A third-degree polynomial function f has real zeros -2, 12, and 3, and its leading coefficient negative. Write an equation for f. Sketch the graph of f. How many different polynomial functions are possible for f?

Answers

Answer 1

Answer:

  f(x) = -(x +2)(x -3)(x -12)

Step-by-step explanation:

You want the equation and a graph for a third-degree polynomial function f(x) that has real zeros -2, 12, and 3, and its leading coefficient negative.

Factors

Each zero of the function corresponds to a factor of the function that has that zero. For example, the zero at x = -2 means (x +2) is a factor of f. The leading coefficient is a multiplier of all of the factors of this form.

An equation for f(x) can be written in factored form as ...

  f(x) = -(x +2)(x -3)(x -12)

Its graph is attached.

Leading coefficient

The leading coefficient is a vertical scale factor for the graph. Changing its magnitude does not change the locations of the zeros. The magnitude can be any of an infinite number of values.

There are infinitely many possible different functions for f(x).

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A Third-degree Polynomial Function F Has Real Zeros -2, 12, And 3, And Its Leading Coefficient Negative.

Related Questions

Two times the sum of 5 and some number is 30. What is the number?

Answers

Answer:

10

Step-by-step explanation:

5+10=15

15×2=30

so the answer to your question is 10

Answer:

x = 10.

Step-by-step explanation:

Given: Two times the sum of 5 and some number is 30. What is the number?

First, write the equation:

2(5 + x) = 30

Simplify the brackets with distribution property:

10 + 2x = 30

Then collect like terms:

2x = 30 - 10

Finally, calculate:

2x = 20   (Divide both sides by 2)

x = 10

10 m =_____ mm hurry pls .​

Answers

Answer:

10,000 mm

Hope that helps!

Step-by-step explanation:

Answer:

10000 mm

Step-by-step explanation:

1m = 1000mm

10 x 1000 = 10000mm

there are 55 students in a band 11 are 6th graders 21 are 7th grader and 23 are 8th graders what is the ratio of the 6th graders in the band to the number of 7th and 8th graders in the band

Answers

Answer:

11 : 44

Step-by-step explanation:

There are 11 6th graders and a combination of 44 7th and 8th graders. Therefore, the ratio is 11 : 44. Hope this helps!

Unconfined test was ran on a clay sample and the major stress at failure is 3,000 psf. What is the unconfined compression strength of the clay sample

Answers

The unconfined compression strength of the clay sample is equal to the major stress at failure, which is 3,000 psf.

To determine the unconfined compression strength of the clay sample, given that the major stress at failure is 3,000 psf, you can follow these steps:

1. Identify the major stress at failure, which is 3,000 psf in this case.

2. The unconfined compression test measures the unconfined compressive strength (UCS) of the clay sample. Since there is no lateral confinement in this test, the major stress at failure is equal to the unconfined compressive strength.


3. Therefore, the unconfined compression strength of the clay sample is 3,000 psf.

In summary, the unconfined compression strength of the clay sample is equal to the major stress at failure, which is 3,000 psf.

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Write a recursive formula for the sequence. 12,3,3​/4,3​/16,3​/64,… a1​= an​=

Answers

This recursive formula states that each term in the sequence (except for the first term) is obtained by dividing the previous term by 4.

To write a recursive formula for the sequence, we need to identify the pattern in how each term is related to the previous term.

In the given sequence, each term is obtained by dividing the previous term by 4. Starting with the first term, 12, we can express the relationship as:

a1 = 12

an = an-1 / 4

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Anybody know this answer?

Anybody know this answer?

