In the case of a standing wave in a string, the wavelength can be found using the following equation:λ = 2L/nwhere λ is the wavelength, L is the length of the string, and n is the harmonic number (1, 2, 3, etc.).For this particular case, we know that L = 0.28 m, and n = 2.
Therefore,λ = 2(0.28)/2= 0.28 m The velocity of a wave can be defined using the following formula:v = fλwhere v is the velocity, f is the frequency, and λ is the wavelength. We are given that the velocity of the wave is 140 m/s, and we have just found that the wavelength is 0.28 m.
Therefore, we can solve for the frequency: f = v/λ = 140/0.28= 500 HzTherefore, the frequency of vibration is 500 Hz.
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the closer together a magnet’s magnetic field lines are,
The closer together a magnet's magnetic field lines are, the stronger the magnetic field in that region.
The density or proximity of magnetic field lines represents the strength and intensity of the magnetic field produced by the magnet.
In regions where the magnetic field lines are close together, it indicates a concentrated and strong magnetic field. This implies that the magnetic field has a higher magnitude and can exert a greater force on magnetic materials or charged particles within that region.
Conversely, when the magnetic field lines are spaced farther apart, it indicates a weaker magnetic field. The density of field lines decreases, suggesting a lower strength and intensity of the magnetic field.
The pattern and distribution of magnetic field lines around a magnet provide a visual representation of the magnetic field's strength and direction. The closer the field lines, the stronger the magnetic field, and the farther apart they are, the weaker the magnetic field.
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A rocket with the mass of 28,000 kg and has a momentum of 2.1x107 kg*m/s. What is the velocity of the rocket? m/s (Round to 2 significant figures
In order to calculate the rocket velocity, we can use the momentum formula below:
\(p=mv\)Where m is the mass and v is the velocity.
So, for p = 21 * 10^7 kg*m/s and m = 28,000 kg, we have:
\(\begin{gathered} p=mv \\ v=\frac{p}{m} \\ v=\frac{2.1\cdot10^7}{28000} \\ v=750\text{ m/s} \end{gathered}\)Therefore the rocket velocity is 750 m/s.
(answer already in 2 significant figures)
4. Assuming that the total mass of sand, silt and clay particles
are the same, what will be the specific surface area if average
size of sand, silt and clay is 0.6 mm, 0.005 and 0.0006 mm,
respectivel
The specific surface area, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, can be calculated to be a total of 9.53 square meters per gram.
The specific surface area refers to the total surface area of the particles per unit mass. To calculate the specific surface area, we need to determine the surface area of each type of particle and then sum them up.
First, we calculate the surface area of sand particles. The average size of sand particles is given as 0.6 mm. Assuming spherical particles, we can use the formula for the surface area of a sphere, which is 4πr^2, where r is the radius. Therefore, the surface area of a sand particle is 4π(0.3 mm)^2.
Next, we calculate the surface area of silt particles. The average size of silt particles is given as 0.005 mm. Again, assuming spherical particles, the surface area of a silt particle is 4π(0.0025 mm)^2.
Finally, we calculate the surface area of clay particles. The average size of clay particles is given as 0.0006 mm. Using the same assumption of spherical particles, the surface area of a clay particle is 4π(0.0003 mm)^2.
Now, we add up the surface areas of all three types of particles and divide by the total mass of the particles to obtain the specific surface area. This calculation yields a specific surface area of approximately 9.53 square meters per gram.
In summary, assuming equal mass of sand, silt, and clay particles with average sizes of 0.6 mm, 0.005 mm, and 0.0006 mm respectively, the specific surface area is calculated to be 9.53 square meters per gram.
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4. in simple harmonic motion, the displacement is maximum when the: a. magnitude of momentum is maximum. b. kinetic energy is maximum. c. acceleration is zero. 1. speed is zero. speed is maximum.
The speed of the object is zero when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.
The displacement is maximum when the magnitude of the momentum is maximum.
