A tension member must be designed for a service dead load of 18 kips and a service live load of 2 kips.

Required:
a. If load and resistance factor design is used, determine the maximum factored load (required strength) and the controlling AISC load combination.
b. If allowable strength design is used, determine the maximum load (required strength) and the controlling AISC load combination.

Tech A says that unitized hubs have a wheel nut with a higher installation torque than serviceable wheel bearings. Tech B says that unitized hubs have the proper bearing end play designed into the assembly once they are torqued properly is Option C: Both a and b

When compared to manually adjusted, PreSet, or LMS hub assemblies, unitized hub assemblies often require a lot more assembly torque and special spindle nut systems.

Therefore, An essential component of the wheel assembly that connects the wheel to the axle is a wheel bearing. A metal ring is used to hold a group of steel balls (also known as ball bearings) or taper (also known as tapered bearings) together. It permits the wheel to spin easily and with little resistance.

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a. The maximum thickness of the copper nozzle is 3.3 mm

b. The maximum thickness of the steel nozzle is 0.054 mm

The question has to do with heat transfer

Heat transfer is the movement of heat energy from one body to anotrher.

Since the rate of heat loss by the gas equal rate of heat gain by the metal.

The rate of heat loss by gas is P = -hA(T - T') where

The rate of heat gain by metal is given by P' = kA(T - T")/t where

Since P = P', we have that

-hA(T - T') =  kA(T - T")/t

Making t subject of the formula, we have

t = -k(T - T")/h(T - T')

Given that for copper

Substituting the values of the variables into t, we have

t = -k(T - T")/h(T - T')

t = -378 W/m-K(540°C - 150°C)/[2 × 10⁴ W/m²-K(540°C - 2750°C)]

t = -378 W/m-K(390°C)/[2 × 10⁴ W/m²-K(-2210°C)]

t = 147420 W/m/4420 × 10⁴ W/m²

t = 147420 W/m/44200000 W/m²

t = 0.0033 m

t = 3.3 mm

So, the maximum thickness of the copper nozzle is 10.71 cm

Given that for steel

Substituting the values of the variables into t, we have

t = -k(T - T")/h(T - T')

t = -23.2 W/m-K(980°C - 150°C)/[2 × 10⁴ W/m²-K(980°C - 2750°C)]

t = -23.2 W/m-K(830°C)/[2 × 10⁴ W/m²-K(-1770°C)]

t = 19256 W/m/3540 × 10⁴ W/m²

t = 19256 W/m/35400000 W/m²

t = 0.0000544 m

t = 0.0544 mm

t ≅ 0.054 mm

So, the maximum thickness of the steel nozzle is 0.054 mm

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The principle of supply chain strategy is Segregate customers on the basis of service needs of different  groups and follow the supply chain to deliver   goods and services to the consumers profitably.

Supply chain is the group of activities performed by an organization to deliver goods and services to the consumer end.

Thus, one of the principle of supply chain strategy is separate the customers on the basis of service needs of different  groups and follow the supply chain to deliver goods and services to the consumers so that they earn profit.

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Explanation:

Road engineering is an engineering discipline branching from civil engineering that involves the planning, design, construction, operation, and maintenance of roads, bridges, and tunnels to ensure safe and effective transportation of people and goods. Road engineering became prominent towards the latter half of the 20th century after World War II. Standards of road engineering are continuously being improved. Road engineers must take into account future traffic flows, design of highway intersections/interchanges, geometric alignment and design, highway pavement materials and design, structural design of pavement thickness, and pavement maintenance.

As the flow rate increases, the extension rate also increases. This is because the flow rate determines the amount of force applied to the material, which in turn causes the material to extend or stretch. Therefore, a higher flow rate will result in a higher extension rate.

When a material is subjected to a flow or shear stress, it begins to deform or stretch, which is referred to as extension. The rate at which this extension occurs depends on several factors, including the flow rate or the rate at which the stress is applied.