Answers

Answer:

x = 29

Step-by-step explanation:

The sum of the 3 angles is 180 degrees since it is a straight line

x-1 + 3x+2  + 2x+5 = 180

Combine like terms

6x +6 = 180

Subtract 6 from each side

6x+6-6= 180-6

6x =174

Divide y 6

6x/6 =174/6

x = 29

Answer:

it's 29

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

please explain how to do this

please explain how to do this

Answers

Answer:

61%

Step-by-step explanation:

Area of square:

=a²

=12²

=144

Area of two quarter circles:

=2(¼×π×r²)

=2(¼×π×6²)

=2×28.72

=56.55

Finding the percentage:

=(56. 55÷144)×100

=0.3937×100

=39.27

subtract 100% by 39.27% to find the percentage of how much is shaded

=100-39.27

=60.73

=61 (rounded off to the nearest whole percent)

Good luck dawg 420 the cow jumped over the moon

a) how many vectors are in {1, 2, 3}?b) how many vectors are in col a?c) is p in col a? why or why not?

Answers

a) The set {1, 2, 3} does not represent vectors, but rather a collection of scalars. Therefore, there are no vectors in {1, 2, 3}.

b) The number of vectors in "col a" cannot be determined without additional context or information. "Col a" could refer to a column vector or a collection of vectors associated with a variable "a," but without further details, the exact number of vectors in "col a" cannot be determined.

c) Without knowing the specific context of "p" and "col a," it is impossible to determine if "p" is in "col a." The inclusion of "p" in "col a" would depend on the definition and properties of "col a" and the specific value of "p."

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another trig thing to help with

another trig thing to help with

Answers

Answer:

Step-by-step explanation:

y = 2.5  sin \(\frac{2}{3}\) x  

a = 2.5

b = \(\frac{2}{3}\)

another trig thing to help with

4x-6+x+3 what is the value of x ?

Answers

Answer: \(5x-3\)

Step-by-step explanation:

First, \(4x-6+x+3~ < --- Simplify ~the ~expression\)

\(4x+x-6+3\)

Add the numbers \(-6+3=-3\):

\(4x+x-3\)

Add similar elements \(4x+x=5x\):

\(=5x+3\)

Answer:

\(\boxed{\tt 5x−3}\)

Step-by-step explanation:

\(\tt 4x−6+x+3 \)

Combine 4x and x = 5x:-

\(\tt 5x−6+3\)

Now, Add -6 and 3 = -3:-

\(\tt 5x−3\)

- :)

if a normal distribution has mean 0 and standard deviation 1, what is the 97.5th percentile?

Answers

Therefore, the 97.5th percentile of a normal distribution with mean 0 and standard deviation 1 is 1.96.

The 97.5th percentile represents the value below which 97.5% of the data falls. In a normal distribution with mean 0 and standard deviation 1, the 97.5th percentile corresponds to a z-score of 1.96.

A z-score represents the number of standard deviations a data point is from the mean. In this case, a z-score of 1.96 means that the value corresponding to the 97.5th percentile is 1.96 standard deviations above the mean.

Using a standard normal distribution table or calculator, we can find that the area under the curve to the left of a z-score of 1.96 is 0.975. This means that 97.5% of the data falls below a z-score of 1.96.

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Three component work in series. the component fail with probabilities p1=0. 09, p2=0. 11, and p3=0. 28. What is the probability that the system will fail?

Answers

The probability that the system will fail is 1 - ((1 - 0.09) * (1 - 0.11) * (1 - 0.28)).

To find the probability that the system will fail, we need to consider that all three components fail in series.

When components are connected in series, the system fails if any one of the components fails.

Therefore, we need to calculate the probability that at least one component fails.

The probability that the first component fails (p1) is 0.09, the probability that the second component fails (p2) is 0.11, and the probability that the third component fails (p3) is 0.28.

To find the probability that at least one component fails, we can calculate the complement of the probability that all components work. In other words, we subtract the probability that all components work from 1.

The probability that all three components work is calculated by multiplying the probabilities of each component working: (1 - p1) * (1 - p2) * (1 - p3).

Therefore, the probability that the system will fail is 1 - ((1 - 0.09) * (1 - 0.11) * (1 - 0.28)).

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Using the point you found in part F, divide the final y-coordinate by the final x-coordinate. What do you think the result represents? Explain.

