Solve for xxx. 12x+7 4012x+7 4012, x, plus, 7, is less than, minus, 11, start color #ed5fa6, start text, space, O, R, space, end text, end color #ed5fa6, 5, x, minus, 8, is greater than, 40 Choose 1 answer: Choose 1 answer: (Choice A) A x \dfrac{48}{5}x> 5 48 x, is greater than, start fraction, 48, divided by, 5, end fraction (Choice B) B -\dfrac32 \dfrac32x> 2 3 x, is greater than, start fraction, 3, divided by, 2, end fraction or x<\dfrac{48}{5}x< 5 48 x, is less than, start fraction, 48, divided by, 5, end fraction (Choice D) D There are no solutions
Answer:
x < -3/2 and x>48/5Step-by-step explanation:
Given the inequality function 12x+7< -11 and 5x-8>40, we are to solve for the value of x. To solve for x, the following steps must be followed.
For the inequality 12x+7< -11
Step 1: Subtract 7 from both sides of the inequality
12x+7-7< -11-7
12x < -18
Step 2: Divide both sides of the inequality by 12
12x/12 < -18/12
x < -3/2 .............. 1
For the inequality 5x-8> 40;
Step 1: Add 8 to both sides of the inequality
5x-8+8 > 40+8
5x > 48
Step 2: Divide both sides of the inequality by 5
5x/5 > 48/5
x>48/5....... 2
Combining equation 1 and 2, we will have;
x < -3/2 and x>48/5
If x>48/5 then 48/5<x
Combining 48/5<x with x < -3/2 will give 48/5<x<-3/2
Answer:
there are no soulutions
Step-by-step explanation:
Given the equation of a circle, identify the center and the radius by completing the square.
x² + y² - 32x+24y +396 = 0
Center:
Radius:
The center and the radius by completing the square of the given equation of circle is x² + y² - 32x+24y +396 = 0 is C( -16, 12) and radius is 2.
The equation of the circle is given as x² + y² - 32x+24y +396 = 0.
Comparing the given equation with general equation of circle, x² + y² + 2gx + 2fy + c = 0.
The center of circle is C = (-g, -f)
The radius of circle is r = √g² + f² - c
Therefore, from the given equation,
2g = -32
g = -16
2f = 24
f = 12
C( -16, 12)
And the radius is
r = √(-16)² + (12)² - 396
= √256 + 144 -396
=√4
= 2
Hence, the center and the radius by completing the square of the given equation of circle is x² + y² - 32x+24y +396 = 0 is C( -16, 12) and radius is 2.
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please help!!!!!!!!!!!!!
Answer:-3
Step-by-step explanation: -3 because when you do it I really don't know how to explain it srry
helppp!! ill give 100 points
The two-way relative frequency table should look like
play a sport Not play a sport Total
Honor Roll 10% 10% 20%
Not Honor Roll 30% 50% 80%
Total 40% 60% 100%
What is a two-way relative frequency table?A two-way relative frequency table is a table that shows the relative frequency distribution of two category variables.
The table tells us how frequent each the combination of categories for the two variables happens when we look at the total percentage.
Looking at the table, we were total that only 20% of the student surveyed are on the honor roll, and we were also told that 10% of student survey play sport and are in the honor roll. This means that additional 10% of student that don't play sport are on the honor roll too.
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answer for brainlest and 25 points
Answer:
Order from greatest to least: 10.5, \(3\pi +1\), \(\sqrt{105}\)
Step-by-step explanation:
step 1 simplify each number
3π + 1 = 10.4247779
*round to the nearest tenth*
3π + 1 = 10.4
\(\sqrt{105} =10.2469507\)
*round to the nearest tenth*
\(\sqrt{105} =10.2\)
10.5 = 10.5
Now that we have simplified each number we can easily put them in order from greatest to least
10.5 is the greatest number
10.4 is the middle number
10.2 is the lowest number
so 10.5, 10.4, 10.2
Now we put them back in the original form
10.5 = 10.5
10.4 = 3π + 1
10.2 = \(\sqrt{105}\)
Your answer is
10.5 , 3\(\pi\) + 1, \(\sqrt{105}\)
A yard cleanup service charges a $254 fee plus $19. 25 per hour. Another cleanup service charges a $133 fee plus $24. 75 per hour. How long is a job for which the two companies' costs are the same?
