a train is moving at a speed of 65 mph. the ticket collector is walking 2 mph toward the front of the train. how fast, in mph is the ticket collector moving from the point of view of a person on the train?

\(\sf Potassium \ : \ 2.2 * 10^{-7}\)

\(\sf Argon \ : \ 7.1 * 10^{-8}\)

\(\sf Boron \ : \ 8.5 * 10^{-8}\)

\(\sf Silver \ : \ 1.6 * 10^{-7}\)

greatest to least :

The order is

Shortcut trick :-

The nature of atomic radii in. periodic table

The minimum number of terms required for the sum sn to have an error less than 0.0399, assuming K = 1 and b-a = 1.

To determine the minimum number of terms n required for the sum sn to have an error less than 0.0399, we need to use the formula for the error term of a finite series:

|En| ≤ ((M * (b-a)^n)/(n!))

where En is the error term, M is the maximum value of the (n+1)th derivative of the function, a and b are the limits of integration, and n is the number of terms in the series.

Since we do not have a specific function or limits of integration, we cannot determine the exact value of M. However, we can use an upper bound for M, which is the maximum value of the (n+1)th derivative of the function over the entire interval [a,b]. Let's assume that M = K, where K is some constant.

Then we have:

|En| ≤ ((K * (b-a)^n)/(n!))

We want the error to be less than 0.0399, so we can set up the following inequality:

((K * (b-a)^n)/(n!)) < 0.0399

To solve for n, we need to use a numerical method such as trial and error, or a graphing calculator. We can also use a table of values for n! and (b-a)^n to simplify the inequality.

For example, if we assume that K = 1 (which is a reasonable assumption for many functions), and let b-a = 1 (i.e. we are integrating over the interval [0,1]), we can create a table of values for n! and (b-a)^n:

n | n! | (b-a)^n
--|----|---------
1 | 1  | 1
2 | 2  | 1
3 | 6  | 1
4 | 24 | 1
5 | 120| 1
6 | 720| 1

Using these values, we can rewrite the inequality as:

(K/n!) < (0.0399/(b-a)^n)

Plugging in our values, we get:

1/n! < 0.0399

Solving for n using trial and error or a graphing calculator, we find that n = 4 is the minimum number of terms required for the sum sn to have an error less than 0.0399, assuming K = 1 and b-a = 1. However, keep in mind that this value may change depending on the specific function and limits of integration.

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Answer: 210

Explanation:

Recall that the perimeter is the distance around the figure. It's the amount of fencing needed to enclose such a shape.

Add up all three sides and set the sum equal to the perimeter 70. Then solve for x.

side1+side2+side3 = perimeter

(3x)+(3x-1)+(4x+1) = 70

10x = 70

x = 70/10

x = 7

We can then calculate each side

Notice how 21+20+29 = 70 to confirm we have the correct side lengths.

Once we know the horizontal and vertical leg (aka base and height), we can find the area.

Area = 0.5*base*height

Area = 0.5*21*20

Area = 210 square cm

Step-by-step explanation:

first you have to find x . Then you can add them and equal them with triangle area.

As the compounding frequency increases, the yield increases as well. But there's a limit to that increase.

Consider depositing $100 into an account at 5% interest. Let's consider a timespan of 1 year. These values were picked arbitrarily.

Using the formula A = P(1+r/n)^(nt), we can find the various yield amounts when n varies

The table below shows how A changes based on the values of n. I've let P = 100, r = 0.05 and t = 1.

As n gets larger, the value of A slowly approaches 105.13 when you round to the nearest penny.

So eventually the investment yield hits a ceiling of some sort.  We cannot make the investment grow forever in some fixed amount of time (in this case 1 year).

Answer:

point D

Step-by-step explanation:

When k is negative, the graph will flip over the y-axis.

When a slider is moved in a graphing tool, the y=k log(x) and y=log(kx) equations are compared.

The impact of changes in k on each equation will be assessed when k is negative.

What is the answer?

The relationship between k and the y=k log(x) equation is as follows:

If k is increased, the graph will be compressed and moved up, resulting in a steeper curve.

If k is decreased, the graph will be expanded and moved down, resulting in a flatter curve.

It should be noted that if k is negative, the graph would not be defined.

Therefore, when k is negative, this graph would not be shown. For this reason, there will be no graph to compare for this equation.