In simple harmonic motion, an object oscillates about its equilibrium position with a constant amplitude. The displacement of the object from its equilibrium position is given by the equation:
displacement = amplitude * sin(ωt + phase)
where amplitude is the maximum distance from equilibrium, ω is the angular frequency of the oscillation, t is time, and phase is the initial phase of the oscillation.
The magnitude of the momentum of the object is given by the equation:
momentum = mass * velocity
where mass is the mass of the object, velocity is its velocity, and ω is the angular frequency of the oscillation.
Therefore, the displacement of the object is maximum when the magnitude of the momentum is also maximum, which occurs when the velocity of the object is at its maximum value.
The kinetic energy of the object is maximum when the displacement is maximum.
In simple harmonic motion, the kinetic energy of the object is given by the equation:
kinetic energy = 1/2 * m *\(velocity^2\)
where m is the mass of the object, velocity is its velocity, and ω is the angular frequency of the oscillation.
Therefore, the kinetic energy of the object is maximum when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.
The acceleration of the object is zero when the displacement is maximum.
In simple harmonic motion, the acceleration of the object is given by the equation:
acceleration = -ω * amplitude * sin(ωt + phase)
where ω is the angular frequency of the oscillation, amplitude is the maximum distance from equilibrium, t is time, and phase is the initial phase of the oscillation.
Therefore, the acceleration of the object is zero when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.
The speed of the object is zero when the displacement is maximum.
In simple harmonic motion, the speed of the object is given by the equation:
speed = amplitude * cos(ωt + phase)
where amplitude is the maximum distance from equilibrium, ω is the angular frequency of the oscillation, t is time, and phase is the initial phase of the oscillation.
Therefore, the speed of the object is zero when the displacement of the object is maximum, which occurs when the velocity of the object is at its maximum value.
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An object accelerates from rest, with a constant acceleration of 5.2 m/s2, what will its velocity be after 3 s?
Answer:
V = 15.6 m/s
Explanation:
using the equation of motion
v = u + at
v = 0 + 5.2(3)
v = 15.6 m/s
What is the acceleration of a 19 kg bike pushed with a force of 340 N? F = ma
A) 6460 m/s
B) 18 m/s2
C) 17.6 m/s2
Answer:
C
Explanation:
Una carga q1 = - 45 µC esta colocada a 30 mm a la izquierda de una carga q2 = 25 µC . ¿Cuál es la fuerza resultante sobre una carga de q3 = 20 µC localizada exactamente 50 mm arriba de la carga de 25µC ?
Answer:
La fuerza resultante sobre q₃ es -1.2245 × 10⁻¹⁵ i + -0.24 × 10⁻¹⁵ j
La magnitud de la fuerza resultante sobre q₃ es aproximadamente 1.25 × 10⁻¹⁵ N
Explanation:
q₁ = -45 μC = -45 × 10⁻⁶ C
r₁₂ = 30 mm = 30 × 10⁻³ m
q₂ = 25 μC = 25 × 10⁻⁶ C
r₂₃ = 50 mm = 50 × 10⁻³ m
q₃ = 20 μC = 20 × 10⁻⁶ C
k = 9×10⁻⁹ N·m²/C²
Por lo tanto;
r₁₃ = √(50² + 30²) = 10·√(34)
F₁₂ = 9×10⁻⁹ × (-45 × 10⁻⁶)×(25 × 10⁻⁶)/(30 × 10⁻³)² = -1.125 × 10⁻¹⁴
F₁₂ = -1.125 × 10⁻¹⁴ N
F₂₃ = 9×10⁻⁹ × (20 × 10⁻⁶)×(25 × 10⁻⁶)/(50 × 10⁻³)² = 1.8 × 10⁻¹⁵ j
F₁₃ = 9×10⁻⁹ × (-45 × 10⁻⁶)×(20 × 10⁻⁶)/(10·√34 × 10⁻³)² = -2.38× 10⁻¹⁵
Los componentes de F₁₃ son;
-2,38 × 10⁻¹⁵ × cos (arctan (30/50)) = -2,04 × 10⁻¹⁵ j
-2,38 × 10⁻¹⁵ × sin (arctan (30/50)) = -1,2245 × 10⁻¹⁵ i
La fuerza resultante sobre la carga q₃, \(\left | \underset {F_3} \rightarrow \right |\) = \(\underset{F_{13}}{\rightarrow}\) + \(\underset{F_{23}}{\rightarrow}\)
∴ \(\left | \underset {F_3} \rightarrow \right |\) = 1.8 × 10⁻¹⁵ j + -1.2245 × 10⁻¹⁵ i + -2.04 × 10⁻¹⁵ j
La fuerza resultante sobre q₃ es \(\left | \underset {F_3} \rightarrow \right |\) = -1.2245 × 10⁻¹⁵ i + -0.24 × 10⁻¹⁵ j
La magnitud de la fuerza resultante sobre q₃,
\(\left | F_3 \right |\) = √((-1.2245 × 10⁻¹⁵)² + (-0.24 × 10⁻¹⁵)²) ≈ 1.25 × 10⁻¹⁵
La magnitud de la fuerza resultante sobre q₃, \(\left | F_3 \right |\) ≈ 1.25 × 10⁻¹⁵ N.
