Answer:
the time taken t is 9.25 minutes
Explanation:
Given the data in the question;
The initial charge on the supercapacitor = 2.1 × 10³ mV = 2.1 V
now, every minute, the charge lost is 9.9 %
so we need to find the time for which the charge drops below 800 mV or 0.8 V
to get the time, we can use the formula for compound interest in basic mathematics;
A = P × ( (1 - r/100 )ⁿ
where A IS 0.8, P is 2.1, r is 9.9
so we substitute
0.8 = 2.1 × ( 1 - 0.099 )ⁿ
0.8/2.1 = 0.901ⁿ
0.901ⁿ = 0.381
n = 9.25 minutes
Therefore, the time taken t is 9.25 minutes
3. A change in _____ indicates the acceleration of an object.
!!WILL MARK BRAINLIEST!! Please help
Answer:
17. A
18. C
Explanation:
np:) and have a wonderful day
Very large forces are produced in joints when a person jumps from some height to the ground. (a) Calculate the magnitude of the force (in N) produced if a 62.0 kg person jumps from a 0.800 m-high ledge and lands stiffly, compressing joint material 1.50 cm as a result. (Be certain to include the weight of the person.) N (b) In practice the knees bend almost involuntarily to help extend the distance over which you stop. Calculate the magnitude of the force (in N) produced if the stopping distance is 0.300 m. N (c) Compare both forces with the weight of the person.
Answer:
a) F = 3.3 10⁴ N, b) F = 2.2 10³ N, c) force when rigid is 15 times greater than when bending the knees
Explanation:
For this exercise we can use the relationship between work and the variation of kinetic energy
K₀ = ½ m v²
the final kinetic energy is zero because the person is stationary
W = (∑ F) x
W = W x - F w
the weight is in the same direction of the displacement therefore the work is positive and the force applied, by the floor, is in the opposite direction to the displacement, consequently the work is negative
we substitute
( W- F ) x = 0-K₀
F = W + K₀ /x
F = mg + \(\frac{1}{2} \frac{mv^2 }{2x}\)
F = m ( g+ \(\frac{v^2 }{2x }\) )
Let's use kinematics to find the velocity of the person when reaching the floor
v² = v₀² - 2g (y + y₀)
the initial velocity is true and when reaching the ground y = 0
v² = -2 g (0-yo)
we calculate
v = \(\sqrt{2 ] 9.8 \ 0.800}\)
v = - 3.96 m/s
the direction of this velocity is vertical down
let's calculate
a) x = 1.50 cm = 0.0150 m
F = 62.0 (3.96² / 2 0.0150 + 9.8)
F = 3.3 10⁴ N
b) x = 30 cm = 0.30 m
F = 62.0 (3.96² / 2 0.30 + 9.8)
F = 2.2 10³ N
c) to compare the force let's look for the relationship between the two
\(\frac{F_{rigid} }{ F_{flexible} }\) = 3.3 10⁴ / 2.2 10³
\frac{F_{rigid} }{ F_{flexible} } = 15
therefore see that the force when rigid is 15 times greater than when bending the knees
What is true about the requirements of your academic care plan
Care plans are a technique to approach academic tasks strategically and make them run more quickly. They also make it possible for an academic team to communicate effectively.
A nursing care plan's goal is to list the patient's needs, preferences, and the nursing interventions (or implementations) that are planned to address those goals.
The care plan is intended to guarantee continuity of care and is kept as a part of the patient's medical file.
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Electric field inside a charged rubber balloon is maximum or zero?
A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
When light travels through a small hole, it appears to be an observer that the light spreads out, blurring the outline of the hole. Does this observation support the theory of light as a wave, or light being made of particles? Explain.
Answer:
support lights as a wave
Explanation:
In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.
In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate the greatest?
Answer:
Volume flow rate is the same in both sections of the pipe
Explanation:
Which of the following statements best support the claim that human actions decreased the whooping crane population? (1
The sharp decline of Burmese pythons, a predator to the whooping crane, have occurred in areas with high whooping crane populations-
o Other bird species such as the California Condor have been placed on the endangered species list.
