"A toy rocket is shot vertically into the air from a launching pad 7 feet above the ground with an initial velocity of 72 feet per second. The height in feet, of the rocket above the ground at t seconds after launch is given by the function h(t)=-16 t²+72 t+7. How long will it take the rocket to reach its maximum height? What is the maximum height?
The rocket reaches its maximum height at second(s) after launch.
(Simplify your answer.)
The maximum height reached by the object is feet.
(Simplify your answer.)"

Answer:

4

Step-by-step explanation:

The equation of the linear relationship in slope-intercept form is y = 2x - 8. Option A is the correct answer.

To determine the equation of the linear relationship in slope-intercept form based on the table, we need to find the slope and y-intercept.

By observing the table, we can calculate the slope by selecting any two points. Let's choose the points (0, -8) and (4, 0).

Slope (m) = (change in y) / (change in x)

= (0 - (-8)) / (4 - 0)

= 8 / 4

= 2

Now that we have the slope, we can find the y-intercept by substituting the values of one point and the slope into the equation y = mx + b and solving for b.

Using the point (0, -8):

-8 = 2(0) + b

b = -8

Therefore, the equation of the linear relationship in slope-intercept form is: y = 2x - 8. Option A is the correct answer.

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Complete Question

The complete question is shown on the first uploaded image  

Answer:

The  standard deviation is  \(\sigma = 2.45\)  

Step-by-step explanation:

From the given data we can compute the expected mean for each random values as follows

          \(E(X) = \sum [ X * P(X = x )]\\\\ X \ \ \ \ \ \ X* P(X =x )\\ 0 \ \ \ \ \ \ \ \ \ \ 0* 0.4 = 0 \\ 2 \ \ \ \ \ \ \ \ \ \ 2 * 0.3 = 0.6 \\ 4 \ \ \ \ \ \ \ \ \ \ 4 * 0.2 = 0.8\\ 6 \ \ \ \ \ \ \ \ \ \ 6* 0.1 = 0.6\)

So  

          \(E(x) = 0 + 0.6 + 0.8 + 0.6\)

          \(E(x) = 2\)

The  

             \(E(X^2) = \sum [ X^2 * P(X = x )]\\\\ X \ \ \ \ \ \ \ \ \ \ X^2 * P(X=x ) \\ 0 \ \ \ \ \ \ \ \ \ \ 0^2 * 0.4 = 0 \\ 2 \ \ \ \ \ \ \ \ \ \ 2^2 * 0.3 = 12 \\ 4 \ \ \ \ \ \ \ \ \ \ 4^2 * 0.2 = 3.2 \\ 6 \ \ \ \ \ \ \ \ \ \ 6^2 * 0.1 = 3.6\)

So  

        \(E(X^2) = 0 + 1.2 + 3.2 + 3.6\)

        \(E(X^2) = 8\)

Now  the variance is  mathematically evaluated as

         \(Var (X) = E(X^2 ) -[E(X]^2\)

Substituting value  

        \(Var (X) = 8-4\)

        \(Var (X) = 6\)

The standard deviation is mathematically evaluated as

       \(\sigma = \sqrt{Var(x)}\)

      \(\sigma = \sqrt{4}\)

      \(\sigma = 2\)

The value of the angle θ is approximately 24.2 degrees to 1 decimal place.

In a right-angled triangle, the tangent of an angle is defined as the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle. Given that tan θ = 23/52, we can find the value of the angle θ.

To find the value of θ, we can use the inverse tangent or arctan function. Taking the inverse tangent of both sides of the equation, we have:

θ = arctan(23/52)

Using a calculator or trigonometric tables, we can evaluate the inverse tangent of 23/52. The result is approximately 24.2 degrees.

Note that in the context of a right-angled triangle, the tangent function is defined for acute angles (less than 90 degrees). Since 0 degrees is the smallest possible angle, it is considered an acute angle in this case.

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You launch an object off a 55-foot cliff. If the object was launched at 85 feet/second,  64.23 feet/second long it will take for the object to hit the ground below. This can be solved using the concept of law of conservation of energy.