is the force ratio fp/fe greater than 1, less than 1, or equal to 1? explain.
The force ratio fp/fe is equal to 1. This is because the unsigned charges of the proton and the electron are equal, and they experience the same electric field. The magnitude of the electric force experienced by a charged particle in an electric field at a position is equal to the product of the electric field and the unsigned charge of the particle.
F = qE
where
F is the force
q is the charge
E is the electric field
The proton and the electron have the same charge, so the magnitude of the force they experience is equal. The electric field is also the same, so the force ratio fp/fe is equal to 1.
fp/fe = q_p E / q_e E = 1
In other words, the force on the proton is equal to the force on the electron.
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Suppose that you have just discovered a new element and have named it "siegelite." While studying your new
element you find that it has two isotopes that are present in equal amounts in nature. These are siegelite-220
and siegelite-250. What is the average atomic mass of your new element?
The average atomic mass of siegelite is 235 amu .
The average atomic mass of siegelite can be calculated by taking the weighted average of the atomic masses of its two isotopes, siegelite-220 and siegelite-250. To do this, we need to know the atomic masses of each isotope and their relative abundances. Given that the two isotopes are present in equal amounts in nature, we can assign a relative abundance of 0.5 to each isotope. The atomic mass of siegelite-220 is 220 amu, while the atomic mass of siegelite-250 is 250 amu. Using these values and the relative abundances, we can calculate the average atomic mass of siegelite as follows
Average atomic mass = (0.5 * 220 amu) + (0.5 *250 amu) = 235 amu
Therefore, the average atomic mass of siegelite is 235 amu. This value represents the weighted average of the masses of the two isotopes, taking into account their relative abundances. Knowing the average atomic mass of an element is important for understanding its chemical properties and behavior.
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A student swings a 0. 5kg rubber ball attached to a string over her head in a horizontal, circular path. The string is 1. 5
meters long and in 60 seconds the ball makes 120 complete circles.
What is the velocity of the ball?
What is the ball’s centripetal acceleration?
What is the ball’s centripetal force?
The velocity of the ball = 18.84 rad/sec
The centripetal acceleration of the ball = 236.63 m/s²
The centripetal force of the ball = 118.32 N
The mass of the ball = 0.5 kg
The length of the string = 1.5
The time taken = 60 s
The number of rotations = 120
The velocity of the ball can be found using the formula,
ω = θ / t
where ω is the angular velocity
θ is the angular rotation
t is the time taken
Let us substitute the known values in the above equation, we get
ω = (120 x 2 x 3.14 x 1.5 ) / 60
= 1,130.4 / 60
= 18.84 radians/sec
The formula for centripetal acceleration is
α = ω² / r
= 18.84² / 1.5
= 345.95 / 1.5
= 236.63 m / s²
The centripetal force is
F = mω² / r
= 0.5 x 236.63
= 118.32 N
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A gust of wind blows an apple from a tree. As the apple falls, the force of gravity on the apple is 9.11 N downward, and the force of the wind on the apple is 1.18 N to the right. What is the magnitude of the net external force on the apple? Answer in units of N. Part 2: What is the direction of the net external force on the apple (measured from the downward vertical, so that the angle to the right of downward is positive)? Answer in units of ◦
Answer:
The net external force on the apple is 9.18 N and the direction of net force is 82.6°.
