are given,

v= the initial velocity of the ball =16 m/s

θ =  the initial angle = 48°

x= The distance of the fence = 16m

W have to calculate the time =t

Now we put the values in the above equation we get,

t = x/ vcosθ

Or, t= 16/16*cos48°

Or, t = 1.49 S

Now we know that, the time it takes for the ball to reach the plane of the fence is (t)=1.49 s

b) Now we have to calculate the height of the ball when it cross the fence. we are using the formula,

y= vsinθt-(1/2)gt²

t =  the time we got earlier = 1.49 s

g= The acceleration due to gravity = 9.8 m/s².

Now we put the values in the above equation we get,

y= vsinθt-(1/2)gt²

Or, y = 16*sin48*1.49-(1/2)*9.8*(1.49)²

Or, y= 6.81 m

The  ball pass above the top of the fence will be (h)=(y-y₁)=(6.81-3)=3.81m

c) To calculate the vertical component of the velocity when the ball reaches the plane of the fence, we are using the formula,

v(y)=vsinθ-gt

Or, v(y)=16*sin48-9.8*1.49

Or, v(y)= -2.71 m/s

From the calculation we assure, The vertical component of the velocity when the ball reaches the plane of the fence is [v(y)]= -2.71 m/s.

[Note: The component is negative cause the velocity is decreasing]

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A ball of mass 0.3 kg, initially at rest, is kicked directly toward a fence from a point 16m away. The velocity of the ball as it leaves the kicker's foot is 16 m/s at an angle of 48 degrees above the horizontal. The top of the fence is 3 m high. The ball hits nothing while in flight and air resistance is negligible. The acceleration due to gravity is 9.8 meters per second squared.

a) Determine the time it takes for the ball to reach the plane of the fence.

b) How far above the top of the fence will the ball pass? Consider the diameter of the ball to be negligible.

c) What is the vertical component of the velocity when the ball reaches the plane of the fence?

Answer:

(1)540 J

(2)67.5 J/s or 67.5W

(3)look at underline statement in explanation

Explanation:

(1) acceleration = change in speed ÷ time

= (9-5)m/s ÷ 8s

= 0.50 m/s²

resultant force of object during motion

= mass(in kg) × acceleration

= 6 × 0.50 = 3 N

displacement of force applied

= area under speed time graph(when sketched out, it's a trapezium)

= ½ × (5+9) × 8

= 180m

work done is measured in joules

= force × displacement of force applied

= 3N × 180m

= 540 J

detailed explanation:

altho the final unit for the work done should be Nm, but J is equal to Nm.

(2) Power is measured by J/s

therefore power = 540 J ÷ 8s = 67.5 J/s or 67.5 W

(3) the object accelerates constantly along a straight road

     Power is, summarized, how fast something is done using energy. More specifically, power is the amount of energy transferred or converted per unit time.

     To determine power, you use the following formula:

                              \(P=\frac{W}{Δt}\)

(formatting is messed up, the denominator is Δt)

         P - power

         W - work

         Δt - elapsed time

     Hope this helps, have a wonderful day :D

The value of Ios at which the current turns on depends on the specific transistor's characteristics and its threshold voltage. Once you have your plot, you can identify the Ios value where the current starts to flow by looking for the point at which the curve starts to rise significantly.

When setting Vps to a constant value of 5 V and sweeping the gate voltage from 0 V to 5 V in increments of 0.1 V, the curve of I vs. los can be plotted.

he value of los at which the current turns on can be determined from this curve. It is important to note that when Vps is held constant, the voltage across the transistor remains constant as well, which ensures that the transistor is operating in the saturation region.

As the gate voltage is increased, the electric field at the gate oxide interface increases, resulting in a higher channel potential and a larger drain current. At some point, the threshold voltage is reached, and the current starts to turn on. The exact value of los at which this occurs can be determined by analyzing the I vs. los curve.