A job that takes approximately 22 hours would result in the same cost for both yard cleanup services.
To determine when the two yard cleanup services have the same cost, you'll need to set up an equation using the given fees and hourly rates
. For the first service, the cost is $254 (fee) + $19.25 per hour (rate).
For the second service, the cost is $133 (fee) + $24.75 per hour (rate).
Let x represent the number of hours for the job.
The equation would be: 254 + 19.25x = 133 + 24.75x
To solve for x, subtract 19.25x from both sides and simplify: 121 = 5.5x
Now, divide both sides by 5.5 to find the number of hours: x ≈ 22 hours
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Solve for the missing side y
12
8
y
The missing side is 6√13 in the given right-angled triangle.
What is right-angled triangle?If one of a triangle's angles is a right angle (90 degrees), the triangle is known as a right-angled triangle or just a right triangle, according to the definition of a right triangle. Triangle ABC is a right triangle that contains the base, altitude, and hypotenuse in the example image.
Base AB, altitude AC, and hypotenuse BC are shown in this equation. The largest side and the side that faces away from the right angle in a right triangle is the hypotenuse, and it is this side that is significant.
Given that A right angle triangle has sides 12cm and 18 cm
y = \(\sqrt{12^2 + 18^2}\)
y = 6√13
Thus, the missing side y is 6√13.
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What is the length of the segment indicated by the question mark
Check the picture below.
\(\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2 \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{6.6+x}\\ a=\stackrel{adjacent}{6.6}\\ o=\stackrel{opposite}{8.8} \end{cases} \\\\\\ (6.6+x)^2= (6.6)^2 + (8.8)^2\implies (6.6+x)^2=121\implies (6.6+x)^2=11^2 \\\\\\ 6.6+x=11\implies x=4.4\)
help ASAP I will Mark brainliest
Answer:
g=-4/5
Step-by-step explanation:
-25/32g=5/8
-200g=160
g=-4/5
Answer:
the answer is g= -4/5 if u want decimal form its g=-0.8
Minimize f(x)=2x2 1-2 x1 x 2+2x2-6 x 1 +6
Subject to: x1+x2-2=0
Using the Lagrange multipliers technique. Compute the optimal point values for x1, x2, l y ll
In an optimization problem with equality constraints, what is the meaning of the values of the Lagrange multipliers?
The optimal point values for x1, x2, λ, and μ (Lagrange multipliers) in the given problem are:
x1 = 1
x2 = 1
λ = -4
μ = 2
To solve the optimization problem using the Lagrange multipliers technique, we first construct the Lagrangian function L(x1, x2, λ) by incorporating the equality constraint:
L(x1, x2, λ) = f(x1, x2) - λ(g(x1, x2))
Where f(x1, x2) is the objective function, g(x1, x2) is the equality constraint, and λ is the Lagrange multiplier.
In this case, the objective function is f(x1, x2) = 2x1^2 - 2x1x2 + 2x2 - 6x1 + 6, and the equality constraint is g(x1, x2) = x1 + x2 - 2.
The Lagrangian function becomes:
L(x1, x2, λ) = 2x1^2 - 2x1x2 + 2x2 - 6x1 + 6 - λ(x1 + x2 - 2)
To find the optimal values, we need to find the critical points by taking partial derivatives of L with respect to x1, x2, and λ and setting them equal to zero. Solving these equations simultaneously, we get:
∂L/∂x1 = 4x1 - 2x2 - 6 - λ = 0
∂L/∂x2 = -2x1 + 2 + λ = 0
∂L/∂λ = -(x1 + x2 - 2) = 0
Solving these equations, we find x1 = 1, x2 = 1, and λ = -4. Substituting these values into the equality constraint, we can solve for μ:
x1 + x2 - 2 = 1 + 1 - 2 = 0
Therefore, μ = 2.
The optimal point values for the variables in the optimization problem are x1 = 1, x2 = 1, λ = -4, and μ = 2. The Lagrange multipliers λ and μ represent the rates of change of the objective function and the equality constraint, respectively, with respect to the variables. They provide insights into the sensitivity of the objective function to changes in the constraints and can indicate the impact of relaxing or tightening the constraints on the optimal solution. In this case, the Lagrange multiplier λ of -4 indicates that a small increase in the equality constraint (x1 + x2 - 2) would result in a decrease in the objective function value. The Lagrange multiplier μ of 2 indicates the shadow price or the marginal cost of satisfying the equality constraint.