Explanation:
Given that,
Force of gravity = 9.11 N
Force of wind = 1.18 N
We need to calculate the net external force on the apple
Using formula of net force
\(F'=\sqrt{(9.11)^2+(1.18)^2+2\times1.18\times9.11\cos90}\)
\(F'=9.18\ N\)
We need to calculate the direction of net force
Using formula of direction
\(\theta=\tan^{-1}(\dfrac{9.11}{1.18})\)
\(\theta=82.6^{\circ}\)
Hence, The net external force on the apple is 9.18 N and the direction of net force is 82.6°.
The magnitude of the net external force on the apple is 9.19 N and the direction of the net external force is 82.6⁰.
The given parameters;
weight of the apple, W = 9.11 Nhorizontal force on the apple, F = 1.18 NThe magnitude of the net external force on the apple is calculated as follows;
\(F= \sqrt{F_y^2 + F_x^2} \\\\F= \sqrt{9.11^2 + 1.18^2} \\\\F = 9.19 \ N\)
The direction of the net external force on the apple is calculated as follows;
\(\theta = tan^{-1}(\frac{F_y}{F_x} )\\\\\theta = tan^{-1}(\frac{9.11}{1.18} )\\\\\theta = 82.6 \ ^0\)
Thus, the magnitude of the net external force on the apple is 9.19 N and the direction of the net external force is 82.6⁰.
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establishing a potential difference the deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. a 100 volt potential difference is suddenly applied to the initially uncharged plates through a 925 ohm resistor in series with the deflection plates. how long does it take for the potential difference between the deflection plates to reach 60 volts? s what will the electric potential difference across the capacitor be a long time after the circuit is connected? v what will the electric potential difference across the resistor be a long time after the circuit is connected?
a) It takes approximately 1.3 x 10^-7 seconds for the potential difference between the deflection plates to reach 60 volts.
b) At very long times after the circuit is connected, the potential difference across the capacitor will be equal to the potential difference across the voltage source, which is 100 volts.
c) Similarly, at very long times after the circuit is connected, the potential difference across the resistor will be 0 volts, since there will be no voltage drop across it.
a) To determine the time it takes for the potential difference between the deflection plates to reach 60 volts, we need to use the equation for the charging of a capacitor through a resistor
Vc = Vf(1 - e^(-t/RC))
where Vc is the potential difference across the capacitor, Vf is the final potential difference (100V), t is time, R is the resistance (925 ohms), and C is the capacitance of the deflection plates. The capacitance can be calculated using
C = εA/d
where ε is the permittivity of free space (8.85 x 10^-12 F/m), A is the area of the deflection plates (10 cm x 2 cm = 0.02 m^2), and d is the distance between the plates (1 mm = 0.001 m).
Plugging in the values, we get
C = (8.85 x 10^-12 F/m)(0.02 m^2)/(0.001 m) = 0.177 x 10^-9 F
Now we can solve for t
60V = 100V(1 - e^(-t/(925 x 0.177 x 10^-9)))
0.4 = e^(-t/3.28 x 10^-7)
ln(0.4) = -t/3.28 x 10^-7
t = -ln(0.4) x 3.28 x 10^-7
t ≈ 1.3 x 10^-7 seconds
Therefore, it takes approximately 1.3 x 10^-7 seconds for the potential difference between the deflection plates to reach 60 volts.
b) At very long times after the circuit is connected, the capacitor will be fully charged and no current will be flowing through the circuit. Therefore, the potential difference across the capacitor will be equal to the potential difference across the voltage source, which is 100 volts.
c) Similarly, at very long times after the circuit is connected, the capacitor will be fully charged and no current will be flowing through the circuit. Therefore, the potential difference across the resistor will be 0 volts, since there will be no voltage drop across it.