When k is negative, the graph will flip over the y-axis.

The x-intercept (when y=0) is also changed from 1/k to -1/k.

The graph, however, is still defined.

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Answer:

20

Step-by-step explanation:

Thing to Remember :

Length of tangents from same external point is the same.

Solving :

Answer: D, x < 8

Step-by-step explanation: Subtract 18 from both sides.

Simplify the expression

Subtract the numbers

Subtract the numbers

Divide both sides by the same factor, and flip the relation because the factor is negative

Cancel terms that are in both the numerator and denominator

Divide the numbers

−6x+18−18>−30−18=

=x<8

Step-by-step explanation:

As we can see it a right angled triangle

so <y =90°

Now

3x + 11° + 25° + 90° = 180°{being sum of angles of triangle}

3x + 126° = 180°

3x = 54°

X = 18°

Answer:

He does not have enough money

Step-by-step explanation:

Step one:

given data

The total money that Goerge has is $15

Expenses to incure

to see a movie ($9.00) and

to buy a pretzel ($2.65),

a drink ($1.35 ), and

two veggie cups ($1.74 each)= 1.74*2= $3.48

Totoal expenses= 9+2.65+1.35+3.48= $16.48

Step two:

The deficit that George will have is 16.48-15= $1.48

Hence he does not have enough money

Answer:

13.48

(Is the answer to the math problem)

The solution to the given unforced ODE with initial conditions y(0) = 2 and y'(0) = 8 is y(t) = 4e-2t + 2e-4t.

To obtain this solution, we start by solving the ODE:

2y (t) + 8y' (t) − 10y(t) = 0

The characteristic equation for this ODE is r2 + 8r − 10 = 0, which has solutions r = -2 and r = -4. This gives us the general solution of the ODE as:

y(t) = A e-2t + B e-4t.

Using the initial conditions given, we can determine the values of A and B:

y(0) = 2 = A + B

y'(0) = 8 = -2A + -4B

By solving the system of equations, we obtain A = 2 and B = 2. Therefore, the solution to the given ODE is y(t) = 4e-2t + 2e-4t.

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Answer:

1/3

Step-by-step explanation:

So there are 12 natural numbers in total: (113 - 102) + 1

Then there are the prime numbers: 103, 107, 109, and 113

so there are 4/12 prime numbers or 1/3

Answer:

1/3

Step-by-step explanation:

We can list all the numbers from 102 to 113:

To check if each number is prime, we simply have to check divisibility by 2, 3, 5, and 7 — if any of these numbers are not divisible by those, it will have no factors lower than its square root, and will therefore be prime.

102 - composite, multiple of 2

103 - prime

104 - composite, multiple of 2

105 - composite, multiple of 5

106 - composite, multiple of 2

107 - prime

108 - composite, multiple of 2

109 - prime

110 - composite, multiple of 2

111 - composite, multiple of 3

112 - composite, multiple of

113 - prime

4/12 or 1/3 of the numbers in this list are prime.

II is higher. When there is very little scatter around the regression line, it means that the data points are tightly clustered and the relationship between the variables is strong.

In this scenario, the slope estimate, b1, is likely to be more precise and have less uncertainty. The regression line will have a small standard error of estimate, indicating that the predicted values are close to the actual values.

On the other hand, when there is a lot of scatter around the regression line, it means that the data points are more spread out and the relationship between the variables is weaker. In this scenario, the slope estimate, b1, is likely to be less precise and have more uncertainty. The regression line will have a larger standard error of estimate, indicating that the predicted values are further from the actual values.

In summary, the amount of scatter around the regression line affects the precision of the slope estimate. When there is very little scatter, the slope estimate is likely to be more precise and have less uncertainty. Conversely, when there is a lot of scatter, the slope estimate is likely to be less precise and have more uncertainty.

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Answer:

Step-by-step explanation:

Given the expression -3-(-5)

This is also expressed as;

-3(-5)

= -3 + 5 (The product of two negative sign gives a positive sign)

= 5 - 3

= 2

Hence the result of the expression is 2

Answer:

4 m

Step-by-step explanation:

I took the test

Answer:

C. 4m

Step-by-step explanation:

The force applied by the jet of water on a fixed object can be calculated using the equation F = A * P, where F is the force, A is the cross-sectional area of the jet, and P is the pressure of the water.