Three fundamental quantities all maintain their original values. Energy, momentum, and angular momentum are these. Energy is a conserved quantity, which could surprise you if you've read instances in previous pages, such the kinetic energy of charging elephants. The first law of thermodynamics, generally known as the law of conservation of energy, stipulates that the energy of a closed system must remain constant and cannot rise or fall on its own without external intervention.

Given that,

Height of the cliff, h= 55 Foot

Initial speed of the projectile, u = 85 m/s

Let, the projectile hit the ground with velocity "v"

Applying the law of conservation of energy,

mgh + 1/2 mu² = 1/2 mv²

or, m (gh + 1/2 u²) = 1/2 mv²

or, (gh + 1/2 u²) = 1/2 v²

or, 10 × 55 + (1/2 × (55)²) = 1/2 v²

or, 550 + 1512.5 = 1/2 v²

or, 2062.5 = 1/2 v²

or, 4125 = v²

or, v = 64.23 feet/second

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True for x is equal to 1 and 0 (Sometimes True)

\(( {x}^{a} )( {x}^{b} ) = {x}^{ab} \)

True for x greater than or equal to 0 (Sometimes True)

\( { \sqrt{x} }^{2} = x\)

Always True

\( { \sqrt{x} }^{ 3 } = \sqrt{ {x}^{3} } \)

True for x does not equal 0 (Sometimes True)

\( \frac{ {x}^{a} }{ {x}^{b} } = {x}^{a - b} \\ \)

Never True

\( {x}^{0} = 0\)

True for x is equal to 0 (Sometimes True)

\( {x}^{2} + {x}^{2} = {x}^{4} \)

1. We have all the information we need here to set up our 'least-squares regression equation.'

Given: r = 0.68, x = 260, y = 70, s₁ = 33, s₂ = 6, remember that the general equation for our least-squares line is in the form y = a + bx. The slope of the regression equation is the linear correlation coefficient multiplied by the standard deviation for x:

b = r(s₂ / s₁) = 0.68(6 / 33) = 0.12363...

Remember that the constant of the regression equation is the mean of y decreased by the product of the slope and the mean of x:

a = y - bx = 70 -  0.12363(260) = 37.8562

The equation of the least-squares regression line would then be y = 37.8562 + 0.12363x. We know that the Jane's previous score was 279, so if we plug that into our equation as 'x' we will receive Jane's final score. The set up will be y = 37.8562 + 0.12363(279) = 72.34897. Your solution for the first part is absolutely correct!

2. Actually the values of 'y' could have been much larger. r^2 = 0.4624, thus the proportion of y explained by x is only about 46%. It would negatively affect her final course grade.

The negations of the given statements with the application of De Morgan's law and/or conditional law.

a) ∃x (¬P(x) ∨ ¬R(x))

De Morgan's law:

∃y ∀z(¬P(y) ∧ ¬Q(z))

b) ∃y ∀z(¬P(y) ∧ ¬Q(z))

The double negation:

∃y ¬∃z(P(y) ∨ Q(z))

c) ¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))

The conditional law:

¬∃x (P(x) ∨ (∀z (¬R(z)) → (∀z ¬Q(z))))

Let's form the negation of the given statements and apply De Morgan's law and/or conditional law, when applicable:

a) ∀x (P(x) ∧ R(x))

The negation of this statement is:

∃x ¬(P(x) ∧ R(x))

Now let's apply De Morgan's law:

∃x (¬P(x) ∨ ¬R(x))

b) ∀y∃z(¬P(y) → Q(z))

The negation of this statement is:

∃y ¬∃z(¬P(y) → Q(z))

Using the conditional law, we can rewrite the negation as:

∃y ¬∃z(¬¬P(y) ∨ Q(z))

c) ∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))

The negation of this statement is:

¬∃x (P(x) ∨ (∀z (¬R(z) → ¬Q(z))))

Using the conditional law, we can rewrite the negation as:

¬∃x (P(x) ∨ (∀z (R(z) ∨ ¬Q(z))))

Applying De Morgan's law:

¬∃x (P(x) ∨ (∀z ¬(¬R(z) ∧ Q(z))))

Simplifying the double negation:

¬∃x (P(x) ∨ (∀z ¬(R(z) ∧ Q(z))))

Using De Morgan's law again:

¬∃x (P(x) ∨ (∀z (¬R(z) ∨ ¬Q(z))))

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The definite integral for this problem has the result given as follows:

\(\int_1^5 x^2 + 2x - \tan{x} dx = 212 - \ln{|\sec{5}|} + \ln{|\sec{1}|}\)

The definite integral for this problem is defined as follows:

\(\int_1^5 x^2 + 2x - \tan{x} dx\)

We have an integral of the sum, hence we can integrate each term, and then add them.

