A toy spacecraft is launched directly upward. When the toy reaches its highest point, a spring is released and the toy splits into two parts with masses of 0.02 kg and 0.08 kg, respectively. Immediately after the separation, the 0.02 kg part moves horizontally due east. Air resistance is negligible. True statements about the 0.08 kg part include which of the following? i. It could move north immediately after the spring is released. II. It takes longer to reach the ground than does the 0.02 kg part. III. It strikes the ground farther from the launch point than does the 0.02 kg part. A) None B) I only C) Ill only D) I and II only E) II and III only

Answer:

Ek= 1/2*m*v^2

Explanation:

kinetic energy= 1/2* mass * square velocity

Answer: 10 kg

Explanation:

Using dimensional analysis, we can find the unit of mass in the given system:

Force (F) = mass (m) × acceleration (a)

In the given system, the unit of force is 100 N, which can be written as:

100 N = (100 kg · m/s²) × (10 m/s²)

Thus, we can see that the unit of force is equivalent to 100 kg·m/s².

Now, we can rearrange the equation to solve for mass (m):

m = F/a

Substituting the units:

m = (100 kg·m/s²) / (10 m/s²)

m = 10 kg

Therefore, the unit of mass in the given system is 10 kg.

Answer:

10m

Explanation:

assuming the ball was at 0 m/s before, after 5 seconds the ball would be traveling at 10m

Drawing (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium, as it shows equal pressure in all three bulbs.

Since the two bulbs contain different gases, the pressures in each bulb will be different. When the stopcocks are opened, the gases will flow into the empty bulb until the pressures are equalized. The final state will have equal pressure in all three bulbs.

What is an equilibrium?

An equilibrium is a state of balance or stability achieved in a chemical reaction when the forward reaction rate is equal to the reverse reaction rate. In other words, it is the point at which the concentrations of reactants and products no longer change with time, because the rates of the forward and reverse reactions are equal.

At equilibrium, the amounts of reactants and products are governed by the equilibrium constant (K), which is a measure of the relative concentrations of the reactants and products at equilibrium.

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The range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations is from 5.45 x 10⁻¹² H to 3.62 x 10⁻¹² H.

The frequency at which the antenna can pick the radio waves broadcasted is known as resonance frequency.

At resonance frequency, the capacitive reactance is equal to inductive reactance.

Xc = Xl

\(\frac{1}{2\pi fC} = 2\pi fL\\\\4\pi^2 f^2 LC = 1\\\\C = \frac{1}{4\pi^2 f^2L}\)

where;

When the frequency is 88 MHz, the capacitance is;

\(C = \frac{1}{4\pi^2 \times (88 \times 10^6)^2 \times (6\times 10^{-7})} \\\\C = 5.45 \times 10^{-12} \ H\\\\\)

When the frequency is108 MHz, the capacitance is;

\(C = \frac{1}{4\pi^2 \times (108 \times 10^6)^2 \times (6\times 10^{-7})} \\\\C = 3.62\times 10^{-12} \ H\\\\\)

Thus, the range of capacitance values that are needed so the antenna can pick up all the radio waves broadcasted by FM stations is from 5.45 x 10⁻¹² H to 3.62 x 10⁻¹² H.

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The answer by onyebuchinnaji is correct, except for the fact that the final answer is in Farad (F), not H.

Answer:  1)Scientists seek to acquire: scientific hypothesis

2)A scale measures the weight of a light object: 0.240 lbs

3)What does the process of scientific inquiry: It starts with a problem to solve or a question to answer

4)A mouse in a maze scurries 41 cm south: 76 cm southwest

5)When might an object's average velocity be equal to its average speed in two dimensions:

If the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.

6)Using the velocity versus time graph, calculate the acceleration of Object A: 3 m/s^2

7)What is the range of a bullet fired horizontally at a height of 1.5m: 66.4m

8)What two vertical forces act on a falling leaf: weight, friction

9)What is equal and opposite to the applied force: spring force

10)Using the free-body diagram, calculate the net force: 12N, right

11)How does the force of impact during a collision change: it increases

12)The threads of a screw used to fasten two pieces of wood: by increasing the normal force exerted by the wood on the screw thread

13)A 60 kg skier with an initial velocity of 12 m/s coasts up a hill: 2.5m

14)A 1,500 kg car’s speed changes from 30 m/s to 15 m/s: -506,250 (negative 506,250| NOT POSITIVE)

15)What is true about weather: The weather depends on so many conditions that it is not possible to account for them all in any model.

