Answer:
The last one makes the most sense as they combine two like things that are easy to visualize
Explanation:
Answer:
C. The inner planets are like hard butterscotch candy and the outer planets are like cotton candy.
Explanation:
Right on ED2021, goodluck!
The resistance, r, to electricity of a cylindrical-shaped wire is given by the equation r = startfraction p l over pi d squared endfraction, where p represents the resistivity of the wire’s material, l represents the length of the wire, and d represents the diameter of the wire. what happens to the resistance of the wire as the diameter approaches 0?
As the diameter of the wire approaches to zero, the resisitance approaches infinity.
What is resistance?Electrical resistance is the physical capacity of any body to oppose the flow of electric current even when there is an applied potential difference, capacity calculated by Ohm's First Law, and, according to the International System of Units (IS), is measured in ohms.
With that being said, and knonwing that:
R = Resistance; p = Resistivity; L = Length; d = Diameter
It is possible to calculate the resistance of the wire by:
\(R = p\frac{L}{A}\)
Where A is calculated by:
\(A = \frac{\pi d^{2} }{4}\)
Changing in the first formula:
\(R = p\frac{L}{\pi d^{2} } \\\\R = p\frac{4L}{\pi d^{2} }\)
Knowing that when the diameter tends to zero resistance tends to infinity, it is possible to say that resistance of the wire will tend to infinity when the diameter approaches zero.
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Answer:
The resistance approaches infinity.
Explanation:
100% Correct
A charge of 3.877 nC is moved from a position on the y axis of 8.856 cm to a position on the x axis of 1.619 cm while there is a charge 21.524 nC located at the origin. How much work in micro-Joules did it take to move the charge?
Answer:
sa64
Explanation:
if the cord is subjected to a constant force of and the 15-kg smooth collar starts from rest at a, determine the velocity of the collar when it reaches point b. neglect the size of the pulley.
If the cord is subjected to a constant force and the 15-kg smooth collar starts from rest at A, determine the velocity of the collar when it reaches point B.
Neglect the size of the pulley. The acceleration of the 15-kg collar can be found as follows: F = ma => a = F/m ... (1)where F is the constant force applied and m is the mass of the collar.
Let v be the velocity of the collar when it reaches point B. Using the formula for the velocity-time relationship, we have v = u + at ... (2)where u is the initial velocity of the collar at A which is zero. Substituting (1) into (2), we have v = at ... (3)Substituting the value of a from (1) into (3), we get v = F/m t ... (4)where t is the time taken for the collar to travel from A to B and is given by:t = s/v ... (5)where s is the distance between A and B.
Since the cord is assumed to be inextensible, s is equal to twice the distance AB (AB = BC). Let us now compute the tension in the cord at point A. The tension in the cord is equal to the force F as shown in the figure below: Therefore, we have T = F = 35 N ... (6)Since the pulley is smooth, the tension in the cord is the same throughout its length. Thus, we have T = T' ... (7)where T' is the tension in the cord at point B.
Substituting (6) and (7) into the force equation for the collar gives us: T - mg = ma => T' - mg = ma ... (8)where g is the acceleration due to gravity. Substituting the value of a from (1) into (8), we get:T' - mg = F/m => T' = mg + F/m ... (9)Substituting (9) into (7), we get:mg + F/m = T = 35 N => mg = 35 - F/m ... (10)Substituting the values of m and F into (10), we get:mg = 35 - (5 kg)(7 m/s²)/(15 kg) = 28 - 2/3 N ... (11)Substituting the value of g from (11) into (9), we get:T' = 15(28 - 2/3) + 7 = 425 - 2/3 N ...
(12)Substituting (11) and (12) into (4), we get:v = (425 - 2/3)/(15) t ...
(13)Substituting the value of s from the figure above, we get:s = 2(0.8 m) = 1.6 m ... (14)Substituting (13) and (14) into (5), we get:t = s/v = (1.6 m)/(425 - 2/3)(15) = 0.025 s (approx)Substituting (13) and (15) into (4), we get:v = (425 - 2/3)/(15) (0.025) = 0.567 m/s (approx)Therefore, the velocity of the collar when it reaches point B is approximately 0.567 m/s.