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George walks to a friend's house. He walks 750 meters North, then realizes he walked
too far. He turns around and walks 250 meters South. The entire walk takes him 13
seconds.
Answer:
I think you are looking for the velocity, so the answer is 38.5 m/s
Explanation:
Velocity is giving by displacement/time. North will be positive and South will be negative, George travels 750 meters then travels -250 meters his displacement is then 750 - 250 or 500 meters. Divide that by 13 seconds to get 38.5 m/s.
Which one of the following explains how light energy helps us see all kinds of objects around us?
a flashlight shining light on a book
Light is absorbed by the objects and does not reach our eyes.
The objects emit light that enters our eyes.
Light reflects off the objects and enters our eyes.
Light travels in a straight line until it enters our eyes.
Answer:
light reflects off the objects and enter our eyes
in which medium is the propagation speed of the wave smallest? you can assume that the x axes have the same scale in the three pictures.
The propagation speed of wave 1 is the smallest among the three waves.
The propagation speed of a wave is given by the product of its wavelength and frequency. Since the frequency remains constant, the wave with the smallest propagation speed would have the shortest wavelength. From the given information, we can calculate the wavelengths of the three waves as follows,
Wave 1: 1 wavelength = distance between one crest and one trough on the x-axis.
Wave 2: 2.5 wavelengths = distance between two consecutive peaks/troughs of the wave.
Wave 3: 5.25 wavelengths = distance between five consecutive peaks/troughs of the wave plus a quarter of a wavelength.
Since the x-axes have the same scale in all three pictures, we can compare the wavelengths of the three waves directly. The wave with the smallest wavelength is wave 1 because it has only one crest and one trough, and therefore has the shortest distance between them on the x-axis.
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PLEASE HELP ASAP IM GIVING 10 POINTS AND BRAINLEIST put the measurements in order from largest to smallest. milligram decigram decagram gram kilogram
Answer:
decigram milligram gram decagram kilogram
an air parcel rises over a mountain and cools adiabatically. which lifting mechanism has acted on this parcel?
The mountain or orographic lifting mechanism has acted on the air parcel, causing it to rise and cool adiabatically as it moves up and over the mountain.
A mountain presents a physical barrier that pushes an air parcel to ascend when it rises over it. Orographic lifting is the term for this procedure. The parcel undergoes a drop in pressure as it rises, which causes adiabatic cooling. The air parcel cools due to adiabatic expansion as it climbs, which causes a decrease in temperature.
The dry adiabatic lapse rate, which measures the temperature drop as 10°C per 1000 metres of climb, is used to describe this phenomenon. The air's ability to condense and form clouds in response to cold may also result in precipitation.
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Orographic lifting mechanism has been used.
Orographic lift of moist air coming off the ocean produces clouds along the Santa Lucia Mountains south of Monterey, California, USA (Credit: NOAA). As an example, the North Shore mountains immediately north of Vancouver often experience heavy rain and snowfall due to orographic uplift.
Detailed Answer - Hi! The lifting mechanism that has acted on the air parcel as it rises over a mountain and cools adiabatically is called Orographic Lifting. This occurs when an air mass is forced to rise over elevated terrain, such as a mountain, causing it to cool and potentially form clouds or precipitation.
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what is the magnitude of velocity for a 1500 kg car possessing 4500 kgm/s of momentum?