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The Sugar Sweet Company is going to transport its sugar to market. It will cost $5000 to rent trucks, and it will cost an additional $200 for each ton of sugar transported. Let C represent the total cost (in dollars), and let S represent the amount of sugar (in tons) transported. Write an equation relating C to S, and then graph your equation using the axes below.
The linear function relating the variables C and S is given as follows:
C(S) = 5000 + 200S.
The graph of the linear function is given by the image at the end of the answer.
How to define the linear function?The linear function in this problem is defined in the slope-intercept as follows:
y = mx + b.
In which the coefficients of the function are defined as follows:
m is the slope, representing the rate of change of the output y relative to the input x.b is the y-intercept, representing the initial value of the output y.In the context of this problem, the variables are given as follows:
Output: Cost.Input: Tons of Sugar.It will cost $5000 to rent trucks, hence the intercept is of:
b = 5000.
It will cost an additional $200 for each ton of sugar transported, hence the slope is of:
m = 200.
Then the equation is defined as follows:
C(S) = 5000 + 200S.
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1 in = 2.45 how many centimeters equal 13 in
Answer:
33.02 cm in 13inches
Step-by-step explanation:
justin went to the track at bobcat stadium and performed the 1.5-mile run test to estimate his vo2max. he completed 1.5 miles in 11 minutes and 25 seconds. what is his estimated vo2max? round your answer to the first decimal place.
3Justin's estimated Vo2 max is 25.8(mL*kg*min)
What is Vo2 max ?
The amount (volume) of oxygen used by your body while exercising as hard as you can is referred to as VO2 max. It's a common tool for determining your level of fitness. Knowing your VO2 max can assist you in training for sports, tracking fitness progress, and improving your heart health.
Here using vo2 max fomula 1.5 miles ,
=> VO2 max = 3.5+483/Time
Here Time= 11 min 25 sec = 25/60 = 0.41 min
Then time=11.42 mins. Now,
=> VO2 max = 3.5+ 483/11.41
=> VO2 max = 3.5+42.3
=>VO2 max = 25.8(mL*kg*min)
Hence His estimated Vo2 max is 25.8(mL*kg*min)
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the diagonal of a square is 10 inches long. what is the length, in inches, of each side of the square? write the answer in simplified radical form.
if length of the diagonal is 10 inch then the side will be 5\(\sqrt{2}\) ,
we came to this conclusion by using Pythagoras theorem.
in a square the diagonal intersect each other at right angle so we can apply Pythagoras theorem.
Given right triangle ABC with a=50, and m
Answer:
A=50 B=40 C=90
Step-by-step explanation:
B is a right angle so its automatically 90 degrees since A=50 and a triangle has to be 180 degrees 90+50= 140, 180-140=40.
In a game show, players play multiple Rounds to score points. Each round has five times as many points available as the previous round.
Gingy started out with 40 gumdrop buttons. Every time
he did not answer Lord Farquard's questions correctly,
gumdrop buttons are taken away from his starting
value. If he did not answer 10 questions correctly and
20 gumdrop buttons were deducted in total, how many
gumdrops did Lord Farquad take for each incorrect
question?
on a number line, the directed line segment from Q to S has endpoints at -2 and S at 6. point R partitions the directed line segment from Q to S in the 3:2 ratio. rachel use the section formula to find the location of point R on the number line. her work is shown below. let m = 3, n = 2, x1 =-2, and x2 = 6. what is the location of point R on the number line?
Answer:
[3/3+5](2-(-14))+(-14)
Step-by-step explanation:
3:5 Ratio means that the m/m+n would be 3/3+5.
Then X2 is 2 and X1 is -14.