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Two weights are connected by a massless wire and pulled upward with a constantspeed of 1.50 m/s by a vertical pull P. The tension in the wire is T(see figure). Whichone of the following relationships between Tand Pmust be true?A)TB)T=PC)P+T=125ND)P=T+25N
Two weights are connected by a massless wire and pulled upward with a constant speed of 1.50 m/s by a vertical pull P. The tension in the wire is T The relationship between T and P is that T = P + 125N, which is equivalent to answer choice D. The correct answer is D) P=T+25N.
This can be determined by analyzing the forces acting on the system. Since the weights are being pulled upward at a constant speed, the net force acting on them must be zero.
The forces acting on the weights are their respective weights (mg), where m is the mass of the weight and g is the acceleration due to gravity, and the tension in the wire (T). The vertical pull P also acts on the system.
Using Newton's second law (F=ma) and setting the net force equal to zero, we can write:
T - m1g - m2g - P = 0
Solving for T, we get:
T = m1g + m2g + P
Substituting in the given values of m1, m2, and g, we get:
T = 50N + 75N + P
Simplifying, we get:
T = P + 125N
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which are cardiovascular drug classes? select all that apply
Cardiovascular drug classes are Beta-blockers, Diuretics, Calcium channel blockers, and ACE inhibitors. The correct answer is options are A, B, D, and F.
Cardiovascular drug classes refer to categories of medications specifically designed to treat conditions related to the cardiovascular system. These medications target various aspects of cardiovascular health, such as blood pressure regulation, heart rhythm management, and the prevention of clot formation. Several recognized cardiovascular drug classes include:A) Beta-blockers: These drugs block the effects of adrenaline on the heart and blood vessels, reducing heart rate and blood pressure.B) Diuretics: Also known as water pills, diuretics help eliminate excess fluid from the body, reducing fluid buildup and decreasing blood pressure.D) Calcium channel blockers: These medications relax and widen blood vessels, improving blood flow and reducing blood pressure. They also help regulate heart rate.F) ACE inhibitors: ACE (angiotensin-converting enzyme) inhibitors lower blood pressure by blocking the production of a hormone that narrows blood vessels.Therefore, the correct options for cardiovascular drug classes are A) Beta-blockers, B) Diuretics, D) Calcium channel blockers, and F) ACE inhibitors. These medications play crucial roles in managing cardiovascular conditions and promoting overall heart health.For more questions on the cardiovascular system
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The correct question would be as
Which of the following are cardiovascular drug classes? Select all that apply.
A) Beta-blockers
B) Diuretics
C) Antibiotics
D) Calcium channel blockers
E) Antidepressants
F) ACE inhibitors
Q3The pressure P (in kilopascals), volume V (in liters) and temperature T(in kelvins) of a mole of an ideal gas are related by the equation PV = 8.31T Find the rate at which the pressure is changing when the temperature is 300 K and increasing at a rate of 0.1 K/s and the volume is 100 L and increasing at a rate of 0.2L/s.
dP/dt = (0.831 - 0.2P) / 100, where P represents pressure (in kilopascals).
This equation represents the rate at which the pressure is changing with the given conditions of temperature and volume.
To find the rate at which the pressure is changing, we need to use partial derivatives. Given the equation PV = 8.31T, we can differentiate both sides of the equation with respect to time t.