For the first two terms, applying the power rule, the integrals are given as follows:

The integral of the tangent is given as follows:

ln|sec(x)|

Then the integral is given as follows:

I = x³/3 + x² - ln|sec(x)|, from x = 1 to x = 5.

Applying the Fundamental Theorem of Calculus, the result of the integral is obtained as follows:

I = 5³/3 + 5² - ln|sec(5)| - (1³/3 + 1² - ln|sec(1)|)

I = 625/3 - 1/3 + 5 - 1 - ln|sec(5)| + ln|sec(1)|

I = 208 + 5 - 1 - ln|sec(5)| + ln|sec(1)|

I = 212 - ln|sec(5)| + ln|sec(1)|.

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The consumer surplus is approximately $145.83.

To find the consumer surplus, we first need to find the demand function's inverse, which gives us the willingness to pay for each unit of the product. The demand function is:

D(x) = √(739 - 3x)

Setting D(x) equal to the equilibrium price of $25, we get:

25 = √(739 - 3x)

Squaring both sides, we get:

625 = 739 - 3x

Solving for x, we get:

So at a price of $25 per unit, the consumer is willing to buy 38 units per month.

Now we can calculate the consumer's surplus.

The consumer\(x = (739 - 625) / 3 = 38\) surplus is the difference between the total amount that consumers are willing to pay for a certain quantity of a good and the total amount they actually pay. In this case, the consumer's surplus can be calculated as:

\(CS = \int_0^{38} [D(x) - 25] dx\)

where D(x) is the demand function, and the integral is taken over the range of 0 to 38, which represents the quantity demanded at a price of $25 per unit.

Evaluating this integral, we get:

\(CS = \int_0^{38} [\sqrt{(739 - 3x)} - 25] dx\\\\= [1/6 (739 - 3x)^{(3/2)} - 25x]_0^{38}\\\\= \$ 145.83\)

Therefore, the consumer surplus is approximately $145.83.

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The exact solutions of the Quadratic equation x^2 - 3x - 5 = 0 are:

x = (3 + √29) / 2 ,x = (3 - √29) / 2. The correct answer choice is:

x = the quantity of 3 plus or minus the square root of 29 all over 2.

The exact solutions of the quadratic equation x^2 - 3x - 5 = 0 using the quadratic formula, we can identify the values of a, b, and c, and substitute them into the formula:

a = 1

b = -3

c = -5

Now, we can apply the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values into the formula:

x = (-(−3) ± √((−3)^2 - 4(1)(−5))) / (2(1))

x = (3 ± √(9 + 20)) / 2

x = (3 ± √29) / 2

Therefore, the exact solutions of the quadratic equation x^2 - 3x - 5 = 0 are:

x = (3 + √29) / 2

x = (3 - √29) / 2

The correct answer choice is:

x = the quantity of 3 plus or minus the square root of 29 all over 2.

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On solving the provided question ,we can say that The statement "The number of new clients (x) is 149% of the number of old clients (y)" can be written mathematically as: x = 1.49y

A sequence is a grouping of "terms," or integers. Term examples are 2, 5, and 8. Some sequences can be extended indefinitely by taking advantage of a specific pattern that they exhibit. Use the sequence 2, 5, 8, and then add 3 to make it longer. Formulas exist that show where to seek for words in a sequence. A sequence (or event) in mathematics is a group of things that are arranged in some way. In that it has components (also known as elements or words), it is similar to a set. The length of the sequence is the set of all, possibly infinite, ordered items. the action of arranging two or more things in a sensible sequence.