The Migratory Bird Treaty Act, signed by Congress, has made hunting whopping cranes illegal.
O The draining of wetlands to build housing, farm, and look for oil and gas has led to the loss of habitats.
Answer:
D
Explanation:
A is incorrect because it would actually increase the population...
B is incorrect because other birds do not matter, it is only whooping cranes...
C is incorrect because it would also increase the population.
If you drop an egg off of the Empire State Building, which of the following things will happen first?
O The egg will appear to hover
O Gravity and drag will fall into balance
O Drag will increase
O The net force will be zero
**NEED USEFUL ANSWER ASAP, H.W QUESTION**
Given that hotter blackbodies produce more energy than cooler blackbodies, why do cooler red giants have much higher luminosities than much hotter white dwarfs?
Given that hotter blackbodies produce more energy than cooler blackbodies, cooler red giants have much higher luminosities than much hotter white dwarfs.
The hotter blackbodies emits more light as compared to the cooler blackbodies over all the wavelength. A blackbody emits light over all wavelength. the red giant is a star , hydrogen is fused to helium core to stat the fusion reactions. this hydrogen fusion caused the star to expand. the sun becomes red giant it will swell up to size of earth orbit. This gives a red color and make red giant much hotter. while the white dwarf comes after the red giant . white dwarf is also very hot but it is not hot enough to star fusion reaction in carbon and oxygen.
Thus, Given that hotter blackbodies produce more energy than cooler blackbodies, cooler red giants have much higher luminosities than much hotter white dwarfs.
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A boat on a river is moving with a steady speed. The engine is running.
What would happen if the engine was turned off?
If the engine of a boat on a river is turned off while the boat is moving with a steady speed, several things would happen Loss of propulsion,Drifting,Loss of steering control and Potential hazards.
Loss of propulsion: Without the engine running, the boat would lose its power source for propulsion. The boat would gradually slow down and eventually come to a stop unless other external forces, such as currents or wind, continue to move it.
Drifting: Once the boat comes to a stop, it would start to drift with the current of the river or be affected by wind forces. The direction and speed of the drift would depend on the strength and direction of the current or wind.
Loss of steering control: When the engine is turned off, the boat's steering mechanism, such as a rudder, would also lose power. Without the ability to steer, the boat would follow the course determined by the river's current or the wind direction.
Potential hazards: Depending on the surroundings and the current conditions, there could be potential hazards for a boat that is no longer under power. These hazards might include other vessels, obstacles, shallow areas, or strong currents. The boat's crew would need to take appropriate actions to ensure the safety of the boat and its occupants.
It's important to note that the specific behavior of the boat after the engine is turned off can vary depending on factors such as the size and design of the boat, the strength and direction of the current, and the presence of wind or other external forces.
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Can anyone please help me
To solve this problem, we can use Coulomb's law, which states that the electric force between two point charges is proportional to the product of their charges and inversely proportional to the square of the distance between them.
We can then use the electric force to find the electric field at the location of q3 and the initial acceleration of q3.
a) To find the electric field at the location of q3, we can first find the electric force on q3 due to q1 and q2 and then use the definition of the electric field, which is the electric force per unit charge. The electric force on q³ due to q¹ and q² is:
F1 = k x q¹ x q³/ r1²
F2 = k x q² x q³ / r2²
where r¹ and r² are the distances from q¹ and q² to q³, respectively, and k is Coulomb's constant.
Since q³ is equidistant from q¹ and q², we have r¹ = r² = 0.20 m. Substituting the given values, we get:
F1 = (9.0 x 10⁹ N-m²/C²) x (4.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = 1.8 N
F2 = (9.0 x 10⁹ N-m⁻²/C²) x (-6.0 x 10⁻⁶ C) x (2.0 x 10⁻⁶C) / (0.20 m)² = -5.4 N
The negative sign of F2 indicates that the force on q³ due to q² is in the opposite direction to the force due to q¹.