As the flow rate increases, the amount of force applied to the material increases, resulting in a higher extension rate. This is because the material experiences more stress, causing its molecules to rearrange and elongate, resulting in an increased extension rate. The extension rate may continue to increase with the flow rate up to a certain point, beyond which further increases in flow rate may not lead to significant increases in extension rate.

It's important to note that the relationship between flow rate and extension rate can vary depending on the material being tested, as well as other factors such as temperature, pressure, and the presence of impurities. Understanding the relationship between flow rate and extension rate is important in various fields, including materials science, engineering, and manufacturing, where the mechanical properties of materials are critical for their successful use.

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The change in the velocity of the object will be 314.30 meters per second.

The movement of an object in relation to another observer is known as its relative velocity. It is the pace at which one object's relative location changes in relation to another object over time.

An object travels to the right with a speed of 149.5 m/s and then travels left at 164.8 m/s.

Then the velocity of the object is given as,

v = 149.50 - (-164.80)

v = 149.50 + 164.80

v = 314.3 m/s

The change in the velocity of the object will be 314.30 meters per second.

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Answer: 45

Explanation:just cuase I need to

Given the following data:

Mass of astronaut = 150-lbm.

Acceleration due to gravity on Moon = 5.48 ft/s².

Weight can be defined as the force acting on an object or a physical body due to the effect of gravity. Also, the weight of a physical object (body) is typically measured in Newton or ounces.

Mathematically, the weight force on a physical body can be calculated by using this formula:

W = mg

Where:

Substituting the given parameters into the formula, we have;

Weight = 150 × 1/32.2 × 5.48

Weight = 25.5 lbf.

A beam scale is a measuring instrument that is designed and developed to compare the masses of a physical body and as such, it's not affected by the variations in acceleration due to gravity. Therefore, the beam scale would read 150-lbf as it read on earth.

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Answer:

D

Explanation:

Because the Boat D engine looks fast

Answer:

a) 4.51 lbf-s^2/ft

b) 65.8 kg

c) 645 N

d) 23.8 lb

e) 65.8 kg

Explanation:

Weight of the man on Earth = 145 lb

a) Mass in slug is...

32.174 pound = 1 slug

145 pound = \(x\) slug

\(x\) = 145/32.174 = 4.51 lbf-s^2/ft

b) Mass in kg is...

2.205 pounds = 1 kg

145 pounds = \(x\) kg

\(x\) = 145/2.205 = 65.8 kg

c) Weight in Newton = mg

where

m is mass in kg

g is acceleration due to gravity on Earth = 9.81 m/s^2

Weight in Newton = 65.8 x 9.81 = 645 N

d) If on the moon with acceleration due to gravity of 5.30 ft/s^2,

1 m/s^2 = 3.2808 ft/s^2

\(x\) m/s^2 = 5.30 ft/s^2

\(x\) = 5.30/3.2808 = 1.6155 m/s^2

weight in Newton = mg = 65.8 x 1.6155 = 106

weight in pounds = 106/4.448 = 23.8 lb

e) The mass of the man does not change on the moon. It will therefore have the same value as his mass here on Earth

mass on the moon = 65.8 kg

SQL can be used to access customer records in a database most relevant to the campaign.

SQL (Structured Query Language) is a standardized programming language that's used to manage relational databases and perform various operations on the data in them.

SQL can be used to access customer records in a database most relevant to the campaign.

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Answer:

The person above is totally correct.

Answer:

Work is needed to overcome a resistance to the push.

how am I going to do this, I have a friend that might be able to help I will check

Answer:

is it a free point? or just a question if it is kindly respond

If one tries to solve the equation 4.1-21 by the method of separation of variables without first recognizing that the solution can be written as the sum of a steady-state solution and a transient solution, the solution is incorrect.

Separation of Variables method is a method of solving linear and homogeneous partial differential equations that are classified as first-order. It's based on the concept of separating the variables by putting them on the opposite side of the equation sign before integration.