16)A student records the mass of objects A, B, C, and D:  A

17)Newton’s cradle is a contraption where metal balls: friction force

18)In a closed system, an object with a mass of 10 kg: 12kgm/s

19)Given the data, what is the kinetic energy of the: 3J

20)A wedge is a simple machine that is essentially two: A length of 12 in. and a thickness of 2 in.

21)Object A and Object B are at equal distances on opposite: 3/4

22)A geosynchronous satellite has an orbital period of 24: 35,900 km

23)Calculate the eccentricity for the planet if the: 0.0167

24)A planet travels in its orbit close to apogee : the same amount of time

25)If astronomers discovered a new planet and found its: 22.3 AU

Explanation:

Hope this helps you guys!!! <3 (this is for 'A Semester Exam')

The characteristics of the image are: Inverted, Smaller, and Real.

The principal axis is an imaginary straight line passing through the center of a lens or a mirror, perpendicular to the surface at its center. All the parallel rays of light that pass through a lens or a mirror and are parallel to the principal axis converge at the focal point on the principal axis after refraction or reflection, respectively. Similarly, any ray of light that passes through the focal point before refraction or reflection will emerge parallel to the principal axis. The principal axis is an important reference line used in the geometry of optical systems.

To determine the image characteristics of the photograph when placed 21 cm in front of a converging lens with a focal length of 6.0 cm, we can use ray tracing.

Using the rules of ray tracing, we can draw three rays:

1. A ray parallel to the principal axis that passes through the focal point after refraction.

2. A ray that passes through the center of the lens and continues in a straight line.

3. A ray that passes through the focal point before refraction and emerges parallel to the principal axis.

The point where these rays intersect after refraction is the location of the image. In this case, the image is located 9 cm behind the lens.

Therefore, The characteristics of the image are: Inverted, Smaller, and Real.

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Each of the five friends needs to pay £12 to cover the cost of their own meals and contribute towards the birthday person's meal. Using mean allows us to distribute the cost equally among the friends, ensuring a fair division of expenses for the meal.

To determine how much each of the five friends needs to pay, we can use the concept of averages (mean) and divide the total cost by the number of people paying.

In this scenario, the total cost of the meal for 6 people is £12 per person. Since the other 5 friends have decided to pay for the birthday person's meal, they will collectively cover the cost of their own meals plus the birthday person's meal.

To calculate the total cost covered by the five friends, we can subtract the cost of one person's meal (since the birthday person's meal is being paid by the group) from the total cost. The cost of one person's meal is £12.

Total cost covered by the five friends = Total cost - Cost of one person's meal

= (£12 x 6) - £12

= £72 - £12

= £60

Now, to find out how much each of the five friends needs to pay, we divide the total cost covered by the five friends (£60) by the number of friends (5).

Amount each friend needs to pay = Total cost covered by the five friends / Number of friends

= £60 / 5

= £12

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Vehicles need to be serviced for several reasons such as preventing costly repairs and improving fuel economy.

First, regular maintenance can help to prevent costly repairs down the road. Second, maintenance can help to improve fuel economy and emissions. Third, maintenance can help to keep your vehicle safe and reliable.

The servicing requirements for petrol/diesel and electric vehicles differ in a number of ways. Petrol/diesel vehicles require oil changes more frequently than electric vehicles. This is because petrol/diesel engines use oil to lubricate the moving parts, while electric motors do not. Petrol/diesel vehicles also require tune-ups more frequently than electric vehicles.

This is because petrol/diesel engines have more moving parts that need to be synchronized, while electric motors have fewer moving parts.

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Answer:

. an increase in the mass on the spring

Explanation:

Period of oscillation is inversely proportional to amplitude. Since amplitude is displacement and displacement is, the answer of objective b is ignored

My answer is a

Answer:

A spring scale measures weight or force when an object is hung from its hook.