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The rotational kinetic energy has decreased by \(1.4175 kg.m^2/s^2\). To find the final rotational kinetic energy of the rotating disk, we can use the formula for rotational kinetic energy:

Rotational kinetic energy = (1/2) * (moment of inertia) *\( (angular velocity)^2\)
First, we need to find the moment of inertia of the rotating disk. For a solid disk, the moment of inertia is given by the formula:

Moment of inertia = (1/2) * (mass) *\( (radius)^2\)
Substituting the given values:
Moment of inertia = (1/2) * (0.7 kg) * \((0.1 m)^2\)
Moment of inertia = \(0.035 kg.m^2/\(

Next, we need to find the final angular velocity of the rotating disk. Given that the rotation rate decreases by 20%, the final angular velocity will be 80% of the initial angular velocity.
Final angular velocity = 0.8 * 15 rev/s
Final angular velocity = 12 rev/s

Now we can calculate the final rotational kinetic energy using the formula:
Rotational kinetic energy = (1/2) *\( (moment of inertia) * (angular velocity)^2\)
Final rotational kinetic energy = (1/2) *\( (0.035 kg.m^2) * (12 rev/s)^2\)
Simplifying the equation:

Final rotational kinetic energy = 0.5 * 0.035 *\( (12^2) kg\(.\(m^2/s^2\)
Final rotational kinetic energy = 0.5 * 0.035 * 144 kg.\(m^2/s^2\)
Final rotational kinetic energy = 2.52 kg.\(m^2/s^2\)
So, the final rotational kinetic energy of the rotating disk is 2.52 kg.\(m^2/s^2\)
To find how much the rotational kinetic energy has decreased, we can subtract the final rotational kinetic energy from the initial rotational kinetic energy.

Initial rotational kinetic energy = \((1/2) * (moment of inertia) * (initial angular velocity)^2\)
Initial rotational kinetic energy = \((1/2) * (0.035 kg.m^2) * (15 rev/s)^2\)
Simplifying the equation:
Initial rotational kinetic energy = \(0.5 * 0.035 * (15^2) kg.m^2/s^2\)
Initial rotational kinetic energy = \(0.5 * 0.035 * 225 kg.m^2/s^2\)
Initial rotational kinetic energy = \(3.9375 kg.m^2/s^2\)

Rotational kinetic energy decrease = Initial rotational kinetic energy - Final rotational kinetic energy
Rotational kinetic energy decrease = \(3.9375 kg.m^2/s^2 - 2.52 kg.m^2/s^2\)
Rotational kinetic energy decrease = \(1.4175 kg.m^2/s^2\)

Therefore, the rotational kinetic energy has decreased by \(1.4175 kg.m^2/s^2\).

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The two football layers will have a velocity of 3.36 m/s (to the right) immediately after the collision.

Before the collision, the total momentum of the system is given by:

p = m1v1 + m2v2

Plugging in the numbers, we get:

p = (81 kg)(6.5 m/s) + (140 kg)(0 m/s)

p = 526.5 kg m/s

The total momentum of the system after the collision is:

p' = (81 kg + 140 kg) * v

Using the principle of conservation of momentum, we can equate p and p', and solve for v:

p = p'

(81 kg)(6.5 m/s) + (140 kg)(0 m/s) = (81 kg + 140 kg) * v

Solving for v, we get:

v = (81 kg)(6.5 m/s) / (81 kg + 140 kg)

v = 3.36 m/s

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Answer:

18.9 N or 19 N rounded

Explanation:

m = 0.145 kg

a = 130 m/s^2

F = ma = (0.145 kg)(130 m/s^2) = 18.9 N

Magnitude of the average force

F = 18. 9 N

There are three laws of motion that are  given by  Newton in order to study the Force and Inertia on the objects in motion or rest.

Newton's First Law defines Inertia

The second law gives the definition of Force

Third law states about action reaction pairs on the objects interacting with each other.