X2-X1 is 2-(-14)
The point(0, 0) is a solution to which inequality?*
O y-9<3x - 10
Oy - 9> 3x + 10
O y-9> 3x - 10
O y + 9 > 3x + 10
what’s is 63 fl oz;7 c; and 1.5 qt from least to greatest
Step-by-step explanation:
explain what 7 c is please and I'll write the answer in the comments:))
1. In a radical engine the moving parts have a total moment of inertia of 1 kg m 2
, and this is concentrated in the plane of the single crankpin. The engine is directly connected to an air-screw of moment of inertia 18 kg m 2
, by a hollow shaft having outer and inner diameters of 80 mm, and 35 mm, and a single effective length of 0.30 m. The stiffness of the crank-throw alone is 2.5×10 4
Nm/rad. Estimate the natural frequency of torsional vibration of the custen What percentage is involved if the air-screw mass is assumed to be infinite. G=83000 N/mm 2
HINT The stiffness of the crank-throw may be reduced to an equivalent length of shaft at the same diameter as the engine using q
1
= q 1
1
+ q 2
1
The percentage change in frequency is 0%.Hence, the natural frequency of torsional vibration of the custen is given by f = 25.7 / L₀^(1/2) and the percentage change in frequency is 0%.
We are given that:
Total moment of inertia of moving parts = I = 1 kgm²
Moment of inertia of air-screw = I = 18 kgm²
Outer diameter of hollow shaft = D₀ = 80 mm
Inner diameter of hollow shaft = Dᵢ = 35 mm
Length of hollow shaft = L = 0.30 m
Stiffness of the crank-throw = K = 2.5 × 10⁴ Nm/rad
Shear modulus of elasticity = G = 83000 N/mm²
We need to calculate the natural frequency of torsional vibration of the custen.
The formula for natural frequency of torsional vibration is: f = (1/2π) [(K/L) (J/GD)]^(1/2)
Where, J = Polar moment of inertia
J = (π/32) (D₀⁴ - Dᵢ⁴)
The formula for equivalent length of hollow shaft is given by:
q₁ = q₁₁ + q₁₂
Where, q₁₁ = (π/32) (D₀⁴ - Dᵢ⁴) / L₁q₁₂ = (π/64) (D₀⁴ - Dᵢ⁴) / L₂
L₁ = length of outer diameter
L₂ = length of inner diameter
For the given shaft, L₁ + L₂ = L
Let L₁ = L₀D₀ = D = 80 mm
Dᵢ = d = 35 mm
So, L₂ = L - L₁= 0.3 - L₀...(1)
For the given crank-throw, q₁ = (π/32) (D⁴ - d⁴) / L, where D = 80 mm and d = 80 mm
Hence, q₁ = (π/32) (80⁴ - 35⁴) / L
Therefore, q₁ = (π/32) (80⁴ - 35⁴) / L₀...(2)
From the formula for natural frequency of torsional vibration, f = (1/2π) [(K/L) (J/GD)]^(1/2)
Substituting the values of K, J, G, D and L from above, f = (1/2π) [(2.5 × 10⁴ Nm/rad) / (L₀) ((π/32) (80⁴ - 35⁴) / (83000 N/mm² (80 mm)³))]^(1/2)f = (1/2π) [(2.5 × 10⁴ Nm/rad) / (L₀) (18.12)]^(1/2)f = 25.7 / L₀^(1/2)...(3)
Now, if we assume that the air-screw mass is infinite, then the moment of inertia of the air-screw is infinite.
Therefore, the formula for natural frequency of torsional vibration in this case is:
f = (1/2π) [(K/L) (J/GD)]^(1/2)Substituting I = ∞ in the above formula, we get:
f = (1/2π) [(K/L) (J/GD + J/∞)]^(1/2)f = (1/2π) [(K/L) (J/GD)]^(1/2)f = 25.7 / L₀^(1/2)
So, in this case also the frequency is the same.
Therefore, the percentage change in frequency is 0%.Hence, the natural frequency of torsional vibration of the custen is given by f = 25.7 / L₀^(1/2) and the percentage change in frequency is 0%.
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Two customers went to a post office to buy postcards and large envelopes. Each postcard costs the same amount, and each large envelope costs the same amount.
The first customer paid $13.88 for 17 postcards and 4 large envelopes.
The second customer paid $23.60 for 10 postcards and 12 large envelopes.
What were the cost in dollars and cents for each large envelope?
each large envelope costs $1.60.
What did we do?
Let's represent the cost of a postcard by "p" and the cost of a large envelope by "e".
From the information given, we can create a system of equations:
17p + 4e = 13.88 (equation 1)
10p + 12e = 23.60 (equation 2)
To solve for "e", we can use the method of elimination.