Answers

I tried 14,29

Step-by-step explanat IDK

hElp Me PLaesssssssssssssssssssssssssssss

hElp Me PLaesssssssssssssssssssssssssssss

Answers

I think it is the first one

Find the gradient of the line segment between the points (-3,2) and (-2,5).

Answers

Answer:

slope = 3

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 3, 2 ) and (x₂, y₂ ) = (- 2, 5 )

m = \(\frac{5-2}{-2-(-3)}\) = \(\frac{3}{-2+3}\) = \(\frac{3}{1}\) = 3

Please help, I have no clue what I’m doing

Please help, I have no clue what Im doing

Answers

Answer: x= negative 6

if thats what its asking for

Step-by-step explanation:

if a = 1 3 5 and b equals to 1 3 5 find a into B and Plot the co-ordinate in graph paper​

Answers

To find the result of multiplying vector a by vector b, we use the dot product or scalar product. The dot product of two vectors is calculated by multiplying the corresponding components and summing them up.

Given:

a = [1, 3, 5]

b = [1, 3, 5]

To find a · b, we multiply the corresponding components and sum them:

\(a . b = (1 * 1) + (3 * 3) + (5 * 5)\\ = 1 + 9 + 25\\ = 35\)

So, a · b equals 35.

Now, let's plot the coordinate (35) on a graph paper. Since the coordinate consists of only one value, we'll plot it on a one-dimensional number line.

On the number line, we mark the point corresponding to the coordinate (35). The x-axis represents the values of the coordinates.

First, we need to determine the appropriate scale for the number line. Since the coordinate is 35, we can select a scale that allows us to represent values around that range. For example, we can set a scale of 5 units per mark.

Starting from zero, we mark the point at 35 on the number line. This represents the coordinate (35).

The graph paper would show a single point labeled 35 on the number line.

Note that since the coordinate consists of only one value, it can be represented on a one-dimensional graph, such as a number line.

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An athlete ran 10 times around the circular track shown below. Approximately how many meters did the athlete run?

Answers

Answer:

Step-by-step explanation:

Since the picture isn't given. I have no idea what the radius or diameter is and as such, have no definite answer for you.

However, from the question, if he's to run round the circular track once, then he must have run a total of

2πr meters, with r being the radius.

Now, the question says that he ran round the track 10 times, this means that whatever value we get there, for 1 trial, we multiply it by 10, to get the value for 10 trials. Essentially,

10 * 2πr

The value gotten is the needed answer. All you have to do is substitute r for the value you have in your diagram. We already know that π is 3.142

find f(t). ℒ−1 1 s2 − 4s 5 f(t) =

Answers

The solutuion to the given differntial equation is: f(t) = -1/4 e^(2t) + t e^(2t) + 3/4 sin(t)

How can we factor the denominator of the fraction?

ℒ{f(t)}(s) = 1/(s^2 - 4s + 5)

We can factor the denominator of the fraction to obtain:

s^2 - 4s + 5 = (s - 2)^2 + 1

Using the partial fraction decomposition, we can write:

1/(s^2 - 4s + 5) = A/(s - 2) + B/(s - 2)^2 + C/(s^2 + 1)

Multiplying both sides by the denominator (s^2 - 4s + 5), we get:

1 = A(s - 2)(s^2 + 1) + B(s^2 + 1) + C(s - 2)^2

Setting s = 2, we get:

1 = B

Setting s = 0, we get:

1 = A(2)(1) + B(1) + C(2)^2

1 = 2A + B + 4C

Setting s = 1, we get:

1 = A(-1)(2) + B(1) + C(1 - 2)^2

1 = -2A + B + C

Solving this system of equations, we get:

A = -1/4

B = 1

C = 3/4

Therefore,

1/(s^2 - 4s + 5) = -1/4/(s - 2) + 1/(s - 2)^2 + 3/4/(s^2 + 1)

Taking the inverse Laplace transform of both sides, we get:

f(t) = -1/4 e^(2t) + t e^(2t) + 3/4 sin(t)

Therefore, the solution to the given differential equation is:

f(t) = -1/4 e^(2t) + t e^(2t) + 3/4 sin(t)

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Comparing two algorithms.