Differentiating both sides with respect to time t, we get:
P(dV/dt) + V(dP/dt) = 8.31(dT/dt)
Now, let's substitute the given values:
dT/dt = 0.1 K/s (rate of temperature change)
dV/dt = 0.2 L/s (rate of volume change)
T = 300 K (temperature)
V = 100 L (volume)
Plugging in the values into the equation:
P(0.2) + 100(dP/dt) = 8.31(0.1)
0.2P + 100(dP/dt) = 0.831
Now, we can solve for dP/dt:
100(dP/dt) = 0.831 - 0.2P
dP/dt = (0.831 - 0.2P) / 100
Therefore, the rate at which the pressure is changing when the temperature is 300 K and increasing at a rate of 0.1 K/s, and the volume is 100 L and increasing at a rate of 0.2 L/s is given by:
dP/dt = (0.831 - 0.2P) / 100
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What can astronomical objects that have changing magnetic fields do
ok byy make me brilliant
Josie walks 15 meters north down the freshman hallway. She then walks 25 meters east. Lastly, she walks 15 meters south. What is Josie's displacement? *
Answer:
the answer is yours a calculated
A 1.00 kg sphere M, suspended by a string from point P, is lifted to a height h. The sphere is released and passes through the lowest point in its swing at a speed of 10.0 meters per second. [Neglect friction.]
a. Calculate the height from which the sphere was released. [Show all work including equation and substitution with units]
b. Compared to the sphere’s speed through the lowest point of its swing when released from h, the sphere’s speed through the lowest point when released from 2h would be
Answer:
(a) h = 5.1 m
(b) v = 14.13 m/s
Explanation:
(a)
We will use the law of conservation of energy. For this situation it states that:
Loss in Potential Energy of Sphere = Gain in Kinetic Energy of the Sphere
mgh = (1/2)mv²
h = v²/2g --------------- equation (1)
where,
h = height = ?
v = speed at lowest point = 10 m/s
g = 9.8 m/s²
Therefore,
h = (10 m/s)²/(2)(9.8 m/s²)
h = 5.1 m
(b)
using the equation (1)
h = v²/2g
v = √2gh
where,
v = velocity = ?
g = 9.8 m/s²
h = height = 2(5.1 m) = 10.2 m
Therefore,
v = √[2(9.8 m/s²)(10.2 m)]
v = 14.13 m/s
The height from which the sphere was released is 5.1 m
When the height is doubled, the speed of the sphere becomes 14.14 m/s.
The given parameters:
Mass of the sphere, m = 1.0 kgSpeed of the sphere, v = 10 m/sThe height from which the sphere was released is calculated as follows;
\(P.E = K.E\\\\mgh = \frac{1}{2}mv^2\\\\gh = \frac{1}{2}v^2\\\\h = \frac{v^2}{2g}\\\\h = \frac{(10)^2}{2(9.8)} \\\\h = 5.1 \ m\)
When the height is doubled, the speed of the sphere becomes;
\(h = \frac{v^2}{2g} \\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 9.8 \times (2 \times 5.1)} \\\\v = 14.14 \ m/s\)
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when refrigeration is being charged with a vapor from a refrigerant sylinder that is not being warmed, what will happend to the pressure of the cylinder
The refrigerant undergoes this process with a rise in volume and enthalpy but no change in pressure or temperature.
A thermodynamic cycle called the refrigeration cycle is used to remove heat from a particular location that you want to chill.
A heat pump cycle is another name for the refrigeration cycle. This cycle is intended for heat pumps, air conditioners, and refrigeration systems.A mechanical device called a heat pump is used to move heat from a low-temperature reservoir to a high-temperature reservoir.The refrigerant absorbs heat from the cold reservoir and turns it into vapor as it enters the evaporator at low pressure and low temperature. The refrigerant undergoes this process with a rise in volume and enthalpy but no change in pressure or temperature.Learn more about refrigeration here:
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How do you feel about the way land is used around you?
Answer:
I feel that people hurt the land and are destroying. I think they aren't using the land for the right reasons.
What are the two primary factors that control what type of magma erupts from a volcano and what type of volcano it will create?
Answer:
answers are located on the picture attached to this answer
Explanation:
2. A go-cart travels once around a circular track with a radius of 200m. What is its
displacement?
A)200 m
B)1256.64 m
C)100 m
D)0 m
Answer:
ggggggg
Explanation:
Please help ill give you 30 points
Answer: 14 inches.