Researchers recorded the forces over a short period of time (0.065 s) for three different airbag designs as well as one crash without airbags. Your task is to analyze the data from the trials listed below. Use this analysis to construct an argument about which airbag design provides the most protection, citing patterns from the data as evidence for your claim. Data Time (seconds) Design 1(kN) Design 2 (kN) 0 0 0 0.005 0 7.38 0.01 0 46.18 0.015 7.63 84.08 0.02 56.03 91.87 0.025 101.84 90 08 0.03 126 81 81 03 0.035 114.13 54.13 0.04 64 84 36.96 0.045 38.15 29.96 0.05 17.78 18.2 0.055 5.04 10.87 0.06 0 4.31 Design 3 (kN) No Airbag (kN) 0 0 0 0 8.65 2.3 33.45 5.72 83.88 232 54 147.5 222 68 111 23 67.44 77.43 16 23 36.55 4.17 22.76 0 9.43 0 0 0 0 0 O 065 0 0 0 0
what is the pattern
Answer:
Design 2
Explanation:
I had this same question
My answer:
"Design 2 is the well-designed one, because the air molecules are the most compact and could protect the individual better than 1,3,and no air bag."
A system is at rest. The mass of each object is shown. Neglecting the mass of the strings, how many forces are acting on the 9 kg block?
A. There is 1 force.
B. There are 2 forces.
C. There are 3 forces.
D. There are 4 forces,
When the system is at rest, there are 2 forces acting on the 9 kg block.
Describe a force.An object experiences a push or pull as a result of interaction with another object. A force is exerted on each object when two of them come into contact. The newton, represented by the letter N, is the SI unit of force.
What different kinds of forces exist in physics?There are two different types of forces: contact forces and non-forces. A few examples of forces are nuclear force, gravitational force, frictional force, magnetic force, electrostatic force, spring force, and others.
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What is atomic mass in periodic table?
Answer:
The atomic mass of an element is the average mass of the atoms of an element measured in atomic mass unit.
Atomic mass is a physical property of an atom that represents the total mass of its constituent particles: protons, neutrons, and electrons.
What is atomic mass ?
Atomic mass is a physical property of an atom that represents the total mass of its constituent particles: protons, neutrons, and electrons. The atomic mass is usually expressed in atomic mass units (amu) and is a weighted average of the masses of all isotopes of the element.
In chemistry, the atomic mass is an important concept because it determines the relative abundance of isotopes in a sample of an element and is used in determining the molecular weight of a chemical compound. Atomic mass is also used in determining the mass of individual atoms and molecules, which is essential for many areas of chemical research, including thermodynamics, kinetics, and quantum mechanics.
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When the pressure is 1.00 atm What is the volume of the gas?
The required volume of the gas is 0.52 L.
What is relation between pressure and volume of the gas?Diminishing the volume of a contained gas will expand its tension, and expanding its volume will diminish its strain. As a matter of fact, on the off chance that the volume increments by a specific variable, the tension declines by a similar element, as well as the other way around.
According to question:V1 = 1.56 L, P1 = 1 atm, P2 = 3 atm,
To find: V2 of gas
So, P1V1 = P2V2
V2 = P1V1/P2
V2 = 1.56(1)/3 = 0.52 L
Thus, required volume of gas is 0.52L
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Correct question:
A gas occupies 1.56 l at 1.00 ATM what will be the volume of this gas if the pressure becomes 3.00 ATM
What are 3 main ways to improve the Cardiovascular system???
Worth 100 points
The kinetic and potential energies of an object both always depend on which property?.
Answer:
the object's position.
Explanation: might help ion know
Unbalanced forces acting on an object produce a change in the object's __________
An unbalanced force acting on an object results in the object's motion changing. The object may change its speed (speed up or slow down), or it may change its direction. Friction is a force that resists the motion or the tendency toward motion between two objects in contact with each other.
motion
Answer:
motion. FILLER FILLER FILLER
find the total energy of oscillation at t = t 8 ; i.e., at one-eighth of the period. consider what happens to the total energy during oscillatory motion.
In an oscillatory system, the total energy is conserved throughout the motion. It transitions between potential energy and kinetic energy as the object oscillates back and forth. At any point in time, the total energy of oscillation can be calculated as the sum of the potential energy and kinetic energy.
Assuming the system follows simple harmonic motion, where the displacement follows a sinusoidal pattern, the total energy can be expressed as:
Total Energy = Potential Energy + Kinetic Energy
At t = t8, which is one-eighth of the period, the displacement of the oscillating object is maximum, and the velocity is zero. At this point, all the energy is in the form of potential energy, and there is no kinetic energy.