Say we have two different algorithms with respective runtimes of f(n) and g(n). Given the following cases, prove whether or not f(n) = ϴ(g(n)) is true in each case. Show your work but with the crucial steps only. P.S. sqrt(n) means the square-root of n, aka n^(½).

Case

f(n)

g(n)

A

log(n^200)

log(n^2)

B

sqrt(n)

log(n)

C

3^n

5^n

D

sin(n)+3

cos(n)+1

Answers

f(n) = ϴ(g(n)) is not true in cases B(sqrt(n)log(n), C(\(3^n 5^n\)), and D(sin(n)+3 cos(n)+1).

A) \(log(n^200) log(n^2)\)

Here, f(n) = \(log(n^200)\) and g(n) = \(log(n^2)\). Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = \([log(n^200) / log(n^2)]\) = 100

This means that as n approaches infinity, the ratio f(n) / g(n) is constant, and so we can say that f(n) = ϴ(g(n)). Therefore, f(n) = ϴ(g(n)) is true in this case.

B) sqrt(n) log(n) Here, f(n) = sqrt(n) and g(n) = log(n). Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = [sqrt(n) / log(n)]

As log(n) grows much slower than sqrt(n) as n approaches infinity, this limit approaches infinity. Therefore, we cannot say that f(n) = ϴ(g(n)) is true in this case.

C) 3^n 5^n

Here, f(n) = \(3^n\) and g(n) = \(5^n\) . Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = \([3^n / 5^n]\)

As \(3^n\) grows much slower than \(5^n\) as n approaches infinity, this limit approaches zero. Therefore, we cannot say that f(n) = ϴ(g(n)) is true in this case.

D) sin(n) + 3 cos(n) + 1

Here, f(n) = sin(n) + 3 and g(n) = cos(n) + 1. Now, if we take the limit of f(n) / g(n) as n approaches infinity, then:

f(n) / g(n) = [sin(n) + 3] / [cos(n) + 1]

As this limit oscillates between positive and negative infinity as n approaches infinity, we cannot say that f(n) = ϴ(g(n)) is true in this case.

Therefore, f(n) = ϴ(g(n)) is not true in cases B, C, and D.

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To prove triangles similar, we only need to prove corresponding angles congruent OR corresponding sides are proportional. However, with a quadrilateral we need to prove corresponding angles congruent AND corresponding sides are proportional. Explain in your own words why it takes more to prove quadrilaterals congruent. Include examples demonstrating how “just angles” or “just sides” is not enough.

Answers

Answer:

we can proove by ASA congruence or SAS congruence rule

Choose the data set where the median and mode of the set are equal.
O A. 2, 2, 2, 3, 4, 4,4
OB. 4, 8, 12, 16, 16, 20
O C. 1, 1, 11, 11
OD. 1, 1, 6, 6, 6, 8, 8

Answers

Answer: 1, 1, 6, 6, 6, 8, 8

Step-by-step explanation:

Median = 6

Mode = 6

please give me a brainliest answer

First find the median of ABCD
The median is the middle most number.
A)3
B) 12,16 sometimes teachers might left you make it 14 but let’s leave it as it is right now.
C)1,11 same explanation as B
D)6

Now find the mean of each. You find the mean by finding the average. So add up all the numbers in a possible answer and then divide by the number of numbers you added together. That’s confusing so let’s do A together. 2+2+2+3+4+4+4=21
No since I added 7 numbers together to get 21, we divide it by that many numbers. 21/7=3
A)3
B)12.6
C)6
D)5.14

Since A has the same mean and median it will be the correct answer.