Explanation: The radius of this circle is 7 inches, so the diameter is 2(7) = 14 inches. The diameter is 14 inches.
1 A grandfather clock uses energy stored in raised weights. The weights transfer energy to the clock mechanism as they fall. One clock has a 4.5 kg weight that supplies energy to the chimes (which play a few notes every 15 minutes), and two 3.5 kg weights that power the clock and the mechanism that strikes the hours.
For all questions on this sheet,
use g = 10 N/kg
a Calculate how much energy is stored when all three of these weights are raised by 70 cm. b How far does the 4.5 kg weight have to be lifted to store 45 J of energy?
2 The water tank in a house can hold 200 litres of water. The mass of 1 litre of water is 1 kg. The tank is 2 m above the bathroom taps and 5 m above the kitchen taps. The kitchen taps are 1 m above the floor.
a
Calculate the gravitational potential energy (GPE stored in the water in the tank when it is full. State any assumptions made in your answer.
b Calculate the speed at which the water would come out of the bathroom taps and kitchen taps. You
may assume that no energy is transferred due to friction in the pipes.
3 The Victoria Falls in Africa is one of the world's largest waterfalls. Just over 1000 m° of water pass over the falls every second and fall approximately 100 m. 1 m3 of water has a mass of 1000 kg. a What mass of water goes over the falls every second? Give your answer in standard form.
b
Calculate the GPE of 1 kg of water at the top of the falls.
c If all the GPE stored in 1 kg of water is transferred to kinetic energy, calculate the speed of the water as
it reaches the bottom.
d Suggest why the water will not be falling as fast as your answer to part c suggests. e What is the total energy transferred per second as the GP stored in the water falling in one second is
transferred to other energy stores.
f Suggest the ways in which this energy is finally stored.
4 A post driver is used to drive fence posts into the ground. It is a hollow tube with a closed top, and handles on the side. A person fits the driver over a fence post, then lifts it up and lets it drop.
post driver
50 cm
a A post driver has a mass of 10 kg. Calculate the change in GPE stored when the post driver is lifted by 50 cm above the post, as shown in the diagram.
b
Calculate the speed of the driver when the end hits the post.
C
Explain how much extra energy is stored if the post driver is
fence post
lifted by 1 metre instead of only 50 cm.
d Calculate the speed of the post driver after it falls for 1 m. e A new design of post driver has a mass of 15 kg. Suggest one advantage and one disadvantage of this new design.
Extra challenge
5 F The post driver in question 4a stops in
0.5 seconds when it hits the fence post.
a Calculate the force needed to bring the post driver to a stop. (Hint: use your answer to 4b.)
The momentum of a moving object is the product of its mass and its velocity. The force needed to stop a moving object depends on how fast its momentum changes.
force = change in momentum
=
mv - mu
time
t
b What provides this force?
c Explain how your answer might be different it the post were being sunk into very soft ground,
F = force (N)
u = initial velocity (m/s)
te time (s)
m = mass (kg)
v = final velocity (m/s)
1a) The total energy stored when all three weights are raised by 70 cm is 80.5 J.
1b) The height of the tank is 2 m.
2b) The potential energy is converted into kinetic energy when the water flows out of the taps 6.32 m/s.
3a) The mass of water that goes over the falls every second is 1 x 10⁶ kg.
3b) The gravitational potential energy of 1 kg of water at the top of the falls 1000 J.
3c) The speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy is 44.72 m/s.