Both of these solutions are crucial in the method of separation of variables. The transient solution is necessary because it captures the behavior of the solution when it is not in a steady state, while the steady-state solution is required because it helps in obtaining the solution by assuming that the solution is in steady state.

If one tries to solve the equation 4.1-21 by the method of separation of variables without first recognizing that the solution can be written as the sum of a steady-state solution and a transient solution, then the solution obtained is incorrect.

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Answer:

The correct option is - A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.

Explanation:

As,

Categorical syllogisms follow an "If A is part of C, then B is part of C" logic.

Conditional syllogisms follow an "If A is true, then B is true" pattern of logic.

So,

The correct option is - A categorical syllogism argues that A and B are both members of C whereas a conditional syllogism argues that if A is true then B is also true.

This is because relative humidity level increases as dry-bulb temperature decreases. This temperature is measured using a specific thermometer.

The dry-bulb temperature refers to the air temperature, which can be estimated by using a thermometer exposed to the air.

The thermometer used to measure the dry-bulb temperature must be protected from radiation and moisture (i.e., the humidity of the air).

The dry bulb temperature can be considered as ambient temperature, whereas the wet-bulb temperature measures the humidity of the air.

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Current is the rate at which electrons flow past a point in a complete electrical circuit. At its most basic, current = flow.

An ampere (AM-pir), or amp, is the international unit used for measuring current. It expresses the quantity of electrons (sometimes called "electrical charge") flowing past a point in a circuit over a given time.

A current of 1 ampere means that 1 coulomb of electrons—that's 6.24 billion billion (6.24 x 1018) electrons—is moving past a single point in a circuit in 1 second.

The calculation is similar to measuring water flow: how many gallons pass a single point in a pipe in 1 minute (gallons per minute, or GPM).

Therefore, Current is the rate at which electrons flow past a point in a complete electrical circuit. At its most basic, current = flow.

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Answer:

The answer is "\(I = 0.0085106383 \ A\)"

Explanation:

Given:

\(R= 470 \ \Omega \\\\V= 4 \ v\)

Formula:

\(\to V=IR\\\\\to I = \frac{V}{R}\\\\\)

      \(= \frac{4}{470}\\\\ = 0.0085106383 \ A\)

Answer:

drugs

Explanation:

Answer:

What is the rms value Vrms of the voltage plotted in the graph?

Express your answer in volts.

Vrms = ? V

2.

When a lamp is connected to a wall plug, theresulting circuit can be represented by a simplified AC circuit, asshown in the figure. (Part B figure) Here the lamp has been replaced by a resistor with an equivalentresistance Part B figure) Here the lamp has been replaced bya resistor with an equivalent resistance R = 120 . What is the rms value Irms of the current flowing through the circuit?

Express your answer in amperes.

Irms = ? A

3.

What is the average power Pavg dissipated in the resistor?

Express your answer in watts.

Pavg = ? W

The sexagesimal system angles for 125 is 2.18 and for 12 is 0.209

What is the sexagesimal system?

We know that 180 = π

Therefore,

(i) 125  = 125 *  π / 180

                         = 125 * 22/ 7 * 180

                         = 2750 / 1260

                          = 2.18

(ii) 180 = π

12 = 12*  π /180

   = 12* 22/ 7 *  180

    = 264/ 1260

  = 0.209

Therefore, The sexagesimal system angle for 125 is 2.18 and for 12 is 0.209.

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The answer is D, one or two datum references may be necessary to obtain the desired level of control with an orientation tolerance.

Datum references are used to establish a reference point or plane on a part, and orientation tolerances specify the allowable variation in orientation of features relative to those datum references. The number of datum references required depends on the complexity of the part and the orientation tolerances specified. In some cases, a single datum reference may be sufficient, while in others, two or more may be necessary to achieve the desired level of control. Ultimately, the number of datum references needed should be determined by the engineer or designer based on the specific requirements of the part and its intended function.