In order to find the force, we first need to find the cross-sectional area of the jet. The diameter of the jet is given as 55 mm, so we can calculate the radius by dividing the diameter by 2: r = 55 mm / 2 = 27.5 mm.

Next, we need to convert the radius from millimeters to meters, as the SI unit for force is Newtons, which uses meters: r = 27.5 mm = 0.0275 m.

To find the cross-sectional area, we can use the formula for the area of a circle: A = π * r^2.

Plugging in the value of the radius, we get: A = π * (0.0275 m)^2 = 0.00236 m^2.

Now, we need to find the pressure of the water. The flow rate of the water is given as 25 liter/s. We can convert this to cubic meters per second by multiplying by 0.001 (since 1 liter = 0.001 cubic meters): 25 liter/s * 0.001 = 0.025 m^3/s.

Since pressure is defined as force per unit area, we can rearrange the equation F = A * P to solve for P: P = F / A.

Plugging in the values of the force and the area, we get: P = 0.025 m^3/s / 0.00236 m^2 ≈ 10.593 m/s^2.

Therefore, the force applied by the jet of water on a fixed object is approximately 10.593 Newtons.

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Answer:

Let number be ‘x’

x - 13 = -2

x = -2 + (-13)

x = -2 - 13

x = - 15

Answer:

First step

Step-by-step explanation:

you should guess the number greater than 13

and

step 2

subtract that number to 13

=13-15

=-2ans

Options (a) and (b) have smaller absolute values of the correlation coefficient, indicating weaker linear relationships. Option (d) is incorrect as the correlation coefficient measures the linear relationship between two variables, which would be represented as a straight line on a scatter plot.

The Pearson correlation measures the strength and direction of the linear relationship between two variables. A correlation coefficient of -1 indicates a perfect negative linear relationship, a correlation coefficient of 0 indicates no linear relationship, and a correlation coefficient of +1 indicates a perfect positive linear relationship.

In general, the closer the absolute value of the correlation coefficient is to 1, the closer the data points will be to a straight line. Therefore, among the given options, the correlation coefficient that would result in data points being clustered most closely around a straight line is option (c) r = –0.70, which indicates a strong negative linear relationship between the two variables. When the correlation is close to -1, the data points tend to form a straight line with a negative slope, indicating a strong and consistent negative relationship between the two variables.

Options (a) and (b) have smaller absolute values of the correlation coefficient, indicating weaker linear relationships. Option (d) is incorrect as the correlation coefficient measures the linear relationship between two variables, which would be represented as a straight line on a scatter plot.

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Answer:

(H)

Step-by-step explanation:

Less than signs are <

Greater than signs are >

Since in this case x is the number

7 has to be less than x which is x<7

Answer:

f

Step-by-step explanation:

13) The electron configuration [Kr]5s²4d¹5p³ corresponds to the element iodine (I).

14) The electron configuration [Xe]6s²4f¹⁴5d¹⁰6p⁶ corresponds to the element lead (Pb).

15) The electron configuration [Rn]7s²5f¹⁴ corresponds to the element lawrencium (Lr).

16) The electron configuration 1s²2s²2p¹3s²3p⁵4s²4d¹⁰4p⁹ is valid.

17) The electron configuration 1s²2s²2p¹3s²3d³ is not valid as it violates the Aufbau principle.

18) The electron configuration [Ra]7s²5f is not valid as it is incomplete.

19) The electron configuration [Kr]5s²4d¹⁰5p³ is valid.

20) The electron configuration [X] is not a valid electron configuration as it does not specify the specific subshells and electrons present.

13) The electron configuration [Kr]5s²4d¹5p³ corresponds to iodine (I) because it has 53 electrons. The [Kr] represents the electron configuration of the noble gas krypton, and the subsequent orbitals represent the additional electrons in the iodine atom.

14) The electron configuration [Xe]6s²4f¹⁴5d¹⁰6p⁶ corresponds to lead (Pb) because it has 82 electrons. The [Xe] represents the electron configuration of the noble gas xenon, and the subsequent orbitals represent the additional electrons in the lead atom.

15) The electron configuration [Rn]7s²5f¹⁴ corresponds to lawrencium (Lr) because it has 103 electrons. The [Rn] represents the electron configuration of the noble gas radon, and the subsequent orbitals represent the additional electrons in the lawrencium atom.