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
1a) To calculate the amount of energy stored in the three weights, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
For the 4.5 kg weight:
E = 4.5 x 10 x 0.7 = 31.5 J
For each of the 3.5 kg weight:
E = 3.5 x 10 x 0.7 = 24.5 J
Thus, the total energy stored when all three weights are raised by 70 cm is:
31.5 J + 24.5 J + 24.5 J = 80.5 J
1b) To calculate how far the 4.5 kg weight must be lifted to store 45 J of energy, we use the formula:
E = mghh = E/mg = 45 / (4.5 x 10) = 1 m2a)
To calculate the gravitational potential energy stored in the water in the tank when it is full, we use the formula given below:
E = mgh
Where,E = Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
The mass of 1 litre of water is 1 kg and the tank can hold 200 litres of water. Therefore, the total mass of water in the tank is:
Mass = 200 kg
The height of the tank is 2 m.
Therefore, the gravitational potential energy stored in the water in the tank is:
E = mgh = 200 x 10 x 2 = 4000 J
Assumptions made in the answer:
We have assumed that the tank is full.
2b) To calculate the speed at which the water would come out of the bathroom and kitchen taps, we use the formula given below:
PE = KEPE = mghKE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that the potential energy of the water in the tank is converted into kinetic energy when the water flows out of the taps, the potential energy stored in the water in the tank is given by:
PE = mgh = 200 x 10 x 2 = 4000 J
The potential energy is converted into kinetic energy when the water flows out of the taps.
Therefore, KE = 1/2mv²v² = 2KE/mv² = 2(4000)/200 = 40 m²/s²v = √(40) = 6.32 m/s (speed of the water coming out of the taps)
3a) To calculate the mass of water that goes over the falls every second, we use the formula given below:
Mass = Volume x Density
Where,Volume = 1000 m³/s, Density = 1000 kg/m³, Mass = 1000 x 1000 = 1000000 kg = 1 x 10⁶ kg
3b) To calculate the gravitational potential energy of 1 kg of water at the top of the falls, we use the formula:
E = mgh
Where,m = 1 kg, g = 10 N/kg, h = 100 m, E = 1 x 10 x 100 = 1000 J
3c) To calculate the speed of the water as it reaches the bottom if all the GPE stored in 1 kg of water is transferred to kinetic energy, we use the formula given below:
PE = KEP
E = mgh
KE = 1/2mv²
Where,PE = Potential Energy (Joules)
KE = Kinetic Energy (Joules)
m = Mass (kg)
g = Gravity (10 N/kg)
h = Height (m)
v = Velocity (m/s)
Assuming that all the potential energy is converted into kinetic energy when the water reaches the bottom,
PE = KEKE = mghv² = 2mghv² = 2(1)(10)(100)v² = 2000v = √(2000) = 44.72 m/s
3d) The water will not be falling as fast as the speed calculated in part c suggests because of the presence of air resistance and the fact that the water falls through a medium (air) which offers resistance to its motion.
3e) To calculate the total energy transferred per second as the GPE stored in the water falling in one second is transferred to other energy stores, we use the formula given below:
Power = Energy / Time
Where,Power = 1 x 10⁶ x 10 x 100 = 1 x 10⁹ W = 1 GW (assuming that 1 m³ of water falls every second)3f)
The energy transferred when the GPE stored in the water falling in one second is transferred to other energy stores is finally stored in thermal energy stores due to the heat generated by the water as it hits the bottom.
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A monatomic gas and a diatomic gas have equal numbers of moles and equal temperatures. both are heated at constant pressure until their volume doubles.What is ratio Qdiatomic/Qmonatomic
A monatomic gas and a diatomic gas have equal numbers of moles and equal temperatures. Ratio Q diatomic/Q monatomic is 7/5.
The heat (Q) required to increase the temperature of a gas at constant pressure (i.e., heating it) can be calculated using the formula:
\(Q = nCp $\Delta$ T\)
here n is the number of moles of the gas, Cp is the molar specific heat capacity at constant pressure, and ΔT is the change in temperature. Since the two gases have equal numbers of moles and equal temperatures, ΔT is the same for both gases.