The net electric force on q3 is the vector sum of the forces due to q1 and q2:
Fnet = F1 + F2 = 1.8 N - 5.4 N = -3.6 N
The electric field at the location of q³ is then:
E = Fnet / q³ = (-3.6 N) / (2.0 x 10⁻⁶ C) = -1.8 x 10⁻⁶N/C
The negative sign of the electric field indicates that the field is directed towards q².
b) To find the initial acceleration of q³, we can use Newton's second law, which states that the net force on an object is equal to its mass times its acceleration:
Fnet = ma
where m is the mass of q³ and a is its initial acceleration.
Substituting the given values, we get:
-3.6 N = (2.0 x 10⁻⁶ kg) x a
Solving for a, we get:
a = -1.8 x 10³ m/s²
The negative sign of the acceleration indicates that it is directed towards q².
c) The direction of the initial acceleration of q³ is towards q².
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If the mass = 1.50 kg, F1 = 1.50 N, 0, = 35.0°, 02 = 45.00 and the acceleration of the object in the + x direction is 1.0 m/s?, what must be the force F2? (Shown in image)
The magnitude of force F₂ is determined as 0.38 N.
What is the magnitude of F₂?
The magnitude of force (F₂) is calculated by applying Newton's second law of motion as follows;
F = ma
where;
F is the resultant of the two forcem is the mass of the objecta is the acceleration of the objectThe resultant forces in the x-direction is given as
F₁cosθ₁ + F₂cosθ₂ = maₓ
(1.5 cos35) + F₂(cos45) = 1.5 x 1
1.23 + 0.71F₂ = 1.5
0.71F₂ = 1.5 - 1.23
0.71F₂ = 0.27
F₂ = 0.27/0.71
F₂ = 0.38 N
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A girl rode a scooter 43 m north, then 38 m south, and then 16 m north. The girl then rode south again before stopping. Her total distance traveled was 122 m. How far south did she ride on the last part of her trip, and what was her total displacement
Answer:
First, let's write some definitions.
Displacement is the distance between the final position and the initial position.
Here we can define north as the positive direction and south as the negative one.
First, we assume that the initial position is 0m
We know that she first goes 43m north
Then she goes 38m south
Then she goes 16m north
And then she goes south again for X meters, such that the total distance traveled is 122m
The total distance traveled is the sum of all distances traveled, regardless of the direction
then we have:
43m + 38m + 16m + X = 122m
Solving this for X we get:
97m + X = 122m
X = 122m - 97m = 25m
So she finally goes 25m south.
Now let's analyze how her position changes:
First, she starts at 0m
Then she goes north for 43m, then her new position is:
0m + 43m = 43m
Now she goes 38m south, then her new position is:
43m - 38m = 5m
Then she goes north again, for 16m
Then the new position is:
5m + 16m = 21m
Now she goes south for 25m, then the final position is:
21m - 25m = -4m
The displacement is equal to the difference between the final position and the initial one, so the displacement is:
-4m - 0m = -4m
The displacement is -4m.
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves downstream at a velocity of 15 km/h relative to the river. What is the velocity of the boat relative to the riverbank?
How is cold front formation different from stationary front formation?
Stationary fronts form between warm and cold air masses, while cold fronts form when a cold air mass advances against a warm air mass.
Cold fronts form between two air masses that barely move, while stationary fronts form when a warm air mass is trapped between two cold air masses.
Cold fronts form when a warm air mass moves over a cold air mass, while stationary air fronts form when a cold air mass moves over a warm air mass.
Stationary fronts form when a warm air mass is trapped between two cold air masses, while cold fronts form when a warm air mass moves over a cold air mass.
Mark this and return
Answer:
A
Explanation:
What is the moment of inertia of a 4.2-kg uniform cylindrical grinding wheel of radius 32 cm?
The moment of inertia of the uniform cylindrical grinding wheel is 2,150 kgm².