According to Newton' s second law of motion we can write equation (1)

\(\rm F = ma.....(1) \\\rm Where\; F = Net\; unbalanced\; external\; force\; acting\; on \; the \; system \\\\a = acceleration \; of \; center\; of\; mass\\\)

Now according to the question

we can write

Mass of the baseball = 0.145 kg

Acceleration of the baseball = 130 \(m/s^2\)

Magnitude of the average force can be find out by putting in equation (1)

F = ( 0.145 ) ( 130) = 18.85 N \(\approx\) 18. 9 N

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Explanation:

The emf is equal to the work done on the charge per unit charge (ϵ=dWdq) when there is no current flowing. Since the unit for work is the joule and the unit for charge is the coulomb, the unit for emf is the volt (1V=1J/C).

Answer:

The EMF or electromotive force is the energy supplied by a battery or a cell per coulomb (Q) of charge passing through it. The magnitude of emf is equal to V (potential difference) across the cell terminals when there is no current flowing through the circuit. (byjus)

Explanation:

Answer: B

Explanation:

Magnetic fields are created due to charges in motion. Current by definition is the amount of charge flowing over time. Therefore, the answer is B, when an electric current flows through a wire.

Answer:

b. when an electric current flows through a wire

Explanation:

Hans Oersted discovered about two hundred years ago that when the electric current flowed through a wire a magnetic field was created.

(*) Sorry for my late answer but I hope this helps others that are looking for this.

I got 100%  ;)

The type of electromagnetic radiation is Radiowaves which have a wavelength of 10 meters.

Since these waves have a longer wavelength, they are used for communication over long distances. Some examples of sources that emit these radiations - radiowaves - are TV and radio stations, cell phone towers, as well as satellites.

Radio waves are very beneficial as they can travel long distances without any power losses and getting absorbed or scattered by the atmosphere. Also, radio waves are non-ionizing and generally considered safe for human exposure. They are widely used in many applications, including broadcasting, navigation, remote sensing, and medical imaging.

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to find the modulus of elasticity MoE at 23% of moisture content based on the already given modulus of elasticity of 12% moisture content we need to consider a shrinkage behavior of material. the expected MoE comes out to be approximately \(6,836 N/mm².\)

given information:

Modulus of elasticity at 12% moisture content =7,920 N/mm²

resultant shrinkage or final shrinkage percentage FSP = 30%

To calculate the expected MoE at 23% moisture content we have the following equation:

MoE-23% =   \(MoE-12%\) \((1 - FSP (23 - 12) / (100 - 12))\)

MoE-23% = \(7,920 N/mm² × (1 - 0.30 × (23 - 12) / (100 - 12))\)

MoE-23% =\(7,920 N/mm² × (1 - 0.30 × 11 / 88)\)

MoE-23% = \(7,920 N/mm² × (1 - 0.1364)\)

MoE-23% = \(7,920 N/mm² × 0.8636\)

MoE-23% =  \(6,836 N/mm²\)

therefore the expected modulus of elasticity at 23% moisture content comes out to be approx \(6,836 N/mm²\).

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The answer is C. I searched it up and people keep on saying that it's B, which is incorrect. I found another question on Brainly where someone said that C was the answer and the person who asked the question said "Correct, thanks."

Answer:

amounts

Explanation:

every surface has different amounts of friction

hope this helps :) plz brainliest?

Answer:

Amounts of frictions

Explanation:

take for example a football player it is harder to push a  sled

The force should be applied at an angle of approximately 34.6 degrees with respect to the handle.

The torque produced by a force applied to a lever arm is given by the equation:

Torque = Force × Lever Arm × sin(θ)

Where Torque is the torque produced, Force is the applied force, Lever Arm is the length of the lever arm, and θ is the angle between the force and the lever arm.

Rearranging the equation, we have:

sin(θ) = Torque / (Force × Lever Arm)

Plugging in the given values:

sin(θ) = 0.56 Nm / (11 N × 0.091 m)

sin(θ) ≈ 0.559

To find the angle θ, we take the inverse sine (sin⁻¹) of 0.559:

θ ≈ sin⁻¹(0.559)

θ ≈ 34.6 degrees

Therefore, the force should be applied at an angle of approximately 34.6 degrees with respect to the handle.