Explanation:

Based on the information provided, it is likely that the figure shows an alternating current (AC). The arrows under the electrons pointing right and left, both towards and away from the light bulb, indicate that the direction of the electron flow is changing periodically. This is a characteristic of alternating current, where the flow of electric charge reverses direction periodically, typically in a sinusoidal manner.

In an AC circuit, the voltage also changes direction periodically, which is consistent with the changing direction of the electron flow shown in the figure.

In an alternating current, the flow of electrons periodically reverses direction, causing the current to switch between positive and negative values. This is different from direct current (DC), where electrons flow in a single, constant direction.

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If the distance between the centres of the two spheres were doubled, there would be a gravitational force of 60 N.

The force affecting the Sun and Earth. the cause of the Moon's orbital rotation around the Earth. The ocean's tides are controlled by the force of the Moon. the force that confines all gases to the Sun.

Mass of the lead sphere F = 57 million kg

Initial center distance r = 20m

The gravitational constant of spacetime G = 6.67 * 10⁻¹¹ Nm²/ kg²

Gravitational force of attraction F₁ = 540 N

Newton's law of gravity says that we have;

F = Gm₁m₂ / r

F₁ / F₂ = r₂² / r₁²

F₂ = F₁r₁² / r₂²

F₂ = F₁r₁₂ / (3r₁)²

F₂ =F1 / 9

F₂ = 540 N / 9

F₂ = 60 N

If the space between the centres of the two spheres were to be quadrupled, the gravitational force of attraction would be 60 N.

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answer.

...............................................

The location at the point where electric field becomes zero is at 3.6m, when a positive point charge Q1= 2.6×10−5 C is fixed at the origin and a negative point charge Q2= −5.1×10−6 C is fixed at 2.0m.

Electric field is field around electrically charged particle where columbic force of attraction or repulsion can be experienced by other charged particles. It is denoted by letter E and it's SI unit is V/m Volt per meter or N/C newton per coulomb.

Electric field comes inward to the center of the negative charge and it is going outward for positive charge.

Given,

Q₁= 2.6×10⁻⁵ C

Q₂= −5.1×10⁻⁶ C

x = 2.0m,

In this case there are two charges, one at the origin and other is at 2m distance from origin. Both these charges are kept along positive x axis. looking at the situation there are 2 cases

Case 1 ( electric field in between two charges)

in this case direction of the resultant electric field in between two charges is along positive x direction (direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis which is also in positive x direction).

Case 2 ( right side of the negative charge)

In this case direction of electric field of positive charge is outward along x axis which is along positive x direction and direction of electric field of negative charge is inward along x axis but which is in opposite direction of electric field due to positive charge.

Hence our electric field is zero at right side of the negative charge.

on right side, electric fields due to both charges are opposite to each other then we can write mathematically E₁ - E₂ = 0 at the point where resultant electric field is zero. Where E₁ is elctric field due to positive charge and E₂ is electric field due to negative charge.

E₁ - E₂ = 0

E₁ = E₂

\(\frac{kQ_{1}}{x^{2}} = \frac{kQ_{2} }{(x+2)^{2}}\)

\(\frac{Q_{1}}{x^{2}} = \frac{Q_{2} }{(x+2)^{2}}\)

\(\frac{Q_{1}}{Q_{2} }} = \frac{x^{2} }{(x+2)^{2}}\)

(2.6×10⁻⁵ C ÷ -5.1×10⁻⁶ C)  \(= \frac{x^{2} }{(x+2)^{2}}\)

\(\frac{x^{2} }{(x+2)^{2}}\) = 5.098 ≅ -5.1

x² = 5.1 (x+2)²

x = 2.25(x+2)

x=2.25x + 4.5

x(1-2.25) = 4.5

x(-1.25) = 4.5

x = 3.6m

Hence Electric field is zero at 3.6m from origin.

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Answer:

Look at this picture hopefully it helps

Answer:

unless an external unbalanced force acts on it.

Answer:

An object in motion will not change unless an external force acted upon it.