What is the moment of inertia?
This refers to the angular mass or rotational inertia can be defined with respect to the rotation axis, as a property that shows the amount of torque needed for a desired angular acceleration or a property of a body due to which it resists angular acceleration. The unit is kgm².
From the question:
Mass,M =4.2kg
Radius, R=32Cm
The formula for calculating the moment of inertia for uniform cylindrical grinding wheel:
moment of inertia, I =1/2MR²
I =\(\frac{1}{2}\) * 4.2 * 32²
=2,150.4 kgm²
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A Young’s double-slit apparatus is set up where a screen is positioned 0.80 m from the double slits. If the distance between alternating bright fringes is 0.95 cm, and the light source has a wavelength of 580 nm, what is the separation of the double slits?
Answer: 0.0488 mm
Explanation:
Given
The position of the screen is \(D=0.80\ m\)
Distance between alternating bright fringes is \(0.95\ cm\)
The wavelength of the light source is \(\lambda =580\ nm\)
Distance between successive bright fringes is \(\frac{\lambda D}{d}\)
Distance between alternating bright fringes is half of the distance between successive fringes i.e. \(\frac{\lambda D}{2d}\)
Insert the values for alternating fringes
\(\Rightarrow 0.95\times 10^{-2}=\dfrac{580\times 10^{-9}\times 0.8}{d}\quad [\text{d=separation of the doubleslits}]\\\\\Rightarrow d=\dfrac{464\times 10^{-9}}{0.95\times 10^{-2}}\\\\\Rightarrow d=488.42\times 10^{-7}\ m\\\Rightarrow d=0.0488\ mm\)
PLEASE BE FAST IM BEING TIMEDDDDD
If the current of a circuit is 2.8A. Find the number of charge in Coulomb in
3 seconds.
Answer:
I=Q/T
2.8=Q/3
8.4C=Q
Explanation:
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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Using the same cost and time estimates, consider any trade-offs that Drehex Corporation may have to make to complete the project. Camilla John Nora Oracio Cost per Hour $40 $30 $20 $15 Time to Complete Job 20 hours 30 hours 40 hours 50 hours Ideally, the process of technological design should be cost-effective and time-effective. However, sometimes this is simply not possible and trade-offs are necessary. Explain the trade-offs Drehex Corporation may have to make to complete the project.
Drehex Corporation may need to make trade-offs between cost and time to complete the project, considering the hourly rates and time estimates of their team members.
Corporation may have to make several trade-offs to complete the project based on the cost and time estimates provided. Here are some possible trade-offs they may need to consider:
Cost vs. Time: The corporation may need to decide whether to prioritize completing the project quickly or keeping the costs low. If they want to minimize costs, they might opt for a longer completion time by choosing a team member with a lower cost per hour. Conversely, if time is crucial, they might choose a team member with a higher cost per hour to expedite the process.Expertise vs. Cost: The team members have different levels of expertise, as indicated by their respective costs per hour. Drehex Corporation may need to evaluate the trade-off between the level of expertise required for the project and the associated cost. They might decide to invest more in a highly skilled team member to ensure the quality and efficiency of the project, even if it means incurring higher costs.Resource Allocation: The corporation will need to allocate resources effectively among the team members to ensure a balanced workload. They may need to assign tasks and responsibilities based on individual strengths and expertise, considering the trade-off between utilizing the most capable team members and maintaining a fair distribution of work.Quality vs. Time/Cost: The trade-off between project quality and time/cost is a common consideration. If Drehex Corporation wants to deliver a high-quality output, they might need to allocate more time and resources to ensure thoroughness and attention to detail. Conversely, if time or cost constraints are significant factors, they may need to compromise on certain aspects of quality to meet project deadlines or budget limitations.Ultimately, the trade-offs Drehex Corporation makes will depend on their specific project goals, budget, timeline, and the importance they place on factors such as cost-effectiveness, timeliness, expertise, and quality. Balancing these trade-offs effectively is crucial for successful project completion.