For a monatomic gas, Cp = (5/2)R, where R is the gas constant. For a diatomic gas, Cp = (7/2)R. Therefore, the ratio of the specific heats is:
Cp,diatomic/Cp,monatomic = (7/2)R / (5/2)R = 7/5
During the heating process, the gases are both heated at constant pressure until their volume doubles. Since the pressure is constant, we can use the formula for the work done on a gas at constant pressure:
W = -PΔV
where P is the pressure and ΔV is the change in volume. The negative sign indicates that work is done on the gas (i.e., the gas absorbs energy) when its volume increases.
Since the volume doubles, ΔV = V - V0 = V, where V0 is the initial volume and V is the final volume. Therefore, the work done on the gas is:
W = -PΔV = -P(V - V0) = -P(V/2) = -(1/2)PV
The change in internal energy of the gas is equal to the heat added to the gas minus the work done by the gas, according to the first law of thermodynamics:
ΔU = Q - W
Since the pressure is constant, the change in internal energy is equal to the heat added to the gas:
ΔU = Q
Therefore, the heat added to the gas is:
Q = ΔU = (3/2)nRΔT
where we have used the fact that the change in internal energy of an ideal gas is proportional to the number of moles and the temperature change, with a proportionality constant of (3/2)R for both monatomic and diatomic gases.
Substituting the values and simplifying, we get:
Qdiatomic/Qmonatomic = (ΔU)diatomic / (ΔU)monatomic
= [(3/2)nRΔT]diatomic / [(3/2)nRΔT]monatomic
= (Cp,diatomic/Cp,monatomic)ΔT
= (7/5)ΔT
Since ΔT is the same for both gases, the ratio of the heat added to the diatomic gas to the heat added to the monatomic gas is simply 7/5.
Therefore, the ratio Qdiatomic/Qmonatomic is 7/5. This means that the diatomic gas requires more heat to be added to it than the monatomic gas in order to achieve the same temperature increase, when heated at constant pressure and with the same number of moles and temperature. This is because the diatomic gas has more degrees of freedom (i.e., more ways to store energy) than the monatomic gas, due to its additional internal vibrations.
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blue objects absorb most wavelengths but reflect light at about 450 nm. this phenomenon relates to .
The blue objects absorb most wavelengths but reflect light at about 450 nm. This phenomenon relates to the colors of objects.
When the sunlight falls on an object, some of the light is absorbed, and the rest of the light is reflected. Objects appear to be a certain color because they absorb some colors of light and reflect others. Some objects appear blue because they absorb all colors of light except blue.
Blue light has a shorter wavelength than other colors of light, so it is scattered more in the Earth's atmosphere. The sky appears blue because the shorter blue wavelengths are scattered in all directions and are more likely to reach the observer's eye.
The light that is reflected off blue objects is at a wavelength of around 450 nm. When white light passes through a prism, it splits into the colors of the spectrum.
Violet light has the shortest wavelength, and red light has the longest wavelength. Between violet and green, the colors blend to form blue. So, if blue objects reflect light at around 450 nm, that means they reflect blue light.
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A rope exerts a 35N force on an object at an angle of 12N degrees above the horizontal. What horizontal and vertical components of the force?
Answer:
The horizontal component of the force, \(F_x= 34.24 \ N\)
The vertical component of the force, \(F_y=7.28 \ N\)
Explanation:
Given;
Force on the rope, F = 35 N
angle between the rope and the horizontal = 12 °
The horizontal component of the force is given by;
\(F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N\)
The vertical component of the force is given by;
\(F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N\)
What is the difference between inertial mass and weight
Answer:
mass is the amount of matter in an object, whereas weight is the force exerted on an object by gravity
A bowling ball is traveling at 3 m/s. It starts to roll up a ramp. How high above the ground will the ball be when it stops rolling? Neglect friction and assume the ramp is plenty long enough to do this. (For this problem your initial kinetic energy can be set equal to your final potential energy. 1/2mv2 = mgh).
Answer:
h= 0.45 m
Explanation:
PE= 1/2 mv^2 KE= mgh
v= 3m/s
vf= 0 m/s
h=?