Rachel is setting up tables for a party. Four of the tables are covered with red tablecloths, and
eight of the tables are covered with white tablecloths. Guests will be randomly seated at the
tables when they arrive. Each table can seat 8 guests.
What is the probability that the first guest to arrive will be seated at a table with a red
tablecloth?
A 1/2
B 1/3
C 1/4
D 1/8​

Answers

Answer:

1/3

Step-by-step explanation:

Consider the wave packet: ψ(x)=[ 2πa 2
1

] 1/2
exp[− 4a 2
(x−⟨x⟩) 2

+i ℏ
px

]. Calculate the uncertainties ⟨Δx 2
⟩=⟨( x
^
−⟨x⟩) 2
⟩ and ⟨Δp 2
⟩=⟨( p
^

−⟨p⟩) 2
⟩, where ⟨ A
^
⟩ denotes the expectation value ⟨ψ∣ A
^
∣ψ⟩ of the observable A
^
on the state ∣ψ>.

Answers

The uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ are given by the expressions ⟨Δx^2⟩ = a^2/2 and ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

To calculate the uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ for the given wave packet, we need to find the expectation values of the observables (x^ - ⟨x⟩)^2 and (p^ - ⟨p⟩)^2, respectively.

The wave packet is represented by the function ψ(x) = [2πa^2]^(1/2) exp[-4a^2(x - ⟨x⟩)^2 + iℏpx]. Here, a is a constant, ⟨x⟩ represents the expectation value of x, and p is the momentum operator.

To find ⟨Δx^2⟩, we calculate the expectation value of (x^ - ⟨x⟩)^2 with respect to ψ(x). By integrating (x - ⟨x⟩)^2 multiplied by the squared magnitude of the wave packet over all x values, we obtain the result ⟨Δx^2⟩ = a^2/2.

Similarly, to find ⟨Δp^2⟩, we calculate the expectation value of (p^ - ⟨p⟩)^2 with respect to ψ(x). Since p is the momentum operator, its expectation value is ⟨p⟩ = 0 for the given wave packet. By integrating (p^ - 0)^2 multiplied by the squared magnitude of the wave packet over all x values, we obtain the result ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

Therefore, the uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ are given by the expressions ⟨Δx^2⟩ = a^2/2 and ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

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A researcher was interested in comparing the resting pulse rate of people who exercise regularly and people who do not exercise regularly. Independent simple random samples of 16 people ages 30-40 who do not exercise regularly and 12 people ages 30-40 who do exercise regularly were selected and the resting pulse rate of each person was measured. The summary statistics are as follows. Do Not Exercise X1=72.3 s1=10.3 n1=16 Do Exercise X2=69.0 s2=8.9 n2=12 At the 2.5% significance level, do the data provide sufficient evidence to conclude that the mean resting pulse rate of people who do not exercise regularly is greater than the mean resting pulse rate of people who exercise regularly? Use the critical-value approach.

Answers

For a hypothesis testing by considering two samples related to rate of people who exercise and who do not exercise, the observed t-value < standard so, null hypothesis does not rejected and there is no evidence to support the claim.

We have a researcher who was interested in making a comparison of resting pulse rate of people who exercise regularly and who do not exercise regularly. There is two independent samples. In 1ˢᵗ sample, sample size, n₁= 16

Sample mean, \(\bar X_1\) = 72.3

Standard deviations, s₁ = 10.3

In case of second sample, sample size, n₂ = 12

Sample mean, \( \bar X_2\) = 69.0

Standard deviations, s₂ = 8.9

Level of significance = 2.5% = 0.25

Consider the null and alternative hypothesis for the test hypothesis are defined as \(H_0 : μ_1 =μ_2\)

\(H_a : μ_1 >μ_2\)

The test statistic : using t-test formula

\(t = \frac{ \bar X_1 - \bar X_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2}}}\)

\(= \frac{72.3- 69}{ \sqrt{ \frac {10.3^2}{16} + \frac{8.9^2}{12}}}\)

= 0.91

Degree of freedom, df = n1 + n2 - 2

= 16 + 12 -2 = 26

Using the t-distribution table, the critical value for t(0.025, df = 26) is equals to the 2.06. Now, the observed t-value = 0.91 is less than 2.06 ( standard t value), so, we do not reject H₀ . Hence, no evidence to support the researcher claim.