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Answer:
Sample Response: Oracio is the most cost-effective choice because he would cost the least to complete the project. However, he would also take the longest amount of time. Camilla could complete the job the fastest, but she costs more than Oracio. Drehex Corporation will have to decide if it is more important to save money or complete the work quickly to meet the deadline.
Explanation:
The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C. If the current is supplied by a 12.0 - V battery, what total energy in Joules is delivered to the lightbulb filament during 2.00 s
Answer:
E = 20.03 J
Explanation:
Given that,
The amount of charge that passes through the filament of a certain lightbulb in 2.00 s is 1.67 C,
Voltage, V = 12 V
We need to find the energy delivered to the lightbulb filament during 2.00 s.
The energy delivered is given by :
\(E=I^2Rt\). ....(1)
As,
\(I=\dfrac{q}{t}\\\\I=\dfrac{1.67}{2}\\\\I=0.835\ A\)
As per Ohm's law, V = IR
\(R=\dfrac{V}{I}\\\\R=\dfrac{12}{0.835}\\\\R=14.37\ \Omega\)
Using formula (1).
\(E=0.835^2\times 14.37\times 2\\\\=20.03\ J\)
So, the energy delivered to the lightbulb filament is 20.03 J.
Which descriptions apply to Mendels pea plant experiments ? Select three options
used cross breeding to purposely breed plan
studied a variety of pea plant traits
studied several generations of plants
In order to breed or cross one plant with another, Mendel opened the petals and removed the anthers from the flower and dusted the pistil with pollen from the plant he wished to cross it with and covered the flower with a small bag to prevent the pollen in the air from landing in the pistil. This process is called cross pollination.
Mendel considered 7 characters of pea plant for his study and did the study for several generations.
in the early solar system,comets that struck earth may have brought in
A.water
B.advanced life
c.plankton
D.all of the above
\(\huge{\mathbb{\tt { QUESTION↓}}}\)
In the early solar system,comets that struck earth may have brought in
\(\color{green}{\tt{O} \: \: \color{black}{\tt {A.water}}}\)
\(\color{green}{\tt{O} \: \: \color{black}{\tt {B.Advanced Life}}}\)
\(\color{green}{\tt{O} \: \: \color{black}{\tt {C.Plankton}}}\)
\(\color{green}{\tt{O} \: \: \color{black}{\tt {D. All \: of \: the \: above}}}\)
\(\huge{\mathbb{\tt { ANSWER↓}}}\)
\(\color{red}{\tt {D. \: All \: of \: the \: above}}\)
\(\color{black}{\tt {because \: the \: true \: answer \: is \: comet}}\)
\({\boxed{\boxed{\tt{WHAT \: IS \: COMET?}}}}\)
\(\color{black}{\tt{A \: comet \: is \: an \: icy, \: small \: Solar \: System \: body}}\)
\(\color{black}{\tt { that, \: when \: passing \: clos \: e to}}\)
\( \color{black}{\tt {the \: Sun, \: warms \: and \: begins \: to \: release}}\)
\(\color{black}{\tt { gases, \: a \: process \: that \: is \: called \: outgassing. }}\)
\(\color{black}{\tt{This \: produces \: a \: visible \: atmosphere \: or \: coma,}}\)
\(\color{black}{\tt{and \: sometimes \: also \: a \: tail}}\)
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→XxKim02xXWhat are two important factors to consider when describing the effect of an applied force on an object’s motion
The magnitude of the applied force and the mass of the object, together determine how an object's motion will change in response to the applied force.
When describing the effect of an applied force on an object's motion, two important factors to consider are:
Magnitude of the Force: The magnitude or strength of the applied force determines the amount of acceleration or deceleration experienced by the object. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. A greater force will result in a greater acceleration, while a smaller force will result in a smaller acceleration. Additionally, the direction of the force relative to the object's initial motion will determine if it speeds up, slows down, or changes direction.