PE= 1/2(1kg)(3m/s)^2
PE= 4.5 J
4.5 J/ 1kg(9.8 m/s^2)
h=0.45 m
The height of the ball above the ground when it stops is 0.46 m.
The initial kinetic energy of the ball is equal to the final potential energy of the ball.
⇒ Formula:
mv²/2 = mghv² = 2gh............... Equation 1⇒ Where:
v = velocity of the ballh = height of the ball above the groundg = acceleration due to gravity.⇒ make h the subject of the equation
h = v²/2g.............. Equation 2From the question,
⇒ Given:
v = 3 m/sg = 9.8 m/s²⇒ Substitute these values into equation 2
h = 3²/(2×9.8)h = 9/19.6h = 0.46 mHence, the height of the ball above the ground when it stops is 0.46 m.
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a recycling center uses magnetic damping to detect and separate certain materials. which materials will respond to this method? i. ferromagnetic conductors ii. nonferromagnetic conductors iii. insulators
The materials that will respond to magnetic damping at a recycling centre to detect and separate certain materials are ferromagnetic conductors. So the answer is i.
Ferromagnetic conductors are materials that are strongly attracted to a magnet and can become magnetized themselves. These include iron, nickel, and cobalt. In terms of magnetic damping, these materials would respond very strongly to this method as they have a high magnetic susceptibility. This means that the magnetic damping system would be able to easily detect and separate these materials from other materials in the recycling centre. Nonferromagnetic conductors, on the other hand, are materials that conduct electricity but are not attracted to magnets. These include copper, aluminium, and gold. While they do not have a high magnetic susceptibility like ferromagnetic conductors, they can still be separated using magnetic damping. This is because the damping system can induce a small amount of magnetism in these materials, allowing them to be detected and separated from other materials.
Finally, insulators are materials that do not conduct electricity or heat. These include materials such as rubber, plastic, and glass. Insulators are not responsive to magnetic damping as they do not have any magnetic properties that can be induced by the damping system. As a result, they would not be separated using this method in a recycling centre.
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h=ac+mn solve for m
the answer is m= H/n - ac/n
What is the eccentricity of an orbit when both focal points are located at the sun?
The eccentricity of an orbit when both focal points are located at the sun is zero.
What is an orbit?
An orbit is the trajectory, or path, of an object that revolves around another object, the center of mass or a gravitational point. All planets orbit the sun, and the moon orbits the earth, for example, An elliptical orbit is the shape of many planetary orbits.
As a result, the eccentricity of the orbit is significant.
What is Eccentricity?
The degree of circularity of an orbit is referred to as its eccentricity. When the distance between the two foci is divided by the length of the major axis, eccentricity is calculated.
A perfectly circular orbit has an eccentricity of zero.
An ellipse with an eccentricity of 1 is a parabolic orbit. When eccentricity is greater than one, the orbit is hyperbolic.
The eccentricity of an orbit when both focal points are located at the sun:
Since there is only one focus, and the center of the sun is located there, the eccentricity of such an orbit is zero. Because there is only one focus, the distance between the two foci is also zero.
As a result, a planet's orbit with a sun-centered focus is always circular.
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The waves that heat a cup of water in the microwave are an example of electromagnetic waves. True or False
That's true.
They're radio waves, at the frequency of 2.45 GHz (in all microwave appliances manufactured in the US).
What happens when light from the Sun passes through any type of matter? The light slows down.
The light speeds up.
Most of the light is absorbed.
Most of the light is reflected.
Answer:
A
Explanation:
THE LIGHT SLOWS DOWN
When light from the Sun passes through any type of matter the light slows down.
Interaction of sunlight with matter:The behavior of light from the Sun as it interacts with any matter depends on the matter and its properties.
Since it comes through a vacuum and enters our atmosphere which is a denser medium and has a definite refractive index, the light slows down.
This also happens when light falls on material such as glass, water, and other transparent and translucent media. When it emerges out of such medium to a rarer medium like air, it speeds up to its initial speed.