The statement "The number of new clients (x) is 149% of the number of old clients (y)" can be written mathematically as:

x = 1.49y

-1.49y + x = 0

-149y + 100x = 0

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The linear equation in the required form is: x - 1.49y = 0

What is linear equation?

A linear equation is a mathematical equation that describes a straight line in a two-dimensional plane. It is an equation of the form:

y = mx + b

Let's start by assigning variables to the given information. We are told that "the number of new clients (x) is 149% of the number of old clients (y)."

Using this information, we can write:

x = 1.49y

To write this equation in the form ax + by = c, we need to move all the variables to one side of the equation and simplify.

Subtracting 1.49y from both sides, we get:

x - 1.49y = 0

So the linear equation in the required form is:

x - 1.49y = 0

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Airplane 1 had the fastest rate of descent during its landing.

To compare the rates of descent of the two airplanes, we need to convert both rates to a common unit of measurement. Let's convert both rates to feet per minute (ft/min) to make the comparison easier.

Airplane 1 had a rate of descent of -130 ft/s, which is equivalent to:

-130 ft/s × 60 s/min = -7800 ft/min

Airplane 2 had a rate of descent of -97/8 ft/s, which is equivalent to:

(-97/8) ft/s × 60 s/min = -729.375 ft/min

Comparing these two rates, we can see that Airplane 1 had the faster rate of descent during its landing:

-7800 ft/min (Airplane 1) > -729.375 ft/min (Airplane 2)

Therefore, Airplane 1 had the fastest rate of descent during its landing.

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Answer: 280

Step-by-step explanation:

The products of each pair of numbers are:

1 x 33 = 33

4 x 30 = 120

8 x 26 = 208

14 x 20 = 280

b. To find the pair of numbers that will produce the largest possible product, we need to look for the pair with the closest product to 340 (the square of 17, which is the average of the two numbers).

The pair of numbers with the closest product to 340 is 14 and 20, whose product is 280. Therefore, the pair of numbers that will produce the largest possible product is 14 and 20, and the product is 280.

The following elements were included in the response: labeling x-axis as age, labeling y-axis as texting speed, plotting points according to age and texting speed, and identifying a relationship between texting speed and age.

In the response, the following elements were included:

1. Labeling the x-axis as the input variable, age: This is important to indicate the independent variable being plotted.

2. Labeling the y-axis as the output variable, texting speed: This is crucial to indicate the dependent variable being represented.

3  Plotting the points according to age and texting speed: This involves placing the ordered pairs (age, texting speed) on the coordinate plane, with age values on the x-axis and texting speed values on the y-axis.

4. Identifying a relationship between the change in texting speed as age increases: By analyzing the plotted points and examining the pattern or trend, one can determine if there is a relationship between age and texting speed. For example, if the texting speed generally increases as age increases or if there is a linear or nonlinear relationship between the two variables.

Including all of these elements allows for a comprehensive analysis of the relationship between age and texting speed, providing a visual representation and enabling the identification of any patterns or trends.

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The depth of the aquarium is approximately 4 feet when rounded to the nearest whole number (since 3.64 is closer to 4 than it is to 3 when rounded to the nearest whole number).

To calculate the depth of the aquarium, we need to use the formula for volume of a rectangular prism,

which is V = lwh where V is the volume, l is the length, w is the width, and h is the height (or depth, in this case).

Given that the aquarium holds 11.35 cubic feet of water, the volume of the aquarium can be represented by V = 11.35 cubic feet.We are also given that the length of the aquarium is 2.6 feet and the width is 1.1 feet.

Substituting these values into the formula for volume,

we get:11.35 = 2.6 × 1.1 × h

Simplifying this expression:

11.35 = 2.86h

Dividing both sides by 2.6 × 1.1,

we get:h ≈ 3.64 feet (rounded to two decimal places)

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The decision of which two homework assignments to complete depends on Mofor's individual circumstances and priorities.

If Mofor only has time to do two homework assignments out of the five subjects, he will need to choose which subjects to prioritize. The specific subjects he chooses to work on will depend on various factors such as his strengths, weaknesses, upcoming deadlines, and personal preferences. Here are a few strategies he could consider:

1. Prioritize based on importance: Mofor can prioritize the homework assignments that carry more weight in terms of grades or have upcoming deadlines. This way, he ensures that he completes the assignments that have a higher impact on his overall academic performance.