Mass of the Object: The mass of the object being acted upon is another crucial factor. As mentioned earlier, according to Newton's second law, the acceleration of an object is inversely proportional to its mass. This means that for a given force, an object with a larger mass will experience a smaller acceleration compared to an object with a smaller mass. In simpler terms, it requires more force to accelerate a heavier object compared to a lighter object.
These two factors, the magnitude of the applied force and the mass of the object, together determine how an object's motion will change in response to the applied force.
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1. A material emits electrons when the electromagnetic radiation with a frequency equal to or less than the material's threshold frequency strikes the material.
True
False
2. In a particle model to show energy transfer, which of the following is correct?
a. Energy jumps are best described of electrons in packages known as photons
b. In energy transfers, electrons can absorb or emit energy
c. Photons carry energy from one location or object to another
d. All of the above are correct of particle models
1) The photoelectric effect is the phenomena by which, the metals release electrons when they are exposed to electromagnetic radiation with the suitable frequency. The photoelectrons are the electrons that are released in this process.
So, the statement is true.
2) In a particle model, energy transfer can be done through many ways such as:
The energy jumps between the particles in the form of photons.
Electrons can absorb or emit energy during energy transfer.
The energy is transferred between different objects in the form of photons.
So, all of them are true.
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Determine the magnitude and direction of the electric field at a point midway between a –8.0 µC and a +5.8 µC charge 6.0 cm apart. Assume no other charges are nearby.
The magnitude and direction of the electric field is equal to 3.45 x10^13 N/m and the direction in towards the negative charge.
Electric field
To calculate the electric field of a point it is necessary to use the following expression:
\(E = k\frac{Q}{d^{2}}\)
Thus, calculating the field formed by each charge we have:
–8.0 µC
\(E = 9 \times 10^{9} \times \frac{8}{36\times 0.0001}\)
\(E = 2\times 10^{13} V/m\)
+5.8 µC\(E = 9 \times 10^{9} \times \frac{5.8}{36\times 0.0001}\)
\(E = 1.45 \times 10^{13} N/m\)
The direction of the electric field of the negative charge is towards the charge (attracted) and of the positive charge is repelled.
So, we can add the two values of field found, since the two are directed towards the negative charge, so that :
\(E = 2 \times 10^{13} + 1.45 \times 10^{13}\)
\(E = 3.45 \times 10^{13} N/m\)
So, the magnitude of eletric field is equal to 3.45 x10^13 N/m and the direction in towards the negative charge.
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magnets stick to all metals
bonjours
non il y a des métaux type alu, argent, plomb qui ne reagissent pas au aimants
j espère que cela vous aura aidée
bonne fin de journée a vous
31. Box A of mass m sits on the floor of an elevator, with box B of mass 2 m on top of it, as shown in the figure above. The elevator is moving upward and slowing down. F_A is the magnitude of the force exerted on box A by box B, F_B is the magnitude of the force exerted on box B by box A, and F_g is the magnitude of the gravitational force exerted on box B. Which of the following ranks the forces in order of increasing magnitude?
(A) F_B=F_A=F_g
(B) (F_B=F_A)
(C) F_B<(F_A=F_g)
(D) F_g
The rank of the forces in order of increasing magnitude is Fg < FB < FA.
option D is the correct answer.
What is the net force on elevator moving upwards?The net force on an elevator moving upwards is determined by the force of gravity acting downwards and the normal force of the elevator acting upwards.
That is, the two forces acting on a person when he is moving in an elevator are:
the force of gravity and the normal force by the elevator.When the two forces are of equal magnitude, the elevator will be static or moving with constant velocity.
When the magnitude of the two force are unequal, then the elevator will be accelerating upward or downward.
Since the elevator is moving upwards, it implies that the normal force is greater than the force of gravity acting downwards.
the normal force = FB + FAForce of gravity = FgThe box at the bottom will feel much heavier due to the weight of box and gravity acting downwards.
FA = FB + Fg
Thus, the force exerted on box A is the greatest, followed by the force on box B and then, the smallest is force of gravity.
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