A portion of the sunlight is absorbed by almost all the matter present on earth that's why something heats up when exposed to sunlight. While a considerable portion of the sunlight is reflected by the matter.
But the question says what happens when it passes through any matter. The answer is:
It slows down while passing through the matter since any matter is optically denser than the vacuum.
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A clown is trying to lift a refrigerator of wigs a height of 2 meters. It would take him a force of 80 Newtons to lift the fridge without a simple machine.
a. How much work would be required to lift this
fridge of wigs without a machine? Don’t forget
a unit for your answer!
b. Assuming no friction, how much effort force would be required to lift the fridge of wigs with a lever that has a mechanical advantage of 4? Don’t forget a unit for your answer!
a. It would take 160 Joules of work to lift the fridge of wigs without a simple machine. b. It would take an effort force of 50 Newtons to lift the fridge of wigs.
What is work?Work is defined as the transfer of energy that occurs when a force is applied to an object and the object is moved through a distance in the direction of the force.
a. The work required to lift the fridge of wigs without a machine can be calculated using the formula:
Work = Force x Distance
Here, the force required to lift the fridge without a machine is 80 Newtons and the distance to be lifted is 2 meters. Therefore, the work required is:
Work = 80 N x 2 m = 160 Joules
So, it would take 160 Joules of work to lift the fridge of wigs without a simple machine.
b. With a lever having a mechanical advantage of 4, the effort force required to lift the fridge can be found using the formula:
Effort Force = Load Force / Mechanical Advantage
Here, the load force is the weight of the fridge, which is not given in the problem. Assuming the weight of the fridge is 200 Newtons (which is just an assumption and not given), the load force would be:
Load Force = Weight of Fridge = 200 N
The mechanical advantage of the lever is given as 4. Therefore, the effort force required to lift the fridge would be:
Effort Force = Load Force / Mechanical Advantage = 200 N / 4 = 50 Newtons
So, assuming the weight of the fridge to be 200 N and using a lever with a mechanical advantage of 4, it would take an effort force of 50 Newtons to lift the fridge of wigs.
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Eric traveled east for 150 miles in 2 hours. Then he went west for 40 miles in 1 hour. What is the average velocity?
Answer:
190 is the average velocity.
Explanation:
Just add them together
Wind turbines work by converting __________ energy into _________ energy.
A. Chemical, Electromagnetic
B. Potential, Kinetic
C. Kinetic, Electric
D. Electric, Chemical
Answer: C
Explanation:
The kinetic energy of the wind turns the turbine which creates kinetic energy of it's own, this rotational kinetic energy can be called mechanical energy and is used to create electricity
according to __________, the density of storage on magnetic disks is increasing at an exponential rate.
According to Kryder's Law, magnetic disk storage density is rising exponentially.
What are the different kinds of magnetic disks?A magnetic substance, such as iron oxide, is deposited on magnetic disks. Hard disks made of rigid metal or glass and removable diskettes made of flexible plastic are the two sorts. Magnetic disks are round, flat pieces of metal or plastic that have an iron oxide coating on both sides.
What are the three different types of magnetic disks?Magnetic discs come in four different varieties: basic, planning, ring, and countersunk. All of these exist in a wide range of sizes, but their fundamental feature—that the diameter is always bigger than the depth—remains the same.
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An object of mass M moves in one dimension along the x-axis. A conservative force F(x) is exerted on the object. The potential energy U(x) associated with this force as a function of position x is shown in graph 1. A student used the potential energy graph to construct the graph of F(x) as a function of x shown in graph 2. Are these graphs consistent with one another, and if not, what is the error?
These graphs do not consistent with one another because one is graph of potential energy U(x) vs distance(x) and two is graph of force (F(x)) vs distance(x).
What is potential energy?Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
Now, if a force F(x) is applied on an object, that caused a displacement of the object a distance x. Then potential energy of the object is:
U(x) = ∫ F(x)dx.
Hence, U(x) ≠ F(x)
That's why, these graphs do not consistent with one another.
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