Answer:

Explanation:

The empirical equation y = 9.8x represents the relationship between the displacement y of an object and the time x it has been falling under the influence of gravity.

On the other hand, the equation V = gT + V0 represents the relationship between the velocity V of an object, the time T, the initial velocity V0, and the acceleration due to gravity g.

To compare the two equations, we can equate the displacement y in the first equation with the expression for displacement in terms of velocity and time, which is y = (1/2)gt^2 + V0t, where t is the time.

Substituting this into the empirical equation, we get:

9.8x = (1/2)gt^2 + V0t

We can see that this equation has three variables: g, V0, and t. We can't determine all three variables from this equation alone.

However, if we know the time it takes for an object to fall a certain distance, we can use this equation to solve for g and V0. For example, if we know that an object falls 1 meter in 0.45 seconds, we can substitute x=1 and t=0.45 into the equation:

9.8(1) = (1/2)g(0.45)^2 + V0(0.45)

Simplifying this equation, we get:

g = 19.62 m/s^2

V0 = 0.45(9.8) = 4.41 m/s

So the acceleration due to gravity is 19.62 m/s^2 and the initial velocity is 4.41 m/s. Note that these values may not be exactly equal to the true values, as the empirical equation y=9.8x is only an approximation and there may be other factors affecting the motion of the object.

Answer:

2.753*10^-11N

Explanation:

According to Newton's law of gravitation, the force between the masses is expressed as;

F = GMm/d²

M and m are the distances

d is the distance between the masses

Given

M = 3.71 x 10 kg

m = 1.88 x 10^4 kg

d = 1300m

G = 6.67 x 10-11 Nm²/kg

Substitute into the formula

F = 6.67 x 10-11* (3.71 x 10)*(1.88 x 10^4)/1300²

F = 46.52*10^(-6)/1.69 * 10^6

F = 27.53 * 10^{-6-6}

F = 27.53*10^{-12}

F = 2.753*10^-11

Hence the gravitational force between the asteroid is 2.753*10^-11N

44.4  is the work done by friction  14.4  s the velocity of the block at point C . Correct Option a)

Friction is the force that prevents solid surfaces, fluid layers, and material components from moving against each other. There are various kinds of friction.

Dry friction is the force that resists the relative lateral motion of two in touch solid surfaces. Dry friction is further classified as static friction ("stiction") between non-moving surfaces and kinetic friction ("stiction") between moving surfaces. Dry friction, with the exception of atomic or molecular friction, is caused by the interplay of surface characteristics known as asperities . Fluid friction explains the friction that occurs between sliding segments of a thick fluid.

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Full Question: In the figure below, a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with a coefficient of kinetic friction uk = 0.15. The block makes it up the incline to B a second flat frictionless surface. The incline is 22 m long at an angle = 15° What is the total work done in joules when the block goes from A to C and what is the speed of the block at point C in m/s? (fist value is work, second is speed) A) 44.4; 14.4 B) 44.4, -14.4 C) 14.4, 44.4 D) 44.4, 14.4 E) 44.4, 44.4

Answer:

Accordng to Hook's law

F=kx

So

spring constant × displacement

Explanation:

Answer:  A) spring constant × displacement

Accordng to Hook's law

F=kx

So

A) spring constant × displacement

Explanation: hope this helps pls mark me brainliest

Gay-Lussac's law of volume states that for a fixed mass of an ideal gas kept at a fixed pressure, the volume and temperature are directly proportional.

This means that if the temperature of a gas is increased, its volume will also increase, and vice versa.

The reason for Gay-Lussac's law of volume is that the average kinetic energy of the gas molecules is directly proportional to the temperature. As the temperature increases, the molecules move faster and collide with the walls of the container more often. This causes the pressure to increase. However, if the pressure is kept constant, the increase in pressure will cause the volume to increase.

Gay-Lussac's law of volume can be expressed mathematically as follows:

V₁ / T₁ = V₂ / T₂

where:

V₁ = initial volume of the gas

T₁ = initial temperature of the gas

V₂ = final volume of the gas

T₂ = final temperature of the gas

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Gay-Lussac's Law of Volume provides a useful relationship between the volumes of reactant and product gases, allowing for predictions and calculations in chemical reactions involving gaseous substances.