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Answer:

  $681.29

Explanation:

The amortization formula seems to apply. The monthly payment on a loan of P at rate r for t years is ...

  A = P(r/10)/(1 -(1 +r/12)^(-12t))

For the given loan parameters, the monthly payment is ...

  A = $60,000(0.065/12)/(1 -(1 +0.065/12)^(-12·10)) ≈ $681.29

The monthly payment is $681.29.

Using the following transfer functions to find the steady-state response yss(t) to the given input function f(t) the steady-state response to the input f(t) = 16 sin 5t.

(a) First, we need to find the Laplace transform of the input function f(t):

F(s) = L{f(t)} = L{10 sin 0.2t} = 10/(s^2 + 0.04)

Then, we can find the steady-state response by evaluating the transfer function at s = jω (where j = sqrt(-1) and ω is the frequency of the input signal):

T(jω) = Y(jω)/F(jω) = 10/[(10jω + 1)(4jω + 1)]

|T(jω)| = |Y(jω)/F(jω)| = 10/|10jω + 1||4jω + 1|

Phase angle of T(jω) = phase angle of 10 - phase angle of (10jω + 1) - phase angle of (4jω + 1)

At steady state, the output will have the same frequency as the input (ω = 0.2), so we can substitute ω = 0.2 in the above expressions to get:

|T(j0.2)| = 10/|2j + 1||0.8j + 1| ≈ 0.267

Phase angle of T(j0.2) = phase angle of 10 - phase angle of (2j + 1) - phase angle of (0.8j + 1) ≈ -2.06 radians

Finally, we can find the steady-state response by taking the inverse Laplace transform of T(j0.2):

yss(t) = L^-1{T(j0.2)} = 0.267 cos(0.2t - 2.06)

Therefore, the steady-state response to the input f(t) = 10 sin 0.2t is yss(t) = 0.267 cos(0.2t - 2.06).

(b) First, we need to find the Laplace transform of the input function f(t):

F(s) = L{f(t)} = L{16 sin 5t} = 16/(s^2 + 25)

Then, we can find the steady-state response by evaluating the transfer function at s = jω (where j = sqrt(-1) and ω is the frequency of the input signal):

T(jω) = Y(jω)/F(jω) = 1/(2jω^2 + 20jω + 200)

|T(jω)| = |Y(jω)/F(jω)| = 1/|2jω^2 + 20jω + 200|

Phase angle of T(jω) = phase angle of 1 - phase angle of (2jω^2 + 20jω + 200)

At steady state, the output will have the same frequency as the input (ω = 5), so we can substitute ω = 5 in the above expressions to get:

|T(j5)| = 1/|2(-25)j + 20j + 200| ≈ 0.0126

Phase angle of T(j5) = phase angle of 1 - phase angle of (2(-25)j + 20j + 200) ≈ -1.46 radians

Finally, we can find the steady-state response by taking the inverse Laplace transform of T(j5):

yss(t) = L^-1{T(j5)} = 0.0126 cos(5t - 1.46)

Therefore, the steady-state response to the input f(t) = 16 sin 5t.

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To complete the algorithm, the missing steps 3 and 4 should iterate through the list until the end is reached. This can be achieved with a loop. Here is a possible solution:

Step 3: while position is less than or equal to n, repeat steps 4 and 5.
Step 4: increase the value of position by 1.
Step 5: if the value of the element at index position is greater than 100, increase the value of count by 1.
This revised algorithm will go through each element in the list and count the number of elements with a value greater than 100. The loop in steps 3-5 ensures that all elements are considered.
It is worth noting that there are other ways to implement this algorithm, such as using a for loop or a foreach loop, but the core logic remains the same: iterate through the list and count the elements that meet a certain condition.To complete the algorithm that counts the number of elements in a list with values greater than 100, you can replace steps 3 and 4 with the following:
Step 3: Increase the value of position by 1.
Step 4: If position is less than or equal to n, go back to step 2.
So, the complete algorithm is as follows:
1. Set count to 0 and position to 1.
2. If the value of the element at index position is greater than 100, increase the value of count by 1.
3. Increase the value of position by 1.
4. If position is less than or equal to n, go back to step 2.
5. Display the value of count.