To achieve a torque of 0.56 Nm with an applied force of 11 N and a spanner length of 9.1 cm, the force should be applied at an angle of approximately 34.6 degrees with respect to the handle. This angle ensures that the force component perpendicular to the lever arm generates the desired torque.

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Answer:

1 Atm (atmospheric pressure) is equal to 101325 pascal (Pa). To convert atm to pascal, multiply the atm value by 101325. atm to pascal formula. Pa = atm * 101325.

Explanation:

Answer:

i dont know

Explanation:

hello

Answer:

La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.

Explanation:

La regla de tres es una forma de resolver problemas de proporcionalidad entre tres valores conocidos y un valor desconocido, estableciendo una relación de proporcionalidad entre todos ellos.

Si la relación entre las magnitudes es directa, es decir, cuando una magnitud aumenta, también lo hace la otra (o cuando una magnitud disminuye, también lo hace la otra), se debe aplicar la regla directa de tres. Para resolver una regla directa de tres, se debe seguir la siguiente fórmula, siendo a, b y c los valores conocidos y x el valor a determinar:

a ⇒ b

c ⇒ x

Entonces \(x=\frac{c*b}{a}\)

La regla directa de tres es la regla que se aplica en este caso donde hay un cambio de unidades. Para realizar esta conversión de unidades, primero debes saber que 1 km = 3280,84 pies. Entonces, si 1 km son 3280,84 pies, ¿cuántos pies son 12 km?

1 km ⇒ 3280.84 pies

12 km ⇒ x

\(x=\frac{12 km*3280.84 pies}{1 km}\)

x= 39370.08 pies

La distancia por carretera de Chitré a Parita es de 12 km o 39370.08 pies.

Using mirror's equation, The smallest diameter mirror in which the observer can just see the reflected edge of the coin is 6 cm.

We must compute the size of the mirror's produced image in order to identify the lowest diameter mirror that would allow the spectator to just view the coin's reflected edge.

We must first determine how far the picture is from the mirror. In order to compute this, use the mirror equation:

\(\frac{1}{f} = \frac{1}{d} + \frac{1}{d'}\)

where f is the mirror's focal length, d and d' are the object's and image's distances from the mirror, respectively.

Since the mirror is flat, the focal length is determined by dividing the radius in half. Therefore, we may apply the formula:

\(f = \frac{R}{2}\)

This results from substituting it into the mirror equation:

\(\frac{2}{R} = \frac{1}{3} + \frac{1}{d'}\)

Calculating d':

\(d' = \frac{3R}{ (R-6) (R-6)}\)

The mirror's diameter, D, is equal to 2R. As a result, the minimal diameter of the mirror, at which the spectator can only see the coin's edge reflected, can be calculated as follows:

\(D = 2R = \frac{2d' (R - 6)}{ 3}\)

d' = 9, thus we can condense it to:

D = 18 / 3 = 6 cm

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Answer:

A group is a column (vertical, up and down)

Explanation:

A group is vertical and a period is horizontal!

Hope i helped you

Have a great day!

Answer:

A group is a row that goes up and down. (Its vertical)

Explanation:

I do A P E X.

The thermal efficiency of the given heat engine is 47%, while the thermal efficiency of the corresponding Carnot cycle is 58.24%. The heat engine falls short of the Carnot efficiency, suggesting inefficiencies or design limitations.

(a) To determine the thermal efficiency of the given heat engine, we can use the formula:

Thermal Efficiency = (Net Work Output / Heat Input) * 100

The net work output can be calculated by subtracting the heat rejected from the heat input:

Net Work Output = Heat Input - Heat Rejected

Given:

Heat Input = 500 kW

Heat Rejected = 265 kW

Substituting these values into the formula, we have:

Net Work Output = 500 kW - 265 kW = 235 kW

Now, we can calculate the thermal efficiency:

Thermal Efficiency = (235 kW / 500 kW) * 100 = 47%

Therefore, the thermal efficiency of this cycle is 47%.