Gay-Lussac's Law of Volume, also known as the Law of Combining Volumes of Gases, states that "the volumes of gases involved in a chemical reaction at constant temperature and pressure are in the ratio of small whole numbers."

Reason for Gay-Lussac's Law of Volume

1. Avogadro's Law: According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of particles (atoms, molecules, or ions). This law established the concept of the mole, which is a unit of measurement representing a fixed number of particles. Since the number of particles is the same, the volume occupied by these particles should also be the same.

2. Stoichiometry: Chemical reactions involve the rearrangement of atoms and molecules to form new substances. The coefficients in a balanced chemical equation represent the relative amounts of reactants and products. In the gaseous state, these coefficients can be directly related to the volumes of the gases involved. For example, if the balanced equation shows that two volumes of gas A react with three volumes of gas B to form four volumes of gas C, it implies that the gases react in simple volume ratios.

3. Gas Behavior: Gases follow certain ideal gas laws, such as Boyle's Law (pressure-volume relationship), Charles's Law (temperature-volume relationship), and Gay-Lussac's Law (pressure-temperature relationship). These laws describe how the physical properties of gases change under different conditions. Gay-Lussac's Law of Volume specifically relates the volumes of gases involved in a chemical reaction and shows that the volumes are proportional to each other.

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Since the displacement is frictionless, that means the energy loss is negligible. Work of the non conservative forces acting on the particle during this displacement = 0

In a given frictionless displacement of a particle, its kinetic energy increases by 25 J while its potential energy decreases by 10 J.

A non conservative force changes mechanical energy of a system to another form of energy. In most cases to thermal energy. Friction is a good example of non conservative forces.

Since the displacement is frictionless, that means the energy loss is negligible.

The work of the non conservative forces acting on the particle during this displacement is therefore equal to zero.

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Answer:

73.3m/s

Explanation:

We can find the velocity of the player.

Momentum = mass * velocity

Given

Mass = 0.15kg

Momentum = 11kgm/s

Get the velocity

Velocity = Momentum/Mass

Velocity = 11/0.15

Velocity = 73.3m/s

Hence the velocity of the player is 73.3m/s

Answer:

100 mR

Explanation:

Answer:

I'm not %100 sure but it might be d

Explanation:

After 0.100 s, the cat would be 0.049 m below its initial position, with a velocity of 0.98 m/s. After 0.200 s, the cat would be 0.196 m below its initial position, with a velocity of 1.96 m/s. Finally, after 0.300 s, the cat would be  0.441 m below its initial position, with a velocity of approximately 2.94 m/s.

To calculate the position and velocity of the sleeping cat after certain time intervals, we need to make some assumptions and use basic principles of physics.

Assuming the cat falls vertically downward due to gravity and ignoring air resistance, we can apply kinematic equations to solve the problem.

(a) Position:

Using the equation for the position of an object in free fall, h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time, we can determine the position of the cat.

After 0.100 s: h = (1/2)(9.8 m/s^2)(0.100 s)^2 = 0.049 m (approximately)

After 0.200 s: h = (1/2)(9.8 m/s^2)(0.200 s)^2 = 0.196 m (approximately)

After 0.300 s: h = (1/2)(9.8 m/s^2)(0.300 s)^2 = 0.441 m (approximately)

(b) Velocity:

The velocity of the cat can be calculated using the equation v = gt, where v is the velocity and t is time.

After 0.100 s: v = (9.8 m/s^2)(0.100 s) = 0.98 m/s (approximately)

After 0.200 s: v = (9.8 m/s^2)(0.200 s) = 1.96 m/s (approximately)

After 0.300 s: v = (9.8 m/s^2)(0.300 s) = 2.94 m/s (approximately)

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We can use the formula for the period of a pendulum:

T = 2π√(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity (9.8 m/s^2).

Rearranging the formula to solve for L, we get:

L = (gT^2)/(4π^2)

Plugging in the given values, we get:

L = (9.8 m/s^2) x (3.17 s)^2 / (4π^2) = 2.00 m

Therefore, the length of the pendulum is approximately 2.00 m.