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The received power if the effective aperture area of the receiving antenna is 20 m2 is 177.77 m2.

In physics, power is referred to as the rate of energy conversion or transfer over time. The unit of power in the SI system, often known as the International System of Units, is the Watt (W). A single joule per second is one watt.

Power was formerly referred to as activity in some research. A scalar quantity is power. As power is always a function of labor done, it follows that if a person's output varies during the day depending on the time of day, so will his power.

A measure of the pace at which energy is transferred, power is a physical quantity. As a result, it can be described as the pace of job completion relative to time.

Therefore, The received power if the effective aperture area of the receiving antenna is 20 m2 is 177.77 m2.

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Bimetal thermometers should be calibrated at least once a year or whenever readings are suspect.

A bimetal thermometer should be calibrated at least once a year, or whenever readings are suspect. This is important because bimetal thermometers are made up of two strips of different metals that contract and expand in response to changes in temperature. Over time, the bimetallic strips can become misaligned, resulting in inaccurate temperature readings.

To ensure accuracy, bimetal thermometers need to be calibrated by a professional. During the calibration process, the thermometer is compared to a reference thermometer and adjusted accordingly to bring it back to its original accuracy.

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Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source.

Engineering controls are a type of hazard control that reduces or eliminates the hazard at its source. Engineering controls are used to minimize or eliminate hazards that pose a significant risk of harm or danger to individuals, such as chemical or noise exposure.

These measures are frequently a vital component of an effective occupational health and safety program in the workplace. Examples of engineering controls include the use of ventilation to control fumes, dust, and other airborne hazards, as well as the use of sound barriers to reduce noise levels. In addition, the use of machine guards, interlocks, and other safety devices on equipment and machinery is considered a form of engineering control to safeguard workers from contact with hazardous moving parts.

Other types of engineering controls include changes in the manufacturing process or the substitution of less harmful materials to eliminate the hazard. Engineering controls are an essential element of hazard control in the workplace, providing a means of minimizing or eliminating hazards at their source. These controls, when combined with other forms of hazard control, such as administrative and personal protective equipment, provide a comprehensive approach to worker safety and health.

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Answer:

The answer is below

Explanation:

\(\theta_1=cos^{-1}0.28=73.74^o\ lagging\\\\S_1=125\angle 73.74^o=35\ kW+j120\ kVAR\\\\S_2=10\ kW-j40\ kVAR\\\\S_3=15\ kW\)

Total power = P = 35 kW + 10 kW + 15 kW = 60 kW

Total kVAR = 120 kVAR - 40 kVAR = 80 kVAR

\(Total\ apparent \ power =S= S_1+S_2+S_3=(35+j120)+(10-j40)+(15)\\\\S=60\ kW+j80\ kVAR=100\angle 53.13^o\\\\Current(I)=\frac{S^*}{V^*} \frac{100000\angle -53.13^o}{1400\angle0}=71.43\angle-53.13^o\\ \\Power\ factor (PF)=cos(53.13)=0.6\ lagging\\\\The \ new\ power\ factor\ is\ to \ be\ 0.8[cos^{-1}0.8=36.87^o], hence\ since\ the\ total\ \\real\ power(P)= 60\ kW, the\ capacitor\ kVAR(Q_c)\ is:\\\\Q_c=60tan(53.13)-60tan(36.87)=80-45=35\ kVAR\\\\\)

\(C=\frac{Q_c}{wV^2} =\frac{35000\ VAR}{2\pi*60\ Hz*1400\ V}=47.38\ \mu f\)

New current (I') = \(\frac{S'^*}{V^*}=\frac{60000-j45000}{1400}=53.57\angle-36.87^o\)

Current reduce from 71.43 A to 53.57 A