2. Focus on challenging subjects: If Mofor finds certain subjects more difficult or time-consuming, he can prioritize those assignments to allocate more time and effort to them. This approach allows him to concentrate on improving his understanding and performance in subjects that require extra attention.

3. Balance workload: Mofor can choose to distribute his efforts evenly across subjects, selecting two assignments from different subjects. This strategy ensures that he maintains a balanced workload and avoids neglecting any particular subject.

The decision of which two homework assignments to complete depends on Mofor's individual circumstances and priorities. It is essential for him to consider his academic goals, time constraints, and personal strengths to make an informed decision.

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Answer:

b.) distance north or south of the equator

Step-by-step explanation:

Lines of latitude are horizontal lines parallel with the equator.

The equator is the central line of latitude, and latitude is measured north or south of the equator.

Answer: b.) distance north or south of the equator

Answer:

B

Step-by-step explanation:

lines of latitude run east-west around the globe and are used to measure distances NORTH and SOUTH of the equator

9514 1404 393

Explanation:

You can check your answer by making sure that each of the primes you found is actually a prime. (Compare to a list of known primes, for example.) After you have determined your factors are primes, multiply them together to see if the result is 73. If so, you have found the correct prime factorization.

__

Additional comment

73 is prime, so its prime factor is 73.

  73 = 73

Answer:

-20 -d

Step-by-step explanation:

-(20+d)

Distribute he minus sign

-20 -d

Hi :)

The reciprocal of 5 is 1/5.

Every number has a reciprocal except 0.

For example

5/1 is just 5 but the reciprocal of that would be 1/5.

Essentially flipping the fraction.

Answer: \(\frac{1}{5}\)

Step-by-step explanation:

Reciprocal means the multiplicative inverse of a number. It means the numerator and the denominator which their places.

Since 5 does not have a denominator, we can keep the denominator as 1. The fraction will be \(\frac{5}{1}\). Now when we switch the numerator and denominator, we will get \(\frac{1}{5}\).

Answer:

She needs 16 recipe to make 8 gallons

Answer:

Hii!

Birthday cards = 4

Thankyou cards = 7

So The answer might be

4 : 7

A) Formation of the Earth:

B) Origin of Life

C) Oxygenation of the Atmosphere

D) Formation of the Supercontinent:

E) Cambrian Explosion.

To determine which event in the history of the Earth happened first, we need to examine the chronological order of the events mentioned. Since you have not provided any specific events to compare, I will provide a few major events in Earth's history and order them accordingly:

1. Formation of the Earth: The Earth was formed approximately 4.6 billion years ago through the accretion of dust and gas in the early solar system.

2. Origin of Life: The first evidence of life on Earth dates back to around 3.5 to 4 billion years ago. This includes the emergence of single-celled organisms such as bacteria and archaea.

3. Oxygenation of the Atmosphere: Cyanobacteria, which are photosynthetic organisms, began producing oxygen as a byproduct of photosynthesis. This led to the oxygenation of Earth's atmosphere around 2.4 billion years ago.

4. Formation of the Supercontinent: Around 1.1 billion years ago, the supercontinent Rodinia began forming through the collision and merging of various landmasses.

5. Cambrian Explosion: The Cambrian Explosion, a rapid diversification of multicellular life, occurred around 541 million years ago. This event marked the emergence of a wide variety of complex animal forms.

Based on these events, we can conclude that the formation of the Earth happened first, followed by the origin of life, oxygenation of the atmosphere, formation of the supercontinent, and finally, the Cambrian Explosion.

It's important to note that these events are estimated based on scientific evidence and can have some degree of uncertainty. The precise timing and sequencing of events in Earth's history are continuously studied and refined as new discoveries are made.

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Answer:

Step-by-step explanation:

Given,

Gallon of juice drank in 5 weeks = 4

Therefore,

Gallon of juice drank in 1 week

\( = \frac{4}{5} (ans)\)

Answer:

8

Step-by-step explanation:

Answer:

d

Step-by-step explanation:

You are asking a question trying to suggest whether it can be done later