First, let's multiply equation 1 by 3:
51p + 12e = 41.64 (equation 3)
Now, we can subtract equation 3 from equation 2:
10p + 12e = 23.60
-(51p + 12e = 41.64)
-41p = -18.04
Dividing both sides by -41, we get:
p = 0.44
Substituting this value into equation 1:
17(0.44) + 4e = 13.88
7.48 + 4e = 13.88
4e = 6.4
Therefore, the cost of each large envelope is:
e = 6.4/4 = 1.6
So each large envelope costs $1.60.
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if f(x)= -x^2-3x+5, find f(-3)
Answer:
5
Step-by-step explanation:
-9-(-9)+5=5
i really need help with these questions, i don’t even have a clue how to do these.
Answer:
231
Step-by-step explanation:
because the whole circle has an area of 360 so on the right side there is half and a little more so you would cut it in half so you have 180 and on the right side you still have a little left so thats about 10 so now you have 190 then you add 21 +20 you have 41 +190 =231 hope this helps
In the rhombus below, AC = 14 cm and BC = 25 cm. Find the area
In order to calculate the area of the rhombus, first let's draw the diagonal BD.
This diagonal and the diagonal AC will intersect at point M, which is the midpoint of each diagonal.
Since M is midpoint of AC, we have AM = MC = 7 cm.
Now, let's calculate the length of BM, using the Pythagorean theorem in the right triangle BMC:
\(\begin{gathered} BC^2=BM^2+MC^2\\ \\ 25^2=BM^2+7^2\\ \\ BM^2=625-49\\ \\ BM^2=576\\ \\ BM=24 \end{gathered}\)Calculating the area of this triangle, we have:
\(\begin{gathered} A=\frac{MC\cdot BM}{2}\\ \\ A=\frac{7\cdot24}{2}\\ \\ A=84\text{ cm^^b2} \end{gathered}\)The triangles BMC, BMA, DMC and DMA are all congruent, so the area of the rhombus is:
\(A_{rhombus}=4\cdot84=336\text{ cm^^b2}\)What is the rounded average of the test grades: 98, 100, 100, 79, 85, 79, 83?
2
90%
87%
89%
88%
Answer:
Step-by-step explanation:
Average = sum of number/total number
Given 07 number are= 98, 100, 100, 79, 85, 79, 83
average=98+100+100+79+85+79+83/7=89
Grounded average=89% answer
shopkeeper sells tins of the same dog food in packs of four or packs of six.
Packs of four tins cost £1. Packs of six tins cost £1.20
Which is the best value for money?
You must show your working.
Answer:
Pack of 6
Step-by-step explanation:
Pack of 4 = £1
Packs of 6 = £1.20
Price per unit of each pack:
Pack of 4 ;
Unit price : cost / units
Unit price = £1 / 4 = £0.25
Pack of 6 ;
Unit price : cost / units
Unit price = £1.20 / 6 = £0.20
Pack of 6 is the best value for money as it has a lower unit price
T.L Hanna High School’s theatre department is putting on their annual play. Tickets (t) are $12 each. Parking is $5 flat. You and your family attend the play and pay a total of $53. How many tickets did your family purchase?
Answer:
No. of ticket bought is 4
Step-by-step explanation:
Let the no. of ticket bought be x
Given cost of 1 ticket = $12
Therefore cost x ticket = x*cost of 1 ticket = x*$12 = $12x
parking fee = $5
given that it is flat so, whatever be the no. of ticket bought or family member,
the parking cost will remain $5 only.
Total money paid by family = parking charge + cost x ticket = 5+12x
But , given that family paid total of $53
then
5 + 12x = 53
=> 12x = 53-5 = 48
=> x = 48/12 = 4
Thus, no. of ticket bought is 4.
This can be validated as shown below
cost of 4 ticket as 12 each will be = 12*4 = 48
thus total money paid = $(48+5 )= $53
What are the steps to solve 5x+7+3x-4=?
Answer:
x= -3 / 8
Step-by-step explanation:
5x+7+3x-4=0
Sum 5x and 3x
8x+7-4=0
Subtract 7-4
8x+3=0
Move the constant to the other side and change his symbol with his opposite
8x=-3
8 is multiplying x, the opposite of multiplying is dividing, so it divide the -3 (under it)
x= -3 / 8
Evaluate the following expression: (show work)
3x^2 – 4^3 – 4^3 – z
If x =3, y =–2 and z=-5