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Kelly works two jobs. She usually works at a retail store for 8 hours during the day and is paid $12.90 per hour by the store. In the evening she works at a restaurant as a manager for 4 hours and is paid $12.20 per hour. How much does she make on average per hour for the day?

Answers

Answer:

i believe its 12.55

Step-by-step explanation:

if you add both number,  12.90 and 12.20, then divide by 2.

you'll will gain the same result

Find the simple intrest on$5,000 at 6% interest for 3.5 years

Answers

Answer:1,050

Step-by-step explanation:

Find the simple intrest on$5,000 at 6% interest for 3.5 years

y=3x-4
y=2x+1
what would be the first step to solving system​

Answers

Answer:

Step one. Equate the two right hand sides to each other.

3x - 4 = 2x + 1

Step-by-step explanation:

Well one of the things you could do is graph the two equations. The intersection point is the solution to the system. We get 5,11 as the answer. I can hear you saying that's cheating, and it likely is, but it does get the answer.

The very first step without the graph is to equate each of the right hand sides to each other. That's because the left side are both ys and they have to be equal.

3x - 4 = 2x + 1                     Add 4 to both sides

3x - 4 + 4 = 2x + 1 + 4

3x = 2x + 5                         Subtract 2x from both sides

3x-2x = 2x-2x + 5              Combine

x = 5

y = 3x - 4

y = 3*5 - 4

y = 15 - 4

y = 11.

y=3x-4y=2x+1 what would be the first step to solving system

The Kennedy High School cross-country running team ran the following distances in recent practices: 3. 5 miles, 2. 5 miles, 4 miles, 3. 25 miles, 3 miles, 4 miles, and 6 miles. Find the mean and median of the team’s distances

Answers

The mean of the team’s distances is 3.75 miles. The median of the team’s distances is 3.5 miles.

To find the mean of the distances run by the Kennedy High School cross-country running team, we will first add up all the distances and then divide by the number of distances. The distances ran by the Kennedy High School cross-country running team are:

3.5 miles, 2.5 miles, 4 miles, 3.25 miles, 3 miles, 4 miles, and 6 miles adding up these distances, we get:

3.5 + 2.5 + 4 + 3.25 + 3 + 4 + 6 = 26.25

So the sum of the distances is 26.25 miles. Now, to find the mean, we will divide by the number of distances, which is 7. Therefore, the mean of the distances is: Mean = Sum of distances / Number of distances

Mean = 26.25 / 7

Mean = 3.75 miles

To find the median of the distances run by the team, we will first arrange the distances in order from smallest to largest:2.5 miles, 3 miles, 3.25 miles, 3.5 miles, 4 miles, 4 miles, 6 miles

Now, we will find the middle value. Since there are 7 distances, the middle value will be the 4th value. Counting from the left, the 4th value is 3.5 miles. Therefore, the median of the distances ran by the team is 3.5 miles.

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Determine whether the set of all pairs of real numbers (x
1

,y) with the operations (x
1

,y
1

)+(x
2

,y
2

)=(x
1

+x
2

,y
1

+y
2

) and k(x,y)=(2b,2ky) is a vector space, If it is, then verify each vector-space axiom: if not, then state all vector space axioms that fail (and show that they fail). [3 points]

Answers

The set of all pairs of real numbers (x1, y) with the operations (x1, y1) + (x2, y2) = (x1 + x2, y1 + y2) and k(x, y) = (2k, 2ky) is not a vector space.

The first axiom of a vector space is that the sum of two vectors is a vector. In this case, the sum of two vectors (x1, y1) and (x2, y2) is (x1 + x2, y1 + y2).

However, this vector does not belong to the set of all pairs of real numbers, because the second component is not necessarily a real number.

For example, if (x1, y1) = (1, 2) and (x2, y2) = (3, 4), then the sum is (4, 6), which is not a pair of real numbers.

Therefore, the set of all pairs of real numbers with the operations (x1, y1) + (x2, y2) = (x1 + x2, y1 + y2) and k(x, y) = (2k, 2ky) does not satisfy the first axiom of a vector space.

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