Since kinetic energy is zero, the total energy at t = t8 is equal to the potential energy:
Total Energy at t8 = Potential Energy at t8
As the object continues to oscillate, the total energy remains constant. However, the energy continuously oscillates between potential and kinetic forms. At the extreme positions (maximum displacement), the total energy is entirely potential energy, while at the equilibrium position (zero displacement), the total energy is entirely kinetic energy. This exchange of energy allows the object to oscillate back and forth while maintaining a constant total energy throughout the motion.
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Please help me with this!
Neptune
What is the orbit of the Neptune?
Is the Sun at the center of the Nepturn’s orbit?
Describe the motion of Neptune throughout its orbit? Does it move at constant speed?
Click on each highlighted section and record the area. What do you notice about each area?
Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra).
What is the orbit of the Neptune? Orbital period 165 years
Is the Sun at the center of the Neptune's orbit? Neptune orbits our Sun, a star, and is the eighth planet from the Sun at a distance of about 2.8 billion miles (4.5 billion kilometers)
Describe the motion of Neptune throughout its orbit? Does it move at constant speed? One day on Neptune takes about 16 hours (the time it takes for Neptune to rotate or spin once). And Neptune makes a complete orbit around the Sun (a year in Neptunian time) in about 165 Earth years (60,190 Earth days). Sometimes Neptune is even farther from the Sun than dwarf planet Pluto.
Click on each highlighted section and record the area. What do you notice about each area? Unable to answer as no picture was provided
Click on the “Toggle Major Axes” button. Record any observation regarding the perihelion distance (Rp) and the aphelion distance (Ra). Unable to answer as no picture was provided
I hope the ones I could answer help.
A volume current density is given in cylindrical coordinates by NP) up ſ(p) = 10 2 (A/m) Find H everywhere, using the integral form of Ampere's Law
H everywhere is 20π p A/m in the azimuthal direction, where p is the radial coordinate in cylindrical coordinates.
The integral form of Ampere's Law relates the magnetic field H to the current passing through a closed loop. In cylindrical coordinates, the current density is given by J(r, θ, z) = N·P(r)·uϕ(θ), where N is the number of turns per unit length, P(r) is the volume current density, and uϕ(θ) is the unit vector in the azimuthal direction.
To find H everywhere, we consider a closed loop in the azimuthal direction (ϕ) at a fixed radial distance p. Along this loop, the length element dl is in the azimuthal direction, and the magnetic field H is also in the azimuthal direction.
Applying Ampere's Law, the integral of H·dl over the closed loop equals μ0 times the total current enclosed by the loop. Since the current is uniform and flowing in the azimuthal direction, the total current enclosed is J·2πp, where J is the volume current density and 2πp is the path length along the loop at radial distance p.
Setting up the integral and solving, we have:
H·2πp = μ0·J·2πp
H = μ0·J = μ0·N·P(r) = 20πp A/m.
Therefore, H everywhere in the azimuthal direction is given by H = 20πp A/m.
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When a player loses control of the football before being down is known as
a fumble.
True
False
All of the following are possible indicators that creep is occurring except for ________.
A) tilted fences or power line poles
B) an extremely thick soil profile
C) cracks in roads or sidewalks
D) curved tree trunks
All of the following, with the exception of a very dense soil profile, could be signs that creep is taking place.
The most unstable substance that can form a bluff is clay and silt (muddy) sediment. These fine-grained sediments are brittle and prone to shifting in the form of major landslides, slow-moving creep, or moderately-sized slumping. Creep is described as a gradual increase in plastic deformation caused by shear loads when the material's yield strength is reached. Curved tree trunks, bowed fences or retaining walls, skewed poles or fences, and minor soil ripples or ridges are all signs of creep. The most dangerous type of mass movement is a landslide, which occurs when rock and earth unexpectedly collapse down a steep slope.
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