(b) The Carnot cycle is an idealized reversible heat engine that operates between two heat reservoirs. Its thermal efficiency can be determined using the formula:

Thermal Efficiency Carnot = 1 - (T_low / T_high)

Given:

T_low = 50°C + 273.15 = 323.15 K

T_high = 500°C + 273.15 = 773.15 K

Substituting these values into the formula, we have:

Thermal Efficiency Carnot = 1 - (323.15 K / 773.15 K) ≈ 0.5824 (58.24%)

Therefore, the thermal efficiency of the corresponding Carnot cycle is approximately 58.24%.

(c) Comparing the thermal efficiency of the given heat engine (47%) with the thermal efficiency of the Carnot cycle (58.24%), we can conclude that the heat engine is less efficient than the corresponding Carnot cycle. In theory, the maximum efficiency any heat engine can achieve is the Carnot efficiency when operating between the same temperature limits. The given heat engine falls short of the Carnot efficiency, indicating that it is not operating at the maximum possible efficiency.

This comparison suggests that the given heat engine may not be feasible or ideal. It could be due to factors such as irreversibilities, inefficiencies in the conversion of heat to work, or losses in the system. Improving the design or addressing these inefficiencies would be necessary to approach the ideal efficiency of the Carnot cycle.

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Part A: The average power dissipated if the resistance R is doubled is 8.0 W.

Part B: The average power dissipated if the peak emf E0 is doubled will be 16.0 W.

Part C: If both the resistance R is doubled and the peak emf E0 is doubled simultaneously, the average power dissipated will be 32.0 W.

Part A: The average power dissipated by a resistor can be calculated using the formula:

P_avg = (1/2) * V_avg * I_avg

Since we are given the average power P_avg as 4.0 W, and power is directly proportional to resistance (P_avg = (1/2) * V_avg * I_avg = (1/2) * (V_avg² / R) = (1/2) * (I_avg² * R)), we can conclude that if the resistance R is doubled, the average power will also double.

Therefore, if the resistance R is doubled, the average power dissipated will be 8.0 W.

Part B: The average power dissipated by a resistor can also be calculated using the formula:

P_avg = (1/2) * V_avg * I_avg

If the peak emf E0 is doubled, the average voltage V_avg will also double since V_avg = E0/√(2).

Therefore, if the peak emf E0 is doubled, the average power dissipated will be four times the original value, resulting in 16.0 W.

Part C: Since both the resistance and the peak emf are doubled, the average power dissipated will be the product of the changes in resistance and voltage.

Doubling the resistance will double the power (8.0 W), and doubling the peak emf will quadruple the power (16.0 W). Therefore, when both changes are combined, the resulting average power dissipated will be the sum of these changes, which is 24.0 W.

Therefore, if both the resistance R is doubled and the peak emf E0 is doubled simultaneously, the average power dissipated will be 32.0 W.

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A sample of matter, either a single element or a single compound, that has definite chemical and physical properties: is an atom

An atom is the smallest unit of an element that still retains the distinctive behavior and definite chemical and physical properties of the element.

A single atom of an element keep its distinctive behavior, that's because the atom is the smallest unit of the composition of matter

The atom is the smallest part of the composition of matter, it is indivisible and is composed of a nucleus that has protons and neutrons, and around the nucleus there are the electrons.

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The cloud needs to spin more quickly to keep its angular momentum (if the distance of the mass from the center of the cloud decreases, the rate of spin must increase to compensate).

Stars and planets are created when enormous cosmic gas and dust clouds clash. These clouds revolve in the general gravitation of the galaxy, and the contents of the clouds as well as the clouds themselves are in constant motion.

This movement will most likely result in a small rotation of the cloud as seen from a place near its center. This rotation can be described in terms of its invariant measure of motion, angular momentum.

Because of the conservation of angular momentum, ice skaters spin more quickly when they draw their arms in. As her arms approach her axis of rotation, she rotates faster while retaining the same angular momentum.

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Answer:

My teacher said 36m when I asked her

Explanation:

HOPE THIS HELPS!!

proton are the subatomic particles that are _positive_ charged and found in the centre of the atom. neutron are the subatomic particles that are _neutral_ charged and found in the centre of the atom .