16) The electron configuration 1s²2s²2p¹3s²3p⁵4s²4d¹⁰4p⁹ is a valid electron configuration because it follows the Aufbau principle, filling the orbitals in increasing order of energy.

17) The electron configuration 1s²2s²2p¹3s²3d³ is not valid because it violates the Aufbau principle. According to the Aufbau principle, electrons should fill the orbitals in increasing order of energy.

18) The electron configuration [Ra]7s²5f is not valid because it is incomplete. It should specify the specific subshells and electrons present in the atom.

19) The electron configuration [Kr]5s²4d¹⁰5p³ is a valid electron configuration for an element, following the Aufbau principle.

20) [X] is not a valid electron configuration as it does not specify the specific subshells and electrons present. It is incomplete and does not provide information about any element.

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The number kilometers Ted ran in 285 minutes is 60 km.

The speed formula can be defined as the rate at which an object covers some distance. Speed can be measured as the distance travelled by a body in a given period of time. The SI unit of speed is m/s.

Given that, Ted likes to run long distances. He can run 20 km in 95 minutes.

We know that, speed =Distance/Time

Now, speed =20/95

= 0.21 km per minute

Number kilometers ran in 285 minutes is

285×0.21

= 59.85

≈ 60 km

Therefore, the number kilometers Ted ran in 285 minutes is 60 km.

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"Your question is incomplete, probably the complete question/missing part is:"

Ted likes to run long distances. He can run 20 km in 95 minutes. He wants to know how many kilometers he will go if he runs at the same pace for 285 minutes

Answer:

error

Step-by-step explanation:

Answer:

35%

Step-by-step explanation:

There are 20 sqaures, 7 of them are not shaded, 7/20=35%

Answer:

0.00284090909

Step-by-step explanation:

It’s basicly a unit conversion that converse whatever you have to miles/h, so you are getting a miles and get a time and do the math, the final answer will be 180/(5280*12)=0.00284090909

For this problem, let's think of this shape as a rectangle and a triangle put together. We'll calculate the area of each shape and add them together to get the total area.

For the rectangle, the equation is b*h. Here the base = 7 cm and the h = 4cm

For the triangle, the equation is 1/2 * (b*h). Here the base is a little tricky to find. We know the total length is 12cm and the rectangle length was 7cm. So 12-7= 5cm, which is the base of the triangle. The height would be the same (4cm).

Once you calculate those two areas and add them up, you'll have the total area of this shape.

The perimeter of triangle is 66.24 units.

What is triangle?

In Euclidean geometry, any 3 points, once non-collinear, verify a unique triangle and at the same time, a unique plane

Main body:

according to question :

c = 28

let the vertices be A,B,C

∠A= 30°

by using trigonometric ratios,

BC/ AB = sin30°

AB = C = 28

BC/28 = sin30°

BC = 28*sin30°

BC= 28*(1/2)

BC = 14

similarly

AB /CA = cos 30°

28/CA = √3/2

CA = 28*√3/2

CA = 14/√3

CA = 24.24

Hence , perimeter = AB +BC +CA = 28+14+24.24

                              =66.24 units

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The correct answer is 475 and 525. To find the range of values that 95% of the observations lie between.

We can use the empirical rule, which states that for a normal distribution with mean μ and standard deviation σ, about 95% of the observations will fall within 2 standard deviations of the mean.

In this case, the mean is 500 and the standard deviation is 10. So, 2 standard deviations below the mean is 500 - 2(10) = 480, and 2 standard deviations above the mean is 500 + 2(10) = 520.

Therefore, about 95% of the observations lie between 480 and 520, or approximately between 475 and 525.

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A rental company charge $65 a day and 20 cent a mile for renting a truck. Michael rented a truck for 3 day, and he bill came to $275. He drive 400 mile.

In the given question we have to find how many mile did he drive.

From the given question, a rental company charge $65 a day and 20 cent a mile for renting a truck.

Michael rented a truck for 3 day, and he bill came to $275.

The rental company charges for three days renting

$(65×3)=$195

Also there is a expense of a mile for renting the truck is

20 cents =$0.20

Let Michel drove x miles in 3 days.

Therefore total bill in 3 days is $(0.20x+195).

According to the question,

0.20x+195 = 275

Subtract 195 on both side we get

0.20x = 80

Divide by 0.20 on both side we get

x = 400

Hence, he drive 400 mile.

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